Q 7 Organisations which do not have a diverse range of funding streams are at
8 DEVELOPMENT OF AN HEURISTIC
8.1 Notes on the Heuristic
Chapter III
Specificities
β’ uοΏ½is closed under pullback.
β’ For each objectπ inuοΏ½:
β π©πΏ(π)is the set of all finite and jointly surjective sinks onπ.
β π©πΏπ(π) is the set of all finite sinks Ξ¦on π such that the induced mapβ(π,π₯)βΞ¦π β π is a universal topological quotient.
3.1.3 ΒΆ The following terminology is non-standard.
Definition. A continuous mapπ : π β π issemiproper if it has the following property:
β’ For every pullback square inTopof the form below,
πβ² π
πβ² π
πβ² π
ifπβ²is compact, thenπβ²is also compact.
Remark. Thus, from the relative point of view, a semiproper map of topological spaces is a continuous family of compact spaces.
Example. Every continuous map from a compact space to a Hausdorff space is semiproper. Indeed, given a pullback square in Top as in the definition, ifπ is compact andπ is Hausdorff, then the comparison map πβ² β πβ²Γ πis a closed embedding, soπβ²is compact whenπβ²is.
Properties of semiproper maps
Proposition.
(i) Every closed embedding of topological spaces is semiproper.
(ii) For every topological spaceπ, the codiagonalβπ : π β¨Ώ π β π is semiproper.
(iii) The class of semiproper maps of topological spaces is a quadrable class of morphisms inTop.
(iv) The class of semiproper maps of topological spaces is closed under composition.
(v) The class of semiproper maps of topological spaces is closed under (possibly infinitary) coproduct inTop.
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3.1. Compactness (vi) Given a surjective continuous mapπ : π β π and a continuous mapπ : π β π, ifπ β π : π β π is semiproper, thenπ : π β π is also semiproper.
Proof. Straightforward. β§«
Corollary. Letβ±ππbe the class of semiproper maps in uοΏ½. Then every morphism inuοΏ½ that is of β±ππ-typeπ©πΏ-semilocally on the domain is semi-proper.
Proof. Applyproposition 3.1.3. β
3.1.4 ΒΆ We will see that the following is a specialisation of the notion of semi-proper map.
Definition. A continuous mapπ : π β π isproper if it has the fol-lowing property:
β’ For every pullback square inTopof the form below,
πβ² π
πβ² π
πβ² π
the mapπβ² : πβ² β πβ²is closed, i.e. the image of every closed sub-space ofπβ²is a closed subspace ofπβ².
Example. Ifπis a compact topological space, then the unique mapπ β 1is proper: this is the precisely the statement of the tube lemma.
Properties of proper maps
Proposition.
(i) An injective continuous map is proper if and only if it is a closed embedding.
(ii) For every topological spaceπ, the codiagonalβπ : π β¨Ώ π β π is proper.
(iii) The class of proper maps of topological spaces is a quadrable class of morphisms inTop.
(iv) The class of proper maps of topological spaces is closed under com-position.
(v) The class of proper maps of topological spaces is closed under (pos-sibly infinitary) coproduct inTop.
(vi) Given a surjective continuous mapπ : π β π and a continuous mapπ : π β π, ifπ β π : π β π is proper, thenπ : π β π is also proper.
(vii) Given a pullback square inTopof the form below,
Μπ π
Μπ π
Μπ π
where Μπ β π is a universal topological quotient, if π : ΜΜ π β Μπ is proper, thenπ : π β π is also proper.
Proof. Straightforward. β§«
Corollary. Letβ±πbe the class of proper maps inuοΏ½. Then every morph-ism inuοΏ½ that isπ©πΏπ-semilocally ofβ±π-type is proper.
Proof. Applyproposition 3.1.3. β
Remark. In the language of Β§2.2, what we have shown is that(uοΏ½,β±π, π©πΏπ) is a finitary (i.e. β΅0-ary) extensive regulated ecumene that satisfies the descent axiom and in which every eunoic morphism is genial.
3.1.5 ΒΆ Properness is closely related to compactness. For instance, suppose π is a topological space such that the unique mapπ β 1is proper. Let π = {1 β π+11 | π β β} βͺ {1} β β and let (π₯π| π β β) be a sequence of points ofπ. Considerπ = {(1 β π+11 , π₯π) | π β β} β π Γ π. The closure ofπ is Μπ = π βͺ{1}Γπ΄, whereπ΄is the set of accumulation points of (π₯π| π β β). Since Μπ is a closed subspace of π Γ π, its image is a closed subspace ofπ. In particular,1is in the image of Μπ, i.e.π΄contains a point. Thus, every sequence inπ contains a convergent subsequence, 148
3.1. Compactness i.e.π is sequentially compact. A similar argument using nets instead of sequences can be used to show thatπ is compact.
Much more generally, we have the following result.
Recognition principle for proper maps
Theorem. Let π : π β π be a continuous map. The following are equivalent:
(i) The mapπ : π β π is proper.
(ii) For every topological spaceπ, the mapidπ Γ π : π Γ π β π Γ π is closed.
(iii) The map π : π β π is closed and, for every π¦ β π, πβ1{π¦}is compact.
(iv) The mapπ : π β π is closed and, for every subspaceπβ² β π, if πβ²is compact, thenπβ1πβ²is also compact.
(v) The mapπ : π β π is closed and semiproper.
Proof. (i)β(ii). Immediate.
(ii)β(iii), (iii)β(i). Seetag005Rin [Stacks].
(i)β(v). Consider a pullback square inTopof the form below:
πβ² π
πβ² π
πβ² π
Supposeπ : π β π is proper andπβ² is compact. We must show that πβ²is compact. Then, byproposition 3.1.4,πβ²: πβ²β πβ²is also proper.
Since the unique mapπβ² β 1 is proper (by the tube lemma), it follows that πβ² β 1 is also proper. But we know (i) β (iii), so πβ² is indeed compact.
(v)β(iv), (iv)β(iii). Immediate. β‘
Example. Ifπis a compact topological space andπ is a Hausdorff space, then every continuous mapπ β π is proper: in view ofproposition 3.1.4 andtheorem 3.1.5, this is a special case oflemma 1.1.9.
3.1.6
When semiproper implies proper
Lemma. Letπ : π β π be a continuous map. Assumingπ is a compactly generated Hausdorff space, the following are equivalent:
(i) The mapπ : π β π is proper.
(ii) The mapπ : π β π is semiproper.
(iii) For every subspace πβ² β π, if πβ²is compact, then πβ1πβ²is also compact.
Proof. (i)β(ii). Seetheorem 3.1.5.
(ii)β(iii). Immediate.
(iii)β(i). In view of the theorem, it is enough to check thatπ : π β π is a closed map.
Let πβ²be a closed subspace of π and let πβ² be its image inπ. We wish to show that πβ² is a closed subspace ofπ. Since π is compactly generated, it is enough to show thatπβ²β© π is a closed subspace ofπ for all compact subspacesπ β π.
Letπ be a compact subspace ofπ. Thenπβ1π is a compact subspace ofπ. Sinceπβ²β© πβ1π is a closed subspace ofπβ1π, it is compact. The image ofπβ²β© πβ1π inπ isπβ²β© π, and sinceπ is Hausdorff, it follows thatπβ²β© π is indeed a closed subspace ofπ. β 3.1.7 Definition. A continuous map π : π β π is perfect if it has the
following properties:
β’ π : π β π is proper.
β’ π : π β π is separated, i.e. the relative diagonalΞπ : π β π Γπ π is a closed embedding.
Example. For a topological spaceπ, the unique mapπ β 1 is perfect if and only ifπ is a compact Hausdorff space.
Properties of perfect maps
Proposition.
(i) An injective continuous map is perfect if and only if it is a closed embedding.
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3.1. Compactness (ii) For every topological spaceπ, the codiagonalβπ : π β¨Ώ π β π
is perfect.
(iii) The class of perfect maps of topological spaces is a quadrable class of morphisms inTop.
(iv) The class of perfect maps of topological spaces is closed under composition.
(v) The class of perfect maps of topological spaces is closed under (possibly infinitary) coproduct inTop.
(vi) Given continuous maps π : π β π and π : π β π, if both π : π β π andπ β π : π β π are perfect, thenπ : π β π is also perfect.
(vii) Given a surjective continuous mapπ : π β π and a continuous mapπ : π β π, ifπ : π β π is proper andπ βπ : π β πis perfect, thenπ : π β π is also perfect.
(viii) Given a pullback square inTopof the form below,
Μπ π
Μπ π
Μπ π
where Μπ β π is a universal topological quotient, if π : ΜΜ π β Μπ is perfect, thenπ : π β π is also perfect.
Proof. (i)β(vi). Straightforward. (Recall propositions1.1.11and3.1.4.) (vii). Under the hypotheses,π : π β πis proper. It remains to be shown thatπ : π β πis separated.
Consider the following commutative square inTop:
π π
π Γπ π π Γπ π
Ξπβπ
π
Ξπ
πΓππ
Sinceπ : π β π is proper, so too isπ Γπ π : π Γπ π β π Γπ π. On the other hand, since π β π : π β π is separated, the relative diagonal
Ξπβπ : π β π Γπ π is a closed embedding. Hence,Ξπ : π β π Γπ π is indeed a closed embedding.
(viii). Under the hypotheses, the following is a pullback square inTop,
Μπ π
Μπ Γ Μπ Μπ π Γπ π
ΞπΜ Ξπ
and the claim follows. β
Corollary. LetuοΏ½πbe the class of perfect maps inuοΏ½. Then every morph-ism inuοΏ½ that is(uοΏ½π, π©πΏπ)-semilocally ofuοΏ½π-type is perfect.
Remark. In the language of Β§2.2, what we have shown is that(uοΏ½,uοΏ½π, π©πΏπ) is an Γ©tale finitary (i.e.β΅0-ary) extensive regulated ecumene that satisfies the descent axiom.
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