Theses
Thesis/Dissertation Collections
1972
Pulse-Width-Modulation Control for Second
Order Plants Via a Quadratic Criterion
Charles Gebo
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PULSE-WIDTH-MODULATION CONTROL
FOR SECOND ORDER PLANTS VIA A
QUADRATIC CRITERION
by
Charles H. Gebo
A Thesis Submitted
in
Partial Fulfillment
of the
Requirements for the Degree of
MASTER OF SCIENCE
in
Electrical Engineering
Prof.
Robert E. Lee
(Thesis Advisor)
Prof.
Harvey E. Rhody
Prof.
George A. Brown
Prof.
Walton F. Walker
(Department Head)
DEPARTMENT OF ELECTRICAL ENGINEERING
COLLEGE OF APPLIED SCIENCE
ROCHESTER INSTI'I'UTE OF TECHNOLOGY
ROCHESTER, NEW YORK
ABSTRACT
This paper presents a mathematical study of the control of
a second order plant
having
real distinct rootsby
use ofpulse-width-modulation. An integrator connected between the
pulse-wldth-modulator and
the
plant is a fixed element ofthe control
loop.
The integral-square err.or is used as theIndex of performance. The ISE is minimized with the con
straint that the pulse modulator is limited to a maximum of
one output reversal for a step change in
input.
Derivation of the equation which will predict the exact switching timeof the modulator output to minimize the performance index
for any step amplitude is presented. A3n example problem is
worked to illustrate the use of
the
switching equation indetermining
switchingtime.
The example is concluded with graphs showing the optimal plant response for various stepinput amplitudes, variation of switching time as a function
of step amplitude, and variation of
integral-square
error as a function of switchingtime.
TABLE OF CONTENTS
Page
List of Tables
-vi
List of Figures vii
I,
IntroductionII.
GeneralTheory
A.
System DescriptionB. Derivation of Plant Response Equation
8
C. Investigation of Plant Response 12
D. Formulation of Integral-Square Error
21
E.
Derivation of theSwitching
Equation27
TABLE OF CONTENTS
(CONT'D)
Page
A.
Objective and Plant Description35
B.
Calculation of T35
s
IV.
Conclusion 50V.
References 52VI.
Appendix53
A.
Derivation ofC,(m,T_tt)
in Termsj s
of
c2(Ts,t)
53
B.
Evaluation of~.M *>
u r
f
//
TABLE
(CONT'D)
C,
Evaluation of7r
Page
fe^WU*
67
D. Evaluation of
A^r
cj
^7?^
tftt 78LIST OF TABLES
Page
Tables
1,
2,
3
- Tabulation ofSwitching
Equation Coefficients
29, 30,
31Tables
kt
5,
6
- Evaluation ofSwitching
Equation Coefficients
36,
37,
38Table
7
- OptimumSwitching
Times ,^0
LIST OF FIGURES
Page
Figure 1 - Block Diagram of System
7
Figure 2 - Plant Response 16
Figure
3
- Optimum Plant Input 18Figure
k
- Flow Chart for Solution ofSwitching
Equation 3k
Figure
5
- OptimumSwitching
Timekl
Figure
6
- Comparison of Optimal and Sub-Optimal PlantResponses ,
k3
Figure
7
- Optimum Response Curves,
kk
Figure
8
- Variation of Integral-Square Error withLIST OF FIGURES
(CONT'D)
Page
Figure
9
-P.
W.
Modulator Output & Plant Input forInput
Step
-0.5
^8
Figure 10- P. W. Modulator Output & Plant Input for
the same size motor can be used to operate several different sized valves. This reduces
the
spare partsinventory.
A typical motor drive device for use with valves consists
basically
of an AC motor, geartrain,
limit switches and aslidewire which is driven from the output shaft. The motor
used in this drive will reach full speed from rest or go
from full speed to rest in the time required for one cycle
of the applied voltage
(i.e.
1 of a sec.). This response is extremely fastby
comparison with the speed of responseof most processes and for all practical purposes the motor dynamics may be neglected. The nonlinear characteristic
of the valve can be compensated
(i.e.
linearized) by
adjust ment of a crank and linkage mechanism on the drive unit.Therefore,
the combination of the drive unit and valve can be regarded as anintegrator.
The standard approach to controlling systems
having
electrically actuated drive mechanisms evolves around the classic three response controller with a slight modification, A dead band circuit is added between the controller output and the motor actuating relays and the controller feedback signal is taken off the slidewire wiper instead of from the controller output. The dead band circuit is used to prevent small random changes in plant output from continually turn
The basic
difference
between an electric valve drive and apneumatic diaphragm motor drive is that the latter is a con-.
tinuous
device
whereas the former is an on-off typedevice.
Taking
the controller feedback signal from the slidewirewiper in an electric motor drive system is an attempt to
eliminate the on-off nature of the drive and make its res
ponse more like the pneumatic
device.
This goal is achievedto the extent that it is possible to control the average rate
of valve
travel.
Assume thatthe
controller integral responseis adjusted so that the rate of change of voltage at the
slide-wire wiper generates a feedback signal large enough to cancel
the difference between the reference input and plant output.
Under this condition the motor will stop and remain at rest
until the decrease in feedback voltage allows the controller
output to exceed the dead band limit and turn the motor on
again. The motor on-off sequence is continued until plant
output and reference signal are in agreement. The valve move
ment is a quasl-staircase function and it can be seen that the
average valve velocity can be controlled
by
adjusting thecontroller integration rate.
Loops are generally tuned according to the 1/k
decay-ratio
criterion. This means that the process
loop,
andtherefore
the motor and valve, will cycle until the plant reaches
the
wear on
the
motor, valve, and other mechanical parts itwould
be
desirable
to find an alternative tothe
cyclingoperation. This is particularly desirable if
the
controlledflow contains abrasive material.
Ideally,
from an equipmentstandpoint, one would like to find a scheme whereby the
motor would turn on in response to an error signal,
drive
the
valve tothe
correct new position, and then turn off.However,
in addition to equipment considerations, some meansfor gauging the "goodness" of control must also be a part
of this scheme. In the analysis that
follows,
theintegral-square error is used as the performance index and provides
this "goodness"
measure. This index is minimized under the
constraint that only one reversal of the motor will be al
lowed for a step change in
input.
Therefore,
some form ofon-off type controller would provide the necessary control
signal..
An on-off type controller can also be used with a process
requiring a continuous input
by
adding an integrate and holdcircuit in the controller output. This circuit has
the
sameoutput characteristics as a motor driven valve and
the
analysis of this paper applies to both systems.
However,
the physical phenomena
taking
place in the two systems aredifferent.
In the system with the motor, the sequence ofduring
which AC power isbeing
applied to the motor terminals. In the system with the Integrate and hold circuit
the pulse sequence is the variable period of time
during
which a constant input voltage is
being
applied to the integrator.
In both systems the excitation will be appliedso that integration in the proper direction will occur.
The control problem becomes one of
deciding
how to synthesize the pulse sequence to be fed into the motor or inte
grator circuit in order to achieve the desired plant
response within the constraints specified. The analysis
in this paper develops a method for
doing
this and leadsto a system which is a departure from the current approach
GENERAL THEORY
A,
System DescriptionThe block diagram of the system is shown in Figure
1.
Itconsists of a pulse-width-modulator,
integrator,
and aplant. The plant is a linear system and may be described
in Laplace Transform notation
by
the transfer function^
=raW
where K is the plant gain.
The plant input signal will have the form shown on
the
diagram.
This signal is producedby
integration of thepulse-width-modulator output which is also shown.
In the
following
analysis the modulator output is assumeddue to a step change in the reference input R(S). The
function of
the
pulse modulator in this system is to correctly synthesize the pulse sequence required to minimize
the performance index subject to the single reversal con
+>
3
H O
O
cfl
s
CO
rH fa
w
a
o
H O fa <j! M
o
CQ
6
B,
Derivation of Plant Response EquationsLet
the
normalized plant output beC(t)
and represent thedynamic response
by
the vector matrix differential equationwhere: A is a constant system matrix
x(t) is the state vector
b is the control vector
u(t) is the plant input
t is the normalized time variable
Since we are only interested in the plant output, the phase
variables will be used.
Therefore,
the state vector iswhere
and
jr
(-6)
-Kit
-a.I/,
M
-frrt)
'Xj.
(6)
From these equations we get the
following
A
=o
i
i -ab
~(a--(-l>)
1
C(-t)
=[l
*]j
(4)
The
solution of equation(2)
Isto.y^&M
'fa^o*'
The
state transition matrix can he found as followstl-l
&
66
Also
where:
A
s are the eigenvalues of An is
the
system orderThe eigenvalues of A are the roots of the plant character
istic equation and will be assumed to be ordered as follows
From equation
(7)
e*= <*-,*
(8)
Therefore
-^ y
*FT-6
tt*
)
(9)
From equation
(6)
4-b
**=<<0x+,
(ye.
~*.&J
>~Ub(^e)
-(e-^l
(10)
When initial conditions are given at t
tQ
rather thanat t =
0,
equation(10)
becomes&(--t)
j_
0
-*.(&--)
^/>tt-*)\
fe'fi'^l
*&-*<))
L
-a(>(<
-a(-6-*.)
-
*
fr-th
./
?**)
,4*>tO
C.
Investigation of Plant ResponseWe will now use
the
general response equations developedin
the
last section to investigate the plant response forvarious
inputs.
The objective is to obtain insight intothe
problem of selecting the best input signal to achievethe optimum operating conditions as outlined in the intro
duction.
Let us assume that the plant input is a ramp followed
by
a constant value and compute the plant response.
/9-&t
06E**,
where k~/9 t.
The steady state output is from equation
(1)
If the desired steady state output is m, then from equation
(12)
From equations
(5)
and(10)
for x(tQ) t - 0 andu(t) -# t
%(t)
-b-a.
O
L
%,
y
(^y^}
(y^6^r)}
j
]Jr
.X,
-t
(t)
jLJ^-6
e~yt-r))rA'r
d3)
Performing
the
integrations indicated in equations(13)
and(lk)
and using the notation of equation(3)
<*(*)
=Ca.t>y
<*<>+.16
-apt
(15)
M)
-_jl
tjl\4ZE
y*
(16)
The plant response for the constant input k can be found
from equations
(5)
and(11)
X>jT
&-*
-h
L
^K
-m
<***>-
y(i<))
y-^^H!^
a
jf-a.
'tr./
_*.(-r) -hC*-*),E6^-%<E"(i-rJl
C4t
(-e)
=[*&)
+X,
(tP
-
A6]-6-*,)
(17)
<E^)
= -666h^+^}J>K~\^(E-,)
a.
b-a.
L
M.1
^ft-*')
(18)
Figure 2 shows the plant response obtained from equations
(15)
and(17)
where the constants have been chosen asa-l,
b-2,
K-2,
k-1,
and^
-1.
The desiredsteady
state output is
C(<x>)
-1,
Curve A showsthe
plant response when the input ramp is stopped and held constant at the instant it reaches the level required to maintain
j | , 1 i 1 l 1 1 | i | 1 |
'
i 1 I | 1 1 ' ' _,_ |_
_y ii
j
: j 1 1 i !'
L
1 i 1 | i i
| i | [
f~f
- - - 11 i
"
i i i i in 3-
y
4-'
| ; j J __ii_) l_
;i I ! i
1 '
I6eF~ _l -1- 111 _J_II r*
H
1
1 ! iH . E-^r3*-o
j-ii 1 i i +1 p-< * ' ;
'
~r co
\
| i
-o
4- --
r-t- -J- -t-
O
-4
6
1 i i i ,-.
1 ' '
^
Il
_,_...i
i. -": ^ ^ <
-4- . .
1
6
\
Ah ~^t- 4 > 3T 3t
\ '4-
-\ T
1
-1
o
1 U:
I
^ : ' !-0
CO w
\
1
V
'\
V
66
I
Er 3t333lL:iz
-A 4-4- -1-
-h-\
EHV
i o MV , , . \ ! i - ?*?,
,1
\
\ "3"H
\
1 Eh Oi\1
\
1\ 1 \
\ . 1
CVJ
\ \ I ' ' ' ' ' i
\
\
1 ' ' '1 M
\ \ ! 1 ! 1 ! | ,i K
N. v i'i . )
x \ | '
'
!
'
i . i i
p~> r^
\ \ ; i '
j i , i | i
M
\ VI i . i '
i ! rt.
\ \ 'III
""N- ' * '
*L x
^^">-
X 1v X. !
'**^s 1 > | <->
'
''S~^->J
|S^v '
i**"1**! ^^ """LEX: 1 ^"*^jj ' 1 '
^""^"-v
"*^
^^s. 1
_L_ _,_
'
F
S4
j_ 0^ . ^V ri 1 s J X-\ V '
|
Y 3 " 0in 0 *n
0
,_, rH O
Curve B shows
the
plant response when the input ramp is allowed to run on past
the
required steady statelevel.
This curve shows a considerable reduction in the error whichexists up until
the
time
the plant output reaches the desired
level.
Obviously
the steady state output is considerably greater than the desired output, so that the reduction
in error in the lower part of the response curve is more
than offset
by
the increase in error in the tipper portion of the curve. It is easy to see that Curve A with the associated large error is the best response possible if the
input signal is restricted to ramp and hold at the final
level.
The Improved response of the lower part of the curve could
be maintained if the input ramp for Curve B is switched,
at the appropriate
time,
from a positive to a negative slope and allowed to ramp back and hold at the final required
level.
The switchingtime,
T , must be carefullys
determined in order to prevent large overshoots in the
plant response. Figure
3
shows an input of thistype.
From Figure
3
r
fa
0tTc
"M^Sfifri-*),
rr<-**(J*-f)
<w>
(rryf)6-3S^|^3^ffip333:|33333E33^
Z I ZZZZZZZZZZ" "ZZZZ3 "ZZ" ZZZZZZZ31 1 1 1 I I I 1 I 1 . 1 111
1 I I 1
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Ml|
|
u u u izzzzzzzzz:zzzzz-=============
=========zzzzzz:zzzzzzzzz:
j
i i i 3 3i_ZZ_i| " i ~ | _ ZZ" " 3ZZZZZZZZ zzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz^zzppzzzzzzzzi::: zp_
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[
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[JZ-L-^iT-u666\
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SF^rr~Hi"- :zzzz ~zzEEEEEE^E^ffjff
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^ffi^^^^===========
_ _| |V| I
U^"sj
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-So-I ra En CM to Eh M EH EH Ph Eh3
Oi Eh PL, o M C5The
plant responses for this input will be defined asfollows
4lJ-,
/
JUL)
(20)
C^(t). and
C.,(t)
are givenby
equations(15)
and(16)
respectively.
C2(Ts,t)
and Cg(T ,t) can be found from equations(5)
and
(11).
-^C/CrJ+cXvh
*fSrO+"*Jm
-*(--!}) e,
-b
(-/<.)
(21)
*rfo)
-ir^
+ZEiWiC6)+6
(r6-p-(iH-6]
-*&-/z)
Mt-ix?)
e
C_(m,T_t)
and C,j(m,T ,t) are also found from equationsj s J 8
(5)
and(11).
b
J
Jr
(23)
iM^6\^y?F^y-P^6^f)
6zhkyr-p4ky-f)->fY(^P)
2
D.
Formulation of Integral-Square ErrorConsideration of the response curves shown in Figure 2 led
to the heuristic conclusion that an input such as that shown
in Figure
3
would appreciably reduce the response error. As stated earlier, ifthe
switching time is too large the response will exhibit a large overshoot.
Obviously,
the overshoot can be controlled
by
controllingT_.
Smaller values of T reduce overshoot and negative error, but allow theS
positive error in the lower part of the response curve to
increase.
The undesirability of an error is Independent of its alge
braic sign and we are primarily concerned with error magni
tude.
The larger the error, the more undesirable itbecomes.
The integral-square error is a performance index that
heavily
weights large errors of either sign. It will therefore serve
our purposes well, and the optimum value of T will be found
s
based on the ISE criterion.
The plant input signal is a ramp and some
finite
amount oftime is required for it to reach the level which will sus
tain the steady state output we want. In addition to
this,
the response of the plant to the applied control signal is
application of an input signal to the system, errors must be
accepted as
inevitable.
In any given system, the ramp rate A is fixed and determines
the length of time required for a given input level to be
reached. Until this level is reached, nothing can be done
to improve the plant response.
However,
from this point onin
time,
the system designer can control the. magnitude ofthe
error through the proper choice ofT_.
Therefore,
only sthe error in the interval -jr-- - - eo is considered. The P
error will be defined as
follows.
6)='^e^(^Jrrj-t)jr^^(^-f)
(25)
The ISE is then
iz^ld
J6?~
fi
oO'jih^y)^
+}*
We could procede
formally
to make the substitutions forthe error expressions, do the
integrations,
differentiatethe result with respect to T_ , and solve for
T
by
set-ting
-cp--0. This is a very formidable task and it isdesirable to reduce the labor as much as possible. In
spection of the first integral in equation
(26)
shows thatthe integrand is not a function of
Tg
and further thatTg
appears only in the upper limit of this integral.If the integration is performed and the result evaluated
at the
limits,
only the evaluation at the upper limit yieldsan expression
involving
T The next step in the procedure5
is differentiation with respect to
T_.
As a result ofdif-ferentiation,
the integral evaluated at the lower limitvanishes,
We know that the error at the end of one response interval
is identical to the error at the
beginning
of thefollowing
response interval.
e,
fas)
=e.
fat,
J77)
(27)
This means that the first integral evaluated at the upper
limit is equal in magnitude to
the
second Integral in equation
(26)
evaluated at its lowerlimit,
but the algebraicsigns of the two terms are opposite. These terms will can
cel and
therefore,
the entire first integral in equation(26)
ultimately vanishes,
It can be shown^that
by doing
the differentiationfirst,
the terms which will eventually cancel will be placed in
evidence at the
beginning
and can therefore be eliminated.Also,
the terms notinvolving
T will vanish.Therefore,
s
In order to insure that the first integral vanishes at the
outset, we will change the normal order of operations and
take the -w^
first.
d isLet:
77
1
<r
%.to**>r:)-tftftop+Jfr!M*
fri
fi
=
Let:
Zr
^76
--4^-f)4C^/z-f)-^(-r6eU^r6
-J/2-fi
+)iFs46K-t)J
T<r
-3&.
fabi1*-?
-f)
-
4(^t^
-^J-k^c^s6^7?
(29)
Let:
jrr,~#-&7j
y
^
/
__JUL
J7F-fi
=
-i4^~SjATyf)
+J-k46,rA^(30)
By
combining equations(28),
(29),
and(30),
and making useof equation
(27)
J7}
* * 7s
/7
J
'(3D
is
fi
The first integral has vanished as anticipated. Equation
(30)
can now be set equal to zero and solved forT_.
s
7~-J/t~ *
fy*(nv>*
y&*w*
=",
JT--J2.
E,
Derivation of theSwitching
EquationRefer to the integrands in equation
(32).
=
-1*1*4
c*y)
*
jt?
<4fcy)
(33
Similarly
<&&)
--*r7z%
(&)
+**<(>>**)
(3k)
Substituting
equations(33)
and(3*0
into equation(32)
and changing the order of the terms yields
-*)&,
fc
*)
y*
-a^j-fe
dj
fa-u,*)
a
^
fi
. co+J-k4'(-&)*
+$i*4
(,%*)*
(35)
Consider the first two integrals in equation
(35).
CQ(m,T ,t) can be expressed in terms of C2(T ,t),
plus some additional .terms.
See appendix. If this isdone,
it can be shown thatthese integrals reduce to
*66o-ir^&f6
Equation
(36)
shows that a particularly simple result isobtained if the ramp rate
A
Is unity. In any case,the
first two integrals reduce to
(36)
^LiL
-*MAJL
T
(37)
/2*lo /ZLfo
r
Evaluation of the remaining two integrals in equation
(35)
yields equations containing both algebraic and
transcenden-2
tal
terms.
The results for the integralInvolving
C0(T0,t)
c. s
are given in Tables 1 and
2,
Table3
gives the results for2,
the integral
involving
C,(m,T ,t). The entries in these tables are the coefficients of the terms appearing at theleft of each row. The numbers at the
top
of each column indicates the term in the derivation from which those particular coefficients came. As will be seen
later,
it iso
H
I
I
O
o
o
o
ty)
S
o
o
o
O
^> j in o
\
t
*
^
o
ty
MS
o
o
O
o
o
o
o
^3-o
^
H*
-I
O
o
o
o
o
o
o
o
o
w Eh tn EH O En
wv
>
^
k-1'ty
0)
^
^ty
1^7
7
w.
^ S^
1
V
*>
Ias
o
0
o
o
O
o
I
i
4-o
O
o
CO o
o
o
-S>o
o
u
o
O
ty
1
^3
i-i
t
-f-^
r
*.^
o4-o
o
i
i tyo
o
o
O
O
O
cc w EH tn EH 1 53 OEh o tn
^
\E
k>'ty
'ty
V
ty
>
'ty
several expressions which make up
the
coefficients of eachterm,
rather than combining them into onelong
expression,All of the letters appearing in
the
table entries which havenot previously been
defined,
are defined in the appendix.The final result from carrying out the indicated operations
in equation
(35)
is foundby
combining the coefficients oflike terms In Tables
1,
2.
and3,
and adding -tothis,
equation
(37).
We now have an equation with only one unknown,T_.
Solution of this equation yields the optimum value fors
T
The switching time equation is most easily solved
by
usinga digital computer. A general program would require that
all the symbols used in Tables
1,
2,
and3.
be expressedby
their definitions in terms of the plant and system varia
bles.
Then,
a statement must be includedin
the program forevaluation of each of these
terms.
This is generally notworth the effort unless a
lengthy
analysis to determine theeffect of variations in all the parameters is to be conducted,
A good procedure to follow is to construct tables similar to
Tables
1,
2,
and3,
and use a desk calculator to evaluateeach of the entries in the coefficient
tables.
As each extables.
These results are easily summarized to yield theswitching equation coefficients,
A simple program such as indicated
by
the flow chart inFigure
k
is sufficient to findT_.
The operator mustpro-vide the limits or the time interval to be searched for a
solution, the time
increment,
and the input step magnitude.The program evaluates the coefficients of each term in
the
equation.
Next,
the equation is evaluated for values oftime in the search range. The print out is the term co
efficients, the
time,
and the equation value for eachtime
value. It is not necessary to print out the coefficients,
but this information is helpful in
finding
errors.If the solution for T is in the range searched, the value s
of the equation will change sign between two successive
values of
time.
Initially,
it is suggested that rathercourse time increments be used.
Succeeding
print outs willindicate narrower and narrower ranges for the solution and
the time increments can be reduced accordingly until T is s
INPUT
Tg
(max,
min)AT0
m
CALCULATE
COEFFICIENTS
COEFFICIENTS
DO
3
J=^min,
TSmax
EVALUATE
SWITCHING EQN.
END
FIGURE
k
EX AMPLE PROBLEM
A.
Objective and Plant DescriptionIn order to illustrate the formulation and solution of the
switching equation, a specific example will be worked. Con
sider the second order plant described
by
equation(1).
Forthis example the plant gain is chosen as
K-2,
and the polesas S. =-l,-2. The plant input signal will be considered a
unit ramp.
B. Calculation of T s
Using
the values given above in equation(37)
we obtain***-
4-
mX-(38)
Evaluation of the coefficients in Tables
1,
2,
and3,
aregiven in Tables
k,
5.
and6.
Summarizing
the entries inTables
k
and5,
we getti-66
j*-
&<?)***+
[o-^-*-)*]*-*
+(&*+,
^
ty
4.
o
o
o
o
*1*
J
!
ty
o
o
o
^
'
ty
*K
^>
^s
4*<
%
)
o
ty
o
o
o
o
o
o
o
Tt
^
<^
1
i
M)
*k
O
o
o
o
o
o
o
o
o
CC
w
EH
1^
n
^
i
ty
ty
'ty
>
1ty
k^
ty
'ty
1ty
*>
Os
U
+
o
^>
o
o
o
1
1
ty
1
ty
o
c>
Q
OO O
1
0
o
^kc^
o
*-4-o
o
ty
r
ty
it
ty
o
o
1 Jr
ty
O
^
o
o
O
o
s cc w EH tn Eh 1 s O &H o tn V^5 kS 1
ty
?>
ty
'ty
ty
'ty
ks
v>
tn EH -H t-Q
1
^
o
I^
ty
ty
)
o
4
ty
5
4-ty
o Ph W o o o H EH of w o i-H Q4*
kQ>
C^)
o
o
o
ty
1
1
>
1
ty
<^>
^
O
g
M X u EH M 3= OO Ph o o H Eh Q . >ko
o
5.
ty
1
^
^>
o
o
<0
^)
3
1-3
W
1
VO
8
o
o
<^
o
o
*
^
^
9
<^
o
^>
O
o
Eh Q
k
o
^
1
^
c^
o
o
o
o
0
<o
5h 00 &i O h o tn K17 k^>
"ty
k^ty
k^ty
ty
*k^
ty
Jty
ty
k?
'ty
fc?
>
Collectlon
of coefficients inTable
6
yields-(ye
)e
'+(Te
)e
+(&+T&
~T&)e
_
(ff+
uT)e*+
[t*6
(? +,)*'"]
(gM+~f)^My
f
h^
+*f
-376
e
(ko)
The
switching equation is foundby
combining equations(38),
(39).
and(40).
i-i~-K
+
(^-e"+--)e~r
+26
-4*171
=
o
(*D
This equation can be solved for the optimum values of T for s
various step input magnitudes
by
use of the computer programpreviously described. Table
7
lists the optimumT_
valuess
TABLE
7
OPTIMUM SWITCHING
TIME
Step
AmplitudeSwitching
Time.0125 .141
.025 .201
.050 .290
.10 .423
.25 .711
..50
- 1.081
.75 1.^01
1.0
1,697
1.25
1.980I.50
2.253
J 1
tz
6
i
i i i
i_ !_ <
i i i i i
'
i [
I |
V ! .
.-\( l
\ i
\| |_
ZL... \T ~^
\
t
zt
\\
Is. i\
Z
3ZlZV
zrS3 ZlZ _J_ Zt Zt
\
X
zt |Z\
zt
$
zt\
\
\ \ \ \ ' \ \ v. \ A-y
X
Zt
^
Ar
-+--4- -4- Ay-
-h-V
1 1
\ \
1
\
: I 1 \ ' ! '
I ! Iii i
! \l
-4-Z3Z. Zf3 3V Z3Z .ZiZZt
-h-
6p
zt zt v zt izt
n~ ^ 6
^\
\ \ \ "" "i i i \
i *,
-L- ZT ZtZK Zt Zfl
- -\
\
._ "' ... \ \ .... -6 v ^ ^ \ . \ ... !\ ... \| \T
\
X
T
4^, i\3*4^
...-!.., ^*- M
o CO vo EH M CM o w J Eh ^ CO H En O M o EH M 3= 00 s M EH Ph O W
g
O M fc VA O* o CA CVI o CVJ vn o r-H VA OPlant response for the optimum switching time and for switch
ing
times greater than and less than the optimum are shown inFigure
6
for a unit stepinput.
Clearly,
the best response is obtained when the plant input is switched at t -Tg0.
Study
ofthe optimum response curve shows that peak overshoot has been
held to less than
3.5^.
The straight line plots in Figure6
are the plant inputs corresponding to the three response
curves.
Figure
7
shows the optimum plant response for several inputmagnitudes. In each case, the desired steady state output is equal in magnitude to the
input.
The ISE can be computed from the error equations
by
use ofthe trapezoidal rule.
(e
-[m-c(t)J,n
-1,2,3;
refer toequation
(20))
Evaluation of the ISEby
this method requiresonly a simple computer program. Table
8
gives the ISE versusswitching time for step inputs of
0.5
and1,
The table showsthat the minimum ISE does indeed occur at the value of T
s predicted
by
the switching equation(Refer
to Table7
forT_
optimum). Figure8
is a plot of Table8 data.
s
The ISE versus T plots in Figure
8
indicate that the ISEincreases much more rapidly for switching times greater than
i \ H y-_, L J_
I ' '
... m
~|
i i
i
6~
776
r Zl3r- 31 r i c~ ... " 776 Zt
zt
t
zt
zt
J3
ZZi
Zt 7 Zt
ZZ
I/
.~h~^~
6676E
EL 76 Zt Zt
^ yp-6
tt
li/
/
_lia_JL _u.l
_u _l_ i
TrpFl M -+- -t~
t>
l' , 1_^i_Sj__iL_iL_ _i_ _l_ ^_
A v
\
i/ ' l<s '
1
\
6
-t/ ^: ..'.
ll,r
i*
T
ErF\
\
FTkJ
|\ r
/ *>M'J !'V| lit.
'
\
k?
/
\
l1'/--4- 4- -4v-
-h--r
-f- +- -*ft^- -+-
-+-\ V \ 1 fA
\ (t "^
\
\
-*o
\
V\ \
\
^S>-*J \ |\
1 """"-"J. N
'
\l
| i _1-r^"^-^ \ 1
\
_^
r~*~"| ^"-kn^ xl
1 i~~>~-v^' ^v !
i ^""^i^ ^kj
- "-'^Uo^f ^"^k. "^**"*_
^^****-l
isT**--~~-_ _j_ ~^^ i_
""""- ~^
"
"""--Zt
""
""^
"^-" ^ ^
~"^-- _,_ ____ 2k
.^
+
-=^ -p^ .^ "s ---.. \ "j^. V^L '
"k^ V
----.^ j
^~-==.
1 1 1 1 , 1 1 1 II 1 1 1 1 1 II
ITkko
h-i EH VA VA CVJ VA O VA CVJ
'
1 1 1 1 1 1 1 TT 1 .ill | | p
-r-i 1 1 "
...
.
-00
1
...
I''-""' . , , .
^
1 1
OT
Z 3 _' Ztzt Pi>
--
r-& E>
"J O
-. * 1 Z " Zl3
g
S o Cu4 y- '-'- - 6P r?
4 - - _ _J_ _j_
7
-i ^ M y
Zt
J -j Zt _i_ ..it _^Z^Zl HB
4 4Z _l.
2
4 3ZZ ..
EH
1 cu
O
l\ :
V
3zL
_tzt
zt
_. ..\
1\ l nv n
\ \ 1 w
V 03
V. \ ^
v^ \ V
-o
zt
^^
%
3 ::-
ss
^ty
4-+
~~*~>is- v, \
^s
k
^^^
^
-f-^^vl **
\
^""^.^ \. \
2p=ik V
a>>*k
\i ^k. \ ^<^ V ^vj \ ^\ " " kk ri'V
^^ *s \s
V 3JZ\
ilp, vr\ O vn o in o
cvj cv vn oj .
H rH .
-. . q
TABLE 8
INTEGRAL-SQUARE
ERRORInput
Step
- 1T
s ISE
I.25
.4471.55
.3751.65
.3631.697
.3611.75
.3631.85
.3822.0 .454
2.125
.564Input
Step
-0.5
!s
ISE.5 .169
.75 .148 .90 .128
1.081 .115
1.20 .123
1.40 .192
ll I 1 1 1 1 I I i i i i i i i i i i i i i i i i i i i i i i rn i i i i i i i i i i i i i * . ^^ ^^.^ V ^N,,
.rfS^ , o
ZZ3 ZSL
^.r
.-A/ . . >!. f\l
E^ |
I N^
V-\ in
V
k
-T-^ _, ,_ _,_
Al_'-r-' Zt"
Zt V .
\
T H}.. . ., _ __ 1 .... ,_. _ T.m
1 '
J
r-7
Zt
EJL^
/
""k-t
P6
^kZ ^r^
'/ "N
-/
ik
/-
-$6>-^/
4^
-M-*. \/\ ''. '
N,
I 4 N,
/ \
7 s; vn
/ i \ cvj
y \ \ *-\ \ \ t-X
._ ._ .- C .. .... _ ... ,
T
-4-H ^ zt itt
^3k+
zt
X
t
16
L-,
-^
t
r^4P
-J-i-l--i,,l,i.l.., , III
caused
by
the rapid increase in overshoot for largervalues of
Tg,
Figures
9
and 10 are plots of the optimumpulse-width-modulator output and the resulting integrator output for
^1 43 fc Eh !=> O fc
1.5
1.0 Eh P-i M50-5
0.0 I T i | i 1 . ... | ^ . _ -y^1 1 1
' "* i
_| 1 1 1
zt
1 i i 1 ' , /l\.2 1 >.
/ S
Z
/ V.z V. 2
^^.
2 s 2 V Z^v
/T N.,/l X _j_
p jf / ~7 ~? 2 2 ^ ^ ^ I^Q&I L.ii7"
Z it
I
_ .1 2
3
TIME
FIGURE
9
- P. W. MODULATOR OUTPUT &PLANT
INPUTi_ I. i
'
i
i
u Zt Zl
| ;. I ; I
'ill!
,
f~
Eh
t
u Zt3
!
fc + I ,
B^
3 O
,n I ! _
a
="-|
-- " ' ' ' ~
j
fc " "
'y 't r\ r..'J .a
Y
6
/
**1 r-
y
\
/
\\^
^
v
"~> / Sy
z ^
^ ^
r> j/ ^
Cij 1 n ... S , \
5 l.U
-7
ri x
^ A
5
z fc <^-n r-. /* U.J/
2 ^ 2 2 2 ^^ 1+166 ^pij.e
2 n n Z
0 1 2
3
TIME
FIGURE 10 - P. W. MODULATOR OUTPUT & PLANT INPUT
CONCLUSION
This paper has presented a method for
finding
the optimumswitching time to minimize the integral-square error for
linear second order plants
having
real distinct roots. Certain types of industrial control systems have fixed elements
in the form of an
integrator,
and an element of this typehas been included in the analysis.
The data in Tables
1,
2,
and3,
together with equation(37),
provide the necessary Information to formulate the switching
equation. This equation is general and can be used to in
vestigate the effect on switching time of changes in system variables such as, integration rate and input step amplitude,
as well as changes in plant gain and poles.
The pulse-width-modulator in the system discussed in this
paper is required to respond in the optimum fashion for any
input amplitude. In
designing
the modulator, it istherefore
necessary to know the relationship between T_ and the input
step amplitude. This design information is provided
by
theswitching equation.
tolerated,
or at the veryleast,
is
highly
undesirable. Aworthwhile extension of this analysis would be to rederive
the switching equation to minimize the ISE under the
REFERENCES
1.
Schultz,
D.
G. , andMelsa,
J.
L. , State Functions andLinear Control Systems , McGraw-Hill Book
Company,
New
York,
1967
2.
Newton,
G. C, ,Gould,
L.
A.,
andKaiser,
J. F. ,Analytical Design of Linear Feedback Controls.
Wiley,
New
York,
1957
3.
Buck,
R.C,,
andBuck,
E. F. , Advanced Calculus.APPENDIX
A.
Derivation
ofC3(m,Ts,t)
in terms of C2(T,t)
From equation
(23)
-ttfa
&*&
+4
k
*-t)-*py
***?>
+
a.b
(Al)
The C2(Tg,2Ts-^)and
C2(TS,2TS-^)
terms in equation(Al)
willbe expressed in terms of
(^(Tg)
and^(T
).
Refer to equations(21)
and(22)
^y^rJ^/T^^O^^)]^^?'^
&--&te-f-*-Zr)
'
m[
*-(*-*+^
\c,fc)
+6(V)-^
O+'Tr)]**^^
+
K
>niE
_j
+l+
M
(m
)\
J-"
&&*-?)
HE
At, a.'
<*
\
at-/]
& r-M.
b
e,
(t?)
+
C,(rf)
--%r
(t**t)
e
+
B.yf-iy]e^-^P
-"/*-%)
<A2)
^
t
*rL\..
J
/_ M \h*Jlk~\
~*(-6 ^'s*#
J
a.
C,
0Sj
*Q-j)
1-t{%Jrrt-f)--f-\*
f
-16
i,
b
rt
4 (Tj
^4
fe)
-M-
(f+
&)]*
-b(t-K)
f-fintk
_
fik
MKfik
/(o+< )1 -bl-t'l's+T).
z~
*,b
h
b(irJJer
a
clfrJ*cl(T6-g(l^vj\e,'(*-v)
+
6
lh
~f
t,t-*1yt>(--J6TJ-)
M
**,&)+*,
ft)-
f-O-ri&l*
rb(-6
-ti)
Jr
Jl-r
h
(A3)
Substituting
equations(A2)
and(A3)
into equation(Al)
-f-+
b(y-*-)
hn$k
/Z-b
(A4)
Comparison of equation
(A4)
with equation(21)
shows thatthe
first two terms to the right of the equal sign inequation
(A4)
are equal to C.(T
,t)
?(t-2T
-~
)
c. S ^t S ^C-b
l6\e-*(P-Jp-+f-)
+&>[(t-0+\
h
yisk
a.
b
B. Evaluation of
EL
6
P
o^r- ^Tr^
Consider the first two integrals in equation
(35)
and replaceC_(m,T ,
t)
in the second Integralby
equation(A5).
3 s
OC?
^J^faJJk -J^Jjz^fa^J^
<&y-&y
fs
*v
-Mr
-3.ME
fik
\ji(b-^)l
tir-O**
W
(.
p
d
e
P
)
+JLM
k
\b(h-*)\_
(t")+t
oo
-Jz*
b+*\
.f"fik
y-e
JT?
<&bCombining
terms andsimplifying
in equation(Bl)
yields-*)&>&.*)
J*
Tc
cfi>
~^/v7
\6t-or]
\
!
i~M
1
y-t
OO
-h^M
(B2)
Notice that the upper limit on all
integrals,
including
theone
involving
C(T_,t),
is now Infinity. As a result,inte-c. S .
grands
involving
terms of the form & ' will vanish atthe
upperlimit.
Most of the integrands do contain terms ofthis
form.
Also,
it should be noted that the lower limit on(i.e,
constant with respect tothe
variable ofintegration)
Therefore,
evaluation of the integral at the lower limityields a constant which is just the positive reciprocal of
the coefficient of
the
exponent. Since we previously established that the integral vanishes at the upper
limit,
thisconstant is the value of the
integral.
For example:
rft-p)
. i(B3)
In
the
analysis thatfollows,
we willfrequently
encounterintegrals of the form of equation
(B3).
The above observations allow one to evaluate these integrals
by
inspection.
In order to complete the evaluation of equation
(B2).
C(T ,t)
y~ smust be expressed in terms of the system and plant parameters. This can be done
by following
the same procedure used inRefer to equation
(21)
ye,CT,)
+
i,(r,)-#(,+*v)y*('~7:J
-*6
,M./-7-.-^)
+--j6
,**_
_jK_
\
-*?
M.
fc-4$)
0*
/zr(/+*v)
or-*Hr
+
k
a>
L
jt
+
b
hJ7
4.L
b
L(kzS[e^
+
M
O^LAk
\. tbJ
)
&
* "*M6
-*(*-r6
^'
<5
M
OE
(i-a<z
)e
(B4)
[**l&j+'tM-$-o+n)y(*~vJ
=ee16^_i6.
\&-r*
,I6(r.^y\
+
?A-*i
6(b--)>&
+
b
(^
ir
]
+
Ml
a
-j~0^)]^^6
b-a.
U
bXJ
f
16
6
qrH
J_
_i
-r
I
rb&-%)
ab
+
"
b
S
6
yb(t-T,)*
e
60-^ir')e-li
(B5)
Substituting
equations(B4)
and(B5)
into equation (20)- weobtain
-
M
$(%*>
=z&
o-^>*
0-T<r I -& *
^-
(t-xe^)e-^
*Ywj
^6
L
^^
J
Taking
the partialderivative
yields^<v;
=j?^
-*
^
#-",/
*-(b-*)
(B6)
-f
UL-*-*>
(*-T?)
b(b-*>J
Using
equation(B7)
we get forthe
first integral inequation
(B2)
i
-2m
IjpCjT^)
Ji
ti
-
*+'&,(>*>*
p.
it-*))
e
&
Tf
fa
-4?- -fa^ -^JJL/'lIntegratlng
the
remaining terms in equation(B2)
yields'"hfebtf-'^l
+4-dzl"tt-'>*rt.
+
fl
(B9)
27^-J*~
P
Notice that four of the six integrals involved in
finding
equations
(B8)
and(B9)
are in the form of equation(B3).
Combining
the results of equations(B8)
and(B9)
and simplifying
we get'_-
-J
-jha6-
t
1
-1
)]
^
[*Y*-*J
aHb-*)
&(h-*)
lP
J\
fEw
p
_ _6
+
EpyP-
(-i--i)
+
+.
//)ab
*rf-oc.
fr-Af
}J*
-j
Ji
-)Ab-*
3-76 -H
*"6j
-f*TZ
X
^&JU-i
b-*--+(**-?-*)
0~b r
a.ip
4/^fik
^h
"^
/t\> a.b
T*
Therefore
XT'?
ti
iV-Vf
;
"
(B11)
C.
Evaluation
ofc?<r
From equation
(B6)
rif.16
%fc*J
=(>-**
')e
-a.*
PK
/,
~h*LA(6
O-b
-t-1%-b+t*'
cvb J
(Cl)
After squaring this expression, the next operation is differ
entiation with respect to T . Before squaring equation
(Cl)
5
it is convenient to redefine the coefficients so that the
terms containing T are grouped together
following
the squar-sing
operation.-4& -b*
(C2)
and
where:
From
these definitions
the coefficients in equation(C3)
become
aZ7i.
aAC .
flS,^4Lr(j(>+f7E)(i-3e
')
$flc
=jn
(4>+g6)
(/-^yV)
&>=
fO-AerT'f
38c
=j
rn
(r<i^r6
('-je
v)
d^yo^yT6
Performing
the
differentiation
we get
r<-.^77
=
j
rU-*(*f+py*r'-zaf7'^^
ttz-
47?
jF
(ane)
=4
n
(s
-z&f><z -.ap?-^
V
e^)
37?
(&)=-****(!-*
By
comparison withthe
definitions forA,
B,
and Ct'-S-ifiSi'*/'**/"
where ^
b^^
cz-b
a
jfik^
r-
A
**((,-*)
n
-~
h
(b-tz)
The definition of A shows that this term involves p and in
turn the definition of p shows that this term involves t .
These terms must be expanded before the integrations are
done.
Integration of equation
(C3)
results in some verylengthy
butotherwise straightforward algebra.
Only
enough of the algebraic steps to serve as check points have been retained in
Carrying
out the integration of equation(C3)
yields thefollowing
results.T<
rs
rr
-kfl^-ff-6*]
, El JL 4
J-M
/)
^T$r*+-fi
I
<***)***A
Er
AY/^~fi
7
6
J"
+3Lf(*feAV)
^e-^J-6
Tf
M_f<*U
=.
-Jire
(i-ae*
^-Z^Te
Xr
/EEL
a.
-f
^n^lf*^-^
/z6Tg <z
Tt
-OEh7
X%-"/fi
[_
O^If
77
, ..^^uj^-^-<ay\
=
-!&(<-(^)^-^V^
-3?*>
??-6L(fiJ
fi
<ZL<M +i)e/8
e
-J&V
y^
-fa?+'J
-6
=
iIte-*H-jr,^-Af
-^^-Mfsfg
r*HyI
"-a^p*
+3.VJ6,
-hjrf/a.
-m.^Ty^
ay/L
fi
-0676-<&
(C5)
JL&-fi
-y-t
T-J-(3fic)&
V~A
jr*
f
tt
/-r-J*1*
')je-'*S6
IPs
Ts
rV
= -6M.fr-^_b-syr6(efie
~JbTs -b^r
;
~t-bnf<
'/
EP6r-f
Lb:
+3.hgjo/
(e.fie
4
= _
^!$-(jr.(,^)e.^-b^y'")(a-r<s
.bTA/kp--MV
^
-<?
y
(-&
-2J,Tr &?&
b^
fabV-js
+i
)-e
-bTr/,^
V
(*&')
bV
--iE$(^T--(b^)-2b%)
-^
[y^v-
(i,M-*)y*-*
^~hv]<sf
f
\e
-hi?
-mjr-e-**
-_
0%
<
u
.-"
fi
"*
tzPH. ,
^-Tr
= -M'h-a*')*-Je^A
(r
=
6ir
'O^js*^*-**-***)
-*y
(,-*<?*)***
**
-**7F
-ha^O-*^)* <
&
-4
V
&
+
4-?*
&V
U^P^y*
J
tt
T-b+*
L
*T<
,bT
*e6iy-z(b*6e
l/l/l
tb+*-)TA\
Q**ty
-*((**.)?e
'e
-eb+*~
L
Jt/L
f
^
**
I
-a.l
-*rri&yi*-</-rftiIJze
-Fern
fat
b-t*>
M
pi
-gfn
<e(b+*Ji$
-(b+*)-%
"j_
y^*ji
yu
(4--^4
(-AH*F-V-)
ZLK
e,pA
-^fi
e,
r
^
'
o26J^ -jlcPf
/
&
-h
T^
(09)
Summation of equations
(C4)
thru(C9)
completes the evaluationof the integral. This summation is given in Tables 1 and 2 in
Oo
D.
Evaluation
ofFrom equation
(A4)
_2r
C?
(*j7Z,-6j
?7}~J6L
fi
M
k+d.+
fiK
\
/-L--lu-LXEa-(*-z77+y)_
J6E
yf-o+t\e
+
From equation
(B6)
-fik
/
J5i
-^#
^
e
-;^(-^tfn^(^-2rJ
(Dl)
Substituting
equation(B6)
into equation(A4)
and using equa tion(Dl)
we can writefi*
(b~"J
+
Mfik
(D2)
^z:(It
will be shown later that there is an advantage to this form forC_)
For the same reasons given in
the
last sectionfollowing
equation
(Cl),
it is advantageous to write the coefficientsof equation
(D2)
in a different form.By
doing
a slightamount of simplification in the coefficients,
the
following
ryf6(t-^FA^r^6]
r
4
J*lfL
r
-.
f
J
-6-3-6+
j-(D3)
and
Using
the definition
for ll> in equation(D4)
jzcifam)
-'fr-J-V+f-)
J-
/
.i-*6-3t+J6)+-E-A
^yy^-^fKM^)^'mtf)
4(b+*JD&
r
+~3=q@)
e
fi
y(D5)
The advantage of the form used for equation
(D2)
is now apparent. When equation
(D5)
isintegrated,
all of the integrals are of the form of equation
(B3)
and the integration00
/.
J
&
4
fay)
J*
s
fi
-
<//>r
i-7
fc
of)
i
j
+
?
+J-65-
(^f)
-* -J-
6.
ic*\
+^t
+JJ,
Jv
I*
/
^/D
+^i
(*0F)
(d6)
At this point it is convenient to redefine
D,
E,
andF,
inorder to separate those terms which contain T from
those
s
which do not.
D
4
J+f
By
comparison with the originaldefinitions
we see thatj
M
ril(b-tZj
{*/->)
i-S.
0
A
fi^
/
f
=7E6766 0-*e
)(e
a.-Pi-"-)
tQ,
,
6-(jt-26)
)
*
~-,t)
(*")
(*
b(7~-2Zr)
(/
)
-abT -*>%
=
W
(&
-zeJ
f~*b
j
V~
afi(^)
C
J
W
-fa)
b
re
fi
The only terms containing T are g and
j
.Having
identi-s
fled these
terms,
we may now proceed with the reduction ofequation
(D6).
, For the sake ofbrevity,
as inthe
last-section, some of the lengthier algebraic maneuvering has
DF*f(y+f)
fifi
+
a~k
(SDF)
34-\
a.
\2*J+b*J+r*
<) ? . ,^//
z'
-**7r
~aT-2>Ts
/ -3L#-Ir -an* I
J
/ _ r) .,!>//) -clL(D7)
\4-MF+6,^(3DF)
=tf*
(
J-
y
**'*)
F
-7
/
(J*f)
This expression is of the same form as DF.
By
analogy with
the
previous derivation we may write ,sff
+y
jps
(jiff)
=*u-^y^)
y
=(jt^y
=y63fy+?*
j
See the derivation of equation
(D7)
for/
<r)
JT
KJ
o
*
U.J.
*>?+&
(*?s+F)
=
1^-
{Jv e
~*
6
(a A
Wje*-J.
V*e***(D9)
EX=
(J>+jfi
This expression is of the same form as D .
By
analogy withthe previous derivation we may write
I
J-
J4*+li
jk(J
=
Jsft~6ylwe
6^.
+
fyJiA/+'Sw*)&
/-/
...A
-367r
dl
=(*fr$)
u+i
)
-Js+jJ
+f-s
+jj
++k
A
(&*)
=WiTi-tk^
(ft+jS+jt)
=
+0F
+
J.
6+a
^TrJP+^W+Tkap}
J&&--
= -3a.E7i
v
u-^u-
.yAr6
yk
QJ
-at,yw(e^-*-**)
&
O'fJ
t/J>E^
</jS++s&\f
(e^-Ae**)
+sJj
C^^-^-^)
+f/Mv(6*(*+"jTFa6(H+*)7;-je-^>b)T*
6.
*Jtr
+
(*'*)
Jb+&-\
-o6t:=
4U++M
(&)***<*<
(t)'
-**>
(W)***
+
j>*
te)
-(b+a.)
^
Summation
of equations(D7)
thru(Dll)
completes the evaluation
of theintegral.
This summation is given in Table3
in