R E S E A R C H
Open Access
Sums of finite products of Bernoulli
functions
Ravi P Agarwal
1, Dae San Kim
2, Taekyun Kim
3,4*and Jongkyum Kwon
5*Correspondence: tkkim@kw.ac.kr 3Department of Mathematics, Kwangwoon University, Seoul, 139-701, Republic of Korea 4Department of Mathematics, College of Science, Tianjin Polytechnic University, Tianjin, 300160, China
Full list of author information is available at the end of the article
Abstract
In this paper, we consider three types of functions given by sums of finite products of Bernoulli functions and derive their Fourier series expansions. In addition, we express each of them in terms of Bernoulli functions.
MSC: 11B68; 42A16
Keywords: Fourier series; sums of finite products of Bernoulli functions
1 Introduction
As is well known, theBernoulli polynomials Bm(x) are given by the generating function
t et– e
xt=
∞
m= Bm(x)
tm
m! (see [–]). (.)
Whenx= ,Bm=Bm() are called Bernoulli numbers. For any real numberx, we let
x=x– [x]∈[, ) (.)
denote the fractional part ofx.
Fourier series expansion of higher-order Bernoulli functions was treated in the recent paper []. Here we will consider the following three types of functions given by sums of finite products of Bernoulli functions and derive their Fourier series expansions. In addition, we will express each of them in terms of Bernoulli functions.
() αm(x) =c+c+···+cr=m,c,...,cr≥Bc(x)Bc(x)· · ·Bcr(x)(m≥);
() βm(x)=
c+c+···+cr=m,c,...,cr≥
c!c!···cr!Bc(x)Bc(x)· · ·Bcr(x)(m≥);
() γr,m(x) =c+c+···+cr=m,c,...,cr≥
cc···crBc(x)Bc(x)· · ·Bcr(x)(m≥r).
For elementary facts about Fourier analysis, the reader may refer to any book (for example, see [, ]).
As toβm(x), we note that the next polynomial identity follows immediately from
The-orems . and ., which is in turn derived from the Fourier series expansion ofβm(x):
c+c+···+cr=m
c!c!· · ·cr!
Bc(x)Bc(x)· · ·Bcr(x) =
rm++
m
j= rj–
j! m–j+Bj(x),
where
l=
max{,r–l}≤a≤r–
r a
c+c+···+ca=l+a–r
BcBc· · ·Bca
c!c!· · ·ca!
. (.)
The obvious polynomial identities can be derived also forαm(x) andγm(x) from
The-orems . and ., and TheThe-orems . and ., respectively. It is remarkable that from the Fourier series expansion of the function mk=–k(m–k)Bk(x)Bm–k(x) we can derive the
Faber-Pandharipande-Zagier identity (see [–]) and the Miki identity (see [–]).
2 The function
α
m(x)Letαm(x) =
c+c+···+cr=mBc(x)Bc(x)· · ·Bcr(x) (m≥). Here the sum runs over all
non-negative integersc,c, . . . ,crwithc+c+· · ·+cr=m(r≥). Then we will consider the
function
αm
x=
c+c+···+cr=m
Bc
xBc
x· · ·Bcr
x, (.)
defined on (–∞,∞), which is periodic with period . The Fourier series ofαm(x) is
∞
n=–∞
A(nm)eπinx, (.)
where
A(nm)=
αm
xe–πinxdx
=
αm(x)e–πinxdx. (.)
Before proceeding further, we need to observe the following.
αm(x) =
c+c+···+cr=m
cBc–(x)Bc(x)· · ·Bcr(x)
+· · ·+crBc(x)Bc(x)· · ·Bcr–(x)Bcr–(x)
=
c+c+···+cr=m,c≥
cBc–(x)Bc(x)· · ·Bcr(x)
+· · ·+
c+c+···+cr=m,cr≥
crBc–(x)Bc(x)· · ·Bcr(x)
= (m+r– )
c+c+···+cr=m–
Bc(x)Bc(x)· · ·Bcr(x)
= (m+r– )αm–(x). (.)
From this, we have
αm+(x) m+r
and
αm(x)dx=
m+r
αm+() –αm+()
. (.)
Form≥, we put
m=αm() –αm()
=
c+c+···+cr=m
Bc()Bc()· · ·Bcr() –BcBc· · ·Bcr
=
c+c+···+cr=m
(Bc+δ,c)· · ·(Bcr+δ,cr) –BcBc· · ·Bcr
=
≤a≤r a≥r–m
r a
c+c+···+ca=m+a–r
BcBc· · ·Bca–
c+c+···+cr=m
BcBc· · ·Bcr
=
max{,r–m}≤a≤r–
r a
c+c+···+ca=m+a–r
BcBc· · ·Bca, (.)
where we understand that, forr–m≤ anda= , the inner sum isδm,r.
Observe here that the sum over allc+c+· · ·+cr=mof any term withaofBceandb
ofδ,cf (≤e,f≤r,a+b=r), all give the same sum
c+c+···+cr=m
Bc· · ·Bcaδ,ca+· · ·δ,ca+b
=
c+c+···+ca=m+a–r
BcBc· · ·Bca, (.)
which is not an empty sum as long asm+a–r≥, i.e.,a≥r–m. Thus
αm() =αm() ⇐⇒ m= (.)
and
αm(x)dx=
m+rm+. (.)
Now, we are ready to determine the Fourier coefficientsA(nm).
Case :n= .
A(nm)=
αm(x)e–πinxdx
= –
πin αm(x)e –πinx
+ πin
αm(x)e–πinxdx
=m+r– πin A
(m–)
n –
πinm
=m+r– πin
m+r– πin A
(m–)
n –
πinm–
–
=(m+r– )
Let us recall the following facts about Bernoulli functionsBm(x):
(a) form≥,
integersmwithm= and discontinuous with jump discontinuities at integers for those
positive integersmwithm= .
Assume first thatmis a positive integer withm= . Thenαm() =αm(). Henceαm(x)
is piecewiseC∞and continuous. Thus the Fourier series ofαm(x) converges uniformly
We can now state our first result.
Theorem . For each positive integer l,we let
l=
Assume thatm= for a positive integer m.Then we have the following.
(a) c+c+···+cr=mBc(x)Bc(x)· · ·Bcr(x)has the Fourier series expansion
for allx∈R,where the convergence is uniform. (b)
piecewiseC∞and discontinuous with jump discontinuities at integers. The Fourier series ofαm(x) converges pointwise toαm(x) forx∈/Zand converges to
Now, we can state our second result.
Theorem . For each positive integer l,we let
l=
Assume thatm= for a positive integer m.Then we have the following.
(b)
defined on (–∞,∞), which is periodic with period . The Fourier series ofβm(x) is
∞
Before proceeding further, we need to observe the following.
βm(x) =
From this, we have
βm+(x) r
and
βm(x)dx=
r
βm+() –βm+()
. (.)
Let
m=βm() –βm()
=
c+c+···+cr=m
Bc()Bc()· · ·Bcr()
c!c!· · ·cr!
–
c+c+···+cr=m
BcBc· · ·Bcr
c!c!· · ·cr!
=
c+c+···+cr=m
(Bc+δ,c)(Bc+δ,c)· · ·(Bcr+δ,cr)
c!c!· · ·cr!
–
c+c+···+cr=m
BcBc· · ·Bcr
c!c!· · ·cr!
=
max{,r–m}≤a≤r–
r a
c+c+···+ca=m+a–r
BcBc· · ·Bca
c!c!· · ·ca!
, (.)
where we understand that, forr–m≤ anda= , the inner sum isδm,r.
Observe here that the sum over allc+c+· · ·+cr=mof any term withaofBceandb
ofδ,cf (≤e,f≤r,a+b=r), all give the same sum
c+c+···+cr=m
Bc· · ·Bcaδ,ca+· · ·δ,ca+b
c!c!· · ·cr!
=
c+c+···+ca=m+a–r
BcBc· · ·Bcr
c!c!· · ·cr!
, (.)
which is not an empty sum as long asm+a–r≥, i.e.,a≥r–m. Also, we have
βm() =βm() ⇔ m= (.)
and
βm(x)dx=
rm+. (.)
Now, we would like to determine the Fourier coefficientsB(nm).
Case :n= .
B(m)
n =
βm(x)e–πinxdx
= –
πin βm(x)e –πinx
+ πin
βm(x)e–πinxdx
= – πin
βm() –βm()
+ r
πin
= r
integersmwithm= and discontinuous with jump discontinuities at integers for those
positive integersmwithm= .
Assume first thatm= for a positive integerm. Thenβm() =βm(). Henceβm(x) is
piecewiseC∞and continuous. Thus the Fourier series ofβm(x) converges uniformly to
βm(x), and
Now, we can state our first result.
Theorem . For each positive integer l,we let
l=
(a) c+c+···+cr=mc
is piecewiseC∞and discontinuous with jump discontinuities at integers. Thus the Fourier series ofβm(x) converges pointwise toβm(x) forx∈/Zand converges to
Now, we can state our second result.
Theorem . For each positive integer l,let
l=
Assume thatm= for a positive integer m.Then we have the following.
(a)
Here the convergence is pointwise.
rm++
m
j= rj–
j! m–j+Bj
x
=
c+c+···+cr=m
c!c!· · ·cr!
BcBc· · ·Bcr+
m for x∈Z.
Here Bj(x)is the Bernoulli function.
4 The function
γ
r,m(x)Letγr,m(x) =
c+c+···+cr=m,c,...,cr≥cc···crBc(x)Bc(x)· · ·Bcr(x) (m≥r≥). Here the sum
is over all positive integersc,c, . . . ,crwithc+c+· · ·+cr=m.
γr,m(x) =
c+c+···+cr=m,c,...,cr≥
c· · ·cr
Bc–(x)Bc(x)· · ·Bcr(x)
+
c+c+···+cr=m,c,...,cr≥
cc· · ·cr
Bc(x)Bc–(x)· · ·Bcr(x)
+· · ·+
c+c+···+cr=m,c,...,cr≥ cc· · ·cr–
Bc(x)Bc(x)· · ·Bcr–(x)
=
c+···+cr=m–,c,...,cr≥ c· · ·cr
Bc(x)· · ·Bcr(x)
+
c+···+cr=m–,c,...,cr≥ c· · ·cr
Bc(x)· · ·Bcr(x)
+· · ·+
c+c+···+cr–=m–,c,...,cr–≥
cc· · ·cr–
Bc(x)· · ·Bcr–(x)
+
c+c+···+cr=m–,c,...,cr≥
cc· · ·cr–
Bc(x)· · ·Bcr(x)
=rγr–,m–(x) + (m– )γr,m–(x). (.)
Thus,
γr,m(x) =rγr–,m–(x) + (m– )γr,m–(x) (m≥r), (.)
withγr,r–(x) = .
Replacingmbym+ , we get
mγr,m(x) =γr,m+(x) –rγr–,m(x). (.)
Denotingγr,m(x)dxbyar,m, we have
ar,m= –
r
mar–,m+
m r,m+, (.)
where r,m=γr,m() –γr,m(). From the recurrence relation (.), we can easily show that
γr,m(x)dx= r–
j=
(–)j–(r)j–
r,m=γr,m() –γr,m()
=
c+c+···+cr=m,c,...,cr≥
Bc()· · ·Bcr()
c· · ·cr
–
c+c+···+cr=m,c,...,cr≥
Bc· · ·Bcr
c· · ·cr
=
c+c+···+cr=m,c,...,cr≥
(Bc+δ,c)· · ·(Bcr+δ,cr)
–
c+c+···+cr=m,c,...,cr≥
Bc· · ·Bcr
c· · ·cr
=
≤a≤r–
r a
c+c+···+ca=m+a–r,c,...,ca≥
BcBc· · ·Bca
cc· · ·ca
. (.)
Observe here that the sum over all positive integersc, . . . ,crsatisfyingc+c+· · ·+cr=
mof any term withaofBceandbofδ,cf (≤e,f≤r,a+b=r), all give the same sum
c+c+···+cr=m,c,...,ca≥
Bc· · ·Bcaδ,ca+· · ·δ,ca+b
cc· · ·cr
=
c+c+···+ca=m+a–r,c,...,ca≥
BcBc· · ·Bca
cc· · ·ca
, (.)
and that, asm+a–r≥a, there are no empty sums.
Here we note that, fora= , the inner sum isδm,rsince it corresponds to the sums
c+c+···+cr=m,c,...,cr≥
δ,cδ,c· · ·δ,cr
cc· · ·cr
. (.)
Also,γr,m() =γr,m()⇔ r,m= .
Now, we would like to consider the function
γr,m
x=
c+c+···+cr=m,c,...,cr≥ cc· · ·cr
Bc
xBc
x· · ·Bcr
x, (.)
defined on (–∞,∞), which is periodic with period . The Fourier series ofγr,m(x) is
∞
n=–∞
Cn(r,m)eπinx, (.)
where
Cn(r,m)=
γr,m
xe–πinxdx=
γr,m(x)e–πinxdx. (.)
Case :n= .
From this, we obtain
Also, we note that, forn= ,
Cn(,m)= m
Bm(x)e–πinxdx= –
(m– )!
(πin)m. (.)
Thus, forn= , (.) together with (.) determine allCn(r,m)recursively.
Case :n= .
C(r,m)=
γr,m(x)dx= r
j=
(–)j–(r)j–
mj r–j+,m+. (.)
γr,m(x) (m≥r≥) is piecewiseC∞. In addition,γr,m(x) is continuous for those
pos-itive integersr,mwith r,m= and discontinuous with jump discontinuities at integers
for those positive integersr,mwith r,m= .
Assume first that r,m= for some integersr,mwithm≥r≥. Thenγr,m() =γr,m().
Henceγr,m(x) is piecewiseC∞and continuous. Thus the Fourier series ofγm(x)
con-verges uniformly toγm(x), and
γm
x=C(r,m)+ ∞
n=–∞
n=
Cn(r,m)eπinx,
whereC(r,m)is given by (.), andCn(r,m), for eachn= , are determined by relations (.)
and (.).
Now, we are ready to state our first theorem.
Theorem . For all integers s,l,with l≥s≥,we let
s,l=
≤a≤s–
s a
c+···+ca=l+a–s,c,...,ca≥
Bc· · ·Bca
c· · ·ca
=δs,l+
≤a≤s–
s a
c+c+···+ca=l+a–s,c,...,ca≥
Bc· · ·Bca
c· · ·ca
. (.)
Assume that r,m= for some integers r,m with m≥r≥.Then we have the following.
c+c+···+cr=m,c,...,cr≥
c···crBc(x)· · ·Bcr(x)has the Fourier series expansion
c+c+···+cr=m,c,...,cr≥ c· · ·cr
Bc
x· · ·Bcr
x
=C(r,m)+ ∞
n=–∞,n=
C(nr,m)eπinx,
where C(r,m)=
r–
j=(–)j– (
r)j–
mj r–j+,m+,with C(,m)= ,and C (r,m)
n ,for each n= ,are
de-termined recursively from
Cn(r,m)=
m–r+
j=
r(m– )j– (πin)j C
(r–,m–j)
n –
m–r+
j=
(m– )j–
and
Cn(,m)= –(m– )!
(πin)m. (.)
Here the convergence is uniform.
Next, assume that r,m= for some integersr,mwithm≥r≥. Thenγr,m()=γr,m().
Henceγr,m(x) is piecewiseC∞and discontinuous with jump discontinuities at integers.
Then the Fourier series ofγr,m(x) converges pointwise toγr,m(x) forx∈/Zand
con-verges to
γr,m() +γr,m()
=γr,m() +
r,m
=
c+c+···+cr=m,c,...,cr≥
c· · ·cr
Bc· · ·Bcr+
r,m (.)
forx∈Z.
Now, we can state our second result.
Theorem . For all integers s,l with l≥s≥,we let
s,l=
≤a≤s–
s a
c+c+···+ca=l+a–s,c,...,ca≥
Bc· · ·Bca
c· · ·ca
=δs,l+
≤a≤s–
s a
c+c+···+ca=l+a–s,c,...,ca≥
Bc· · ·Bca
c· · ·ca
. (.)
Assume that r,m= for some integers r,m with m≥r≥.Let C(r,m),C (r,m)
n (n= )be
as in Theorem..Then we have the following.
C(r,m)+ ∞
n=–∞,n=
Cn(r,m)eπinx
=
⎧ ⎨ ⎩
c+c+···+cr=m,c,...,cr≥
c···crBc(x)· · ·Bcr(x) for x∈/Z,
c+c+···+cr=m,c,...,cr≥c···crBc· · ·Bcr+ r,m for x∈Z.
(.)
Acknowledgements
The third author is appointed as a chair professor at Tianjin Polytechnic University by Tianjin City in China from August 2015 to August 2019.
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
All authors contributed equally to the manuscript and typed, read, and approved the final manuscript.
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Received: 28 February 2017 Accepted: 29 July 2017 References
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