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Copyright1998 by the Genetics Society of America

Statistical Analysis of Half-Tetrads

Hongyu Zhao* and Terence P. Speed

*Department of Epidemiology and Public Health, Yale University School of Medicine, New Haven, Connecticut 06520

andDepartment of Statistics, University of California, Berkeley, California 94720

Manuscript received January 20, 1998 Accepted for publication May 18, 1998

ABSTRACT

Half-tetrads, where two meiotic products from a single meiosis are recovered together, arise in different forms in a variety of organisms. Closely related to ordered tetrads, half-tetrads yield information on chromatid interference, chiasma interference, and centromere positions. In this article, for different half-tetrad types and different marker configurations, we derive the relations between multilocus half-half-tetrad probabilities and multilocus ordered tetrad probabilities. These relations are used to obtain equality and inequality constraints among multilocus half-tetrad probabilities that are imposed by the assumption of no chromatid interference. We illustrate how to apply these results to study chiasma interference and to map centromeres using multilocus half-tetrad data.

H

ALF-TETRADS, where two meiotic products from heterozygous at the marker. When there is one crossover between centromere and the marker, there is equal a single meiosis are recovered together, arise in

different forms in a variety of organisms. The first well- chance of producing homozygous and heterozygous half-tetrads. In Figure 2, the mechanism of meiosis II (MII) studied half-tetrad data were attached-X chromosomes

in Drosophila (Beadle andEmerson1935;Welshons nondisjunctions is shown. Given no crossovers between centromere and a heterozygous marker, MII nondis-1955). Half-tetrads were also constructed using

au-tosomes in Drosophila (BaldminandChovnick1967). junction always results in homozygous half-tetrads, whereas a single crossover always results in heterozygous They have been used in the study of many other

organ-half-tetrads. For half-tetrads from MI nondisjunctions, isms, including maize (Rhoades andDempsey 1966),

the two strands were attached to different centromeres potatoes (Mendiburu and Peloquin 1979), leopard

during meiosis, whereas the two strands in half-tetrads frog (Volpe 1970), rainbow trout (Thorgaard et al.

from MII nondisjunctions were attached to the same 1983;Allendorfet al. 1986), salmonid fish (K. R.

John-centromere during meiosis. MI and MII nondisjunction

sonet al. 1987), catfish (Liuet al. 1992), and zebrafish

are not the only mechanisms that are responsible for (S. L. Johnsonet al. 1995). In mammals, half-tetrads

half-tetrads. For example, attached-X chromosomes in can be studied in the form of autosomal trisomies (

Mor-Drosophila are the result of a different mechanism (

Bea-tonet al. 1990;Shermanet al. 1991) and ovarian

terato-dle and Emerson 1935). In this article, we broadly mas (Ottet al. 1976;EppigandEicher1983;

Chakra-classify half-tetrads into two types: type I half-tetrads, in varti and Slaugenhaupt 1987; Chakravarti et al.

which no crossover between centromere and marker 1989;Dekaet al. 1990). However, the material required

always results in heterozygous half-tetrads, and type II of trisomies and teratomas is rare, and the

recombina-half-tetrads, in which no crossover always results in ho-tion pattern in meiosis that generates trisomies and

mozygous half-tetrads. On the basis of this classification, teratomas can differ from that in normal meiosis (

Sher-tetrads from MI nondisjunctions are type I

half-manet al. 1991, 1994;Lambet al. 1996).Cuiet al. (1992)

tetrads, and those from MII nondisjunctions are type II introduced one technique that uses the polymerase

tetrads. Attached-X chromosomes are type I half-chain reaction to analyze the products of meiosis I in

tetrad. Half-tetrads from fish are mostly type II half-tetrads. individual secondary oocytes. This method has been

Autosomal trisomies and ovarian teratomas can be of since used to map genetic markers in mice (Cuiet al.

either type. In addition, ovarian teratomas can result 1992) and cows (Jarrell et al. 1995).

from mechanisms other than MI or MII nondisjunctions Half-tetrads may arise from different mechanisms. In

(Surtiet al. 1990). Throughout this article, we also make Figure 1, we illustrate how meiosis I (MI)

nondisjunc-the assumptions that nondisjunc-the parental origin of nondisjunc-the half-tions lead to half-tetrads. It is easy to see that when there

tetrads is known and that phases are known in parents. is no crossover between centromere and a heterozygous

These assumptions are usually true for experimental marker, MI nondisjunction results in half-tetrads being

organisms, although human half-tetrad data are more complex and may not satisfy these assumptions. For either type I or type II half-tetrads, a further distinction Corresponding author: Hongyu Zhao, Department of Epidemiology

may be made when two or more markers are studied:

and Public Health, Yale University School of Medicine, 60 College

Street, New Haven, CT 06520. E-mail: [email protected] haplotype information can be either available (attached-X

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Figure1.—Diagram illus-trating nondisjunction dur-ing the first meiotic division. No crossover between the centromere and the marker always results in heterozy-gous half-tetrads. One cross-over between the centro-mere and the marker has equal chance of resulting in homozygous half-tetrads and heterozygous half-tetrads.

chromosomes in Drosophila) or unavailable. The two shons 1955); (2) when chromatid interference is ab-sent, chiasma interference can be detected with two loci types of tetrads are called type Ia and type IIa

half-tetrads when haplotype information is available and type and may be detected with just one locus if the locus is sufficiently far from the centromere; and (3) the posi-Ib and type Iposi-Ib half-tetrads when such information is

not available. tion of the centromere can be mapped.

Most studies on half-tetrads (Welshons 1955; Cote As with ordered and unordered tetrads, half-tetrads

are very valuable in studying crossovers during meiosis andEdwards1975;Ottet al. 1976;Chakravartiand Slaugenhaupt1987) used only three loci for the detec-because (1) chromatid interference and chiasma

inter-ference can be distinguished with half-tetrads (Wel- tion of chromatid interference and one locus for the

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mapping of centromeres. In the context of chromatid (Griffiths et al. 1996; Zhao and Speed 1998) using half-tetrad data.

interference, Zhaoet al. (1995a) andZhaoandSpeed

(1998) derived a set of linear equality and inequality We use the following notations in this article. Markers are denoted by script letters. For example, we use A constraints on the multilocus probabilities of unordered

and ordered tetrad patterns under the assumption of andBto denote markers. Alleles are denoted by italic letters. For example, A and a denote two alleles of no chromatid interference (NCI). These constraints can

be used to test the assumption of NCI and to order markerA. We use [X, Y, Z, W ] to denote the observed marker configuration for an ordered tetrad, where X markers. Risch and Lange (1983) and Zhao et al.

(1995b) fitted chiasma interference models to multilo- and Y are attached to one centromere and Z and W are attached to the other centromere. For example, [AB, cus unordered tetrad data. For half-tetrad data analysis,

Chakravarti et al. (1989) proposed two approaches Ab, aB, ab] represents an ordered tetrad with two strands carrying AB and Ab attached to one centromere and for multilocus analysis. One was to assume that there

are at most three chiasmata across the region under ge- two strands carrying aB and ab attached to the other centromere. For type Ia and IIa half-tetrads, two strands netic study. The other was to treat the proximal marker

as a pseudocentromere relative to the distal marker. are separated by a / . For half-tetrads from MII nondis-junctions, these two strands were attached to the same Because the first approach does not apply to tetrads with

more than three chiasmata and the second approach centromere during meiosis. For half-tetrads from MI nondisjunctions, these two strands were attached to dif-applies only in the absence of chiasma interference,

neither is completely satisfactory. Daet al. (1995) pre- ferent centromeres. For type Ib and IIb half-tetrads, genotypes at each marker are combined and separated sented an approach to analyzing two markers under

the assumptions of NCI and no chiasma interference. by ; in parentheses. For example, aB/Ab represents a half-tetrad with one strand bearing aB and the other Assuming complete chiasma interference, Tavoletti

et al. (1996) proposed a maximum likelihood method. strand bearing Ab, whereas (Aa; Bb) represents a

half-tetrad with genotype Aa at A and genotype Bb at B,

Lamb et al. (1997) followed Weinstein’s (1936)

ap-proach to inferring joint chiasma probabilities at the without knowing whether A and B are on the same strand or A and b are on the same strand.

four-strand stage. There is no assumption on the chi-asma process in this approach except that there are at most two chiasmata in each marker interval.

METHODS

In this article, we assume that when strands attached

to different centromeres during meiosis form a half- No chromatid interference (one marker):With one marker, haplotype information is irrelevant. We need tetrad, each of the two strands attached to the same

centromere has equal chance of being in the half-tetrad, consider only two types: type I and type II half-tetrads.

Type II half-tetrads: For a heterozygous markerAwith

and when strands attached to the same centromere

dur-ing meiosis form a half-tetrad, the two pairs have equal alleles A and a, there are three observed patterns: AA,

Aa, and aa. For MII nondisjunction, patterns AA and

chance of being in the half-tetrad. Under this

assump-tion, four nonsister chromatid pairs have the same aa are derived from ordered tetrads having first division

segregation (FDS) pattern [A, A, a, a]. Pattern Aa is chance of being observed in a half-tetrad from MI

non-disjunctions. For MII nondisjunctions, two sister chro- derived from ordered tetrads having second division segregation (SDS) pattern [A, a, A, a]. Under RRA, matid pairs have the same chance of being recovered.

This assumption is abbreviated as RRA (random recov- tetrads having FDS pattern should give rise to AA and

aa with the same probability. Tetrads having SDS pattern

ering assumption) in the following discussion.

Under RRA and the assumption of NCI, we derive can only give rise to Aa. Therefore, P(AA)5 P(aa) 5

P(FDS)/2 and P(Aa)5 P(SDS).

multilocus half-tetrad probabilities as functions of

multilocus ordered tetrad probabilities. These relations Type I half-tetrads: For MI nondisjunction, patterns AA

and aa can result only from SDS ordered tetrads. Pattern are then used to derive linear equality and inequality

constraints among multilocus half-tetrad probabilities Aa can result from both FDS and SDS tetrads. Under

RRA, SDS gives rise to AA, Aa, and aa with probability 1/4, imposed by NCI. The constraints can be used to test

NCI, order markers, and construct genetic maps under 1/2, and 1/4. Therefore, P(AA)5P(aa) 5P(SDS)/4

and P(Aa) 5 P(SDS)/2 1 P(FDS). This leads to the

a certain chiasma process model. We discuss one-marker

and two-marker cases in detail before presenting the inequality constraint for type I half-tetrads: P(Aa) $

P(AA)1 P(aa) 5 2 P(AA). This inequality constraint

general results for multiple markers. The four half-tetrad

types are discussed in the order of type IIa, IIb, Ia, and is imposed by RRA.

No chromatid interference (two markers, type IIa Ib half-tetrads, respectively.

Since only two of the four strands are recovered in a half-tetrads):For two markersAandB, with the parent undergoing nondisjunction carrying AB on one chro-half-tetrad, the original ordering of the four strands is

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Ab/Ab, AB/aB, AB/ab, Ab/aB, Ab/ab, aB/aB, aB/ab, and ab/ h0 5 I 3 p0 and h1 5 H 3 p1, where hi

1 5 (hi10, hi11,

ab. Under RRA, each of the following four pairs should h

i12)9, pi1t5(pi1t0, pi1t1, pi1t2)9,

have the same probability: AB/AB and ab/ab, AB/Ab and

aB/ab, Ab/Ab and aB/aB, and AB/aB and Ab/ab. These

four pairs plus Ab/aB and AB/ab lead to at most six distinct

I5

1 0 0

0 1 0

0 0 1

and H5

1 1⁄4 0

0 1⁄2 0

0 1⁄4 1

. probabilities for half-tetrads with two markers. Two

markersAandBmay be (1) on different chromosomes; (2) on the same chromosome but on different sides of

Therefore, there is a one-to-one correspondence be-the centromere; or (3) on be-the same chromosome and

tween the pi1ti2tand the hi1i2: p05I3h0and p15H 213 on the same side of the centromere. We consider these

h1. Because the pi1ti2tare nonnegative, RRA imposes the

three cases separately.

Two markers on different chromosomes: Let p and q denote constraint that H213h

1 $0.

It was shown in Zhao and Speed (1998) that the the probability of SDS at A and B, respectively. It is

inequality constraints imposed by NCI for ordered tet-easy to show that P(AB/AB)5 P(ab/ab)5P(Ab/Ab)5

rad probabilities are

P(aB/aB)5[(12p)(12q)]/4; P(AB/Ab)5P(aB/ab)5

q(12p)/2; P(AB/aB)5P(Ab/ab)5 p(1 2 q)/2; and

T21

1 p0$0 and T211p1 $0,

P(Ab/aB)5P(AB/ab)5pq/2. These four distinct

proba-bilities are determined by two parameters, p and q. where

Two markers on different sides of the centromere (A–CEN–B):

It was shown inZhaoandSpeed(1998) that there are at most five distinct probabilities for ordered tetrads when

T15

1 0 1⁄4

0 1 1⁄2

0 0 1⁄4

and T21 1 5

1 0 21

0 1 22

0 0 4

. two markers are on different sides of the centromere. The

corresponding five classes can be described as: (1) FDS

at bothAandBand parental ditype betweenAandB; Using these constraints for the p

i1ti2t, it can be shown that,

(2) FDS at bothAandBbut nonparental ditype between

under NCI, the hi1i2satisfy the following inequality

con-AandB; (3) FDS atAand SDS atB; (4) SDS atAand

straints: h00$h02, h01$2h02, h10$h12, 3h11$2h12, and FDS atB; and (5) SDS at both A and B. Denote the

2h12$h11. No equality constraints are imposed by NCI probabilities of these five classes by a, b, g, d, and ε;

among these six half-tetrad probabilities. the constraints imposed by NCI are the proportionality

Using constraints under NCI, we can distinguish dif-constraint P([AB, ab, AB, ab]):P([AB, ab, Ab, aB]):P([Ab,

ferent configurations for two markers: on different

chro-aB, Ab, aB])51:2:1, and the inequality constraintsa $

mosomes, on the same side, or on different sides of the bandg 1 d $2b. Under RRA, P(AB/AB)5P(ab/ab)5

centromere.ZhaoandSpeed(1998) discussed how to a/2, P(Ab/Ab)5 P(aB/aB) 5 b/2, P(AB/Ab)5 P(aB/

apply constraints imposed by NCI to order markers

us-ab)5 g/2, P(AB/aB)5P(Ab/ab)5 d/2, and P(Ab/aB)

ing ordered tetrads.

5 P(AB/ab) 5 ε/2. Therefore, there are five distinct

No chromatid interference (two markers, type IIb probabilities for type IIa half-tetrads when two markers

half-tetrads):For type IIb half-tetrads—because haplo-are on different sides of the centromere. The equality

type information is unavailable—two patterns, AB/ab constraint imposed by NCI is P(Ab/aB) 5 P(AB/ab).

and Ab/aB, which are distinguishable in type IIa half-The constraintsa $ bandg 1 d $2bfor ordered tetrads

tetrads, are no longer distinguishable. This leads to 9, imply similar constraints among half-tetrad probabilities.

instead of 10 distinguishable patterns: (AA; BB), (AA;

Two markers on the same side of the centromere (CEN–AB,

Bb), (AA; bb), (Aa; BB), (Aa; Bb), (Aa; bb), (aa; BB), (aa;

the case of CEN–BAcan be discussed similarly): There are Bb), and (aa; bb). Under RRA, the following four pairs

six distinct probabilities for ordered tetrads in this case. should have the same probability: (AA; BB) and (aa; These six types can be distinguished by whetherAshows bb), (AA; Bb) and (aa; Bb), (AA; bb) and (aa; BB), and FDS or SDS pattern and whetherAandBshow parental (Aa; BB) and (Aa; bb).

ditype (P), tetratype (T ), or nonparental ditype (N) . Two markers on different chromosomes: Because AB/ab Denote these types by (it

1it2), where it150 or 1 corre- and Ab/aB have the same probability when markers are sponds to FDS or SDS atA, and it

250, 1, or 2 corre- on different chromosomes, there is no loss of informa-sponds to P, T, or N betweenAandB. The probability tion under NCI compared to type IIa data. The probabil-of (it

1it2) is denoted by pit

1i2t. For half-tetrads, there are six ities are the same as type IIa half-tetrads.

distinct probabilities as well. Each of these six types can Two markers on different sides of the centromere (A–CEN–B):

be denoted by (i1i2), where i15 0 or 1 corresponding As above, AB/ab and Ab/aB have the same probability, toAbeing homozygous or heterozygous, and i250, 1, or and there is no loss of information under NCI compared 2 corresponding 0, 1, or 2 strands showing recombination to type IIa data. We arrive at the same probabilities and betweenA and B. These probabilities are denoted by constraints as those for type IIa half-tetrads. The only exception is that there is no longer the equality

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straint P(Ab/aB) 5 P(AB/ab) because these two types g/4 1 d/4 1 ε/8; and P(Ab/aB)5 b 1 g/4 1d/4 1 are not distinguishable for type IIb half-tetrads. ε/8. The equality constraints imposed by NCI are that

Two markers on the same side of the centromere (CEN–AB, the probabilities of AB/AB and ab/ab are equal to the

the case of CEN–BA can be discussed similarly): Unlike probabilities of Ab/Ab and aB/aB. Denote the

probabili-the above two cases, AB/ab and Ab/aB have different ties of these five classes by p1, p2, p3, p4, and p5. The probabilities for type IIa half-tetrads whenAandBare probabilitiesa, b,g, d, and εfor ordered tetrads can on the same side of the centromere. Thus, there is some be obtained from the pi, i 51, · · · , 5:

loss of information because AB/ab and Ab/aB cannot be

a 51⁄2(p12 p

22p312p5), distinguished. There are five, instead of six, distinct

probabilities. These five classes can be represented as b 51⁄2(p12 p

22p312p4), (0, i2), which corresponds toAbeing homozygous and

g 52(p3 2p1),

i250, 1, or 2 strands showing recombination between

A andB; and (1, i2), which corresponds to Abeing d 52(p22p1), heterozygous andBbeing homozygous (i250) or het- ε

54p1. erozygous (i25 1). Let ui1i2 denote the probability of

RRA imposes the constraints that the expressions on type (i1i2); we have u05I3p0and u15U3p1, where

the right-hand side of the above equations be nonnega-u05 (u00, u01, u02)9, u15(u10, u11)9,

tive. Because the inequality constraints among ordered tetrad probabilities imposed by NCI are a $ b and U5

0 1⁄2 0

1 1⁄2 1

, g 1 d $ 2b (Zhao and Speed 1998), the inequality

constraints among the pi imposed by NCI are p5 $ p4 and 3p21 3p3 $5p1 12p4.

and pit

1i2twas defined above as the probability of ordered

Two markers on the same side of the centromere (CEN–AB,

tetrad pattern (it

1it2).

the case of CEN–BA can be discussed similarly): There

Therefore, we can obtain only p10 1 p12 from the

are six distinct probabilities. Each of these six types is

ui1i2 but not the individual values of p10 and p12. The

denoted by (i1i2), where i1and i2 were defined in the inequality constraints on the pi1ti2t, imposed by NCI are

discussion of type IIa data. Denote the probability of

p00$p02, p01$2p02, p10$p12, and p11$2p12(Zhaoand half-tetrad pattern (i

1i2) by hIi1i2. The relations between

Speed1998). As long as p101p12$0 (i.e., u112u10$0)

the hI

i1i2and the pi1ti2tare h I

051⁄2I3p1and hI15H3p01 the inequalities involving the p1it

2are always satisfied by

1⁄2I3p1, where hI

i1, pi1t, I, and H are similarly defined as

setting p12to 0. Because the relations between the u0i2

for type IIa half-tetrads. RRA imposes the constraints and the p0i2are the same as the relations between the

that the pi1ti2tinferred from the h I

i1i2are nonnegative. The

h0i2and the p0i2, the constraints under NCI are u00$u02,

inequality constraints among the hI

i1i2 imposed by NCI

u01$ 2u02, and u11$ u10.

can be derived from the constraints among the pit 1i2t. It

No chromatid interference (two markers, type Ia

half-can be shown that these constraints are tetrads):For type Ia half-tetrads, the strands in the same

half-tetrad were not attached to the same centromere at the four-strand stage during meiosis. Under RRA, each of the four nonsister chromatid pairs has the same chance of being recovered in a half-tetrad. As for type

21 0 1 1 0 21

0 21 2 0 3 22

0 0 24 0 22 4

2 0 22 0 0 0

0 2 24 0 0 0

0 0 8 0 0 0

hI

00

hI

01

hI

02

hI

10

hI

11

hI

12

$

0 0 0 0 0 0

. IIa half-tetrads, there are 10 distinguishable types and

at most six distinct probabilities.

Two markers on different chromosomes: We also use p and

q to denote the probability of SDS at AandB. It can

No chromatid interference (two markers, type Ib half-be shown that P(AB/AB) 5 P(ab/ab) 5 P(Ab/Ab) 5

tetrads):As type IIb half-tetrads, because haplotype

in-P(aB/aB)5 pq/16, P(AB/Ab)5P(aB/ab)5 p(12q)/

formation is unavailable, patterns AB/ab and Ab/aB

can-41pq/8, P(AB/aB)5P(Ab/ab)5q(12p)/41pq/8,

not be distinguished. There are nine distinguishable and P(Ab/aB)5P(AB/ab)5(12p)(12q)/21p(12

patterns. Under RRA, the following four pairs of

pat-q)/41q(12p)/41pq/8. These four distinct

probabili-terns have the same probability: (AA; BB) and (aa; bb), ties are determined by two parameters, p and q.

(AA; Bb) and (aa; Bb), (AA; bb) and (aa; BB), and (Aa;

Two markers on different sides of the centromere (A–CEN–B):

BB) and (Aa; bb). Therefore, there are at most five

There are five classes, each with a distinct probability.

distinct probabilities for type Ib half-tetrads. Using the same notations as in the discussion of type

Two markers on different chromosomes: Because AB/ab and

IIa half-tetrads to define the probabilities of these five

Ab/aB have the same probability, there is no loss of

infor-classes, we have P(AB/AB) 5 P(ab/ab)5 P(Ab/Ab) 5

mation under NCI compared to type Ia data. The

probabil-P(aB/aB)5 ε/16; P(AB/Ab)5 P(aB/ab)5 d/41ε/8;

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Two markers on different sides of the centromere (A–CEN–B): denoted by 0, 1, 2, and 3, respectively, at each marker Ar. The pattern (i1i2. . . in) of each type IIa half-tetrad

Since P(AB/ab) and P(Ab/aB), in general, are different

for type Ia half-tetrads, there is information loss in type is thus defined with ir 5 0, 1, 2, and 3, respectively.

Because two strands in a half-tetrad are not labeled, we Ib half-tetrads compared to type Ia half-tetrads. There

are four distinct probabilities. Because P(AB/ab) 1 can evenly divide the cases by two different labelings of the two strands. The results in the following discussion

P(Ab/aB)5 a 1 b 1 g/21 d/21ε/4, ordered tetrad

probabilitiesa and b cannot be uniquely determined hold under this even division.

There are 233n21distinct probabilities for ordered from type Ib half-tetrad probabilities. Both linear

in-equality constraints, a $ b and g 1 d $ 2b, can be tetrad data under NCI. These different ordered tetrad classes are denoted by (it

1it2. . . itn), where it150 or 1 satisfied by settingbto be 0. The only constraints imposed

by NCI are the equality constraints that the probabilities corresponding to FDS or SDS at A1, and it

r50, 1,

or 2, r5 2, . . . , n, corresponding to parental ditype, of AB/AB and ab/ab are equal to the probabilities of

Ab/Ab and aB/aB. tetratype, and nonparental ditype between Ar21 and

Ar. Let pit

1i2t...intbe the probability of type (i t

1it2 . . . itn). In

Two markers on the same side of the centromere (CEN–AB,

the case of CEN–BAcan be discussed similarly): There are the following, we derive the relations between type IIa

five different classes with distinct probabilities. These half-tetrad probabilities, the hi

1i2...in, and ordered tetrad

five classes are denoted by (i1i2), where i1 and i2 were probabilities, the p

it

1i2t...int. For one marker,

defined in the discussion of type IIb data. Let uI

i1i2denote

the probability of pattern (i1i2). It can be shown that uI

05 1⁄2I3 p1and uI1 5 U3 p0 1 1⁄2U3 p1, where uI0, uI1, U and the p

it

1i2tare similarly defined as in the

discus-

h0 h1 h2 h3

5

1⁄2 0

0 1⁄2 0 1⁄2 1⁄2 0

   p0 p1   5C1

   p0 p1   .

sion of type IIb half-tetrads. From the uI

i1i2, we cannot uniquely determine p00and

p02. Only the sum of p00and p02 can be inferred, and For two markersA

1andA2, we consider four patterns we denote it by p*00. It is easy to show the following: atA

1separately. If the pattern atA1is A1/A1, parental ditype betweenA1 andA2 will result in A2/A2 at A2, tetratype betweenA1andA2will result in A2/a2or a2/

A2 at A2 with the same probability, and nonparental ditype betweenA1andA2will result in a2/a2atA2. If

p *00

p01 p10 p11 p12

5

21 0 21 21 1

0 21 0 2 0

2 0 0 0 0

0 2 0 0 0

0 0 2 0 0

uI 00 uI 01 uI 02 uI 10 uI 11

.

the pattern atA1is a1/a1, parental ditype betweenA1 andA2will result in a2/a2atA2, tetratype betweenA1 andA2will result in A2/a2or a2/A2atA2with the same The constraints imposed by RRA are that the pit

1i2tin- probability, and nonparental ditype between A1 and ferred from the ui1i2 being nonnegative. We can also A2 will result in A2/A2 at A2. If the pattern at A1is

A1/a1, under NCI, there is equal chance that the four-derive the inequality constraints imposed by NCI from

strand bundle during meiosis has configuration [A1,a1; the above relations.

A1,a1], [A1,a1; a1,A1], [a1,A1; A1,a1], or [a1,A1; a1,A1]. There-No chromatid interference (multiple markers on the

fore, parental ditype betweenA1andA2will result in same side of the centromere): For n markers in the

A2/a2at A2, tetratype between A1 and A2 will have order of CEN–A1–A2– · · · –An, there are 2n21(2n11)

the same probability resulting in A2/A2, A2/a2, a2/A2, or distinguishable patterns (appendix,Proposition 1) for

a2/a2 at A2, and nonparental ditype betweenA1and both type Ia and type IIa half-tetrads. For type Ib and

A2will result in a2/A2atA2. The case that the type at type IIb half-tetrads, there are three possible patterns

A1being a1/A1can be considered similarly. Therefore, at each marker: ArAr, Arar, and arar. Therefore, there

are 3ndistinguishable patterns for type Ib and type IIb

half-tetrads. Under RRA, the number of distinct proba-bilities is at most 4n21 1 2n21 (appendix, Proposition

h00 h01 A h33

5

1⁄2X0 0X0

0X1 1⁄2X1 0X2 1⁄2X2 1⁄2X3 0X3

p00 p01 A p12

, 2) for type Ia and type IIa half-tetrads. Among the 3n

distinguishable patterns for type Ib and type IIb half-tetrads, there are at most (3n11)/2 distinct

probabili-ties (appendix,Proposition 3). where

Type IIa half-tetrads: To simplify the derivation of the

general results for n markers, we proceed differently from the discussion of the one- and two-marker cases.

We first assume that the two strands have already been X05

1 0 0

0 1⁄2 0 0 1⁄2 0

0 0 1

, X15

0 1⁄4 0 1 1⁄4 0 0 1⁄4 1 0 1⁄4 0

, labeled and are thus distinguishable. Then there are

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shown in Zhao andSpeed (1998) that the inequality constraints for ordered tetrads are

X25

0 1⁄4 0 0 1⁄4 1 1 1⁄4 0 0 1⁄4 0

, X35

0 0 1

0 1⁄2 0 0 1⁄2 0

1 0 0

. T21

n21p0$ 0 and T2n211p1 $0,

where T1 and T21

1 were defined in (1) and T2n211 5 T21^(n21)

1 . The operator^is the standard tensor product For an arbitrary n, the probability hi1i 2...inof the type IIa

(see, e.g.,Bellman1970). Therefore, the inequality con-half-tetrad pattern (i1i2. . . in) can be expressed in terms

straints among the hi1i2...incan be established. A likelihood

of the pi1tit2...itnas

ratio test can be used to test these constraints; seeZhao

hi1i2...in5

o

i1ti2t...itn

ci1i2...in i1ti2t...intpi

t

1i2t...int. et al. (1995a).

Type IIb half-tetrads: For type IIb half-tetrads, there are

three patterns at each marker. These three patterns are Write the ci1i2...in

i1ti2t...intinto a matrix Cnsuch that the columns

denoted by 0, 1, and 2, corresponding to observing 0, are labeled by it

1it2. . . itn and the rows are labeled by

1, and 2 copies of allele AratAr, r 5 1, · · · , n. The

i1i2. . . in, each in lexicographical order. It can be shown

probability for each type (i1i2. . . in) can be expressed

that (appendix,Theorem 1) the 4r113(233r) matrix

in terms of the ordered tetrad probabilities pit 1i2t...intas

Cr115(c

i1i2...irir11 it

1i2t...irtirt11) can be obtained recursively by

replac-ing each ci1i2...ir it

1i2t...irt

in Cr 5 (c i1i2...ir it

1i2t...irt) by the 4 3 3 matrix ui1i2...in5

o

it

1i2t...int ai1i2...in

it 1i2t...intpi

t 1i2t...int. ci1i2...ir

it 1i2t...irtXir.

Because the probabilities hi1...in can be expressed in Write the a i1i2...in it

1i2t...int into a matrix such that the columns

terms of the pit

1...int through the matrix Cn, for two identi- are labeled by it1it2. . . itn and the rows are labeled by

i1i2. . . in, each in lexicographical order. It is easy to see

cal rows in Cn, the corresponding half-tetrad patterns

should have the same probability. Note that some of these equalities are the result of RRA and they can be

readily identified. Equality constraints under NCI can A 15

1⁄2 0

0 1 1⁄2 0

. be established by removing these equality constraints

resulting from RRA.

The inequality constraints can be established as fol- Define lows. Define

D15 

1 0 0 1

0 1 1 0

 

, E05

1 0 0

0 1 0

0 0 1

, E15

0 1 4 0 1 1

2 1 0 1

4 0

, E25

0 0 1

0 1 0

1 0 0

;

then the matrix Ar11 5 (a

i1i2...irir11 it

1i2t...irtirt11) can be obtained by

Y05

1 0 0 0

0 1 1 0

0 0 0 1

, Y1 5

21⁄2 1 0 21⁄2

2 0 0 2

21⁄2 0 1 21⁄2

,

replacing each ai1i2...ir it

1i2t...irtin Arby the 333 matrix a i1i2...ir it

1i2t...irtEir.

In the discussion of two-marker data, it was noted that

p00and p02cannot be determined from the ui1i2. Similarly

in the n marker case, not all the pit

1i2t...intcan be recovered

Y25

21⁄2 0 1 21⁄2

2 0 0 2

21

2 1 0 21⁄2

, Y35

0 0 0 1

0 1 1 0

1 0 0 0

. from the u

i1i2...in. Equality constraints can be established

as in the discussion of type IIa half-tetrads. To establish inequality constraints, define

The matrix Dr115(ci

t 1it2...itritr11

i1i2...irir11) is defined recursively from

Dr5(d it

1it2...itr

i1i2...ir ) by replacing each d it1it2...itr

i1i2...ir in Drby the 334

B15

  

1 0 1

0 1 0

  ,

matrix dit1it2...itr

i1i2...ir Yir. From the facts that

D1C15 

 1 0 0 1   

F05

1 0 0

0 1 0

0 0 1

, F15

21 1 21 2 0 2

0 0 0

, F25

0 0 1

0 1 0

1 0 0

. and YiXi5 I333for i50, 1, 2, and 3, it is easy to show

that

The matrix Br11 5 (b

i1tit2...itri t r11

i1i2...irir11) is defined by replacing

each bi

t 1it2...itr

i1i2...ir in Br 5 (b it1it2...itr

i1i2...ir) by the 3 3 3 matrix

DnCn5   

I3n2133n21 0

0 I3n2133n21   .

bit1it2...itr

i1i2...irFir. It can be shown that RRA imposes the

con-So the p0it

2...int and p1i2t...int can be recovered from the straints that p 5 Fnu $ 0, and NCI imposes the

con-straints that T21

n p5 T2n1Fnu$ 0.

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Type Ia half-tetrads: For type Ia half-tetrads, let hI

i1i2...in have been labeled. Any type IIa half-tetrad pattern can

be represented by ij5(i1i2. . . in; j1j2. . . jm), where each

and pit

1i2t...itn denote the half-tetrad and ordered tetrad

ik(k5 1, · · · , n) or jl(l 51, · · · , m) is 0, 1, 2, or 3.

probabilities. The relations between the hI

i1i2...inand the

The probability of this half-tetrad pattern is denoted by

pit

1i2t...intcan be expressed as h

(i1i2...in;j1j2...jm). If the centromere were observable, ordered

tetrad pattern could be represented by itjt 5 (it

1it2. . .

hI

i1i2...in5

o

it

1i2t...int

ci1i2...in it

1i2t...intpi t 1i2t...int.

it

n;jt1jt2. . . jtm), where each itk( jtl) is 0, 1, or 2,

correspond-ing to parental ditype, tetratype, or nonparental ditype Write theci1i2...in

it

1i2t...intinto a matrixCnsuch that the columns

between Ak21 andAk(Bl21andBl). Both A0andB0 are labeled by it

1it2. . . itn and the rows are labeled by

correspond to CEN. The hijcan be expressed in terms i1i2 . . . in, each in lexicographical order. Using

argu-of the pitjtas

ments similar to those used in the proof of type IIa half-tetrads in theappendix,it can be shown that

hij5

o

gijitjtpitjt.

It is shown in theappendix(Theorem 2) that

gijitjt5

o

it

1,jt1

vi1j1 it

1j1tq i itqjjt,

C15

0 1⁄4 1⁄2 1⁄4

1⁄2 1⁄4

0 1⁄4

where vi1j1

it

1j1t is the element in the (i1j1)th row and the

and that the matrix Cr11 5 (c

i1i2...irir11 it

1i2t...irtirt11) is obtained by (i t

1jt1)th column of the following matrix: replacing each ci1i2...ir

it

1i2t...irt in Cr by the 4 3 3 matrix

ci1i2...ir it

1i2t...irtXir, where X1, X2, X3, and X4 were defined in the

discussion of type IIa half-tetrads. Linear equality and inequality constraints imposed by RRA and NCI can be similarly established.

Type Ib half-tetrads: For type Ib half-tetrad data, the

relations between the uI

i1i2...inand the pi1ti2t...int can be

ex-pressed as

uI

i1i2...in5

o

i1ti2t...int

φi1i2...in it

1i2t...intpi t 1i2t...int.

(00) (01) (02) (10) (11) (12) (20) (21) (22)

(00) 1⁄2 0 0 0 0 0 0 0 1⁄2

(01) 0 1⁄4 0 0 0 0 0 1⁄4 0 (02) 0 1⁄4 0 0 0 0 0 1⁄4 0 (03) 0 0 1⁄2 0 0 0 1⁄2 0 0 (10) 0 0 0 1⁄4 0 1⁄4 0 0 0

(11) 0 0 0 0 1⁄4 0 0 0 0

(12) 0 0 0 0 1⁄4 0 0 0 0

(13) 0 0 0 1⁄4 0 1⁄4 0 0 0 (20) 0 0 0 1⁄4 0 1⁄4 0 0 0

(21) 0 0 0 0 1⁄4 0 0 0 0

(22) 0 0 0 0 1⁄4 0 0 0 0

(23) 0 0 0 1⁄4 0 1⁄4 0 0 0 (30) 0 0 1⁄2 0 0 0 1⁄2 0 0 (31) 0 1⁄4 0 0 0 0 0 1⁄4 0 (32) 0 1⁄4 0 0 0 0 0 1⁄4 0

(33) 1⁄2 0 0 0 0 0 0 0 1⁄2

Write theφi1i2...in it

1i2t...intinto a matrix such that the columns are

labeled by it

1it2. . . itnand the rows are labeled by i1i2. . . in,

each in lexicographical order. It can be shown that

F15

0 1 4 1 1

2 0 1

4

and that the matrix Fr11 5 (φ

i1i2...irir11

i1ti2t...irtirt11) is obtained by

replacing eachφi1i2...ir it

1i2t...irtinFrby the 33 3 matrixφ i1i2...ir it

1i2t...irtEir Write the coefficients q i it5 q

i1i2...in

it

1i2t...int into a matrix Qnsuch

where E0, E1, and E2 were defined in the discussion of that the columns are labeled by it

1it2...itn and the rows

type IIb half-tetrads. The linear equality and inequality are labeled by i1i2...in, each in lexicographical order. As

constraints under RRA and NCI can be established simi- in the derivation of Theorem 1 (appendix), it can be larly to those for type IIb half-tetrads. shown that

No chromatid interference (multiple markers on different sides of the centromere): Consider markers on different sides of the centromere in the order of

Bm– · · · –B1–CEN–A1– · · · –An. Here we show only Q15

1 0 0

0 1⁄2 0

0 1⁄2 0

0 0 1

the relations between type IIa and type IIb half-tetrad probabilities and ordered tetrad probabilities. Con-straints imposed by RRA and NCI can be derived using

and that the matrix Qr115 (q

i1i2...irir11 it

1i2t...irtirt11) is obtained by

re-these relations following the approach described above.

placing each qi1i2...ir it

1i2t...irtby the the 433 matrix q i1i2...ir it

1i2t...irtXir, where

Derivations for type Ia and type Ib half-tetrads are

simi-X0, X1, X2, and X3were defined in the discussion of type lar, and we omit the details here.

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centromere. The coefficients qjjt5q j1j2...jm jt

1j2t...jmtare defined the between this marker and the centromere can be easily

derived. same as qi

it5qi1i2...in it

1i2t...int.

A crossover process model is needed for multilocus

Type IIb half-tetrads: As for type IIa half-tetrads, the

analysis. Different models have been proposed in the liter-probability uijfor type IIb half-tetrad pattern ij5 (i1i2

ature to model the crossover process (McPeekandSpeed . . . in;j1j2. . . jm), where each ikor jlis 0, 1, or 2, can be

1995). Among them, the chi-square model was found to expressed in terms of the pitjtas

provide better fit to data from different organisms (Zhao

et al. 1995b).

uij5

o

f

ij itjtpitjt.

The chi-square model, which was first introduced by It can be shown that Fisheret al. (1947), was suggested as a plausible biological model byFosset al. (1993). The model, which is

repre-fijitjt5

o

it

1,jt1

wi1j1 it

1j1ts i

itsjjt,

sented as Cx(Co)m, assumes that the crossover

intermedi-ates, C events, are randomly distributed along the four-where wi1j1

it

1j1t is the element in the (i1j1)th row and the strand bundle, and every intermediate resolves either as

(it

1jt1)th column of the following matrix:

a crossover (Cx) or not (Co). When an intermediate re-solves as a Cx, the next m intermediates must resolve as a

Co, and after m Co’s the next intermediate must resolve

as a Cx. The process is made stationary by letting the leftmost crossover intermediate have the same chance of being one of Cx(Co)m. The chi-square model has recently

been generalized to a more general class, the Poisson-skip (00) (01) (02) (10) (11) (12) (20) (21) (22)

(00) 1⁄2 0 0 0 0 0 0 0 1⁄2

(01) 0 1⁄2 0 0 0 0 0 1⁄2 0

(02) 0 0 1⁄2 0 0 0 1⁄2 0 0

(10) 0 0 0 1⁄2 0 1⁄2 0 0 0

(11) 0 0 0 0 1 0 0 0 0

(12) 0 0 0 1⁄2 0 1⁄2 0 0 0

(20) 0 0 1⁄2 0 0 0 1⁄2 0 0

(21) 0 1⁄2 0 0 0 0 0 1⁄2 0

(22) 1⁄2 0 0 0 0 0 0 0 1⁄2

model (Lange et al. 1997). Both the chi-square model and the Poisson-skip model lead to closed-form expression for the probability of any ordered tetrad pattern. This gives a rather flexible and tractable class of models for genetic linkage analysis. Note that the Poisson model is a special case of the chi-square model.

For an arbitrary number of markers on the same side Write the si1i2...in

it

1i2t...intinto a matrix Sn, then or different sides of the centromere,Zhao andSpeed (1998) derived general closed-form expressions for or-dered tetrad probabilities under the Cx(Co)m model.

Using these results and the relations we derived between S1 5

1 0 0

0 1 0

0 0 1

,

half-tetrad probabilities and ordered tetrad probabili-ties, we can evaluate any half-tetrad probability. There-fore, maximum likelihood estimates of the interference and Sr11is obtained by replacing each s

i1i2...ir

i1ti2t...irtin Srby the

parameter m and the genetic distances among the mark-3 3 3 matrix si1i2...ir

i1ti2t...irtEir, where E0, E1, E2, and E3 were ers and the centromere are tractable under this class

defined in the discussion of type IIb half-tetrads for

of models. markers on the same side of the centromere. The

coef-ficients sjjt5 s j1j2...jm

j1tj2t...jmt are defined the same as s i

it5si1i2...in i1ti2t...itn.

RESULTS

Multilocus genetic mapping:In the studies of ordered tetrads,ZhaoandSpeed(1998) compared various map

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TABLE 1

Observed and expected counts of six different half-tetrad types of alfalfa progeny

Expected

Group Genotypes Observed Cx CxCo Cx(Co)2

1 AAA1BBB 94 96 94 92

2 AAH1BBH 30 26 28 30

3 HHA1HHB 1 1 1 0

4 AHH1BHH 12 10 12 14

5 HAA1HBB 1 0 0 0

6 HHH 14 14 15 16

log-likelihood 2266 2265 2266

Three markers in the order of CEN–UWg 119–MTSc 9–UWg65 were typed. The observed genotypes are denoted by G1G2G3, where Gi5A or B corresponding to homozygous alleles at the ith marker and Gi5H corresponding to heterozygous alleles at the ith marker.

et al. 1996) and rainbow trout (Thorgaardet al. 1983) three intervals. The CxCo model, which imposes

moder-ate amount of chiasma interference, gave almost perfect via the method of maximum likelihood. Haplotype

in-formation is unavailable in both data sets. Because there fit to the observed data under the assumption of no meiosis I nondisjunctions. Recall that complete chiasma is little consistent evidence of chromatid interference

(Zhao et al. 1995a) and both data sets yield little evi- interference was assumed in deriving the estimate of

the meiosis I nondisjunction proportion in alfalfa by dence of chromatid interference, NCI is assumed in the

following analyses. For both data sets, we assume known Tavolettiet al. (1996). Therefore, it is difficult to dis-tinguish the model studied by Tavolettiet al. (1996) marker order and use the chi-square model for the

chiasma process. and the chi-square model studied here using this data set. Note that in some cases, the meiosis I nondisjunc-Alfalfa:By assuming complete chiasma interference,

Tavolettiet al. (1996) introduced a maximum likeli- tion proportion, pMI, and the map distance between the centromere and the most proximal marker, dCEN–A,

hood approach to analyzing half-tetrads from alfalfa.

We analyze a subset of three markers in their study. cannot be simultaneously identified. The Poisson model is the simplest such model, under which dCEN–A varies

These three markers are in the order of CEN–UWg 119–

MTSc9–UWg 65 and were genotyped in 152 progeny. according to pMI. In general, the estimate of dCEN–A

in-creases as the estimate of pMIdecreases. This is because Tavolettiet al. (1996) found that a very small

percent-age, approximately 6%, of half-tetrads in this organism as pMIdecreases, more crossover events are needed be-tween CEN andAto explain the observed heterozygous were the results of meiosis I nondisjunctions. To study

whether the observed data can be explained by a moder- half-tetrads at A, thus increasing the estimated map distance between them. As an example, for the alfalfa ate chiasma interference and no meiosis I

nondisjunc-tions, we fitted the chi-square model to the data set, data, the estimated map distance between CEN and

UWg 119 is 5 cM when no meiosis I nondisjunctions are

and the results are presented in Table 1. In our analysis,

all half-tetrads were assumed to be type IIb half-tetrads assumed, whereas the estimated map distance is 3 cM when the meiosis I nondisjunction rate is estimated at (i.e., they all resulted from meiosis II nondisjunctions).

The CxCo model gave the best fit among the chi-square around 6%.

Rainbow trout: Two markers in the order of CEN– models. The estimated map distances under the CxCo

model were 5, 4, and 11 cM in the three intervals CEN– Idh2–Est1 in rainbow trout were studied byThorgaard

et al. (1983). A total of 138 progeny were genotyped. UWg119, UWg 119–MTSc 9, and MTSc 9–UWg65,

respec-tively. The standard errors were estimated using the The number of progeny for each of the six observed half-tetrad types are given in Table 2. When the Cx(Co)m

parametric bootstrap method by (1) simulating data

sets with the same sample size under the CxCo model models, where m 50, · · · , 6, were fitted to the data, the model with the greatest degree of chiasma inter-assuming the estimated parameter values; (2) estimating

model parameters for each simulated data set; and (3) ference, the Cx(Co)6 model, gave the best fit to this data set. This is consistent with the conclusion of Thor-approximating the standard errors of the parameter

estimates using the standard errors of the estimated gaard et al. (1983) that there is high interference in rainbow trout. The estimated map distances under the parameter values from these simulated data sets. Using

this method, the standard errors were estimated to be Cx(Co)6model were 36 and 11 cM in the two intervals

CEN–Idh2 and Idh2–Est1. The corresponding standard

1, 1, and 2 cM, respectively. The above estimated genetic

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TABLE 2

Observed and expected counts of six different half-tetrad types of rainbow trout progeny

Expected

Group Genotypes Observed Cx(Co)4 Cx(Co)5 Cx(Co)6

1 AH 13 9 9 10

2 AA 14 15 14 14

3 HB 2 3 3 3

4 HH 92 84 85 86

4 BB 8 15 14 14

6 BH 9 9 9 10

log-likelihood 2163 2162 2161

Two markers in the order of CEN–Idh2–Est1 were typed. The observed genotypes are denoted by G1G2, where

Gi5A or B corresponding to homozygous alleles at the ith marker and Gi5H corresponding to heterozygous alleles at the ith marker.

genetic distances in these two intervals are 35 and 9 cM, address chiasma interference issue in their half-tetrad analysis. But their methods either were only applicable respectively. Our estimates agree fairly well with their

esti-mates. to one-marker data or made different assumptions

about chiasma interference in the same analysis for mul-In both examples, we have assumed no chromatid

interference. If chromatid interference indeed exists, tiple markers. In contrast, our proposed approach in this article applies to any crossover process model that map distances can be either over- or underestimated

depending on the specific pattern of chromatid interfer- incorporates chiasma interference. Zhao and Speed (1998) noted that most map functions proposed in the ence. In addition, chiasma interference can be

incor-rectly “detected” even if it is absent. A detailed study of context of centromere mapping can be well approxi-mated by the map function under the Cx(Co)2 model. chromatid interference is reported inH. ZhaoandT. P.

Speed (unpublished results). Therefore, multilocus gene-centromere mapping, as de-scribed above using the chi-square model as the cross-over process model, may provide a tractable and flexible

DISCUSSION

approach to analyzing multilocus half-tetrad data. The chi-square model has recently been extended to allow In this article, four types of half-tetrad data, type Ia,

Ib, IIa, and IIb, were studied. Half-tetrads, just like or- a more general class of interarrival distributions, yet the tractability of the model is still preserved (Langeet al. dered and unordered tetrads, provide information on

both chromatid interference and chiasma interference. 1997). This class of generalized chi-square models can also be used to analyze multilocus half-tetrad data. In addition, they can be used to map centromeres.

Under the assumptions of no chromatid interference H. ZhaoandT. P. Speed(unpublished results) stud-ied a Markov model for chromatid interference. They and random recovering of half-tetrads, the relations

between ordered tetrad probabilities and half-tetrad showed how this chromatid interference model can be applied with the chi-square model to study both chroma-probabilities were established. Using these relations, we

derived constraints among half-tetrad probabilities im- tid and chiasma interference. Their approach can be easily adopted here to study both types of genetic inter-posed by RRA and NCI. These constraints can be used

to test for NCI. When the order of the markers and ference using half-tetrads.

Throughout this article, we have assumed that the their relations to the centromere are not known, the

best order for these markers can be established through type of half-tetrads observed is known (type Ia, Ib, IIa, or IIb) and the phases in parents are known. Although examining the constraints imposed by NCI.

The relations between tetrad probabilities and half- these assumptions cover many data sets from experimen-tal organisms, they are often violated in human data. For tetrad probabilities can be used to construct genetic maps

and to locate centromeres under a given chiasma process example, autosomal trisomies could be the result of MI or MII nondisjunction events. If the probability of each model. This provides an approach to incorporating

chi-asma interference in genetic analysis. Because of the half-tetrad type is known, the maximum likelihood method can still be applied for multilocus gene-centro-presence of chiasma interference in most organisms, the

approach ofDaet al. (1995), which assumes no chiasma mere mapping. Alternatively, we can introduce parame-ters to account for the uncertainties in determining interference, is not consistent with biological evidence.

Several articles in the literature on half-tetrads (Ottet half-tetrad types (H. Zhao,unpublished results). Another assumption we have made is that the

ob-al. 1976;ChakravartiandSlaugenhaupt1987;

Figure

TABLE 1
TABLE 2

References

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