MATHEMATICAL MONOGRAPHS
MATHEMATICAL MONOGRAPHS.
EDITED BY
MANSFIELD MERRIMAN
andROBERT
S.WOODWARD.
No. 8,
VECTOR ANALYSIS
AND
QUATERNIONS
BY
ALEXANDER MACFARLANE,
Secretaky of International Association forPromoting theStudyof Quaternions.
FOURTH EDITION.
FIRST THOUSAND.
NEW YORK: ^ | t^
JOHN WILEY & SONS. X
London:
CHAPMAN & HALL,
Limited.1906.
t
Copyright,1896, BY
MANSFIELD
MERRIMAN
andROBERT S.WOODWARD.
UNDERTHE TiTLE
HIGHER MATHEMATICS.
First Edition, September,1896.
Second Edition,January, 1898.
Third Edition, August, 1900.
FourthEdition, January,1906.
ROBKRT DRUMMOND, PRINTHR,NBWVORIC,
EDITORS' PREFACE.
The
volume called Higher Mathematics, the first edition of whichwas
published in 1896, contained eleven chapters by eleven authors, each chapter being independent of the others, but all supposing the reader to have at least a mathematical training equivalent to that given in classical and engineering colleges.The
publication of that volume isnow
discontinued and the chapters are issued in separate form. In these reissues it will generally be found that the monographs are enlarged by additional^
articles or appendices which either
ampHfy
the former presentation or record recent advances. This plan of publication has been arranged in order to meet thedemand
of teachers and the convenience of classes, but it is also thought that itmay
prove advantageous to readers in special lines of mathematical Hterature.It is the intention of the publishers and editors to add other
monographs
to the series from time to time, if the call for thesame
seems to warrant it.Among
the topics which are under consideration are those of eUiptic functions, the theory ofnum-
bers, the group theory, the calculus of variations, and non- Euclidean geometry; possibly also monographs on branches of astronomy, mechanics,and mathematicalphysics
may
beincluded.It is the hope of the editors that this form of publication
may
tend to promote mathematical study and research over a wider
fieldthan that which the formervolume has occupied.
December, 1905. ij*
X
AUTHOR'S PREFACE.
Since this Introduction to Vector Analysis and Quaternions
was
first published in 1896, the study of the subject hasbecome much more
general; and whereassome
reviewers then regarded the analysis as a luxury, it isnow
recognized as a necessity for the exact student of physics or engineering. In America, Pro- fessorHathaway
has pubHshed aPrimer of Quaternions(New
York, 1896), and Dr. Wilson has amplified and extended Pro- fessor Gibbs' lectures on vector analysis into a text-book for the use of students of mathematics and physics(New
York, 1901).In Great Britain, Professor Henrici and Mr. Turner have pub- lished a
manual
forstudentsentitled Vectorsand Rotors (London, 1903); Dr. Knott has prepared anew
edition of Kelland and Tait's Introduction to Quaternions (London, 1904); and Pro- fessor Joly has realizedHamilton's idea of aManual
of Quater- nions (London, 1905). InGermany
Dr. Bucherer has pub- lished Elemente der Vektoranalysis (Leipzig, 1903) which hasnow
reached a second edition.Also the writings of the great masters have been rendered
more
accessible.A new
edition of Hamilton's classic, the Ele- ments of Quaternions, has been prepared by Professor Joly (London, 1899, 1901); Tait's Scientific Papers have been re- printed in collected form (Cambridge, 1898, 1900); and a com-plete edition of Grassmann's mathematical and physical works has been editedby Friedrich Engel with the assistance of several of the eminent mathematicians of
Germany
(Leipzig, 1894-).In the
same
intervalmany
papers, pamphlets, and discussions have appeared. For thosewho
desire information on the litera- ture of the subject a Bibliography has been published by the Association for the promotion of the study of Quaternions and Allied Mathematics (Dublin, 1904).There is still
much
variety in the matter of notation, and the relation of Vector Analysis to Quaternions is still the subject of discussion (see Journal of the Deutsche Mathematiker-Ver- einigung for 1904 and 1905).Chatham, Ontario, Canada, December, 1905.
CONTENTS.
Art.I. Introduction . Page 7
2. Addition of Coplanar Vectors 8
3. Products of Coplanar Vectors 14
4. Coaxial Quaternions 21
5. Addition of Vectors in Space 25
6. Product of
Two
Vectors 267. Product of Three Vectors 31
8. Composition of Located Quantities 35
9. Spherical Trigonometry 39
10. Composition of Rotations 45
Index 49
VECTOR ANALYSIS AND QUATERNIONS.
Art.
1.Introduction.
By
"Vector Analysis"
is
meant
a space analysis inwhich
the vectoristhefundamentalidea;by
'*Quaternions" ismeant
a space-analysis in which the quaternion is the fundamental idea.
They
are in truthcomplementary
parts of one whole;and
in this chapter they willbe treated assuch,and developed so as toharmonize with one anotherand
with the Cartesian Analysis.*The
subject to be treated is the analysis of quanti- ties in space,whether
they are vectorin nature, or quaternionin nature,or ofastill different nature,or areofsuchakind that they can be adequately represented
by
space quantities.Every
proposition about quantities in space ought to re-main
truewhen
restricted to a plane; just as propositions about quantities in a plane remain truewhen
restricted to a straight line.Hence
in the followingarticles the ascenttothe algebra ofspace ismade
through the intermediate algebra of the plane. Arts. 2-4 treat of themore
restricted analysis, while Arts. 5-10 treat ofthe generalanalysis.Thisspace analysis is a universal Cartesian analysis, in the
same manner
as algebra is a universal arithmetic.By
provid- ingan explicit notation for directed quantities, it enables their general properties to be investigated independently of any particular system of coordinates, whether rectangular, cylin- drical, orpolar. It also hasthis advantage that it can express*For a discussion of the relation of Vector Analysis to Quaternions, see Nature, 1891-1893.
QUATERNIONS.
the directed quantity
by
alinear function of the coordinates, instead of in aroundabout way by means
of a quadratic func- tion.The
differentviewsof this extension of analysis which have been heldby
independentwriters are briefly indicatedby
thetitles of their
works
:Argand, Essai sur una maniere de representer les quantit^s imaginaires dans les constructions geometriques, 1806.
Warren, Treatise on the geometrical representation ofthesquare roots ofnegative quantities, 1828.
Moebius,Der barycentrische Calcul, 1827.
Bellavitis, Calcolo delle EquipoUenze, 1835.
Grassmann, Die linealeAusdehnungslehre, 1844.
De
Morgan, Trigonometry and Double Algebra, 1849.O'Brien, Symbolic
Forms
derived from the conception of the translation of a directed magnitude. Philosophical Transactions,1851.
Hamilton, Lectures on Quaternions, 1853, and Elements of Quaternions, 1866.
Tait, Elementary Treatise on Quaternions, 1867.
Hankel, Vo'rlesungen iiber die complexen Zahlen und ihre Functionen, 1867.
Schlegel, System der Raumlehre, 1872.
Hoiiel, Theorie des quantites complexes, 1874.
Gibbs, Elementsof VectorAnalysis, 1881-4.
Peano, Calcologeometrico, 1888.
Hyde,
The
Directional Calculus, 1890.Heaviside, Vector Analysis, in "
Reprint of Electrical Papers,"
1885-92.
Macfarlane,Principles of the Algebraof Physics, 1891. Papers on SpaceAnalysis, 1891-3.
An
excellent synopsis is given byHagen
in the second volumeof his "Synopsis der hoheren Mathematik."
Art.
2.Addition of Coplanar Vectors.
By
a " vector" ismeant
a quantitywhich
hasmagnitude
and
direction. It is graphically representedby
a linewhose
ADDITION OF
COPLANAR
VECTORS. 9length represents the
magnitude
onsome
convenient scale,and whose
direction coincides with or represents the direction of the vector.Though
a vector is representedby
a line, its physical dimensionsmay
be different from thatofa line.Ex-
amples are a linear velocity which is of one dimension in length, a directed area which is oftwo
dimensions in length, an axis which is of no dimensions in length.A
vectorwill be denotedby
acapital italic letter,asB*
itsmagnitude by
a smallitalicletter,asb,and
itsdirectionby
a smallGreek
letter,asyS.For
example,B —
bfi,R=
rp.Sometimes
it is necessary to introduce a dot or a
mark /
to separate the specification of the direction from the expression for themagnitude
;f but in such simple expressionsasthe above, the difference is sufficientlyindicatedby
thedifference of type.A
system of three mutually rectangular axes will be indicated, as usual,
by
the lettersi,j\ k.The
analysis of avector here supposed is that into magni- tude and direction. According toHamilton and
Tait and otherwriterson Quaternions, the vectorisanalyzed into tensorand
unit-vector, whichmeans
that the tensor is amere
ratio destitute of dimensions, while the unit-vector is the physical magnitude.But
itwill be found that the analysis into magni- tude and direction ismuch more
in accord with physical ideas,and
explains readilymany
thingswhich
are difficult toexplainby
the other analysis.A
vector quantitymay
be such that itscomponents
have acommon
pointof application and are applied simultaneously;or it
may
be such that itscomponents
are applied in succes- sion, eachcomponent
starting from the endof its predecessor.An example
of the former isfoundintwo
forcesapplied simul- taneously at thesame
point,and
anexample
of the latter in* This notationisfound convenientbyelectrical writers in order toharmo-
tiizewiththeHospitaliersystem ofsymbols andabbreviations.
fThedot wasused for thispurposeintheauthor'sNote on Plane Algebra, 1883; Kennellyhassinceused Z for thesamepurpose inhiselectricalpapers
10 QUATERNIONS.
two
rectilinear displacementsmade
in succession to one an-^other.
Composition of
Components
having acommon
Point of Application.—
LetOA and OB
representtwo
vectors of thesame
kind simultaneously applied at the point O.Draw BC
g f^ parallel to
OA, and AC
parallel toOB,
andjoin
OC. The
diagonalOC
represents inmag-
nitude
and
directionand
point of application o ^ the resultant ofOA and OB.
This principlewas
discovered with reference to force, but it applies toany
vector quantitycoming
under theabove
conditions.Take
the direction ofOA
for the initial direction; the di- rection ofany
other vector will be sufficiently denotedby
the angle roundwhich
the initial direction has to be turned in order to coincide with it.Thus OA may
be denotedby
//o, OB by
/,/^,,OC
by//6[.
From
thegeometry
of the fig-ure it follows that
and
tan d=
^V
!!" ' ^;/.
+/,
cos 6/,/, sin e^
hence
OC = V/^ + f^ +
2/,/,cosd^/tan'^^ _^^^ ^^^ ^^.
Example. —
Let the forces applied at a point be 2/0"and
3/60°.Then
the resultant is 1/4+ 9+
12X
i- /tan-^ ?—
5If the first
component
isgiven as/,/6^,, thenwe
have themore
symmetrical formulaOC ^
f/.'+/« +
././, COS(.,-.,
I^jX^^X^Xk
When
thecomponents
are equal, the direction of the re- sultant bisects the angleformed by
the vectors;and
themag-
nitude ofthe resultant istwice the projection of either
compo-
nent on the bisecting line.The above
formula reduces taOC = 2/
cos^
2/2
/-'.ADDITION OF
COPLANAR
VECTORS, 11Example. — The
resultant oftwo
equal alternating electro- motive forces which differ 120° in phase is equal inmagnitude
to either
and
has a phase of 60°.Given a vector and one component, to find the other com-i ponent.
—
LetOC
represent the resultant,and OA
thecompo-
nent. JoinAC and draw OB
equaland
g^ parallel to
AC. The
lineOB
representsthe
component
required, for it is the onlyy^
line
which combined
withOA
givesOC
a' oa
as resultant.
The
lineOB
isidenticalwith the diagonal ofthe parallelogramformed by OC
andOA
reversed; hence the ruleis,
** Reverse the direction of the
component,
thencompound
it with the given resultant to find the required component."
Let f/B
be the vectorand fjo
onecomponent
; then the othercomponent
is/sin
efj^ = Vr+f: - 2fA
cos ^/tan--/+/cos^-
Given the resultant and the directions of the
two compo-
nents, to findthemagnitude
ofthecomponents.— The
resultantis represented
by OC, and
the directionsby OX
andOY.
Y,
From C draw CA
parallel toOY,
andCB
parallel to
OX
; the linesOA
andOB
cut off represent the required components. Itis evident that
OA and OB when com- pounded
produce the given resultantOC, and
there is onlyone set oftwo components
which produces a given resultant; hence they are the only pair ofcomponents
having the given directions.Let//6'be the vector
and /^ and
/d_^ the given directions.Then
/.
+/,
cos (<;,-
e,)
=/cos
{0-
e,),
/. cos {e,
-
0,)
+/, =/cos
(d,-
ff),
from
which it follows that^ jcos {e
^
e,)-
COS (e,-
S) cos (e,
-
e,) \
'^'~^
I
-
cos'{(i,-
6,)QUATERNIONS.
For
example, let 100/60°,/30°, and /qo" be given; then. cos 30°
•^'
I
+
cos 60°Composition of
any Number
of Vectors applied at acom- mon
Point.— The
resultantmay
be foundby
the following graphic construction:Take
the vectorsinany
order,a.sAjByC'
Q
From
the end ofA draw
B' equal and par-allel toBj
and
from the end ofB'draw
C^.gequal
and
parallel to C; the vector from the beginning ofA
to the end of C^ is the resultant ofthe givenvectors. Thisfollowsby
continued application of the parallelo-gram
construction.The
resultant obtained is the same, what^ever the order; and as the orderis arbitrary, the area enclosed has nophysical meaning.
The
resultmay
be obtained analytically as follows: Given /,/e,+ /y^, +
/s/^s+
. • •+
/n /On,Now
/,/6,=/,
cosejo_-\-f,sin d,
/^.
Similarly
f
J_0^= /,
cos6',/o+/,
sin6,/^,
and /„/^ =
/„ cos 0„/o+/„
sin(i„/^.
Hence 2\//d\ = i:Vcos
0\/o_-{- {J^/sin 6]
/- 2/
SMI=
i/(^/cosOy + (^/sin
Oy .tan-^^?^^^.
Inthe caseofa
sum
ofsimultaneousvectors appliedatacom- mon
point,the ordinaryruleaboutthe transposition ofaterm inan equation holdsgood.
For
example, ifA
-]-B ~{-C —
o,then
A
-{-B
=r -^ C, BindA
-{-C = -
B,Rnd B
-{-C = -
A, etc.This is permissible because there is no real orderof succession
among
the given components.**This does not holdtrue ofasumofvectorshaving a real orderof succes- sion. It isamistaketoattempttofoundspace-analysis uponarbitraryformal
ADDITION OF
COPLANAR
VECTORS. 1^Composition of Successive Vectors.
— The
composition of successive vectors partakesmore
of the nature of multiplica- tion than of addition. Let^
bea vectorstart-ing from the point O, and
B
a vector starting from the end of A.Draw
the third sideOP, /
and fromO draw
avector equalto B^ and fromits extremity a vector equal to A.
The
lineOP
is not the complete equivalent of^ +
-^1 if it were so, itwould
also bethe complete equivalent of
B
-\- A.But A
-{-B
andB
-{-Adetermine different paths;
and
as they go oppositely around, the areas they determine withOP
have different^signs.The
diagonal
OP
representsA
-{-B
only so far as it is consid- ered independent of path.For any number
of successive vectors, thesum
so far as it is independent of path is the vector from the initial point of thefirst to the final point of the last. This is also true
when
the successive vectorsbecome
so small as toform a continuous curve.The
areabetween
the curveOPQ
and the vectorOQ depends
on the path,and
has a physical meaning.Prob. I.
The
resultant vector, is 123/45°, and one componentis100/0°; find the other component.
Prob. 2.
The
velocity of a bodyina given planeis 200 /75°,and one component is 100/25°; findthe othercomponent.Prob. 3. Three alternating magnetomotive forces are of equal virtual value, but each pair differs in phase by 120°; find the re- sultant. (Ans. Zero.)
Prob. 4. Findthecomponentsof thevector 100/70°inthedirec- tions 20° and 100°.
Prob. 5. Calculate tlie resultantvector of 1/10°, 2/20°, 3/30°, 4/40°'
Prob. 6.
Compound
the following magnetic fluxes: /i sin /// -f-^sin («/
—
i2o°)/t2o°
+
^ sin (nf—
24o°)/24o°. (Ans. \h/?it.) laws; thefundamentalrulesmustbemadetoexpressuniversal properties ofthe thingdenoted. In this chapter no attempt is made to apply formal laws to directed quantities. What isattempted isan analysis of these quantities.QUATERNIONS.
Prob. 7.
Compound
twoalternating magnetic fluxes at a point, a cos nt/o andasinnt/ —
. (Ans.a/ni.)/ 2
—
Prob8. Find the resultant of two simple alternating electromo- tiveforces100/20°and50/75°.
Prob. 9. Prove that a uniform circular motion is obtained by- compounding two equal simple harmonic motions which have the space-phaseoftheirangular positions equalto the supplement of the time-phaseoftheirmotions.
Art.
3.Products of Coplanar Vectors.
When
all the vectors considered are confined to acommon
plane, each
may
be expressed asthesum
oftwo
rectangular components. Let iand/
denotetwo
directions inthe planeat right anglestoone another; thenA =
aJ,-f"^ij\B =
b^i-j-b^j\R-=xi-\-yj.
Here
iand y
are not unit-vectors, but rather signs of direction.Product of
two
Vectors.— Let A—
a^i-^ajand B =
b^ir\-hJbe any two
vectors,notnecessarily of thesame
kindphysically.We assume
that their product is obtainedby
applying the<iistributive law, but
we do
notassume
that the order of the factors is indifferent.Hence
AB =
{a,i+
aJ){b,iArKJ) =
^fi.ii-f a^bjj-{-afi^ij-\-aJ)JL
If
we
assume, as suggestedby
ordinary algebra, that the•square of a sign of directionis -j-,and furtherthat the product of
two
directions at rightangles to one anotheristhe directionnormal
to both, then the above reduces toAB =
aj)^+
aj)^+
{afi^—
a^b^k.Thus
the complete product breaksup
intotwo
partial products, namely, ^/i -j- <^A which is independent of direc-tion,
and
{a^b^—
a^b^)kwhich
has the axis of the plane for direction.**
A
commonexplanationwhichisgivenofij=
>^isthatiisanoperator,/an•operand,andktheresult. Thekindofoperator whichi issupposedto denote
isa quadrantof turning round the axisi ; itissupposednottobeanaxis,but a quadrant of rotation round an axis. This explains the result
iJ
=
k, but unfortunatelyitdoes not explainii= +
; for itwould give ii=
i.PRODUCTS OF
COPLANAR
VECTORS. 15 Scalar Product oftwo
Vectors.— By
a scalarquantity is
meant
a quantitywhich hasmagnitude
andmay
be positive or negative but is destitute of direction.The
formerpartial product is so called because it is of such a nature. It is
denoted
by SAB
where thesymbol
S, being inRoman
type,denotes, not a vector, but a function of the vectors
A
and B.The
geometricalmean-
ing ofSAB
is the product ofA
and the | orthogonal projection of i5upon
A. Let i,tOP
andOQ
represent the vectorsA
andB;
\\draw QM and NL
perpendicular toOP. o^Z^Z^
Then
(OP)(OM) = (OP)(OL) + (OP)(LM),
= ^{^-f+''-a\'
Corollary I.
— SB A = SAB. For
instance, letA
denote a force andB
the velocity of its point of application; thenS^^
denotes the rate of
working
of the force.The
result is thesame
whether the force is projected on the velocity or the velocity on the force.Example
i.— A
force of 2pounds
East+
3pounds North
ismoved
with avelocity of4
feetEast per second+
5 feetNorth
per second; find the rate at whichwork
is done.2X4+3X5=
23 foot-pounds per second.Corollary2.
— A^
=ia^*
+
a^^—
0^,The
squareofany
vectoris independent of direction; it is an essentially positive or signless quantity; forwhateverthedirection ofA,the direction of the other
A must
be thesame
; hence the scalarproduct cannot be negative.Example
2.— A
stone of 10pounds mass
ismoving
with avelocity 64 feet
down
per second+
100 feet horizontal persecond. Its kinetic energy then is
—
(64'+
100')foot-poundals.16 QUATERNIONS.
a quantity
which
has no direction.The
kinetic energy due to thedownward
velocity is lOX — and
thatdue
to the hori-2 zontal velocity is
— X
lOo'*; the
whole
kinetic energy is ob- tained, notby
vector, butby
simple addition,when
thecom-
ponents are rectangular.Vector
Product oftwo
Vectors.— The
otherpartial product from its nature iscalled the vector product,and
is denotedby
YAB.
Its geometricalmeaning
is the product ofA and
the projection ofi?whichis perpendicular to Ay that is, the area of the parallelogram
formed upon A and
B, LetOP and OO
represent the vectorsA
L._^i.__> i and By
and draw
the lines indicatedby
thefigure. It is then evident that the area ofthetriangle
OPQ =
a,b^—
^a,a^
—
^b^b^—
^(a,—
b,){b,
—
a,)y
=
i(^,^,-
a^b,).
Thus
{a^b^—
ajb^k denotes themagnitude
of the parallelo- grarnformed by A and B and
also the axis of the plane inwhich
it lies.It follows that
VBA = — NAB,
It is to be observed that the coordinates ofA and B
aremere component
vectors, whereasA and B
themselves are taken in a real order.Example. —
Let^ = (iO^+
117)inchesand B —
{^i-\- 12j)
inches, then
YAB = (120—
55)/^ square inches; that is, 65 square inches in the planewhich
has the direction k for axis.If
A
isexpressed asaa and B
as bj3,thenS^^ =
abcosa^ywhere
aj3 denotesthe anglebetween
the directionsa and
y5.Example. — The
effective electromotive force of 100 volts per inch /go° along aconductor 8 inch /45°isSAB =
8X
100cos/45° /9o°volts,thatis,800cos 45°volts.
Here
/45°indicates the directiona and
790° the direction y^,and
745° 790°means
the anglebetween
the direction of45°and
the di^-ection of 90°.Also
VAB=
absina^
. aft,where a^
denotesthedirectionwhich
is normal to botha and
y^, that is, their pole.PRODUCTS
OFCOPLANAR
VECTORS. I7Example. — At
a distance of lo feet730° there isa force of 100pounds
/6o°.The moment
isWAB
=
10X
100 sin /30^ /6o° pound-feet907
790°=
1000sin 30° pound-feet 90°//go°.Here
90°/ specifiesthe planeofthe angleand /go°theangle.The two
together writtenas above specify the normalJb.Reciprocal of a Vector.
— By
the reciprocal of a vector ismeant
the vectorwhichcombined
with the originalvector pro- duces the product+
!•The
reciprocal ofA
is denotedby A~\
SinceAB =
ab (cos a/?-)-sin «/?.afi), bmust
equala~^ and /?
must
be identical witha
in order that the productmay
be i. It follows that_
I_
<^«_
<^i^+ ^J
a a a'
+
a^The
reciprocal and opposite vector is— A~\
In the figure letOP = 2^
be the given vector; thenOQ = \^
isitsrecipro-cal,
and OR =
^(—
y5) is its reciprocaland
opposite."*
R
Q PExample.—
If^ =
10 feet East+
5 feet North, A-^=
—
feet East+ —
feetNorth
and—
A-'=
feet125
^
125 125
East
— —
feet North.125
Product ofthe reciprocal of a vectorand another vector.
—
A-'B = -.AB,
= ^\^A + ^A + i^A - ^A)^}*
=
-(cos a/3-j-sin a/3. a/3),*Writerswhoidentifyavectorwitha quadrantal versor arelogically ledto define the reciprocal ofa vectorasbeing oppositein direction as well as recii>- rocalin magnitude.
18 QUATERNIONS,
b b
Hence
S^-'i5= -cos aQ and YA-'B =
-sinaB
. ati.a ' a ' '
Product of three Coplanar Vectors.
—
LetA = aj +
a^jjB =
b^t+
b^j,C =
cj+
c^j denoteany
three vectors in acommon
plane.Then
{AB)C =
{{a,b,+ aA) +
(^/,- ^AWi^^^ + cj)
=
(^/i+
^A)(^i^*+ ^J) + i^A - aA)(-
^J+
^^y)•The
former partial productmeans
the vectorC
multipliedR\
by
the scalarproductofA
andB
; while the/P latter partial product
means
the comple-/c
mentary
vector ofC
multipliedby
themag-
nitude ofthe vector product ofA and
B.^ J
Ifthese partialproducts(representedby OP
and
OQ)
unite to form a total product, thetotalproductwillbe representedby OR,
the resultant ofOP and OQ.
The
former product isalso expressedby SAB
. C,where
the point separates the vectors towhich
theS
refers;and more
analytically
by
abc cos a/3. y.The
latterproduct is also expressedby
{'VAB)C, which is equivalent toy(VAB)C,
becauseYAB
is at right angles to C. It is also expressedby
abcsina^
.a^y, where
afty de- notes thedirection which is perpendicular tothe perpendicular toa and
ftand
y.Ifthe product is
formed
afterthe othermode
ofassociationwe
haveA{BC) = iaj+
aj){b,c,+
b,c,)+
{a,i+
aj){b,c,-
b,c,)k=
{b,c,+
b^c^)(a,i+
a,j)+
{b,c,-
b,c;)(a,i-
a,J)
=zSBC.A +YA{VBC).
The
vectoraj —
aJ
is the opposite of thecomplementary
sector ofaj,+
a^j.Hence
the lattei partial product differswith the
mode
of association.Example.— Let
yi=
i/o+
2/90°,^ =
3/0°+
4/90;^, iC—
5/0°
+
6/90°.The
fourth proportional to A, B,C
isPRODUCTS
OFCOPLANAR
VECTORS. 1^(A-'B)C=
'
^3+^X4
I j 5/0°+
6/90°( -f-2+
'^,f~,^^
I ^1-6/0° +5/90°}
-j- 2
= 134/0° +
11.2/90°.Square of a Binomial of Vectors.
—
IfA
-]-B
denotes asum
of non-successive vectors, it is entirelyequivalent to the resultant vector C.But
the square ofany
vector is a positive scalar, hence the square oiA
-\-B must
be a positive scalar.Since
A
andB
are in reaHtycomponents
of one vector, the squaremust
be formed after the rules for the products of rect- angularcomponents
(p. 432).Hence
{AJrBy = {A-^B){A+B),
= A' + AB + BA + B\
=
.4'+
^^+ S^^ +
'^BA+ ^lAB + NBA,
= A' +
B'+ 2SAB,
This
may
alsobe written in the formd
-^-b"-{• 2abcos ap.But when A
-\-B
denotes asum
ofsuccessive vectors,thereisnothird vector
C
which is thecompleteequivalent ;and
con- sequentlywe
need not expect the square to be a scalar quan-tity.
We
observe that there is a real order, not of the factors, but of the terms in the binomial; this causes both product terms to beAB,
giving= ^«
4_^^+ 2^AB +
2SIAB,The
scalar part gives the square ofthe length ofthe third side, while the vector part gives four times the area includedbetween
the pathand
the third side.Square ofa Trinomial of CoplanarVectors.
— Let^ +^-[- C
denoteasum
ofsuccessivevectors.The
product termsmust
be formed so as to preserve the order of the vectorsin the tri-nomial; that is,
A
is prior toB and
(7, andB
is prior to C,QUATERNIONS.
Hence
{A
-{-B+ Cy ^A' +
B'+ r-i- 2AB+ 2AC+ 2BC,
= A' +
B'+ C + 2{SAB
•i-SAC-\-SBC),
(i)+ 2{Y AB + V^
(T+ VBC),
(2)Hence S{A + B + Cy =
(i)=
«'-j-^'
+
^^+
2ad cos a/3-\-2ac cosay
-\-2bccos ftyand N{A^B^Cy =
{2)=^\2ab sin
a^ +
^^^ sin a:;/+
2bcsin y^/}.ary^'The scalarpart gives the square ofthe vector from the be-
^
ginning ofA
tothe end ofC and
is all that existswhen
the vectors are non-successive.The
vector/^ part is four times the area included
between
the successive sidesand
the resultant side of the~^ "
polygon.
Note
that it is hereassumed
thatN{A ^B)Cz=VAC +
YBC, which
isthetheorem
ofmoments.
Alsothat the prod- uct terms are notformed
in cycHcal order, but in accordance with the order of the vectors in the trinomial.Example.— Let A =
3/0^
B =
5/30°,C =
7/45°; find the areaof the polygon.iV{AB+AC+BC),
= ili5sin/o/30° +
2isin/o/^° +
35sin/30°/45_°!,= 375 + 742 +
4.53=
157-Prob. 10. At a distance of 25 centimeters /2o° thereis a force of 1000 dynes /8o°; find the moment.
Prob. II.
A
conductor in an armature has a velocity of 240 inches per second 7300° and the magneticflux is 50,000lines per jsquare inch/o; find the vector product.(Ans. 1.04
X
10' lines per inch per second.) Prob. 12. Find the sine and cosine of the angle between the directions 0.8141 E.+
0.5807 N., and 0.5060 E.+
0.8625 N.Prob. 13.
When
a force of 200 pounds 7270° is displaced by 10 feet 73o°> what is the work done (scalar product)?What
is the meaning of the negative sign inthe scalarproduct?COAXIAL QUATERNIONS. 21 Prob. 14.
A
mass of loopounds is movingwith a velocity of 30 feetE. per second+
50 feetSE.persecond; find itskineticenergy.Prob. 15.
A
force of 10 pounds745° is acting at the end of 8 feet/2oo°; find the torque, or vector product.Prob. 16.
The
radius of curvature of a curve is 2/0°+
5/90°; findthe curvature. (Ans. .03/0°-f .17/90°.)Prob. 17. Find the fourth proportional to 10/0°
+
2/90°8/0°
- 3/V,
and6/o_°
+
5/90^.~
Prob. 18. Find the area of the polygonwhose successivesides are 10/30°, 9/1 00°, 8/180°, 7/225°.
Art.
4.Coaxial Quaternions.
By
a *'quaternion"
is
meant
the operator v^^hich changesone
vector into another. It iscomposed
of amagnitude and
a turning factor.The magnitude may
ormay
not be amere
ratio, that is, a quantity destitute of physical dimensions; for the
two
vectorsmay
ormay
not be of thesame
physical kind.The
turning is in a plane,that is to say, it is not conical.For
the present all the vectors considered lie in acommon
plane;hence allthe quaternions considered have a
common
axis.*Let
A and R
betwo
coinitial vectors; the direction normal to the planemay
be denotedby
ft.The
operator which changesA
intoR
consists of a scalar multiplierand
aturninground the axis/?. Lettheformer be denotedby
rand
the latterby ^^ where
6denotes the angle in radians.Thus R =
r/3^Aand
recip-rocally^
A = -6-^R.
Also^R =
r/3^and^A = -6-\
r
A ^ R r
The
turning factor/?^may
be expressed asthesum
oftwo component
operators, one of which has a zero angleand
the other an angle of a quadrant.Thus
yS«
=
cos6^.yS<^
+
sin^.^^/\*The idea of the "quaternion"isdue to Hamilton. Its importance may
be judgedfromthe fact thatithasmadesolidtrigonometrical analysis possible.
It isthemostimportant keytotheextensionof analysis to space. Etymologi- cally "quaternion" meansdefinedbyfour elements; whichistrueinspace
• in
planeanalysisitisdefinedbytwo.
QUATERNIONS.
When
the angle is naught, the turning-factormay be
omitted; but the
above
formshows
that the equation ishomogeneous, and
expresses nothing but the equivalence of a given quaternion totwo component
quaternions.*^Hence
rft^=
r cos 6-\-rsm
.^-"'^and
rft^A=pA
+g/3''/'A= pa
,a
-j-ga, /3'^/*ar.The
relationsbetween
rand
6, and/ and
^, are givenby
r
= V/+7y =
tan -'tExample. — Let E
denote a sine alternating electromotive force inmagnitude and
phase,and /
the alternating current inmagitude and
phase, thenE=
{r-{- 27tnl. fi^/'%where
ris the resistance, /the self-induction,n the alternations perunit of time,and ^
denotes the axis of the plane of repre- sentation. It follows thatE —
rl-\-27tnl,ft'^/^I\ also that
I''E =
r-]-27tnl. ^-/^that is, the operator which changes the current into the elec- tromotive force is a quaternion.
The
resistance is the scalar part of the quaternion,and
the inductance is the vectorpart.Components
of the Reciprocal of a Quaternion.— Given
then
A = —. —
^-^-^R
_
/>—
^.yg^/gR
*In the methodof complex numbers/S'r/a isexpressed byi, which stands for |/
—
I. Theadvantagesofusing theabove notation are thatit iscapable of being applied to space,andthatitalsoservesto specify thegeneral turning factoryS^as wellasthequadrantal turningfactorjS'^/i.COAXIAL QUATERNIONS.
2$
Example. — Take
thesame
application as above. It is im- portant to obtain/
in terms of E,By
the abovewe deduce
that from
E —
{r-\-2nnL
yS'^/^)//=
i r^^^^
/gv^ IE
\r'+(27rn/y
r'+
(27rn/y:^ )^'
Addition of Coaxial Quaternions.
—
If the ratio of each of several vectors to a constant vectorA
is given, the ratio of their resultant to thesame
constant vector is obtainedby
tak- ing thesum
of theratios. Thus, if^n = (A +
?- •/S'-'V.then
2Ji=\:Sp+
(,2g).^'/^}A,and
reciprocally^- {2pr + (2gy
^^-
Example. —
In the case of acompound
circuitcomposed
of a
number
of simple circuits in parallelA -
r,'
+
{2nnri: ' ^^"
r,'+
(2nnfi;^' ^^^'^therefore,
:SY=
^']
^7,
^,^ '(a^ [^
=
\ :^( ,,
/
.^] - 27rn2^-r7
xii5.y^'/« IE,
I \r^-}-(27tnyPj
r'-^{2nnyf ^
j '
and
reciprocally^\
, , ^^ ,,J +
27tn:^\-^—---)
.fi-"/^_
\r -\-{2nnyiVV +
(2;r;g)VV_^^
Product of Coaxial Quaternions.
—
If the quaternions which changeA
to R, andR
toR\
are given, the quaternion which changesA
toR'is obtainedby
taking theproduct of the given quaternions.*This theorem wasdiscoveredby Lord Rayleigh; PhilosophicalMagazine, May, 1886. Seealso Bedell