ESE319 Introduction to Microelectronics
Differential Amplifier Offset
●
Causes of dc voltage and current offset
●Modeling dc offset
●R
Cmismatch
●I
Smismatch
●β mismatch
●
dc offsets in differential amplifiers due to component
mismatch can be modeled as
differential
phenomena
ESE319 Introduction to Microelectronics
IC1 RC1 RC2 IC2 VCC VCC + - VO I Q1 Q21. Let the ac sources be zero, i.e. the bases of matched Q1 & Q2 are connected to ground.
2. To further simplify, let there be no external base RB and emitter resistors RE.
3. Let the mismatch be in RC where RC1 ≠ RC2.
I IC1=IC2= 1 I 2 = I 2 If VOdm VOdm=0⇒ RC1 IC1=RC2 IC2 V Odm=V C2−V C1=RC1 IC1−RC2 IC2
Since Q1=Q2 and I is fixed, currents are matched i.e.
VEE
IC1=IC2= I
ESE319 Introduction to Microelectronics
Assume matched currents:
IC1=IC2= I
2
RC1≠RC2
Split the mismatch between both
collector resistors, and decompose into common and differential components:
RC= RC2RC1
2
RC=RC2−RC1
(common)
(differential - mismatch)
Solving for RC1 & RC2:
RC2=RC RC 2 =RC1 1 2 RC RC RC1=RC− RC 2 =RC1− 1 2 RC RC Let: I 2 I 2 s.t. RC2RC1 I VOdm vid/2 −vid/2 VEE vic
ESE319 Introduction to Microelectronics
V Odm=RC2 IC2−RC1 IC1 Recall: V Odm=
RC RC 2
IC2−
RC− RC 2
IC1 V Odm=
RC RC 2
I 2−
RC− RC 2
I 2 IC1=I C2= I 2 Hence : or: V Odm= I2 RC output offset voltage
I 2 I 2 random variable (rv) I VOdm RC1≠RC2 VEE
ESE319 Introduction to Microelectronics
V Odm= I
2 RC
Collector-collector voltage due to resistor mismatch: V OS≡V Odm Avdm RC VOS is highly variable, rv & can be + or -VEE VOdm I 2 I 2 I I 2 I 2 I -VOS 0 V VEE VEE
Define the input offset voltage
as that input voltage that will cancel
VOdm. If the amplifier differential gain is Avdm:
Input offset voltage is the output offset voltage referred to the input due to
ESE319 Introduction to Microelectronics
VOS=V Odm Avdm V OS= I 2 RC gm RC gm= IC V T = I 2 1 V T V OS R C=V T RC RCInput referred offset due to ΔRC mismatch: where Avdm=gm RC random variable VEE V Odm= I 2 RC I 2 I 2 I -VOS 0 V
ESE319 Introduction to Microelectronics
Offset Voltage From Transistor Mismatch
V Odm=0⇒ RC1 IC1=RC2 IC2
Perfect balance requires:
Previous case considered RC1 ≠ RC2
& Q1 = Q2 => IC1 = IC2.
Consider now Q1 ≠ Q2 => IC1 ≠ IC2. ASSUME: 1. RC1 = RC2 = RC
2. VBE1 = VBE2 3. VT1=VT2
Only difference is in the saturation currents of the transistors, i.e.
I S1≠IS2 + -VOdm I VEE RC RC
ESE319 Introduction to Microelectronics
Again using common and differential
mode concepts:
I S= IS2I S1
2
I S=I S2−IS1
The two transistor saturation currents are: I S2=I S I S 2 IS1=I S− IS 2 + -I −vid/2 vid/2 vic VEE VOdm
ESE319 Introduction to Microelectronics
ICdm/2 IS eVBE/VT IS 2 e VBE/VT IS eVBE/VT − IS 2 e VBE/ VT IC1 IC2 ICdm/2 IC≈ISe VBE/VT Vee IC1≈ I S1e VBE VT =
I S− I S 2
e VBE VT IC2≈ IS2e VBE VT =
IS IS 2
e VBE VTESE319 Introduction to Microelectronics
IC1≈I S e VBE VT − I2 S e VBE VT IC2≈IS e VBE VT I2 S e VBE VT alsoThe parallel current sources are illustrated in the schematic.
ICdm/2
ICdm/2
Large signal Model:
ISeVBE/VT IS 2 e VBE/VT ISeVBE/VT − IS 2 e VBE/ VT Vee IC1 IC2 IC2≈
IS IS 2
e VBE VT IC1≈
IS− IS 2
e VBE VT IC1≈ I S1eVBE/VT IC2≈ IS2eVBE/VTESE319 Introduction to Microelectronics
IC2≈ISe VBE VT I2 S e VBE VT ≈ IS e VBE VT 1 IS 2 IS IC2≈ I 2 1 IS 2 I S IC1≈ I 2 1− I S 2 IS IC≈ I Se VBE VT ≈ 2INote: differential IC components
cause current flow in opposite directions through the RC's
resulting in an offset voltage. The
common IC components cause no offset voltage.
V Odm=RC IC2−RC IC1≈ I
2
IS
ESE319 Introduction to Microelectronics
gm= IC V T ≈ I 2 1 V T V Odm≈ I 2 IS I S RC V Odm≈ I 2 VT VT IS IS RC V Odm≈gmVT IS I S RC V OS I S≈V T IS I S random variable V OS I S= V Odm Avdm = VOdm gm RC ≈V T I S I S Recall:ESE319 Introduction to Microelectronics
Offset Voltage Summary
1. We considered two sources of offset voltage: a. Unbalanced collector resistors
b. Unbalanced saturation currents
i. Due to mismatched transistor geometries 2. We ignored base or emitter circuit unbalance
3. Since the relationship between resistor and current unbalances are random and assumed independent, we combine their effect as an rms quantity: V OSrms=
V OS− R C 2 V OS− IS 2 =V T
RC RC
2
II S S
2ESE319 Introduction to Microelectronics
Average & Offset Base (input) Bias Currents
Consider the case where the base currents differ IB1 ≠ IB2.
Since IB1 & IB2 are related to bias current I, their mismatch may be due to β1 ≠ β2.
Let's represent β1 & β2 in terms of differential
& common components:
1= 2 2=− 2 IB1 IB2 IE1=I 2 IE2= I 2 vid/2 −vid/2 vi−cm VEE
ESE319 Introduction to Microelectronics
I B1≈ I 2 1 1 =2I 1 2 =2I 1 1 1 2 Using this notation, the two base currents are:
1
1x =1−xx
2
−x3...≈1−x
For x << 1 we can expand the fraction as the series:
where x≈ ± 2 nonlinear f(Δβ) I B2≈ I 2 1 2 = 2I 1 −2 = 2I 1 1 1− 2
ESE319 Introduction to Microelectronics
I B1≈ I 2 1
1− 1 2
I B2≈ I 2 1
1 1 2
Using the expansion and approximating :I B= I B1I B2 2 = I 2 IOS ≡
∣
I B1−I B2∣
= I 2∣
∣
¿ IOS =I B∣
∣
The base or input offset current can also be written as:
(input offset current)
1≈
ESE319 Introduction to Microelectronics
DC Offset Voltage & Current Summary
1. DC offset voltage and current occur due to mismatches in the BJT differential amplifier external resistors and transistor parameters (Is and β).
2. These mismatches are imperfections that are inherent to all differ-ential amplifiers and their applications (e.g. op amps).
3. DC offset voltage and current are statistical quantities, i.e. no two differential amplifiers will have the same offset voltage and current. 4. MOS differential amplifiers have zero input offset current.