R E S E A R C H
Open Access
Existence of a common solution of an integral
equations system by
(
ψ
,
α
,
β
)
-weakly
contractions
Parvaneh Lo’lo’
1, Seiyed Mansour Vaezpour
2, Reza Saadati
3and Choonkil Park
4**Correspondence:
4Department of Mathematics,
Research Institute for Natural Sciences, Hanyang University, Seoul, 133-791, Republic of Korea Full list of author information is available at the end of the article
Abstract
In this paper, we consider a system of integral equations and apply the coincidence and common fixed point theorems for four mappings satisfying a (ψ,
α,
β)-weakly
contractive condition in ordered metric spaces to prove the existence of a common solution to integral equations. Also we furnish suitable examples to demonstrate the validity of the hypotheses of our results.MSC: 54H25; 47H10
Keywords: coincidence point; common fixed point; partially weakly increasing mappings; compatible pair of mappings; weakly compatible pair of mappings; semi-compatible pair of mapping; (ψ,
α,
β)-weakly contraction; reciprocally
continuous mappings;f-weak reciprocally continuous mappings1 Introduction and preliminary
Fixed point theory has wide and endless applications in many fields of engineering and sci-ence. Its core, the Banach contraction principle (see []), has attracted many researchers who tried to generalize it in different aspects. In particular, Alber and Guerre-Delabriere [] introduced the concept of weak contractions in Hilbert spaces. Rhoades [] showed that the result which Alberet al.had proved in Hilbert spaces was also valid in complete metric spaces. Eshaghi Gordjiet al.[] proved a new coupled fixed point theorem related to the Pata contraction for mappings having the mixed monotone property in partially ordered metric spaces. Singhet al.[] obtained coincidence and common fixed point the-orems for a class of Suzuki hybrid contractions involving two pairs of single-valued and multi-valued maps in a metric space.
Definition .([]) The functionψ : [, +∞)→[, +∞) is called an altering distance function if the following properties are satisfied:
(i) ψ is continuous and non-decreasing, (ii) ψ(t) = if and only ift= .
Definition .([]) Let (X,d) be a metric space. A mappingf :X→Xis said to be weakly contractive if
d(fx,fy)≤d(x,y) –ϕd(x,y) for eachx,y∈X,
whereϕ: [, +∞)→[, +∞) is an altering distance function.
In [], Rhoades proved that ifXis complete, then every weak contraction has a unique fixed point.
The weak contraction principle, its generalizations and extensions and other fixed point results for mappings satisfying weak contractive type inequalities have been considered in a number of recent works.
In , Dutta and Choudhury [] proved the following theorem.
Theorem .([]) Let(X,d)be a complete metric space and f :X→X be such that
ψd(fx,fy)≤ψd(x,y)–ϕd(x,y) for each x,y∈X,
whereψ,ϕ: [, +∞)→: [, +∞)are altering distance functions.Then f has a fixed point in X.
In [], Eslamian and Abkar introduced the concept of (ψ,α,β)-weak contraction. They stated the following theorem as a generalization of Theorem ..
Theorem .([]) Let(X,d)be a complete metric space and f :X→X be a mapping satisfying
ψd(fx,fy)≤αd(x,y)–βd(x,y)
for all x,y∈X,whereψ,α,β: [, +∞)→[, +∞)are such thatψ is an altering distance function,αis continuous,βis lower semi-continuous,and
ψ(t) –α(t) +β(t) > for each t> ,
andα() =β() = .Then f has a unique fixed point.
Aydiet al.[] proved that Theorem . is a consequence of Theorem .. (Define ϕ: [, +∞)→[, +∞) byϕ(t) =ψ(t) –α(t) +β(t) for allt≥.)
It is also known that common fixed point theorems are generalizations of fixed point theorems. Recently, many researchers have been interested in generalizing fixed point the-orems to coincidence point thethe-orems and common fixed point thethe-orems.
Definition .([]) LetXbe a non-empty set,Nbe a natural number such thatN≥ andf,f, . . . ,fN–,fN:X→Xbe given self-mappings ofX. Ifw=fx=fx=· · ·=fN–x=
fNxfor somex∈X, thenxis called a coincidence point off,f, . . . ,fN–andfN, andwis called a point of coincidence off,f, . . . ,fN–andfN. Ifw=x, thenxis called a common fixed point off,f, . . . ,fN–andfN.
On the other hand, compatibility of two mappings introduced by Jungck [, ] is an important concept in the context of common fixed point problems in metric spaces.
Definition . ([]) Two mappings f,g :X→X, where (X,d) is a metric space, are weakly compatible if they commute at their coincidence points, that is, ifft=gtfor some
t∈Ximplies thatfgt=gft.
It is clear that if the pair (f,g) is compatible, then (f,g) is weakly compatible.
Recently, fixed point theory has developed rapidly in partially ordered metric spaces (for example, see [–] and the references therein). Harjani and Sadarangani in [, ] extended Theorem . in the framework of partially ordered metric spaces in the follow-ing way. In , Choudhury and Kundu [] established the (ψ,α,β)-weak contraction principle to coincidence point and common fixed point results in partially ordered metric spaces and proved the following fixed point theorem as a generalization of Theorem ..
Theorem .([]) Let(X,d,)be a partially ordered complete metric space.Let f,g:
X→X be such that fX⊆gX,f is g-non-decreasing,gX is closed and
ψd(fx,fy)≤αd(gx,gy)–βd(gx,gy) for all x,y∈X such that gxgy,
where ψ,α,β : [, +∞)→[, +∞) are such that ψ is continuous and monotone non-decreasing,αis continuous,βis lower semi-continuous,
ψ(t) –α(t) +β(t) > for all t> ,
andψ(t) = if and only if t= andα() =β() = .Also,if any non-decreasing sequence {xn}in X converges to z,then we assume xnz for all n∈N∪ {}.If there exists x∈X
such that gxfx,then f and g have a coincidence point.
Altun and Simsek [] introduced the concept of weakly increasing mappings as follows.
Definition . Letf,gbe two self-maps on a partially ordered set (X,). A pair (f,g) is said to be
(i) weakly increasing iffxg(fx)andgxf(gx)for allx∈X[], (ii) partially weakly increasing iffxg(fx)for allx∈X[].
Note that a pair (f,g) is weakly increasing if and only if the ordered pairs (f,g) and (g,f) are partially weakly increasing.
Nashine and Samet [] introduced weakly increasing mappings with respect to another map as follows.
Definition .([]) Let (X,) be a partially ordered set andf,g,h:X→Xbe given mappings such thatfX⊆hXandgX⊆hX. We say thatf andgare weakly increasing with respect tohif and only if for allx∈X, we have
fxgy, ∀y∈h–(fx)
and
gxfy, ∀y∈h–(gx),
Iff =g, we say thatf is weakly increasing with respect toh.
Ifh:X→Xis the identity mapping (hx=xfor allx∈X), thenf andg being weakly increasing with respect tohimplies thatf andgare weakly increasing mappings.
Nashineet al.[] proved some new coincidence point and common fixed point theo-rems for a pair of weakly increasing mappings with respect to another map.
In [], Esmailyet al.gave the following definition.
Definition .([]) Let (X,) be a partially ordered set andf,g,h:X→Xbe given mappings such thatfX⊆hX. We say that (f,g) is partially weakly increasing with respect tohif and only if for allx∈X, we have
fxgy, ∀y∈h–(fx).
Theorem . ([]) Let (X,d,) be a partially ordered complete metric space. Let f,g,S,T:X→X be given mappings satisfying the following:
(i) fX⊆TX,gX⊆SX,
(ii) f,g,SandTare continuous,
(iii) the pairs(f,S)and(g,T)are compatible,
(iv) (f,g)is partially weakly increasing with respect toTand(g,f)is partially weakly increasing with respect toS.
Suppose that for every x,y∈X such that Sx and Ty are comparable,we have
ψd(fx,gy)≤ψM(x,y)–φN(x,y), ()
where
M(x,y) =max
d(Sx,Ty),d(Sx,fx),d(Ty,gy),
d(Sx,gy) +d(fx,Ty),
N(x,y) =maxd(Sx,Ty),d(Sx,gy),d(Ty,fx) ,
andψ: [, +∞)→[, +∞)is an altering distance function,andφ: [, +∞)→[, +∞)is a continuous function withφ(t) = if only if t= .Then the pairs(f,S)and(g,T)have a co-incidence point u∈X;that is,fu=Su and gu=Tu.Moreover,if Su and Tu are comparable,
then u∈X is a coincidence point f,g,S and T.
Definition .([]) Let (X,d,) be an ordered metric space. We say thatXis regular if the following hypothesis holds: if{xn}is a non-decreasing sequence inXwith respect to
such thatxn→x∈Xasn→ ∞, thenxnxfor alln∈N.
Theorem .([]) Let(X,d,)be a partially ordered complete metric space such that X is regular.Let f,g,S,T:X→X be given mappings satisfying the following:
(i) fX⊆TX,gX⊆SX,
(ii) SXandTXare closed subsets of(X,d), (iii) pairs(f,S)and(g,T)are weakly compatible,
Suppose that for every x,y∈X such that Sx and Ty are comparable, ()holds.Then the pairs(f,S)and(g,T)have a coincidence point u∈X.
In this paper, an attempt is made to derive some coincidence and common fixed point theorems for four mappings on complete ordered metric spaces, satisfying a (ψ,α,β )-weak contractive condition, which generalizes the existing results. Our results are sup-ported by some examples.
2 Coincidence and common fixed point results We begin our study with the following result.
Theorem . Let(X,d,)be a partially ordered complete metric space.Let f,g,S,T:X→ X be given mappings satisfying:
(i) fX⊆TX,gX⊆SX,
(ii) f,g,SandT are continuous,
(iii) the pairs(f,S)and(g,T)are compatible,
(iv) (f,g)is partially weakly increasing with respect toTand(g,f)is partially weakly increasing with respect toS.
Suppose that for every x,y∈X such that Sx and Ty are comparable,we have
ψd(fx,gy)≤αM(x,y)–βN(x,y), ()
where
M(x,y) =max
d(Sx,Ty),d(Sx,fx),d(Ty,gy),
d(Sx,gy) +d(fx,Ty),
N(x,y) =maxd(Sx,Ty),d(Sx,fx),d(Ty,gy) ,
and ψ,α,β : [, +∞)→[, +∞) are such that ψ is a continuous and monotone non-decreasing function,αis an upper semi-continuous function,βis a lower semi-continuous function and for all t> ,
ψ(t) –α(t) +β(t) > . ()
Then the pairs(f,S)and(g,T)have a coincidence point u∈X;that is,fu=Su and gu=Tu.
Moreover,if Su and Tu are comparable,then u∈X is a coincidence point of f,g,S and T.
Proof Letxbe an arbitrary point inX. SincefX⊆TX, there existsx∈Xsuch thatTx=
fx. SincegX⊆SX, there existsx∈Xsuch thatSx=gx. Continuing this process, we
can construct sequences{xn}and{yn}inXdefined by
yn=fxn=Txn+, yn+=gxn+=Sxn+, ∀n∈N∪ {}. ()
By construction we havexn+∈T–(fxn). Then, using the fact that (f,g) is partially weakly increasing with respect toT, we obtain
On the other hand, we havexn+∈S–(gxn+). Then, using the fact that (g,f) is partially
weakly increasing with respect toS, we obtain
Sxn+=gxn+fxn+=Txn+, ∀n∈N∪ {}.
Therefore, we can then write
TxSxTx · · · Txn+Sxn+Txn+ · · ·
or
yyy · · · ynyn+yn+ · · ·. ()
We will prove our result in four steps. Step .
lim
n→∞d(yn,yn+) = . ()
SinceSxnandTxn+are comparable, by applying inequality (), we have
ψd(yn,yn+)
=ψd(fxn,gxn+)
≤αM(xn,xn+)
–βN(xn,xn+)
, ()
where
M(xn,xn+) =max
d(Sxn,Txn+),d(Sxn,fxn),d(Txn+,gxn+),
d(Sxn,gxn+) +d(fxn,Txn+)
=max
d(yn–,yn),d(yn–,yn),d(yn,yn+),
d(yn–,yn+) +d(yn,yn)
=max
d(yn–,yn),d(yn,yn+),
d(yn–,yn+)
.
Sinced(yn–,yn+)≤[d(yn–,yn) +d(yn,yn+)], it follows that
M(xn,xn+) =max
d(yn–,yn),d(yn,yn+) ()
and
N(xn,xn+) =max
d(Sxn,Txn+),d(Sxn,fxn),d(Txn+,gxn+)
=maxd(yn–,yn),d(yn–,yn),d(yn,yn+)
Ifd(yn–,yn) <d(yn,yn+), then it follows from () and () that
M(xn,xn+) =N(xn,xn+) =d(yn,yn+).
Therefore, () implies that
ψd(yn,yn+)
≤αd(yn,yn+)
–βd(yn,yn+)
. ()
By (), we haved(yn,yn+) = ; that is,yn=yn+, and consequently we obtain
M(xn+,xn+) =N(xn+,xn+) =d(yn+,yn+).
Now, by applying inequality (), we have
ψd(yn+,yn+)
=ψd(fxn+,gxn+)
≤αM(xn+,xn+)
–βN(xn+,xn+)
=αd(yn+,yn+)
–βd(yn+,yn+)
,
and () implies thatd(yn+,yn+) = ; that is,yn+=yn+. Repeating the above process
inductively, one obtainsyk=ynfor allk≥n, which implies that () holds. On the other hand, if
d(yn,yn+)≤d(yn–,yn), ()
by a similar calculation we obtain
d(yn+,yn+)≤d(yn,yn+). ()
Thus by () and () we obtain
d(yn+,yn+)≤d(yn,yn+),
which implies that the sequence {d(yn,yn+)} is monotonically non-increasing. Hence,
there existsr≥ such that
lim
n→∞d(yn,yn+) =r.
Taking the upper limit on both sides of () and using (), (), the upper semi-continuity ofα, the lower semi-continuity ofβand the continuity ofψ, we obtainψ(r)≤α(r) –β(r), which by () implies thatr= . So equation () holds and the proof of Step is completed. Step . We claim that{yn}is a Cauchy sequence in X. By (), it suffices to show that the subsequence{yn}of{yn}is a Cauchy sequence inX. If not, then there exists> for which we can find two subsequences{ym(k)}and{yn(k)}of{yn}such thatn(k) is the smallest integer and, for allk> ,
This means that
d(ym(k),yn(k)–) <. ()
Therefore we use (), () and the triangular inequality to get
≤d(ym(k),yn(k))≤d(ym(k),yn(k)–) +d(yn(k)–,yn(k)–) +d(yn(k)–,yn(k))
<+d(yn(k)–,yn(k)–) +d(yn(k)–,yn(k)).
Lettingk→ ∞in the above inequality and using (), we obtain
lim
k→∞d(ym(k),yn(k)) =. ()
Again, using the triangular inequality, we have
d(ym(k)–,yn(k)) –d(ym(k),yn(k))≤d(ym(k)–,ym(k)).
Letting againk→ ∞in the above inequality and using (), (), we get
lim
k→∞d(ym(k)–,yn(k)) =. ()
On the other hand we have
d(ym(k),yn(k))≤d(ym(k),yn(k)+) +d(yn(k)+,yn(k)).
Thanks to (), (), lettingk→ ∞, we have from the above inequality that
≤ lim
n→∞d(ym(k),yn(k)+). ()
Also, by the triangular inequality, we have
d(ym(k),yn(k))≤d(ym(k),ym(k)–) +d(ym(k)–,yn(k)+) +d(yn(k)+,yn(k)).
Letting againk→ ∞in the above inequality and using () and (), we obtain
≤ lim
k→∞d(ym(k)–,yn(k)+).
Similarly, we can show thatlimk→∞d(ym(k)–,yn(k)+)≤, so
lim
n→∞d(ym(k)–,yn(k)+) =. ()
From () we have
ψd(ym(k),yn(k)+)
=ψd(fxm(k),gxn(k)+)
≤αM(xm(k),xn(k)+)
–βN(xm(k),xn(k)+)
where
M(xm(k),xn(k)+) =max
d(Sxm(k),Txn(k)+),d(Sxm(k),fxm(k)),d(Txn(k)+,gxn(k)+),
d(Sxm(k),gxn(k)+) +d(fxm(k),Txn(k)+)
=max
d(ym(k)–,yn(k)),d(ym(k)–,ym(k)),d(yn(k),yn(k)+),
d(ym(k)–,yn(k)+) +d(ym(k),yn(k))
and
N(xm(k),xn(k)+) =max
d(Sxm(k),Txn(k)+),d(Sxm(k),fxm(k)),d(Txn(k)+,gxn(k)+)
=maxd(ym(k)–,yn(k)),d(ym(k)–,ym(k)),d(yn(k),yn(k)+) .
Sinceψis a non-decreasing function, () implies that
ψ()≤ψ
lim
k→∞d(ym(k),yn(k)+)
. ()
Taking the upper limit on both sides of () and using (), (), (), (), () and the upper semi-continuity ofα, the lower semi-continuity ofβ and the continuity ofψ, we obtain
ψ()≤α
max
, , , (+)
–βmax{, , }.
By (), we have= , which is a contradiction. Thus{yn}is a Cauchy sequence inX, and hence{yn}is a Cauchy sequence.
Step . Existence of a coincidence point for (f,S) and (g,T). From the completeness of (X,d), there isu∈Xsuch that
lim
n→∞yn=u. ()
From () and (), we obtain
d(Sxn,u)→, d(fxn,u)→,
d(Sxn+,u)→, d(gxn+,u)→, d(Txn+,u)→.
()
Since the pairs (f,S) and (g,T) are compatible,
dS(fxn),f(Sxn)
→, dT(gxn+),g(Txn+)
→. ()
Using the continuity off,g,S,Tand (), we have
df(Sxn),fu
→, dg(Txn+),gu
→,
dS(Txn+),Su
→, dT(Sxn+),Tu
→.
The triangular inequality and () yield
d(Su,fu)≤dSu,S(Txn+)
+dS(fxn),f(Sxn)
+df(Sxn),fu
,
d(Tu,gu)≤dTu,T(Sxn+)
+dT(gxn+),g(Txn+)
+dg(Txn+),gu
.
Takingn→ ∞and using () and (), we obtain
d(Su,fu)≤, d(Tu,gu)≤,
which means thatSu=fuandTu=gu.
Step . The existence of a coincidence point forf,g,SandT. SinceSuandTuare comparable, we can apply inequality ()
ψd(fu,gu)≤αM(u,u)–βN(u,u),
where
M(u,u) =max
d(Su,Tu),d(Su,fu),d(Tu,gu),
d(Su,gu) +d(fu,Tu)
=max
d(Su,Tu), , ,
d(Su,Tu) +d(Su,Tu)=d(Su,Tu)
and
N(u,u) =maxd(Su,Tu),d(Su,fu),d(Tu,gu)
=maxd(Su,Tu), , =d(Su,Tu).
Therefore we have
ψd(Su,Tu)≤αd(Su,Tu)–βd(Su,Tu).
By (), we haved(Su,Tu) = ; that is,Su=Tu. Thereforeuis a coincidence point off,g,S
andT.
Now, we relax the conditions of Theorem ., the continuity off,g,SandT and the compatibility of the pairs (f,S) and (g,T), and we replace them by other conditions in order to find the same result. This will be the purpose of the next theorems.
Theorem . Let(X,d,)be a partially ordered complete metric space such that X is regular.Let f,g,S,T:X→X be given mappings satisfying:
(i) fX⊆TX,gX⊆SX,
(ii) SXandTXare closed subsets of(X,d), (iii) pairs(f,S)and(g,T)are weakly compatible,
(iv) (f,g)is partially weakly increasing with respect toTand(g,f)is partially weakly increasing with respect toS.
Then the pairs(f,S)and(g,T)have a coincidence point u∈X;that is,fu=Su and gu=
Tu.Moreover,if Su and Tu are comparable,then u∈X is a coincidence point of f,g,S and T.
Proof We take the same sequences{xn}and{yn}as in the proof of Theorem .. In partic-ular,{yn}is a Cauchy sequence in (X,d). Hence, there existsv∈Xsuch that
lim
n→∞yn=v. ()
SinceSXandTXare closed subsets of (X,d), there existu,u∈Xsuch that
yn=Txn+→Tu, yn+=Sxn+→Su.
Thereforev=Tu=Su.
Since{yn}is a non-decreasing sequence andXis regular, it follows from () thatynv for alln∈N∪ {}. Hence,
Txn+=ynv=Su.
Applying inequality (), we have
ψd(fu,yn+)
=ψd(fu,gxn+)
≤αM(u,xn+)
–βN(u,xn+)
, ()
where
M(u,xn+) =max
d(Su,Txn+),d(Su,fu),d(Txn+,gxn+),
d(Su,gxn+) +d(fu,Txn+)
=max
d(v,yn),d(v,fu),d(yn,yn+),
d(v,yn+) +d(fu,yn)
and
N(u,xn+) =max
d(Su,Txn+),d(Su,fu),d(Txn+,gxn+)
=maxd(v,yn),d(v,fu),d(yn,yn+) .
Lettingn→ ∞in () and using (), we obtain
ψd(fu,v)≤α
max
,d(v,fu), ,
+d(fu,v)–βmax,d(v,fu),
or
By (), we haved(v,fu) = , and hencev=fu. Similarly, we have
Sxn=yn–v=Tu.
Therefore we can apply inequality () to obtain
ψd(yn,gu)
=ψd(fxn,gu)
≤αM(xn,u)
–βN(xn,u)
, ()
where
M(xn,u) =max
d(Sxn,Tu),d(Sxn,fxn),d(Tu,gu),
d(Sxn,gu) +d(fxn,Tu)
=max
d(yn–,v),d(yn–,yn),d(v,gu),
d(yn–,gu) +d(yn,v)
and
N(xn,u) =max
d(Sxn,Tu),d(Sxn,fxn),d(Tu,gu)
=maxd(yn–,v),d(yn–,yn),d(v,gu) .
Lettingn→ ∞in () and using (), we obtain
ψd(v,gu)≤α
max
, ,d(v,gu),
d(v,gu) + –βmax, ,d(v,gu)
or
ψd(v,gu)≤αd(v,gu)–βd(v,gu).
By (), we haved(v,gu) = and hencev=gu. Therefore we have obtained
v=Su=fu, v=Tu=gu.
Now, if (f,S) and (g,T) are weakly compatible, thenfv=fSu=Sfu=Svandgv=gTu=
Tgu=Tv, andvis a coincidence point of (f,S) and (g,T).
The rest of the conclusion follows as in the proof of Theorem ..
Definition .([]) Let (X,d) be a metric space andf,g:X→Xbe given self-mappings onX. The pair (f,g) is said to be semi-compatible if the two conditions hold:
(i) ft=gtimpliesfgt=gft,
(ii) limn→∞fxn=limn→∞gxn=tfor somet∈X, implieslimn→∞fgxn=gt.
Definition . ([]) Let (X,d) be a metric space and f,g : X → X be given self-mappings on X. The pair (f,g) is said to be reciprocally continuous iflimn→∞fgxn=ft andlimn→∞gfxn=gtwhenever{xn}is a sequence such thatlimn→∞fxn=limn→∞gxn=t for somet∈X.
Definition .([]) Let (X,d) be a metric space andf,g:X→Xbe given self-mappings onX. The pair (f,g) is said to bef-weak reciprocally continuous iflimn→∞fgxn=ft when-ever{xn}is a sequence such thatlimn→∞fxn=limn→∞gxn=tfor somet∈X.
In the next theorem, the concepts of semi-compatibility andf-weakly reciprocal conti-nuity are used.
Theorem . Let(X,d,)be a partially ordered complete metric space.Let f,g,S,T:X→ X be given mappings satisfying:
(i) fX⊆TX,gX⊆SX,
(ii) the pair(f,S)isf-weak reciprocally continuous and semi-compatible, (iii) the pair(g,T)isg-weak reciprocally continuous and semi-compatible,
(iv) (f,g)is partially weakly increasing with respect toTand(g,f)is partially weakly increasing with respect toS.
Suppose that for every x,y∈X such that Sx and Ty are comparable, ()holds.
Then the pairs(f,S)and(g,T)have a coincidence point u∈X;that is,fu=Su and gu=
Tu.Moreover,if Su and Tu are comparable,then u∈X is a coincidence point f,g,S and T.
Proof We take the same sequences{xn}and{yn}as in the proof of Theorem .. In partic-ular,{yn}is a Cauchy sequence in (X,d). Hence, there existsu∈Xsuch that
lim
n→∞yn=u. ()
From () and (), we obtain
d(Sxn,u)→ and d(fxn,u)→.
Hence by (ii) we deduce that
lim
n→∞fSxn=fu and n→∞limfSxn=Su,
which implies thatfu=Su. Similarly, we can apply () and () to obtain
d(gxn+,u)→ and d(Txn+,u)→.
Hence by (iii) we deduce that
lim
n→∞gTxn+=gu and n→∞limgTxn+=Tu,
which implies thatgu=Tu. Therefore, we have proved thatuis a coincidence point of (f,S) and (g,T).
Now, we shall prove the existence and uniqueness theorem of a common fixed point.
Theorem . If,in addition to the hypotheses of Theorems., .and.,we suppose that Tu with Tu and Su with Su are comparable,where u is a coincidence point of f,g,S and T,then f,g,S and T have a common fixed point in X.Moreover,if a set of fixed points of one of the mappings f,g,S and T is totally ordered,then f,g,S and T have a unique common fixed point.
Proof We set
w:=Su=fu=Tu=gu. ()
Since the pair (g,T) is compatible in Theorem ., the pair (g,T) is weakly compatible in Theorem . and the pair (g,T) is semi-compatible in Theorem ., we have
gw=gTu=Tgu=Tw. ()
SinceTuandTTuare comparable, it follows thatSuandTware comparable. Applying inequality () and using () and (), we obtain
ψd(w,gw)=ψd(fu,gw)≤αM(u,w)–βN(u,w), ()
where
M(u,w) =max
d(Su,Tw),d(Su,fu),d(Tw,gw),
d(Su,gw) +d(fu,Tw)
=max
d(w,gw),d(w,w),d(gw,gw),
d(w,gw) +d(w,gw)
=maxd(w,gw), , ,d(w,gw) =d(w,gw)
and
N(u,w) =maxd(Su,Tw),d(Su,fu),d(Tw,gw)
=maxd(w,gw),d(w,w),d(gw,gw) =d(w,gw).
Therefore, () implies that
ψd(w,gw)≤αd(w,gw)–βd(w,gw).
By (), we haved(w,gw) = , that is,w=gw. Then, by (), we have
w=gw=Tw. ()
Similarly, we can show that
Hence, by () and (), we deduce thatw=fw=gw=Sw=Tw. Thereforewis a common fixed point off,g,SandT.
Now, suppose that the set of fixed points offis totally ordered. Assume on the contrary thatfp=gp=Sp=Tp=pandfq=gq=Sq=Tqbutp=q. Sincepandqcontain a set of fixed points off, we obtainp=Spandq=Tqare comparable, by inequality (), we have
ψd(p,q)=ψd(fp,gq)≤αM(p,q)–βN(p,q), ()
where
M(p,q) =max
d(Sp,Tq),d(Sp,fp),d(Tq,gq),
d(Sp,gq) +d(fp,Tq)
=max
d(p,q),d(p,p),d(q,q),
d(p,q) +d(p,q)=d(p,q)
and
N(p,q) =maxd(Sp,Tq),d(Sp,fp),d(Tq,gq)
=maxd(p,q),d(p,p),d(q,q) =d(p,q).
Therefore, () implies that
ψd(p,q)≤αd(p,q)–βd(p,q),
by (),d(p,q) = , a contradiction. Thereforef,g,SandT have a unique common fixed point. Similarly, the result follows when the set of fixed points ofg,SorTis totally ordered.
This completes the proof of Theorem ..
3 Some examples
In this section we present some examples which illustrate our results.
Now, we present an example to illustrate the obtained result given by the previous the-orems.
Example . LetX= [, +∞). We define an orderonXasxyif and only if x≥y
for allx,y∈X. We take the usual metricd(x,y) =|x–y|forx,y∈X. It is easy to see that (X,d,) is a partially ordered complete metric space. Letf,g,S,T:X→Xbe defined by
fx=ln( +x), gx=ln
+x
, Sx=ex– , Tx=ex– .
Defineψ,α,β: [, +∞)→[, +∞) byψ(t) =t,
α(t) =
t if ≤t< ,
t+
ift≥
and β(t) =
if ≤t≤,
ift> .
Proof The proof of (i) and (ii) is clear. To prove (iii), let{xn}be any sequence inXsuch that
lim
n→∞fxn=n→∞limSxn=t
for somet∈X. Sincefxn=ln( +xn) andSxn=exn– , we havexn→et– andxn→
ln( +t). By the uniqueness of limit, we get thatet– =
ln( +t) and hencet= . Thus, xn→ asn→ ∞. Sincef andSare continuous, we havefxn→f = andSxn→S = asn→ ∞. Therefore,
lim n→∞d
S(fxn),f(Sxn)
=d(S,f) =d(, ) = .
Thus, the pair (f,S) is compatible. Similarly, one can show that the pair (g,T) is compatible. To prove that (f,g) is partially weakly increasing with respect toT, letx,y∈Xbe such thaty∈T–(fx). ThenTy=fx. By the definition off andT, we haveln( +x) =ey– . So, we havey=ln( +ln( +x)). Now, sinceex– ≥x≥x≥ln( +x), we have
+x≥ + ln
+ln( +x)
or
fx=ln( +x)≥ln
+ ln
+ln( +x)=ln
+y
=gy.
Therefore, fxgy. Thus, we have proved that (f,g) is partially weakly increasing with respect toT. Similarly, one can show that (g,f) is partially weakly increasing with respect toS.
Now, we prove thatψ,αandβdo satisfy the inequality of (). Ift> , thenψ(t) –α(t) + β(t) =t–t–+ =t> ; ift= , thenψ() –α() +β() = – –= > . And if ≤t< , thenψ(t) –α(t) +β(t) =t–t=t> .
In order to show thatf,g,S,T,ψ,αandβ do satisfy the contractive condition () in Theorem ., using a mean value theorem, we have, forx,y∈X,
|fx–gy|=ln( +x) –ln
+y
≤
|x–y| ≤ e
x–ey=
|Sx–Ty| ≤ M(x,y).
Then the following cases are possible. Case I.M(x,y)≥.
In this case, we haveN(x,y) > orN(x,y)≤. IfN(x,y) > , thenα(M(x,y)) =M(x,y) + andβ(N(x,y)) =. Therefore, we have
ψd(fx,gy)=|fx–gy| ≤
M(x,y) =
M(x,y) + –
=α
M(x,y)–βN(x,y).
IfN(x,y)≤, thenα(M(x,y)) =M(x,y) + andβ(N(x,y)) = . Therefore, we have
ψd(fx,gy)=|fx–gy| ≤
M(x,y) <
M(x,y) + – =α
M(x,y)–βN(x,y).
Case II.M(x,y) < .
In this case, sinceN(x,y)≤M(x,y), we obtainN(x,y) < . Therefore, we haveα(M(x,y)) =
M(x,y) andβ(N(x,y)) = . So, we obtain
ψd(fx,gy)=|fx–gy| ≤
M(x,y) – =α
M(x,y)–βN(x,y).
Therefore in this case () is satisfied.
Thus,f,g,S,T,ψ andϕ satisfy all the hypotheses of Theorems .. Therefore,f,g,S
andThave a coincidence point. Moreover, sincef,g,SandTsatisfy all the hypotheses of Theorem ., we obtain thatf,g,SandT have a unique common fixed point. In fact, is the unique common fixed point off,g,SandT.
Clearly, the above example satisfies all the hypotheses of Theorem ..
Example . LetX={, , , }. Letd:X×X→Rbe given as
d(x,y) =
, x=y,
x+y, x=y
and:={(, ), (, ), (, ), (, ), (, ), (, ), (, )}onX. Clearly, (X,d,) is a partially or-dered complete metric space.
Let{xn}be a non-decreasing sequence inXwith respect tosuch thatxn→x. By the definition of metricd, there existsk∈Nsuch thatxn=xfor alln≥k. So (X,d,) is regular.
Letψ,α,β: [,∞)→[,∞) be defined byψ(t) =t,
α(t) =
t+
t, t≥,
, t< and β(t) =
t, t> , +t, t≤
and self-mapsf,g,SandTonXbe given by
f =
, g=
,
S=
, T=
.
It is easy to see thatf,g,SandTsatisfy all the conditions given in Theorem .. Thus , and are coincidence points of the pairs (f,S) and (g,T). SinceS = andT = are comparable, is a coincidence pointf,g,SandT. Moreover, sinceS = andSS = are not comparable, so Theorem . is not applicable for this example. It is observed that is not a common fixed pointf,g,SandT.
4 Application: existence of a common solution to integral equations Consider the integral equations:
x(t) =
b
a
Kt,s,x(s)ds,
x(t) =
b
a
Kt,s,x(s)ds,
whereb>a≥. The purpose of this section is to give an existence theorem for a solution of () using Theorem . or ..
Theorem . Consider the integral equations().
(i) K,K: [a,b]×[a,b]×R→Rare continuous; (ii) for allt,s∈[a,b],
K
t,s,x(s)≤K
t,s,
b
a
K
s,τ,x(τ)dτ
,
Kt,s,x(s)≤K
t,s,
b
a
Ks,τ,x(τ)dτ
,
(iii) for alls,t∈[a,b]and comparableu,v∈R,
K(t,s,u) –K(t,s,v)≤p(t,s)log +|u–v|,
wherep: [a,b]×[a,b]→[, +∞)is a continuous function satisfying
sup a≤t≤b
b
a
p(s,t)ds<
b–a.
Then integral equations()have a solution x∈C[a,b].
Proof LetX:=C[a,b] (the set of continuous functions defined onC[a,b] and taking value inR) with the usual supremum norm, that is,x=supa≤t≤b|x(t)|, forx∈C[a,b]. Consider onXthe partial order defined by
x,y∈X, xy ⇐⇒ x(t)≤y(t), ∀t∈[a,b].
Then (X,) is a partially ordered set and regular. Also (X, · ) is a complete metric space. Definef,g:X→Xby
fx(t) =
b
a
Kt,s,x(s)ds, ∀t∈[a,b]
and
gx(t) =
b
a
Kt,s,x(s)ds, ∀t∈[a,b].
Now, letx,y∈Xsuch thatxy. From condition (iii), for allt∈[a,b], we can write
fx(t) –gy(t)≤
b
a
Kt,s,x(s)–Kt,s,y(s)ds
≤ b
a ds
b
a
Kt,s,x(s)–Kt,s,y(s)ds
≤(b–a)
b
a
≤(b–a)
b
a
p(t,s)log +d(x,y)ds
= (b–a)
b
a
p(t,s)ds
log +d(x,y)
< log +d(x,y)≤log +M(x,y)
= M(x,y)
–M(x,y)–log +M(x,y).
SinceM(x,y)≥N(x,y) andφ(t) =t–log( +t) is a non-decreasing function in [,∞),
we have
sup a≤t≤b
fx(t) –gy(t)≤ M(x,y)
–N(x,y)–log +N(x,y).
Putψ(t) =t,α(t) =
tandβ(t) =t–log( +t), we get
ψd(fx,gy)≤αM(x,y)–βN(x,y),
andψ(t) –α(t) +β(t) > for eacht> . By takingS=T =IX (the identity mapping on
X), all the required hypotheses of Theorem . (or Theorem .) are satisfied. Then there existsx∈X, a common fixed point off andg, that is,xis a solution to ().
Competing interests
The authors declare that they have no competing interests.
Authors’ contributions
All authors conceived of the study, participated in its design and coordination, drafted the manuscript, participated in the sequence alignment, and read and approved the final manuscript.
Author details
1Department of Mathematics, Science and Research Branch, Islamic Azad University (IAU), Tehran, Iran.2Department of
Mathematics and Computer Science, Amirkabir University of Technology, Hafez Ave., P.O. Box 15914, Tehran, Iran.
3Department of Mathematics, Iran University of Science and Technology, Tehran, Iran.4Department of Mathematics,
Research Institute for Natural Sciences, Hanyang University, Seoul, 133-791, Republic of Korea.
Received: 12 August 2014 Accepted: 9 December 2014 Published:23 Dec 2014
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10.1186/1029-242X-2014-517