–Factorization of Symmetric Complete
Bipartite Digraph
U S Ra jput
Department of mathematics and astronomy, Lucknow University,
Bal Go vind Shukla
Department of mathematics and astronomy, Lucknow University
,
ABSTRACT
In path factorization, Ushio [1] gave the necessary and sufficient conditions for -design when k is odd.
-factorization of a complete bipartite graph for an integer, was studied by Wang [2]. Further, Beiling [3] extended the work of Wang [2], and studied -factorization of complete bipartite multigraphs. For even value of in -factorization the spectrum problem is completely solved [1, 2, 3]. However, for odd value of k i.e. and , the path
factorization have been studied by a number of researchers [4, 5, 6, 7, 8]. The necessary and sufficient conditions for the existence of -factorization of symmetric complete bipartite digraph were given by Du B [9]. Earlier we have discussed the necessary and sufficient conditions for the existence of and -factorization of symmetric complete bipartite digraph [10, 11]. Now, in the present paper, we give the necessary and sufficient conditions for the existence of factorization of symmetric complete bipartite digraph, .
Mathemati cal
Clas sificati on
- 6 8 R 1 0 , 0 5 C 7 0 , 0 5 C 3 8 .Key words
– Complete bipartite Graph, Factorization of Graph, Spanning Graph.Introdu cti on:
Let be a complete bipartite symmetric digraph with two partite sets having and vertices. A spanning sub graph of is called a path factor if each component of is a path of order at least two. In particular, a spanning sub graph of is called a factor if each component of is isomorphic to . If is expressed as an arc disjoint sum of factors, then this sum is called
factorization of . Here, we take path of order 9. A is the symmetric directed path on vertices.
Mathemati cal Analysis:
The necessary and sufficient conditions for the existence of factorization of complete bipartite symmetric digraph are given below in theorem 1.
Theorem 1:
Let be the positive integers. Then has a factorization iff:1. 2.
3.
4. is an integer
Proof of n ecessi ty
Proof: Let be the number of factors in the
factorization, and be the number of copies of in a factor. Since any –factor spans , hence the
number of copies of in any factor,
. … (1 )
Since every –factor has symmetric
edges in a factorization, therefore total number of edges in symmetric complete bipartite digraph will be,
Also, since total number of edges in a symmetric complete bipartite digraph are therefore,
H e n c e ,
. … ( 2 )
Obviously, and will be integers. Thus conditions 3 and 4 in theorem 1 are necessary. In a particular
its end points in , and with end points in , then by simple arithmetic we can obtain,
and
From this, we can compute and , which are as follows:
… (3) ... (4). Since, by definition and are positive integers, therefore equations (3) and (4) imply,
and
This implies
and
Therefore, conditions 1 and 2 in theorem 1 are necessary.
This proves the necessity of theorem 1.
Proof of sufficien cy
Further, we need the following number theoretic result (lemma 1) to prove the sufficiency of theorem 1. The proof of lemma 1 can be found in any good text related to elementary number theory, one such is given in [12].
Lem m a 1:
If gcd then gcdwhere and are positive integers. We prove the following result (lemma 2), which will be used further.
Lem m a 2:
If has -factorization, thenhas a -factorization for every positive
integer .
Proof: Let is 1- factorable [13] and { }
be a 1- factorization of it. For each with replace every edge of by a to get a spanning subgraph of , such that the graphs
are pair wise edge disjoint, and there union is . Since has a -factorization, it
is clear that is also , and hence
is -
Now to prove the sufficiency of theorem 1, there are three cases to consider:
Case I: . In this case from lemma 2, has
-factorization. For instance (trivial case) has
-factorization. These factorizations are illustrated in figure from 1 to 5.
F i g ( 1 )
F i g ( 2 ) y1x2y2x3y3x4y4x5y5 , y5x5y4x4y3x3y2x2y1; y6x6y7x7y8x8y9x1y1 0, y1 0x1y9x8y8x7y7x6y6:
.
F i g ( 3 ) y1x3y2x4y3x5y4x6y5 , y5x6y4x5y3x4y2x3y1; y6x7y7x8y8x1y9x2y1 0, y1 0x2y9x1y8x8y7x7y6:
F i g ( 5 ) y1x4y2x5y3x6y4x7y5 , y5x7y4x6y3x5y2x4y1; y6x8y7x1y8x2y9x3y1 0, y1 0x3y9x 2 y8x1y7x8y6: .
C a s e I I : . O b v i o u s l y , h a s
-f a c t o r i z a t i o n .
C a s e I I I : a n d . I n t h i s c a s e , l e t
,
a n d
T h e n f r o m c o n d i t i o n s 1 - 4 o f t h e o r e m ( 1 ) ,
a r e i n t e g e r s a n d , . A s o b t a i n e d p r e v i o u s l y
a n d
. H e n c e ,
S i n c e i s a p o s i t i v e i n t e g e r , t h e r e f o r e ,
( s a y )
mu s t b e p o s i t i v e i n t e g e r .
A g a i n l e t t h e n a n d
w h e r e a r e i n t e g e r s a n d g c d . T h e n b e c o m e s
T h e s e e q u a l i t i e s i mp l y t h e f o l l o w i n g e q u a l i t i e s
T o c o mp u t e a l l p o s s i b l e v a l u e s o f a n d f o r c a s e ( I I I ) , w e e s t a b l i s h t h e f o l l o w i n g l e m m a , l e m m a 3 .
Lem m a 3:
C a s e ( 1 ) : I f g c d a n d g c d t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r s u c h t h a t
a n d
C a s e ( 2 ) : I f g c d a n d g c d a n d l e t , t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r s u c h t h a t
a n d
C a s e ( 3 ) : I f g c d a n d g c d
a n d l e t , t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r , s u c h t h a t
a n d
C a s e ( 4 ) : I f g c d a n d g c d a n d l e t t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r s u c h t h a t
a n d
.
C a s e ( 5 ) : I f g c d a n d g c d (q, 2 5 ) = 5 , a n d l e t t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r s u c h t h a t
a n d
C a s e ( 6 ) : I f g c d a n d g c d a n d l e t t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r s u c h t h a t
a n d
C a s e ( 7 ) : I f g c d a n d g c d a n d l e t t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r s u c h t h a t
a n d
C a s e ( 8 ) : I f g c d g c d a n d l e t t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r s u c h t h a t
a n d
C a s e ( 9 ) : I f g c d g c d a n d l e t , t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r , s u c h t h a t
a n d
C a s e ( 1 0 ) : I f g c d g c d a n d l e t , t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r , s u c h t h a t
a n d
C a s e ( 1 1 ) : I f g c d g c d a n d l e t t h e n t h e r e e x i s t s a
p o s i t i v e i n t e g e r , s u c h t h a t
a n d
C a s e ( 1 2 ) : I f g c d g c d a n d l e t , t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r , s u c h t h a t
a n d
C a s e ( 1 3 ) : I f g c d g c d a n d l e t , t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r , s u c h t h a t
a n d C a s e ( 1 4 ) : I f g c d g c d
a n d l e t , t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r , s u c h t h a t
a n d
C a s e ( 1 5 ) : I f g c d g c d a n d l e t , t h e n t h e r e e x i s t s a p o s i t i v e i n t e g e r s u c h t h a t
a n d
P r o o f : L e t g c d g c d a n d g c d h o l d .
T h e n g c d = g c d .
S i n c e g c d a n d g c d ,
h e n c e
g c d a n d g c d .
S i n c e
i s a p o s i t i v e i n t e g e r . T h e r e f o r e b y l e m m a 2 . 2 , w e s e e t h a t
g c d = g c d .
H e n c e mu s t b e a n i n t e g e r , w h e r e :
.
T h e r e f o r e , w i l l b e a p o s i t i v e i n t e g e r , w h e r e :
S i mi l a r l y a l l v a l u e s o f a n d r a r e p o s i t i v e i n t e g e r s i n c a s e ( 1 ) o f l e m m a 3 .
T h e p r o o f s o f o t h e r e q u a l i t i e s i n l e m m a 3 a r e s i m i l a r t o c a s e ( 1 ) .
T h i s p r o v e s l e m m a 3 .
B e l o w i n l e m m a 4 , w e g i v e t h e c o n s t r u c t i o n o f
-f a c t o r o f c o m p l e t e b i p a r t i t e s y m m e t r i c d i g r a p h ( f o r c a s e I I I o n l y ) , b y t a k i n g t h e v a l u e s o f a n d f r o m c a s e 1 o f l e m m a 3 a t
.
Lem m a (4 ) : -
L e t , a n d
b e p o s i t i v e i n t e g e r s , t h e n
h a s -f a c t o r i z a t i o n .
P r o o f : - F o r g i v e n v a l u e s o f a n d w e h a v e
n u mb e r o f c o p i e s o f , w i t h i t s e n d p o i n t s i n Y i n a p a r t i c u l a r - f a c t o r , a n d
n u mb e r o f c o p i e s o f , w i t h i t s e n d p o i n t s i n X i n a p a r t i c u l a r - f a c t o r .
H e n c e t o t a l n u m b e r o f c o p i e s o f
a n d t h e n u mb e r o f - f a c t o r s
w h e r e
a n d
H e r e X , Y a r e t w o p a r t i t e s e t s o f a s ,
a n d
w i t h
a n d
N o w f o r e a c h l e t b e t h e s e t o f g r a p h s w i t h e n d p o i n t s i n Y , s u c h t h a t
w h e r e
F o r e a c h l e t b e a s e t o f g r a p h s
w i t h e n d p o i n t s i n X , s u c h t h a t
= { x5p + 5 ( i - 1 ) + 2 ( u - 1 ) + v , j + 2 ( 5p + 4q) v + 3 ( 5 p + 4 q ) w + ( 5 p + 4 q ) t y2 5p + 1 6 ( i - 1 ) + 4 u + 2 v + w + 1 , j + 1 0p+ 8 ( i - 1 ) + 2 u + v + w} ,
w h e r e
1 ≤ j ≤ 2 ( 5p + 4q), 1 ≤ u ≤3 , 0 ≤ v, w, t ≤1 . L e t O b v i o u s l y c o n t a i n s t
n u mb e r o f v e r t e x d i s j o i n t a n d e d g e d i s j o i n t c o mp o n e n t s s u c h t h a t
t = a + b
= 2 ( 5p + 4q) 2 = ( 5p + 4q) n
0 ,
A l s o s p a n s T h e n t h e g r a p h i s a -
f a c t o r o f . F u r t h e r , i n t h e g r a p h , e a c h o f t h e s e c o n d s u b s c r i p t o f s m e e t s
e a c h o f t h e s e c o n d s u b s c r i p t s o f s o n c e a n d
o n l y o n c e . Al s o i n g r a p h , t h e
s e c o n d s u b s c r i p t o f s m e e t s e a c h o f t h e
s e c o n d s u b s c r i p t s o f s o n c e a n d o n l y o n c e ,
F u r t h e r , i n t h e g r a p h , w e s e e t h a t e a c h o f t h e s e c o n d s u b s c r i p t o f s
c o n n e c t e a c h o f t h e s e c o n d s u b s c r i p t s o f s
o n c e a n d o n l y o n c e . H e n c e w e d e f i n e a b i j e c t i o n s u c h t h a t
:
onto
XUY
XUY
wi t h
a n d
f o r e a c h a n d e a c h
L e t
Fξ , η = { ξ( x) η( y ) ; x
X , y
Y , x y
F } b e t h e s e t o f g r a p h s , t h e n i t i s s h o w n t h a t t h e g r a p h s Fξ , η { 1 ≤ ξ ≤ r1, 1 ≤ ≤ r2} , a r e e d g e d i s j o i n t -f a c t o r s o f a n d t h e r e u n i o n i s.
T h u s { Fξ , η: 1 ≤ ξ ≤r1, 1 ≤ η ≤r2} i s a -f a c t o r i z a t i o n o -f .T h i s p r o v e s l e m m a ( 4 ) .
P roof of t heorem ( 1) :
C o mb i n i n g l e m m a s 2 t o 4 , i t c a n b e s e e n t h a t w h e n t h e p a r a m e t e r s a n d s a t i s f y c o n d i t i o n s ( 1 ) - ( 4 )i n t h e o r e m 1 , t h e g r a p h h a s -f a c t o r i z a t i o n .
Con clusion :
I n t h i s p a p e r , w e h a v e o b t a i n e d t h e c o n d i t i o n f o r p a t h f a c t o r i z a t i o n o f c o mp l e t e b i p a r t i t e s y m m e t r i c d i g r a p h w i t h 9 n u mb e r o f v e r t i c e s h a v i n g s y m m e t r i c d i s j o i n t e d g e s .R e f e r e n c e s
[ 1 ] U s h i o K : G - d e s i g n s a n d r e l a t e d d e s i g n s , D i s c r e t e M a t h . , 1 1 6 ( 1 9 9 3 ) , 2 9 9 - 3 1 1 . [ 2 ] W a n g H : - f a c t o r i z a t i o n o f a c o mp l e t e
b i p a r t i t e g r a p h , d i s c r e t e m a t h . 1 2 0 ( 1 9 9 3 ) 3 0 7 - 3 0 8 .
[ 3 ] B e i l i n g D u : - f a c t o r i z a t i o n o f c o m p l e t e
b i p a r t i t e m u l t i g r a p h . A u s t r a l a s i a n J o u r n a l o f C o m b i n a t o r i c s 2 1 ( 2 0 0 0 ) , 1 9 7 - 1 9 9 .
[ 5 ] W a n g J a n d D u B :
P
5 - f a c t o r i z a t i o n o f c o mp l e t e b i p a r t i t e g r a p h s . D i s c r e t e m a t h . 3 0 8 ( 2 0 0 8 ) 1 6 6 5 – 1 6 7 3 .[ 6 ] W a n g J :
P
7 - f a c t o r i z a t i o n o f c o mp l e t e b i p a r t i t e g r a p h s . Au s t r a l a s i a n J o u r n a l o f C o mb i n a t o r i c s , v o l u m e 3 3 ( 2 0 0 5 ) , 1 2 9 -1 3 7 .[ 7 ] U . S . R a j p u t a n d B a l Go v i n d S h u k l a :
9
P
f a c t o r i z a t i o n o f c o mp l e t e b i p a r t i t e g r a p h s . A p p l i e d M a t h e m a t i c a l S c i e n c e s , v o l u m e 5 ( 2 0 1 1 ) , 9 2 1 - 9 2 8 .[ 8 ] D u B a n d W a n g J : - f a c t o r i z a t i o n o f
c o mp l e t e b i p a r t i t e g r a p h s . S c i e n c e i n C h i n a S e r . A M a t h e m a t i c s 4 8 ( 2 0 0 5 ) 5 3 9 – 5 4 7 .
[ 9 ] D u B : - f a c t o r i z a t i o n o f c o mp l e t e b i p a r t i t e s y m m e t r i c d i g r a p h s .
Au s t r a l a s i a n J o u r n a l o f C o mb i n a t o r i c s , v o l u m e 1 9 ( 1 9 9 9 ) , 2 7 5 - 2 7 8 .
[ 1 0 ] U . S . R a j p u t a n d B a l G o v i n d S h u k l a :
f a c t o r i z a t i o n o f c o mp l e t e b i p a r t i t e s y m m e t r i c d i g r a p h . N a t i o n a l S e m i n a r o n “Cu rr en t Tr en d s in Mat h e mati cs wi th Sp eci al Fo cu s o n O.R. an d Co mp u t er s” , D . R . M . L . A . U . F a i z a b a d , I n d i a , ( 2 0 1 0 ) .
[ 1 1 ] U . S . R a j p u t a n d B a l G o v i n d S h u k l a :
f a c t o r i z a t i o n o f c o mp l e t e b i p a r t i t e s y m m e t r i c d i g r a p h . I n t e r n a t i o n a l M a t h e m a t i c a l F o r u m, v o l . 6 ( 2 0 1 1 ) , 1 9 4 9 -1 9 5 4 .
[ 1 2 ] D a v i d M . B u r t o n : E l e m e n t a r y N u mb e r T h e o r y . U B S P u b l i s h e r s N e w D e l h i , 2 0 0 4 .