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In the problems assume the parameter given in In the problems assume the parameter given in follo

following table. wing table. Use Use the the tempertemperatureature T T 

=

=

300 K unless300 K unless other

otherwise wise stated.stated. P Prrooppeerrtty y SSii GaAsGaAs GeGe B Baannddggaap p EEnneerrggy y 1.1.112 2 11..442 2 00..6666 D Diieelleeccttrriic c CCoonnssttaannt t 1111..7 7 1133..1 1 1166..00 Effective density of 

Effective density of  states in conduction states in conduction band band N N cc( ( cmcm--33)) 2 8 2 8 ..

´

´

10101919 4 7 4 7 ..

´

´

11001717 1 01 04 .. 4

´

´

11001919

Effective density of  Effective density of 

states in valence states in valence band band N N vv( ( cmcm )) --33 1 0 1 04 .. 4

´

´

11001919 7 0 7 0 ..

´

´

11001818 6 0 6 0 ..

´

´

11001818 Intrinsic carrier Intrinsic carrier concertration concertration n nii ( ( cmcm--33)) 1 5 1 5 ..

´

´

10101010 1 8 1 8 ..

´

´

110066 2 4 2 4 ..

´

´

11001818 Mobility Mobility Electron Electron Hole Hole 1350 1350 480 480 8500 8500 400 400 3900 3900 1900 1900 1.

1. In In germangermanium ium semicosemiconductonductor r materimaterial al atat T T 

=

=

400 K 400 K  the intrinsic concentration is

the intrinsic concentration is (

(A) A) 226 6 8 ..8

´

´

10101414 cmcm--33 (B(B) ) 18 18 ..4 4

´

´

10101414 cmcm--33 (

(CC) ) 8 5 8 5 ..

´

´

10101414 cmcm--33 ((DD) ) 3 6 3 6 ..

´

´

10101414 cmcm--33

2.

2. The intrinsic carrier concentration in silicon is to beThe intrinsic carrier concentration in silicon is to be no

no grgreaeateter r ththanan nnii

=

=

1 1

´

´

10101212 cmcm--33. . ThThe e mamaxiximumumm te

tempmpererataturure e alallolowewed d fofor r ththe e sisililicocon n is is (A(Assssumumee

 E

 E g g

=

=

1112..12 eV)eV) (

(AA) ) 33000 0 K K ((BB) ) 33660 0 K  K   (

(CC) ) 33882 2 K K ((DD) ) 33664 4 K  K  

3.

3. Two semiconductor material have exactly the sameTwo semiconductor material have exactly the same properties except that material A has a bandgap of 1.0 properties except that material A has a bandgap of 1.0

eV and material B has a bandgap energy of 1.2 eV. eV and material B has a bandgap energy of 1.2 eV. The

The ratratio io of of intintrinrinsic sic conconcencentratratiotion n of of matmaterierial al A A toto that of material B is that of material B is ( (AA) ) 2200116 6 ((BB) ) 4477..55 ( (CC) ) 5588..223 3 ((DD) ) 11004488 4.

4. In In sisililicocon n atat T T 

=

=

300 300 K K the the thethermarmal-el-equiquiliblibriuriumm concentration of electron is concentration of electron is nn00 4 4 5 5 1010

=

=

´

´

cmcm--33. The hole. The hole concen concentratitration on isis ( (AA) ) 4 5 4 5 ..

´

´

10101515cmcm--33 ((BB) ) 4 5 4 5 ..

´

´

10101515 mm--33 (C) (C) 0 0 ..3 3

´

´

1010--66 cmcm--33 (D)(D) 0 0 ..3 3

´

´

1010--66 mm--33 5.

5.In silicon atIn silicon atT T 

=

=

300300K if the Fermi energy is 0.22 eV K if the Fermi energy is 0.22 eV  above the valence band energy, the value of 

above the valence band energy, the value of  pp00 isis (

(AA) ) 2 2

´

´

11001515cmcm--33 (B) 10(B) 101515cmcm--33 (

(CC) ) 3 3

´

´

11001515cmcm--33 ((DD) ) 4 4

´

´

11001515 cmcm--33

6.

6. The thermal-equilibrium concentration of holeThe thermal-equilibrium concentration of hole pp00 inin silicon at

silicon at T T 

=

=

300300 K K isis 10101515cmcm--33. The value of . The value of nn00 isis (

(AA) ) 3 8 3 8 ..

´

´

101088 cmcm--33 ((BB) 4 ) 4 ..4 4

´

´

110044 cmcm--33 (

(CC) ) 2 2 6 ..6

´

´

101044 cmcm--33 ((DD) 4 ) 4 ..3 3

´

´

110088 cmcm--33

7.

7. In In gergermanmanium ium semsemicoicondunductoctor r atat T T 

=

=

300300 K, K, ththee accept

acceptor or concenconcentratiotrations ns isis N N aa

=

=

1010 13

13 cmcm--33 and and donodonorr con

concencentratratiotion n isis N N dd

=

=

0. 0. ThThe e ththerermamal l eqequiuililibrbriuiumm concentration concentration pp00 isis (A) (A) 2 92 97 .. 7

´

´

101099 cmcm--33 (B)(B) 2 2 6..68 8

´

´

11001212 cmcm--33 (C) (C) 2 92 95 .. 5

´

´

11001313 cmcm--33 (D)(D) 2 42 4. . cmcm--33 Statem

Statement for ent for Q.8-9:Q.8-9: In

In germangermanium semiconductium semiconductor or atat T T 

=

=

300300 K, theK, the impurity concentration are

impurity concentration are

 N   N dd

=

=

5 5

´

´

1010 15 15 cmcm--33 andand N  N aa

=

=

00 8.

8. The thermal equilibrium electron concentrationThe thermal equilibrium electron concentration nn00 is

(2)

(

(AA) ) 5 5

´

´

10101515cmcm--33 ((BB) ) 11115 .. 5

´

´

10101111 cmcm--33 (

(CC) ) 11115 .. 5

´

´

110099cmcm--33 (D(D) ) 5 5

´

´

110066 cmcm--33

9.

9. The thermal equilibrium hole concentrationThe thermal equilibrium hole concentration pp00 isis (

(AA) ) 39396 .. 6

´

´

11001313 ((BB) ) 19195 .. 5

´

´

10101313cmcm--33 (

(CC) 4 ) 4 3..36 6

´

´

11001212 cmcm--33 (D(D) ) 39396 .. 6

´

´

11001313cmcm--33

10.

10. A A sasampmple le of of sisililicocon n atat T T 

=

=

30300 0 K K is is dodopeped d wiwithth bo

bororon n at a at a coconcncenentrtratatioion n of 25 of 25 ..

´

´

10101313 cmcm--33 and and witwithh a

arrsseenniic c aat t a a ccoonncceennttrraattiioon n oof f 1 1

´

´

11001313 cmcm--33. . TThhee material is

material is (A)

(A) pp

-

-

type withtype with pp00

13 13 1 15 5 1100

=

=

. .

´

´

cmcm--33 (B)

(B) pp

-

-

type withtype with pp00

7 7 1 15 5 1100

=

=

. .

´

´

cmcm--33 (C)

(C) nn

-

-

type withtype with nn00

13 13 1 15 5 1100

=

=

. .

´

´

cmcm--33 (D)

(D) nn

-

-

type withtype with nn00

7 7 1 15 5 1100

=

=

. .

´

´

cmcm--33 11

11.. In In a a samsamplple e of of gagalllliuium m ararseseninide de atat T T 

=

=

20200 0 K,K,

n

n 0 0

=

=

55pp00 andand N N aa

=

=

0. The value of 0. The value of nn00 isis (A)

(A) 9 9 8..86 6

´

´

110099 cmcm--33 (B) 7(B) 7 cmcm--33 (C)

(C) 4 4 8..86 6

´

´

110033 cmcm--33 (D)(D) 3 cm3 cm--33

12.

12. Germanium atGermanium at T T 

=

=

300 K is uniformly doped with300 K is uniformly doped with an acceptor concentration of 

an acceptor concentration of N N aa

=

=

1010 15

15cmcm--33and a donorand a donor conce

concentratintration on of of  N N dd

=

=

00. The position of fermi energy. The position of fermi energy with respect to intrinsic Fermi level is

with respect to intrinsic Fermi level is ( (AA) ) 00..002 2 eeV V ((BB) ) 00..004 4 eeV  V   ( (CC) ) 00..006 6 eeV V ((DD))00..008 8 eeV  V   13. 13. IIn n ggeerrmmaanniiuum m aatt T T 

=

=

33000 0 KK, , ththe e ddoonnoorr conce

concentratintration on areare N N dd

=

=

1010 14 14

cm

cm--33 andand N N aa

=

=

0. 0. ThThee Fer

Fermi mi eneenergy rgy levlevel el witwith h respecrespect t to to intintrinrinsic sic FerFermimi level is level is ( (AA) ) 00..004 4 eeV V ((BB) ) 00..008 8 eeV  V   ( (CC) ) 00..442 2 eeV V ((DD) ) 00..886 6 eeV  V   14.

14.A GaAs device is doped with a donor concentrationA GaAs device is doped with a donor concentration o

of f 3 3

´

´

10101515cmcm--33. For the device to operate properly, the. For the device to operate properly, the intrinsic carrier concentration must remain less than intrinsic carrier concentration must remain less than 5%

5% of of ththe e tototatal l coconcncenentrtratatioion. n. ThThe e mamaxiximumumm temperature on that the device may operate is

temperature on that the device may operate is (

(AA) ) 77663 3 K K ((BB) ) 99442 2 K  K   (

(CC) ) 44886 6 K K ((DD) ) 22443 3 K  K  

15.

15. FoFor r a a papartrticiculular ar sesemimicocondnducuctotor r atat T T 

=

=

33000 0 K  K  

 E  E g g

=

=

115. . 5 eVeV,, m m  p  p mmnn * *

=

=

110 0 ** aanndd n nii

=

=

1 1

´

´

1010 15 15 cmcm--33. . TThhee

position of Fermi level with respect to the center of the position of Fermi level with respect to the center of the bandgap is

bandgap is (A)

(A)

+

+

00..00445 5 eV eV ((BB))

-

-

0.046 eV 0.046 eV  (C)

(C)

+

+

00..00339 9 eV eV ((DD))

-

-

0.039 eV 0.039 eV 

16.

16. A A sisililicocon n samsamplple e cocontntaiains ns acacceceptptor or atoatoms ms at at aa concen

concentratitration on of of  N N aa

=

=

5 5

´

´

1010 15

15 cmcm--33. . DoDononor r atatoms areoms are a

addddeed d ffoorrmmiinng g aanndd nn

-

-

tytype pe cocompmpenensasatetedd semiconductor such that the Fermi level is 0.215 eV  semiconductor such that the Fermi level is 0.215 eV  below the conduction band edge. The concentration of  below the conduction band edge. The concentration of  donors atoms added are

donors atoms added are (A)

(A) 112 ..2

´

´

10101616 cmcm--33 (B)(B) 4 4 ..6 6

´

´

11001616 cmcm--33 (

(CC) ) 39 39 ..

´

´

10101212 cmcm--33 ((DD) ) 2 2 4 ..4

´

´

10101212 cmcm--33

17.

17. A A silsilicoicon n semsemicoiconducnductor tor sampsample le atat T T 

=

=

300300 K K isis dope

doped d witwith h phophosphosphorus rus atoatoms ms at at a a conconcencentratratiotions ns of of  10

101515 cmcm--33. The position of the Fermi level with respect. The position of the Fermi level with respect to the intrinsic Fermi level is

to the intrinsic Fermi level is (

(AA) ) 00..3 3 eeV V ((BB) ) 00..2 2 eeV  V   (

(CC) ) 00..1 1 eeV V ((DD) ) 00..4 4 eeV  V  

18.

18. A A silsilicoicon n crycrystal having a stal having a crocross-ss-sectsectionional al arearea a of of  0.001

0.001 cmcm22 and a length of 20and a length of 20

m

m

m is connected to itsm is connected to its en

ends ds to to a a 20 20 V V babattttereryy. . AtAt T T 

=

=

300300 KK, , we we wwaannt t aa cu

currrrenent t of of 10100 0 mA in mA in crcrysystatal. l. ThThe e coconcncenentrtratatioion n of of  donor atoms to be added is

donor atoms to be added is (

(AA) ) 2 2 4 ..4

´

´

10101313cmcm--33 ((BB) 4 ) 4 ..6 6

´

´

11001313cmcm--33 (C)

(C) 7 7 ..8 8

´

´

11001414 cmcm--33 (D)(D) 8 8 ..4 4

´

´

11001414 cmcm--33

19.

19. The cross sectional area of silicon bar is 100The cross sectional area of silicon bar is 100

m

m

mm22.. Th

The e lelengngth of th of babar r is 1 is 1 mmmm. . ThThe e babar r is dopis doped wited withh arsenic atoms. The resistance of bar is

arsenic atoms. The resistance of bar is (A) 2.58 m

(A) 2.58 m

W

W

(B) 11.36 k(B) 11.36 k

W

W

(C) 1.36 m

(C) 1.36 m

W

W

(D) 24.8 k(D) 24.8 k

W

W

20.

20.A thin film resistor is to be made from a GaAs filmA thin film resistor is to be made from a GaAs film doped

doped nn

-

-

type. The resistor is to have a value of 2 ktype. The resistor is to have a value of 2 k

W

W

.. The resistor length is to be 200

The resistor length is to be 200

m

m

m and area is to bem and area is to be 10

10--66 cmcm22. . The dopinThe doping g effefficiiciencency y is known to is known to be 90%.be 90%. T Thhe e mmoobbiilliitty y oof f eelleeccttrroonns s iis s 8800000 0 ccm m 22 V V

-

-

ss. . TThhee doping needed is doping needed is (A) (A) 8 7 8 7 ..

´

´

10101515cmcm--33 (B)(B) 8 7 8 7 ..

´

´

10102121 cmcm--33 ( (CC) 4 ) 4 ..6 6

´

´

11001515 cmcm--33 ((DD) 4 ) 4 ..6 6

´

´

11002121 cmcm--33 21.

21.A silicon sample dopedA silicon sample doped nn

-

-

type attype at10101818 cmcm--33have ahave a resistance of 10

resistance of 10

W

W

. The sample has an area of . The sample has an area of  1010--66 1

(3)

cm

cm22 and a length of 10and a length of 10

m

m

m . The doping efficiency of m . The doping efficiency of  the sample is ( the sample is (

m

m

nn

=

=

88000 0 ccm m 22 V V

-

-

ss)) ( (AA) ) 4433..22% % ((BB) ) 7788..11%% ( (CC) ) 9966..33% % ((DD) ) 5544..33%% 22. 22. SSiix x vvoolltts s iis s aapppplliieed d aaccrroosss s a a 2 2 ccm m lloonng  g   semic

semiconductoonductor r barbar. . The average The average drift velocity isdrift velocity is 101044 cm s. The electron mobility is

cm s. The electron mobility is (

(AA) ) 4433996 6 ccm m 22 V V

-

-

ss ((BB) ) 3 3

´

´

101044 ccm V m V 22

-

-

ss (C)

(C) 6 6

´

´

101044 ccm m 22 V V

-

-

ss (D)(D) 3333333 3 ccm m 22 V V

-

-

ss

23.

23. For a For a particulparticular ar semiconsemiconductor material following ductor material following  paramete

parameters rs are are observedobserved::

m

m

nn

=

=

1100000 0 ccm m 22 V V

-

-

ss ,,

m

m

 p p

=

=

66000 0 ccm m 22 V V

-

-

ss ,,  N  N c c

=

=

N N vv

=

=

1010 19 19 cm cm--33 T Thheesse e ppaarraammeetteerrs s arare e iinnddeeppeennddeennt t oof  f   te

tempmpererataturure. e. ThThe e memeasasurured ed cocondnducuctitivivity ty of of ththee int

intrinrinsic sic matmaterierial al isis

s =

s =

1010- - 6 6 ( (

W

W

-

-

ccm m ))--11 aatt

T  T 

=

=

30300 0 K.K. The conductivity at The conductivity at T T 

=

=

500500 K K isis (A) (A) 2 2

´

´

1010--44 ( (

W

W -

-

cmcm))--11 (B)(B) 4 4

´

´

1010--55( (

W

W

-

-

cmcm))--11 ( (CC) ) 2 2

´

´

1100--55 ( (

W

W

-

-

cmcm))--11 (D(D) ) 6 6

´

´

1100--33( (

W

W

-

-

cmcm))--11 24.

24. AnAn nn

-

-

typtype e silsilicoicon n sampsample le has a has a resresististiviivity ty of of 55

W

W

-

-

ccm m aatt T T 

=

=

30300 0 K. K. The The momobibilility ty isis

m

m

nn

=

=

13501350 c

cm m 22 V V

-

-

ss. The donor impurity concentration is. The donor impurity concentration is (A)

(A) 2 2 8..86 6

´

´

1100--1414 cmcm--33 (B)(B) 9 29 25 .. 5

´

´

11001414 cmcm--33 (

(CC) ) 1111..446 6

´

´

11001515cmcm--33 ((DD) ) 11 11 ..

´

´

1010--1515 cmcm--33

25.

25. In In a a silsilicoicon n sampsample le the the eleelectrctron on conconcencentratratiotionn drops line

drops linearly fromarly from10101818 cmcm--33to10to101616 cmcm--33over a over a lengtlengthh of

of 2.2.00

m

m

m. m. The The cucurrrrenent t densdensitity y due due to to ththe e elelecectrtronon d diiffffuussiioon n ccuurrrreennt t iis s ( (  D Dnn

=

=

3535 )) 2 2 c cm m s s .. ( (A) A) 9 9 3 ..3

´

´

101044 A A cmcm22 (B(B) ) 2 2 8 ..8

´

´

101044 A A cmcm22 (C) (C) 9 9 ..3 3

´

´

110099A A cmcm22 (D)(D) 2 2 ..8 8

´

´

110099 A A cmcm22 26.

26. In a GaAs sample the electrons are moving underIn a GaAs sample the electrons are moving under a

an n eelleeccttrriic c ffiieelld d of of 55 kV cmkV cm anand d ththe e cacarrrriierer con

concencentratratiotion n is is uniuniforform m at 10at 101616 cmcm--33. . ThThe e elelecectrtronon velocity is the saturated velocity of 

velocity is the saturated velocity of 101077 cm cm ss. The drift. The drift current density is current density is ( (AA) ) 1 6 1 6 ..

´

´

101044 A A cmcm22 (B(B) ) 2 2 4 ..4

´

´

101044 A A cmcm22 (C) (C) 1 6 1 6 ..

´

´

101088A A cmcm22 (D)(D) 2 2 ..4 4

´

´

110088 A A cmcm22 27.

27.For a sample of GaAs scattering time isFor a sample of GaAs scattering time is

t

t

 sc sc

=

=

1010--1313ss and

and eleelectrctron’on’s s effeffectective ive mass mass isis m m  e  e mmoo *

*

=

=

00670067.. . I f an. I f an ele

electrctric field of ic field of 1 1 kV cm is appliekV cm is applied, the d, the dridrift veloft velocitcityy produced is produced is ( (AA) ) 2 2 6 ..6

´

´

110066 ccm m s s ((BB) ) 22663 3 ccm m ss (C) 1 (C) 14 4 ..8 8

´

´

101066 cm cm ss (D)(D) 482482 28.

28. A gallium arsenide semiconductor atA gallium arsenide semiconductor at T T 

=

=

300300 K K isis doped

doped with with impuriimpurity ty conceconcentratintrationon N N dd

=

=

1010 16 16

cm

cm--33. The. The mobility

mobility

m

m

nn iis s 7755000 0 ccm m 22 V V

-

-

ss. For an applied field of . For an applied field of  10 V cm the drift current density is

10 V cm the drift current density is (A) 120 A cm

(A) 120 A cm22 (B) 120 A cm(B) 120 A cm22

(C)

(C) 12 12

´

´

110044 A A cmcm22 (D)(D) 12 12

´

´

110044A A cmcm22

29.

29. In a particular semiconductor the donor impurityIn a particular semiconductor the donor impurity concentration is

concentration is N N dd

=

=

1010 14

14 cmcm--33. Assume the following . Assume the following  parameters, parameters,

m

m

nn

=

=

1100000 0 ccm m 22 V V

-

-

ss,,  N   N cc

=

=

´

´

æ 

æ 

T T 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

2 2 1010 300 300 19 19 3 2 3 2 cm cm--33,,  N   N vv

=

=

´

´

æ 

æ 

T T 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

1 1 1010 300 300 19 19 3 2 3 2 cm cm--33,,  E  E g g

=

=

1111.. eVeV..   An

  An eleelectrctric ic fiefield ld of of  EE

=

=

10 V cm is applied. The10 V cm is applied. The electric current density at 300 K is

electric current density at 300 K is (A) 2.3 A cm

(A) 2.3 A cm22 (B) 1.6 A cm(B) 1.6 A cm22 (C) 9.6

(C) 9.6 A A cmcm22 (D) 3.4(D) 3.4 A A cmcm22 Statem

Statement ent for for Q.30-31Q.30-31::

 A semiconductor has following parameter  A semiconductor has following parameter

m

m

nn

=

=

7755000 0 ccm m V V ss 2 2

-

-

,,

m

m

 p p

=

=

33000 0 ccm m 22 V V

-

-

ss,, n nii

=

=

3 6 3 6

´

´

1100 12 12 . . cmcm--33 30.

30. WhWhen en cocondnducuctitivvitity y is is mimininimumum, m, ththe e hoholele concen concentratitration on isis (A) (A) 7 2 7 2 ..

´

´

10101111 cmcm--33 (B(B) ) 1 8 1 8 ..

´

´

10101313cmcm--33 ( (CC) ) 144 144 ..

´

´

11001111 cmcm--33 (D(D) ) 9 9

´

´

11001313cmcm--33 31.

31. The minimum conductivity isThe minimum conductivity is (

(AA) ) 0 0 6 . . 6

´

´

1100- - 3 3 ( (

W

W

-

-

ccm m ))--11 (B(B) ) 11. . 7 7

´

´

1010- - 3 3 ( (

W

W

-

-

cmcm))--11 (C)

(4)

32.

32. A A papartrticiculular ar inintrtrininsisic c sesemimicocondnducuctotor r hahas s aa resistivity of 50

resistivity of 50( (

W

W -

-

cmcm))atatT T 

=

=

300300K and 5K and 5( (

W

W -

-

cmcm))atat

=

=

330 K. If change in mobility with temperature is330 K. If change in mobility with temperature is neglected, the bandgap energy of the semiconductor is neglected, the bandgap energy of the semiconductor is ( (AA) ) 11..9 9 eeV V ((BB) ) 11..3 3 eeV  V   ( (CC) ) 22..6 6 eeV V (D(D) ) 00..664 4 eeV  V   33. 33. TThhrreee e ssccaatttteerriinng g memecchhaanniissm m exexiisst t iin n aa se

semimicocondunductctoror. . If If ononly ly the the fifirsrst t memechchananisism m wewerere present, the mobility would be 500

present, the mobility would be 500 ccm m 22 V V

-

-

ss. If only. If only th

the e sesecocond nd memechchananisism m wewere re prpreseesentnt, , ththe e momobibililityty w

wouould ld be be 75750 0 cm cm 22 V V

-

-

ss. If only third mechanism were. If only third mechanism were present, the mobility would be 1500

present, the mobility would be 1500ccm m 22 V V

-

-

ss. The net. The net mobility is mobility is (A) 2750 (A) 2750 ccm m 22 V V

-

-

ss (B) 1114(B) 1114 ccm m 22 V V

-

-

ss (C) 818 (C) 818 ccm m 22 V V

-

-

ss (D) 250(D) 250 ccm m 22 V V

-

-

ss 34.

34. In a sample of silicon atIn a sample of silicon at T T 

=

=

300 K, the electron300 K, the electron concentration varies linearly with distance, as shown concentration varies linearly with distance, as shown in fig. P2.1.34. The diffusion current density is found in fig. P2.1.34. The diffusion current density is found t

to o bbee J J nn

=

=

00. . 1919 A A ccmm22. . If If ththe e elelecectrtron on didifffufusisionon coefficient is

coefficient is DDnn

=

=

2525 2 2 cm

cm ss, , The The electelectron ron concenconcentratitrationon at is at is (A) (A) 4 84 ..86 6

´

´

110088 cmcm--33 (B)(B) 2 5 2 5 ..

´

´

10101313cmcm--33 (C) (C) 9 9 ..8 8

´

´

11002626 cmcm--33 (D)(D) 5 5 ..4 4

´

´

11001515 cmcm--33 35.

35.The hole concentration inThe hole concentration in pp

-

-

type GaAs is given bytype GaAs is given by

 p  p xx  L  L

=

=

æ 

æ 

-

-è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

10 10 1616 11 cmcm--33 forfor 00

£

£

 x  x

£

£

LL where

where LL

=

=

1010

m

m

m. The hole diffusion coefficient ism. The hole diffusion coefficient is 1

10 0 ccm m 22 ss. . ThThe e hohole le didiffffususioion n cucurrrrenent t dedensnsitity y atat

 x  x

=

=

55

m

m

mm isis (A) 20 A cm (A) 20 A cm22 (B) 16 A cm(B) 16 A cm22 (C) 24 (C) 24 A A cmcm22 (D) 30(D) 30 A A cmcm22 36.

36. For For a a parparticticulaular r semiconsemiconductductor or samsample ple conconsidsiderer following parameters: following parameters: Hole concentration Hole concentration p p ee  x  x  L  L p p 0 0 15 15 10 10

=

=

-æ  æ  è  è  ç ç ç ç  ö  ö  ø  ø ÷ ÷ ÷ ÷ cm cm--33,,  x  x

³

³

00 Electron concentration Electron concentrationn n ee  x  x  L  Lnn 0 0 14 14 5 5 1010

=

=

´

´

-æ  æ  è  è  ç ç öö  ø  ø÷÷ cmcm--33 , , x x

£

£

00 Hole diffusion coefficient

Hole diffusion coefficient DD p p

=

=

110 0 ccm m ss 2 2

Elect

Electron ron diffusdiffusion ion coefficoefficientscients DDnn

=

=

225 5 ccm m ss 2 2

Hole diffusion length

Hole diffusion length LL p p

=

=

´

´

-5

5 1010 44 cm,cm, Electron diffusion length

Electron diffusion length LLnn

=

=

-10 10 33 cmcm The total current density at

The total current density at xx

=

=

0 0 isis (A) 1.2

(A) 1.2 A A cmcm22 (B) 5.2(B) 5.2 A A cmcm22 (C) 3.8 A cm

(C) 3.8 A cm22 (D) 2 A cm(D) 2 A cm22

37.

37. A gerA germamaninium Hall devum Hall devicice e is dopeis doped d wiwith 5 th 5

´

´

10101515 donor atoms per

donor atoms percmcm33 atat

=

=

300300 K. The device has theK. The device has the geometry

geometry dd

=

=

5 5

´

´

1010--33 cm,cm, W W 

=

=

2 2

´

´

1010--22 cm andcm and LL

=

=

00..11 cm. The current is

cm. The current is I I  x x

=

=

250250

m

m

 A, the applied voltage is A, the applied voltage is

V  x x

=

=

10100 0 mVmV, and the magne, and the magnetitic flux isc flux is BB z z

=

=

´

´

-5 5 1010 22 tesla. The Hall voltage is

tesla. The Hall voltage is (A)

(A)

-

-

00..3311mmV V (B(B) ) 00..331 1 mmV  V   (

(CC) ) 33..226 6 mV mV ((DD))

-

-

3.26 mV 3.26 mV  Statem

Statement ent for for Q.38-39Q.38-39::   A

  A sisililicocon n HaHall ll dedevivice ce atat T T 

=

=

33000 0 K K hhaas s tthhee geometry geometry dd

=

=

1010--33 cm cm ,, W  W 

=

=

1010--22 cm,cm, L L

=

=

1010--11 cm. Thecm. The fol

followlowing ing parparameameterters s are are meameasursured:ed: I I  x x

=

=

00..7575 mA,mA,

V  x x

=

=

1515 VV,, V V  H  H 

= +

= +

5 85 8.. mV, teslamV, tesla

38.

38. The The majorimajority carrier concty carrier concentratentration ision is ( (AA) ) 8 8

´

´

11001515 cmcm--33,, nn

-

-

typetype (B) (B) 8 8

´

´

10101515 cmcm--33,, p p

-

-

typetype ( (CC) ) 4 4

´

´

11001515 cmcm--33,, nn

-

-

typetype ( (DD) ) 4 4

´

´

10101515 cmcm--33,, p p

-

-

typetype 39.

39. The majority carrier mobility isThe majority carrier mobility is (

(AA) ) 44330 0 ccm m 22 V V

-

-

ss ((BB) ) 22115 5 ccm m 22 V V

-

-

ss (

(CC) ) 33990 0 ccm m 22 V V

-

-

ss ((DD) ) 11995 5 ccm m 22 V V

-

-

ss

40.

40. In In a a semisemiconconducductortor nn00

15 15 10 10

=

=

cmcm--33 andand n nii

=

=

1010 10 10 cm

cm--33. The excess-carrier life time is 10. The excess-carrier life time is 10--66 s. The excesss. The excess ho

holle e coconcncenentrtratatioion n isis

d

d

 p p

=

=

4 4

´

´

10101313 cmcm--33. . TThhee electron-hole recombination rate is

electron-hole recombination rate is ( (AA) ) 4 4

´

´

11001919 cm cm - - 3 3 ss--11 ((BB) ) 4 4

´

´

11001414 cm cm - - 3 3 ss--11 (C) (C) 4 4

´

´

10102424 cm cm - - 3 3 ss--11 (D)(D) 4 4

´

´

10101111 cm cm - - 3 3 ss--11 1 1110 0 SSeemmiiccoonndduuccttoor r PPhhyyssiiccs s CChhaap p 22..11 5 5 ´´10101414  x  x(cm)(cm)      n      n      (      (   c   c   m   m      )      )   -     3      3 0.010 0.010 n n(0)(0) 0 0 Fig. P2.1.34 Fig. P2.1.34

(5)

41.

41. A A semsemicoicondunductoctor r in in thermathermal l equiequiliblibriurium, m, has has aa hole concentrati

hole concentration on of of  pp00

16 16 10 10

=

=

cmcm--33 and and an an intintrinrinsicsic conce

concentratintration on of of  nnii

=

=

1010 10

10 cmcm--33. . The The minminoriority ty carcarrierierr l

liiffe e ttiimme e iis s 4 4

´

´

1010--77s. s. ThThe e ththerermamal l eqequiuililibrbriuiumm recombination rate of electrons is

recombination rate of electrons is (A) (A) 2 5 2 5 ..

´

´

10102222 cm cm - - 3 3 ss--11 (B)(B) 5 5

´

´

10101010 cm cm - - 3 3 ss--11 ( (CC) ) 2 5 2 5 ..

´

´

10101010 cm cm - - 3 3 ss--11 (D(D) ) 5 5

´

´

10102222 cm cm - - 3 3 ss--11 Statement for Q.42-43: Statement for Q.42-43:   A

  A n-n-tytype pe sisililiccon on sasampmple le cocontntaiains ns a a dodononorr conce

concentratintration on of of  N N dd

=

=

1010 6

6 cmcm--33. . The The minminoriority ty carcarrierierr hole lifetime is

hole lifetime is

t

t

 p p00

=

=

1010

m

m

s.s.

42.

42.The thermal equilibrium generation rate of hole isThe thermal equilibrium generation rate of hole is (A)

(A) 5 5

´

´

101088 cm cm - - 3 3 ss--11 (B)(B) 101044 cm cm - - 3 3 ss--11 (

(C) C) 2 2 25 ..25

´

´

101099 cm cm - - 3 3 ss--11 (D) 10(D) 1033 cm cm - - 3 3 ss--11

43.

43. ThThe e ththerermamal l eqequiuililibrbriuium m gegeneneraratition on rarate te foforr electron is electron is ( (A) A) 1121125 .. 5

´

´

101099cm cm - - 3 3 ss--11 (B(B) ) 225 225 ..

´

´

101099 cm cm - - 3 3 ss--11 (C) (C) 8 9 8 9 ..

´

´

1100--1010 cm cm - - 3 3 ss--11 (D)(D) 4 4

´

´

101099 cm cm - - 3 3 ss--11 44.

44. A A  nn

-

-

tytype pe sisililicocon n sasampmple le cocontntaiains ns a a dodononorr conce

concentratintration on of of  N N dd

=

=

10101616 cmcm--33. . The The minminoriority ty carcarrierierr hole lifetime is

hole lifetime is

t

t

 p p00

=

=

2020

m

m

s. The lifetime of the majoritys. The lifetime of the majority carrier is carrier is ( ( nnii

=

=

. .

´

´

)) -1 15 5 110010 10 cmcm 33 ( (AA) ) 8 9 8 9 ..

´

´

110066 s s ((BB) ) 88..9 9

´

´

1100--66 ss (C) (C) 4 5 4 5 ..

´

´

1010--1717ss ((DD)) 1 13 1 1.. 3

´

´

1100--77ss 45.

45. In In a a silsilicoicon n semisemiconconducductor tor matmaterierial al the the dopidoping ng  conce

concentratintration on areare N N aa

=

=

1010 16

16 cmcm--33 andand

N aa

=

=

00. . TThhee equil

equilibriuibrium m recombrecombinatioination n rate rate isis RR p p00

11 11 10 10

=

=

cmcm--33ss--11. . A A  uni

uniforform m gengeneraeratiotion n ratrate e producproduces es an an excexcess- ess- carcarrierierr conce

concentratintration on of of 

d

d

n n

=

=

d

d

pp

=

=

10101414 cmcm--33. . The The fafactctoror, , byby which the total recombination rate increase is

which the total recombination rate increase is ( (A) A) 2 2 3 ..3

´

´

11001313 (B(B) 4 ) 4 ..4 4

´

´

11001313 (C) (C) 2 2 ..3 3

´

´

110099 (D)(D) 4 4 ..4 4

´

´

110099 *********** ***********

Solutions

Solutions

1. 1. (D)(D) n n i i N N c c N N vv ee  E  E  kT   kT   g  g 2 2

=

=

- -æ  æ  è  è  ç ç ç ç  ö ö  ø  ø÷÷÷÷ V  V tt

=

=

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

=

=

00259 00259 400400 300 300 0034500345 . . .. For Ge at 300 K, For Ge at 300 K,  N   N cc

=

=

1 01 04 4

´

´

1100 19 19 . . ,, N N vv

=

=

6 0 6 0

´

´

1100 18 18 . . ,, EE g g

=

=

0 660 66. . eV eV  n n ii22 1199 1188 ee 3 3 0 660 66 0 0345 0 0345 1 1004 14 10 0 6 0 16 0 100 400400 300 300

= ´

= ´

´

´

´

´

´

´

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

´

´

--æ æ  . . .. . . . . è  è  ç ç öö  ø  ø÷÷

Þ

Þ

nnii

=

=

8 5 8 5

´

´

1100 14 14 . . cmcm--33 2. 2. (C)(C) n n i i N N c c N N vv ee  E  E  kT   kT   g  g 2 2

=

=

- -æ  æ  è  è  ç ç ç ç  ö ö  ø  ø÷÷÷÷ ( ( )) .. .. . . 1 10 0 2 2 8 18 10 0 11004 14 100 300 300 1 122 22 1199 1199 3 3 1 121 12

=

=

´

´

´

´

´

´

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

--æ æ  è  è  ç ç öö T  T   e  e  e  e  kT   kT øø÷÷ T T 33ee T T  13 10 13 10 8 8 3 3 9 2 9 28 8 1100 - - ´´

-=

=

. .

´

´

, , BBy y ttrriiaall T T 

=

=

382 K 382 K  3. 3. (B)(B) nn n n  e  e  e  e iA iA iB iB  E  E  kT   kT   E  E  kT   kT   gA  gA  gB  gB 2 2 2 2

=

=

--

=

=

=

=

--æ æ  - -è  è  ç ç ç ç  ö ö  ø  ø÷÷÷÷  e  e  E  E EE  kT   kT  g gA A ggBB 22 22575575..

Þ

Þ

nn

=

=

n n iA iA iB iB 47 47..55 4. 4. (A)(A) pp nn n n i i 0 0 2 2 0 0 10 10 22 4 4 15 15 1 15 5 1100 5 5 1010 4 5 4 5 1100

=

=

=

=

´

´

´

´

=

=

´

´

( ( . . )) . . cmcm--33 5. 5.(A)(A) p p N N vv ee  E  E EE  kT   kT   F  F vv 0 0

=

=

--( ( -- ))

=

=

´

´

-1 0 1 04 4 11001919 0 0 2222 0 0259 0 0259 . . . . . .  e  e

=

=

2 2

´

´

10101515 cmcm--33 6. 6. (B)(B) p p N N vv ee  E  E EE  kT   kT   F  F vv 0 0

=

=

--( ( -- ))

Þ

Þ

E E E E kkT  T   N N   p  p  F  F vv v v

-

-

=

=

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

ln ln 0 0   At 300 K,   At 300 K, N N vv

=

=

110 0

´

´

1100 19 19 . . cmcm--33  E  E  F  F

-

-

EEvv

=

=

´

´

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

=

=

00259 00259 1 01 04 4 1100 10 10 0 2390 239 19 19 15 15 . . lnln .. .. eV eV  n n N N cc ee  E  E EE  kT   kT  c c F F  0 0

=

=

-( ( ))   At 300 K,   At 300 K, N N cc

=

=

2 2 8 8

´

´

1100 19 19 . . cmcm--33  E  E c c

-

-

EE

=

=

11112 . . 2

-

-

0 0 2. . 2339 9

=

=

0 80 . . 88811eeV  V   n n00 4 4 4 4 4 4 1100

=

=

. .

´

´

cmcm--33 7. 7. (C)(C) pp N N a a N N dd  N  N  N N  nn a a d d i i 0 0 2 2 2 2 2 2 22

=

=

-

-

+

+

æ 

æ 

-

-è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

+

+

For Ge For Ge nnii

=

=

2 2 ..4 4

´

´

110033  p  p00 1 13 3 1133 22 13 13 22 10 10 2 2 10 10 2 2 2 2 4 4 1100

=

=

+

+

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

+

+

( ( . .

´

´

))

=

=

2 92 95 5

´

´

1100 13 13 . . cmcm--33

(6)

8. 8. (A)(A) nn N N d d N N aa  N  N  N N  nn d d a a i i 0 0 2 2 2 2 2 2 22

=

=

-

-

+

+

æ 

æ 

-

-è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

+

+

=

=

´

´

+

+

æ 

æ 

´

´

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

+

+

´

´

5 5 1010 2 2 5 5 1010 2 2 2 2 4 4 1100 1 155 1155 22 13 13 22 ( ( . . ))

=

=

5 5

´

´

10101515 cmcm--33 9. 9. (B)(B) pp nn  p  p i i 0 0 2 2 0 0 13 13 22 13 13 2 2 4 4 1100 2 9 2 95 5 1100

=

=

=

=

´

´

´

´

( ( . . )) . .

=

=

1 91 95 5

´

´

1100 13 13 . . cmcm--33 10.

10. (A) Since(A) Since N N a a

>

>

N N dd, thus material is p-type ,, thus material is p-type ,

p p 00

=

=

N N a a

-

-

N  N  dd

= ´

= ´

22..5 5 110 0 33

-

- ´

1 10 1 1

´

0 33

=

=

15 1..5

´

´

10101133 ccmm--33 11 11.. (D)(D) kT kT 

=

=

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

=

=

00259 00259 200200 300 300 0001017373 . . .. eeVV    For GaAs at 300 K, For GaAs at 300 K,  N   N cc

=

=

4 7 4 7 . .

´

´

11001717cmcm--33,, N  N vv

=

=

7 0 7 0 . .

´

´

11001818,, E E g g

=

=

11. . 4242 eV eV  n n ii ee 2 2 1177 1188 3 3 1 1 4242 0 0173 0 0173 4 47 17 10 0 770 10 100 200200 300 300

=

=

´

´

´

´

´

´

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

--æ æ  è  è  ç ç öö . . .. . . . . øø÷÷

Þ

Þ

nnii

=

=

11. . 4848 cmcm --33 n n ii n n p p pp nn 2 2 0 0 0 0 00 2 2 00 2 2 5 5 5 5

=

=

=

=

=

=

n n 00

=

=

5 5 nnii

=

=

33. . 33cmcm --33 12. 12. (A)(A) kT kT 

=

=

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

=

=

00259 00259 400400 300 300 0034500345 . . .. eeVV    n n i i N N c c N N vv ee  E  E  kT   kT   g  g 2 2

=

=

- -æ  æ  è  è  ç ç ç ç  ö ö  ø  ø÷÷÷÷ For Ge at 300 K, For Ge at 300 K,  N   N cc

=

=

1 01 04 4

´

´

1100 19 19 . . cmcm--33 ,, N  N vv

=

=

6 6

´

´

1010 18 18 cmcm--33 ,, E E g g

=

=

0 660 66. . eV eV  n n ii ee 2 2 1199 1188 3 3 0 660 66 0 0345 0 0345 1 1004 14 10 0 6 16 100 400400 300 300

=

=

´

´

´

´

´

´

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

--æ æ  è  è  ç ç öö  ø  ø . . . . . . ÷÷

=

=

7 27 ..2774 4

´

´

11002929 n nii

=

=

8 5 28 5 28 8

´

´

1100 14 14 . . cmcm--33  p  p N N a a N N aa nn i i 0 0 2 2 2 2 2 2 22

=

=

+

+

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

+

+

=

=

+

+

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

+

+

´

´

10 10 2 2 10 10 2 2 7 7 22774 4 1100 1 15 5 1155 22 29 29 . .

Þ

Þ

 p p00

=

=

´

´

15 15 1 4 1 48. . 89 9 1100 cmcm--33 E E E E kkT  T   pp n n F Fi

-

-

i F  F  

=

=

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

ln ln 00 0 0

=

=

´

´

´

´

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

00345 00345 1 4 81 4 89 9 1100 8 5 2 8 5 28 8 1100 15 15 14 14 . . lnln .. . .

=

=

00190019.. eV eV  13. 13. (A)(A) nn N N d d N N dd nn i i 0 0 2 2 2 2 2 2 22

=

=

+

+

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

+

+

For Ge at For Ge at T T 

=

=

300300 K,K, nnii

=

=

2 2 4 4

´

´

1100 13 13 . . cmcm--33 n n00 1 144 1144 22 1 133 22 1144 10 10 2 2 10 10 2 2 2 2 4 4 110 0 1100555 5 1100

=

=

+

+

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

+

+

(( ..

´

´

))

=

=

..

´

´

ccmm --33 E E E E kkT  T   nn n n F F FFii i i

-

-

=

=

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

ln ln 00

=

=

´

´

´

´

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

00259 00259 1010555 5 1100 2 2 4 4 1100 14 14 13 13 . . lnln .. . .

=

=

0038300383.. eV eV  14. 14. (A)(A) nn N N d d N N dd nn i i 0 0 2 2 2 2 2 2 22

=

=

+

+

æ 

æ 

è 

è 

ç

ç

ö

ö

 ø

 ø

÷

÷

+

+

n n ii

=

=

00..0505nn00

Þ =

Þ =

n n 00

´

´

+

+

´

´

+

+

nn 1 155 1155 22 0 0 2 2 1 15 ..5 10 10 ((115 ..5 10 10 )) ((00..0505 ))

Þ

Þ

nn00

=

=

´

´

15 15 30 300. . 0775 5 1100 cmcm--33 n nii

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1515004 4

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1100 14 14 . . cmcm--33 n n i i N N c c N N vv ee  E  E  kT   kT   g  g 2 2

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- -æ  æ  è  è  ç ç ç ç  ö ö  ø  ø÷÷÷÷ For GaAs at For GaAs at T T 

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300 K,300 K,  N   N cc

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4 7 4 7 . .

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11001717,, N  N vv

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10101818,, E E g g

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11. . 4242 eV eV  ( ( . . ) ) .. . . . . 1 155004 4 447 17 10 0 7 17 100 300 300 2 2 1177 1188 3 3 1 42 1 42 303000 0 025 0 025

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763763K K 

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3 3 4 4 ln ln 0044600446.. * * * * eV eV  16. 16. (A)(A) n n N N d d N N a a N N cc ee  E  E EE  kT   kT  c c F F  0 0

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2 2 . . 8 8

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1 11 19 . . 9

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11001616 cmcm--33 17. 17. (A)(A) E E E E kkT  T   N N   N   N  F F FFii d d i i

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00259 00259 1010 1 15 5 1100 02870287 15 15 10 10 . . lnln . . .. eV eV  18. 18. (D)(D) RR V V   I   I 

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2020

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100 100mm 200200

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n n 00

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nnii

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N N dd ,,

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nnnn00,,  R  R LL  A  A  L  L e e n n N N ddAA

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,, 1 1112 2 SSeemmiiccoonndduuccttoor r PPhhyyssiiccs s CChhaap p 22..11

References

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