SIX SIGMA GREEN BELT EXAMINATION
1. The mentor for the Green Belt should at least be a (A) Master Black belt
(B) Champion (C) Black Belt (D) Green Belt Ans:
2. The Black Belt is guiding projects carried out by green or yellow belts on a (A) Full time basis
(B) Partial basis
(C) Beyond official working hours (D) Consulting basis
Ans:
3. The data for projects is collected by the (A) Green Belts
(B) Black belts (C) Both of them (D) None of them Ans:
4. Metric of SIX SIGMA gives an insight into how many (A) Defectives
(B) Defects
(C) Defects per million opportunity (D) Defects per unit
Ans:
5. SIX SIGMA concepts were born in (A) Allied Signal Ltd.
(B) General Electric Ltd. (C) Chrysler Ltd.
(D) Motorola Ltd. Ans:
6. The person who propagated SIX SIGMA concepts in General Electric Ltd. .was :
(A) Jack Welch (B) Bob Smith (C) Philip Crosby (D) None of them C C A A D
Ans:
7. Weaving of Cloth is being done in looms. It was seen that defects like coagulation of thread, Knot, Breakage in continuity of thread, Grease marks are opportunities of defects. The number of such defects were found to be 20 in the 100 dhotis woven. Calculate the six sigma level at which the looms was operating.
Ans: No. of Defects = 20
Total No. of Dhotis Woven = 100
No. of Opportunities = 4 (coagulation of threads, knot, breakage of continuity of threads & grease marks)
Defects per unit (DPU) = D/U = 20/100 = 0.20
Defects per opportunities (DPO) = 20/ (4*100) = 0.05
Defects per million opportunities (DPMO) = 0.05*106 = 50000 PPM Z = 0.5 – 0.05 = 0.45
Z Value = 1.645
Sigma Value to Z = 1.645 + 1.5 = 3.145
8. Kano Model shows the path towards (A) Satisfying a customer (B) Delighting a customer
(C) Ensure basic needs of a customer (D) None of the above
Ans:
9. Pareto Chart is read by the user to find out
(A) which 20% of the causes contribute towards 80% of the problem (B) which 20% of the people in a state posses 80% of the wealth (C) Both of the above
(D) None of the above. Ans:
10. Cause and Effect Diagram was first formulated by (A) Juran
(B) Deming (C) Taguchi (D) Ishikawa Ans:
11. In Measurement System Analysis the variance contribution allowed for Gage R & R is to a maximum of (A) 20% (B) 10% D C B A
(C) 30% (D) 5% Ans:
12. The following data on an experiment is given. Perform the measurement System Analysis on the data.
Parts Operator 1 Operator 2
Trial 1 Trial 2 Trial 1 Trial 2
1 10.2 11.6 11.0 11.2 11.3 11.7 11.2 12.5 2 10.9 11.8 11.0 12.8 14.0 11.5 11.3 12.7 3 12.0 10.2 11.2 13.0 11.6 10.6 10.3 13.4 4 12.6 10.5 11.4 10.3 15.0 14.2 11.2 14.3 5 10.2 14.6 11.3 13.2 10.3 12.3 11.6 10.8 Ans:
Parts Operator 1 Operator 2
Trial 1 Trial 2 avg range Trial 1 Trial 2 avg range
1 10.2 11.6 11 11.2 11.3 11.7 11.2 12.5 Avg 10.75 11.65 11.2 11.1 11.85 11.475 range 1.1 0.1 0.6 0.2 1.3 0.75 2 10.9 11.8 11 12.8 14 11.5 11.3 12.7 Avg 12.45 11.65 12.05 11.15 12.75 11.95 range 3.1 0.3 1.7 0.3 1.3 0.8 3 12 10.2 11.2 13 11.6 10.6 10.3 13.4 Avg 11.8 10.4 11.1 10.75 13.2 11.975 range 0.4 0.4 0.4 0.9 0.4 0.65 4 12.6 10.5 11.4 10.3 15 14.2 11.2 14.3 Avg 13.8 12.35 13.075 11.3 12.3 11.8 range 2.4 3.7 3.05 -0.2 4 1.9 5 10.2 14.6 11.3 13.2 10.3 12.3 11.6 10.8 Avg 10.25 13.45 11.85 11.45 12 11.725 range 0.1 2.3 1.2 0.3 2.4 1.35 Mean of Xa=11.855; C
Mean of Xb=11.785; Range of A=1.39; Range of B=1.09 X diff=0.07
13. The normality check on the data is done through normal probability paper where the Anderson Darling test is performed. For the data to be normal the p-value should be
(A) 0.05 (B) >0.05 (C) <0.05 (D) 0.95 Ans:
14. In FMEA if the RPN number is high then we attack that mode of failure .first and then what do we first see in that mode of failure?
(A) Occurrence is high (B) Detection is difficult (C) Severity is fatal (D) None of the above. Ans:
15. Quality function Deployment is a (A) Planning tool
(B) Diagnostic Tool (C) Check Sheet (D) None of the above Ans:
16. The transformation used to make a normal distribution with mean µ and standard deviation σ to a Standard Normal Distribution is given by
(A) (X- µ) / σ2 (B) (X- µ)2 / σ2 (C) (X- µ) / σ
(D) None of the above Ans:
17. Green belts carry out project work during their (A) normal working hours
(B) beyond office hours (C) take special leave (D) All of the above Ans:
18. If their arises a major doubt in the statistical analysis of the data then the Green Belts and Black Belts seek help of
C
A A D B
(A) Champion
(B) Master Black Belt (C) CEO
(D) Refer a library Ans:
19. A project is spearheaded by a Black Belt after it has been approved by (A) Champion
(B) Master Black Belt (C) CEO
(D) Managing Director Ans:
20. A process is following normal distribution with mean 10 and standard
deviation 2. What is the area under the curve if the sample collected have max reading as 20 and min reading as 5?
Ans: 5<X<20 (5-10)/2<Z<(20-10)/2 -2.5<Z<5 P(Z<5)-P(Z<-2.5) 0.5-(-0.493790) =0.993790
21. If the DPO=0.025 then what is the percentage of acceptance of the product being produced ?
Ans: DPO =0.025
DPMO = DPO*1000000 = 0.025*1000000 = 25,000 ppm
Sigma Level corresponding to 25,000 ppm = 3.4
Sigma percentage = 97.1283 % (from the table 2 for Conversion between PPM & Sigma)
22. While selecting the projects the Black Belts should always choose projects .with
(A) which have less impact but more saving (B) which have more impact and more saving
(C) which are less time consuming and savings is more (D) which have more impact and less time consuming Ans:
23. The path from moving from a six sigma level of 4 to 5 is (A) easy
(B) difficult B
A B
(C) looks impossible (D) none of the above Ans:
24. The first journal on quality was published by (A) U.S.A
(B) Japan (C) Germany (D) Britain Ans:
25. Rajiv Gandhi Award is a quality award given by (A) Rajiv Gandhi Foundation
(B) Conferderation of Indian Industries (C) Bureau of Indian Standard
(D) Indian Statistical Institute Ans:
B B
