Some Quantum f-divergence Inequalities for Convex Functions of Self-adjoint Operators
A. Taghavi, V. Darvish, H. M. Nazari and S. S. Dragomir
abstract: In this paper, some new inequalities for convex functions of self-adjoint operators are obtained. As applications, we present some inequalities for quantum f-divergence of trace class operators in Hilbert Spaces.
Key Words: Self-adjoint bounded linear operator, Trace inequality, Convex function, Quantumf-divergence.
Contents
1 Introduction 125
1.1 The Class ofχα-Divergences. . . 126
1.2 Dichotomy Class . . . 126
1.3 Divergences of Arimoto-type. . . 127
2 Some inequalities for convex functions of self-adjoint operators 128
3 Some quantum f-divergence inequalities for convex functions 132
1. Introduction
Let (X,A) be a measurable space satisfying |A| >2 and µ be a σ-finite
mea-sure on (X,A). LetPbe the set of all probability measures on (X,A) which are
absolutely continuous with respect to µ. For P, Q ∈ P, let p= dP
dµ and q = dQ dµ denote theRadon-Nikodym derivatives of P andQwith respect toµ.
Two probability measuresP, Q∈ P are said to beorthogonal and we denote
this byQ⊥P if
P({q= 0}) =Q({p= 0}) = 1.
Letf : [0,∞) →(−∞,∞] be a convex function that is continuous at 0, i.e., f(0) = limu↓0f(u).
In 1963, I. Csisz´ar [6] introduced the concept of f-divergence as follows.
Definition 1.1. Let P, Q∈P. Then
If(Q, P) =
Z
X p(x)f
q(x) p(x)
dµ(x), (1.1)
is called thef-divergence of the probability distributions QandP.
2010Mathematics Subject Classification:47A63, 47A99. Submitted March 26, 2016. Published March 10, 2017
125 Typeset by
BSP
Mstyle. c
Remark 1.2. Observe that, the integrand in the formula (1.1) is undefined when p(x) = 0.The way to overcome this problem is to postulate for f as above that
0f
q(x) 0
=q(x) lim u↓0 uf 1 u
, x∈X. (1.2)
We now give some examples of f-divergences that are well-known and often used in the literature (see also [3]).
1.1. The Class of χα-Divergences
The f-divergences of this class, which is generated by the function χα, α ∈
[1,∞), defined by
χα(u) =|u−1|α, u∈[0,∞)
have the form
If(Q, P) =
Z X p q p−1
α dµ= Z X
p1−α|q−p|αdµ. (1.3)
From this class only the parameter α = 1 provides a distance in the topologi-cal sense, namely the total variation distance V (Q, P) =R
X|q−p|dµ.The most prominent special case of this class is, however,Karl Pearson’s χ2-divergence
χ2(Q, P) =
Z
X q2
pdµ−1
that is obtained forα= 2.
1.2. Dichotomy Class
From this class, generated by the functionfα: [0,∞)→R
fα(u) =
u−1−lnu for α= 0;
1
α(1−α)[αu+ 1−α−u
α] for α∈R\ {0,1};
1−u+ulnu for α= 1;
only the parameterα= 1 2
f1
2(u) = 2 (
√
u−1)2provides a distance, namely, the Hellinger distance
H(Q, P) =
Z
X
(√q−√p)2dµ
12
.
Another important divergence is the Kullback-Leibler divergence obtained for α= 1,
KL(Q, P) =
1.3. Divergences of Arimoto-type
This class is generated by the functions
Ψα(u) :=
α α−1
h
(1 +uα)α1 −2α1−1(1 +u)
i
for α∈(0,∞)\ {1};
(1 +u) ln 2 +ulnu−(1 +u) ln (1 +u) for α= 1;
1
2|1−u| for α=∞.
It has been shown in [19] that this class provides the distances [IΨα(Q, P)]
min(α,α)1 forα∈(0,∞) and 12V (Q, P) forα=∞.
Forf continuous convex on [0,∞) we obtain the∗-conjugate function off by
f∗(u) =uf
1 u
, u∈(0,∞)
and
f∗(0) = lim u↓0f
∗(u).
It is also known that iff is continuous convex on [0,∞) then so isf∗.
The following two theorems contain the most basic properties off-divergences. For their proofs we refer the reader to Chapter 1 of [17] (see also [3]).
Theorem 1.3(Uniqueness and Symmetry Theorem). Letf, f1be continuous
con-vex on [0,∞).We have
If1(Q, P) =If(Q, P),
for allP, Q∈P if and only if there exists a constantc∈R such that
f1(u) =f(u) +c(u−1),
for any u∈[0,∞).
Theorem 1.4 (Range of Values Theorem). Let f : [0,∞)→ R be a continuous
convex function on [0,∞).
For anyP, Q∈P, we have the double inequality
f(1)≤If(Q, P)≤f(0) +f∗(0). (1.4)
(i) IfP =Q,then the equality holds in the first part of (1.4).
If f is strictly convex at 1, then the equality holds in the first part of (1.4) if and only ifP =Q;
(ii) IfQ⊥P, then the equality holds in the second part of (1.4).
Iff(0) +f∗(0)<∞,then equality holds in the second part of (1.4) if and only
The following result is a refinement of the second inequality in Theorem 1.4
(see [3, Theorem 3]).
Theorem 1.5. Let f be a continuous convex function on[0,∞)with f(1) = 0 (f is normalised) andf(0) +f∗(0)<∞. Then
0≤If(Q, P)≤ 1
2[f(0) +f
∗(0)]V (Q, P) (1.5)
for any Q, P ∈P.
For other inequalities for f-divergence see [2], [7]- [12] and [13] Motivated by the above results, in this paper we obtain some new inequalities for quantum f -divergence of trace class operators in Hilbert spaces. It is shown that for normalised convex functions it is nonnegative. Some upper bounds for quantumf-divergence in terms of variational andχ2-distance are provided. Applications for some classes
of divergence measures such as Umegaki and Tsallis relative entropies are also given.
In what follows we recall some facts we need concerning the trace of operators and quantumf-divergence for trace class operators in infinite dimensional complex Hilbert spaces.
2. Some inequalities for convex functions of self-adjoint operators
Suppose thatI is an interval of real numbers with interior ˚I and f :I→Ris
a convex function on I. Then f is continuous on ˚I and has finite left and right derivatives at each point of ˚I. Moreover, if x, y ∈ ˚I and x < y, then f−′ (x) ≤
f+′ (x) ≤ f−′ (y) ≤ f+′ (y), which shows that both f−′ and f+′ are nondecreasing
function on ˚I. It is also known that a convex function must be differentiable except for at most countably many points.
Let A be a self-adjoint operator on the complex Hilbert space (H,h·,·i) with Sp(A)⊆[m, M] for some real numbersm < Mand let{Eλ}λbe its spectral family. Then for any continuous function f : [m, M]→ R, it is known that we have the
following spectral representation in terms of the Riemann-Stieltjes integral (see for instance [14, p. 257]):
hf(A)x, yi=
Z M
m−0
f(λ)d(hEλx, yi),
and
kf(A)xk2=
Z M
m−0|
f(λ)|2dkEλxk2,
for anyx, y ∈H.
is convex on I, then
hf(A)x, xi − f(M)−f(m)
M −m hAx, xi
≥
"
2 M −m
Z M
m
f(t)dt−M f(M)−mf(m)
M−m
#
kxk2.
Proof. Without loosing the generality, we can assume thatf is differentiable on ˚I. By the convexity off onI, we have
f(t)−f(s)≥f′(s)(t−s), (2.1)
for allt, s∈[m, M]⊂˚I.
If {Et}t∈Ris the spectral family of A then the mapping [m, M]∋t7→ hEtx, xiis
monotonic real mapping for anyx∈H.
If we integrate (2.1) overt∈[m, M] with the integralerhEtx, xithen we get
Z M
m−0
f(t)dhEtx, xi − f(s)
Z M
m−0
dhEtx, xi
≥f′(s)
" Z M
m−0
tdhEtx, xi −s
Z M
m−0
dhEtx, xi
#
for anys∈[m, M] andx∈H.
Using the spectral representation theorem for self-adjoint operators we get
hf(A)x, xi −f(s)kxk2≥f′(s)
hAx, xi −skxk2
(2.2)
for anys∈[m, M] andx∈H.
Now if we integrate (2.2) overson [m, M] and divide by M−m, we get
hf(A)x, xi − kxk2 1 M −m
Z M
m
f(s)ds
≥ hAx, xi 1
M −m
Z M
m
sf′(s)ds
!
=:K
(2.3)
However, we know that
1 M −m
Z M
m
f′(s)ds= f(M)−f(m) M −m
and
1 M −m
Z M
m
sf′(s)ds= 1 M−m
"
M f(M)−mf(m)−
Z M
m
f(s)ds
#
Therefore
K = hAx, xif(M)−f(m)
M−m −
kxk2hM f(M)−mf(m)−RM
m f(s)ds
i
M−m
= hAx, xif(M)−f(m)
M−m −
kxk2hM f(M)−mf(m)−RM
m f(s)ds
i
M−m
+ kxk
2
M −m
Z M
m
f(s)ds
By (2.3) we then get
hf(A)x, xi − f(M)−f(m)
M −m hAx, xi
≥ 2kxk
2
M−m
Z M
m
f(s)ds−kxk
2[M f(M)−mf(m)]
M −m
=kxk2
"
2 M−m
Z M
m
f(s)ds−M f(M)−mf(m)
M −m
#
.
✷
Remark 2.2. Since f(t) =t−1 is convex function for t >0, by above theorem we have
hmM A−1x, xi+hAx, xi ≥2mM ln( M m) M−m for kxk= 1.
Theorem 2.3. Let A and B be two self-adjoint operators on the Hilbert space (H,h·,·i)with Sp(A),Sp(B)⊆[m, M]⊂˚I andf :I →R a continuously
differen-tiable convex function on I. Then
hf(A)x, xikyk2 − hf(B)y, yikxk2
≥DhAx, xif′(B)− kxk2f′(B)By, yE
for any x, y∈H.
Proof. Sincef :I→Ris convex onI we have
f(t)−f(s)≥f′(s)(t−s), for anyt, s∈˚I. (2.4)
Let{Et}t∈Rbe the spectral family ofAand{Ft}t∈Rthe spectral family ofB. The
Integrating (2.4) overton [m, M] with integralerhEtx, xiwe get
Z M
m−0
f(t)dhEtx, xi − f(s)
Z M
m−0
dhEtx, xi
≥f′(s)
Z M
m−0
tdhEtx, xi −s
Z M
m−0
dhEtx, xi
!
which is equivalent to
hf(A)x, xi − kxk2f(s)≥f′(s)hAx, xi −sf′(s)kxk2,
for anys∈[m, M] andx∈H.
Integrating above inequality overs on [m, M] with integralerhFsx, xiwe then get
hf(A)x, xi
Z M
m−0
dhFsy, yi − kxk2
Z M
m−0
f(s)dhFsy, yi
≥ hAx, xi
Z M
m−0
f′(s)dhFsy, yi − kxk2
Z M
m−0
sf′(s)dhFsy, yi
which is equivalent to
hf(A)x, xikyk2 − hf(B)y, yikxk2
≥ hAx, xihf′(B)y, yi − kxk2hf′(B)By, yi.
We know that
D
hAx, xif′(B)− kxk2f′(B)By, yE= hAx, xiI− kxk2B
f′(B)hy, yi
and
hf(A)x, xikyk2− hf(B)y, yikxk2=h(hf(A)x, xiI− hx, xif(B))y, yi
On the other hand, we have
hAx, xiI− kxk2B
f′(B)≤ hf(A)x, xiI− kxk2f(B)
and
hf(A)x, xiI− kxk2f(B)≥f′(B)(hAx, xiI− kxk2B)
for allx∈H. We obtain the desired result. ✷
Remark 2.4. Let B =Pn
j=1αjXj in above theorem and αj ≥0,j ∈ {1, . . . , n}
such that Pn
hf(A)x, xiI − kxk2f n X j=1 αjXj
≥f′
n X j=1 αjXj
hAx, xiI− kxk2
n X j=1 αjXj .
Multiply above inequality by αk and summing onk∈ {1, . . . , n}, we get
* n
X
i=1
αkf(Xk)x, x
+
I− kxk2f
n X j=1 αjXj
≥f′
n X j=1 αjXj * n
X k=1 αkXk ! x, x +
I− kxk2
n X j=1 αjXj . Equivalently, * n X i=1
αkf(Xk)x, x
+
I−f
n X j=1 αjXj
≥f′
n X j=1 αjXj * n
X k=1 αkXk ! x, x + I− n X j=1 αjXj
for kxk= 1which is a Jensen type inequality.
3. Some quantum f-divergence inequalities for convex functions
Let (H,h·,·i) be a complex Hilbert space and{ei}i∈I anorthonormal basis of H.We say thatA∈B(H) is aHilbert-Schmidt operator if
X
i∈I
kAeik2<∞. (3.1)
It is well know that, if {ei}i∈I and {fj}j∈J are orthonormal bases for H and A∈B(H) then
X
i∈I
kAeik2=X
j∈I
kAfjk2=X
j∈I
kA∗fjk2 (3.2)
showing that the definition (3.1) is independent of the orthonormal basis andAis a Hilbert-Schmidt operator iffA∗ is a Hilbert-Schmidt operator.
LetB2(H) the set of Hilbert-Schmidt operators inB(H). ForA∈B2(H) we
define
kAk2:= X
i∈I
kAeik2
!1/2
for {ei}i∈I an orthonormal basis of H. This definition does not depend on the choice of the orthonormal basis.
Using the triangle inequality inl2(I),one checks thatB2(H) is avector space
and that k·k2is a norm on B2(H),which is usually called in the literature as the
Hilbert-Schmidt norm.
Denotethe modulus of an operatorA∈B(H) by|A|:= (A∗A)1/2.
Becausek|A|xk =kAxkfor all x∈H, Ais Hilbert-Schmidt iff|A| is Hilbert-Schmidt and kAk2 =k|A|k2.From (3.2) we have that if A∈B2(H), then A∗ ∈ B2(H) andkAk
2=kA∗k2.
We define thetrace of a trace class operatorA∈B1(H) to be
Tr (A) :=X i∈I
hAei, eii, (3.4)
where {ei}i∈I an orthonormal basis of H.Note that this coincides with the usual definition of the trace if H is finite-dimensional. We observe that the series (3.4) converges absolutely and it is independent from the choice of basis.
Utilising the trace notation we obviously have that
hA, Bi2= Tr (B∗A) = Tr (AB∗) and kAk22= Tr (A∗A) = Tr|A|2
for anyA, B∈B2(H).
IfA≥0 andP ∈B1(H) withP ≥0,then
0≤Tr (P A)≤ kAkTr (P). (3.5)
Indeed, sinceA≥0,thenhAx, xi ≥0 for anyx∈H.If{ei}i∈I an orthonormal basis ofH, then
0≤DAP1/2ei, P1/2eiE≤ kAk P
1/2
ei
2
=kAk hP ei, eii
for anyi∈I.Summing overi∈Iwe get
0≤X
i∈I
D
AP1/2ei, P1/2eiE≤ kAkX
i∈I
hP ei, eii=kAkTr (P)
and since
X
i∈I
D
AP1/2ei, P1/2eiE=X i∈I
D
P1/2AP1/2ei, eiE= TrP1/2AP1/2= Tr (P A)
we obtain the desired result (3.5).
This obviously imply the fact that, ifAand B are self-adjoint operators with A≤B andP∈B1(H) withP ≥0, then
Now, ifAis a self-adjoint operator, then we know that
|hAx, xi| ≤ h|A|x, xi for anyx∈H.
This inequality follows by Jensen’s inequality for the convex function f(t) = |t| defined on a closed interval containing the spectrum ofA.
If{ei}i∈I is an orthonormal basis ofH, then
|Tr (P A)| =
X
i∈I
D
AP1/2ei, P1/2eiE
≤X
i∈I
D
AP1/2ei, P1/2eiE
(3.7)
≤ X
i∈I
D
|A|P1/2ei, P1/2eiE= Tr (P|A|),
for anyA a self-adjoint operator andP ∈B+1 (H) :={P ∈B1(H) withP ≥0}. For the theory of trace functionals and their applications the reader is referred to [22].
For some classical trace inequalities see [4], [5], [18] and [23], which are con-tinuations of the work of Bellman [1].
On complex Hilbert space (B2(H),h·,·i
2), where the Hilbert-Schmidt inner
product is defined by
hU, Vi2:= Tr (V∗U), U, V ∈B2(H),
for A, B ∈ B+(H) consider the operators L
A : B2(H) → B2(H) and RB :
B2(H)→B2(H) defined by
LAT :=AT andRBT :=T B.
We observe that they are well defined and since
hLAT, Ti2=hAT, Ti2= Tr (T∗AT) = Tr|T∗|2
A≥0
and
hRBT, Ti
2=hT B, Ti2= Tr (T∗T B) = Tr
|T|2B≥0
for any T ∈ B2(H), they are also positive in the operator order of B(B2(H)),
the Banach algebra of all bounded operators onB2(H) with the normk·k 2 where
kTk2= Tr
|T|2, T ∈B2(H).
Since Tr|X∗|2
= Tr|X|2for anyX ∈B2(H),then also
Tr (T∗AT) = TrT∗A1/2A1/2T= TrA1/2T∗A1/2T
= Tr
A
1/2T
2
= Tr
A1/2T∗
2
= Tr
T
∗A1/2
forA≥0 andT ∈B2(H).
We observe that LA and RB are commutative, therefore the product LARB
is a self-adjoint positive operator inB(B2(H)) for any positive operatorsA, B ∈ B(H).
For A, B ∈ B+(H) with B invertible, we define the Araki transform A
A,B :
B2(H)→B2(H) byAA,B :=LARB−1.We observe that for T ∈B2(H) we have AA,BT =AT B−1 and
hAA,BT, Ti 2=
AT B−1, T
2= Tr T
∗AT B−1
.
Observe also, by the properties of trace, that
Tr T∗AT B−1= TrB−1/2T∗A1/2A1/2T B−1/2
= TrA1/2T B−1/2∗A1/2T B−1/2= Tr
A
1/2T B−1/2
2
giving that
hAA,BT, Ti 2= Tr
A
1/2T B−1/2
2
≥0 (3.8)
for anyT ∈B2(H).
We observe that, by the definition of operator order and by (3.8) we have r1B2(H)≤AA,B≤R1B2(H) for someR≥r≥0 if and only if
rTr|T|2≤Tr
A
1/2T B−1/2
2
≤RTr|T|2 (3.9)
for anyT ∈B2(H).
We also notice that a sufficient condition for (3.9) to hold is that the following inequality in the operator order ofB(H) is satisfied
r|T|2≤ A
1/2
T B−1/2 2
≤R|T|2 (3.10)
for anyT ∈B2(H).
LetU be a self-adjoint linear operator on a complex Hilbert space (K;h·,·i). The Gelfand map establishes a ∗-isometrically isomorphism Φ between the set C(Sp (U)) of all continuous functions defined on the spectrum of U, denoted Sp (U), and the C∗-algebraC∗(U) generated byU and the identity operator 1K onK as follows:
For anyf, g∈C(Sp (U)) and anyα, β∈Cwe have
(i) Φ (αf+βg) =αΦ (f) +βΦ (g) ; (ii) Φ (f g) = Φ (f) Φ (g) and Φ ¯f
= Φ (f)∗; (iii) kΦ (f)k=kfk:= supt∈Sp(U)|f(t)|;
(iv) Φ (f0) = 1Kand Φ (f1) =U,wheref0(t) = 1 andf1(t) =t,fort∈Sp (U).
With this notation we define
and we call it thecontinuous functional calculus for a self-adjoint operatorU. If U is a self-adjoint operator and f is a real valued continuous function on Sp (U), then f(t)≥ 0 for any t ∈ Sp (U) implies that f(U) ≥0, i.e. f(U) is a positive operator on K. Moreover, if both f and g are real valued functions on Sp (U) then the following important property holds:
f(t)≥g(t) for any t∈Sp (U) implies that f(U)≥g(U) (P)
in the operator order ofB(K).
Letf : [0,∞)→Rbe a continuous function. Utilising the continuous functional
calculus for the Araki self-adjoint operator AQ,P ∈B(B2(H)) we can define the
quantum f-divergence for
Q, P ∈D1(H) :={P ∈B1(H), P ≥0 with Tr (P) = 1}
andP invertible, by
Df(Q, P) :=Df(AQ,P)P1/2, P1/2E 2= Tr
P1/2f(AQ,P)P1/2. (3.11)
If we consider the continuous convex function f : [0,∞)→R, withf(0) := 0 andf(t) =tlntfort >0 then forQ, P ∈D1(H) andQ, P invertible we have
Df(Q, P) = Tr [Q(lnQ−lnP)] =:U(Q, P),
which is the Umegaki relative entropy.
If we take the continuous convex function f : [0,∞) → R, f(t) = |t−1| for
t≥0 then forQ, P ∈D1(H) withP invertible we have
Df(Q, P) = Tr (|Q−P|) =:V(Q, P),
whereV (Q, P) is the variational distance.
If we takef : [0,∞)→R,f(t) =t2−1 fort≥0 then forQ, P ∈D1(H) with
P invertible we have
Df(Q, P) = Tr Q2P−1−1 =:χ2(Q, P),
which is called theχ2-distance
Letq∈(0,1) and define the convex functionfq : [0,∞)→Rbyfq(t) = 1−1−tqq. Then
Dfq(Q, P) =1−Tr Q qP1−q
1−q , which isTsallis relative entropy.
If we consider the convex functionf : [0,∞)→Rbyf(t) =1 2
√
t−12,then
Df(Q, P) = 1−TrQ1/2P1/2=:h2(Q, P),
If we take f : (0,∞) → R, f(t) = −lnt then for Q, P ∈ D1(H) and Q, P
invertible we have
Df(Q, P) = Tr [P(lnP−lnQ)] =U(P, Q).
The reader can obtain other particular quantumf-divergence measures by utilizing the normalized convex functions from Introduction, namely the convex functions defining the dichotomy class, Matsushita’s divergences, Puri-Vincze divergences or divergences of Arimoto-type. We omit the details.
In the important case of finite dimensional spaceH and the generalized inverse P−1, numerous properties of the quantumf-divergence, mostly in the case when f isoperator convex,have been obtained in the recent papers [15], [16], [20], [21] and the references therein.
In the following theorem we apply the same proof of Theorem2.3.
Theorem 3.1. LetAQ,P be Araki self-adjoint operator on B(B2(H))and
Sp(AQ,P)⊆[m, M]⊂I˚whereI is an interval. If the functionf :I→Ris convex
on I, then
hf(AQ,P)T, Ti2 − f(M)−f(m)
M−m hAQ,PT, Ti2
≥
"
2 M −m
Z M
m
f(t)dt−M f(M)−mf(m)
M −m
#
kTk22.
for T ∈B2(H).
Remark 3.2. Let T =P12 in above theorem we get
hf(AQ,P)P12, P21i2 − f(M)−f(m)
M −m hAQ,PP 1 2, P12i2
≥
"
2 M −m
Z M
m
f(t)dt−M f(M)−mf(m)
M −m
#
.
for kP12k2= 1.
On the other hand, by (3.11) we have
Df(Q, P)≥f(MM)−f(m)
−m +
"
2 M −m
Z M
m
f(t)dt−M f(MM)−mf(m)
−m
#
(3.12)
since Q∈D1(H).
If we take the continuous convex function f : [0,∞) → R, f(t) = |t−1| for
t≥0 then forP, Q∈D1(H) withP invertible we have the following form≥1
Df(Q, P) = Tr(|Q−P|)
= V(Q, P)≥2(M+m−1).
Theorem 3.3. LetAQ,P andBV,U be two Araki self-adjoint operators onB(B2(H))
withSp(AQ,P),Sp(BV,U)⊆[m, M]⊂˚Iandf :I→Ra continuously differentiable
convex function on I. Then
hf(AQ,P)T, Ti2kSk2 − hf(BV,U)S, Si2kTk2
≥ DhAQ,PT, Ti2f′(BV,U)− kTk2f′(BV,U)BV,US, SE
2
for any x, y∈H.
Remark 3.4. Let T =P12 andS=U12 in above theorem we get
hf(AQ,P)P12, P12i2 − hf(BV,U)U12, U12i2
≥ DhAQ,PP12, P12i2f
′
(BV,U)−f′(BV,U)BV,UU12, U12
E
2
for kP12k2=kU12k2= 1.
From above inequality we have
Df(Q, P)−Df(V, U)≥Trf′(BV,U)U−f′(BV,U)V (3.13)
sinceQ∈D1(H).
Putf(t) =t2−1 for t≥0 in above inequality (3.13) we get
χ2(Q, P)−χ2(V, U)≥2 Tr (BV,UU−BV,UV)
whereP, Q, U, V ∈D1(H) andP, U are invertible. Equivalently, we have
χ2(Q, P)−χ2(V, U)≥2 Tr V −V2U−1
.
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A. Taghavi, V. Darvish, H. M. Nazari,
Department of Mathematic,s Faculty of Mathematical Sciences, University of Mazandaran, P. O. Box 47416-146, Babolsar, Iran.
E-mail address:[email protected] [email protected], [email protected]
and
S. S. Dragomir,
Mathematics, School of Engineering and Science, Victoria University
P. O. Box 14428, Melbourne City, MC 8001, Australia.