“FORMATION OF UNIFIED EULERIAN INTEGRALS
OFHYPERGEOMETRIC FUNCTION WITH STATISTICAL
DISTRIBUTION”
1
Ms. Samta Gulia ,2 Prof. (Dr.) R.S.Verma and 3Prof. (Dr.) Harish Singh
1Research Scholar, NIMS University, Jaipur, Rajasthan, India
2
Head of Department of Mathematics NIMS University, Jaipur, Rajasthan, India
3
Professor, Maharaja Surajmal Institute, Affiliated to Guru Gobind Singh Indraprastha University, New Delhi, India
INTRODUCTION
In this paper, we evaluate three unified Eulerian integrals. First integral involve the general class polynomials SVU x and the generalized sequence of function Sn,,O x . The
second integral involve the multivariable polynomials by generalized the general class of polynomial 1 r
r 1
,...U U
,...V V
S [x1,...,xr] which was giving by Srivastava where as the last third
integral contain the product of another class of multivariable polynomials by generalized the general class of polynomial U1,...U r
V
S [x1,...,xr] which was introduced by Srivastava
ABSTRACT
In this research paper we proved three Eulerian Integrals. The results of these Integrals
provide interesting unifications and extensions of new and known results. Our integrals
involve simpler polynomials like as , Jacobi polynomials, generalized Lauricella
and Garg (1987) and all the above three integrals used the multivariable Hypergeometric function which was introduced by Srivastava and Daoust (1969) in their integrals.
1.1 Theorem:1 Second Eulerian Integrals Involving U
V
S [x] and Sn, ,0
[x]:
Prove that
1
0
xm(a-1)(1-xm)b-1 U
V
S
yx (1 xm)v
μ m
, ,0
n
S
) x (1 hx m m
1 n n 1
;...q q : p
;...m 1;m
F
λ m λ m λ
m λ m )
n ( q q
p
) n ( m m
1
) x -(1 x n z ,...., ) x -(1 x 1 z ); (b ...; );... (b
: ) a (
); ( β ; ... . ); ( β : ) (
n 1
n 1
dx
= m
1) -m
1 Γ(
) ( 1) -m
1 Γ(
) U V (
0 k
1 (k, v, u, e, p)
n 1
n 1
;...q q : λ 2 p
;...m m λ; 2 1
F
4 z ,...., 4 z ); (b ; );... (b
: λ
2) -m
1 ( ,..., λ
1 -m
1 : ) a (
); ( β ...; . ); ( β λ
2) -m
1 (
,..., λ
1) -m
1 (
: ) (
n 1
) n ( q q
p
) n ( m m
1
n 1
n 1
(1.1) Then p.d.f form of (1.1),we have
F(x) =
] [ p)F
e, u, v, (k, 1)
-1 Γ(
) Γ( 1) -m
1 Γ(
] [ F
] ) x (1 hx [ S ] ) x (1 yx [ S ) x (1 x
2 n ;...q 1 :q λ 2 p
n ;...m 1 m λ; 2 1 1
) U V (
0 k
1 n ;...q 1 p:q
n ;...m 1 m 1; m m
,0 , n m u m U V 1 b m 1) (a m
m
v
Where
1 =
λ m λ m λ
m λ m ) n ( q q
p
) n ( m m
1
) x -(1 x n z ,...., ) x -(1 x 1 z ); (b ...; );... (b
: ) a (
); ( β ; ... . ); ( β : ) (
n 1
n 1
and
4 z ,...., 4 z );
(b );...; (b : λ
2) -m
1 (
.., ,... λ
1) -m
1 (
: ) a (
); ( β ...; . ); ( β λ
2) -m
1 (
,..., λ
1) -m
1 (
: ) (
n 1 )
n ( n q 1
q p
) n ( n m 1
m 1
2
In this integral, we use the definitions of the general class of polynomials U V
S [x], the
generalized sequence of function , ,0 n
S [x] and the multivariable Hypergeometric function
and we calculated the equation (1.1) and make its pdf form (1.2). Here we take xm instead of x in the above definitions and we find a new results shown in proof:
Where
1 (k, v, u, e, p) =
K!
p)h e, u, (v, K) A(V, V)
( UK 1 R
yk (1.3)
α = a + k + R and β = b + + R (1.4) Now assumed the following conditions are to be satisfied.
(iv) Re (a, b, r) > 0, Re (α, β) > 0
(v) Min (, p, q) > 0 (j = 1, 2, ...,n) (not all zero simultaneously) (vi) (a) > 0, v > 0, 1 > 0, 2 > 0
(b) < 0, v < 0, 1 + [V/U] > 0, 2 + v [V/U] > 0
(c) > 0, v 0, 1 > 0, 2 + v [V/U] > 0
where
1 = Re (a) + {(1(m + n) + p +
n
1 j
j
q
2 = Re (a) + {(1(m + n) + p +
n
1 j
j
q
Proof:- To find the first integral (1.1), We first express the general class of polynomials
U V
S [x] and the generalized sequence of function Sn,,0 [x] which was introduced and studies by various research workers such as Singh (1981),Singh and Srivastava (1964), Krall and Frink (1949), Gould and Hopper (1962), Dhilion (1989), etc as defined below: The generalized sequence of function is
0 , , n
S [x] =
p e, u, v,
1
θ (v, u, e, p) xR ... (1.5)
The general class of polynomials is introduced as
U V
S [x] =
) U V (
0
K K!
K) A(V, V) ( UK
xK N= 0,1,2... ... (1.6)
By putting the value from (1.5), (1.6) in (1.1) by taking xm instead of x in the above formulas, while (1.6) is certainly useful generalization, it seems that for some purposes, multiple Hypergeometric function which are of a less general nature are of more immediate value. To this end, we consider the generalized Kamp’ ede Fe’riet function first given by Karlson (1973) which we define later..
1
0
xm(a-1)(1-xm)b-1 U
V
S
yxmμ(1xm)v
Sn,,0
n 1
n 1
;...q q : p
;...m 1;m
F
z1x (1 - x) ,...., znx (1 -x)
); (b ...; );... (b : ) a (
); (β ; ... . ); (β : ) (
λ λ
) n ( n q 1
q p
) n ( n m 1
m 1
dx (1.7)
1
0
xm(a-1) (1-xm)b-1
) U V (
0
k K!
K) A(V, V) ( UK
ykxmk (1-xm)vk
) U V (
0 k
θ1 (k, v, u, e, p)hRxmR
(1-xm)ζR 1 n n 1
;...q q : p
;...m 1;m
F
z1x (1 -x) ,...., znx (1 -x)
); (b ...; );... (b : ) a (
); ( β ; ... . ); ( β : ) (
λ λ
) n ( n q 1
q p
) n ( n m 1
m 1
dx (1.8)
By using multivariable Hypergeometric function which is giving by Srivastava and Daoust (1969) have giving the multiple series as:
(n) ;...q 1 :q p
(n) ;...m 1 m 1;
F
n
z z
: :
1
1 (n)
(n) 1
;...q q : p
;...m m 1;
F
n z ,...., 1 z ); (b ...; );... (b
: ) a (
); ( β ; ... . ); ( β : ) (
) n ( q q
p
) n ( m m
1
n 1
n 1
=
0 s ,..., s1 n
A(s1,...,sn)
! s z
1 s 1
1
...
! s z
n s n
n
(1.9)
Where
A(s1,...,sn)
n
n 1
1 n
1
(n)
n 1
1 n
1
m
1 j
s (n) j m
1 j
... s j 1
1 j
s ... s j
q
1 j
s (n) j q
1 j
... s j p
1 j
s ... s j
) ( β )
( β )
(
) (b )
(b )
(a
Putting value F1;p:qm11;...q;...m nn
λ λx n z ,...., x 1
1
0
xm(a-1) (1-xm)b-1
) U V ( 0 k K! K) A(V, V) ( UK
ykxmk (1-xm)vk
) U V ( 0 k
1 (v, u, e, p)hRxmR
×(1-xm)ζR
0 m ,..., m1 1
(m1, ..., mn)
! m 1 x z 1 1 m 1 m λ 1 m 1 x ... ! m 1 x z 1 1 m 1 m λ n m n x dx Where
(m1, ..., mn)=
(n) (n) j n j 1 (n) j n j 1 (n) (n) j 1 j 1 (n) j n j 1 D 1 j m (n) j D 1 j ... m j C 1 j ψ m ... ψ m j B 1 j m (n) j B 1 j ... m j A 1 j θ m ... θ m j ) (d ) (d ) (c ) (b ) (b ) (a =
) U V ( 0 k K! K) A(V, V) ( UKyk
) U V ( 0 k
1 (v, u, e, p)hR
10
xm(a-1)(1-xm)b-1xmuk(1-xm)vkxmR(1-xm)ζR
(n) D 1 j (n) j n m (n) j D 1 j ... j 1 m j C 1 j (n) j ψ n m ... j ψ 1 m j (n) B 1 j (n) j 1 m (n) j B 1 j ... j 1 m j A 1 j (n) j θ n m ... j θ 1 m j ) (d ) (d ) (c ) (b ) (b ) (a ! m 1 x z 1 1 m 1 m λ 1 m 1 x ... ! m 1 x z 1 1 m 1 m λ n m n x dx =
) U V ( 0 k K! K) A(V, V) ( UKyk
) U V ( 0 k
1 (v, u, e, p)hR
10
(xm)a+k+R-1(1-xm)b+vR+ζR-1
(n) (n) j n j 1 (n) j n j 1 (n) (n) j n j 1 (n) j n j 1 D 1 j m (n) j D 1 j ... m j C 1 j ψ m ... ψ m j B 1 j m (n) j B 1 j ... m j A 1 j θ m ... θ m j ) (d ) (d ) (c ) (b ) (b ) (a ! m 1 x z 1 1 m 1 m λ 1 m 1 x ... ! m 1 x z 1 1 m 1 m λ n m n x dx =
) U V ( 0 k K! K) A(V, V) ( UKyk
) U V ( 0 k
1 (v, u, e, p)hR
10
(n) (n) j n j 1 (n) j n j 1 (n) (n) j 1 j 1 (n) j n j 1 D 1 j m (n) j D 1 j ... m j C 1 j ψ m ... ψ m j B 1 j m (n) j B 1 j ... m j A 1 j θ m ... θ m j ) (d ) (d ) (c ) (b ) (b ) (a ! m 1 x z 1 1 m 1 m λ 1 m 1 x ... ! m 1 x z 1 1 m 1 m λ n m n x dx (1.10) Where α = a + k + R and β = b + k + R=
) U V ( 0 k K! K) A(V, V) ( UKyk
) U V ( 0 k
1 (v, u, e, p)hR
(n) (n) j n j 1 (n) j n j 1 (n) (n) j 1 j 1 (n) j n j 1 D 1 j m (n) j D 1 j . ... m j C 1 j ψ m ... ... ψ m j B 1 j m (n) j B 1 j ... .... m j A 1 j θ m ... ... θ m j ) (d ) (d ) (c ) (b ) (b ) (a
1 0 1 m ... ... m λ 1) 1m ( 1
x n m
(1-xm)β-1
! m 1 z 1 1 m 1 m 1 x ... ! m 1 z n 1 m n m n x
dx (1.11)
Where x x dx x x dx x m xm dx
m m m m m m 1 1 0 1 ) 1 1 ( 1 1 0 ) 1 1 ( 1 1 0 ) 1 ( ) 1 ( ) 1 ( ) 1 (
By using beta integral now applying Euler Integrals
01 xa-1
(1-x)b-1f(x) dx =
) Γ(a ) ( ) Γ( b b a
n n n n ) ( C ) ( b a Above formula can be transformed into the following asdx x
x m m
m 1 1 0 1 ) 1 1 ( ) 1 (
= m
=
) U V ( 0 k K! K) A(V, V) ( UKyk
) U V ( 0 k
1 (v, u, e, p)hR
(n) (n) j n j 1 (n) j n j 1 (n) (n) j n j 1 (n) j n j 1 D 1 j m (n) j D 1 j ... m j C 1 j ψ m ... ψ m j B 1 j m (n) j B 1 j ... m j A 1 j θ m ... θ m j ) (d ) (d ) (c ) (b ) (b ) (a × m 1) -m 1 Γ( ) 1) Γ) -m 1 Γ( n 1 n 1 n 1 n 1 λm ... λm λm ... λm λm ... λm λm ... λm ) m 1 ( ) 1 -m 1 ( ) ( ) 1 -m 1 ( = m 1) -m 1 Γ( ) 1) Γ) -m 1 Γ(
) U V ( 0 kɸ1 (k,v, u, e, p)×
n ;...q 1 q : λ 2 p n ;...m 1 m λ; 2 1 F 2 n 2 1 ) n ( n q 1 q p ) n ( n m 1 m 1 2 z ,...., 2 z ); (b ...; );... (b : λ 1 -λ 1) -m 1 ( ,..., λ 1 -m 1 : ) a ( ); ( β ; ... . ); ( β λ 1 -λ 1) -m 1 ( ,..., λ 1) -m 1 ( : ) (
Where
) U V ( 0 k
1 (k,v, u, e, p) =
) U V ( 0 k K! K) A(V, V) ( UKyk
) U V ( 0 k
1 (v, u, e, p)hR
(1.13) = m 1 ) 1) Γ) -m 1
Γ(
) U V (
ɸ1 (k,v, u, e, p)
4 z ,...., 4 z ); (b ...; );... (b : λ 2) -m 1 ( ,..., λ 1 -m 1 : ) a ( ); ( β ; ... . ); ( β ; λ 2) -m 1 ( ,..., λ 1) -m 1 ( : ) ( n 1 ) n ( n q 1 q p ) n ( n m 1 m 1 (1.14) Hence First integral is proved
2.1 Theorem 2: Second Eulerian Integral Involving 1 r
r 1 ;...U U ;...V V
S [x1....xr]
Prove that
1
0
xm(a-1) (1-xm)b-1 1 r
r 1 ;...U U ;...V V
S
v vr
) x (1 x y ,..., ) x (1 x y m μ m r m μ m 1 r 1 1 n 1 n 1 ;...q q : p ;...m 1;m F λ m λ m λ m λ m ) n ( q q p ) n ( m m 1 ) x -(1 x n z ,...., ) x -(1 x 1 z ); (b ...; );... (b : ) a ( ); ( β ; ... . ); ( β : ) ( n 1 n 1 dx = 1) -m 1 Γ( ) 1) Γ -m 1 Γ( 1 1 1 1 ( m
) U V ( 0 k 1 1 1 …...
) U V ( 0 k r r r r r 11K ... r U K
U
t) ( v )
v
( A(V1, k1 ; …...Vr, kr)
r 1 i 1 k i ! k y i 1 n
F(x) = ] [ F ! k k y ) k , ...v . ; k , A(v ) v ( . ) v ( ... 1) -m 1 Γ( ) ( 1) -m 1 Γ( ] [ F ] ) x (1 x y ... ) x (1 x y [ S ) x (1 x 4 n ;...q 1 :q λ p n ;...m 1 m λ; 1 r 1 i 1 i i r r 1 1 r k r v r ) r U r V ( 0 r k ... 1 k 1 u r ) 1 U 1 V ( 0 1 k 1 1 1 1 3 n ;...q 1 p:q n ;...m 1 m 1; m r u m r 1 m u m 1 r ;...v 1 u r ;...v 1 v 1 b m 1) (a m m r v v
= 0 elsewhere (2.2) Where
3 =
λ m λ m λ m λ m ) n ( q q p ) n ( m m 1 ) x -(1 x n z ,...., ) x -(1 x 1 z ); (b ...; );... (b : ) a ( ); ( β ; ... . ); ( β : ) ( n 1 n 1 and 4 z ,...., 4 z ); (b ; );... (b ; λ 2) -m 1 ( ,..., λ 1 -m 1 : ) a ( ); ( β ...; . ); ( β ; λ 2) -m 1 ( ,..., λ 1) -m 1 ( : ) ( n 1 ) n ( n q 1 q 1 1 p ) n ( n m 1 m 1 1 1 1 1 4
To prove this integral we define as following the multivariable Hypergeometric Function by generalized the general class of polynomial 1 r
r 1 ;...U U ;...V V
S [x1....xr] .
r 1 r 1 U ... U V ... V
S [x1, ..., xr] =
) U V ( 0 k 1 1 1
) U V ( 0 k r r r ) ....k k A(V, ) V ( ) V( 1 U k ... r U k ...U k 1 r
1 r r 1
1
! k x ... ! k x r k r 1 k 1 r 1 (2.3)
Where Vi = 0, 1,2 ... (i = 1, ..., r), U1,...Ur are arbitrary positive integers, The
Where
α1 = a +
n
1 j
j kj and β1 = b +
n
1 j
vj kj (2.4)
Now assumed the following conditions are to be satisfied. (x) Re (a, b, r) > 0, Re (α1, β1) > 0
(xi) Min (, p, q) > 0 (j = 1, 2, ..., n) (not all zero simultaneously) (xii) (a) 1 > 0, 2 > 0
(b) 1 + [V/U] > 0, 2 + [V/U] > 0
(c) 1 > 0, 2 + [V/U] > 0
(d) 1 + [V/U] > 0 and 2 > 0
Where
1 = Re (a) + p +
n 1 j
j
q and 2 = Re (a) + p +
n
1 j
j
q (2.5)
3.1 Theorem 3: Third Eulerian Integrals Involving
r ..U ;... 1 U V
S [x1…….xr] :
Prove that
1
0
xm(a-1) (1-xm)b-1 U1;...U r
V
S
v vr
) x (1 x y ,..., ) x (1 x
y m
μ m r m
μ m 1
1
n 1
n 1
;...q q : p
;...m 1;m
F
λ m λ m λ
m λ m )
n ( q q
p
) n ( m m
1
) x -(1 x n z ,...., ) x -(1 x 1 z ); (b ...; );... (b
: ) a (
); ( β ; ... . ); ( β : ) (
n 1
n 1
dx
= m
1 ) 1) Γ -m
1
Γ(2 (2
...Uk v k
U1 1 r r
1 1K ...U K U
v)
n 1 n 1 .q ;... q : λ 2 p .m ;... m λ; 2 1
F
4 z ,...., 4 z ); (b ; );... (b : λ 2) -m 1 ( ,..., λ 1 -m 1 : ) a ( ); ( β ...; . ); β ( ; λ 2) -m 1 ( ,..., λ 1) -m 1 ( : ) ( n 1 ) n ( q q 2 2 p ) n ( m m 2 2 2 2 1 n 1 n 1 (3.1) Then p.d.f. of (3.1) is given by:
F(x) = ] [ F ) k , ...v . ; k , A(v ) v ( 1) -m 1 Γ( ) 1) Γ -m 1 Γ( ] [ F ] ) x (1 x y ... ) x (1 x y [ S ) x (1 x 6 n ;...q 1 :q λ p 2 ;...m 1 m λ; 1 r r 1 1 r k r v ... 1 k 1 u r v r k r U ... 1 k 1 U 0 r k ,..., 1 k 2 2 2 2 5 n ;...q 1 p:q n ;...m 1 m 1; m r u m r 1 m u m 1 r ;...v 1 u v 1 b m 1 a m
( m r v v (3.2) = 0, elsewhereWhere
5 =
To prove this integral we define as following the multivariable Hypergeometric Function by generalized the general class of polynomial SVU1;...Ur [x1…….xr] as follows:
r 1...U
U V
S [x1, ..., xr] =
V k ....U k U
0 k ,... k
r r 1 1
r 1
) ....k k A(V, V)
( Uk ...U k 1 r
1 1
1
! k x ... ! k x
r k r
1 k 1
r 1
. (3.3)
where U1 ... Ur are arbitrary positive integers and the coefficient A(V; k1, ... kr)
(V, k1 > 0, i = 1, ...., r) are arbitrary constants, real or complex. By using (3.3) and the
multivariable Hypergeometric function from (1.9),we occurred (2.1) and its pdf form (3.2).
Where α2 = a +
n
1 j
jkj and β2 = b +
n
1 j
vjkj (3.4)
Now assumed the following condition to be satisfied. (xvi) Re (a, b, r) > 0, Re (α2, β2) > 0
(xvii) Min (, p, q) > 0 (j = 1, 2, ...,n) (not all zero simultaneously) (xviii) (a) 1 > 0, 2 > 0
(b) 1 + [V/U] > 0, 2 + [V/U] > 0
(c) 1 > 0, 2 + [V/U] > 0
(d) 1 + [V/U] > 0 and 2 > 0
Where
1 = Re (a) + p +
n
1 j
j
q
Proofs of Theorem 2 and Theorem 3: The equations (2.1) of theorem 2 and (3.1) of theorem 3, can be derived by following the same lines as given in the proof of first integral and making appropriate modifications and changes.
References:
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