http://www.scirp.org/journal/ajcm ISSN Online: 2161-1211 ISSN Print: 2161-1203
An Algorithm to Classify the Asymptotic Set
Associated to a Polynomial Mapping
Nguyen Thi Bich Thuy
IBILCE, UNESP, Universidade Estadual Paulista, "Júlio de Mesquita", São José do Rio Preto, São Paulo, Brazil
Abstract
We provide an algorithm to classify the asymptotic sets of the dominant po-lynomial mappings 3 3
:
F → of degree 2, using the definition of the
so-called “façons” in [2]. We obtain a classification theorem for the asymptotic sets of dominant polynomial mappings 3 3
:
F → of degree 2. This
algo-rithm can be generalized for the dominant polynomial mappings F:n→n
of degree d, with any
( )
n d, ∈( )
∗ 2.Keywords
Algorithms, Polynomial Mappings, Asymptotic Sets, Façons
1. Introduction
Let F:n→n be a polynomial mapping. Let us denote by F
S the set of
points at which F is non proper, i.e.,
{ }
( )
{
n such that n, tends to infinity and tends to}
,F k k k k
S = a∈ ∃ ξ ∈ ⊂ ξ F ξ a
where ξk is the Euclidean norm of ξk in
n
. The set SF is called the
asymptotic set of F. The comprehension of the structure of this set is very important by its relation with the Jacobian Conjecture. In the 90’s, Jelonek studied this set in a deep way and described the principal properties. One of the important results is that, if F is dominant, i.e.,
( )
n nF = , then SF is an
empty set or a hypersurface [1].
Notice that it is sufficient to define SF by considering sequences
{ }
ξktending to infinity in the following sense: each coordinate of these sequences either tends to infinity or converges. In [2], the sequences tending to infinity such that their images tend to the points in SF are labeled in terms of “façons”,
as follows: We rank the coordinates of ξk into three categories: 1) the
coordinates tending to infinity (this cotegories is not empty); 2) the coordinates
How to cite this paper: Thuy, N.T.B. (2017) An Algorithm to Classify the Asymp-totic Set Associated to a Polynomial Map-ping. American Journal of Computational Mathematics, 7, 109-126.
https://doi.org/10.4236/ajcm.2017.71010
Received: January 18, 2017 Accepted: March 28, 2017 Published: March 31, 2017
Copyright © 2017 by author and Scientific Research Publishing Inc. This work is licensed under the Creative Commons Attribution International License (CC BY 4.0).
( )
xk i, such that limk→∞xk i, is a complex number “independant on the point a in a neighborhood a in SF”. This means that there exists the points neighbors of ain SF and the sequences
{ }
ξk′ such that limk→∞F( )
ξk′ =a′ and, ,
limk→∞xk i′ =limk→∞xk i, 3) the coordinates
( )
xk i, such that limk→∞xk i, is a complex number “dependant on the point a”. This means that there not exist such points a′ neighbors of a in SF . The example 2.5 illustrates these threecategories.
We define a “façon” of the point a∈SF as a
(
p q,)
-tuple(
i1,,ip)
j1,,jq of integers where ,ra k i
x tends to infinity for r=1,,p
and, for s=1,,q, the sequence ,
s
a k j
x tends to a complex number independently
on the point a when a describes locally SF (definition 2.7).
The aim of this paper is to provide an algorithm to classify the asymptotic sets of dominant polynomial mappings 3 3
:
F → of degree 2, using the definition of
“façons” in [2], and then generalize this algorithm for the general case. One important tool of the algorithm is the notion of pertinent variables. The idea of the notion of pertinent variables is the following: Let
(
)
3 31, 2, 3 :
F = F F F → be a
dominant polynomial mapping of degree 2 such that SF ≠ ∅. We fix a façon κ
of F and assume that
{ }
ξk is a sequence tending to infinity with the façon κsuch that F
( )
ξk tends to a point of SF. Since the degree of F is 2 then eachcoordinate F F1, 2 and F3 of F is a linear combination of f1=x1, f2=x2,
3 3
f =x , f4 =x x1 2, f5=x x2 3 and f6=x x3 1. We call a pertinent variable of F
with respect to the façon κ a minimum linear combination of f1,,f6 such that the image of the sequence
{ }
ξk by this combination does not tend toinfinity (see definition 3.1).
Moreover, if F is dominant then by Jelonek, the set SF has pure dimension 2
(see theorem 2.4). With this observation and with the idea of pertinent variables, we:
• Make the list
( )
of all possible façons for a polynomial mapping3 3
:
F → . This list is finite. In fact, there are 19 possible façons (see the list
(3.4)).
• Assume that a 2-dimensional irreductible stratum S of SF admits l fixed
façons in the list
( )
, where 1≤ ≤l 19.• Determine the pertinent variables of F with respect to these l façons.
• Restrict the above pertinent variables using the dominancy of F and the fact
that the dimension of S is 2. We get the form of F in terms of these pertinent variables.
• Determine the geometry of S in terms of the form of F.
• Let l runs in the list
( )
for 1≤ ≤l 19. We get all the possible 2-dimen- sional irreductible strata of SF. Since the dimension of SF is 2, then we getthe list of all possible asymptotic sets SF.
With this idea, we provide the algorithm 3.10 to classify the asymptotic sets of dominant polynomial mappings 3 3
:
F → of degree 2, and we obtain the
(algorithm 5.1).
2. Dominancy, Assymptotic Set and “Façons”
2.1. Dominant Polynomial MappingDefinition 2.1. Let F:n→n be a polynomial mapping. Let
( )
nF be the
closure of F
( )
n in n . F is called dominant if
( )
n nF = , i.e., F
( )
n isdense in n
.
We provide here a lemma on the dominancy of a polynomial mapping : n n
F → that we will use later on.
Lemma 2.2. Let
(
1, ,)
:n n
n
F = F F → be a dominant polynomial
mapping. Then, the coordinate polynomials F1,,Fn are independent. That
means, there does not exist any coordinate polynomial Fη, where η∈
{
1,,n}
,such that Fη is a polynomial mapping of the variables F1,,Fη−1,Fη+1,,Fn.
Proof. Assume that Fη =ϕ
(
F1,,Fη−1,Fη+1,,Fn)
where η∈{
1,,n}
and ϕ is a polynomial. Then, the dimension of
( )
nF is less than n.
Consequently, the dimension of
( )
nF is less than n. That provides the
contradiction with the fact F is dominant.
2.2. Asymptotic Set
Definition 2.3. Let F:n→n be a polynomial mapping. Let us denote by
F
S the set of points at which F is non-proper, i.e.,
{ }
( )
{
n such that n, and}
,F k k k k
S = a∈ ∃ ξ ∈ ⊂ ξ → ∞ F ξ →a
where ξk is the Euclidean norm of ξk in
n
. The set SF is called the
asymptotic set of F.
Recall that, it is sufficient to define SF by considering sequences
{ }
ξktending to infinity in the following sense: each coordinate of these sequences either tends to infinity or converges to a finite number.
Theorem 2.4. [1] Let F:n→n be a polynomial mapping. If F is
dominant, then SF is either an empty set or a hypersurface.
2.3. “Façons”
In this section, let us recall the definition of façons as it appears in [2]. In order to a better understanding of the definition of façons, let us start by giving an example.
Example 2.5. [2] Let
(
)
(1 2 3) (1 2 3)3 3
1, 2, 3 : x x x, , , ,
F= F F F →α α α be the polynomial
mapping such that
1: 1, 2: 2, 3: 1 2 3.
F =x F =x F =x x x
Notice that by the notations (1 2 3)
3 , ,
x x x
and ( 1 2 3)
3 , ,
α α α
, we want to distinguish the source space and the target space. We determine now the asymptotic set SF by using the definition 2.3. Assume that there exists a
sequence
{
ξk =(
x1,k,x2,k,x3,k)
}
in the source space (1 2 3)3 , ,
x x x
1,k
x and x2,k cannot tend to infinity. Since the sequence
{ }
ξk tends toinfinity, then x3,k must tend to infinity. Hence, we have the three following
cases:
1) x1,k tends to 0, x2,k tends to a complex number α2∈ and x3,k tends
to infinity. In order to determine the biggest possible subset of SF, we choose
the sequences x1,k tending to 0 and x3,k tending to infinity in such a way that
the product x x1,k 3,k tends to a complex number α3. Let us choose, for example
3 2 2 1 , , k k k α ξ α α =
where α2 ≠0, then F
( )
ξk tends to a point a=(
0,α α2, 3)
in SF. We get a 2-dimensional stratum S1 of SF, where S1=(
α1 =0 \)
( 1 2 3) 3
3 , ,
0α ⊂α α α . We say that a “façon” of S1 is
( )
3 1[ ]
. The symbol “(3)” in the façon( )
3 1[ ]
means that the third coordinate x3,k of the sequence{ }
ξktends to infinity. The symbol “[1]” in the façon
( )
3 1[ ]
means that the first coordinate x1,k of the sequence{ }
ξk tends to 0 which is a fixed complexnumber which does not depend on the point a=
(
0,α α2, 3)
when a describes1
S . Notice that the second coordinate of the sequence
{ }
ξk tends to a complexnumber α2 depending on the point a=
(
0,α α2, 3)
when a varies, then the indice “2” does not appear in the façon( )
3 1[ ]
. Moreover, all the sequences tending to infinity such that their images tend to a point of S1 admit only the façon( )
3 1[ ]
.The two following cases are similar to the case 1):
2) x1,k tends to a complex number α1∈, x2,k tends to 0 and x3,k tends
to infinity: then the façon
( )
3 2[ ]
determines a 2-dimensional stratum S2 ofF
S , where
(
)
( )1 2 3
3 2 2 0 \ 0 3 , ,
S = α = α ⊂α α α .
3) x1,k and x2,k tend to 0, and x3,k tends to infinity: then the façon
( )
3 1, 2[ ]
determines the 1-dimensional stratum S3 where S3 is the axis 0α3 in ( 1 2 3)3 , ,
α α α
.
In conclusion, we get
• the asymptotic set SF of the given polynomial mapping F as the union of
two planes
(
α1=0)
and(
α2 =0)
in ( 1 2 3)3 , ,
α α α
,
• all the façons of SF of the given polynomial mapping F: they are three
façons
( )
3 1[ ]
,( )
3 2[ ]
and( )
3 1, 2[ ]
.Remark 2.6. The chosen sequence 3 2 2 1 , , k k k α ξ α α =
in 1) of the above
example is called a generic sequence of the 2-dimensional irreductible component
(
α1=0)
(a plane) of SF, since the image of any sequence of thistype (with differents α2 ≠0 and α3) falls to a generic point of the plane
(
α1=0)
. That means the images of all the sequences{ }
ξk when α2 runs in{ }
\ 0
and α3 runs in cover S1=
(
α1=0 \ 0)
α3 and S1 is dense in the plane(
α1=0)
. We can see easily that a generic sequence of the 2-dimensional irreductible component(
α2 =0)
of SF is 1 31
1 , ,k
k α α α
where α1≠0. More
generally, any sequence 3 2 2 1 , , r r k k α α α
generic sequence of
(
α1=0)
⊂SF. Any sequence 1 3 1 1 , ,r r
k k
α α
α
, where
{ }
\ 0
r∈ and α1≠0, is a generic sequence of
(
α2 =0)
⊂SF.In the light of this example, we recall here the definition of façons in [2]. Definition 2.7. [2] Let F:n→n be a dominant polynomial mapping such that SF ≠ ∅. For each point a of SF, there exists a sequence
{ }
a n
k
ξ ⊂ ,
(
,1, , ,)
a a a
k xk xk n
ξ = tending to infinity such that
( )
a kF ξ tends to a. Then,
there exists at least one index i∈, 1≤ ≤i n such that a, k i
x tends to infinity
when k tends to infinity. We define “a façon of tending to infinity of the sequence
{ }
ak
ξ ”, as a maximum
(
p q,)
-tuple κ=(
i1,,ip)
j1,,jq ofdifferent integers in
{
1,,n}
, such that:1) ,r
a k i
x tends to infinity for all r=1,,p,
2) for all s=1,,q , the sequence ,
s
a k j
x tends to a complex number
independently on the point a when a varies locally, that means:
a) either there exists in SF a subvariety Ua containing a such that for any
point a′ in Ua, there exists a sequence
{ }
ξka′ ⊂n , ξka(
xka,1, ,xk na,)
′= ′ ′
tending to infinity such that i)
( )
ak
F ξ ′ tends to a′,
ii) ,r a k i
x′ tends to infinity for all r=1,,p,
iii) for all s=1,,q, lim ,s lim ,s
a a
k j k j
k x k x
′
→∞ = →∞ and this limit is finite.
b) or there does not exist such a subvariety, then we define
(
i1, ,ip)
j1, ,jn p ,κ = −
where ,r
a k i
x tends to infinity for all r=1,,p and
{
i1,,ip} {
∪ j1,,jn p−}
={
1,,n}
. In this case, the set of points a is asubvariety of dimension 0 of SF.
We call a façon of tending to infinity of the sequence
{ }
a kξ also a a façon of a or a façon of SF.
3. An Algorithm to Stratify the Asymptotic Sets of the
Dominant Polynominal Mappings
F
:
3→
3of Degree
2
In this section we provide an algorithm to stratify the asymptotic sets associated to dominant polynominal mappings F:3→3 of degree 2. In the last section, we show that this algorithm can be generalized in the general case for dominant polynominal mappings F:n→n of degree d where
3 n≥ and 2
d≥ . Recall that by degree of a polynomial mapping F =
(
F1,,Fn)
: n→ n , we mean the highest degree of the monomials F1,,Fn.
Let us consider now a dominant polynomial mapping F =
(
F F F1, 2, 3)
:(1 2 3) ( 1 2 3)
3 3
, , , ,
x x x → α α α
of degree 2 such that SF ≠ ∅. An important step of this
section is to define the notion of “pertinent” variables of F.
3.1. Pertinent Variables
(
)
{
x1,k,x2,k,x3,k}
be a sequence in the source space (1 2 3)3 , ,
x x x
tending to infinity such that F
( )
ξk tends to a point of SF in the target space ( 1 2 3)3 , ,
α α α
. Then the image of ξk by any coordinate polynomial Fη, where η =1, 2, 3, cannot
tend to infinity. Notice that Fη can be written as the sum of elements of the
form 1 2
F Fη η such that if Fη1
( )
ξk tends to infinity, then( )
2k
Fη ξ must tend to
0. In other words, if one element of the above sum has a factor tending to infinity with respect to the sequence
{ }
ξk , then this element must be“balanced” with another factor tending to zero with respect to the sequence
{ }
ξk . For example, assume that the coordinate sequences x1,k and x2,k ofthe sequence
{ }
ξk tend to infinity, then Fη cannot admit neither x1 nor x2 alone as an element of the above sum, but Fη can admit(
x1−νx2)
,(
x1−νx2)
x1,(
x1−νx2)
x2 as elements of this sum, where ν∈\ 0{ }
. So we define:Definition 3.1. Let
(
)
(1 2 3) (1 2 3)3 3
1, 2, 3 : x x x, , , ,
F= F F F →α α α be a polynomial
mapping of degree 2 such that SF ≠ ∅. Let us fix a façon κ of SF. Then
there exists a sequence
{ }
(1 2 3)3 , ,
k x x x
ξ ⊂ tending to infinity with the façon κ
such that its image tend to a point in SF. An element in the list
(
)
, where 1, 2, 3,
, where and , 1, 2, 3, , where and , , 1, 2, 3,
, where , , and , , 1, 2, 3,
i
j j
r r
s s
h i
h i h j
h i h j l
h i h j l
X x i
X x x i j i j
X x x x i j i j l
X x x x i j j k k i i j k
ν ν ν = = = + ≠ = = + ≠ = = + ≠ ≠ ≠ = (3.2)
{ }
(
, , , \ 0)
i j r s
h h h h
ν ν ν ν ∈ is called a pertinent variable of F with respect to the façon κ if the image of the sequence
{ }
ξk by this element does not tend toinfinity.
Remark 3.3. From now on, we will denote X1,,Xh pertinent variables of
F with respect to a fixed façon and we write
(
1, , h)
. F =F X XNotice that we can also determine the pertinent variables of F with respect to a set of façons in the case we have more than one façon.
3.2. Idea of the Algorithm
The aim of the algorithm that we present in this section is to describe the list of all possible asymptotic sets SF for the dominant polynomial mappings
3 3
:
F → of degree 2. In order to do that, we observe firstly that
• The list of all the possible façons of SF for a polynomial mapping
3 3
:
F → is
)
(
)
)
( ) ( )
( )
)
( ) ( )
( )
)
( )
[ ]
( )
[ ]
( )
[ ]
)
( )
[ ]
( )
[ ]
( )
[ ] [ ]
( )
[ ]
( )
[ ]
( )
)
( )
[ ]
( )
[ ]
( )
[ ]
1 GroupI : 1, 2, 3 ,
2 GroupII : 1, 2 , 2, 3 and 3,1 , 3 GroupIII : 1 , 2 and 3 ,
4 GroupIV : 1, 2 3 , 1, 3 2 and 2, 3 1 ,
5 GroupV : 1 2 , 1 3 , 2 1 , 2 3 , 3 1 and 3 2 , 6 GroupVI : 1 2, 3 , 2 1, 3 and 3 1, 2 .
This list has 19 façons.
• Since F dominant, then by the theorem 2.4, the set SF has pure dimen- sion
2.
With these observations, we will:
• assume that a 2-dimensional irreductible stratum S of SF admits l fixed
façons in the list (3.4), where 1≤ ≤l 19,
• determine the pertinent variables of F with respect to these l façons,
• restrict the above pertinent variables by using the dominancy of F and the
fact dimS=2. We get the form of F in terms of these pertinent variables,
• determine the geometry of S in terms of the form of F,
• let l run in the list (3.4) for 1≤ ≤l 19. We get all the possible 2-dimen- sional irreductible strata S of SF. Since the dimension of SF is 2, then we get the
list of all the possible asymptotic sets SF of F.
The following example explains the process of the algorithm, i.e. how we can determine the geometry of a 2-dimensional irreductible stratum S of SF
admitting some fixed façons.
3.3. Example
Example 3.5. Let 3 3 :
F → be a dominant polynomial mapping of degree
2. Assume that a 2-dimensional stratum S of SF admits the two façons
(
1, 2, 3)
κ = and κ′ =
( )
1, 2 3[ ]
. That means that all the sequences tending to infinity in the source space such that their images tend to the points of S admit either the façon κ =(
1, 2, 3)
or the façon κ′ =( )
1, 2 3[ ]
. In order to describe the geometry of S, we perform the following steps:Step 1: Determine the pertinent variable of F with respect to the façons
(
1, 2, 3)
κ = and κ′ =
( )
1, 2 3[ ]
:• With the façon κ=
(
1, 2, 3)
, all the three coordinate sequences of the corresponding sequence tend to infinity (cf. Definition 2.7). Up to a suiable linear change of coordinates, the mapping F admits the pertinent variables:1 2
x −x ,
(
x1−x2)
x1 ,(
x1−x2)
x2 ,(
x1−x2)
x3 , x1−x3 ,(
x1−x3)
x1 ,(
x1−x3)
x2,(
x1−x3)
x3, x2−x3,(
x2−x3)
x1,(
x2−x3)
x2,(
x2−x3)
x3,1 2 3
x −x x , x2−x x1 3 and x3−x x1 2 (see definition 3.1).
• With the façon κ′ =
( )
1, 2 3[ ]
, the first and second coordinate sequences of the corresponding sequence tend to infinity, the third coordinate sequence of the corresponding sequence tends to a fixed complex number. As we refer to the same mapping F, then up to the same suiable linear change of coor- dinates, the mapping F admits the pertinent variables: x3, x x1 3, x x2 3,1 2
x −x ,
(
x1−x2)
x1,(
x1−x2)
x2,(
x1−x2)
x3 and(
x1−x3)
x3.Since S contains both of the façons κ and κ′, then this surface S admits
1 2
x −x ,
(
x1−x2)
x1,(
x1−x2)
x2,(
x1−x2)
x3 and(
x1−x3)
x3 as pertinent variables. Let us denote by(
)
(
)
(
)
(
)
1 1 2 2 1 2 1 3 1 2 2
4 1 2 3 5 1 3 3
, , ,
, .
X x x X x x x X x x x
X x x x X x x x
= − = − = −
We can write
(
1, 2, 3, 4, 5)
.F=F X X X X X (3.6)
Step 2: Assume that
{
ξ =k(
x1,k,x2,k,x3,k)
}
and{
ξ′k =(
x1,′k,x2,′k,x3,′k)
}
are twosequences tending to infinity with the façons κ and κ′, respectively.
A) Let us consider the façon κ=
(
1, 2, 3)
and its corresponding generic sequence{
ξ =k(
x1,k,x2,k,x3,k)
}
:• Assume that X1
( )
ξ =k(
x1,k−x2,k)
tends to a non-zero complex number.Since κ =
(
1, 2, 3)
then all three coordinate sequences x1,k,x2,k and x3,ktend to infinity. Hence X2
( )
ξk =(
x1,k−x2,k)
x1,k, X3( )
ξk =(
x1,k−x2,k)
x2,kand X4
( )
ξk =(
x1,k−x2,k)
x3,k tend to infinity. In this case, X2, X3 and4
X cannot be pertinent variables of F anymore. Then F admits only two
pertinent variables X1 and X5, or F=F X X
(
1, 5)
. We can see that the dimension of S in this case is 1, that provides a contradiction with the fact that the dimension of S is 2. Consequently,(
x1,k −x2,k)
tends to 0.• Assume that
(
x1,k−x3,k)
tends to a non-zero complex number. Then( )
(
)
5 k 1,k 3,k 3,k
X ξ = x −x x tend to infinity, hence X5 cannot be a pertinent variable of F anymore, then F=F X X
(
1, 2,X3,X4)
. We choose a generic sequence{ }
ξk satisfying the conditions: X1,k =(
x1,k −x2,k)
tends to zeroand
(
x1,k−x3,k)
tends to a non-zero complex number, for example, ξk =(
k+α k k, +β k k, +γ)
. Then X2( )
ξk =(
x1,k−x2,k)
x1,k , X3( )
ξk =(
x1,k−x2,k)
x2,k and X4( )
ξk =(
x1,k−x2,k)
x3,k tend to the same complexnumber λ µ− . Combining with the fact X1,k =
(
x1,k−x2,k)
tends to zero,we conclude that the dimension of S in this case is 1, that provides a contradiction with the fact that the dimension of S is 2. Consequently,
(
x1,k−x3,k)
tends to 0.Then, with the façon κ, we have
(
x1,k−x2,k)
and(
x1,k−x3,k)
tend to 0.Hence
(
x2,k−x3,k)
also tends to 0. Let us choose a generic sequence{ }
ξksatisfying these conditions, for example, the sequence
(
)
{
ξk = k+α k k, +β k k, +γ k}
. We see that X2,k =(
x1,k−x2,k)
x1,k,(
)
3,k 1,k 2,k 2,k
X = x −x x and X4,k =
(
x1,k −x2,k)
x3,k tend to a same complexnumber λ α β= − . Moreover, X5,k =
(
x1,k−x3,k)
x3,k tends to µ α γ= − . Sowe have
( )
(
)
lim k 0, , , ,
k→∞F ξ =F λ λ λ µ
(3.7)
B) Let us consider now the façon κ′ =
( )
1, 2 3[ ]
and its corresponding generic sequence{
ξ′k =(
x1,′k,x2,′k,x3,′k)
}
, we have two cases:• If X1
( )
ξ ′k =(
x1,′k−x2,′k)
tends to 0: So X4( )
ξ ′k =(
x1,′k−x2,′k)
x3,′k tends to 0.We have X2
( )
ξ ′k =(
x1,′k−x2,′k)
x1,′k and X2( )
ξ ′k =(
x1,′k−x2,′k)
x2,′k tend to asame complex number λ′ and X5
( )
ξ ′k =(
x1,′k−x3,′k)
x′3,k tends to an arbit-rary complex number µ′. Then in this case, we have
( )
k(
0, , , 0,)
.F ξ′ =F λ λ′ ′ µ′ (3.8)
• If X1
( )
ξ ′k =(
x1,′k−x2,′k)
tends to a non-zero complex number λ′∈: So( )
2 k
pertinent variables of F anymore. Moreover, X4
( )
ξk′ tends to 0 and( )
5 k
X ξ′ tends to an arbitrary complex number µ′. Then in this case, we
have
(
)
( )
(
)
1, 4, 5 , 0, . k
F F X X X
F ξ F λ µ
=
′ = ′ ′
(3.9)
In conclusion, we have two cases: 1) From (3.6), (3.7) and (3.8), we have
(
)
( )
(
)
( )
(
)
1, 2, 3, 4, 5 lim 0, , , ,
lim 0, , , 0, . k
k
k k
F F X X X X X
F F
F F
ξ λ λ λ µ
ξ λ λ µ
→∞
→∞
= =
′ = ′ ′ ′
(*)
2) From (3.6), (3.7) and (3.9), we have
(
)
( )
(
)
( )
(
)
1, 4, 5
lim 0, ,
lim , 0, .
k k
k k
F F X X X
F F
F F
ξ λ µ
ξ λ µ
→∞
→∞
= =
′ = ′ ′
(**)
Step 3: We restrict the pertinent variables in the step 2 by using the three following facts:
• κ and κ′ are two façons of the same stratum S, • dimS=2,
• F is dominant.
Let us consider the two cases (*) and (**) determined in the step 2: 1) F is of the form (*):
• At first, we use the fact that κ and κ′ are two façons of the same stratum
S, then if Xi is a pertinent variable of F then both Xi
( )
ξk and Xi( )
ξk′must tend to either an arbitrary complex number or zero.
• Since the dimension of S is 2 then F must have at least two pertinent
variables Xi and Xj such that the images of the sequences ξk and ξk′
by Xi and Xj, respectively, tend independently to two complex numbers.
In this case:
+ F must admit either X2 =
(
x1−x2)
x1 or X3=(
x1−x2)
x2 as a pertinent variable,+ F must admit X5 =
(
x1−x3)
x3 as a pertinent variable.• Since F is dominant then F must admit at least 3 independent pertinent
variables (see lemma 2.2). Then in this case, F must also admit X1= x1−x2 as a pertinent variable. We see that X1
( )
ξk and X1( )
ξk′ tend to 0. We cansay that this variable is a “free” pertinent variable. The role of this variable is to guarantee the fact that F
( )
3 is dense in the target space 3.In conclusion, F has the following form:
(
)
( )
(
)
( )
(
)
1, 2, 3, 5
lim 0, , ,
lim 0, , , .
k k
k k
F F X X X X
F F
F F
ξ λ λ µ
ξ λ λ µ
→∞
→∞
=
=
′ = ′ ′ ′
Step 4: Describe the geometry of the 2-dimensional stratum S: On the one hand, the pertinent variables X2 (or X3) and X5 tending independently to two complex numbers have degree 2; on the other hand, the degree of F is 2, then the degree of the surface S with respect to the variables λ and µ (or
λ′ and µ′) is 1 (notice that by degree of S, we mean the degree of the
equation defining S). We conclude that S is a plane.
In light of the example 3.5, we explicit now the algorithm for classifying the asymptotic sets of the non-proper dominant polynomial mappings
(
)
3 31, 2, 3 :
F = F F F → of degree 2. 3.4. Algorithm
Algorithm 3.10. We have the five following steps: Step 1:
• Fix l façons κ1,,κl in the list (3.4), where 1≤ ≤l 19.
• Determine the pertinent variables with respect to these l façons (knowing
that they must be refered to a same mapping F). Step 2:
• Assume that S is a 2-dimensional stratum of SF admitting only the l façons
1, , l
κ κ in step 1.
• Take generic sequences 1 , , l
k k
ξ ξ corresponding to κ1,,κl, respectively.
• Compute the limit of the images of the sequences 1 , , l
k k
ξ ξ by the pertinent variables defined in step 1.
• Restrict the pertinent variables in step 1 using the fact dimS=2.
Step 3: Restrict again the pertinent variables in step 2 using the three following facts:
• the façons κ1,,κl belongs to S: then the images of the generic sequences 1, , l
k k
ξ ξ by the pertinent variables defined in the step 2 must tend to either an arbitrary complex number or zero,
• dimS=2: then there are at least two pertinent variables Xi and Xj such
that the images of the sequences ξk and ξk′ by Xi and Xj, respectively,
tend independently to two complex numbers,
• F is dominant: then there are at least 3 independent pertinent variables (see
lemma 2.2).
Step 4: Describe the geometry of the 2-dimensional irreductible stratum S of
F
S in terms of the pertinent variables obtained in the step 3.
Step 5: Letting l run from 1 to 19 in the list (3.4).
Theorem 3.11. With the algorithm 3.10, we obtain the list of all possible asymptotic sets SF of non-proper dominant polynomial mappings
3 3
:
Proof. On the one hand, the process of the algorithm 3.10 is possible, since the number of the façons in the list (3.4) is finite (19 façons). On the other hand, by the step 2, step 4 and step 5, we consider all the possible cases for all 2-dimensional irreductible strata of SF. Since the dimension of SF is 2 (see
theorem 2.4), we get all the possible asymptotic sets SF of non-proper
dominant polynomial mappings 3 3 :
F → of degree 2.
4. Results
In this section, we use the algorithm 3.10 to prove the following theorem.
Theorem 4.1. The asymptotic set of a non-proper dominant polynomial mapping F:3→3 of degree 2 is one of the five elements in the following list ( )3,2
F S
. Moreover, any element of this list can be realized as the asymptotic set of a dominant polynomial mapping F:3→3 of degree 2.
The list ( )3,2
F S
: 1) A plane. 2) A paraboloid.
3) The union of a plane
( )
P :r x1 1+r x2 2+r x3 3+ =r4 0, and a plane of the form( )
P′ :r x1 1′ +r x2′ 2+r x3 3′ + =r4′ 0, where we can choose two of the three coefficients r r r1′ ′ ′, ,2 3, then the third of them and the fourth coefficient r4′ are determined.4) The union of a plane
( )
P :r x1 1+r x2 2+r x3 3+ =r4 0 and a paraboloid of theform
( )
2{
} {
}
4
:r xi′i +r xj′ j+r xl′l+ =r′ 0, , ,i j l = 1, 2, 3 ,
H where we can choose two
of the three coefficients r r r1′ ′ ′, ,2 3 , then the third of them and the fourth coefficient r4′ are determined.
5) The union of three planes
( )
P :r x1 1+r x2 2+r x3 3+ =r4 0,( )
P′ :r x1 1′ +r x2′ 2+r x3 3′ + =r4′ 0,( )
P′′ :r x1 1′′ +r x2′′2+r x3 3′′ + =r4′′ 0, where:a) for
( )
P′ , we can choose two of the three coefficients r r r1′ ′ ′, ,2 3, then the third of them and the fourth coefficient r4′ are determined,b) for
( )
P′′ , we can choose two of the three coefficients r r r1′′ ′′ ′′, ,2 3 , then the third of them and the fourth coefficient r4′′ are determined.In order to prove this theorem, we need the two following lemmas. Lemma 4.2. Let
(
)
3 31, 2, 3 :
F = F F F → be a non-proper dominant
polynomial mapping of degree 2. If SF contains a surface of degree higher than
1, then either SF is a paraboloid, or SF is the union of a paraboloid and a
plane.
Proof. Assume that SF contains a surface
( )
H . Since degF =2 then( )
1≤deg H ≤2.
A) We prove firstly that if SF contains a surface
( )
H where deg( )
H =2then
( )
H is a paraboloid. Since deg( )
H =2 and degF =2 then SFrespect to the façon κ , there exists only one free pertinent variable. That means, one of x1, x2 and x3 is a pertinent variable of F with respect to κ (cf. Definition 3.1). Without loose of generality, we assume that x1 is a pertinent variable of F with respect to the façon κ=
( )
3 2[ ]
. Assume that(
)
{
ξk = x1,k,x2,k,x3,k}
is a generic sequence tending to infinity with the façon κand
i) x3,k tends to infinity, x2,k tends to 0 in such a way that x x2,k 3,k tends to
an arbitrary complex number λ,
ii) x1,k tends to an arbitrary complex number µ.
We see that 2 1,k
x and
(
x1,k +x2,k)
x1,k tend to µ2. Since degF=2 and( )
deg H =2, then
i) one coordinate polynomial Fη, where η∈
{
1, 2, 3}
, must contain x1 as an element of degree 1,ii) the another coordinate polynomial Fη′, where η′∈
{
1, 2, 3}
and η η′ ≠ , must contain 21
x or
(
x1+x2)
x1 as a pertinent variable.Assume that the equation of the surface
( )
H is 1 21 1 2 2
p p
rα +rα + 3
3 3 4 0.
p
rα + =r Since 2 1,k
x and
(
x1,k+x2,k)
x1,k tend to the same complexnumber µ2, and deg
( )
H =2, then there exists an unique index i∈{
1, 2, 3}
such that ri≠0 and pi=2. If rj=0 or pj =0 for all j≠i, j∈{
1, 2, 3}
, then( )
H is the union of two lines. That provides the contradiction with the fact that deg( )
H =2. So, there exists j≠i, j∈{
1, 2, 3}
such that rj≠0 and1 j
p = . Consequently, the surface
( )
H is a paraboloid.B) We prove now that if SF contains a paraboloid then the biggest possible
F
S is the union of this paraboloid and a plane. Since SF contains a paraboloid
then with the same choice of the façon κ=
( )
3 2[ ]
as in A), the mapping F must be considered as a dominant polynomial mapping of pertinent variables1, 2, 1 2
x x x x and x x2 3, that means:
(
1, 2, 1 2, 2 3)
. F=F x x x x x xWe can see easily that if x2 is a pertinent variable of F, then SF admits
only the façon κ and SF is a paraboloid. Assume that SF contains another
irreductible surface
( )
H′ which is different from( )
H . Then F must beconsidered as a polynomial mapping of pertinent variables x x x1, 1 2 and x x2 3, that means:
(
1, 1 2, 2 3)
.F=F x x x x x (4.3)
Let us consider now one façon κ′ of
( )
H ′ such that κ′ ≠κ and let(
)
{
ξk′= x1,′k,x2,′k,x3,′k}
be a corresponding generic sequence of κ′. Notice thatone coordinate of F admits x1 as a pertinent variable. Let us show that x1,′k
tends to 0. Assume that x1,′k tends to a non-zero complex number. As one
coordinate of F admits x x1 2 as a pertinent variable, then x2,′k does not tend to
infinity. We have two cases:
+ If x2,′k tends to 0, then in order to ξk′ tending to infinity, x3,′k must tend
+ If x2,′k tends to a non-zero finite complex number, since one coordinate of
F admits x x2 3 as factor, then x3,′k does not tend to infinity. That provides the
contradiction with the fact that ξk′ tends to infinity.
Therefore, x1,′k tends to 0. We have the following possible cases:
1) κ′ =
( )
2 1[ ]
: then F is a polynomial mapping of the form(
1, 3, 1 2, 1 3)
F =F x x x x x x . Combining with (4.3), then F=F x x x
(
1, 1 2)
. Therefore, F is not dominant, which provides the contradiction.2) κ′ =
( )
3 1[ ]
: then F is a polynomial mapping of the form(
1, 2, 1 2, 1 3)
F =F x x x x x x . Combining with (4.3), then F=F x x x
(
1, 1 2)
. Therefore,F is not dominant, which provides the contradiction.
3) κ′ =
( )
2, 3 1[ ]
: then F is a polynomial mapping of the form(
1, 1 2, 1 3)
F =F x x x x x . Combining with (4.3), then F=F x x x
(
1, 1 2)
. Therefore, F is not dominant, which provides the contradiction.4) κ′ =
( )
3 1, 2[ ]
: then F =F x x x x x x x x(
1, 2, 1 2, 2 3, 3 1)
. Combining with (4.3), we have F =F x x x x x(
1, 1 2, 2 3)
. Since x x1,′ ′k 2,k and x1,′k tend to 0, then( )
dim H ′ ≤1, that provides the contradiction.
5) κ′ =
( )
2 1, 3[ ]
: in this case, F is a polynomial mapping admitting the form(
1, 3, 1 2, 2 3, 3 1)
. F =F x x x x x x x xCombining with (4.3), then
(
1, 1 2, 2 3)
. F=F x x x x xWe know that x1,′k tends to 0. Assume that x x1,′ ′k 2,k tends to a complex
number λ and x x2,′ ′k 3,k tends to a complex number µ, we have
( )
H′ ={
(
F1(
0, ,λ µ) (
,F2 0, ,λ µ) (
,F3 0, ,λ µ)
)
: ,λ µ∈}
,where F=
(
F F F 1, 2, 3)
. Since degF=2, then the degree of Fi with respect tothe variables λ and µ must be 1, for all i∈
{
1, 2, 3}
. Consequently, thesurface
( )
H′ is a plane.Lemma 4.4. Let 3 3 :
F → be a non-proper dominant polynomial
mapping of degree 2. Assume that S is a 2-dimensional irreductible stratum of
F
S . Then S admits at most two façons. Moreover, if S admits two façons, then F
S is a plane.
Proof. Let 3 3 :
F → be a non-proper dominant polynomial mapping of
degree 2. Assume that S is a 2-dimensional irreductible stratum of SF.
A) We provide firstly the list of pairs of façons that S can admit and we write F in terms of pertinent variables in each of these cases. Let us fix a pair of façons
(
κ κ, ′)
in the list (3.4) and assume that S admits these two façons. We use thesteps 1, 2, 3 and 4 of the algorithm 3.10. In the same way than the example 3.5, we can determine the form of F in terms of its pertinent variables with respect to two fixed façons after using the conditions of dimension of S and the dominancy of F. Letting two façons κ κ′, run in the list (3.4), we get the following
possiblilities:
1)
(
κ κ′ =,) (
(
1, 2, 3 ,) (
i i1,2)
[ ]
j)
, where{
i i1, ,2 j} {
= 1, 2, 3}
and(
) (
) (
) (
)
(
i1 i2, i1 i2 i1, i1 i2 i2, i1 i2 j, i1 j j)
.2)
(
κ κ′ =,) (
(
1, 2, 3 ,) ( )
i[
j1,j2]
)
, where{
i j j, 1, 2} {
= 1, 2, 3}
and(
) (
) (
) (
) (
) (
)
(
i j1 j1, i j1 j2, i j2 j1, i j2 j2, j1 j2 , j1 j2 i)
.F =F x −x x x −x x x −x x x −x x x −x x −x x
3)
(
κ κ′ =,) ( )
(
1, 2 3 ,[ ]
( )
i[ ]
3,j)
, where{ } { }
i j, = 1, 2 , and(
)
(
3, j 3, i 3, i j j)
.F =F x x x x x x −x x
4)
(
κ κ′ =,) ( )
(
1, 2 3 , 3 1, 2[ ]
( )
[ ]
)
and(
)
(
)
(
1 3, 2 3, 1 2,1 1 3 2 2 3 3 1 2 1 4 1 2 2)
, F=F x x x x x −x r x x +r x x +r x −x x +r x −x xwhere rl∈, for l=1,, 4, such that
(
r1≠0,r2≠0,(
r r3, 4) ( )
≠ 0, 0)
, or(
) ( ) (
) ( )
(
r r1, 2 ≠ 0, 0 , r r3, 4 ≠ 0, 0)
.5)
(
κ κ′ =,) ( )
(
1, 3 2 ,[ ]
( )
i[ ]
2,j)
, where{ } { }
i j, = 1, 3 , and(
)
(
2, 2 j, i 2, i j j)
.F =F x x x x x x −x x
6)
(
κ κ′ =,) ( )
(
1, 3 2 , 2 1, 3[ ]
( )
[ ]
)
and(
)
(
)
(
1 2, 2 3, 1 3,1 1 2 2 2 3 3 1 3 1 4 1 3 3)
, F =F x x x x x −x r x x +r x x +r x −x x +r x −x xwhere rl∈, for l=1,, 4, such that
(
r1≠0,r2≠0)
, or(
r r1, 2) ( )
≠ 0, 0 and(
r r3, 4) ( )
≠ 0, 0 .7)
(
κ κ′ =,) ( )
(
2, 3 1 ,[ ]
( )
i[ ]
1,j)
, where{ } { }
i j, = 2, 3 , and(
)
(
1, 1 i, 1 j, i j j)
.F =F x x x x x x −x x
8)
(
κ κ′ =,) ( )
(
2, 3 1 , 1 2, 3[ ]
( )
[ ]
)
and(
)
(
)
(
1 3, 1 2, 3 2,1 1 3 2 1 2 3 3 2 3 4 3 2 2)
, F=F x x x x x −x r x x +r x x +r x −x x +r x −x xwhere rl∈, for l=1,, 4, such that
(
r1≠0,r2≠0,(
r r3, 4) ( )
≠ 0, 0)
or(
) ( ) (
) ( )
(
r r1, 2 ≠ 0, 0 , r r3, 4 ≠ 0, 0)
.9)
(
κ κ, ′ =) ( )
(
1 2, 3 ,[ ]
( )
i[ ]
1,j)
, where{ } { }
i j, = 2, 3 , and(
j, 1 i,1 i j 2 1 j)
,F=F x x x r x x +r x x
where r1 et r2 are the non-zero complex numbers.
B) We prove now that S admits at most two façons. We prove the result for the first case of the above possibilities:
(
κ κ′ =,) (
(
1, 2, 3 ,) (
i i1,2)
[ ]
j)
, where{
i i1, ,2 j} {
= 1, 2, 3}
. The other cases are proved similarly. For example, assumethat S admits two façons κ =
(
1, 2, 3)
and κ′ =( )
1, 2 3[ ]
. We prove that S cannot admit the third façon κ′′ different from κ and κ′.Let κ′′ be a façon of SF. Let us denote by
{
ξk′′=(
x1,′′k,x2,′′k,x3,′′k)
}
a genericsequence corresponding to κ′′. By the example 3.5, the mapping F admits X1,
2
X (or X3), and X5 as the pertinent variables, where
(
)
(
)
(
)
1 1 2, 2 1 2 1, 3 1 2 2, 5 1 3 3.
X = −x x X = x −x x X = x −x x X = x −x x
Without loose the generality, we can assume that X2 is a pertinent variable of F. We prove that X1
( )
ξk′′ =(
x1,′′k −x′′2,k)
tends to 0. Assume that X1( )
ξk′′ =(
x1,′′k −x2,′′k)
tends to a non-zero complex number. Then:+ If x1,′′k tends to infinity, then X2
( )
ξk′′ tends to infinity, that provides a+ If x2,′′k tends to infinity, then x1,′′k also tends to infinity since
(
x1,′′k−x2,′′k)
tends to a non-zero complex number. That implies X2
( )
ξk′′ tends to infinityand this provides a contradiction with the fact that X2 is a pertinent variable of F.
Hence, x1,′′k and x2,′′k cannot tend to infinity. Consequently, x3,′′k must tend
to infinity. Therefore, X5
( )
ξ ′′k =(
x1,′′k−x3,′′k)
x3,′′k tends to infinity, that providesthe contradiction with the fact that X5 is a pertinent variable of F. We conclude that
(
x1,′′k −x2,′′k)
tends to 0.Then we have two possibilities:
a) either both of x1,′′k and x2,′′k tend to 0: then X1
( )
ξ ′′k =(
x1,′′k −x2,′′k)
,( )
(
)
2 k 1,k 2,k 1,k
X ξ′′ = x′′ −x′′ x′′ and X3
( )
ξk′′ =(
x1,′′k−x′′2,k)
x′′2,k tend to 0, which pro-vides the contradiction with the fact that the dimension of S is 2,
b) or both of x1,′′k and x2,′′k tend to infinity: Since X5 is a pertinent variable of F, then x3,′′k tends to 0 or infinity. We conclude that the façon κ′′ is
(
1, 2, 3)
or( )
1, 2 3[ ]
.In conclusion, S admits only the two façons κ =
(
1, 2, 3)
and κ′ =( )
1, 2 3[ ]
. c) We prove now that if there exists a 2-dimensional irreductible stratum S ofF
S admitting two façons, then SF is a plane. Similarly to B), we prove this
fact for the first case of the possibilities in A), that means, the case of
(
κ κ′ =,) (
(
1, 2, 3 ,) (
i i1,2)
[ ]
j)
, where{
i i1, ,2 j} {
= 1, 2, 3}
. The other cases are proved similarly. For example, assume that S admits two façons κ =(
1, 2, 3)
and κ′ =
( )
1, 2 3[ ]
. With the same arguments than in the example 3.5, the stratum S is a plane. By B), the asymptotic set SF admits also only two façons(
1, 2, 3)
κ = and κ′ =
( )
1, 2 3[ ]
. In other words, SF and S concide. We con-clude that SF is a plane.
We prove now the theorem 4.1.
Proof. (The proof of theorem 4.1). The cases 1) and 2) are easily achievable by the lemmas 4.4 and 4.2, respectively. Let us prove the cases 3), 4) and 5). In these cases, on the one hand, since SF contains at least two irreductible surfaces,
then SF admits at least two façons; on the other hand, by the lemma 4.4, each
irreductible surface of SF admits only one façon. Assume that κ , κ′ are two
different façons of SF and
{ }
ξk ,{ }
ξk′ are two corresponding genericsequences, respectively. We use the algorithm 3.10 and in the same way than the proofs of the lemmas 4.2 and 4.4, we can see easily that the pairs of façons
(
κ κ, ′)
must belong to only the following pairs of groups: (I, IV), (I, V), (I, VI),(II, VI), (IV, V), (IV, VI), (V, VI) and (VI, VI) in the list (3.4).
i) If κ belongs to the group I and κ′ belongs to the group IV, for example
(
1, 2, 3)
κ = and κ′ =
( )
1, 2 3[ ]
. From the example 3.5, F is a dominant poly- nomial mapping which can be written in terms of pertinent variables:(
) (
) (
) (
)
(
)
( )
(
)
( )
(
)
1 2, 1 2 1, 1 2 2, 1 2 3, 1 3 3
lim 0, , , , ,
lim 0, , , 0, ,
k k
k k
F F x x x x x x x x x x x x x x
F F
F F
ξ λ λ λ µ
ξ λ λ µ
→∞
→∞
= − − − − −
=
′ = ′ ′ ′
{ }
ξk , the pertinent variables tending to an arbitrary complex numbers have thedegree 2, then the façon κ provides a plane, since the degree of F is 2. In the
same way, the façon κ′ provides a plane. Furthermore, it is easy to check that
these two planes must have the form of the case 3) of the theorem and SF is
the union of these two planes.
ii) If κ belongs to the group I and κ′ belongs to the group V, for example
(
1, 2, 3)
κ = and κ′ =
( )
1 2[ ]
. Then, on the one hand, F is a dominant poly- nomial mapping which can be written in terms of pertinent variables:(
) (
) (
)
(
2 3, 2 3 2, 2 3 3, 1 2 2)
. F=F x −x x −x x x −x x x −x xOn the other hand, with the same arguments than the example 3.5, and for suitable generic sequences
{ }
ξk and{ }
ξk′ , we obtain:( )
(
)
( )
(
2)
lim 0, , , ,
lim , 0, , ,
k k
k k
F F
F F
ξ λ λ µ
ξ λ λ µ
→∞
→∞
=
′ = ′ ′ ′
where λ µ λ µ, , ′ ′∈, . With the same arguments than in the case i), we have: a) either the façons κ and κ′ provide two planes of the form of the case 3)
of our theorem,
b) or the façon κ provides the plane
( )
P and, by the lemma 4.2, the façonκ′ provides the paraboloid
( )
H of the form of the case 4) of our theorem. By an easy calculation, we see that if SF admits another façon κ′′ which isdifferent from the façons κ and κ′, then this façon provides a 1-dimensional
stratum contained in
( )
P or contained in( )
H .iii) Proceeding in the same way for the cases where
(
κ κ, ′)
is a pair of façons belonging to the pairs of groups: (I, VI), (II, VI), (IV, V), (IV, VI) and (V, VI), we obtain the case 3) or the case 4) of the theorem.iv) Consider now the case where κ and κ′ belong to the group VI, for
example, κ =
( )
1 2, 3[ ]
and κ′ =( )
2 1, 3[ ]
, then F is a dominant polynomial mapping which can be written in terms of pertinent variables:(
3, 1 2, 2 3, 3 1)
. F=F x x x x x x xWith the same arguments than the example 3.5, and for suitable generic sequences
{ }
ξk and{ }
ξk′ , we obtain:( )
(
)
( )
(
)
lim 0, , 0, , lim 0, , , 0 ,
k k
k k
F F
F F
ξ λ µ
ξ λ µ
→∞
→∞
=
′ = ′ ′
where λ µ λ µ, , ′ ′∈, . In this case, we have two possibilities:
a) either F admits x3 as a pertinent variable: This case is similar to the case i) and we have the case 3) of the theorem,
b) or F does not admit x3 as a pertinent variable, that means
(
1 2, 2 3, 3 1)
.F =F x x x x x x (4.4)
In this case, SF admits one more façon κ′′ =
( )
3 1, 2[ ]
such that with a corre-( )
(
)
( )
(
)
( )
(
)
lim , 0, ,
lim , , 0 ,
lim 0, , ,
k k
k k
k k
F F
F F
F F
ξ λ µ
ξ λ µ
ξ λ µ
→∞
→∞
→∞
=
′ = ′ ′
′′ = ′′ ′′
where λ µ′′ ′′∈, . In this case, SF is the union of three planes the forms of
which are as in the case 5) of the theorem.
5. The General Case
The algorithm 3.10 can be generalized to clasify the asymptotic sets of non- proper dominant polynomial mappings F:n→n of degree d where
3 n≥
and d≥2 as the following.
Algorithm 5.1. We have the six following steps: Step 1: Determine the list (n d, )
F
of all the possible façons of SF.
Step 2: Fix l façons κ1,,κl in the list
( )n d, F
obtained in step 1. Determine the pertinent variables with respect to these l façons (in the similar way than the definition 3.1).
Step 3:
• Assume that S is a
(
n−1)
-dimensional stratum of SF admiting only the lfaçons κ1,,κl determined in step 1.
• Take generic sequences 1, , l
k k
ξ ξ corresponding to κ1,,κl, respectively.
• Compute the limit of the images of the sequences 1 , , l
k k
ξ ξ by pertinent variables defined in step 1.
• Restrict the pertinent variables defined in step 2 using the fact dimS= −n 1.
Step 4: Restrict again the pertinent variables in step 3 using the three following facts:
• all the façons κ1,,κl belong to S: then the images of the generic sequences 1
, , l
k k
ξ ξ by the pertinent variables defined in the step 2 must tend to either an arbitrary complex number or zero,
• dimS= −n 1: then there are at least n−1 pertinent variables
1, , n1
i i
X X −
such that the images of the sequences
{ } { }
1 , , lk k
ξ ξ by Xi1,,Xin−1, re-
spectively, tend independently to
(
n−1)
complex numbers,• F is dominant: then there are at least n independent pertinent variables (see
lemma 2.2).
Step 5: Describe the geometry of the
(
n−1)
-dimensional irreductible stratum S in terms of the pertinent variables obtained in the step 4.Step 6: Let l run in the list obtained in the step 1.
Theorem 5.2. With the algorithm 5.1, we obtain all possible asymptotic sets of non-proper dominant polynomial mapping F:n→n of degree d.
Proof. In the one hand, by theorem 2.4, the dimension of SF is n−1. By
the step 3, step 5 and step 6, we consider all the possible cases of the all
(
n−1)
- dimensional irreductible strata of SF. Since the dimension of SF is n−1(see theorem 2.4), we get all the possible asymptotic sets SF of non-proper