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On Binary Diophantine Equation

3

x

2

5

y

2

12

S. Mallika

1

, V. Surya

2 1

Assistant Professor, 2M. Phil Scholar, Department of Mathematics, SIGC, Trichy-620002, Tamilnadu, India.

Abstract: Non-homogeneous binary quadratic equation representing hyperbola given by

3

x

2

5

y

2

12

is analyzed for its non-zero distinct integer solutions. A few interesting relations among its solutions are presented. Also, knowing an integral solution of the given hyperbola, integer solutions for other choices of hyperbola and parabola are presented.

Keywords: Binary quadratic, Hyperbola, Parabola, Integral solutions, Pell equation. AMS Mathematics subject Classification (2010):11D0

I. INTRODUCTION

The binary quadratic Diophantine equations of the form

ax

2

by

2

N

,

(

a

,

b

,

c

0

)

are rich in variety and have been analyzed by many mathematicians for their respective integer solutions for particular values of

a

,

b

and

N

.

In this context, one may refer [1-18].

This communication concerns with the problem of obtaining non-zero distinct integer solutions to the binary quadratic equation

given by,

3

x

2

5

y

2

12

representing hyperbola. A few interesting relations among its solutions are presented. Knowing an integral solution of the given hyperbola, integer solutions for other choices of hyperbolas and parabolas are presented.

II. METHOD OF ANALYSIS

The Diophantine equation representing the binary quadratic equation to be solved for its non-zero distinct integral solution is

3

x

2

5

y

2

12

(1) Introduce the linear transformation

x

X

5

T

,

y

X

3

T

(2) From (1) & (2) we have,

X

2

15

T

2

6

(3) whose smallest positive integer solution is

1

,

3

0

0

T

X

To obtain the other solutions of (3), consider the Pell equation

X

2

15

T

2

1

(4) whose smallest positive integer solution is

1

~

,

4

~

0 0

T

X

whose general solution is given by

n n

n

n

g

X

f

T

2

1

~

,

15

2

1

~

where

1

1

15

4

15

4

n n

n

f

1

1

15

4

15

4

n n

n

g

Applying Brahmagupta lemma between

x

0

,

y

0

and

x

n

y

n

~

,

~

, the other integer solutions of (1) are given by

n n

n

f

g

x

4

15

15

15

1

n n

n

f

g

y

3

15

12

(2)

The recurrence relations satisfied by x and y are given by

0

8

2 1

3

n n

n

x

x

x

0

8

2 1

3

n n

n

y

y

y

Some numerical examples of x and y satisfying (1) are given in the Table: 1 below:

Table: 1 Numerical examples

n

1

n

x

y

n1

-1 8 6

0 62 48

1 488 378

2 3842 2976

3 30248 23430

4 288142 184464

From the above table, we observe some interesting relations among the solutions which are presented below:

A.

x

n1 &

y

n1values are always even .

B. Relations among the solutions

1)

x

n3

8

x

n2

x

n1

0

2)

5

y

n1

x

n2

4

x

n1

0

3)

15

y

n3

93

x

n2

12

x

n1

0

4)

40

y

n3

x

n1

3

x

n3

0

5)

9

x

n2

36

x

n1

45

y

n1

0

6)

x

n3

31

x

n1

40

y

n1

0

7)

y

n3

24

x

n1

31

y

n1

0

8)

x

n3

x

n1

10

y

n2

0

9)

4

y

n1

3

x

n1

y

n2

0

10)

3

x

n1

24

x

n2

3

x

n3

0

11)

5

y

n1

31

x

n2

4

x

n3

0

12)

5

y

n2

4

x

n2

x

n3

0

13)

y

n3

6

x

n2

y

n1

0

14)

x

n1

4

x

n2

5

y

n2

0

15)

y

n1

3

x

n2

4

y

n2

0

16)

4

x

n1

31

x

n2

5

y

n3

0

17)

4

y

n2

3

x

n2

y

n3

0

18)

4

y

n1

3

x

n3

31

y

n2

0

19)

x

n1

31

x

n3

40

y

n3

0

(3)

21)

y

n2

3

x

n3

4

y

n3

0

22)

24

x

n3

y

n1

31

y

n3

0

23)

8

y

n2

y

n1

y

n3

0

24)

3

x

n1

31

y

n2

4

y

n3

0

C. Each of the following expressions represents a nasty number

1)

48

x

2n2

6

x

2n3

12

2)

378

6

96

8

1

4 2 2

2n

x

n

x

3)

24

x

2n2

30

y

2n2

12

4)

558

90

144

12

1

3 2 2

2n

y

n

x

5)

1464

30

372

31

1

4 2 2

2n

y

n

x

6)

1134

144

36

3

1

4 2 3

2n

x

n

x

7)

6

x

2n3

60

y

2n2

12

8)

186

x

2n3

240

y

2n3

12

9)

366

x

2n3

60

y

2n4

12

10)

24

1890

372

31

1

2 2 4

2n

y

n

x

11)

186

1890

48

4

1

3 2 4

2n

y

n

x

12)

1464

x

2n4

1890

y

2n4

12

13)

24

186

36

3

1

2 2 3

2n

y

n

y

14)

6

366

72

6

1

2 2 4

2n

y

n

y

15)

186

1464

36

3

1

3 2 4

2n

y

n

y

D. Each of the following expressions represents a cubical integer

1)

8

x

3n3

x

3n4

24

x

n1

3

x

n2

2)

63

3 3 3 5

189

1

3

3

8

1

 

n

n

n

n

x

x

x

x

3)

4

x

3n3

5

y

3n3

12

x

n1

15

y

n1

4)

31

3 3

5

3 4

93

1

15

2

4

1

 

n

n

n

n

y

x

y

(4)

5)

244

3 3

5

3 5

732

1

15

3

31

1

  

n

n

n

n

y

x

y

x

6)

63

x

3n4

8

x

3n5

189

x

n2

24

x

n3

7)

x

3n4

10

y

3n3

3

x

n2

30

y

n1

8)

31

x

3n4

40

y

3n4

93

x

n2

120

y

n2

9)

61

x

3n4

10

y

3n5

183

x

n2

30

y

n3

10)

4

3 5

315

3 3

12

3

945

1

31

1

 

n

n

n

n

y

x

y

x

11)

31

3 5

315

3 4

93

3

945

2

4

1

 

n

n

n

n

y

x

y

x

12)

244

x

3n5

315

y

3n5

732

x

n3

945

y

n3

13)

4

3 4

31

3 3

12

2

93

1

3

1

 

n

n

n

n

y

y

y

y

14)

3 5

61

3 3

3

3

183

1

6

1

 

n

n

n

n

y

y

y

y

15)

31

3 5

244

3 4

93

3

732

2

3

1

 

n

n

n

n

y

y

y

y

E. Each of the following expressions represents a bi-quadratic integer

1)

8

x

4n4

x

4n5

32

x

2n2

4

x

2n3

6

2)

63

252

4

48

8

1

4 2 2 2 6 4 4

4n

x

n

x

n

x

n

x

3)

4

x

4n4

5

y

4n4

16

x

2n2

20

y

2n2

6

4)

31

5

124

20

24

4

1

3 2 2 2 5 4 4

4n

y

n

x

n

y

n

x

5)

244

5

976

20

186

31

1

4 2 2 2 6 4 4

4n

y

n

x

n

y

n

x

6)

63

x

4n5

8

x

4n6

252

x

2n3

32

x

2n4

6

7)

x

4n5

10

y

4n4

4

x

2n3

40

y

2n2

6

8)

31

x

4n5

40

y

4n5

124

x

2n3

160

y

2n3

6

9)

61

x

4n5

10

y

4n6

244

x

2n3

40

y

2n4

16

10)

4

315

16

1260

186

31

1

2 2 4 2 4 4 6

4n

y

n

x

n

y

n

x

11)

31

315

124

1260

24

4

1

3 2 4 2 5 4 6

4n

y

n

x

n

y

n

x

12)

244

x

4n6

315

y

4n6

976

x

2n4

1260

y

2n4

6

13)

4

31

16

124

18

3

1

2 2 3 2 4 4 5

4n

y

n

y

n

y

n

(5)

14)

61

4

244

36

6

1

2 2 4

2 4 4 6

4n

y

n

y

n

y

n

y

15)

31

244

124

976

18

3

1

3 2 4

2 5

4 6

4n

y

n

y

n

y

n

y

F. Each of the following expressions represents a quintic integer

1)

8

x

5n5

x

5n6

40

x

3n3

5

x

3n4

80

x

n1

10

x

n2

2)

63

5 5 5 7

315

3 3

5

3 5

630

1

10

3

8

1

 

 

n

n

n

n

n

n

x

x

x

x

x

x

3)

4

x

5n5

5

y

5n5

20

x

3n3

25

y

3n3

40

x

n1

50

y

n1

4)

31

5 5

5

5 6

155

3 3

25

3 4

310

1

50

2

4

1

 

 

n

n

n

n

n

n

y

x

y

x

y

x

5)

244

5 5

5

5 7

1220

3 3

25

3 5

2440

1

50

3

31

1

 

 

n

n

n

n

n

n

y

x

y

x

y

x

6)

63

x

5n6

8

x

5n7

315

x

3n4

40

x

3n5

630

x

n2

80

x

n3

7)

x

5n6

10

y

5n5

5

x

3n4

50

y

3n3

10

x

n2

100

y

n1

8)

31

x

5n6

40

y

5n6

155

x

3n4

200

y

3n4

310

x

n2

400

y

n2

9)

61

x

5n6

10

y

5n7

305

x

3n4

50

y

3n5

610

x

n2

100

y

n3

10)

4

5 7

315

5 5

20

3 5

1575

3 3

40

3

3150

1

31

1

 

 

n

n

n

n

n

n

y

x

y

x

y

x

11)

31

5 7

315

5 6

155

3 5

1575

3 4

310

3

3150

2

4

1

 

 

n

n

n

n

n

n

y

x

y

x

y

x

12)

244

x

5n7

315

y

5n7

1220

x

3n5

1575

y

3n5

2440

x

n3

3150

y

n3

13)

4

5 6

31

5 5

20

3 4

155

3 3

40

2

310

1

3

1

 

 

n

n

n

n

n

n

y

y

y

y

y

y

14)

5 7

61

5 5

5

3 5

305

3 3

10

3

610

1

6

1

 

 

n

n

n

n

n

n

y

y

y

y

y

y

15)

31

5 7

244

5 6

155

3 5

1220

3 4

310

3

2440

2

31

1

 

 

n

n

n

n

n

n

y

y

y

y

y

(6)

III. REMARKABLE OBSERVATIONS

A. Employing linear combinations among the solutions of (1), one may generate integer solutions for other choices of hyperbola which are presented in the Table: 2 below:

Table: 2 Hyperbolas

S. No Hyperbola

X

,

Y

1

15

2 2

60

Y

X

8

x

n1

x

n2

,

31

x

n1

4

x

n2

2

15

2

16

2

3840

Y

X

63

x

n1

x

n3

,

61

x

n1

x

n3

3

3

2

5

2

12

Y

X

4

x

n1

5

y

n1

,

3

x

n1

4

y

n1

4 2

240

2

576

Y

X

93

x

n1

15

y

n2

,

6

x

n1

y

n2

5

3

2

5

2

11532

Y

X

244

x

n1

5

y

n3

,

189

x

n1

4

y

n3

6

5

2

3

2

180

Y

X

189

x

n2

24

x

n3

,

244

x

n2

31

x

n3

7

48

2

5

2

192

Y

X

x

n2

10

y

n1

,

3

x

n2

31

y

n1

8

3

2

5

2

12

Y

X

31

x

n2

40

y

n2

,

24

x

n2

31

y

n2

9

48

2

5

2

192

Y

X

61

x

n2

10

y

n3

,

189

x

n2

31

y

n3

10

3

2

5

2

11532

Y

X

4

x

n3

315

y

n1

,

3

x

n3

244

y

n1

11

3

2

5

2

192

Y

X

31

x

n3

315

y

n2

,

24

x

n3

244

y

n2

12

3

2

5

2

12

Y

X

244

x

n3

315

y

n3

,

189

x

n3

244

y

n3

13 2

15

2

36

Y

X

4

y

n2

31

y

n1

,

8

y

n1

y

n2

14

16

2

15

2

2304

Y

X

y

n3

61

y

n1

,

63

y

n1

y

n3

15 2

15

2

36

Y

(7)

B. Employing linear combinations among the solutions of (1), one may generate integer solutions for other choices of parabola which are presented in the Table: 3 below:

Table: 3 Parabolas

S. No Parabola

X

,

Y

1

15

2

30

Y

X

8

x

2n2

x

2n3

,

31

x

n1

4

x

n2

2

15

2

2

240

Y

X

63

x

2n2

x

2n4

,

61

x

n1

x

n3

3

3

5

2

6

Y

X

4

x

2n2

5

y

2n2

,

3

x

n1

4

y

n1

4

20

2

24

Y

X

93

x

2n2

15

y

2n3

,

6

x

n1

y

n2

5

93

5

2

5766

Y

X

244

x

2n2

5

y

2n4

,

189

x

n1

4

y

n3

6

5

2

30

Y

X

189

x

2n3

24

x

2n4

,

244

x

n2

31

x

n3

7

48

5

2

96

Y

X

x

2n3

10

y

2n2

,

3

x

n2

31

y

n1

8

3

5

2

6

Y

X

31

x

2n3

40

y

2n3

,

24

x

n2

31

y

n2

9

48

5

2

96

Y

X

61

x

2n3

10

y

2n4

,

189

x

n2

31

y

n3

10

93

5

2

5766

Y

X

4

x

2n4

315

y

2n2

,

3

x

n3

244

y

n1

11

12

5

2

96

Y

X

31

x

2n4

315

y

2n3

,

24

x

n3

244

y

n2

12

3

5

2

6

Y

X

244

x

2n4

315

y

2n4

,

189

x

n3

244

y

n3

13

5

2

6

Y

X

4

y

2n3

31

y

2n2

,

8

y

n1

y

n2

14

32

5

2

384

Y

X

y

2n4

61

y

2n2

,

63

y

n1

y

n3

15

5

2

6

Y

X

31

y

2n4

244

y

2n3

,

63

y

n2

8

y

n3

IV. CONCLUSION

In this paper, we have presented infinitely many integer solutions for the Diophantine equation, represented by hyperbola is given

(8)

REFERENCES

[1] R.D. Carmichael, Theory of Numbers and Diophantine Analysis, Dover Publications, New York, 1950. [2] L.E. Dickson, History of theory of numbers, Vol.II, Chelsea Publishing co., New York, 1952. [3] L.J. Mordell, Diophantine Equations, Academic Press, London, 1969.

[4] M.A. Gopalan and R. Anbuselvi, Integral solutions of

4

ay

2

(

a

1

)

x

2

3

a

1

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[5] M.A. Gopalan, etal, Integral points on the hyperbola

(

a

2

)

x

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ay

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4

a

(

k

1

)

2

k

2

,

a

,

k

0

,

Indian Journal of Science, 1(2),2012,125-126.

[6] M.A. Gopalan, S. Devibala and R. Vidhyalakshmi, Integral points on the hyperbola

2

X

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3

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5

,

American Journal of Applied Mathematics and Mathematical Sciences, 1(2012) 1-4.

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ax

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(

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y

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3

a

1

,

Discovery,4(10), 2013,22-24.

[8] K. Meena, M.A. Gopalan and S. Nandhini, On the binary quadratic Diophantine equation

y

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68

x

2

13

,

International Journal of Advanced Education and Research, 2,2017,59-63.

[9] K. Meena, S. Vidhyalakshmi and R. Sobana Devi, On the binary quadratic equation

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7

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32

,

International Journal of Advanced Science and Research, 2,2017,18-22.

[10] K. Meena, M.A. Gopalan, S. Hemalatha, On the hyperbola

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16

,

National Journal of Multidisciplinary Research and Development, 2,2017,1-5.

[11] M.A. Gopalan, K.K. Viswanathan and G. Ramya, On the positive Pell equation

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International Journal of Advanced Education and Research, 2, 2017,4-8.

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102

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33

,

International Journal of Advanced Education and Research, 2(1),2017,91-96.

[13] K. Meena, S. Vidhyalakshmi and N. Bhuvaneswari, On the binary quadratic Diophantine equation

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10

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24

,

International Journal of Multidisciplinary Education and Research, 2,2017,34-39.

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(

a

2

)

x

2

ay

2

4

a

(

k

1

)

2

k

2

,

a

,

k

0

,

Indian Journal of Science, 1(2) ,2012,125-126. [15] M.A. Gopalan and V.Geetha, Observations on some special Pellian equations, Cayley J. Math, 2(2), 2013,109-118.

[16] M.A. Gopalan, S. Vidhyalakshmi and A. Kavitha, On the integer solutions of binary quadratic equation,

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k

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1

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4

t

,

k

,

t

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BOMSR, 2,2014, 42-46.

[17] K. Ambika, T.R. Usha rani, Observations on the Non-Homogeneous Binary Quadratic Diophantine Equation

5

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6

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5

,

Journal of Mathematics and Informatics, Vol-10,2017, 1-9.

References

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