The 3
rd
Harmonic Problem
and how Delta configurations help
reduce its affects.
Harmonics are multiples of the fundamental
frequency of a wave. They cause waveform
distortions like the one seen below.
What causes harmonics?
•
Non-linear components
•
Diodes
•
Transistors
•
Electric motors
•
SMPSs (switch-mode power supply)
Harmonics can be modeled in a system separately as a source with a frequency an integer multiple of the fundamental frequency (60 Hz in our case). So a model
including harmonics can be seen as a source sending a 60 Hz sine wave to a load (and since the load generates the harmonics) and a source bank at the load with each source sending an integer multiple of 60 Hz sine wave.
So we see how the harmonics can be modeled as sources in the system.
Now we can examine why using a wye delta transformer can help us with
the 3rd harmonic problem.
In a balanced 3-phase wye system, the currents going into the neutral node are
supposed to cancel, so that there is no current on the neutral wire. Harmonic waves may not behave this way, so we should investigate…
Harmonics can be modeled as current sources as we have seen, but equivalently, they can be modeled as voltage sources. Lets look at the 2nd Harmonic…
The system will still be balanced in the presence of the 2nd harmonic (except negative
sequence) and the current from the 2nd harmonic sources will still cancel in the neutral
wire! It can be shown that this is true with ANY even harmonic. Now lets examine the 3rd harmonic… ) 120 2 cos( ) 240 2 cos( ) 120 ( 2 cos 2 ) 120 2 cos( ) 240 2 cos( ) 120 ( 2 cos 2 ) 2 cos( ) 0 2 cos( ) 0 ( 2 cos 2 ° − = ° + = ° + = ° + = ° − = ° − = = ° + = ° + = wt E wt E wt E Vcn wt E wt E wt E Vbn wt E wt E wt E Van ) 3 cos( ) 360 3 cos( ) 120 ( 3 cos 3 ) 3 cos( ) 360 3 cos( ) 120 ( 3 cos 3 ) 3 cos( ) 0 3 cos( ) 0 ( 3 cos 3 wt E wt E wt E Vcn wt E wt E wt E Vbn wt E wt E wt E Van = ° + = ° + = = ° − = ° − = = ° + = ° + =
There is something interesting that is immediately visible about the third harmonic voltage equations we just found. All the waves are in phase with each other. This is well
illustrated in the following figure.
In a similar derivation as the previous slide, with current instead of voltage we can get in the neutral wire:
In the 2nd harmonic, the current still cancels in the neutral wire, but the 3rd harmonic
current adds, producing a very large neutral current.
) 3 cos( 3 3 3 3 Ibn Icn I wt Ian In= + + = ⇒
Figure 2: phase waves and their 3rdHarmonic 3rdharmonic wave 3 3 3 Ibn Icn Ian = = ) 3 cos( 3 3 3 Ibn Icn I wt Ian In= + + = ⇒ * VI S =
So we need to get rid of the neutral wire. By using a delta configuration, we can trap the current in the delta loop and also take advantage of one useful property. We all know that when going from line-to neutral voltage, to line-to-line voltage:
And since
we can easily see that the power across the load in a delta loop due to the third harmonic is zero. Vbn Van Vab= − 3 3 3 Vbn Vcn Van = = * VI S = 0 )* )]( 3 cos( ) 3 cos( [ )* )( 3 3 ( )* 3 )( 3 (
3= Vab Iab = Van −Vbn Iab = E wt − E wt Iab =