Galgotias College of Engineering and
Technology
Department of Mechanical Engineering
Project report on
To design, fabrication & testing of gear pump test rig
By
1.SUNIL KUMAR YADAV (0809740092)
2.SHRI BALLABH GOSWAMI (0809740087)
3.VIVEK CHANDRA PANDEY ( 0809740099)
4.SAURABH SINGH ( 0809740082 )
in partial fulfillment of
Degree Requirements as per UPTU Syllabus for the award of
Batch of 2008-12
Galgotias College of Engineering and
Technology
Department of Mechanical Engineering
CERTIFICATE
This is to certify that the project entitled “To design,
fabrication & testing of gear pump test rig” submitted by
Sunil Kumar Yadav (0809740092), Shri Ballabh Goswami (0809740087), Vivek Chandra Pandey (0809740099),
Saurabh Singh ( 0809740082 ) to the
Department of Mechanical Engineering,
Galgotias College of Engineering and Technology, Gr. Noida, in partial fulfillment of Degree Requirements as per GBTU Syllabus for the award of Bachelor of Technology(Mechanical Engineering), is a record of bonafide work carried out by them. They have worked under my
guidance and supervision.
Prof. Dr. M. N. Desmukh Prof.
Sudip Ghatak
Deptt. of Mechanical Engineering
Deptt. of Mechanical Engineering
Galgotia College of Engg. & Tech. Galgotia College of Engg. & Tech
Table of content
1.Project overview2.Literature review of project 3.Technical detail
4.Calculation for gear pump dimension 5.Reference
The overview of project
A gear pump uses the meshing of gears to pump fluid by
displacement.They are one of the most common types of pumps for
hydraulic fluid power applications. Gear pumps are also widely used in chemical installations to pump fluid with a certain viscosity. There are two main variations; external gear pumps which use two external
spur gears, and internal gear pumps which use an external and an internal spur gear. Gear pumps are positive displacement (or fixed
displacement), meaning they pump a constant amount of fluid for
each revolution. Some gear pumps are designed to function as either a
motor or a pump.
Theory of operation
As the gears rotate they separate on the intake side of the pump, creating a void and suction which is filled by fluid. The fluid is carried by the gears to the discharge side of the pump, where the meshing of the gears displaces the fluid. The mechanical clearances are small— in the order of 10 μm. The tight clearances, along with the speed of rotation, effectively prevent the fluid from leaking
backwards.
The rigid design of the gears and houses allow for very high pressures and the ability to pump highly viscous fluids.
Many variations exist, including; helical and herringbone gear sets (instead of spur gears), lobe shaped rotors similar to Roots Blowers
(commonly used as superchargers), and mechanical designs that allow the stacking of pumps.
• External gear pump design for
hydraulic power applications.
•
Internal gear (Gerotor) pump design for automotive oil pumps
Literature Review of
Project
External gear pumps are a popular pumping principle and are often used as lubrication pumps in
machine tools, in fluid power transfer units, and as oil pumps in engines. External gear pumps can come in single or double (two sets of gears) pump configurations with spur
herringbone gears typically offer a smoother flow than spur gears, although all gear types are relatively
smooth. Large-capacity external gear pumps typically use helical or herringbone gears. Small external gear pumps usually operate at 1750 or 3450 rpm and larger models operate at speeds up to 640 rpm. External gear pumps have close tolerances and shaft support on both sides of the gears. This allows them to run to pressures beyond 3,000 PSI / 200 BAR, making them well suited for use in hydraulics. With four bearings in the liquid and tight tolerances, they are not well suited to
handling abrasive or extreme high temperature applications.
Tighter internal clearances provide for a more reliable measure of liquid passing through a pump and for greater flow control. Because of this, external gear pumps are popular for precise transfer and metering applications involving polymers, fuels, and chemical additives.
How External Gear Pumps Work
External gear pumps are similar in
pumping action to internal gear pumps in that two gears come into and out of
mesh to produce flow. However, the external gear pump uses two identical gears rotating against each other -- one gear is driven by a motor and it in turn drives the other gear. Each gear is supported by a shaft with bearings on both sides of the gear.
1. As the gears come out of mesh, they create
flows into the cavity and is trapped by the gear teeth as they rotate.
2. Liquid travels around the interior of the casing in the pockets between the teeth and the casing -- it does not pass between the gears.
3. Finally, the meshing of the gears forces liquid through the outlet port under pressure.
Because the gears are supported on both sides, external gear pumps are quiet-running and are
routinely used for high-pressure applications such as hydraulic applications. With no overhung bearing loads, the rotor shaft can't deflect and cause premature wear
Technical detail
Gear Dimensions
Emprical formula for discharge calculation
:-Ideal discharge
Q= 2aln.N/60
Where a= the area enclosed b/w two adjacent teeth & casing
n = number of teeth in each pinion N = speed in rpm
Parametric curve
Equations of an involute curve for a parametrically
defined function ( x(t) , y(t) ) are:
In Cartesian coordinates the involute of a circle has
the parametric equation:
where a is the radius of the circle and t is a
In polar coordinates the involute of a circle has the
parametric equation:
where a is the radius of the circle and is a parameter
2
ndemperical formula
:- Q = 0.95πC(D – C )lN
where C = the centre to centre distance b/w axis of
gears
D = outside diameter of gears l = axial length of teeth
Outside Diameter (
D = d + 2/Pd
where d = pitch diameter
Pd = Diameterical pitch
Diameterical pitch ( Pd
Pd = n/d
where n = no of teeth d = pitch diameter
Minimum no of teeth to avoid
interence
where n = number of teeth
4-Calculation for gear pump
dimension
• for x = 14.5 n = 23 for x = 20 n = 13 for x = 25
n = 9
For x = 30
n = 7
Table for D/C & n
D/C
1.28 1.21 1.13 1.12
n
7
10
13
18
For x= 20• , n=13, d=20 mm, l=30, D= 23.0769 mm, C= 20.422 mm N = 1500 rpm Q = 7.278 lpm for n=13, d= 25 mm l= 37.5 mm, D= 28.84 mm, C= 25.527mmN = 1500 rpm Q = 14.22 lpm For n =14 , d= 20 mm , l= 30 mm, D= 22.85 mm, C= 20.26 mm N= 1500 rpm Q = 7.056 lpm for n= 15, d =20 mm l= 30 mm, D = 22.666 mm, C= 20.13 mm N = 1500 rpm Q = 6.85 lpm For x=30•, n= 7, d=31.11 mm, l= 31 mm, D= 40.00 mm, C= 31.25 mm N = 1500 rpm Q = 38.08 lpm For x= 30•, n= 7, d= 35 mm
l= 35 mm, D= 45 mm, C= 35.15 mm, N = 1500 rpm
Q = 54.24 lpm
Calculation for gear X= 30•, n= 7, d= 35 l= d l= 35 mm, Pd = n/d Pd = 7/35 Pd = 0.2, Outside dia D = d + 2/Pd D = 35 + 2/0.2 = 45 mm For n=7, D/C = 1.28, Then C = 35.15 mm, N= 1500 rpm Then discharge Q = 0.95*π*C(D-C)lN Then Q = 54.24 lpm
Design of
casing :
-
Casing is like cylinder . Since in gear pump
pressure is relatively high nearly 200 bar . So we design a thick casing for gear pump
thickness of casing ( t
Take factor of safety = 3
for grey cast iron ( FG 200) Sut= 200 MPa Di= 40 mm
Pi = 20 Mpa
permissible tensile strength = 66.666 Mpa then thickness t = 7.25 mm
if fos is = 4
then t = 10.55 mm
For malleable cast iron
Sut= 400 Mpa Di = 40 mm Pi = 20 Mpa if f.o.s. = 3, t = 3.26 mm if f.o.s. = 4, t = 4.49 mm
Gear pump parameter
Parameter Value variable How to get it No. of teeth 7 n We choose Pitch (diameterial) 0.2 p n/ PD Pressure angle 30 x Usually standard (14.5, 20,25, 30) Addendum dia 45 AD PD + 2*a Dedendum dia 22.5 DD PD – 2*d
Pitch dia 35 PD WE CHOOSE
Addendum 5 a 1/p Dedendum 6.25 d 1.25/p
Design of shaft
Pout = (ps – pd )*Q = Pin - Ploss Take ps – pd = 25 bar Q = 54.24 lpm = 9.04 * 10-4 m3/sThen Pout = 2.251 kw
Generally efficiency of gear pump is 85% So Pin = 2.251/0.85 =2.648 kw
N = 1440 rpm T = 60*106*P
in/( 2*π*N )
Then T = 17560.095 N-mm
The permissible shear stress
For alloy steel , 50C4
Syt = 460 MPa , Sut = 660 MPa
Permissible shear strength= minimum of ( 0.3*460 = 138 MPa
& 0.18*660 = 118.8 MPa )
So permissible shear strength = 118.8 MPa
Then d3 = 1003.725 mm
d= 10.012 mm d= 10 mm
References :
-
• Hydraulic machines by Dr. Jagdish Lal published
by Metropolitan Book Co. Private Ltd.
• www.wikipedia.com
• Theory of machine by S.S. Rattan published by T.M.H
• Design of Machine Element by Dr. V.B.