(Andhra Pradesh, Kota and Delhi)
Max. Marks : 150
AITS (Full Test) – CHEMISTRY
Time: 2hrs.
Note : (1) Each question answered correctly is given +3 marks (2) Each question answered incorrectly is given 1 mark
(3) 1 V questions are comprehensive containing 4 questions each
1. A liquid which is immiscible in water was steam distilled at 95.20C at a total pressure of
0.983 atmosphere what is the mass of the liquid is present per gram of water in the distillate. Molar mass of the liquid is 134.3 gm/mol and vapour pressure of water is 0.84atm.
(a) 1 gm (b) 1.27 gm
(c) 0.787 gm (d) 13.43 gm
2.
O
+ CH2 = CH - CN (A) (i) LiAlH4
(ii) H+ (B) (i) C2H5Br(excess) (ii) OH, (C) (an unsaturated compound) O H -dil.
Identify (C) in the given reaction above (a) N(C2H5)2 (b) N(C2H5)2 (c) CH2 Et Et (d) None of these
3. Compound C2H2O3(A) on a reaction with 50% NaOH produces (B) and (C) .Compound (C)
can be prepared by heating sodium formate at 3600C. What is the molecular formula of (B):
(a) || O HC-COOH (b) | COONa COONa (c) CH OH| 2 COONa (d) | CHO COONa
4. What is the ratio of number of atoms per unit cell for molybdenum cubic crystal to the palladium cubic crystal? Use the data given below for Mo and Pd.
Mo Pd a/pm (edge length) 314 pm 388 pm
/g cm-3 10.3 12.16
Molar mass 95.9 g/mol 106.4 g/mol
(a) 1 (b) 2
(c) 1/2 (d) 3/2
5. What is the pH of a solution containing Na2CO3 and NaHCO3. If 50 mL of the solution
requires 20 mL of 0.1N HCl solution in presence of phenolphthalein indicator for the first equivalence point. A further 25 mL of same HCl solution is required when methyl orange is added after the first equivalence point the pH of the log 2 = 0.3010. The pKa1 and pKa2 of
H2CO3 is 6.38 and 10.28 respectively.
(a) 8.98 (b) 10.89
(c) 3.18 (d) 5.18
6. A solution was prepared by dissolving 0.1 gm CrCl3. 6H2O in sufficient water and volume
made to 20mL. 2mL of this solution when treated with excess AgNO3 solution gave a
precipitate. The precipitate is filtered, dried and weighed to be 0.01076 gm. What is the formula of the complex?(At. Masses of Cr = 52, Ag = 108)
(a) [Cr(H2O)6]Cl3 (b) [Cr(H2O)5Cl]Cl2 . H2O
(c) [Cr(H2O)4Cl]Cl .2H2O (d) [Cr(H2O)3Cl3].3H2O
7. Identify the end product in the given reaction:
Ph O OH A B (i) P + Br2 (ii)OH H+ (a) O O O Ph O Ph (b) Ph O Ph O O (c) Ph O Ph O (d) Ph COOH
8. An orange solid (A) on heating produces a gas (B), which on reaction with Mg(s) followed by hydrolysis gives another gas (C). (C) form brown precipitate with K2HgI4 in presence of
KOH. What could be (A),
(a) NH4Cl (b) (NH4)2Cr2O7
(c) (NH4)2CO3 (d) (NH4)2 C2O4
9. Which of the following does not exist as dimmer in benzene:
(a) AlCl3 (b) HCOOH
(c) BF3 (d) All of them
10. In which compound all the sulphur atoms are the centre of tetrahedron: (a) H2S2O5 (b) H2S2O7
(c) H2S2O6 (d) Na2S4O6
11. How many number of moles can be oxidized of FeS2 by 1 mole of potassium permagnate in
acidic medium so as to convert it into Fe3+ and SO 2.
(a) 1.2 (b) 5
(c) 0.454 (d) 11
12. What is the end product of the following sequence of reaction: NO2 NO2 (NH4)2S A (i) NaNO2+HCl, 5 B 0C OH (ii) NH2 O2N (a) N O2N N OH (b) N NH2 N OH (c) O H2N N2Cl (d)
13. Arrange the following in their increasing order of stability. CH2 -(I) CH -(II) C -(III) : C- CH3 (IV) ..
(a) II, I, III, IV (b) III, IV, I, II (c) IV, III, I, II (d) IV, III, II, I 14. Which of the following is the correct order of the acidity:
O N+ H H (I) N+ H H (II) (III) N+ H H
(a) (III) > (I) > (II) (b) (I) > (II) > (III) (c) (II) > (I) > (III) (d) (III) > (II) > (I) 15. Which of the following statement is correct:
(a) when a molecule can best be represented as a series of resonance forms each of these forms always contributes to the same degree in the hybrid.
(b) A node is a region of high electron density between the two atoms in a covalent bond. (c) For a carbon atom, the 2s and 2p orbitals are equal in energy
(d) When filling two or more orbitals of the same energy with electrons, the single electron is filled into different orbital rather than pair up in the same orbital
16. Identify the incorrect statement amongst the following
(a) Liquid nitrogen does not sticks to the polls of magnate whereas liquid oxygen does. (b) NO2 is brown in colour at room temperature but colourless below 00C.
(c) Bond order of CN and N2 are equal but CNis more reactive
(d) NO+ is having lower bond strength then NO.
17. The heat of neutralization of HF, HNO2, HCN and HOCl are –p, -q, -r, and –s respectively.
(a) HF > HNO2 > HOCl > HCN (b) HCN > HNO2 > HOCl > HF
(c) HCN > HOCl> HNO2 > HF (d) HOCl > HCN> HNO2 > HF
18. Match the following
ions/molecules structure Shape
(a) ICl-4 (i) octahedral (p) sea-saw
(b) ClF4+ (ii) tetrahedral (q) square pyramidal (c) +
3
I (iii) triangle bipyramidal (r) bent shape (d) SO3 (iv) trigonal planer (s) trigonal planer
(a) a – (iii) – p, b – (iv) – r, c – (ii) – s , d - (i)- q (b) a – (iii) – p, b – (i) – q, c – (iv) – r , d - (ii)- s (c) a – (ii) – q, b – (iii) – p, c – (i) – s , d - (iv)- r (d) a – (i) – q, b – (iii) – p, c – (ii) – r , d - (iv)- s
19. The plots of compressibility factor versus pressure is shown for the CH4, CO2 and NO2.
Which of the gas will occupy least volume, the Vander Waal constant b is almost same for the given gases. C H 4 C O 2 N O 2 P ( a t m ) I d e a l G a s Z (a) CH4 (b) CO2
(c) NO2 (d) all occupy the same volume
20. Which of the following statements are true
(i) Sucrose does not reduce fehling solution although both the constituent monosaccharides glucose and fructose reduces.
(ii) Glucose and fructose are epimers
(iii) Ketoses exists both in pyranose forms and as furanose derivative (iv) Monosaccharides are insoluble in water but soluble in ether. (a) (ii), (iii), (iv) (b) (i), (iii), (iv) (c) (i), (ii), (iii) (d) (i), (ii), (iv)
CH2COOH CH2COOH
(i) CaO,
(ii) NH2OH A
P2O5
H+ B; Identify the compound B.
21. CH2CONH2 CH2CONH2 (a) (b) NH N H O (c) CH2CN CH2CN (d)
N O O H (I) N H O O (II) N H O O (III) N H CHO CHO (IV) 22.
order of basic strength for the given compounds :
(a) (I) > (IV) > (III) > (II) (b) (IV) > (I) > (III) > (II) (c) (II) > (III) > (I) > (IV) (d) (IV) > (II) > (III) > (I) 23. Electrode potential data given below
Cl2 + 2H2O 2ClO + 4H+ + 2e; E0 = -1.61 volt
ClO + 2H
2O ClO3 + 4H+ + 4e; E0 = -0.50 volt Based on these data which is the spontaneous reaction
(a) Cl2 ClO + ClO-3 (b) ClO Cl2 + ClO-3 (c)
-3
ClO Cl2 + ClO (d) ClO + Cl2 ClO-3
24. A dianion [x] decolourises the dichromate solution in acidified medium. Acidifying the sodium carbonate extract with acetic acid and adding calcium chloride, a white precipitate is obtained. The precipitate dissolves in dilute H2SO4 form [y] which on heating produce two
gases. The [x] is (a) 2-3 SO (b) 2-3 CO (c) 2-2 4 C O (d) 2-2 4 S O 25. Correct order of basicity is:
CH3 N CH3 CH3 CH3 I N CH3 CH3 CH3 II N CH3 CH3 O2N III N CH3 CH3 IV
(a) IV > III > I > II (b) I > II > IV > III (c) III > IV > I > II (d) I > II > III > IV 26. What will be the surface area of catalyst which absorbs 224 cm3 of X
2 (g) at S.T.P. per gram
in order to form monomolecular layer of X2(g). The effective surface area occupied by a gas
molecule on the surface of catalyst is 1.67 10-16 cm2
(a) 2.24 105 cm2 (b) 106 cm2
(c) 1.67 105 cm2 (d) 6 105 cm2
27. A reactant X(g) decomposes in the two way simultaneously
2 1
(g) (g)
3Z K X K 2Y
The decomposition follows first order kinetics and the rate constant K1 and K2 are 1.8 10-4
and 3.0 10-4 sec-1 respectively. What is the ratio of the concentration of Y and Z at 100 sec,
(a) 3 : 5 (b) 2 : 5
(c) 5 : 3 (d) 5 : 2
28. The following questions consist of two statement, one labelled ASSERTION (A) and the another labelled REASON (R) select the correct answers to these questions
Assertion(A) : Thiosulphuric acid, H2S2O3 cannot be prepared by adding acid to a
thiosulphate.
Reason(R) : The free acid decomposes in water into a mixture of S, H2S, H2Sn, SO2 and
H2SO4
(a) both A and R are true and R is the correct explaination of A. (b) both A and R are true but R is not the correct explaination of A (c) A is true but R is false
(d) both A and R are false
CH3 Br 29. NaF (X) C H3 S C H3 O ; CH3 CHCl CH3 H2O NaF (Y) ; (X)+(Y) H + (Z)
Compound (X) and (Z) are respectively
CH3 F (a) CH3 OCHMe2 and (b) CH3 CH3 OCHMe2 and (c) CH3 OCHMe2 CH2and (d) CH3 CH3 OCHMe2 and
30. The relative rate of extraction of H and D is 2.6 : 1. The percentage yield of the product A and B in the following reaction is:
2 2 4 2 2 4 2 2 3 (A) (B) uv C H D + Cl C HD Cl + C H D Cl (a) 27.8%, 72.2% (b) 72.2%, 27.8% (c) 56.52%, 43.48% (d) 43.48%, 56.52%
P-1. Glycerol is a trihydric alcohol when it is treated with potassium hydrogen sulphate it form a compound (A).
Compound (A) gives the following reaction:
3 2 ( ) ( ) / ( ) i O ( ) ( ); ii H O Zn A B C ( ) . 4 4 4 ( ) ( ) i Conc OH ( ) [ ] ii H C D C H O 3 ( )B NH ( )E
Substance (E) can be used in medicinal purpose.
31. Compound (D) in the given sequence of reaction is CHCOOH CHCOOH (a) (b) O O O O (c) CH O CH2 O O O H (d) HC HC O O O H O H H H
32. When compound (B) is treated with 50% NaOH, then it gives two compound which on reaction on reaction in an acidified medium terms
(a) CH3COOH (b) HCOOCH3
(c) CH3COOCH3 (d) CH3COOC2H5
33. Compound (C) is
(a) Glycolic acid (b) Glycerol (c) Oxalic acid (d) Glyoxal 34. Which of the following statements is true for (C):
(I) It reduces Tollen’s reagent (II) It reduces Fehling solution
(III) It gives Canizzarro reaction with conc. Base.
(a) I only (b) I, II
(c) I, III (d) III only
35.
+
C H3 CH2 CH2 Product ; Compound (A)The product of the reaction is :
(a) H3C CHO (b) CHO C H3 (c) CHO C H3 (d) CHO C H3
P-2. Colloid is heterogeneous system is which are substance is dispersed as very fine particles in another substance called dispersion medium
A solution is a homogeneous system. The essential difference between a solution and a colloid is one of particle size. In a solution, the particles are ions or small molecules in a colloid, the dispersed phase may consist of particles of a single macromolecule (such as protein or synthetic polymer) or an aggregate of many atoms, ions or molecules.
Colloidal particles are larger than simple molecules but small enough to remain suspended. Depending upon mlether the dispersed phase and dispersion medium are solids, liquids and gases, eight types of colloidal systems are possible.
Solid Solid Solid solution
Solid Liquid Solution
Solid Gas Aerosol
Liquid Solid Gel
Liquid Liquid Emulsion
Liquid Gas Aerosol
Gas Solid Solid solution
Gas Liquid Foam
Depending upon the type of the particles of the dispersed phase, colloids are classified as multimolecular and associated colloids:
36. Which of the following does not result formation of solution. (A) FeCl3 3H O2 Fe(OH) 3HCl 3
(B) SO2 2H S2 3S 2H O2
(C) As S2 3 2H S2 As S2 3 3H O2
(D) None of these
37. Hair cream is an example of:
(a) Gel (b) Emulsion
(c) Solution (d) Aerosol
38. Which of the following is not an example of aerosol:
(a) Fog (b) Smoke
(c) Froth (d) cloud
39. Depending upon the nature of interaction between the dispersed phase and the dispersion medium colloidal sols are lyophillic and lyophobic. Which of the following is not result lyophobic colloidal solution on mixing with suitable liquid
(a) Gelatin (b) Starch
(c) Rubber (d) all of them
40. Match the followings:
(A) Sol (I) Milk
(B) Gel (II) Whipped cream
(C) Foam (III) Cheese
(D) Emulsion (IV) Paints
(a) (A)–(I) , (B) –(II), (C)-(II), (D)–(IV) (b) (A)–(III) , (B) –(II), (C)-(I), (D)–(IV) (c) (A)–(II) , (B) –(IV), (C)-(III), (D)–(I) (d) (A)–(IV) , (B) –(III), (C)-(II), (D)–(I)
P-3. The rate constant for most of the reactions increases with the increase of temperature. It has been found that a plot of log10K against 1/T gives a straight line (as shown in fig) represented
by the equation log10K = 10
Ea log A
2.303RT
NARAYANA IIT ACADEMY lg10 K
The equation is known as Arrhenius equation and also be written as Ea / RT
K Ae
For an equilibrium reaction A(g) ˆ ˆ†‡ ˆˆ B(g)
The rate constant of forward reaction increases by 130% when its temperature is raised from 300 K to 310 K. The ratio of activation energy of forward reaction to backward reaction is 1 : 3. [Log2.3 = 0.361, antilog (-0.723) = 0.189]
41. By increasing the temperature, the effect on equilibrium constant : (a) It decreased by 130% (b) It decreases by 19% (c) It decreases by 81% (d) It does not change 42. The activation energy of the forward reaction is
(a) 7.92KJ (b) 64.41 KJ
(c) 16.2 KJ (d) 6.44 KJ
43. For the given reaction, the temperature coefficient of the forward reaction is
(a) 1. 3 (b) 0.77
(c) 0.43 (d) 2.3
44. What fraction of molecules are in the activated state in forward reaction [antilog (0.79) = 6.61]
(a) 6.16 10-12 % (b) 6.16 10-10 %
(c) 6.16 10-8 % (d) 6.16 10-6 %
45. For the reactions (i) X Y ; Ea = 40 KJ mol-1
and (ii) X Y ; Ea = 80 KJ mol-1
for the same 100C rise in temperature which of the following statement is correct
(a) Both the reaction’s rate increases to an equal extent. (b) Increase in rate of reaction (i) is more than that of (ii) (c) Increase in rate of reaction (ii) is more than that of (i) (d) The rate will not be affected
P-4. An alkene can be converted to alcohol by the following three methods: (a) acid catalysed hydration
(b) oxymercuration – demercuration reaction (c) Hydroboration – oxidation
the reactions are as shown below:
alkene H + /H2O (a) H OH
(ii) NaBH4 (i) Hg(OAc)2 / H2O (b) OH HgOAc OH H (ii) H2O2/OH (i) B2H6.THF (c) H B H OH
In first method formation of alcohol takes place via formation of carbocation so there is a possibility of rearrangement where as in oxymeration –demercuration and hydroboration-oxidation formation of alcohol takes place without any rearrangement of structure because the formation of carbocation does not takes place. An alkene (X) C10H12 from three isomeric
alcohols by the above three methods as
0 (a) (3 ) Alcohol X A ; (b) 0 (2 alc.) X B ; (c) 0 (1 alc.) X C ;
Alkene (X) with hot KMnO4 gives C7H6O2 which gives effervcence with NaHCO3
46. What is the structure of (X) :
(a) H3C C CH2 CH3 (b) C CH CH3 CH3 (c) H3C CH2 CH CH2 (d) CH CH CH2 CH3
47. The end product for the given sequence of reactions: (X) (i) B2H6.THF (ii) H2O2/OH (C) H + Product C6H6 (a) C CH2CH3 CH3 (b) CH2 CH CH2CH3 (c) CH2 HC CH2 CH3 (d) CH2 C CH3 CH3 C H3
48. When 1-ethyl-6-methyl cyclohexene is treated with mercuric acetate in presence of methyl alcohol followed sodium borohydride gives-
(a) 3 C2H5 CH3 (b) C2H5 H3CO C H3 (c) OCH3 C H3 C2H5 (d) C2H5 C2H5 OCH3 49. C H3 O H CH3
CH2 (i) Hg(OAc)2 / H2O Product
(ii) NaBH4
Identify the product in the given reaction: (a) C H3 O H CH3 OH (b) OH CH3 C H3 (c) O CH 3 C H3 (d) O O CH3 C H3 50. Identify the final product of the given reaction:
CH2
CH3 (i) B
2H6.THF
(ii) H2O2/OH
H+ (i) B2H6.THF
(ii) H2O2/OH Product CH3 OH (a) OH CH3 CH3 (b) (c) CH3 OH CH3 (d) OH CH3 CH3 * * *
NARAYANA IIT ACADEMY
(Andhra Pradesh, Kota and Delhi)
AITS – CHEMISTRY
ANSWERS
1 2 3 4 5 6 7 8 9 10 B D C C B B A B C B 11 12 13 14 15 16 17 18 19 20 C B C A D D C D C C 21 22 23 24 25 26 27 28 29 30 C B B C B B B A B C 31 32 33 34 35 36 37 38 39 40 B B D C B D B C D D 41 42 43 44 45 46 47 48 49 50 C B D B C D A C C DHints and Solution
1. PT = 0.983 atm 0 ter 0.84 tm wa P a ; Pliq i0u d 0.143 tma 0 u d u d u d 0ter ter ter
( t) 0.143 134.3 19.205
( t) 0.84 18 15.12
liq i liq i liq i
wa wa wa w P M w P M u d ter ( t) 1.27 ( t) 1 liq i wa w w O .. + CH2 = CH - CN CH2 O CH2CN LiAlH4 OH CH2CH2 CH2 H2N H+ N H (i) C2H5Br (excess) (ii) OH N Et Et OH N Et CH2 = CH2 + (C) + 2.
NARAYANA IIT ACADEMY
4. For M0 3 A a N N M 3 o 1 1 2 2 3 d 1 2 M A P A N a N M N M a N = 1 2 For Mo N = 2 BCC lattice Pd N = 4 FCC lattice 5. 1Meq 2 Na2CO3 = 20 0.1 = 2 Meq Na2CO3 = 4 1 Meq 2 Na2CO3 + Meq NaHCO3 = 25 0.1 = 2.5 Meq NaHCO3 = 0.5
Na CO2 3 2 Molarity = =0.04 50
NaHCO3 0.5 Molarity = =0.01 50 2-3 2 -3 |CO | pH=pK +log |HCO | = 10.28 + log0.04 0.01 = 10.28 + 0.6020 = 10.88 6. Let formula of CrCl3.6H2O [Cr(H2O)nClx] Cl3-x .(6 – n)H2O [Cr(H2O)nClx]Cl3-x (6 – n)H2O + (3-x)AgNO3 (3 –x) AgCl(ppt.)wt. of complex compound for 2 mL is 0.01 gm
3 x
0.01 0.01076 266.5 143.5 solving x = 1 Formula is [Cr(H2O)5Cl]Cl2. H2O 7. (ii) OH Ph HC COOH OH H+ C O C C O O Ph Ph O (i) P + Br2 Ph OH O9. AlCl3 and HCOOH exist as dimmer in benzene.
O H S O O O S OH O O (H2S2O7) 10. 11. FeS2 + KMnO4 H Fe3+ + SO2 + Mn2+ (n = 11) (n = 5) 4 2 e 110 5 KMnO F S n n nF Se2 = 0.454 mole
NO2 O2N (NH4)2S NH 2 O2N HCl NaNO2 N2Cl O2N + OH -HCl N NO2 N OH + 12. 50C
19. The order of ‘a’ value NO2 > CO2 > CH4 (as per graph). If the gases are having same value of
b but different values of a, then the gas having larger value of a will occupy lesser volume. This is due to larger force of attraction hence the lesser distance between its molecules.
CH2COOH CH2COOH CaO, CH2 CH2 O H2NOH N - OH P2O5, H + NH O 21. 24. 2 2 4 C O + 2 2 7 Cr O Cr3 + CO 2 H2C2O4 H2O + CO + CO2 26. No. of molecules N = 224 6.023 1023 22400 = 6.023 10 21 Area/molecule = 1.67 10-16 cm2
total surface area covered by X2 (g) / gram of the catalyst
= 1.67 10-16 6.023 1021 = 10.06 105 cm2 27. 2 1 (g) (g) 3Z K X K 2Y 4 1 4 2 | | 2 1.8 10 2 | z | 3 3 3 10 5 y K K
3 Br 29 NaF C H3 S C H3 O CH3 CHCl CH3 H2O NaF H+ CH3 [via E2 machanism] CH3 CH CH3 OH [F- is solvated ] CH3 + CH3 CH CH3 OH CH3 OCHMe2 (Z) (Y) (X) 30. Product AProduct B = 2.6× 24×1 = 5.24 % A = 5.2 100 56.52% 9.2 35. A
+
C H3 CH2 CH2 CHO C H3 CH2 CHO P-3. 310 300 K =2.3 K 310 af 300 K E 1 1 log = K 2.303R 300 310 Eaf = log(2.3) 2.303 300 310 10 R = 64.41 kJ As af ar E 1 = E 3
H
r×n=E -Eaf ar 2EafThe reaction is exothermic so by increasing the temperature the equilibrium constant decreases
21 af -2E 1 1 log K 2.303R 300 310 K 2 1 K log K = -2 log2.3 2 1 0.189 K K K2 0.19 K1 equilibrium constant decreases. And it decreases by 81%.
CH2 CH3 (i) B2H6THF (ii) H2O2/OH H+ (i) B2H6.THF (ii) H2O2/OH CH3 OH CH3 C2H5 CH3 C2H5 OH 50. * * *
