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R E S E A R C H

Open Access

Common fixed point of multifunctions on

partial metric spaces

S Mohammad Ali Aleomraninejad

1

, Inci M Erhan

2*

, Marwan A Kutbi

3

and Masoumeh Shokouhnia

4

*Correspondence:

[email protected]

2Department of Mathematics, Atilim

University, ˙Incek, 06836, Ankara Full list of author information is available at the end of the article

Abstract

In this paper, some multifunctions on partial metric space are defined and common fixed points of such multifunctions are discussed. The results presented in the paper generalize some of the existing results in the literature. Several conclusions of the main results are given.

MSC: 47H10; 54H10; 46T99

Keywords: common fixed point; partial metric space; multifunction

1 Introduction

The notion of a partial metric space (PMS) was introduced by Matthews [] in  (see also []). The PMS is a generalization of the usual metric space in whichd(x,x) is no longer necessarily zero. Recently, many authors have focused on the PMS and its topological properties(see for example [–]). Partial metric spaces have extensive application po-tential in the research area of computer domains and semantics (see [–]).

A partial metric is a functionp:X×X→[,∞) satisfying the following conditions: (a) p(x,y) =p(y,x)(symmetry),

(b) x=y⇐⇒p(x,x) =p(x,y) =p(y,y)(equality), (c) p(x,x)p(x,y)(small self-distances),

(d) p(x,y)p(x,z) +p(y,z) –p(z,z)(triangularity), for allx,y,zX. Then (X,p) is called a partial metric space.

Each partial metricponXgenerates aTtopologyτponXwith a base of the family of

openp-balls{Bp(x,ε) :xX,ε> }, where

Bp(x,ε) =

yX:p(x,y) <p(x,x) +ε,

for allxXandε> . For a partial metricponX, the functiondp:X×X→[,∞) given

by

dp(x,y) = p(x,y) –p(x,x) –p(y,y)

is a (usual) metric onX. Another metric onXinduced bypis defined in [] asd(x,y) = p(x,y) wheneverx=yandd(x,y) =  wheneverx=y.

Some topological concepts and basic results on a PMS are defined as follows.

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A sequence{xn}n≥in a PMS (X,p) converges toxXif and only ifp(x,x) =limn→∞p(x, xn).

A sequence{xn}n≥is called a Cauchy sequence if and only iflimn,m→∞p(xn,xm) exists

and is finite.

A PMS (X,p) is said to be complete whenever every Cauchy sequence{xn}n≥inX

con-verges to a pointxwith respect toτp, that is,p(x,x) =limn,m→∞p(xn,xm).

Lemma .([]) Let(X,p)be a partial metric space.Then:

(i) A sequence{xn}n≥is Cauchy in a PMS(X,p)if and only if{xn}n≥is Cauchy in the

metric space(X,dp).

(ii) A PMS(X,p)is complete if and only if the metric space(X,dp)is complete.Moreover,

lim

n→∞dp(x,xn) =  ⇐⇒ p(x,x) =nlim→∞p(x,xn) =n,mlim→∞p(xn,xm).

An interesting property of partial metric spaces is the nonuniqueness of limits of se-quences. To emphasize this property we consider the following example.

Example . LetX= [,∞) and define a partial metricponXas

p(x,y) =max{x,y}.

Consider the sequence{xn}={ +n}. Notice that

lim

n→∞p(xn, ) =nlim→∞max

 + 

n, 

= lim

n→∞ +

n= .

Also

lim

n→∞p(xn, ) =nlim→∞max

 + n, 

= lim

n→∞ = .

Moreover, for anya≥ we have

lim

n→∞p(xn,a) =a.

In what follows, we introduce the notions, notations, and assumptions used in the dis-cussion. Throughout this paper, we suppose that (X,p) is a partial metric space. We denote the family of all nonempty subsets ofXby X, the family of all closed subsets ofXbyC(X)

and the family of all closed and bounded subsets ofXbyCB(X). The partial Hausdorff distanceHponCB(X) was introduced by Aydiet al.[] as follows:

Hp(A,B) =max

sup

aA

p(a,B),sup

bB

p(b,A)

, ()

for allA,BCB(X), where

p(x,A) =inf

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LetT:X→Xbe a multi-valued function (multifunction). We denote the set of fixed

points ofTbyF(T),i.e.,

F(T) ={x∈X:xTx}. ()

Lemma .([]) Let(X,p)be a partial metric space,AX,and xX.Then xA if and only if p(x,A) =p(x,x).

In , Aydiet al.[] proved the following fixed point theorem on partial metric space.

Theorem . Let(X,p)be a complete partial metric space and T:XCB(X)a multi-function.Suppose that there exist k∈(, )such that

Hp(Tx,Ty)kp(x,y), ()

for all x,yX.Then T has a fixed point.

Some fixed point theorems for multifunctions on metric space are given next (see [, , ]).

Theorem . Let(X,d)be a complete metric space and T:XCB(X)a multifunction. Assume that there exists r∈[, )such that

 +rd(x,Tx)d(x,y) implies H(Tx,Ty)rd(x,y), ()

for all x,yX.Then T has a fixed point.

Theorem . Let(X,d)be a complete metric space and T:XC(X)a multifunction. Assume that there exist a,b,c∈[, )such that a+b+c< and

( –bc)

 +a d(x,Tx)d(x,y) ()

implies

H(Tx,Ty)ad(x,y) +bd(x,Tx) +cd(y,Ty), ()

for all x,yX.Then T has a fixed point.

The aim of this paper is to provide a new, more general condition for the multifunction T which guarantees the existence of its fixed point. Our results generalize some of the existing ones.

In what follows, we consider two classes of functions, namely,RandRas defined below.

Definition . LetRbe the set of all continuous functionsg: [,∞)→[,∞), satisfying

the conditions:

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(ii) gis subhomogeneous,i.e.,g(αx,αx,αx,αx,αx)≤αg(x,x,x,x,x), for all

α≥,

(iii) ifxi,yi∈[,∞),xiyifori= , . . . , we haveg(x,x,x,x,x)≤g(y,y,y,y,y).

LetRbe the set of all continuous functiong: [,∞)→[,∞) satisfying the following

conditions:

(a) g(t,t,t,t,t) <t, for allt∈[,∞), (b) gis subhomogeneous,

(c) ifxi,yi∈[,∞),xiyifori= , . . . , we haveg(x,x,x,x,x)≤g(y,y,y,y,x),

(d) for all≤ax,g(x,x,x,x–a,a) =g(x,x,x,x, ).

Remark . It is easy to see that ifgR, theng(, , , , ) =h∈(, ). Indeed, ifgR,

the conditions (i) and (ii) give

g(t,t,t, t,t)tg(, , , , ) <t, ()

which impliesg(, , , , ) =h∈(, ). In addition, ifgR, then by a similar argument

we observe thatg(, , , , ) =h∈(, )

Examples of functions from both classes are given below.

Example . The functiong(x,x,x,x,x) =kmax{xi}i=fork∈(,) is in classR.

Example . The functiong(x,x,x,x,x) =kmax{x,x,x,x+x}fork∈(, ) belongs

toR.

The following results are quite trivial.

Proposition . If gRand u,v∈[,∞)are such that

u≤maxg(v,u,v,u,v),g(v,u,v,v+u,v), ()

then uhv,where h=g(, , , , ).

Proof From (iii) it is clear thatg(v,u,v,u,v)g(v,u,v,v+u,v) and henceu≤max{g(v,u,v, u,v),g(v,u,v,v+u,v)}=g(v,u,v,v+u,v). Ifv<u, then

ug(v,u,v,v+u,v)g(u,u,u, u,u)ug(, , , , ) =hu<u,

which is a contradiction. Thusuv, which implies

ug(v,u,v,v+u,v)g(v,v,v, v,v)vg(, , , , ) =hv.

Proposition . If gRand u,v∈[,∞)are such that

u≤maxg(v,u,v,u+v, ),g(v,u,v,u,v), ()

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Proof Letmax{g(v,u,v,u+v, ),g(v,u,v,u,v)}=g(v,u,v,u+v, ). Ifv<u, then (d) implies

ug(v,u,v,v+u, )g(u,u,u, u, )ug(, , , , ) =ug(, , , , ) =hu<u,

which is a contradiction. Thusuv, and hence,

ug(v,u,v,v+u, )g(v,v,v, v, )vg(, , , , ) =vg(, , , , ) =hv.

Letmax{g(v,u,v,u+v, ),g(v,u,v,u,v)}=g(v,u,v,u,v). Ifv<u, then

ug(v,u,v,u,v)g(u,u,u,u,u)ug(, , , , ) =hu<u.

This contradicts our assumption, that is, we should haveuv. Then

ug(v,u,v,u,v)g(v,v,v,v,v)vg(, , , , ) =hv,

which completes the proof.

2 Main results

We state and proof our main results in this section.

Lemma . Let(X,p)be a partial metric space and T,S:XC(X)be two multifunc-tions.Suppose that there existα∈(,∞)and gR∪Rsuch thatαp(x,Tx)p(x,y)or

αp(y,Sy)p(x,y)implies Hp(Tx,Sy)g

p(x,y),p(y,Sy),p(x,Tx),p(x,Sy),p(y,Tx), ()

for all x,yX.Then for every xF(T)F(S)we have p(x,x) = .

Proof Without loss of generality, we can suppose thatxTx. Thenp(x,Tx) =p(x,x) and hence

p(x,Sx)Hp(Tx,Sx)g

p(x,x),p(x,Sx),p(x,Tx),p(x,Sx),p(x,Tx)

gp(x,x),p(x,Sx),p(x,x),p(x,Sx),p(x,x) . ()

By using Proposition . ifgRor Proposition . ifgR, we have

p(x,x)p(x,Sx)hp(x,x).

However, sinceh<  we havep(x,x) = .

Lemma . Let(X,p)be a partial metric space and T,S:XC(X)be two multifunc-tions.Suppose that there existα∈(,∞)and gR∪Rsuch thatαp(x,Tx)p(x,y)or

αp(y,Sy)p(x,y)implies Hp(Tx,Sy)g

p(x,y),p(y,Sy),p(x,Tx),p(x,Sy),p(y,Tx),

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Proof IfxTx, thenp(x,Tx) =p(x,x) =  by Lemma .. Hence,

p(x,Sx)Hp(Tx,Sx)g

p(x,x),p(x,Sx),p(x,Tx),p(x,Sx),p(x,Tx)

gp(x,x),p(x,Sx),p(x,x),p(x,Sx),p(x,x)

g,p(x,Sx), ,p(x,Sx),  . ()

By using Proposition . whenever gR or Proposition . in case gR, we have

p(x,Sx)h = , and thus xF(S). Thus, F(T)⊆F(S). Similarly, we can show that

F(S)F(T), which completes the proof.

In what follows, we state our main existence result.

Theorem . Let(X,p)be a complete partial metric space and T,S:XC(X)be two multifunctions.Suppose that there exist gR∪Randα∈(, ),such thatα(h+ )≤

where h=g(, , , , )if gRand h=g(, , , , )if gR.Suppose also thatαp(x,Tx)

p(x,y)orαp(y,Sy)p(x,y)implies Hp(Tx,Sy)g

p(x,y),p(y,Sy),p(x,Tx),p(x,Sy),p(y,Tx), ()

for all x,yX.Then F(T) =F(S)and F(T)is nonempty.

Proof By Lemma . we already haveF(T) =F(S). Fix arbitrary  >r>handx∈Xand

choosex∈Txsuch thatαp(x,Tx) <p(x,x). Then by the hypothesis of the theorem

and condition (iii) or (c) in Definition ., respectively, we have

p(x,Sx)≤Hp(Tx,Sx)≤g

p(x,x),p(x,Sx),p(x,Tx),p(x,Sx),p(x,Tx)

gp(x,x),p(x,Sx),p(x,x),p(x,Sx),p(x,x)

gp(x,x),p(x,Sx),p(x,x),p(x,x) +p(x,Sx) –p(x,x),p(x,x)

gp(x,x),p(x,Sx),p(x,x),p(x,x) +p(x,Sx),p(x,x) ,

where obviouslyp(x,Sx)≤p(x,x) +p(x,Sx) –p(x,x) due to triangle inequality in

PMS. Suppose thatgR. Since

p(x,Sx)≤g

p(x,x),p(x,Sx),p(x,x),p(x,x) +p(x,Sx),p(x,x) ,

then, by Proposition ., we have

p(x,Sx)≤hp(x,x) <rp(x,x). ()

Now letgR. Since

p(x,Sx)≤g

p(x,x),p(x,Sx),p(x,x),p(x,x) +p(x,Sx) –p(x,x),p(x,x),

and obviously ≤p(x,x)≤p(x,x) +p(x,Sx), we leta=p(x,x) and employ condition

(d) in Definition . to get

p(x,Sx)≤g

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Now by Proposition ., we have

p(x,Sx)≤hp(x,x) <rp(x,x). ()

We choose a numberμsuch thatinfySxp(x,y) =p(x,Sx) <μ<rp(x,x). Thus there

existsx∈Sxsuch thatp(x,x) <μ<rp(x,x). Sinceαp(x,Sx) <p(x,x), by using ()

and the properties of the functiongwe have

p(x,Tx)≤Hp(Sx,Tx)≤g

p(x,x),p(x,Tx),p(x,Sx),p(x,Tx),p(x,Sx)

gp(x,x),p(x,Tx),p(x,x),p(x,x) +p(x,Tx) –p(x,x),p(x,x)

gp(x,x),p(x,Tx),p(x,x),p(x,x) +p(x,Tx),p(x,x) .

Now, ifgR, using Proposition . and mimicking the proof of () we obtain

p(x,Tx)≤hp(x,x) <rp(x,x). ()

IfgR, lettinga=p(x,x) we get

p(x,Tx)≤g

p(x,x),p(x,Tx),p(x,x),p(x,x) +p(x,Tx) –p(x,x),p(x,x)

gp(x,x),p(x,Tx),p(x,x),p(x,x) +p(x,Tx),  ,

and hence Proposition . yields

p(x,Tx)≤hp(x,x) <rp(x,x). ()

In a similar way, we can choosex∈Txsuch that

p(x,x) <rp(x,x) <rp(x,x). ()

By continuing this process, we obtain a sequence{xn}n≥inXsuch that

xn–∈Txn–, xnSxn–, ()

which satisfies

p(xn,xn+)≤rnp(x,x). ()

Thenp(xn,Txn)≤hp(xn–,xn) andp(xn–,Sxn–)≤hp(xn–,xn–).

Ifxm=xm+for somem≥ wherem= k, then

p(xk,xk)≤p(xk,Txk)≤p(xk,xk+) =p(xk,xk),

sop(xk,Txk) =p(xk,xk), and hencexkTxk. ThusTandShave a fixed point. Ifm=

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Suppose thatxn=xn+, for alln≥. Repeated application of the triangle inequality

im-plies

p(xn,xn+m)≤p(xn,xn+) +p(xn+,xn+) +· · ·+p(xn+m–,xn+m)

rnp(x,x) +rn+p(x,x) +· · ·+rn+m–p(x,x)

rnp(x,x)

 +r+r+· · ·+rm–

rn

 –rp(x,x).

Then we get

lim

n→∞p(xn,xn+m)→,

and hence{xn}n≥is a Cauchy sequence in (X,p). Regarding Lemma .,{xn}n≥ is also a

Cauchy sequence in (X,dp). Since (X,p) is a complete partial metric space, by Lemma .,

(X,dp) is also complete. Thus{xn}n≥converges to a limit, say,xX, that is,

lim

n→∞dp(xn,x) = . ()

Notice that Lemma . yields

p(x,x) = lim

n→∞p(xn,x) =n,mlim→∞p(xn,xm) = . ()

Now, we claim that for eachn≥ one of the relations

αp(xn,Txn)≤p(xn,x) or αp(xn+,Sxn+)≤p(xn+,x) ()

holds. If for somen≥ we haveαp(xn,Txn) >p(xn,x) andαp(xn+,Sxn+) >p(xn+,x)

then

p(xn,xn+)≤p(xn,x) +p(x,xn+)

<αp(xn,Txn) +αp(xn+,Sxn+)

αp(xn,xn+) +αhp(xn,xn+).

This results inα(h+ ) > , which contradicts the initial assumption. Hence, our claim is proved. Observe that by the assumption of the theorem, for eachn≥ we have either

Hp(Txn,Sx)g

p(xn,x),p(x,Sx),p(xn,Txn),p(xn,Sx),p(x,Txn)

or

Hp(Sxn+,Tx)g

p(xn+,x),p(x,Tx),p(xn+,Sxn+),p(xn+,Tx),p(x,Sxn+).

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Case (i). There exists an infinite subsetI⊆Nsuch that

p(xn+,Sx)Hp(Txn,Sx)

gp(xn,x),p(x,Sx),p(xn,Txn),p(xn,Sx),p(x,Txn) ,

for allnI.

Case (ii). There exists an infinite subsetJ⊆Nsuch that

p(xn+,Tx)Hp(Sxn+,Tx)

gp(xn+,x),p(x,Tx),p(xn+,Sxn+),p(xn+,Tx),p(x,Sxn+),

for allnJ. In Case (i), we get

p(x,Sx)p(x,xn+) +p(xn+,Sx)

p(x,xn+) +g

p(xn,x),p(x,Sx),p(xn,Txn),p(xn,Sx),p(x,Txn)

p(x,xn+)

+gp(xn,x),p(x,Sx),p(xn,xn+),p(xn,x) +p(x,Sx) –p(x,x),p(x,xn+),

for allnI. Continuity ofgimplies

p(x,Sx)g,p(x,Sx), ,  +p(x,Sx) – , . ()

Now by using Propositions . and ., we havep(x,Sx) = , and thusxSx. In Case (ii), we have

p(x,Tx)p(x,xn+) +p(xn+,Tx)

p(x,xn+) +g

p(xn+,x),p(x,Tx),p(xn+,Sxn+),p(xn+,Tx),p(x,Sxn+)

p(x,xn+)

+gp(xn+,x),p(x,Tx),p(xn+,xn+),

p(xn+,x) +p(x,Tx) –p(x,x),p(x,xn+) ,

for allnJ. Sincegis continuous, we obtain

p(x,Tx)g,p(x,Tx), ,  +p(x,Tx) – ,  . ()

Again, by using Propositions . and ., we havep(x,Tx) = , which givesxTx. This

completes the proof.

The following results are consequences of Theorem ..

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α(h+ )≤andαp(x,Tx)p(x,y)implies

Hp(Tx,Ty)g

p(x,y),p(y,Ty),p(x,Tx),p(x,Ty),p(y,Tx) , ()

for all x,yX.Then T has a fixed point.

Corollary . Theorem.introduced in[]is a special case of Theorem..

Proof DefinegRbyg(x,x,x,x,x) =kx.

Now we provide the partial metric versions of Theorems . and ..

Theorem . Let(X,p)be a complete partial metric space and T:XCB(X)be a mul-tifunction.Assume that there exists r∈[, )such that

 +rp(x,Tx)p(x,y) implies Hp(Tx,Ty)rp(x,y), ()

for all x,yX.Then T has a fixed point.

Proof DefinegRbyg(x,x,x,x,x) =rx. Letα=+r. Sinceh=randα( +h)≤, by

using Theorem .,Thas a fixed point.

Theorem . Let(X,p)be a complete partial metric space and T:XC(X)be a multi-function.Assume that there exist a,b,c∈[, )such that a+b+c< and

( –bc)

 +a p(x,Tx)p(x,y) implies

Hp(Tx,Ty)ap(x,y) +bp(x,Tx) +cp(y,Ty).

()

Then T has a fixed point.

Proof DefinegRbyg(x,x,x,x,x) =ax+cx+bx. Letα=–+bac. Sinceh=a+b+c

andα( +h)≤, by Theorem .,Thas a fixed point.

Competing interests

The authors declare that they have no competing interests.

Authors’ contributions

All authors contributed equally to this work. All authors read and approved the final manuscript.

Author details

1Department of Mathematics, Qom University of Technology, Qom, Iran.2Department of Mathematics, Atilim University,

˙Incek, 06836, Ankara.3Department of Mathematics, King Abdulaziz University, P.O. Box 80203, Jeddah, 21589, Saudi

Arabia. 4Department of Mathematics, Alzahra University, Tehran, Iran.

Acknowledgements

The authors would like to thank referees for their useful comments and suggestions for the improvement of the paper. The third author gratefully acknowledges the support from the Deanship of Scientific Research (DSR) at King Abdulaziz University (KAU) in Jeddah, Kingdom of Saudi Arabia during this research.

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