DESIGN OF UNBRACED RC COLUMN AND
DESIGN OF UNBRACED RC COLUMN AND PEDESTALPEDESTAL CoCode :de : SS CSS CP 65P 65 S
Sttrruuccttuurree :: CCoolluummnnMMaarrkk ::
1. Design Loads
1. Design Loads Units : kN, kN-mUnits : kN, kN-m
N
Noo.. CCoonnddiittiioonn LLC C ## BBeeaam m ## NN** MMxx MMyy VVxx VVyy Material Strength :Material Strength :
11 MMaax x NN 110022 2222 776655..55 2277..44 5500..44 2277..77 88..55 f f cucu = = 30 Mpa30 Mpa
22 MMiin n NN 224455 1166 --1144..22 113322..11 22..22 44..66 2277..44 f f yy = = 460 Mpa460 Mpa
33 Max MMax Mxx 229911 2222 665533..44 221111..44 00..33 88..66 6611..22 f f yvyv = = 460 Mpa460 Mpa
44 Min MMin Mxx 229922 1155 662211..22 221111..22 88..55 1122..99 6600..55 EEss = = 200000 Mpa200000 Mpa
55 Max MMax Myy 117744 551188 555522..00 1111..22 221155..66 5522..77 33..00
66 Min MMin Myy 116655 552211 553355..88 2277..99 220066..77 4488..44 77..99
* (-) negative signs indicates tension force * (-) negative signs indicates tension force 2. End Condition and Effective Length
2. End Condition and Effective Length (SS CP 65 Part 1 sec. 3.8.1.6)(SS CP 65 Part 1 sec. 3.8.1.6) 12 12 -- T2T200
Column Dimensions : Column Dimensions : Top Bottom Top Bottom b =b = 550 mm550 mm b bxx == 1.21.2 11 11 h =h = 550 mm550 mm b byy == 1.21.2 11 11 c.c. =c.c. = 50 mm50 mm llexex = = bbxx(L(Loxox)=)= 99990000 mmmm lloxox = = 8250 mm8250 mm lleyey== bbyy(L(Loyoy)=)= 99990000 mmmm lloyoy = = 8250 mm8250 mm LLexex/h =/h = 1188 >> 1100 TT1133 @@220000
LLeyey/b =/b = CC22 >> 1100 Design as slender column.Design as slender column.
3. Ultimate Design Moment
3. Ultimate Design Moment Units : kN-m, N/mmUnits : kN-m, N/mm22
No.
No. MMaddxaddx MMaddyaddy MMtxtx MMtyty MMtxtx//hh'' MMtyty//bb'' MMuu MMuu/bh/bh 22 M Muu/hb/hb 22 N/bh N/bh 11 6688..11 6688..11 9955..55 111188..55 220000..33 224488..55 220044..5 5 11..2233 22..5533 22 NNAA NNAA 113322..11 22..22 227766..99 44..66 113344..33 00..881 1 --00..0055 33 5588..11 5588..11 226699..55 5588..44 556655..11 112222..55 332233..33 11..995 5 22..1166 44 5555..33 5555..33 226666..55 6633..88 555588..77 113333..77 332255..22 11..996 6 22..0055 55 4499..11 4499..11 6600..33 226644..77 112266..55 555555..00 332200..8 8 11..9933 11..8822 66 4477..77 4477..77 7755..66 225544..44 115588..55 553333..33 332244..7 7 11..9966 11..7777
Formulas and Conditions for Ultimate Design Moment Calculation Formulas and Conditions for Ultimate Design Moment Calculation Addition
Additional Momenal Moment (SS CP t (SS CP 65 Part 65 Part 1 sec. 3.81 sec. 3.8.3).3) Addition
Additional and al and Maximum MoMaximum Moment abment about X-aout X-axisxis Additional and Additional and Maximum MoMaximum Moment abment about Y-aout Y-axisxis
kkxx== 1.01.0 eeminyminy = 20 mm = 20 mm kkyy== 1.01.0 eeminxminx = 20 mm = 20 mm
b baxax = = (l(lexex/b" )/b" ) 22 / 2000 / 2000 bbayay = = (l(leyey/b" )/b" ) 22 / 2000
/ 2000 where : h' =where : h' = effective depth along Yeffective depth along Y
== 00..116622 == 00..116622 == 44777 7 mmmm
aauxux = = b baxaxkkxxh =h = 0.0890.089 aauyuy = = b bayaykkyyb =b = 0.0890.089 b' = Xeffective b' =Xeffective depth depth along along YY
M
Maddxaddx = Na= Nauxux MMaddyaddy == NaNauyuy == 44777 7 mmmm
M
Mminxminx = Ne= Neminxminx MMminyminy = = NeNeminyminy b"= b"= least least column column dimensiondimension
M
Mtxtx = = MMxx + M + Maddxaddx > M> Mminxminx MMtyty = = MMyy + M + Maddyaddy > M> Mminyminy == 55550 0 mmmm
Ultimate Design Moment for Biaxial Bending (Increase Moment about One Axis)
Ultimate Design Moment for Biaxial Bending (Increase Moment about One Axis) (SS CP 65 Part 1 (SS CP 65 Part 1 sec. 3.8.4.5)sec. 3.8.4.5) when M
when Mtxtx/h' > M/h' > Mtyty/b' ,/b' , MMuu= M= Mtxtx + ( + (bbh'Mh'Mtyty) / b') / b'
when M
when Mtxtx/h' < M/h' < Mtyty/b' ,/b' , MMuu = M = Mtyty + ( + (bbb'Mb'Mtxtx) / h') / h' where :where : ß = 1 - 7/6 N / bh f ß = 1 - 7/6 N / bh f cucu > 0.3 > 0.3
4. Arrangement of Reinforcement 4. Arrangement of Reinforcement Longitudinal Reinforcement
Longitudinal Reinforcement
number of bar bar parallel to
number of bar bar parallel to Y axis at one side Y axis at one side nnyy = = 44 , , ssppaacciinng g == 113344..77 mmm m <<== 115500..00
number of bar bar parallel to X at one side axis n
number of bar bar parallel to X at one side axis nxx = = 44 , , ssppaacciinng g == 113344..77 mmm m <<== 115500..00
P
Prroovviidde e :: 112 -2 - T20T20 A Asc,minsc,min== < < Asc Asc OK OK
A
Ascsc == 3,768.03,768.0 mmmm22 AAscsc/bh =/bh = 1.251.25 %%
Links Provided :
Links Provided : T13T13 @200 mm@200 mm no. of legs of links parallel to the Y axis =no. of legs of links parallel to the Y axis = 22
no. of legs of links parallel to the X axis =
no. of legs of links parallel to the X axis = 22
M
Miinniimmuum Dm Diiaammeetteer or of Lf Liinnkks :s : 6 m6 mmm ssaattiissffiieedd Area of links para Area of links parallel to Y llel to Y axis Aaxis Asvhsvh = = 265.5265.5 mmmm 22
Ma
Maxiximumum Sm Spapacicing ng of of LiLinknks :s : 24240 m0 mmm satitisfsa sfieiedd Area of Area of links paralinks parallel to X llel to X axis Aaxis Asvbsvb = = 265.5265.5 mmmm
Table 3.22 Table 3.22 1,210.0 mm² 1,210.0 mm² xx yy hh bb
5. Capacity Analysis for N/bh - Mu /bh 2 h' / h= 0.87 Capacity Check No. N/bh Mu/bh 2 Remarks 1 0 0 2 0 0 3 2.16 1.95 OK 4 2.06 1.96 OK 5 0 0 6 0 0 -10.00 -5.00 0.00 5.00 10.00 15.00 20.00 0.000 0.500 1.000 1.500 2.000 2.500 3.000 3.500 4.000 N / b h ( M p a ) Mu/bh2 (Mpa)
INTERACTION CURVE N/bh - M
ubh
2 CURVE LOAD6. Capacity Analysis for N/bh - Mu /hb 2 b' / b= 0.87 Capacity Check No. N/bh Mu/hb2 Remarks 1 2.54 1.23 OK 2 0 0 3 0 0 4 0 0 5 1.83 1.93 OK 6 1.78 1.96 OK -10.00 -5.00 0.00 5.00 10.00 15.00 20.00 0.000 0.500 1.000 1.500 2.000 2.500 3.000 3.500 4.000 N / b h ( M p a ) Mu/hb2 (Mpa)
INTERACTION CURVE N/bh - M
uhb
2 CURVE LOAD7. Check Of Shear Stress (sec. 3.8.4.6 SS CP65 Part 1)
Actual Concrete Shear Stress Units : m , N/mm
No. Mx/N Remarks My/N Remarks Vx / hb' Vy / bh'
1 0.036 > 0.06h 0.066 > 0.06b 0.11 0.03 2 9.290 > 0.06h 0.155 > 0.06b 0.02 0.10 3 0.324 > 0.06h 0.000 > 0.06b 0.03 0.23 4 0.340 > 0.06h 0.014 > 0.06b 0.05 0.23 5 0.020 < 0.06h 0.300 < 0.06b 0.20 0.01 6 0.052 > 0.06h 0.300 > 0.06b 0.18 0.03 where : 0.6h = 0.033 m 0.6b = 0.033 m
Design Concrete Shear Stress (Table 3.9 of SS CP65 Part 1) vcy = 0.84(100Asy/bh') 1/3 (400/h')1/4/ γm (f cu/30) 1/2 = 0.53 N/mm2; <= vmax vcx = 0.84(100Asx/bh') 1/3 (400/b')1/4/ γm (f cu/30) 1/2 = 0.53 N/mm2; <= vmax vmax = 4.4 Mpa
Condition : if Mx/N < 0.06h, My/N < 0.06b, Vx/hb' < vcx, and Vy/bh' < vcY', Shear Check is not required
Modification of the design concrete shear stress: Sec 3.4.5.12 of SS CP65 Part 1) Units : N/mm2
No. vyh/Mx vxb/My v'cy v'cx 1 0.17 0.3 0.79 0.99 2 0.11 1 0.51 0.5 3 0.16 1 0.74 1.19 4 0.16 0.83 0.73 1.17 5 0.15 0.13 0.69 0.67 6 0.16 0.13 0.70 0.67
where : v'cy = vcy + 0.6NVyh' / (Mx Ac) <= vcy [1 + N/(Acvcy)] 0.5
v'cx = vcx + 0.6NVxb' / (My Ac) <= vcx [1 + N/(Acvcx)] 0.5
vcx = Vx/hb'
vcy = Vy/bh'
condition : if (vx/v'cx) + (vy/v'cy) < 1.0, provided minimum reinforcement
Design of shear reinforcement Unit : N/mm2, kN
No. v"cy V'cy Vsy Vy - V'cy Remarks v"cx V'cx Vsx Vx - V'cx Remarks
1 0.19 49.85 292.2 -41.35 OK 0.76 199.386 292.16 -171.69 OK 2 0.44 115.43 292.2 -88.03 OK 0.07 18.3645 292.16 -13.76 OK 3 0.65 170.53 292.2 -109.33 OK 0.15 39.3525 292.16 -30.75 OK 4 0.60 157.41 292.2 -96.91 OK 0.21 55.0935 292.16 -42.19 OK 5 0.04 10.49 292.2 -7.49 OK 0.63 165.2805 292.16 -112.58 OK 6 0.10 26.24 292.2 -18.34 OK 0.58 152.163 292.16 -103.76 OK Where : v''cx = v'cxvx / (vx + vy) v''cy = v'cyvy / (vx + vy) V'cx = v''cxbh' V'cy = v''cyhb' Vsx = 0.87f yv Asvbh / S Vsy = 0.87f yv Asvhb / S
Condition : if Vsy > Vy-V'cyand Vsx > Vx-V'cx, OK (shear reinforcement is adequate)
Condition : if Vsy < Vy-V'cyand Vsx < Vx-V'cx, NG (shear reinforcement is not adequate)
0.34 0.36 0.32 0.32 Remarks < 1.0 ,provide minimum. < 1.0 ,provide minimum. < 1.0 ,provide minimum. < 1.0 ,provide minimum. (vx/v'cx) + (vy/v'cy) 0.15 0.24 < 1.0 ,provide minimum. < 1.0 ,provide minimum. Remarks shear check is required shear check is required shear check is required shear check is required shear check is required shear check is required
8. Biaxial Bending and Tension
Assuming that the lever arm to resist bending moment about each axis is the distance between the center of steel reinforcement on each face.
ax = 404 mm, distance of center of steel reinforcement parallel at X axis
ay = 404 mm, distance of center of steel reinforcement parallel at Y axis
Unit : mm2
No. Astx, required Astx, provided Remarks Asty, required Asty, provided Remarks Ast, required Ascor, required Ascor, provided Remarks
1 0 1256 OK 0 1256 OK 0 0 314 notension 2 817 1256 OK 14 1256 OK 36 217 314 OK 3 0 1256 OK 0 1256 OK 0 0 314 notension 4 0 1256 OK 0 1256 OK 0 0 314 notension 5 0 1256 OK 0 1256 OK 0 0 314 notension 6 0 1256 OK 0 1256 OK 0 0 314 notension where :
Area of bars required on each face parallel to the x-axis: Astx,required = Mx / [ (f yax / 1.15) ]
Area of bars required on each face parallel to the y-axis: Asty,required = My / [ (f yay / 1.15) ]
Area of steel required for tension: Ast,required = N / (f y / 1.15)
Area of bars provided on each face parallel to the x-axis: Astx,provided
Area of bars provided on each face parallel to the y-axis: Asty,provided
Required area for one corner bar : Ascor, required
= Astx,required / nx + Asty,required / ny + Ast,required / 4 Area of bar provided for one corner bar : Ascor, provided