1 1
DOCUMENT NO. : OMPL-DC-204 30-Apr-15
COVER PAGE CHKD. APPD.
SNS CP
P.O. NO. : 4608183-000/7.12.050/I06
CUSTOMER : AIR LIQUIDE GODREJ
EQUIPMENT :
JOB NO. : V-505
MFR'S SERIAL NO. : 001345
TOTAL PAGES : 11
(INCL. THIS PAGE)
MECHANICAL DESIGN CALCULATIONS
FOR
RECTANGULAR TANK FOR DIRECT COOILNG WATER
Tag No.: 105F06
DOCUMENT NO. : OMPL-DC-204
REVISION NO. OF THIS SHEET INDICATES REVISION NO. OF ENTIRE DOCUMENT
1 30-Apr-15 ISSUE FOR APPROVAL SNS CP
0 18-Mar-15 ISSUE FOR APPROVAL SNS CP
REV. DATE CONTENT CHKD APPD
ORIENTAL MANUFACTURERS
RECTANGULAR TANK FOR DIRECT COOILNG WATER
RECTANGULAR TANK CALCULATION SHEET FOR TAG 104F04
I. DESIGN PARAMETERS:
- Code Design : API 650 & Roark's Formulas
- Design pressure 2169.5 (Annexure-1)
= 21.28 kPa
- Design temperature : 100
- Operating pressure : ATM
- Operating temperature : 50
- Corrosion Allowance C.A : 0mm
- Liquid Specific Gravity : 1.00
- Joint Efficiency : 0.85 (For Shell)
: 1.00 (For Roof & Bottom)
- Elastic Modulus E :2.74*E+7 psi
= 188916350 kPa
MATERIAL SPECIFICATION: :
- Shell, Roof & Bottom : SS 304L
- Allowable Stress 16700.1psi
= 115143 kPa
- Allowable Bending Stress 11022.066 psi
= 75994.47 kPa
- Nozzle Neck : A 182 F 304L
- Flange : A 182 F 304L
- Pipe Fittings : A 312 TP 304L
- Bolts & Nuts : A 193 Gr B7 / A 194 Gr. 2H
- Stiffeners : SS 304L TANK GEOMETRY: - Height H : 1500mm - Length L : 1600mm - Width W : 1400mm Pd : kg/m2 oC oC Sa : Sb : Width (W) H ei gh t (H )
II. DESIGN
II.1 Side Wall Plate Calculation (Height x Length) II.1.1 Wall Thickness Calculation
(As per Roark's Formulas 7Th Ed, Table 11.4 Case 1a)
Vertical length without reinforced a : 500 mm Horizontal length without reinforced b : 533 mm
Ratio, a/b : 0.94
α = 0.0444
β = 0.2874
Required thickness (Formula No.-3 of Ch. 13 -Design Of Rectangular Tank)
= 4.78 mm
Adopted thickness 6.00 mm
Maximum deflection (Formula No.-4 of Ch. 13 -Design Of Rectangular Tank)
= 1.87 mm
<
1.87mm < 3mm
Therefore, adopted thickness is satisfactory II.1.2 Top Edge Stiffener
Ref: Formula No.-12 & 14 of Ch. 13 -Design Of Rectangular Tank
= 0.32 kN/m
= 3.40 kN/m
= 118.64
= 0.0119
Moment inertia of used stiffener (angle 50x50x6):
= 12.8
Therefore, Top edge stiffener is satisfactory II.1.3 Horizontal Stiffener
= 1265.55
= 0.1266
Moment inertia of used stiffener (angle 50x50x6):
= 12.8
Therefore, Horizontal stiffener is satisfactory
tr = Sqrt(β*Pd*b2)/S b) + C.A ta : Ymax = α*Pd*b 4/(E*t a 3)
Ymax 1/2 ta (Last para. Of Design Procedure w/o stiffner, Ch. 13 -Design Of Rectangular Tank)
R1 = 0.03*Pd*a R2 = 0.32*Pd*a
Moment inertia required: (Ref: Formula No.-9 of Ch. 13 -Design Of Rectangular Tank ) Jmin = R1*b
4/(192*E*t
a) mm4
cm4
Jx = Jy cm4
Moment inertia required: (Ref: Formula No.-9 of Ch. 13 -Design Of Rectangular Tank ) Jmin = R2*b4/(192*E*t a) mm4 cm4 Jx = Jy cm4 H ei gh t (H ) a b Length (L) a b Stiffeners a b a b
II.1.4 Vertical Stiffener
288.70 mm
= 0.06 kNm
Required section modulus:
= 5.27E-07
= 0.53
Section modulus of used stiffener (angle 50x50x6):
Z = 3.61
Therefore, Vertical stiffener is satisfactory II.2 Side Wall Plate Calculation (Height x Width) II.2.1 Wall Thickness Calculation
(As per Roark's Formulas 7Th Ed, Table 11.4 Case 1a)
Vertical length without reinforced a : 750 mm Horizontal length without reinforced b : 467 mm
Ratio, a/b : 1.61
α = 0.0906
β = 0.5172
Required thickness (Formula No.-3 of Ch. 13 -Design Of Rectangular Tank)
= 5.62 mm
Adopted thickness 6.00 mm
Maximum deflection (Formula No.-4 of Ch. 13 -Design Of Rectangular Tank)
= 2.24 mm
<
2.24mm < 3mm
Therefore, adopted thickness is satisfactory II.2.2 Top Edge Stiffener
Ref: Formula No.-12 & 14 of Ch. 13 -Design Of Rectangular Tank
= 0.48 kN/m
= 5.11 kN/m
Moment inertia required: (Ref: Formula No.-9 of Ch. 13 -Design Of Rectangular Tank )
= 104.32
= 0.0104
Moment inertia of used stiffener (angle 50x50x6):
= 12.8
Therefore, Top edge stiffener is satisfactory
Maximum bending moment at Hy = 0.5774*amax = (Pg. 272 Adding vertical stiffner - Dist. For maxmium bending moment)
Maximum bending moment: (Ref: Formula No.-16 of Ch. 13 -Design Of Rectangular Tank ) Mmax = 0.0642*Pd*b*Hy2 Zr = Mmax/Sa mm3 cm3 cm3 tr = Sqrt(β*Pd*b2)/S b) + C.A ta : Ymax = α*Pd*b4/(E*ta3)
Ymax 1/2 ta (Last para. Of Design Procedure w/o stiffner, Ch. 13 -Design Of Rectangular Tank)
R1 = 0.03*Pd*a R2 = 0.32*Pd*a Jmin = R1*b4/(192*E*t a) mm4 cm4 Jx = Jy cm4 H ei gh t (H ) a b a b Stiffeners a b a b Width (W)
II.2.3 Horizontal Stiffener
Moment inertia required: (Ref: Formula No.-9 of Ch. 13 -Design Of Rectangular Tank )
= 1112.76
= 0.1113
Moment inertia of used stiffener (angle 50x50x6):
= 12.8
Therefore, Horizontal stiffener is satisfactory II.2.4 Vertical Stiffener
432.98 mm
= 0.12 kNm
Required section modulus:
= 1.04E-06
= 1.04
Section modulus of used stiffener (angle 50x50x6):
Z = 3.61
Therefore, Vertical stiffener is satisfactory II.3 Roof Plate Calculation
Loads on roof plate:
- Roof area: = 2.24
- Live load: = 1.5 kPa
- Roof weight: = 156 kg
- Roof structure weight: = 100 kg
- Roof Equipment weight: = 100 kg
- Dead load: = 1.6 kPa
Total load on roof plate: = 3.1 kPa
Distance without reinforced in width a : 700 mm Distance without reinforced in length b : 533.333333 mm
Ratio, a/b : 1.31
α = 0.0703
β = 0.4194
Required thickness: (Formula No.-3 of Ch. 13 -Design Of Rectangular Tank)
= 2.19 mm
Adopted thickness 6.00 mm
Maximum deflection: (Formula No.-4 of Ch. 13 -Design Of Rectangular Tank)
= 0.43 mm
<
0.43mm < 3mm
Therefore, adopted thickness is satisfactory
Jmin = R2*b4/(192*E*ta) mm4
cm4
Jx = Jy cm4
Maximum bending moment at Hy = 0.5773*amax = (Pg. 272 Adding vertical stiffner - Dist. For maxmium
bending moment)
Maximum bending moment:(Ref: Formula No.-16 of Ch. 13 -Design Of Rectangular Tank ) Mmax = 0.0641*Pd*b*Hy2 Zr = Mmax/Sa m3 cm3 cm3 m2 tr = Sqrt(β*Pd*b2)/Sb) + C.A ta : Ymax = α*Pd*b 4/(E*t a 3)
Ymax 1/2 ta (Last para. Of Design Procedure w/o stiffner, Ch. 13 -Design Of Rectangular Tank)
Stiffeners W id th ( W ) Length (L) a a b b
II.4 Bottom Plate Calculation
Distance without reinforced in width a : 700.000 mm Distance without reinforced in length b : 533.333 mm
Ratio, a/b : 1.31 α = 0.0703 β = 0.4194 Required thickness: = 5.78 mm Adopted thickness 6.00 mm
Maximum deflection: (Formula No.-4 of Ch. 13 -Design Of Rectangular Tank)
= 2.96 mm
<
2.96mm < 3mm
Therefore, adopted thickness is satisfactory
tr = Sqrt(β*Pd*b2)/Sb) + C.A
ta :
Ymax = α*Pd*b4/(E*ta3)
Ymax 1/2 ta (Last para. Of Design Procedure w/o stiffner, Ch. 13
-Design Of Rectangular Tank)
a b a b Stiffeners a b a b W id th ( W ) Length (L)
RECTANGULAR TANK CALCULATION SHEET
I. DESIGN PARAMETERS:
- Code Design : API 650 & Roark's Formulas - Design pressure Full water + 5 kPag
= 16.77 kPa - Design temperature : 10 - Operating pressure : ATM - Operating temperature : 50 - Corrosion Allowance C.A : 0 mm - Liquid Specific Gravity : 0.99
- Joint Efficiency : 0.85 (For Shell)
: 1.00 (For Roof & Bottom) - Elastic Modulus E : 2.74*E+7 psi
= 199947962 kPa
retangular MATERIAL SPECIFICATION: :
- Shell, Roof & Bottom : SS 316L
- Allowable Stress 16700.1 psi = 115143 kPa - Nozzle Neck : A 182 F 316L - Flange : A 182 F 316L - Pipe Fittings : A 312 TP 316L
- Bolts & Nuts : A 193 Gr B7 / A 194 Gr 2 - Stiffeners : SS 316L TANK GEOMETRY: - Height H : 1200 mm - Length L : 1100 mm - Width W : 1000 mm Pd : oC / AMB oC Sa : Width (W) H ei gh t (H )
II. DESIGN
II.1 Side Wall Plate Calculation (Height x Length) II.1.1 Wall Thickness Calculation
(As per Roark's Formulas 7Th Ed, Table 11.4 Case 1a)
Vertical length without reinforced a : 600 mm Horizontal length without reinforced b : 550 mm
Ratio, a/b : 1.09 α = 0.0522 β = 0.3278 Required thickness = 3.80 mm Adopted thickness 6.00 mm Maximum deflection = 1.86 mm < 1.86mm < 3mm
Therefore, adopted thickness is satisfactory
II.1.2 Top Edge Stiffener
= 0.30 kN/m = 3.22 kN/m Moment inertia required:
= 119.93 = 0.0120 Moment inertia of used stiffener (angle 50x50x8):
= 16.3
Therefore, Top edge stiffener is satisfactory
II.1.3 Horizontal Stiffener
Moment inertia required:
= 1279.29 = 0.1279 Moment inertia of used stiffener (angle 50x50x8):
= 16.3
Therefore, Horizontal stiffener is satisfactory
tr = Sqrt(β*Pd*b2)/S a) + C.A ta : Ymax = α*Pd*b4/(E*t a3) Ymax 1/2 ta R1 = 0.03*Pd*a R2 = 0.32*Pd*a Jmin = R1*b4/(192*E*t a) mm4 cm4 Jx = Jy cm4 Jmin = R2*b4/(192*E*t a) mm4 cm4 Jx = Jy cm4 H ei gh t (H ) a b Length (L) a b Stiffeners a b a b
II.1.4 Vertical Stiffener
346.38 mm Maximum bending moment:
= 0.07 kNm Required section modulus:
= 6.16E-07 = 0.62 Section modulus of used stiffener (angle 50x50x8):
Z = 4.68
Therefore, Vertical stiffener is satisfactory
II.2 Side Wall Plate Calculation (Height x Width) II.2.1 Wall Thickness Calculation
(As per Roark's Formulas 7Th Ed, Table 11.4 Case 1a)
Vertical length without reinforced a : 600 mm Horizontal length without reinforced b : 500 mm
Ratio, a/b : 1.20 α = 0.062 β = 0.376 Required thickness = 3.70 mm Adopted thickness 6.00 mm Maximum deflection = 1.50 mm < 1.5mm < 3mm
Therefore, adopted thickness is satisfactory
II.2.2 Top Edge Stiffener
= 0.30 kN/m = 3.22 kN/m Moment inertia required:
= 81.92 = 0.0082 Moment inertia of used stiffener (angle 50x50x8):
= 16.3
Therefore, Top edge stiffener is satisfactory
Maximum bending moment at Hy = 0.5773*amax =
Mmax = 0.0641*Pd*b*Hy2 Zr = Mmax/Sa mm3 cm3 cm3 tr = Sqrt(β*Pd*b2)/S a) + C.A ta : Ymax = α*Pd*b4/(E*t a3) Ymax 1/2 ta R1 = 0.03*Pd*a R2 = 0.32*Pd*a Jmin = R1*b4/(192*E*t a) mm4 cm4 Jx = Jy cm4 H ei gh t (H ) a b a b Stiffeners a b a b Width (W)
II.2.3 Horizontal Stiffener
Moment inertia required:
= 873.77 = 0.0874 Moment inertia of used stiffener (angle 50x50x8):
= 16.3
Therefore, Horizontal stiffener is satisfactory
II.2.4 Vertical Stiffener
346.38 mm Maximum bending moment:
= 0.06 kNm Required section modulus:
= 5.60E-07 = 0.56 Section modulus of used stiffener (angle 50x50x8):
Z = 4.68
Therefore, Vertical stiffener is satisfactory
II.3 Roof Plate Calculation
Loads on roof plate:
- Roof area: = 1.1
- Live load: = 1.5 kPa Assumed - Roof weight: = 102 kg
- Roof structure weight: = 100 kg Assumed - Roof Equipment weight: = 100 kg Assumed - Dead load: = 2.7 kPa
Total load on roof plate: = 4.2 kPa Distance without reinforced in width a : 500 mm Distance without reinforced in length b : 550 mm
Ratio, a/b : 0.91 α = 0.0444 β = 0.2874 Required thickness: = 1.78 mm Adopted thickness 6.00 mm Maximum deflection: = 0.39 mm Jmin = R2*b4/(192*E*t a) mm4 cm4 Jx = Jy cm4
Maximum bending moment at Hy = 0.5773*amax =
Mmax = 0.0641*Pd*b*Hy2 Zr = Mmax/Sa mm3 cm3 cm3 m2 tr = Sqrt(β*Pd*b2)/S a) + C.A ta : Ymax = α*Pd*b4/(E*t a3) Stiffeners W id th ( W ) Length (L) a a b b
<
0.39mm < 3mm
Therefore, adopted thickness is satisfactory
II.4 Bottom Plate Calculation
Distance without reinforced in width a : 500 mm Distance without reinforced in length b : 550 mm
Ratio, a/b : 0.91 α = 0.0444 β = 0.2874 Required thickness: = 3.56 mm Adopted thickness 6.00 mm Maximum deflection: = 1.58 mm < 1.58mm < 3mm
Therefore, adopted thickness is satisfactory
tr = Sqrt(β*Pd*b2)/S a) + C.A ta : Ymax = α*Pd*b4/(E*t a3) Ymax 1/2 ta a b a b Stiffeners a b a b W id th ( W ) Length (L)
TANK CALCULATION SHEET
I. DESIGN PARAMETERS:
- Code Design : API 650 & Roark's Formulas - Design pressure Full water + 5 kPag
= 24.62 kPa - Design temperature : 60 - Operating pressure : ATM - Operating temperature : 27 - Corrosion Allowance C.A : 0 mm - Liquid Specific Gravity : 1.00
- Joint Efficiency : 0.85 (For Shell)
: 1.00 (For Roof & Bottom) - Elastic Modulus E : 2.9*E+7 psi
= 199947962 kPa
retangular MATERIAL SPECIFICATION: :
- Shell, Roof & Bottom : SS 316L
- Allowable Stress 16700 psi = 115142 kPa - Nozzle Neck : A 182 F 316L - Flange : A 182 F 316L - Pipe Fittings : A 312 TP 316L
- Bolts & Nuts : A 193 Gr B8M / A 194 Gr 8M - Stiffeners : SS 316L TANK GEOMETRY: - Height H : 2000 mm - Length L : 5700 mm - Width W : 1250 mm Pd : oC / AMB oC Sa : Width (W) H ei gh t (H )
II. DESIGN
II.1 Side Wall Plate Calculation (Height x Length) II.1.1 Wall Thickness Calculation
(As per Roark's Formulas 7Th Ed, Table 11.4 Case 1a)
Vertical length without reinforced a : 667 mm Horizontal length without reinforced b : 633 mm
Ratio, a/b : 1.05 α = 0.0487 β = 0.3096 Required thickness = 5.15 mm Adopted thickness 8.00 mm Maximum deflection = 1.88 mm < 1.88mm < 4mm
Therefore, adopted thickness is satisfactory
II.1.2 Top Edge Stiffener
= 0.49 kN/m = 5.25 kN/m Moment inertia required:
= 257.95 = 0.0258 Moment inertia of used stiffener (angle 65x65x6):
= 29.4
Therefore, Top edge stiffener is satisfactory
II.1.3 Horizontal Stiffener
Moment inertia required:
= 2751.49 = 0.2751 Moment inertia of used stiffener (angle 65x65x6):
= 29.4
Therefore, Horizontal stiffener is satisfactory
tr = Sqrt(β*Pd*b2)/S a) + C.A ta : Ymax = α*Pd*b4/(E*t a3) Ymax 1/2 ta R1 = 0.03*Pd*a R2 = 0.32*Pd*a Jmin = R1*b4/(192*E*t a) mm4 cm4 Jx = Jy cm4 Jmin = R2*b4/(192*E*t a) mm4 cm4 Jx = Jy cm4 H ei gh t (H ) a b Length (L) a b Stiffeners a b a b
II.1.4 Vertical Stiffener
384.87 mm Maximum bending moment:
= 0.15 kNm Required section modulus:
= 1.29E-06 = 1.29 Section modulus of used stiffener (angle 65x65x6):
Z = 6.26
Therefore, Vertical stiffener is satisfactory
II.2 Side Wall Plate Calculation (Height x Width) II.2.1 Wall Thickness Calculation
(As per Roark's Formulas 7Th Ed, Table 11.4 Case 1a)
Vertical length without reinforced a : 667 mm Horizontal length without reinforced b : 625 mm
Ratio, a/b : 1.07 α = 0.0504 β = 0.3185 Required thickness = 5.16 mm Adopted thickness 8.00 mm Maximum deflection = 1.85 mm < 1.85mm < 4mm
Therefore, adopted thickness is satisfactory
II.2.2 Top Edge Stiffener
= 0.49 kN/m = 5.25 kN/m Moment inertia required:
= 244.64 = 0.0245 Moment inertia of used stiffener (angle 65x65x6):
= 29.4
Therefore, Top edge stiffener is satisfactory
Maximum bending moment at Hy = 0.5773*amax =
Mmax = 0.0641*Pd*b*Hy2 Zr = Mmax/Sa mm3 cm3 cm3 tr = Sqrt(β*Pd*b2)/S a) + C.A ta : Ymax = α*Pd*b4/(E*t a3) Ymax 1/2 ta R1 = 0.03*Pd*a R2 = 0.32*Pd*a Jmin = R1*b4/(192*E*t a) mm4 cm4 Jx = Jy cm4 H ei gh t (H ) a b a b Stiffeners a b a b Width (W)
II.2.3 Horizontal Stiffener
Moment inertia required:
= 2609.51 = 0.2610 Moment inertia of used stiffener (angle 65x65x6):
= 29.4
Therefore, Horizontal stiffener is satisfactory
II.2.4 Vertical Stiffener
384.87 mm Maximum bending moment:
= 0.15 kNm Required section modulus:
= 1.27E-06 = 1.27 Section modulus of used stiffener (angle 65x65x6):
Z = 6.26
Therefore, Vertical stiffener is satisfactory
II.3 Roof Plate Calculation
Loads on roof plate:
- Roof area: = 7.125 - Live load: = 1.5 kPa - Roof weight: = 386 kg - Roof structure weight: = 116 kg - Roof Equipment weight: = 120 kg - Dead load: = 0.9 kPa Total load on roof plate: = 2.4 kPa Distance without reinforced in width a : 1250 mm Distance without reinforced in length b : 712.5 mm
Ratio, a/b : 1.75 α = 0.0989 β = 0.5559 Required thickness: = 2.40 mm Adopted thickness 6.00 mm Maximum deflection: = 1.39 mm Jmin = R2*b4/(192*E*t a) mm4 cm4 Jx = Jy cm4
Maximum bending moment at Hy = 0.5773*amax =
Mmax = 0.0641*Pd*b*Hy2 Zr = Mmax/Sa mm3 cm3 cm3 m2 tr = Sqrt(β*Pd*b2)/S a) + C.A ta : Ymax = α*Pd*b4/(E*t a3) Stiffeners W id th ( W ) Length (L) a a b b
<
1.39mm < 3mm
Therefore, adopted thickness is satisfactory
II.4 Bottom Plate Calculation
Distance without reinforced in width a : 625 mm Distance without reinforced in length b : 633 mm
Ratio, a/b : 0.99 α = 0.0435 β = 0.283 Required thickness: = 4.93 mm Adopted thickness 8.00 mm Maximum deflection: = 1.68 mm < 1.68mm < 4mm
Therefore, adopted thickness is satisfactory
tr = Sqrt(β*Pd*b2)/S a) + C.A ta : Ymax = α*Pd*b4/(E*t a3) Ymax 1/2 ta a b a b Stiffeners a b a b W id th ( W ) Length (L)
TANK CALCULATION SHEET
I. DESIGN PARAMETERS:
- Code Design : API 650 & Roark's Formulas - Design pressure Full water + 5 kPag
= 24.62 kPa - Design temperature : 60 - Operating pressure : ATM - Operating temperature : 27 - Corrosion Allowance C.A : 0 mm - Liquid Specific Gravity : 1.00
- Joint Efficiency : 0.85 (For Shell)
: 1.00 (For Roof & Bottom) - Elastic Modulus E : 2.9*E+7 psi
= 199947962 kPa
retangular MATERIAL SPECIFICATION: :
- Shell, Roof & Bottom : SS 316L
- Allowable Stress 16700 psi = 115142 kPa - Nozzle Neck : A 182 F 316L - Flange : A 182 F 316L - Pipe Fittings : A 312 TP 316L
- Bolts & Nuts : A 193 Gr B8M / A 194 Gr 8M - Stiffeners : SS 316L TANK GEOMETRY: - Height H : 2000 mm - Length L : 2100 mm - Width W : 1250 mm Pd : oC / AMB oC Sa : Width (W) H ei gh t (H )
II. DESIGN
II.1 Side Wall Plate Calculation (Height x Length) II.1.1 Wall Thickness Calculation
(As per Roark's Formulas 7Th Ed, Table 11.4 Case 1a)
Vertical length without reinforced a : 500.0 mm Horizontal length without reinforced b : 525 mm
Ratio, a/b : 0.95 α = 0.0401 β = 0.2652 Required thickness = 3.95 mm Adopted thickness 6.00 mm Maximum deflection = 1.74 mm < 1.74mm < 3mm
Therefore, adopted thickness is satisfactory
II.1.2 Top Edge Stiffener
= 0.37 kN/m = 3.94 kN/m Moment inertia required:
= 121.80 = 0.0122 Moment inertia of used stiffener (Flat bar 65x6):
= 13.7
Therefore, Top edge stiffener is satisfactory
II.1.3 Horizontal Stiffener
Moment inertia required:
= 1299.20 = 0.1299 Moment inertia of used stiffener (Flat bar 65x6):
= 13.7
Therefore, Horizontal stiffener is satisfactory
tr = Sqrt(β*Pd*b2)/S a) + C.A ta : Ymax = α*Pd*b4/(E*t a3) Ymax 1/2 ta R1 = 0.03*Pd*a R2 = 0.32*Pd*a Jmin = R1*b4/(192*E*t a) mm4 cm4 Jx = Jy cm4 Jmin = R2*b4/(192*E*t a) mm4 cm4 Jx = Jy cm4 H ei gh t (H ) a b Length (L) a b Stiffeners a b a b
II.1.4 Vertical Stiffener
288.65 mm Maximum bending moment:
= 0.07 kNm Required section modulus:
= 6.00E-07 = 0.60 Section modulus of used stiffener (Flat bar 65x6):
Z = 4.2
Therefore, Vertical stiffener is satisfactory
II.2 Side Wall Plate Calculation (Height x Width) II.2.1 Wall Thickness Calculation
(As per Roark's Formulas 7Th Ed, Table 11.4 Case 1a)
Vertical length without reinforced a : 500 mm Horizontal length without reinforced b : 417 mm
Ratio, a/b : 1.20 α = 0.0616 β = 0.3762 Required thickness = 3.74 mm Adopted thickness 6.00 mm Maximum deflection = 1.06 mm < 1.06mm < 3mm
Therefore, adopted thickness is satisfactory
II.2.2 Top Edge Stiffener
= 0.37 kN/m = 3.94 kN/m Moment inertia required:
= 48.32 = 0.0048 Moment inertia of used stiffener (Flat bar 65x6):
Maximum bending moment at Hy = 0.5773*amax =
Mmax = 0.0641*Pd*b*Hy2 Zr = Mmax/Sa mm3 cm3 cm3 tr = Sqrt(β*Pd*b2)/S a) + C.A ta : Ymax = α*Pd*b4/(E*t a3) Ymax 1/2 ta R1 = 0.03*Pd*a R2 = 0.32*Pd*a Jmin = R1*b4/(192*E*t a) mm4 cm4 H ei gh t (H ) a b a b Stiffeners a b a b Width (W)
= 13.7
Therefore, Top edge stiffener is satisfactory
II.2.3 Horizontal Stiffener
Moment inertia required:
= 515.46 = 0.0515 Moment inertia of used stiffener (Flat bar 65x6):
= 13.7
Therefore, Horizontal stiffener is satisfactory
II.2.4 Vertical Stiffener
288.65 mm Maximum bending moment:
= 0.05 kNm Required section modulus:
= 4.76E-07 = 0.48 Section modulus of used stiffener (Flat bar 65x6):
Z = 4.2
Therefore, Vertical stiffener is satisfactory
II.3 Roof Plate Calculation
Loads on roof plate:
- Roof area: = 2.625 - Live load: = 1.5 kPa - Roof weight: = 174 kg - Roof structure weight: = 116 kg - Roof Equipment weight: = 120 kg - Dead load: = 1.5 kPa Total load on roof plate: = 3.0 kPa Distance without reinforced in width a : 1250 mm Distance without reinforced in length b : 700 mm
Ratio, a/b : 1.79 α = 0.1011 β = 0.5662 Required thickness: = 2.70 mm Adopted thickness 6.00 mm Jx = Jy cm4 Jmin = R2*b4/(192*E*t a) mm4 cm4 Jx = Jy cm4
Maximum bending moment at Hy = 0.5773*amax =
Mmax = 0.0641*Pd*b*Hy2 Zr = Mmax/Sa mm3 cm3 cm3 m2 tr = Sqrt(β*Pd*b2)/S a) + C.A ta : Stiffeners W id th ( W ) Length (L) a a b b
Maximum deflection:
= 1.70 mm <
1.7mm < 3mm
Therefore, adopted thickness is satisfactory
II.4 Bottom Plate Calculation
Distance without reinforced in width a : 625 mm Distance without reinforced in length b : 525 mm
Ratio, a/b : 1.19 α = 0.0607 β = 0.3718 Required thickness: = 4.68 mm Adopted thickness 8.00 mm Maximum deflection: = 1.11 mm < 1.11mm < 4mm
Therefore, adopted thickness is satisfactory
Ymax = α*Pd*b4/(E*t a3) Ymax 1/2 ta tr = Sqrt(β*Pd*b2)/S a) + C.A ta : Ymax = α*Pd*b4/(E*t a3) Ymax 1/2 ta a b a b Stiffeners a b a b W id th ( W ) Length (L)
DESIGN CALCULATION SHEET FOR TAG 104F07
Design Calculation For Top Portion Of The Tank
I. Inputs :
1 LENGTH OF RECTANGULAR TANK L 790 mm 2 WIDTH OF RECANGULAR TANK W 790 mm 3 HEIGHT OF RECTANGULAR TANK H 595 mm 4 THICKNESS OF MATERIAL USED t 5 mm 5 CORROSION ALLOWANCE c 0 mm
6 Ws 400 Kg
7 - SA-240 Typ 304L
8 DENSITY OF THE MATERIAL OF TANK ρc 8000 9 DENSITY OF THE OPERATING LIQUID ρw 1000 10 ELASTIC MODULUS OF THE MATERIAL E 19264.00 11 YIELD STRESS OF THE MOC Sy 1757.9 13 ALLOWABLE BENDING STRESS 1160.2
Calculation:
Total Volume of the tank V =
371339500 0.37
Empty weight of the tank with 5 mm thickness We = 275 kg Weight of the liquid in the tank Wl = V x ρw
371 kg Total weight of tank with liquid W = We + Wl + Ws
1074 kg The Analysis of the tank shell will be done in three
parts;-1 Thickness requirement for the top of the tank 2 Thickness requirement for the length of the tank
This thickness analysis would be followed by the check for structural requirement for stiffener. APPROXIMATE WEIGHT OF STRUCTURE
AND AND NOZZLES
MATERAIL OF CONSTRUCTION OF THE TANK kg/m3 kg/m3 kg/mm2 kg/cm2 σb kg/cm2
Rectangular tanks are designed for static head of the liquid. No internal or external pressure is considered. In order to satisfy thickness requireement, external stiffeners are provided so that the tank plates do not buckle under the stress developed due to no liquid head.
L × W × H
mm3
m3
The structural calculation for the adequacy of the structure for lifting of the tank and for operating condition with full liquid along with adequacy check for the lifting lug shall conclude the calculations.
Total vertical load on the bottom plate Wl = 371 kg Total area of the bottom plate Ab = L X W
Ab = 624100 Ab = 0.6241 Hence the load per unit area of the plkate q = Wl/Ab q = 595
0.000595 Divide length in 3 parts and width in 2 parts
The maxmium unstiffened length becomes a = L/2
395 mm The maxmium unstiffened width becomes b = W/2
395 mm Hence the ratio of length to width a/b = 1.000
Interpolating the value for a/b = 1.143 0.308 0.139 α = 0.014
Hence from this value an as per Roark's equation for stress, as per the case mentioned above, -1142982.981
-114.2982981 Induced stress at the centre
σ =
514676.547 51.5
Maximum deflection of the plate Y =
-0.08 mm Considering the allowable deflection as a/324 1.22 mm Since the deflection caused is less than the allowable deflection, design is acceptable.
As per Roark's formula for stress and strain ,Seventh Edition, Table 11.4, Page 508, Case No.8 For a rectangular plate with all edges fixed and load distributed uniformly over the entire plate The base of the tank can be assumed too be a plate with uniform loading.
mm2 m2 kg/m2 kg/mm2 ß1 = ß2 =
Maximum bending stress at the centre of long
edge = -ß1qb 2/t2 kg/m2 kg/cm2 ß2qb2/t2 kg/m2 kg/cm2
Since the induced stress is less then the allowable stress the provided thickness with the stiffener ring arrangment is accepted.
-αqb4/Et3
Where Ps = ρh
h:-height of the element ρ:-density of liquid
Again in the case the length would be divided into 2 parts and height into 2 parts. Thus,the unstiffened length becomes a = L/2
395.00 mm b = H/2
297.5 mm Now for the height, we go as per the following distribution
Bottom Section = 1200
The following value can be tabulated
a/b = 1.33 0.513 0.122 0.082 0.126 0.178 α = 0.011 Maximum bending stress induced at the vertical centre
Maximum bending stress induced at the horizontal centre
Section Bottom -108.01 25.73 -17.33 26.64 -37.59 0.02 mm L /324 1.22 mm
The Maximum stress generated in the plate 108.01 Design allowable stress 1160.2
Provided plates are safe in deflection check.
Since the static pressure increases downwards, more stiffing would be required at the part of the tank. The static pressure along the length is given the relation.
Hence in the case, for a height of 1200mm, the static pressure increses from 0 kg/m2 at top to 1200
kg/m2 at the bottom of the tank.
kg/m2
As per Roark's formula for stress and strain 7th edition table 11.4, case 8d For a rectangular plate fix on all sides with uniformly decreasing load parallel to side plate.
ß1 = ß2 = ß3 = ß4 = ß5 = σb = -ß1qb2/t2 σb = -ß5qb2/t3 -ß1qb2/t2 kg/cm2 ß2qb2/t2 kg/cm2 -ß3qb2/t2 kg/cm2 ß4qb2/t2 kg/cm2 -ß5qb2/t2 kg/cm2 y = αqb4/Et3
σ
max=
kg/cm2σ
b=
kg/cm2Since the induced stress in the plate is less than the allowable, the provided thickness and stiffening is safe.
Design Calculation For Bottom Portion Of The Tank
I. Inputs :
1 LENGTH OF RECTANGULAR TANK L 790 mm 2 WIDTH OF RECANGULAR TANK W 790 mm 3 HEIGHT OF RECTANGULAR TANK H 370 mm 4 THICKNESS OF MATERIAL USED t 5 mm 5 CORROSION ALLOWANCE c 0 mm
6 Ws 300 Kg
7 - SA-240 Typ 304L
8 DENSITY OF THE MATERIAL OF TANK ρc 8000 9 DENSITY OF THE OPERATING LIQUID ρw 1000 10 ELASTIC MODULUS OF THE MATERIAL E 19264.00 11 YIELD STRESS OF THE MOC Sy 1757.9 13 ALLOWABLE BENDING STRESS 1160.2
Calculation:
Total Volume of the tank V =
230917000 0.23
Empty weight of the tank with 5 mm thickness We = 275 kg Weight of the liquid in the tank Wl = V x ρw
231 kg Total weight of tank with liquid W = We + Wl + Ws
833 kg The Analysis of the tank shell will be done in three
parts;-1 Thickness requirement for the top of the tank 2 Thickness requirement for the length of the tank
This thickness analysis would be followed by the check for structural requirement for stiffener. APPROXIMATE WEIGHT OF STRUCTURE
AND AND NOZZLES
MATERAIL OF CONSTRUCTION OF THE TANK kg/m3 kg/m3 kg/mm2 kg/cm2 σb kg/cm2
Rectangular tanks are designed for static head of the liquid. No internal or external pressure is considered. In order to satisfy thickness requireement, external stiffeners are provided so that the tank plates do not buckle under the stress developed due to no liquid head.
L × W × H
mm3
m3
The structural calculation for the adequacy of the structure for lifting of the tank and for operating condition with full liquid along with adequacy check for the lifting lug shall conclude the calculations.
Where Ps = ρh
h:-height of the element ρ:-density of liquid
Again in the case the length would be divided into 2 parts and height into 2 parts. Thus,the unstiffened length becomes a = L/2
395.00 mm b = H/2
370 mm Now for the height, we go as per the following distribution
Bottom Section = 1200
The following value can be tabulated
a/b = 1.07 0.264 0.093 0.076 0.089 0.161 α = 0.008 Maximum bending stress induced at the vertical centre
Maximum bending stress induced at the horizontal centre
Section Bottom -53.54 18.87 -15.32 17.96 -32.67 0.02 mm L /324 1.22 mm
The Maximum stress generated in the plate 53.54 Design allowable stress 1160.2
Provided plates are safe in deflection check.
Since the static pressure increases downwards, more stiffing would be required at the part of the tank. The static pressure along the length is given the relation.
Hence in the case, for a height of 1200mm, the static pressure increses from 0 kg/m2 at top to 395
kg/m2 at the bottom of the tank.
kg/m2
As per Roark's formula for stress and strain 7th edition table 11.4, case 8d For a rectangular plate fix on all sides with uniformly decreasing load parallel to side plate.
ß1 = ß2 = ß3 = ß4 = ß5 = σb = -ß1qb2/t2 σb = -ß5qb2/t3 -ß1qb2/t2 kg/cm2 ß2qb2/t2 kg/cm2 -ß3qb2/t2 kg/cm2 ß4qb2/t2 kg/cm2 -ß5qb2/t2 kg/cm2 y = αqb4/Et3
σ
max=
kg/cm2σ
b=
kg/cm2Since the induced stress in the plate is less than the allowable, the provided thickness and stiffening is safe.
WIND LOAD CALCULATION
As per IS-875 Part3
Basic wind speed for the site
44 m/sec158.4 km/hr
Risk Factor k1 = 1.07
Terrain Fctor k2 = 1.05
Topography Factor k3 = 1
Overall height of vessel H = 1470 mm
Design wind speed
49.4 m/sec
The Effective Wind Pressure
1466.23 The area exposed to the wind along length/width Al =
1.176
Total wind force acting on along length Fl =
1724.29 N `
Total wind force acting on along width Fw =
689.20 N
Hence the maximum of the wind load Pw = Fl
1724.29 N wind moment Mw = 258.4 kg-m Vb = Vz = k1*k2*k3*Vb Pz = 0.6 x Vz2 N/m2 L × H m2 Al * Pz Aw * Pz
SEISMIC LOAD CALCULATION
As per 1893 part 4,2005Total weight of the tank full of liquid W = 1074 kg Seismic zone as specified by the client Z = III
Z = 0.16
Sa/g = 2.5
Importance factor as per Table 2 of IS 1893 I = 1.5
R = 3
Hence the horizontal seismic coefficient Ah =
R/I
Ah = 0.10
The total seismic force acting on the vessel Fs = W × Ah 107.38 kg
Thus the maximum of wind and seismic Fh = max(Pw,Fs)
175.77 kg
CG from the bottom of vessel = 870 mm
The vertical effect of wind/ seismic force F =
= 193.6 kg
= 1898.9 N
Zone Factor as per Annex. A in accordance to Table 2 of IS 1893 Part I
Spectral acceleration coefficient as in Annex. B : (Max)
Response reduction factor as per table 3 of IS 1893
Z/2 × Sa/g
Fh × (CG distance from bottom/ distance between support)
ANCHOR CHAIR CALCULATION
Anchor Gusset(Pressure Vessel Book, By Bednar)
No. Of Gusset N = 2
Load On Each Gusset f = 949.45 N
Height Of the Gusset h = 400 mm
Width Of The Gusset d = 350 mm
Distance Between Gusset b = 175 mm
Gusset Angle α = 51 degree
Dimesion a of base plate a = 235 mm
Force bearing width of base plate 100 mm (Client to confirm) MOC of Gusset IS 2062 Gr. B
Yield Stress
Allowable compressive stress
Yield Stress Sy = 240 MPa
Sa = 108 MPa
MOC of Base plate IS 2062 Gr. B
Yield Stress Fy =
240 MPa 34809.12 Psi fc = 1450.38 Psi10 MPa
Provided Bottom Plate Thickness t = 16 mm
Corroded Bottom Plate Thickness tc = 16 mm
Required Gusset Thickness =
0.56 mm
Hence the Provided thickness is Sufficient.
when b/d = 0.5
Therefore ß = 0.12 (From Roark's formula table 11.4 case no. 7d) Uniform load
q = 0.081F/db Max. stress to base plate (S) : =
4.64
Therefore the provided base plate is safe Allowanle Compressive Strength = 0.45 x Sy
Compressive Strength of the structure (Client To Confirm)
f(3d-b) / (Sa*b^2 × sina^2)
Since the base plate has to accommodate one or more anchor bolt therefore we are analyzing the base plate as a uniformly loaded rectangular plate with one edge free and three supported.
N/mm2 ßqb2/tc2
N/mm2 Which is less than allowable compressive stress 108 N/mm2