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doi:10.1155/2010/971540

Research Article

Existence and Uniqueness of Positive Solutions for

Discrete Fourth-Order Lidstone Problem with

a Parameter

Yanbin Sang,

1, 2

Zhongli Wei,

2, 3

and Wei Dong

4

1Department of Mathematics, North University of China, Taiyuan, Shanxi 030051, China 2School of Mathematics, Shandong University, Jinan, Shandong 250100, China

3Department of Mathematics, Shandong Jianzhu University, Jinan, Shandong 250101, China 4Department of Mathematics, Hebei University of Engineering, Handan, Hebei 056021, China

Correspondence should be addressed to Yanbin Sang,[email protected] Received 9 January 2010; Revised 23 March 2010; Accepted 26 March 2010 Academic Editor: A. Pankov

Copyrightq2010 Yanbin Sang et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

This work presents sufficient conditions for the existence and uniqueness of positive solutions for a discrete fourth-order beam equation under Lidstone boundary conditions with a parameter; the iterative sequences yielding approximate solutions are also given. The main tool used is monotone iterative technique.

1. Introduction

In this paper, we are interested in the existence, uniqueness, and iteration of positive solutions for the following nonlinear discrete fourth-order beam equation under Lidstone boundary conditions with explicit parameterβgiven by

Δ4yt2βΔ2yt1 htf 1

ytf2

yt, ta1, b−1Z, 1.1

ya 0 Δ2ya−1, yb 0 Δ2yb−1, 1.2

whereΔis the usual forward difference operator given byΔyt yt1−ytnyt

Δn−1Δyt, c, d

Z:{c, c1, . . . , d−1, d}, andβ >0 is a real parameter.

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1–7and references therein. Especially, there was much attention focused on the existence and multiplicity of positive solutions of fourth-order problem, for example, 8–10, and in particular the discrete problem with Lidstone boundary conditions 11–17. However, very little work has been done on the uniqueness and iteration of positive solutions of discrete fourth-order equation under Lidstone boundary conditions. We would like to mention some results of Anderson and Minh ´os 11and He and Su 12, which motivated us to consider the BVP1.1and1.2.

In 11, Anderson and Minh ´os studied the following nonlinear discrete fourth-order equation with explicit parametersβandλgiven by

Δ4yt2βΔ2yt1 λft, yt, t a1, b1

Z, 1.3

with Lidstone boundary conditions1.2, whereβ > 0 andλ > 0 are real parameters. The authors obtained the following result.

Theorem 1.1see 11. Assume that the following condition is satisfied

A1ft, y gtwy, where g : a1, b−1Z → 0,with bza11gz > 0,w :

0,∞ → 0,is continuous and nondecreasing, and there existsθ ∈ 0,1such that

wκyκθwyforκ∈0,1andy∈ 0,,

then, for anyλ∈0,, the BVP1.3and1.2has a unique positive solutionyλ. Furthermore,

such a solutionyλsatisfies the following properties:

ilimλ→0yλ0andlimλ→ ∞yλ; iiyλis nondecreasing inλ;

iiiyλis continuous inλ, that is, ifλλ0, thenyλ0 → 0.

Very recently, in 12, He and Su investigated the existence, multiplicity, and nonexistence of nontrivial solutions to the following discrete nonlinear fourth-order boundary value problem

Δ4ut2 ηΔ2ut1ξut λft, ut, tZ a1, b1,

ua 0 Δ2ua−1, ub2 0 Δ2ub1,

1.4

whereΔdenotes the forward difference operator defined byΔut ut1−utnut

ΔΔn−1ut,Z a1, b1is the discrete interval given by{a1, a2, . . . , b1}withaand

ba < bintegers,η, ξ, λare real parameters and satisfy

η <8 sin2 π

2ba2, η

24ξ0, ξ4ηsin2 π

2ba2 <16 sin

4 π

2ba2, λ >0.

1.5

For the functionf, the authors imposed the following assumption:

B1ft, x gthx, where g : Z a1, b1 → 0,∞ with b1

ta1gt > 0, h : R → 0,∞is continuous and nondecreasing, and there existsθ ∈0,1such that

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Their main result is the following theorem.

Theorem 1.2see 12. Assume thatB1holds. Then for anyλ ∈ 0,, the BVP1.4has a

unique positive solutionuλ. Furthermore, such a solutionuλsatisfies the properties (i)–(iii) stated in

Theorem 1.1.

The aim of this work is to relax the assumptionsA1andB1on the nonlinear term,

without demanding the existence of upper and lower solutions, we present conditions for the BVP1.1and1.2to have a unique solution and then study the convergence of the iterative sequence. The ideas come from Zhai et al. 18,19and Liang 20.

Let Bdenote the Banach space of real-valued functions on a−1, b1Z, with the supremum norm

y sup

ta−1,b1Z

yt. 1.6

Throughout this paper, we need the following hypotheses:

H1fi: 0,∞ → 0,∞are continuous andfiy>0 fory >0i1,2;

H2h: a1, b−1Z → 0,∞withbza11hz>0;

H3f1 : 0,∞ → 0,∞is nondecreasing,f2 : 0,∞ → 0,∞is nonincreasing,

and there existϕτ, ψτon interval a1, b−1Zwithϕ: a1, b−1Z → 0,1, for alle0∈0,1, there existsτ0∈ a1, b−1Zsuch thatϕτ0 e0, andψτ> ϕτ,for

allτa1, b−1Zwhich satisfy

f1

ϕτyψτf1

y, f2

1

ϕτy

ψτf2

y,τa1, b−1Z, y≥0. 1.7

2. Two Lemmas

To prove the main results in this paper, we will employ two lemmas. These lemmas are based on the linear discrete fourth-order equation

Δ4yt2βΔ2yt1 ut, t a1, b1

Z, 2.1

with Lidstone boundary conditions1.2.

Lemma 2.1see 11. Letu: a1, b−1Z → Rbe a function. Then the nonhomogeneous discrete fourth-order Lidstone boundary value problem2.1,1.2has solution

yt

b

sa b−1

za1

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whereG2t, sgiven by

G2t, s

1

1,0b, a

⎧ ⎨ ⎩

t, ab, s: ts,

s, ab, t: st,

t, sa−1, b1Z× a, bZ 2.3

witht, s μtsμstforμ β2ββ4/2, is the Green’s function for the second-order

discrete boundary value problem

−Δ2yt1βyt0, t a, b

Z,

ya 0yb,

2.4

andG1s, zgiven by

G1s, z 1

ba

⎧ ⎨ ⎩

sabz: sz,

zabs: zs, s, za, ba1, b−1Z 2.5

is the Green’s function for the second-order discrete boundary value problem

−Δ2xs1 0, s a1, b1

Z,

xa 0xb.

2.6

Lemma 2.2see 11. Let

m: 1,0b, a1

ba2b, a , M:

ba2b/2, a/2

41,0b, a . 2.7

Then, fort, s, za1, b−13Z, one has

mG2t, sG1s, zM. 2.8

3. Main Results

Theorem 3.1. Assume thatH1–H3hold. Then, the BVP1.1and1.2has a unique solution

ytinD, where

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Moreover, for anyx0, y0 ∈D, constructing successively the sequences fixed point of the operator equation

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conditionH2impliesL >0. Sincefiy>0 fory >0i1,2, byLemma 2.2, we have

AL, L

b−1

sa1 b−1

za1

G2t, sG1s, zhz

f1L f2L

mf1L f2L b−1

sa1 b−1

za1

hz

mf1L f2L

L

3.6

formin2.1andLin3.5. Moreover, we obtain

AL, LMf1L f2L

L 3.7

forMin2.1. Thus

mf1L f2L

LAL, LMf1L f2L

L. 3.8

Therefore, we can choose a sufficiently small numbere1∈0,1such that

e1LAL, L

L e1

, 3.9

which together withH3implies that there existsτ1∈ a1, b−1Zsuch thatϕτ1 e1, so

ϕτ1LAL, LL

ϕτ1. 3.10

Sinceψτ1/ϕτ1>1, we can take a sufficiently large positive integerksuch that

ψτ 1

ϕτ1 k

≥ 1

ϕτ1

. 3.11

It is clear that

ϕτ 1

ψτ1 k

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Thus, we have

Av0, u0 A

L

ϕτ1 k,

ϕτ1 k

L

A

L ϕτ1

ϕτ1

k−1, ϕτ1

ϕτ1 k−1

L

≤ 1

ψτ1

A

L

ϕτ1 k−1,

ϕτ1 k−1

L

≤ · · ·

1

ψτ1

kAL, L

1

ψτ1 k

L ϕτ1

.

3.17

In accordance with3.12, we can see that

Av0, u0≤

L

ϕτ1

k v0. 3.18

Construct successively the sequences

unAun−1, vn−1, vnAvn−1, un−1, n1,2, . . . . 3.19

By the mixed monotonicity ofA, we haveu1 Au0, v0≤Av0, u0 v1. By induction, we

obtainunvn, n 1,2, . . .. It follows from3.14,3.18, and the mixed monotonicity ofA

that

u0≤u1≤ · · · ≤un≤ · · · ≤vn≤ · · · ≤v1≤v0. 3.20

Note thatu0≥λv0, so we can getuntu0tλv0tλvnt, ta, bZ, n1,2, . . .. Let

λnsup{λ >0|untλvnt, ta, bZ}, n1,2, . . . . 3.21

Thus, we have

untλnvnt, ta, bZ, n1,2, . . . , 3.22

and then

un1tuntλnvntλnvn1t, ta, bZ, n1,2, . . . . 3.23

Therefore,λn1 ≥λn,that is,{λn}is increasing with{λn} ⊂0,1. Setλlimn→ ∞λn. We can

show thatλ1. In fact, if 0<λ < 1, byH3, there existsτ2∈ a1, b−1Zsuch thatϕτ2 λ.

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iThere exists an integerN such thatλN λ. In this case, we have λn λfor all

nNholds. Hence, fornN, it follows from3.4and the mixed monotonicity ofAthat

un1Aun, vnA λv n,

1

λun

A ϕτ2vn,

1

ϕτ2

un

ψτ2Avn, un ψτ2vn1.

3.24

By the definition ofλn, we have

λn1λψτ2> ϕτ2 λ. 3.25

This is a contradiction.

iiFor all integern,λn < λ. In this case, we have 0 < λn/λ < 1. In accordance with

H3, there existsθna1, b−1Zsuch thatϕθn λn/λ. Hence, combining3.4with the

mixed monotonicity ofA, we have

un1 Aun, vnA λnvn,

1

λnun

A

⎛ ⎜ ⎝λn

λ

λvn,

un

λn/λ

λ

⎞ ⎟

⎠A ϕθnϕτ2vn,

un

ϕθnϕτ2

ψθnA ϕτ2vn,

un

ϕτ2

ψθnψτ2Avn, un

ψθnψτ2vn1.

3.26

By the definition ofλn, we have

λn1≥ψθnψτ2> ϕθnψτ2

λn

λ ψτ2. 3.27

Letn → ∞, we haveλλ/ λψτ2>λ/ λϕτ2 ϕτ2 λ, and this is also a contradiction.

Hence, limn→ ∞λn1.

Thus, combining3.20with3.22, we have

0≤unltuntvntuntvntλnvnt 1−λnvnt≤1−λnv0t 3.28

forta, bZ, wherelis a nonnegative integer. Thus,

unlunvnun ≤1−λnv0. 3.29

Therefore, there exists a functiony∗∈Dsuch that

lim

n→ ∞unt nlim→ ∞vnt y

t fort a1, b1

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By the mixed monotonicity ofAand3.20, we have contrary, that there exist two nontrivial solutionsy1 andy2of the BVP1.1and1.2such

thatAy1t, y1t y1tandAy2t, y2t y2tforta−1, b1Z. According to3.9,

Thus, we can choose a sufficiently large positive integerksuch that

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Obviously,u"0< x0, y0<v"0. Let

Similarly to the above proof, it follows that there existsy"∈Dsuch that

lim

This completes the proof of the theorem.

Remark 3.2. From the proof ofTheorem 3.1, we easily know that assumey Ay, x,x Ax, y, thus, lety0y,x0x, we have

yny, xnx, n1,2, . . . . 3.42

Thereforeyxy∗.

Theorem 3.3. Assume thatH2holds, and the following conditions are satisfied:

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C3for fixedτa1, b−1Z, one has

iψτ, yis nonincreasing with respect toy, and there existsτ4∈ a1, b−1Zsuch

that

mfLϕτ4,

ψτ4, L/ϕτ4

ϕτ4 ≥

MfL 3.44

or

iiψτ, yis nondecreasing with respect toy, and there existsτ5 ∈ a1, b−1Zsuch

that

mfLϕτ5 ψτ5, L

, 1 ϕτ5 ≥

MfL, 3.45

wherem, Mare defined in2.1,Lis defined in3.5. Then, the BVP

Δ4yt2βΔ2yt1 htfyt, t a1, b1

Z, ya 0 Δ2ya−1, yb 0 Δ2yb−1

3.46

has a unique solutiony.

Proof. For convenience, we still define the operator equationAby

Ayt

b

sa b−1

za1

G2t, sG1s, zhzf

yz, ta−1, b1Z. 3.47

In the following, we consider the following two cases.

iFor fixedτa1, b−1Z,ψτ, yis nonincreasing with respect toy.

According to conditionC3andLemma 2.2, we can know that there existsτ4 ∈ a

1, b−1Zsuch that

ϕτ4LAL

ψτ4, L/ϕτ4

ϕτ4

L. 3.48

Sinceψτ4, L/ϕτ4>1, we can find a sufficiently large positive integerksuch that

ψτ 4, L

ϕτ4 k

≥ 1

ϕτ4

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Forta1, b−1Z, we still define

u0t

ϕτ4 k

L, v0t L

ϕτ4 k,

unt Aun−1t, vnt Avn−1t, n1,2, . . . .

3.50

By the proof ofTheorem 3.1, it is sufficient to show that

u0 ≤u1≤v1 ≤v0. 3.51

Obviously,u0≤v0andu1≤v1.

In this case, it follows from conditionsC2,C3, and3.49that

u1 Au0Aϕτ4 kL

Aϕτ4

ϕτ4 k−1

L

ψτ4,

ϕτ4 k−1

LAϕτ4 k−1

L

ψτ4,

ϕτ4 k−1

LAϕτ4

ϕτ4 k−2

L

ψτ4,

ϕτ4 k−1

Lψτ4,

ϕτ4 k−2

LAϕτ4 k−2

L

≥ · · ·

ψτ4,

ϕτ4 k−1

Lψτ4,

ϕτ4 k−2

L· · ·ψτ4, LAL

ψτ4, L k

ϕτ4L

ϕτ4 k

Lu0.

3.52

In accordance with3.16, we have

A y ϕs

≤ 1

(14)
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Forta1, b−1Z, we still define

u0t

ϕτ5 k

L, v0t

L

ϕτ5 k,

unt Aun−1t, vnt Avn−1t, n1,2, . . . .

3.57

We continue to prove that

u1≥u0, v1≤v0. 3.58

By3.52, combining3.55with the monotonicity ofψ, we have

u1 Au0Aϕτ5 k

L

ψτ5,

ϕτ5 k−1

Lψτ5,

ϕτ5 k−2

L· · ·ψτ5, LAL

ϕτ5 k−1ψτ

5, LALϕτ5

k

Lu0.

3.59

In accordance with3.54, combining the monotonicity ofψand3.55, we get

v1Av0A

L

ϕτ5 k

≤ 1

ψτ5, L/

ϕτ5 k

1

ψτ5, L/

ϕτ5

k−1· · ·

1

ψτ5, L/ϕτ5 AL

1

ψτ5, L/ϕτ5 k

L ϕτ5.

3.60

An application of3.56yields

v1≤ 1

ϕτ5

kLv0. 3.61

Therefore, we obtain

u0 ≤u1≤v1 ≤v0. 3.62

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Remark 3.4. InTheorem 3.1, the more general conditions are imposed on the nonlinear term thanTheorem 1.1. In particular, inTheorem 3.3,ψτ, ycontains the variabley; therefore, the more comprehensive functions can be incorporated.

4. An Example

Example 4.1. Consider the following discrete fourth-order Lidstone problem:

Δ4yt2Δ2yt1 t

Moreover, for anyx0, y0∈D, constructing successively the sequences

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ψτ ϕτ1/2. It is easy to see that

f1

ϕτy1ϕτy1/4≥ψτ1y1/4ψτf1

y,τ∈ 3,6Z, y≥0,

f2

y ϕτ

2 1

y/ϕτ1/4 ≥ψτ

2 1

y1/4

,τ∈ 3,6Z, y≥0.

4.5

The conclusion then follows fromTheorem 3.1.

Acknowledgments

The authors were supported financially by the National Natural Science Foundation of China

10971046, the Natural Science Foundation of Shandong ProvinceZR2009AM004, and the Youth Science Foundation of Shanxi Province2009021001-2.

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