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PII. S0161171201006548 http://ijmms.hindawi.com © Hindawi Publishing Corp.

ROUGH MARCINKIEWICZ INTEGRAL OPERATORS

HUSSAIN AL-QASSEM and AHMAD AL-SALMAN

(Received 16 January 2001)

Abstract.We study the Marcinkiewicz integral operator Mf (x)=(−∞ ||y|≤2tf (x−(y))((y)/|y|n−1) dy|2dt/22t)1/2, whereis a polynomial mapping fromRnintoRd

andΩis a homogeneous function of degree zero onRnwith mean value zero over the

unit sphereSn−1. We prove anLpboundedness result ofMfor roughΩ. 2000 Mathematics Subject Classification. 42B20, 42B15, 42B25.

1. Introduction. LetRn,n2 be then-dimensional Euclidean space andSn−1be the unit sphere inRn equipped with the induced Lebesgue measure. Consider the Marcinkiewics integral operator

µf (x)=

−∞

Ft(x) 2dt

22t

1/2

, (1.1)

where

Ft(x)=

|x−y|≤2tf (y)

(x−y)

|x−y|n−1dy, (1.2)

andΩis a homogeneous function of degree zero which has the following properties:

∈L1Sn−1,

Sn−1Ω

ydσy=0. (1.3)

WhenΩLipα(Sn−1),(0< α≤1), Stein proved theLpboundedness ofµ(f )for all 1< p≤2. Subsequently, Benedek, Calderón, and Panzone proved theLpboundedness ofµ(f )for all 1< p <∞under the conditionΩ∈C1(Sn−1)(see [2]).

The authors of [3] were able to prove the following result for the more general class of operators

µPf (x)=

−∞

FP ,t(x) 2dt

22t

1/2

, (1.4)

where

FP ,t(x)=

|y|≤2tf

x−P (|y|)y(y)

|y|n−1dy (1.5)

andP is a real-valued polynomial onRand satisfiesP (0)=0.

Theorem1.1(see [3]). Letα >0, andVα(n). Then the operatorµP is bounded

(2)

In [1], Al-Salman and Pan studied the singular integral operator

T,f (x)=p.v.

Rnf

x−ᏼ(y)Ω

y

|y|n dy, (1.6)

whereᏼ=(P1, . . . , Pd):Rn→Rd is a polynomial mapping,d≥1,n≥2. The authors of [1] proved thatT,ᏼis bounded inLp(Rd)whenever(2+2α)/(1+2α) < p <2+2α

andΩ∈Wα(n). HereWα(n)is a subspace ofL1(Sn−1)and its definition as well as the definition ofVα(n)will be reviewed inSection 2. It was shown in [1] thatWα(n)= Vα(n),if n=2 and it is a proper subspace ofVα(n)ifn≥3.

Our purpose in this paper is to study theLpboundedness of the class of operators

Mf (x)=

−∞

F,t(x)2dt 22t

1/2

, (1.7)

where

F,t(x)=

|y|≤2tf

x−ᏼ(y) Ω(y)

|y|n−1dy. (1.8) Our main result in this paper is the following theorem.

Theorem 1.2. Letα >0, and Wα(n). Then the operator M is bounded in Lp(Rd)for(2α+2)/(2α+1) < p <2+2α. The bound ofM

f is independent of the coefficients of{Pj}.

By [1, Theorem 3.1] andTheorem 1.2we have the following corollary.

Corollary 1.3. Letα >0,∈Vα(2) andᏼ:R2→Rd. Then M is bounded in Lp(Rd)for(2α+2)/(2α+1) < p <2+2α. The bound ofM

is independent of the coefficients of{Pj}.

2. Preparation. We start this section by recalling the following definition from [1].

Definition2.1. Forα >0,N≥1, letᐂ(n, N) = Nm=1ᐂ(n, m)and letWα(N, n)be the subspace ofL1(Sn−1)defined by

Wα(N, n)=

∈L1Sn−1:

Sn−1Ω

ydσy=0, Mα(N, n) <∞

, (2.1)

where

Mα(N, n)

=max

Sn−1

y

log 1 |P (y)|

1

dσy:P∈ᐂ(n, N) withP =1

.

(2.2)

Forα >0, we defineWα(n)to be

Wα(n)=

N=1

Wα(N, n). (2.3)

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Hereᐂ(n, m)is the space of all real-valued homogeneous polynomials onRnwith degree equal tomand with norm·defined by

|α|=m aαyα

=

|α|=m

aα. (2.4)

Now we need to recall the following results.

Lemma2.2(see van der Corput [7]). Supposeφandψare real-valued and smooth

in(a, b), and that|φ(k)(t)| ≥1for allt(a, b). Then the inequality

abe−iλφ(t)ψ(t) dtCk|λ|1/k

|ψ(b)|+

b

a

ψ(t)dt

, (2.5)

holds when

(i) k≥2, or

(ii) k=1andφis monotonic.

The boundCkis independent ofa,b,φ, andλ.

Lemma2.3(see [7]). Let=(P1, . . . , Pd)be a polynomial mapping fromRnintoRd.

Letdeg()=max1j≤ddeg(Pj). Suppose∈L1(Sn−1)and

µ,f (x)=sup

h>0

1

hn

|y|<hf

x−ᏼ(y)Ωydy. (2.6)

Then for every1< p≤ ∞, there exists a constantCp>0which is independent ofand

the coefficients of{Pj}such that

µ,fp≤CpL1(Sn−1)fp (2.7)

for everyf∈Lp(Rd).

To each polynomial mappingᏼ=(P1, . . . , Pd):Rn→Rd with

degᏼ=max

1≤j≤ddegPj=N, d≥1, n≥2, (2.8)

we define a family of measures

ϑtl, λlt:l=0,1, . . . , N, t∈R

(2.9)

as follows.

For 1≤j≤d, 0≤l≤N letPj=

|α|≤NCjαyα and let Ql=(Ql1, . . . , Qld) where Ql

j=

|α|≤lCjαyα.

Now for 0≤l≤Nandt∈R, letϑl

t andλlt be the measures defined in the Fourier transform side by

ϑltˆ

(ξ)=

|y|≤2te

2π iξ·Ql(y)y |y|n−1

dy 2t ,

λltˆ

(ξ)=

|y|≤2te

2π iξ·Ql(y)y |y|n−1

dy 2t .

(4)

The maximal functions(ϑl)defined by

ϑl∗(f )(x)=sup t∈R

λl

t∗f (x), (2.11)

forl=0,1, . . . , N.

For later purposes, we need the following definition.

Definition 2.4. For each 1≤l≤N, letNl= |{α∈Nn:|α| =l}|and let {α∈

Nn :|α| =l} = {α

1, . . . , αNl}. For each 1≤l≤N, define the linear transformations lj:RdRandL

l:Rd→RNl by

lj(ξ)= d

i=1

Ci,α

jyαj

ξi, j=1, . . . , Nl,

Ll(ξ)=

1

l (ξ), . . . , L αNl l (ξ)

.

(2.12)

To simplify the proof of our result we need the following lemma.

Lemma2.5. Let{σtl:l=0,1, . . . , N, tR}be a family of measures such thatσt0=0

for allt∈R. LetDl:Rn→Rd,l=0,1, . . . , N be linear transformations. Suppose that

for allt∈Randl=0,1, . . . , N,then σl

t≤C(l),

σl t

ˆ

(ξ)≤C

logc2ltDl(ξ)1+α,

σl t

ˆ

(ξ)−σtl−1

ˆ

(ξ)≤C2ltDl(ξ).

(2.13)

Then there exists a family of measures{νtl:l=1, . . . , N}t∈Rsuch that

νl

t≤C(l),

νtlˆ

(ξ)≤C logc2ltD

l(ξ) 1+α,

νl tˆ

(ξ)≤C2ltDl(ξ),

σN t =

N

l=1 νl

t.

(2.14)

Proof. By [5, Lemma 6.1], for eachl=1, . . . , Nchoose two nonsingular linear

trans-formations

Al:Rr (l) Rd, Bl:Rd Rd, (2.15)

such that

Alπr (l)d Bl(ξ)≤Dl(ξ)≤NAlπr (l)d Bl(ξ), ξ∈Rd, (2.16)

(5)

Now chooseη∈C0∞(R)such thatη(t)=1 for|t| ≤1/2 andη(t)=0 for|t| ≥1. Let ϕ(t)=φ(t2)and let

νl

tˆ

(ξ)=σl t

ˆ (ξ)

l<j≤N

ϕ2tjA

jπr (j)d Bj(ξ)

−σtl−1

ˆ

(ξ)

l−1<j≤N

ϕ2tjA

jπr (j)d Bj(ξ)

(2.17)

with the conventionj∈∅aj=1, 1≤l≤N.

Hence, one can easily see that {σtl:l=1, . . . , N, t∈R} is the desired family of measures.

Now for the boundedness of the maximal functions(ϑl),l=0,1, . . . , N, we have the following lemma whose proof is an easy consequence ofLemma 2.3, polar coordinates and Hölder’s inequality:

Lemma2.6. Forl=1, . . . , Nandp(1,), there exists a constantCp,lwhich is

inde-pendent of the coefficients of the polynomial components of the mappingQlsuch that

ϑl∗f

p≤Cp,lfp. (2.18)

3. Boundedness of some square functions. For a nonnegativeC∞radial function

ΦonRnwith

supp(Φ)⊂

x∈Rn:1

2≤ |x| ≤2

,

0

Φ(t)

t dt=1, (3.1)

and for a linear transformationL:RnRd, define the functionsψt,tRby ˆψ t(y)=

Φ(2tL(y)).

For a family of measures{σt}t∈R, real numberuandl∈N, letJlu(f )be the square function defined by

Jlu(f )(x)=

−∞

σt∗ψl(t+u)∗f (x) 2

dt 1/2

. (3.2)

For such a square function we have the following theorem.

Theorem3.1. If{σt}t∈Ris a family of measures such that the corresponding

maxi-mal function

σ∗(f )(x)=sup t∈R

σtf (x) (3.3)

is bounded onLp(Rd)for every1< p <, then

Jl

u(f )LpRd≤Cp,l

σ∗

(p/2)sup t∈R

σtfLpRd (3.4)

for every1< p <∞. HereCp,lis a constant that depends only onpand the dimension

(6)

Proof. If supt∈Rσt = ∞, then the inequality holds trivially. Thus we may assume

that supt∈Rσt<∞. In this case we follow a similar argument as in [4]. Letp >2 and q=(p/2). Choose a nonnegative functionv∈Lq+withvq=1 such that

Jl u(f )

2 p=

Rd

−∞

σt∗ψl(t+u)∗f (x) 2

dt

v(x)dx. (3.5)

Thus it is easy to see that

Jl u(f )

2 p≤sup

t∈R

σt −∞

Rd

ψl(t+u)f (z)2

σ∗(v)(−z)dz dt

sup t∈R

σt

Rd[g(f )]

2(z)σ(v)(z) dz,

(3.6)

where

g(f )(x)=

−∞

ψl(t+u)f (x)2 dt

1/2

. (3.7)

Now sinceRdψt(x) dx=0, it is well known that

g(f )p≤Cpfp 1< p <∞ (3.8)

with constantCpthat depends only onpand the dimension of the underlying space. Thus by (3.6) and Hölder’s inequality we have

Jl u(f )

2 p≤sup

t∈R

σtg(f )2pσ∗(u)q

≤Cp2sup t∈R

σtσ

(p/2)f2p.

(3.9)

Hence our result follows by taking the square root on both sides. The casep <2 follows by duality.

4. Proof of the main theorem. Let α >0, Ω∈Wα(n). Let ᏼ=(P1, . . . , Pd) be a polynomial mapping fromRnintoRdwith deg=max1

≤j≤ddegPj=N, whered≥1 andn≥2. For 0≤l≤NletNl,Ql,νl

t,λlt, andLlbe as inSection 3. The first step in our proof is to show that eachϑl

t,l=1, . . . , Nsatisfies the hypothe-ses ofLemma 2.5, that is,

ϑl

t≤C(l), (4.1)

ϑl tˆ

(ξ)≤C logc2ltL

l(ξ)1

, (4.2)

ϑl tˆ

(ξ)−ϑlt−

(ξ)≤C2ltLl(ξ). (4.3)

One can easily see that (4.1) holds trivially. Using the cancellation property ofΩ, it is easy to see that (4.3) holds. Thus, we need only to verify (4.2). To see that, we notice that

ϑl tˆ

(ξ)≤

Sn−1

y 1

0e

(7)

Now the quantityξ·Ql(2tlr y)can be written in the form

ξ·Ql2tlr y=2tlrlλGly+ξ·R2tr y, (4.5)

whereQlis a homogeneous polynomial of degreelwithGl =1,Ris a polynomial of degree at mostl−1 in the variabler,

λ= Nl

j=1

Lαj

l (ξ)≥NlLl(ξ) (4.6)

andα1, . . . , αNl are the constants that appeared inSection 2. Thus by van der Corput lemma, we have

01e−2π iξ·Ql(2tr y)

dr≤Cmin1,2tlL

l(ξ)Gly−1/l

(4.7)

and hence

01e−2π iξ·Ql(2tr y)

dr≤C

logcGly11

logc2tlLl(ξ)1 , (4.8)

whereC is a constant independent oft andξ. SinceΩ∈Wα(n), the estimate (4.2) follows.

ByLemma 2.5, there exists a family of measures{νtl:l=1, . . . , N, t∈R}such that

νl

t≤C(l), (4.9)

νl tˆ

(ξ)≤C logc2ltL

l(ξ)

1+α, (4.10)

νl tˆ

(ξ)≤C2ltLl(ξ), (4.11)

ϑtN= N

l=1

νtl. (4.12)

Also byLemma 2.6and the definition ofνtl(see the proof ofLemma 2.5), we have

νl∗f

p≤Cp,lfp 1< p <∞. (4.13)

Now one can easily see that

2−tF,t(x)=ϑNt ∗f (x)= N

l=1

νtl∗f (x). (4.14)

Therefore,

Mfp N

l=1

Ml

fp, (4.15)

where

Mlf (x)=

−∞ νl

t∗f (x) 2

dt 1/2

(8)

Thus to show the boundedness ofMf, it suffices to show that Ml

fp≤Cp,lfp (4.17)

forp∈((2+2α)/(1+2α),2+2α), and for alll=1, . . . , N.

To show (4.17), we proceed as follows: letΦandψtbe as inSection 3. Then

Ml

f (x)=log 2l

−∞ −∞ νl

t∗ψl(t+u)∗f (x) du

2dt

1/2

log 2l

−∞S l

uf (x) du,

(4.18)

where

Sulf (x)=

−∞ νl

t∗ψl(t+u)∗f (x) 2

dt 1/2

. (4.19)

Now by (4.13) andTheorem 3.1, we have

Sl

ufp≤Cpfp (4.20)

for allp∈(1,∞)and forl=1, . . . , N which in turn implies that

1

1

Sl

ufpdu≤2Cpfp ∀p∈(1,∞). (4.21)

On the other hand, ifu≥1, by the estimate (4.11) we have

Sl uf

2 2=

Rd

−∞ νl

t∗ψl(t+u)∗f (x)2dt dx

=

−∞

Rd

Φ2lt+luL l(ξ)

2 νl

tˆ

(ξ)2f (ξ)ˆ 2dξ dt

22l2lu

Rd

f (ξ)ˆ 2log(2 l/|L

l(ξ)|)−u

log(1/2l|L l(ξ)|)−u

dt

=2 log 2l22l2luf2 2.

(4.22)

Thus

Sl uf2

2 log 2l2l−luf2. (4.23)

By interpolating between (4.20) and (4.23) we get

Sl

ufp≤Cp,l2θl−θlufp (4.24)

for all 1< p <∞and for someθ=θ(p) >0. Hence we have

1

Sl

(9)

Finally, if u <−1, by the estimate (4.10) and similar argument as in the case of u≤1, we get

Sl

uf2≤Cl(|u|)−1−αf2. (4.26)

By interpolating between (4.26) and anyp ∈(1,∞) in (4.20), we get that, ifp∈ ((2+2α)/(1+2α),2+2α)there existsβ >0 such that

Sl

ufp≤Cp(|u|)−βfp, (4.27)

which implies that

1

−∞ Sl

ufpdu≤Cpfp (4.28)

forp∈((2+2α)/(1+2α),2+2α).

Hence by combining (4.18), (4.21), (4.25), and (4.28) we get (4.17).

Acknowledgement. The publication of this paper was supported by Yarmouk

University Research Council.

References

[1] A. Al-Salman and Y. Pan,Singular integrals with rough kernels, to appear in Canad. Math. Bull.

[2] A. Benedek, A. P. Calderón, and R. Panzone, Convolution operators on Banach space valued functions, Proc. Nat. Acad. Sci. U.S.A. 48 (1962), 356–365.MR 24#A3479. Zbl 103.33402.

[3] J. Chen, D. Fan, and Y. Pan,A note on a Marcinkiewics integral operator, to appear in Math. Nachr.

[4] J. Duoandikoetxea and J. L. Rubio de Francia,Maximal and singular integral operators via Fourier transform estimates, Invent. Math.84(1986), no. 3, 541–561.MR 87f:42046. Zbl 568.42012.

[5] D. Fan and Y. Pan,Singular integral operators with rough kernels supported by subvarieties, Amer. J. Math.119(1997), no. 4, 799–839.MR 99c:42029. Zbl 0899.42002.

[6] L. Grafakos and A. Stefanov, Lp bounds for singular integrals and maximal singular integrals with rough kernels, Indiana Univ. Math. J. 47 (1998), no. 2, 455–469.

MR 99i:42019. Zbl 913.42014.

[7] E. M. Stein,Harmonic Analysis: Real-Variable Methods, Orthogonality, and Oscillatory Inte-grals, Princeton Mathematical Series, vol. 43, Princeton University Press, New Jersey, 1993.MR 95c:42002. Zbl 821.42001.

Hussain Al-Qassem: Department of Mathematics, Yarmouk University, Irbid, Jordan E-mail address:husseink@yu.edu.jo

References

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