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A NEW FACTOR THEOREM ON ABSOLUTE MATRIX SUMMABILITY METHODS

S¸. YILDIZ1,§

Abstract. The aim of this paper is to obtain a new theorem dealing with absolute matrix summability factors.

Keywords: Summability factors, absolute matrix summability, infinite series, H¨older inequality, Minkowski inequality

AMS Subject Classification: 26D15, 40D15, 40F05, 40G99

1. Introduction

Let A= (anv) be a normal matrix and (sn) be the sequence of thenth partial sums of the seriesP

an, then we define

An(s) = n

X

v=0

anvsv. (1)

Let (θn) be any sequence of positive constants. The series P

an is said to be summable

|A, θn|k,k≥1,if (see [2])

∞ X

n=1

θnk−1|∆An(s)¯ |k<∞. (2) where

¯

∆An(s) =An(s)−An−1(s). (3) One can also see [1] for this method. If we take θn = n, then the |A, θn|k summability reduces to|A|k summability (see [3]).

Given a normal matrix A = (anv), we associate two lower semimatrices ¯A = (¯anv) and ˆ

A= (ˆanv) as follows:

¯ anv=

n

X

i=v

ani, n, v= 0,1, ... ∆a¯ nv =anv−an−1, v a−1,0 = 0 (4)

1

Department of Mathematics, Ahi Evran University, Kır¸sehir, Turkey. e-mail: [email protected]; [email protected]. ORCID: https://orcid.org/0000-0003-3763-0308.

§ Manuscript received: March 02, 2017; accepted: May 05, 2017.

TWMS Journal of Applied and Engineering Mathematics, Vol.9, No.2 cI¸sık University, Department of Mathematics, 2019; all rights reserved.

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and

ˆ

a00= ¯a00=a00, anvˆ = ¯∆¯anv = ¯anv−¯an−1,v, n= 1,2, ... (5)

It may be noted that ¯A and ˆA are the well-known matrices of series-to-sequence and series-to-series transformations, respectively. Then, we have

An(s) = n

X

v=0

anvsv = n

X

v=0 ¯

anvav (6)

and

¯

∆An(s) = n

X

v=0 ˆ

anvav. (7)

We say thatA is a normal matrix if A is lower triangular andann 6= 0 for alln.

2. The Known Result

Sulaiman [4] has proved the following theorem for matrix summability methods.

Theorem 2.1 Let (λn), (Xn) be two sequences such thatP∞n=1n−1λnXn is convergent, and the conditions

n∆λn=O(λn), n→ ∞, (8)

n

X

v=1

λv=O(nλn), n→ ∞, (9)

are satisfied. LetA be a lower triangular with non-negative entries satisfying

an0 = 1, n= 0,1, ..., (10)

an−1,v≥anv, forn≥v+ 1, (11) nann =O(1), 1 =O(nann) (12)

n−1

X

v=1

avvan,vˆ =O(ann). (13)

If tkv = O(1)(C,1), where tv = v+11 v

P

r=1

rar, then the series

P

anλnXn is summable |A|k,

k≥1.

3. The Main Result

The aim of this paper is to generalize Theorem 2.1 for |A, θn|k summability method in the following form.

Theorem 3.1 Let A be a positive normal matrix satisfying the conditions (10)-(13) of Theorem 2.1. Let (θnann) be a non-increasing sequence. If (θn) is any sequence of positive constants such that

∞ X

n=v+1

(θnann)k−1ˆan,v =O

n

(θvavv)k−1

o

, (14)

∞ X

n=v+1

(θnann)k−1|∆a¯ nv|=O

n

(θvavv)k−1avv

o

, (15)

and all the conditions of Theorem 2.1 are satisfied, then the seriesP

anλnXnis summable

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We need the following lemmas for the proof of Theorem 3.1.

Lemma 3.1[4] If P

n−1λ

n is convergent, then (λn) is non-negative, non-decreasing, λnlogn=O(1), andn∆λn=O(1/(logn)2).

Lemma 3.2[4] If P

n−1λnXn is convergent, and the conditions (8) and (9) of Theorem 2.1 are satisfied, then

nλn∆Xn=O(1), (16)

∞ X

n=1

λn∆Xn=O(1), n→ ∞, (17)

m

X

n=1

nλn∆2Xn=O(1), m→ ∞. (18)

Lemma 3.3[4] Under the conditions (10) and (11) of Theorem 2.1, we have

n−1

X

v=0

|∆a¯ nv| ≤an,n, (19)

ˆ

an,v+1≥0, (20)

m+1

X

n=v+1 ˆ

an,v+1=O(1). (21)

Proof of Theorem 3.1

Let (Vn) denotes the A-transform of the series

∞ P

n=1

anλnXn. We write ϕn = λnXn, so

we have

¯ ∆Vn=

n

X

v=1 ˆ

an,vavϕv = n

X

v=1

v−1ˆan,vvavϕv

Applying Abel’s transformation to this sum, we have that

¯ ∆Vn=

n−1

X

v=1

∆v(ˆan,vϕvv−1) v

X

r=1

rar+annϕnn−1 n

X

v=1 vav

= n−1

X

v=1

(v+ 1)tv(v−1(v+ 1)−1ˆan,vϕv+ (v+ 1)−1∆anvϕv¯ + (v+ 1)−1an,v+1∆ϕvˆ ) +n+ 1

n annϕntn

= n−1

X

v=1

v−1tvan,vˆ ϕv+ n−1

X

v=1

tv∆anvϕv¯ + n−1

X

v=1

tvˆan,v+1∆ϕv+n+ 1

n annϕntn

=Vn,1+Vn,2+Vn,3+Vn,4.

To complete the proof of Theorem 3.1, by Minkowski’s inequality, it is sufficient to show that

∞ X

n=1

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First, by applying H¨older’s inequality with indicesk and k0, wherek>1 and k1 +k10 = 1, we have that

m+1

X

n=2

θnk−1 |Vn,1|k= m+1

X

n=2 θkn−1

n−1

X

v=1

v−1ˆan,vtvϕv

k ≤ m+1 X n=2 θnk−1

n−1

X

v=1

v−ktkva1vv−kˆan,vϕkv n−1

X

v=1

avvˆan,v

!k−1

=O(1) m+1

X

n=2

(θnann)k−1 n−1

X

v=1

tkvavvϕkvˆan,v =O(1) m

X

v=1

avvtkvϕkv m+1

X

n=v+1

(θnann)k−1ˆan,v

=O(1) m

X

v=1

(θvavv)k−1avvtkvϕkv =O(1) m

X

v=1

(θvavv)k−1ϕvk−1ϕvtkvv−1,

usingnXn∆λn=O(λnXn) =O(1) from Lemma 3.2 and writingϕn=λnXnwe have that

m+1

X

n=2

θnk−1|Vn,1 |k=O(1) m

X

v=1

(θvavv)k−1ϕvtkvv

−1=O(1)(θ

1a11)k−1 m

X

v=1 ϕvtkvv

−1

=O(1) m−1

X

v=1 v

X

r=1 tkr

!

∆(v−1ϕv) + m

X

v=1 tkv

!

m−1ϕm

=O(1) m−1

X

v=1

v(v−2ϕv+ (v+ 1)−1∆ϕv) +O(1)ϕm

=O(1) m−1

X

v=1

v−1ϕv+O(1) m−1

X

v=1

∆ϕv+O(1)ϕm

=O(1) m−1

X

v=1 λvXv

v +O(1)λmXm=O(1), as m→ ∞,

by virtue of the hypotheses of Theorem 3.1 and Lemma 3.3. Now, using H¨older’s inequality, and by the hypotheses of Theorem 3.1 and Lemma 3.3. we have that

m+1

X

n=2

θkn−1 |Vn,2 |k= m+1

X

n=2 θnk−1

n−1

X

v=1 ¯

∆anvtvϕv

k ≤ m+1 X n=2 θkn−1

n−1

X

v=1

tkv|∆anv¯ |ϕkv n−1

X

v=1

|∆anv¯ | !k−1

=O(1) m+1

X

n=2

(θnann)k−1 n−1

X

v=1

tkvϕkv|∆a¯ nv|=O(1) m

X

v=1 tkvϕkv

m+1

X

n=v+1

(θnann)k−1|∆a¯ nv|

=O(1) m

X

v=1

(θvavv)k−1avvtkvϕkv = m

X

v=1

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as in the case ofVn,1. Furthermore, we have that

m+1

X

n=2

θkn−1|Vn,3 |k= m+1

X

n=2 θnk−1

n−1

X

v=1 ˆ

an,v+1tv∆ϕv

k

m+1

X

n=2 θkn−1

n−1

X

v=1

tkva1vv−kˆan,v+1(∆ϕv)k n−1

X

v=1

avvˆan,v+1

!k−1

=O(1) m+1

X

n=2

(θnann)k−1 n−1

X

v=1

tkva1vv−kˆan,v+1(∆ϕv)k

=O(1) m

X

v=1

tkva1vv−k(∆ϕv)k m+1

X

n=v+1

(θnann)k−1ˆan,v+1

=O(1) m

X

v=1

(θvavv)k−1avv1−ktkv(∆ϕv)k=O(1) m

X

v=1

(θvavv)k−1vk−1tkv(∆ϕv)k−1∆ϕv

=O(1) m

X

v=1

(θvavv)k−1tvk∆ϕv(v∆ϕv)k−1,

by usingn∆(λnXn) =O(1) from Lemma 3.1 we have that

m+1

X

n=2

θkn−1 |Vn,3|k=O(1)(θ1a11)k−1 m

X

v=1 tkv∆ϕv

=O(1) m

X

v=1

tkv(∆λvXv+λv+1∆Xv) =O(1) as m→ ∞, (see [4] for detail).

Finally, as in the case ofVn,1, we have that m

X

n=1

θnk−1|Vn,4 |k= m

X

n=1 θkn−1

n+ 1

n anntnϕn

k

=O(1) m

X

n=1

(θnann)k−1anntknϕkn=O(1) m

X

n=1

(θnann)k−1n−1tknϕn=O(1) as m→ ∞, by the hypotheses of Theorem 3.1 and Lemma 3.3. This completes the proof of Theorem 3.1.

In the special case, if we takeθn=nand A as a lower triangular matrix in Theorem 3.1, then we obtain Theorem 2.1.

Acknowledgment

The author would like to express her sincerest thanks to the referee for his/her sugges-tions for improvement of this paper.

References

[1] ¨Ozarslan, H. S., Kandefer, T., (2009), On the relative strength of two absolute summability methods, J. Comput. Anal. Appl. 11, 576–583.

[2] Sarıg¨ol, M. A., (2010), On the local property of factored Fourier series, Appl. Math. Comput., 216, 3386–3390.

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[4] Sulaiman, W. T., (2013), Some new factor theorem for absolute summability, Demonstr. Math., XLVI (1), 149–156.

References

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