• No results found

The roots of the third Jackson q Bessel function

N/A
N/A
Protected

Academic year: 2020

Share "The roots of the third Jackson q Bessel function"

Copied!
8
0
0

Loading.... (view fulltext now)

Full text

(1)

PII. S016117120320613X http://ijmms.hindawi.com © Hindawi Publishing Corp.

THE ROOTS OF THE THIRD JACKSON

q

-BESSEL FUNCTION

L. D. ABREU, J. BUSTOZ, and J. L. CARDOSO

Received 16 July 2002

We derive analytic bounds for the zeros of the third Jacksonq-Bessel function J(ν3)(z;q).

2000 Mathematics Subject Classification: 33D15, 33D67.

1. Introduction. There are three knownq-analogs of classical Bessel func-tions [6,5] that are due to Jackson [7]. Following the notation of Ismail [6,5], these are designated byJν(k)(z;q),k=1,2,3.

The parameterq is taken to satisfy 0< q <1. The third Jackson q-Bessel functionJν(3)(z;q)is defined as

J(3)

ν (z;q):=

qν+1;q

(q;q)∞ z

ν

1Φ1

0

qν+1 ;q,qz2

. (1.1)

This function is also known as the Hahn-Extonq-Bessel function [8,9]. The notation1Φ1in (1.1) is the standard in use forq-hypergeometric series [4]. The

functionJν(3)(z;q)satisfies a linearq-difference equation and it is known that

Jν(3)(z;q)has an infinite number of simple real zeros [8]. In this paper, we will give lower and upper bounds for these zeros. The roots of these functions are of interest for several reasons. Firstly, it is intrinsically interesting to provide information about the roots of a function such as (1.1), which is an entire func-tion of order zero. Also, the roots ofJν(2)(z;q)andJν(3)(z;q)figure prominently in expansions in terms of “q-Fourier series” [2,3]. Lastly, if we denote the roots ofJν(3)(z;q)byjn,ν(3), then the mass points of the orthogonality measure for aq -analog of Lommel polynomials are located at the points 1/j(n,ν3). Furthermore, although the function defined in (1.1) is of a simpler character than the re-maining Jacksonq-Bessel functions, it is hoped that the results given here for

Jν(3)(z;q)may be extended in the future toJν(k)(z;q),k=1,2.

(2)

First we apply the following transformation to (1.1):

(c;q)∞1Φ1

0

c ;q,z

=(z;q)∞1Φ1

0

z ;q,c

. (2.1)

This produces

J(3) ν (z;q)=

qz2;q

(q;q)∞ z

ν

1Φ1

0

qz2 ;q,qν+1

. (2.2)

This last relation in a series form gives

Jν(3)(z;q)= z ν

(q;q)∞

k=0 (−1)k

qz2;q

qz2;q

k(q;q)kq

k(k+2ν+1)/2

=

(q;q)∞

k=0 (−1)k

qk+1z2;q

(q;q)k q

k(k+2ν+1)/2.

(2.3)

This representation will be critical in the proof of the next two lemmas.

Lemma2.1. Ifqν+1<(1q)2, thensgn[J(3)

ν (q−m/2;q)]=(−1)m,m=1,2,....

Proof. Setz=q−m/2in (2.3) to obtain

(q;q)∞

q−mν/2J

(3) ν

q−m/2;q=

k=0 (−1)k

q−m+k+1;q

(q;q)k q

k(k+2ν+1)/2

. (2.4)

Now observing that(q−m+k+1;q)

∞=0 ifk < m, the series on the right-hand

side of this last equality can be written as

k=m

(−1)k

q−m+k+1;q

(q;q)k q

k(k+2ν+1)/2

. (2.5)

Settingj=k−min this last series yields

(q;q)m

q−mν/2J

(3) ν

q−m/2;q=(−1)m

j=0

(−1)jAj, (2.6)

where

Aj=

qj+1;q

(q;q)j+mq

(j+m)(j+m+2ν+1)/2. (2.7)

Now we prove that Aj+1< Aj. A calculation shows thatAj+1< Ajis equiv-alent toqm+j+ν+1< (1qm+j+1)(1qj+1). But the left-hand side of this

in-equality is decreasing inmandj, while the right-hand side is increasing inm

(3)

q

this is the hypothesis of the lemma. Clearly, sinceAj+1< Aj, then

sgn(−1)m

j=0

(−1)jAj=(−1)m. (2.8)

Lemma 2.1states that there exist an odd number of roots in the interval

(q−m/2+1/2,q−m/2). The next lemma refines this statement.

Lemma2.2. Letqν+1< (1q)2and define

α(ν) m (q)=

log1−qm+ν/1qm

logq . (2.9)

Then

sgnJν(3)

q−m/2+α(ν)m(q)/2;q =(1)m−1, m=1,2,.... (2.10)

Proof. First observe that the functionα(ν)m (q)is well defined because if

qν+1< (1q)2, thenqν+1< (1q) and so, for positive integerm,qm+ν <

(1−qm), that is, 1qm+ν/(1qm) >0. Being defined, it is clear thatα(ν) m (q) is positive because 1−qm+ν/(1qm) <1 holds for anyq(0,1).

Observe also that

α(ν)

m (q) <1⇐⇒log

11qm+ν

qm

>logq⇐⇒qm+ν< (1q)1qm, (2.11)

which is true ifqν+1< (1q)2. So, we have 0< α(ν) m(q) <1. Now, setz=q−m/2+α(ν)m(q)/2in (2.3). The substitution gives

(q;q)∞

q−mν/2+να(ν)m (q)/2J

(3) ν

q−m/2+α(ν)m (q)/2;q

= m2

k=0 (−1)k

q−m+α(ν)m(q)+k+1;q

(q;q)k q

k(k+2ν+1)/2

+

k=m−1 (−1)k

q−m+α(ν)m(q)+k+1;q

(q;q)k q

k(k+2ν+1)/2.

(2.12)

Denote the first sum above byS1and the second byS2. If 0≤k≤m−2, then 0< α(ν)m (q) <1 implies that sgn(q−m+α

(ν)

m (q)+k+1;q)=(1)m−k−1. Thus sgnS1=(−1)m−1,m=1,2,....

InS2, setj=k−m+1 to obtain

S2=(−1)m−1

j=0 (−1)jA

(4)

where

Aj=

qα(ν)m(q)+j;q

(q;q)j+m−1 q

(j+m−1)(j+m+2ν)/2

. (2.14)

A calculation shows thatAj+1< Ajis reduced toqj+m+ν<(1−qα (ν)

m(q)+j)(1

qm+j), which holds becauseqm+ν=(1qαm(ν)(q))(1qm)and because the left-hand side of the last inequality is decreasing inj and the right-hand side is increasing inj. The infinite series is thus positive and therefore

sgnS2=(−1)m−1=sgnS1. (2.15)

From Lemmas2.1and2.2, we know thatJ(ν3)(z;q) has an odd number of roots in the interval(q−m/2+α(ν)m(q),q−m/2). The next theorem proves that there

is exactly one root in each such interval and that there are no other roots.

Theorem 2.3. If qν+1< (1q)2 and if w(ν)

k (q) are the positive roots of

Jν(3)(z;q), ordered increasingly ink, thenwk(ν)(q)=q−k/2+k(ν), with0< k(ν) <

α(ν)k (q),k=1,2,....

Proof. From the preceding lemmas, we know thatJν(3)(z;q)has roots of the formwk(ν)=q−k/2+k, with 0< k< α(ν)k (q).

To simplify the notation, we set

F(z)= (q;q)∞ qν+1;q

∞zνJ

(3)

ν (z;q). (2.16)

We prove that the only positive roots ofF(z)inside the disk|z|< q−m/2are wk(ν)(q),k=1,2,...,m.

Suppose there are other roots±λk,k=1,2,...,Pm;λk>0. By Jensen’s theo-rem [1], we can write

1 2π

2π

0 log F

q−m/2eiθdθ

=2 m

k=1

logq

−m/2

wk + 2

Pm

k=1

logq

−m/2

λk

=2 m

k=1

logq−m/2+k/2−k+2 Pm

k=1

logq

−m/2

λk

=−m22+mlogq−2 logq

m

k=1 k+2

Pm

k=1

logq

−m/2

λk .

(5)

q

On the other hand, by the definition of theq-Bessel function, we have

Fq−m/2e=

k=0

(−1)k qk(k+1)/2−mk

qν+1;q

k(q;q)ke

2ikθ

=(−1)m q

(−m2+m)/2

qν+1;q

m(q;q)me

2imθ

×

k=−m

(−1)k q

k(k+1)/2

qm+ν+1;q

k

qm+1;q

k

e2ikθ.

(2.18)

Then we have

logFq−m/2eiθ=−m22+mlogq−logqν+1;qm−log(q;q)m

+log

k=−m

(−1)k q

k(k+1)/2

qm+ν+1;q

k

qm+1;q

k

e2ikθ (2.19) so that lim m→∞ 1 2π 2π 0

logFq−m/2e

= lim m→∞

−m2+m

2 logq−log

qν+1;q

∞−log(q;q)∞

+lim m→∞ 1 2π 2π 0 log

k=−m

(−1)k qk(k+1)/2

qm+ν+1;q

k

qm+1;q

k

e2ikθ

dθ.

(2.20)

Now observe that

lim m→∞

k=−m

(−1)k qk(k+1)/2

qm+ν+1;q

k

qm+1;q

k

e2ikθ=

k=−∞

(−1)kqk(k+1)/2e2ikθ.

(2.21)

The above limit is uniform inθ. By the Jacobi triple product identity [4],

k=−∞

−q1/2e2iθk

q1/2k2=

q;qe2;e2;q

(6)

Using the uniform convergence to interchange the limit and the integral, lim m→∞ 1 2π 2π 0 log

k=−m

(−1)k qk(k+1)/2

qm+ν+1;q

k

qm+1;q

k

e2ikθ

= 1 2π 2π 0

logq;qe2;e2;q

∞dθ

=log(q;q)∞+21

π 2π

0 log

qe2;q

∞dθ

+21

π 2π

0

loge−2;q

∞dθ

=log(q;q)∞+

j=0

1 2π

2π

0 log

1qj+1

e2iθ∞dθ

+

j=0

1 2π

2π

0 log

1−qje−2iθ∞dθ

=log(q;q)∞.

(2.23)

The integrals in the third equality above vanish because of the mean value theorem for harmonic functions.

We have thus concluded that

lim m→∞ 1 2π 2π 0 log F

q−m/2eiθdθ

= lim m→∞

−m2+m

2 logq−log

qν+1;q

∞.

(2.24)

From (2.17), we can write

lim m→∞  2 Pm

k=1

logq− m/2

λk

 lim

m→∞

 2 logq

m

k=1 k

= −logqν+1;q∞. (2.25)

But, as can be seen by the Taylor expansion ofα(ν)k (q),k=O(qk), and this impliesk=1k<∞.

Also

Pm

k=1

logq− m/2

λk > logq−

m/2

λ1 → ∞ asm→ ∞. (2.26)

(7)

q

Remark2.4. It follows from (2.25) thatk=0k=log(qν+1;q)∞/2 logq.

Remark2.5. Observe that for fixedj, we can always choosemsufficiently large so that

qm+j+ν+1<1qm+j+11qj+1,

qj+m+ν<1qαmν(q)+j1qm+j. (2.27)

Thus, we have the asymptotic behaviour

wk q−m/2 whenm → ∞ (2.28)

without the restrictionqν+1< (1q)2. In [5], Ismail conjectured that

(1) limm→∞qm/2wm(ν)(q)=1,

(2) limm→∞wm(ν)+1(q2)/wm(ν)(q2)=1/q.

The asymptotic relation (2.28) establishes these conjectures.

Remark 2.6. Lemmas 2.1 and 2.2 and Theorem 2.3 state that the roots

wk(ν)(q)satisfy the inequalities

q−m/2+α(ν)m (q)< w(ν)

k (q) < q−m/

2

. (2.29)

These bounds are quite accurate. This is evident if we estimate the length of the interval containing the roots. A somewhat tedious calculation with Taylor series shows that

q−m/2q−m/2+αm(ν)(q)=qm/2O(1). (2.30)

Clearly, for fixedq satisfying the conditions of the theorem, the bounds be-come increasingly accurate as eitherkorνincreases.

References

[1] L. V. Ahlfors,Complex Analysis, 3rd ed., McGraw-Hill, New York, 1979.

[2] J. Bustoz and J. L. Cardoso,Basic analog of Fourier series on aq-linear grid, J. Approx. Theory112(2001), no. 1, 134–157.

[3] J. Bustoz and S. K. Suslov,Basic analog of Fourier series on aq-quadratic grid, Methods Appl. Anal.5(1998), no. 1, 1–38.

[4] G. Gasper and M. Rahman,Basic Hypergeometric Series, Encyclopedia of Math-ematics and Its Applications, vol. 35, Cambridge University Press, Cam-bridge, 1990.

[5] M. E. H. Ismail,Some properties of Jacksons thirdq-Bessel function, to appear. [6] ,The zeros of basic Bessel functions, the functionsJν+ax(x), and associated

orthogonal polynomials, J. Math. Anal. Appl.86(1982), no. 1, 1–19. [7] F. H. Jackson,On generalized functions of Legendre and Bessel, Trans. Roy. Soc.

Edin.41(1904), 1–28.

(8)

[9] R. F. Swarttouw,The Hahn-Extonq-Bessel function, Ph.D. thesis, Technische Uni-versiteit Delft, Delft, the Netherlands, 1992.

L. D. Abreu: Department of Mathematics, University of Coimbra, Coimbra 3000, Por-tugal

E-mail address:[email protected]

J. Bustoz: Department of Mathematics, Arizona State University, Tempe, AZ 85287-1804, USA

E-mail address:[email protected]

J. L. Cardoso: Department of Mathematics, University of Tras-os-Montes and Alto Douro, Vila Real 5000-410, Portugal

References

Related documents