Volume 2011, Article ID 676020,8pages doi:10.1155/2011/676020
Research Article
On
BE
-Semigroups
Sun Shin Ahn
1and Young Hee Kim
21Department of Mathematics Education, Dongguk University, Seoul 100-715, Republic of Korea 2Department of Mathematics, Chungbuk National University, Chongju 361-763, Republic of Korea
Correspondence should be addressed to Young Hee Kim,[email protected]
Received 26 January 2011; Accepted 2 March 2011
Academic Editor: Young Bae Jun
Copyrightq2011 S. S. Ahn and Y. H. Kim. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
The notion of aBE-semigroup is introduced, and related properties are investigated. The concept of leftresp., rightdeductive systems of aBE-semigroup is also introduced.
1. Introduction
Hu and Li, Is´eki and Tanaka, respectively, introduced two classes of abstract algebras:
BCK-algebras and BCI-algebras 1–3. It is known that the class of BCK-algebras is a proper
subclass of the class ofBCI-algebras. In1,4Hu and Li introduced a wide class of abstract
algebras:BCH-algebras. They have shown that the class ofBCI-algebras is a proper subclass
of the class of BCH-algebras. We refer to 5 for general information on BCK-algebras.
Neggers and Kim6introduced the notion of ad-algebra which is a generalization of
BCK-algebras, and also they introduced the notion of aB-algebra7,8, that is,Ix∗x 0,II
x∗0x,III x∗y∗zx∗z∗0∗y, for anyx, y, z∈X, which is equivalent to the idea
of groups. Moreover, Jun et al.9introduced a new notion, called anBH- algebra, which is
another generalization ofBCH/BCI/BCK-algebras, that is,I,II, andIVx∗y 0 and
y∗x 0 imply thatx y for anyx, y ∈ X. Walendziak obtained other equivalent set of
axioms for aB-algebra10. Kim et al.11introduced the notion of apre-Coxeter algebra
and showed that a Coxeter algebra is equivalent to an abelian group all of whose elements
have order 2, that is, a Boolean group. C. B. Kim and H. S. Kim12introduced the notion
of aBM-algebra which is a specialization ofB-algebras. They proved that the class of
BM-algebras is a proper subclass ofB-algebras and also showed that aBM-algebra is equivalent
to a 0-commutativeB-algebra. In13, H. S. Kim and Y. H. Kim introduced the notion of a
an equivalent condition of the filter inBE-algebras. In14,15, Ahn and So introduced the
notion of ideals inBE-algebras and proved several characterizations of such ideals.
In this paper, by combiningBE-algebras and semigroups, we introduce the notion of
BE-semigroups. We define leftresp., rightdeductive systemsLDSresp., RDSfor short
of a BE-semigroup, and then we describe LDS generated by a nonempty subset in a
BE-semigroup as a simple form.
2. Preliminaries
We recall some definitions and results discussed in13.
Definition 2.1see13. An algebraX;∗,1of type2, 0is called aBE-algebra if
BE1x∗x1 for allx∈X,
BE2x∗11 for allx∈X,
BE31∗xxfor allx∈X,
BE4x∗y∗z y∗x∗zfor allx, y, z∈Xexchange.
We introduce a relation “≤” onXbyx≤yif and only ifx∗y1.
Proposition 2.2see13. IfX;∗,1is aBE-algebra, thenx∗y∗x 1 for anyx, y∈X.
Example 2.3see13. LetX:{1, a, b, c, d,0}be a set with the following table:
∗ 1 a b c d 0
1 1 a b c d 0
a 1 1 a c c d
b 1 1 1 c c c
c 1 a b 1 a b
d 1 1 a 1 1 a
0 1 1 1 1 1 1
2.1
ThenX;∗,1is aBE-algebra.
Definition 2.4see13. ABE-algebra X;∗,1is said to be self-distributive ifx∗y∗z
x∗y∗x∗zfor allx, y, z∈X.
Example 2.5see13. LetX:{1, a, b, c, d}be a set with the following table:
∗ 1 a b c d
1 1 a b c d
a 1 1 b c d
b 1 a 1 c c
c 1 1 b 1 b
d 1 1 1 1 1
2.2
Note that theBE-algebra inExample 2.3is not self-distributive, sinced∗a∗0 d∗d
1, whiled∗a∗d∗0 1∗aa.
Proposition 2.6. LetXbe a self-distributiveBE-algebra. Ifx≤y, thenz∗x≤z∗yandy∗z≤x∗z
for anyx, y, z∈X.
Proof. The proof is straightforward.
3.
BE
-Semigroups
Definition 3.1. An algebraic system X;,∗,1 is called a BE-semigroup if it satisfies the
following:
i X;is a semigroup,
ii X;∗,1is aBE-algebra,
iiithe operation “” is distributiveon both sidesover the operation “∗”.
Example 3.2. 1Define two operations “” and “∗” on a setX :{1, a, b, c}as follows:
1 a b c
1 1 1 1 1
a 1 1 1 1
b 1 1 1 1
c 1 a b c
∗ 1 a b c
1 1 a b c
a 1 1 b c
b 1 a 1 c
c 1 1 1 1
3.1
It is easy to see thatX;,∗,1is aBE-semigroup.
2Define two binary operations “” and “∗” on a setA:{1, a, b, c}as follows:
1 a b c
1 1 1 1 1
a 1 1 1 1
b 1 1 1 b
c 1 1 b c
∗ 1 a b c
1 1 a b c
a 1 1 b c
b 1 a 1 c
c 1 1 1 1
3.2
It is easy to show thatA;,∗,1is aBE-semigroup.
Proposition 3.3. LetX;,∗,1be aBE-semigroup. Then
i ∀x∈X 1xx11,
ii ∀x, y, z∈X x≤y⇒xz≤yz,zx≤zy.
Proof. iFor allx ∈ X, we have that 1x 1∗1x 1x∗1x 1 andx1
iiLetx, y, z∈Xbe such thatx≤y. Then
xz∗yzx∗yz1z1,
zx∗zyzx∗yz11. 3.3
Hencexz≤yzandzx≤zy.
Definition 3.4. An elementa/1in aBE-semigroupX;,∗,1is said to be a leftresp., right
unit divisor if
∃b/1∈X ab1 resp., ba1. 3.4
A unit divisor is an element ofXwhich is both a left and a right unit divisors.
Theorem 3.5. LetX;,∗,1be aBE-semigroup. If it satisfies the left (resp., right ) cancellation law
for the operation, that is,
∀x/1, y, z∈A xyyzresp., yxzx⇒yz, 3.5
thenXcontains no left (resp., right) unit divisors.
Proof. LetX;,∗,1satisfy the left cancellation law for the operationand assume thatx
y1 wherex /1. Thenxy1x1 byProposition 3.3i, which impliesy1. Similarly
it holds for the right case. Hence there is no leftresp., rightunit divisors inX.
Now we consider the converse ofTheorem 3.5.
Theorem 3.6. LetX;,∗,1be aBE-semigroup in which there are no left (resp., right ) unit divisors.
Then it satisfies the left (resp., right) cancellation law for the operation.
Proof. Letx, y, z∈Xbe such thatxyxzandx /1. Then
xy∗zxy∗xz 1,
xz∗y xz∗xy1. 3.6
SinceXhas no left unit divisor, it follows thaty∗z1z∗yso thatyz. The argument is
the same for the right case.
Definition 3.7. LetX;,∗,1be aBE-semigroup. A nonempty subsetDofXis called a left
resp., right deductive systemLDSresp., RDS, for shortif it satisfies
ds1XD⊆Dresp.,DX⊆D,
Example 3.8. LetX:{x, y, z,1}be a set with the following Cayley tables:
1 x y z
1 1 1 1 1
x 1 x 1 1
y 1 1 y z
z 1 1 z y
∗ 1 x y z
1 1 x y z
x 1 1 y z
y 1 1 1 z
z 1 1 1 1
3.7
It is easy to show thatX;,∗,1is aBE-semigroup. We know thatD:{1, x}is an LDS ofX,
butE:{1, y}is not an LDS ofX, sincezyz /∈Eand/ory∗x1∈E,y∈Ebutx /∈E.
LetX;∗,1be aBE-algebra, and leta, b∈X. Then the set
Aa, b:{x∈X|a∗b∗x 1} 3.8
is nonempty, since 1, a, b∈Aa, b.
Proposition 3.9. IfDis an LDS of aBE-semigroupX;,∗,1, then
∀a, b∈D Aa, b⊆D. 3.9
Proof. Letx∈Aa, bwherea, b∈D. Thena∗b∗x 1∈Dand sox∈Dbyds2. Therefore
Aa, b⊆D.
Theorem 3.10. Let{Di}be an arbitrary collection of LDSs of aBE-semigroupX;,∗,1, wherei
ranges over some index setI. Then∩i∈IDiis also an LDS ofA.
Proof. The proof is straightforward.
LetX;,∗,1be aBE-semigroup. For any subsetDofX, the intersection of all LDSs
resp., RDSs of X containing D is called the LDSs resp., RDSs generated by D, and is
denoted by Dl resp., Dr. It is clear that if D and E are subsets of a BE-semigroup
X;,∗,1satisfyingD ⊆E, thenDl ⊆ Elresp.,Dr ⊆ Er, and ifDis an LDSresp.,
RDSofX, thenDlDresp.,Dr D.
ABE-semigroupX;,∗,1is said to be self-distributive ifX;∗,1is a self-distributive
BE-algebra.
Theorem 3.11. LetX;,∗,1be a self-distributiveBE-semigroup and letDbe a nonempty subset of
Xsuch thatAD⊆D. ThenDl:{a∈X|yn∗· · ·∗y1∗a· · · 1 for somey1, . . . , yn∈D}.
Proof. Denote
B:a∈X|yn∗· · · ∗y1∗a
· · ·1 for somey1, . . . , yn∈D
Leta∈Xandb∈B. Then there existy1, . . . , yn ∈Dsuch thatyn∗· · · ∗y1∗b· · · 1. It
follows that
1x1
xyn∗· · · ∗y1∗b
· · ·
xyn∗· · · ∗xy1
∗xb· · ·.
3.11
Sincexyi∈Dfori1, . . . , n, we have thatxb∈B. Letx, a∈Xbe such thata∗x∈Band
a∈B. Then there existy1, . . . , yn, z1, . . . , zm∈Dsuch that
yn∗· · · ∗y1∗a∗x
· · ·1, 3.12
zm∗· · · ∗z1∗a· · · 1. 3.13
UsingBE4, it follows from3.12thata∗yn∗· · · ∗y1∗x· · · 1, that is,a≤yn∗· · · ∗
y1∗x· · ·, and so from3.13andProposition 2.6it follows that
1zm∗· · · ∗z1∗a· · ·
≤zm∗· · · ∗z1∗
yn∗· · · ∗y1∗x
· · ·· · ·. 3.14
Thuszm∗· · · ∗z1∗yn∗· · · ∗y1∗x· · ·· · · 1, which impliesx∈ B. ThereforeBis
an LDS ofX. ObviouslyD ⊆B. LetGbe an LDS containingD. To showB ⊆G, letabe any
element ofB. Then there existy1, . . . , yn ∈Dsuch thatyn∗· · · ∗y1∗a· · · 1. It follows
fromds2thata∈Gso thatB⊆G. Consequently, we have thatDlB.
In the following example, we know that the union of any LDSsresp., RDSsDandE
may not be an LDSresp., RDSof a self-distributiveBE-semigroupX;·,∗,1.
Example 3.12. LetX:{1, a, b, c, d}be a set with the following Cayley tables:
1 a b c d
1 1 1 1 1 1
a 1 1 1 1 1
b 1 1 1 1 1
c 1 1 1 1 1
d 1 1 1 1 d
∗ 1 a b c d
1 1 a b c d
a 1 1 b b d
b 1 a 1 a d
c 1 1 1 1 d
d 1 1 b b 1
3.15
It is easy to check thatX;,∗,1is a self-distributive BE-semigroup. We know that D :
{1, a}andE:{1, b}are LDSs ofX, butD∪E{1, a, b}is not an LDS ofX, sinceb∗ca∈
D∪E,c /∈D∪E.
Theorem 3.13. LetDandEbe LDSs of a self-distributiveBE-semigroupX;·,∗,1. Then
D∪El:
Proof. Denote
K:a∈X |x∗y∗a1 for somex∈D, y∈E. 3.17
Obviously,K ⊆ D∪El. Letb ∈ D∪El. Then there exist y1, . . . , yn ∈ D∪Esuch that
yn∗· · · ∗y1∗b· · · 1 byTheorem 3.11. Ifyi ∈Dresp.,Efor alli1, . . . , n, thenb∈D
resp.,E. Henceb∈Ksinceb∗1∗b 1resp., 1∗b∗b 1. If some ofy1, . . . , ynbelong
toDand others belong toE, then we may assume thaty1, . . . , yk∈Dandyk1, . . . , yn∈Efor
1≤k < n, without loss of generality. Letpyk∗· · · ∗y1∗b· · ·. Then
yn∗· · · ∗yk1∗p
· · ·
yn∗· · · ∗yk1∗
yk∗· · · ∗y1∗b
· · ·· · ·
1,
3.18
and sop∈E. Now letqp∗b yk∗· · · ∗y1∗b· · ·∗b. Then
yk∗· · · ∗y1∗q
· · ·
yk∗· · · ∗y1∗
yk∗· · · ∗y1∗b
· · ·∗b· · ·
yk∗· · · ∗y1∗b
· · ·∗yk∗· · · ∗y1∗b
· · ·
1,
3.19
which implies thatq∈D. Sincep∗q∗b q∗p∗b q∗q1, it follows thatb∈Kso that
D∪El⊆K. This completes the proof.
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