231586521 Calculator Techniques New

MATHEMATICS

and

CALCULATOR

TECHNIQUES

THE MEMORY VARIABLES

MEMORY

CALCULATOR BUTTONS

A

ALPHA (-)

B

ALPHA

O

‘ “

C

ALPHA hyp

D

ALPHA sin

E (ES PLUS only)

ALPHA cos

F (ES PLUS only)

ALPHA tan

X

ALPHA )

Y

ALPHA S D

M

ALPHA M+

HOW TO CLEAR MEMORY

• SHIFT 9 1 =

– This means you will automatically go to MODE 1

• SHIFT 9 2 =

– All values stored in the memory variables will be

erased

• SHIFT 9 3 =

– This means you will automatically go to MODE 1

and all values stored in the memory variables

will be erased.

MODE 1 :

GENERAL

Sec)

Min

(Degree

DMS

to

.

Convert

237

615

0

HOW TO CONVERT BETWEEN

DEGREES, RADIANS AND GRADIANS

BASICS

"

54

'

36

237

237.615

:

0 O

DISPLAY

degrees.

decimal

to

47'12"

21

Convert

0

HOW TO CONVERT BETWEEN

DEGREES, RADIANS AND GRADIANS

BASICS

7

21.7866666

12

47

21

:

0 0 0

DISPLAY

.

120

0

to

radians

Convert

HOW TO CONVERT BETWEEN

DEGREES, RADIANS AND GRADIANS

BASICS



3

2

120

:

0

DISPLAY

degrees.

to

radians

2

π

Convert

HOW TO CONVERT BETWEEN

DEGREES, RADIANS AND GRADIANS

BASICS

90

2

:

r



DISPLAY

system?

centesimal

in

120

is

What

0

PAST CE BOARD EXAM

BASICS

ENTER

3

400

20

1

:

0

DISPLAY

HOW TO GET THE POLAR AND

RECTANGULAR COORDINATE OF A

POINT IN THE CARTESIAN PLANE

BASICS

30993247

.

56

,

211102551

.

7

)

6

,

4

(

:











r

Pol

DISPLAY

PAST CE BOARD EXAM

6).

-(4,

point

the

of

coordinate

polar

the

Find

HOW TO GET THE POLAR AND

RECTANGULAR COORDINATE OF A

POINT IN THE CARTESIAN PLANE

BASICS

PAST ECE BOARD EXAM

P (-3,-4)

point

t he

cont ains

side

t erminal

t he

if

cos

of

value

t he

Find



:

Solution

HOW TO GET THE POLAR AND

RECTANGULAR COORDINATE OF A

POINT IN THE CARTESIAN PLANE

BASICS

PAST ECE BOARD EXAM

8698976

.

126

,

5

)

4

,

3

(

:













r

Pol

DISPLAY

Y.

to

and

X

lly to

automatica

stored

is

r

:

NOT E



5

3

)

cos(

:



Y

DISPLAY

BASICS

).

(3,120

is

coordinate

polar

whose

point

a

of

coordinate

r

rect angula

the

Find

0

59807621

.

2

,

5

.

1

Rec(3,120)

:

DISP LAY







Y

X

HOW TO SOLVE COMBINATION

AND PERMUTATION PROBLEMS.

BASICS

PAST ECE BOARD EXAM

collinear?

are

which

of

three

no

points

distinct

10

by

formed

are

gles

many trian

How

10C3.

is

point s

collinear

non

10

from

formed

be

can

t hat

t riangles

of

number

T he

:

Solut ion

120

3

10

:

DISP LAY

C

BASICS

cont est ?

essay

st udent

a

in

finalist s

10

t he

among

from

up

runner

first

t he

and

winner

t he

choose

judges

can t he

ways

different

many

how

In

here

import ant

is

order

:

Not e

t ime.

a

at

2

t aken

finalist s

10

are

T here

:

Solut ion

90

2

10

:

DISP LAY

P

HOW TO EVALUATE FACTORIAL

NUMBERS

BASICS

10!

of

value

the

Find

18.

3628800

!

10

:

DISP LAY

BASICS

I?

MISSISSIP P

let t ers

t he

from

made

be

can

ns

permut at io

different

many

How

1!4!2!2!

11!

:

is

ns

permut at io

different

of

number

T he

:

Not e

11.

Let t ers

of

Number

4;

s

S'

2;

s

P '

4;

s

I'

1;

M

of

Number

:

Solut ion











BASICS

PAST EE BOARD EXAM

34650

x4!

x2!

!

4

x

!

1

!

11

:

DISP LAY

6

5

3

3

6

11

. Evaluate

f(

) if f(x)



x

4



x

2

-

x



HOW TO EVALUATE

FUNCTIONS

BASICS

3 2 2 2 3

2

3

4

,

3

,

4

12

. Evaluate

f(



) if f(x

y)



x

y



x

y-

xy



y

HOW TO EVALUATE

FUNCTIONS

BASICS

2.

by x

divided

is

4

x

4x

-2x

3x

when

remainder

the

Find

4



3 2







PAST ME BOARD EXAM

BASICS

)

f(-rem ainder

,

x

x

-x

x

f(x)

Solution:

2

4

4

2

3

4



3 2









?

x

-x

-x

x

of x

) a factor

Is (x

.

3

6

6

5

8

4

6

3

9

2

13







HOW TO EVALUATE

FUNCTIONS

BASICS 2 3 4 5 6

9

6

8

6

of

fact or

a

is

3

t hen x

0,

f(-3)

Since

:

x

-x

-x

x

x

Conclusion









ADVANCE

PAST ECE BOARD EXAM

:

ENTER

1.5 Y 0, 3 2Y : DISP LAY  

3.

2

by

divided

is

4

8

18

4

when

remainder

the

Find

y

3



y

2



y



y



y.

for

solve

and

zero

divisor to

Set the

:

Concept

:

ENTER

11 is remainder T he : Answer 11 4 -8Y Y 18 Y 4 : DISP LAY 2 3  

HOW TO USE THE ∑ SIGN

BASICS

20

...

3

2

1

sum.

the

Find









210

:

DISP LAY

20 1

x

x





)

4

(

5

)

3

(

4

x

x

SOLVE







HOW TO SOLVE LINEAR

EQUATIONS

1

9

2

6

1

12

3













x

x

x

SOLVE

HOW TO SOLVE LINEAR

EQUATIONS

?

,

9

,

2

,

4

),

2

2

(

7

Y

of

value

the

is

what

A

and

D

X

Y

X

D

A

If











HOW TO SOLVE A

SPECIFIC VARIABLE

BASICS

.

5

7

.

5

9

,

5

3

num ber

the

tim es

than

less

Find

num ber

the

tim es

than

less

is

result

the

num ber

a

than

less

by

m ultiplied

is

When

PAST ECE BOARD EXAM

PAST ECE BOARD EXAM

HOW TO USE MULTILINE FUNCTION

BASICS

12m.

8m,

6m,

are

sides

whose

triangle

a

of

area

the

Find

:

ENTER

PAST EE BOARD EXAM

2

c

b

a

s

c)

-b)(s

-a)(s

-s(s

A

:

Formula

s

Heron'

Using

:

Solut ion









HOW TO USE MULTILINE FUNCTION

BASICS

:

ENTER

C)

-B)(X

-A)(X

-X(X

:

2

C

B

A

X

:

DISP LAY







PAST EE BOARD EXAM

13

2

C

B

A

X

:

DISP LAY







455

)

)(

)(

(

:

DISP LAY

C

X

B

X

A

X

X







HOW TO SOLVE TRIGONOMETRIC

EQUATIONS

BASICS

360

0

:

2tan

3

-5tan

Solve

x



x



x



:

ENTER

0

R

-L

30

X

t an x

2

3

t an x

5

:

DISP LAY







:

ENTER

0

R

-L

210

X

t an x

2

3

t an x

5

:

DISP LAY







0 0

210

and

30

X

:

Answer



HOW TO USE LOGARITHMIC EQUATIONS

BASICS

10

5)

(x

log

x

log

in

for x

Solve

₂



₂





:

ENTER

PAST ME BOARD EXAM

0

R

-L

9

29.5975076

X

10

5)

(x

log

x

log

:

DISP LAY

2 2











HOW TO USE LOGARITHMIC EQUATIONS

BASICS

100x

in x

for x

Solve

3log x



PAST ECE BOARD EXAM

0

R

-L

10

X

100

:

DISP LAY

log 3







x

x

x

BASICS

HOW TO GET THE

DERIVATIVE AT A POINT

.

3

when

3

of

derivative

the

Find

x

3



x

2

x



:

ENTER

45

)

3

(

:

DISP LAY

3 2 3 



x

X

X

dx

d

PAST ECE BOARD EXAM

)

1

(

2

.

2

.

)

1

(

.

)

1

(

2

.

1

equat ion

t he

ate

Different i

2 2 2 2













x

x

d

x

c

x

x

b

x

x

x

a

x

x

y

d.

subst it ut e

is

x

of

value

same

when

choices

t he

of

value

t he

t o

value

t his

compare

and

2

say x

x,

of

any value

at

y

at e

Different i

:

T echnique



:

ENTER

8888888889 . 0 2 1 : DISP LAY 2         x x x dx d ADVANCE

PAST ECE BOARD EXAM

d.

substitute

being

is

x

of

value

the

as

choices

the

it to

Compare

:

Note

2

x

Substitute

)

1

(

2

)

₂ 2







x

x

x

a

:

ENTER

8888888889 . 0 ) 1 ( 2 : DISP LAY 2 2   x x x

 

 

 

3 4 ) 1 ( . 4 2 . 3 2 ) 1 ( . : follows as summarized are 2 when x choices t he of rest t he of values T he 2 2 2 2          x x x x x d x c x x b

 

2 ₂ ) 1 ( 2 a. : Answer   x x x ADVANCE

BASICS

HOW TO INTEGRATE



2





1 5

)

1

3

(

Evaluate

x

x

dx

:

ENTER

16

1

3

:

DISP LAY

2 1 5

dx

x

x







MODE 2 :

COMPLEX NUMBER

CALCULATIONS

HOW TO SOLVE COMPLEX NUMBERS

BASICS

argument .

t he

Find

b.

value.

absolut e

t he

Find

a.

4i

-3

z

number

complex

For t he



0

53.13

is

argument

the

and

5

is

value

absolute

T he

:

Answer

13010235

.

53

5

4

3

:

DISP LAY









i 

r



HOW TO SOLVE COMPLEX NUMBERS

BASICS

product.

the

find

2i),

3i)(5

-(2

:

Given



i

i

i

11

16

)

2

5

)(

3

2

(

:

DISP LAY







:

ENTER

HOW TO SOLVE COMPLEX NUMBERS

BASICS

2i

-5

2i

4

:

Simplify



i

i

i

29

23

29

14

2

5

3

4

:

DISP LAY







:

ENTER

HOW TO GET THE COMPONENT OF A

FORCE AND RESULTANT OF FORCES

BASICS 0

37

300N

F

force

the

of

components

y

and

x

the

Find





i

5445069

.

180

590635

.

239

37

300

:

DISPLAY

0





:

ENTER

N.

180.54

is

component

y

the

and

N

239.5

is

component

x

T he

:

Answer

HOW TO GET THE COMPONENT OF A

FORCE AND RESULTANT OF FORCES

BASICS

.

40

00

8

F

force

the

of

component s

y

and

x

the

Find

0

Quadrant

III

at

angle

with

lbs



i

5142300877

8355545

.

612

220

800

:

DISP LAY

0







:

ENTER

514.23lbs.

-is

component

y

t he

and

612.84lbs

-is

component

x

T he

:

Answer

0

220

800

40)

(180

800

F

as

force

the

Express

:

Solution











HOW TO GET THE COMPONENT OF A

FORCE AND RESULTANT OF FORCES

BASICS

.

140

angle

of

an

wit h

400N

F

and

60

at

350N

F

forces,

t he

of

result unt

t he

Find

0 2 0 1





2017875

.

103

4315683

.

575

140

400

60

350

:

DISP LAY

0 0









:

ENTER

e)

erclockwis

axis(count

-x

with the

103.20

with

575.43N

is

resultant

the

of

magnitude

T he

:

Answer

0



140

400

60

350

numbers

complex

t he

of

sum

t he

is

result ant

T he

:

Solut ion







ADVANCE

number.

imaginary

an

is

where

expression

he

Simplify t

i

1997



i

1999

i

:

ENTER

PAST EE/ECE BOARD EXAM

remainder.

get the

and

4

to

exponents

the

Divide

:

T echnique

4 1 499 4 1997 : DISP LAY 

ENTER

:

4 3 499 4 1999 : DISP LAY  1) (i 1 t o s correspond remainder) (0 number whole i) -(i i t o s correspond 3/4 i) (i 1 t o s correspond 2/4 i) (i i t o s correspond 1/4 : Not e 4 3 2 1    

_ENTER

_:

Answer) ( 0 : DISP LAY i i 

ADVANCE

number?

imaginary

an

is

where

)

1

(

of

value

the

Find



i

5

i

:

ENTER

PAST CE/ECE BOARD EXAM

2 3

)

1

(

)

1

(

as

Rewrite

:

T echnique



i



i

:

ENTER

i i i 4 4 ) 1 ( ) 1 ( : DISP LAY 2 3    

MODE 3 :

STATISTICAL AND

REGRESSION

HOW TO FIND THE MEAN AND

STANDARD DEVIATION

BASICS

mean.

t he

Find

hrs.

888

and

852,

840,

859,

867,

last ing

aft er

out

burned

bulbs

light

Five

2

.

861

:

DISP LAY

x

888

5

852

4

840

3

859

2

867

1

:

DISP LAY

x

BASICS

PAST ME BOARD EXAM

197

183

176

164

156

144

132

112

:

Dat a

deviat ion.

st andard

t he

det ermine

dat a,

l

st at ist ica

following

Given t he

ENTER

197 8 183 7 176 6 164 5 156 4 144 3 132 2 112 1 : DISP LAY x

21545346

.

26

x

:

DISP LAY



HOW TO GET THE MEAN, VARIANCE

AND STANDARD DEVIATION OF

GROUPED DATA

BASICS 3 80 7 5 77 6 8 74 5 15 71 4 12 68 3 5 65 2 2 62 1 : DISP LAY FREQ x

HOW TO GET THE MEAN, VARIANCE

AND STANDARD DEVIATION OF

GROUPED DATA

BASICS 50 : DISP LAY n 94 . 70 : DISP LAY x 391132065 . 4 : DISP LAY sx 28204082 . 19 : DISP LAY 2 Ans

HOW TO FIND AREAS IN THE

NORMAL CURVE

BASICS

a

z

t o

0

z

from

area

means

Q(a)

z

t o

a

z

from

area

means

R(a)

a

z

t o

-z

from

area

means

P (a)



















HOW TO FIND AREAS IN THE

NORMAL CURVE

BASICS

1.64.

z

of

left

t he

t o

curve

normal

under t he

area

t he

Find



:

ENTER

9495

.

0

P (1.64)

:

DISP LAY

HOW TO FIND AREAS IN THE

NORMAL CURVE

BASICS

1.58.

-point

t he

and

0

z

bet ween

curve

normal

st andard

a

beneat h

area

t he

Find



:

ENTER

44295

.

0

Q(-1.58)

:

DISP LAY

HOW TO FIND AREAS IN THE

NORMAL CURVE

BASICS

mean.

t he

of

deviat ion

st andard

1

z

wit hin

be

will

variable

random

on

dist ribut i

normal

a

y t hat

probabilit

t he

Find



:

ENTER

68268

.

0

Q(1)

Q(-1)

:

DISP LAY



1.

z

to

1

-z

from

area

for the

looking

are

We

:

Solution





HOW TO FIND AREAS IN THE

NORMAL CURVE

BASICS

mean.

t he

above

deviat ion

st andard

1.5

t han

more

lie

will

variable

random

d

dist ribut e

normally

a

y t hat

probabilit

t he

Find

:

ENTER

0.066807

R(1.5)

:

DISP LAY

.

z

to

1.5

z

from

area

for the

looking

are

We

:

Solution







HOW TO SOLVE LINEAR REGRESSION

PROBLEMS

HOW TO SOLVE LINEAR REGRESSION

PROBLEMS

BASICS

:

ENTER

2 0 10 5 2 9 6 4 8 4 6 7 8 8 6 7 10 5 6 14 4 11 16 3 10 18 2 12 20 1 : DISP LAY y x 1359045 . 3 A : DISP LAY 409 0.40449955 B : DISP LAY

HOW TO SOLVE LINEAR REGRESSION

PROBLEMS

BASICS

09X

0.40449954

3.1359045

Y

BX

A

Y

is

equat ions

regression

T he

:

T herefore









:

t

coefficien

n

correlatio

the

determine

To

.

b

8854825905

.

0

r

:

DISP LAY

:

23

X

when

Y

of

value

e

predict th

T o

.

c



43939394

.

12

23

:

DISP LAY

y

HOW TO GET THE EQUATION OF A

LINE GIVEN 2 POINTS

BASICS

(-3,8).

and

(2,5)

t hrough

passes

t hat

line

t he

of

equat ion

t he

Find

5

31

A

:

DISP LAY

:

ENTER

PAST ECE BOARD EXAM

8 3 2 5 2 1 : DISP LAY  y x

5

3

B

:

DISP LAY



HOW TO GET THE EQUATION OF A

LINE GIVEN 2 POINTS

BASICS

31

5

3

3

31

5

:

5

3

5

31

Y

BX

A

Y

:

is

line

t he

of

equat ion

t he

:

T herefore

















Y

X

X

Y

or

X

HOW TO GET A POINT ON THE LINE

GIVEN TWO POINTS

BASICS

y)?

(-5,

in

y

of

value

t he

and

(x,4)

in

x

of

value

t he

is

what

line,

on t he

is

y)

(x,

and

(3,-7)

and

(4,1)

t hrough

passes

line

a

If

8

35

ˆ

4

:

DISP LAY

x

8

35

y

4,

When x

:

Answer





HOW TO GET A POINT ON THE LINE

GIVEN TWO POINTS

BASICS

71

ˆ

5

:

DISP LAY





y

71

x

5,

-y

When

:

Answer





ADVANCE

PAST ME BOARD EXAM

6 0 0 4 x 2 1 : DISP LAY  y

:

is

6

-y

at

axis

-y

t he

and

4

at x

axis

x

t he

int ercept s

t hat

line

t he

of

equat ion

T he





:

ENTER

6 A : DISP LAY

:

ENTER

:

ENTER

3/2 or 1.5 B : DISP LAY 0 12 -2Y -3X : as rewrit t en be can ich wh 3/2X 6 -Y BX A Y : Answer     

ADVANCE

10...

7,

4,

n

progressio

arithmetic

the

of

term

30

the

Find

th

:

ENTER

PAST CE/ECE BOARD EXAM

:

ENTER

7 2 2 4 1 1 y x : DISP LAY 91 Yˆ 0 3 : DISP LAY

ADVANCE

term?

20

the

to

up

14...

9,

4,

n

progressio

the

of

sum

the

is

What

th

:

ENTER

PAST CE/ECE BOARD EXAM

:

ENTER

9 2 2 4 1 1 y x : DISP LAY 1 A : DISP LAY 

:

ENTER

1 A Ans : DISP LAY  

:

ENTER

5 B :

DISP LAY

_ENTER

_:

5 B Ans : DISP LAY 

ADVANCE

term?

20

the

to

up

14...

9,

4,

n

progressio

the

of

sum

the

is

What

th

PAST CE/ECE BOARD EXAM

:

ENTER

1030 BX A : DISP LAY 20 1



  x

ADVANCE

term.

8

the

Find

1944.

is

6th term

the

and

216

is

GP

the

of

term

4

T he

th th

PAST CE BOARD EXAM

:

ENTER

17496 Yˆ 8 : DISP LAY 1944 6 2 216 4 1 y x : DISP LAY

:

ENTER

MODE 4 :

SPECIFIC NUMBER

SYSTEMS

HOW TO DO BASE NUMBER

CALCULATIONS

BASICS

2).

(base

binary

to

234

Convert

₁₀

:

ENTER

234

ec

234

:

DISP LAY

D

:

ENTER

101010

0000000011

Bin

234

:

DISPLAY

2 10

11101010

234

:



Thus

HOW TO DO BASE NUMBER

CALCULATIONS

BASICS

system.

L

HEXADECIMA

to

1234

Convert

₁₀

:

ENTER

:

ENTER

000004D2

Hex

1234

:

DISPLAY

16 10

0

00004

2

1234

:

D

Thus



HOW TO DO BASE NUMBER

CALCULATIONS

BASICS

system.

OCT AL

to

ABC12

Convert

₁₆

:

ENTER

:

ENTER

2

0000253602

Oct

ABC12

:

DISP LAY

8 16

0

0002536022

ABC12

:



Thus

HOW TO DO BASE NUMBER

CALCULATIONS

BASICS

).

)(3F

(AB

Evaluate

_{16 16}

:

ENTER

:

ENTER

00002A15

Hex

3F

x

AB

:

DISPLAY

HOW TO DO BASE NUMBER

CALCULATIONS

BASICS

10.

base

to

values

all

Convert

:

Solution

10)

base

(in

.

77

AB2

45

11

Evaluate

₂



₁₀



₁₆



₈ 2

11

For

Result

:

3

16

AB2

For

Result

:

2738

8

77

For

Result

:

63

2849

:

Answer

63

2738

45

3

:

Add







HOW TO DO BASE NUMBER

CALCULATIONS

BASICS

)

110

and

101

(

AND

logical

the

Find

_{2 2}

000100

0000000000

Bin

110

and

101

:

DISP LAY

:

ENTER

HOW TO DO BASE NUMBER

CALCULATIONS

BASICS

)

110

and

101

(

XOR

logical

the

Find

_{2 2}

000110

0000000000

Bin

11

xor

101

:

DISP LAY

:

ENTER

MODE 5 :

EQUATION

SOLUTION

1

2

4

7

2









y

x

y

x

SOLVE

HOW TO SOLVE EQUATIONS

IN 2 UNKNOWNS

.

.

,

.

'

,

5

ages

present

their

Find

friend

his

as

old

as

tim es

three

was

she

ago

years

Five

Jun

friend

her

of

age

the

as

twice

be

will

age

s

Ana

years

In

PAST ME BOARD EXAM

PAST ME BOARD EXAM

.

invest ment

each

of

amount

t he

Find

P 1800.

be

would

income

t ot al

t he

ed,

int erchang

were

rat es

int erest

t he

If

P 1700.

is

s

invest ment

t he

from

income

t ot al

T he

int erest .

4%

at

ot her

t he

and

int erest

annual

3%

paying

one

s

invest ment

2

has

man

A

PAST EE BOARD EXAM

PAST EE BOARD EXAM

needed?

is

each

of

much

How

nickel.

6%

cont aining

anot her

wit h

nickel

14%

cont aining

st eel

mixing

by

made

be

t o

is

nickel

8%

cont aining

st eel

of

kg

2000

PAST ECE BOARD EXAM

BASICS

nickel

6%

cont aining

st eel

of

amount

Y

nickel

14%

cont aining

st eel

of

amount

X

:

Let

:





Solution

PAST ECE BOARD EXAM

0

5

7

6

x

2



x





equation

quadratic

Solve the

HOW TO SOLVE

QUADRATIC EQUATIONS

BASICS

0

5

2

2







x

in x

alues of x

Find the v

HOW TO SOLVE

QUADRATIC EQUATIONS

BASICS

0

9

2

5

x

2



x





equation

quadratic

Solve the

HOW TO SOLVE

QUADRATIC EQUATIONS

root s

irrat ional

give

can

It

-ES

OLD

over t he

P LUS

ES

CASIO

of

advant age

t he

is

T his

:

NOT E

BASICS

14 6 16 2 9 4 3 3 z - y x z y x - z y - x if: , y and z alues of x Find the v      

HOW TO SOLVE EQUATIONS

IN 3 UNKNOWNS

HOW TO SOLVE EQUATIONS

IN 3 UNKNOWNS

0

6

5

2

2 3

x -

-x

tion x

cubic equa

Solve the





HOW TO SOLVE CUBIC

EQUATIONS

0

1

3

-

Solve x



HOW TO SOLVE CUBIC

EQUATIONS

MODE 6 :

MATRIX

HOW TO SOLVE PROBLEMS

INVOLVING MATRICES

BASICS

:

ENTER

PAST ECE BOARD EXAM

                     9 8 1 7 1 9 2 9 4 1 7 5 3 3 Simplify t oMATA 9 4 1 7 5 3 St ore : Solut ion           B MAT t o 9 8 1 7 1 9 St ore : Solut ion          

_ENTER

_:

HOW TO SOLVE PROBLEMS

INVOLVING MATRICES

BASICS

PAST ECE BOARD EXAM

:

ENTER

B

MAT

2

A

MAT

3

:

DISP LAY



:

ENTER





















45

28

5

35

17

27

Ans

:

DISP LAY

HOW TO SOLVE PROBLEMS

INVOLVING MATRICES

BASICS A. mat rix t o 2 3 1 -8 7 3 1 -2 3 St ore          

_ENTER

_:

          2 8 1 -3 7 2 1 -3 3 Ans : Ent er A) (Mat T rn : DISP LAY























2

3

1

-8

7

3

1

-2

3

A

if

A

mat rix

of

t ranspose

t he

Find

:

ENTER

HOW TO SOLVE PROBLEMS

INVOLVING MATRICES

BASICS A. mat rix t o 2 7 3 4 1 6 3 1 2 St ore          

_ENTER

_:

          0.061 -0.169 -0.6 0.1538 0.076 -0 0.0153 0.2923 0.4 Ans Mat A : DISP LAY -1























2

7

3

4

1

6

3

1

2

A

if

A

mat rix

of

inverse

t he

Find

:

ENTER

HOW TO COMPUTE THE

DETERMINANT OF A 3X3 MATRIX

BASICS

2

1

8

7

1

2

5

4

2

:

t

determinan

the

Find

228

det (Mat A)

:

DISP LAY

:

ENTER

ADVANCE

area?

t he

is

What

(3,3).

and

(4,0)

(-2,0),

point s

following

t he

by

defined

are

t riangle

a

of

vert ices

t he

s,

coordinat e

Cart esian

a

In

PAST CE BOARD EXAM

:

ENTER

1 3 3 1 0 4 1 0 2 : DISP LAY 1 3 3 1 0 4 1 0 2 det 2 1 A 1 1 1 2 1 A : is ) y , (x and ) y , (x ), y , (x ices wit h vert le any t riang of area T he : Concept 3 3 2 2 1 1 3 3 2 2 1 1    y x y x y x

:

ENTER

9 A) 0.5det (Mat : DISP LAY

MODE 7 :

GENERATING TABLE

FROM A FUNCTION

HOW TO TABULATE VALUES OF A

FUNCTION

BASICS 1197 10 11 888 9 10 637 8 9 438 7 8 285 6 7 172 5 6 93 4 5 42 3 4 13 2 3 0 1 2 3 0 1 F(X) X : DISP LAY 

st ep.

unit

every

10

x

t o

0

x

from

3

2x

x

f(x)

of

values

T abulat e

3 2











:

ENTER

MODE 8 :

VECTOR

HOW TO DO VECTOR CALCULATIONS

BASICS

B.

and

A

vect ors

of

product

cross

t he

Find

c.

B.

and

A

vect or

of

product

dot

t he

Find

b.

B.

and

A

vect ors

of

result ant

t he

of

magnit ude

t he

Find

a.

9k.

5j

3i

B

and

7k

j

-4i

A

:

vect ors

2

Given t he











] 7 1 4 [ A : DISP LAY

:

ENTER

:

ENTER

] 9 5 3 [ B : DISP LAY

HOW TO DO VECTOR CALCULATIONS

BASICS 7 17.9164728 Vct B) Abs(Vct A : DISP LAY 

:

ENTER

:

ENTER

b.

70 Vct B Vct A : DISP LAY 

:

ENTER

c.

23] 15 44 -[ Ans Vct B Vct A : DISP LAY 

HOW TO DO VECTOR CALCULATIONS

BASICS

vector.

cosine

direction

it s

give

and

7k

2j

4i

A

vector

t he

of

magnit ude

t he

is

What







:

ENTER

PAST ME/CE BOARD EXAM

:

ENTER

:

magnit ude

get the

T o

:

ENTER

HOW TO DO VECTOR CALCULATIONS

BASICS

PAST ME/CE BOARD EXAM

Ans)

in

st ored

is

(T his

:

Not e

3

8.30662386

(Vct A)

Abs

:

DISP LAY

:

cosine

direct ion

get t he

T o

0.8427]

0.2407

[0.4815

Ans

:

DISP LAY

THANK YOU VERY

MUCH AND