Gliding, Climbing, and Turning Flight Performance!
Robert Stengel, Aircraft Flight Dynamics, MAE 331, 2014
!
Copyright 2014 by Robert Stengel. All rights reserved. For educational use only.!
http://www.princeton.edu/~stengel/MAE331.html!
http://www.princeton.edu/~stengel/FlightDynamics.html!
•! Conditions for gliding flight"
•! Parameters for maximizing climb angle and rate"
•! Review the V-n diagram"
•! Energy height and specific excess power"
•! Alternative expressions for steady turning flight"
•! The Herbst maneuver!
Learning Objectives! Reading:! Flight Dynamics ! Aerodynamic Coefficients, 130-141! 1!
Gliding Flight!
D = CD 1 2!V2S = "W sin# CL 12 !V2S =W cos# ! h =V sin# ! r =V cos#
Equilibrium Gliding Flight"
3!
Gliding Flight"
•! Thrust = 0"
•! Flight path angle < 0 in gliding flight"
•! Altitude is decreasing"
•! Airspeed ~ constant"
•! Air density ~ constant "
tan! = "D L = "CCDL = h! ! r = dhdr; ! = "tan "1 D L # $ % & ' ( = "cot"1 L D # $ % & ' (
Gliding flight path angle "
Corresponding airspeed "
Vglide = 2W
Maximum Steady Gliding Range"
•! Glide range is maximum when !! is least
negative, i.e., most positive"
•! This occurs at (L/D)max " 5!
Maximum Steady Gliding Range"
•! Glide range is maximum when !! is least
negative, i.e., most positive"
•! This occurs at (L/D)max "
tan! = h! ! r =negative constant = h "ho ( ) r"ro ( ) #r= #h tan! = "#h
"tan! =maximum when LD =maximum
!max ="tan"1 D L # $ % & ' ( min ="cot"1 L D # $ % & ' ( max
Sink Rate, m/s "
•! Lift and drag define !! and V in gliding equilibrium"
D =CD 1 2!V2S= "W sin# sin# =" D W L =CL 1 2!V2S =W cos" V = 2W cos" CL!S ! h=Vsin! =" 2W cos! CL#S D W $ % & ' ( )=" 2W cos! CL#S L W $ % & ' ( ) D L $ % & ' ( ) =" 2W cos! CL#S cos! 1 L D $ % & ' ( )
•! Sink rate = altitude rate, dh/dt (negative)"
7!
•! Minimum sink rate provides maximum endurance"
•! Minimize sink rate by setting "(dh/dt)/"CL = 0 (cos !! ~1)"
Conditions for Minimum Steady Sink Rate"
! h=! 2W cos" CL#S cos" CD CL $ % & ' ( ) =! 2W cos3" #S CD CL3/2 $ % & ' ( ) * ! 2 # W S $ % & ' ( ) CD CL3/2 $ % & ' ( ) CLME = 3CDo ! and CDME = 4CDo
L/D and VME for Minimum Sink Rate" VME = 2W !S CD2ME+CL2ME" 2 W S( ) ! # 3CDo "0.76VL Dmax L D
( )
ME = 1 4 !C3Do = 3 2( )
L D max "0.86 L D( )
max 9!L/D for Minimum Sink Rate"
•! For L/D < L/Dmax, there are two
solutions"
•! Which one produces minimum
sink rate?"
L D
( )
ME ! 0.86( )
LD maxClimbing Flight!
11!
•! Rate of climb, dh/dt = Specific Excess Power "
Climbing Flight" ! V=0= (T !D!W sin") m sin" =(T !D) W ; " =sin!1 T !D ( ) W ! !=0=(L"W cos!) mV L=W cos! ! h=Vsin! =V T( "D) W = Pthrust "Pdrag ( ) W
Specific Excess Power (SEP)= Excess Power
Unit Weight #
Pthrust "Pdrag
( )
W •! Flight path angle " •! Required lift"
•! Note significance of thrust-to-weight ratio and wing loading" Steady Rate of Climb"
! h=V sin! =V T W " # $ % & '( CDo +)CL 2
(
)
q W S ( ) * + , , -. / / L=CLq S=W cos" CL= WS # $ % & ' ( cos" q V= 2 W S # $ % & ' ( cos" CL) ! h=V T W ! " # $ % &' CDoq W S ( ) ' ((W S)cos2) q * + , -. / =V T( )h W ! " # $ % &'CDo0( )h V 3 2 W S( ) ' 2((W S)cos2) 0( )h V •! Climb rate" 13!•! Necessary condition for a maximum with
respect to airspeed"
Condition for Maximum Steady Rate of Climb"
! h=V T W ! " # $ % &' CDo(V 3 2 W S( )' 2)(W S)cos2* (V !h! !V =0 = T W " # $ % & '+V !T /!V W " # $ % & ' ( ) * +,-. 3CDo/V 2 2(W S) + 20(W S)cos21 /V2
Maximum Steady " Rate of Climb: " Propeller-Driven Aircraft" !Pthrust !V =0= T W " # $ % & '+V !T /!V W " # $ % & ' ( ) * +, -•! At constant power" !h! !V =0=" 3CDo#V 2 2 W S( ) + 2$(W S) #V2
•! With cos2!! ~ 1, optimality condition reduces to"
•! Airspeed for maximum rate of climb at maximum power,Pmax"
V4 = 4 3 ! " # $ % &'(W S) 2 CDo( 2 ; V = 2 W S( ( ) ' 3CDo =VME 15! Maximum Steady Rate of Climb: " Jet-Driven Aircraft"
•! Condition for a maximum at constant thrust and cos2!! ~ 1"
•! Airspeed for maximum rate of climb at maximum thrust, Tmax"
!h! !V =0 0 = ax2 +bx+c and V = + x =! 3CDo" 2 W S( )V4 + WT # $ % & ' (V2+2)(W S) " =! 3CDo" 2 W S( ) V 2 ( )2+ T W # $ % & ' (( )V2 +2)(W S) "
Optimal Climbing Flight!
17!
What is the Fastest Way to Climb from One Flight Condition to
•! Specific Energy "
•! = (Potential + Kinetic Energy) per Unit Weight"
•! = Energy Height"
Energy Height"
•! Could trade altitude with airspeed with no change in energy
height if thrust and drag were zero"
Total Energy
Unit Weight !Specific Energy= mgh
+mV2 2 mg =h+V 2 2g ! Energy Height,Eh, ft or m 19!
Specific Excess Power" dEh dt = dtd h+V 2 2g ! " # $ % &= dhdt +!Vg " # $ % &dVdt
Rate of change of Specific Energy "
=V sin! + V g " #$ % &' T (D(mgsin! m " #$ %&' =V T( W(D)=V CT (CD ( )12)(h)V2S W
=Specific Excess Power(SEP)
= Excess Power
Unit Weight !
Pthrust"Pdrag
( )
Contours of Constant Specific Excess Power"
•! Specific Excess Power is a function of altitude and airspeed"
•! SEPis maximized at each altitude, h, when" d SEP(h)[ ]
dV =0
21!
Subsonic Energy Climb"
•! Objective:Minimize time or fuel to climb to desired altitude and airspeed"
Supersonic Energy Climb"
•! Objective:Minimize time or fuel to climb to desired altitude and airspeed"
23!
•! Maneuvering envelope: limits on normal load factor and allowable equivalent airspeed"
–! Structural factors"
–! Maximum and minimum achievable lift coefficients"
–! Maximum and minimum airspeeds"
–! Protection against
overstressing due to gusts"
–! Corner Velocity: Intersection of maximum lift coefficient and maximum load factor"
Typical Maneuvering Envelope:
V-n Diagram"
•! Typical positive load factor limits"
–! Transport: > 2.5"
–! Utility: > 4.4"
–! Aerobatic: > 6.3"
–! Fighter: > 9"
•! Typical negative load factor limits"
–! Transport: < –1"
–! Others: < –1 to –3"
C-130 exceeds maneuvering envelope!
http://www.youtube.com/watch?v=4bDNCac2N1o&feature=related! 25!
Maneuvering Envelopes (V-n Diagrams)
for Three Fighters of the Korean War Era" Republic F-84!
North American F-86!
Turning Flight!
27!
•! Vertical force equilibrium"
Level Turning Flight"
L cosµ =W
•! Load factor"
n= LW = Lmg =secµ,"g"s
•! Thrust required to maintain level flight"
Treq = CDo +!CL 2 ( )12"V2S= Do + 2! "V2S W cosµ # $% & '( 2 = Do+ 2! "V2S(nW) 2 µ : Bank Angle
•! Level flight = constant altitude"
•! Bank angle"
Maximum Bank Angle in Level Flight" cosµ= W CLqS =1 n=W 2 ! Treq"Do ( )#V2S µ=cos"1 W CLqS $ % & ' ( ) =cos"1 1 n $ % & ' ( ) =cos"1 W 2! Treq"Do ( )#V2S * + , , -. / /
•! Bank angle is limited by "
µ: Bank Angle
CLmax or Tmax or nmax
29!
•! Turning rate"
Turning Rate and Radius in Level Flight" ! ! = CLqSsinµ mV = W tan µ mV = gtan µ V = L 2"W2 mV = W n 2"1 mV = Treq " Do ( )#V2S 2$ "W2 mV
•! Turning rate is limited by "
CLmax or Tmax or nmax
•! Turning radius "
Rturn =V!
! = V2
Maximum Turn Rates"
“Wind-up turns”!
31!
•! Corner velocity"
Corner Velocity Turn"
•! Turning radius " Rturn = V
2 cos2!
g nmax2 " cos2!
Vcorner = 2nmaxW
CLmas!S
•! For steady climbing
or diving flight" sin! = Tmax
" D
Corner Velocity Turn"
•! Time to complete a
full circle " t2! =
V cos"
g nmax2 # cos2"
•! Altitude gain/loss " !h2" = t2"V sin#
•! Turning rate " !! = g nmax
2 " cos2#
(
)
V cos#
33!
Herbst Maneuver"
•! Minimum-time reversal of direction"
•! Kinetic-/potential-energy exchange"
•! Yaw maneuver at low airspeed"
Next Time:!
Aircraft Equations of Motion!
Reading:! Flight Dynamics, ! Section 3.1, 3.2, pp. 155-161! Airplane Stability and Control !
Chapter 5!
35!
Gliding Flight of the P-51 Mustang" Loaded Weight=9,200 lb (3,465 kg) L / D ( )max= 1 2 !CDo =16.31 "MR= #cot#1 L D $ % & ' ( ) max = #cot#1(16.31)= #3.51° CD ( )L/Dmax=2CDo=0.0326 CL ( )L/Dmax= CDo ! =0.531 VL/Dmax= 76.49 * m / s ! hL/Dmax=V sin"= # 4.68 * m / s Rho=10km=(16.31)( )10 =163.1 km
Maximum Range Glide!
Loaded Weight=9,200 lb (3,465 kg) S=21.83 m2 CDME=4CDo =4 0.0163( )=0.0652 CLME = 3CDo ! = 3 0.0163( ) 0.0576 =0.921 L D ( )ME=14.13 ! hME=" 2# WS $ % & ' ( ) CDME CLME 3/2 $ % && ' ( ))="4.11 # m / s *ME ="4.05° VME =58.12# m / s
Maximum Endurance Glide!