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ISSN 2229 β 5046
FACE MAGIC
πΈ
- LABELING OF GRAPHS
A. MEENA KUMARI
1AND S. AROCKIARAJ
21Research Scholar,Department of Mathematics,
Bharathiar Univeristy,Coimbatore and Faculty in department of Mathematics, Mepco Schlenk Engineering College, Sivakasi - 626 005, Tamil Nadu, India.
2Department of Mathematics,
Government Arts and Science College, Sivakasi β 626 124, Tamil Nadu, India.
(Received On: 18-08-18; Revised & Accepted On: 11-10-18)
ABSTRACT
I
n this paper, we introduce the Face magic πΈ-labeling of graphs, where the labels are the elements of an arbitraryabelian group πΈ, of order π+π and the weight of each face is the product of the labels of all vertices and edges in the
boundary of that face, an assignment of labels to the vertices and edges which induces an assignment of labels to the
faces of a graph such that the weight of each face is constant. We discuss the Face magic πΈ-labeling of some graphs
and the relationship between face, vertex and edge magic constants.
Key Words. Labeling, Face magic πΈ-labeling of graphs, Face magic graph over πΈ.
AMS(2010): 05C76,05C78.
1 INTRODUCTION
By a graph, we mean a finite, connected, undirected planar graph without loops and multiple edges. By a planar graph,
we mean that it can be drawn in a plane such that no two edges intersect.The group πΈ is always a finite abelian group.
Let us consider πΈ=β©πβͺ where ππ= 1πΈ or simply 1, the identity element of πΈ .
A graph πΊ is magic if the edges of πΊ can be labeled by the numbers 1,2,3, β¦ , |πΈ(πΊ)| so that the sum of the labels of all
the edges incident with any vertex is the same [1]. A group distance magic labeling of a graph πΊ(π,πΈ) with |π| =π is
an injection form π to an abelian group Ξ of order π such that the sum of labels of all neighbors of every vertex π₯ in π
is equal to the same element π in Ξ. A graph that admits a distance magic labeling is called a distance magic graph [4].
There are some graphs with an embedding in the plane such that all vertices belong to the unbounded face of the embedding. Such planar graph is an outer planar graph.
Path on n vertices is denoted by ππ and a cycle on n vertices is denoted by πΆπ. Duplication of a vertex π£ of a graph πΊ by
a vertex π£β² produces a new graph πΊβ² with π(π£β²) =π(π£) where π(π£) is the set of all neighbors of π£. Duplication of an
edge π=π’π£ of a graph πΊ by an edge πβ²=π’β²π£β² produces a new graph πΊβ² where π(π’) and π(π£). Duplication of an edge
π=π’π£ by a vertex π£β² in a graph πΊ produces a new graph πΊβ² where π(πΊβ²) =π(πΊ)βͺ{π£β²}, πΈ(πΊβ²) =πΈ(πΊ)βͺ{π’π£β²,π£β²π£}.
Duplication of a vertex π£ of a graph πΊ by an edge πβ²=π’β²π£β² produces a new graph πΊβ² where π(π’β²) = {π£,π£β²} and
π(π£β²) = {π£,π’β²}.
The (π,π)β tadpole graph G is a graph obtained by identifying a vertex of a cycle of length π and a vertex of a path
of length π. A Barbell graph π·π,π,π is a graph obtained by connecting two disjoint cyles on π and π number of vertices
respectively by a path of π number of vertices.
Corresponding Author: A. Meena Kumari1, 1Research Scholar,Department of Mathematics,
Let π be a labeling over a group πΈ. D.Combe et al. [5] define the π-weight, π=ππ of the graph as follows
(i) for every vertex π₯ππ, the weight is the product of the label of π₯ and the labels of the edges incident with π₯, that is
π(π₯) =π(π₯) x βπ¦βπ:π₯π¦ π(π₯π¦); (ii) for every edge π₯π¦ β πΈ, the weight is the product of the labels of π₯π¦ and the
labels of π₯ and π¦, that is π(π₯π¦) =π(π₯) x π(π₯π¦) x π(π¦).
The labeling π is a vertex magic πΈ-labeling of G if there is an element β=β(π) of πΈ such that for every
π₯ β π,π(π₯) =β. The element β is the vertex constant. The labeling π is an edge magic πΈ-labeling of G if there is an
element π=π(π) of πΈ such that for every π₯π¦ β πΈ,π(π₯π¦) =π. The element π is the edge constant.
The labeling π is a totally magic πΈ-labeling of G if it is both a vertex magic πΈ-labeling and an edge magic πΈ-labeling.
A graph πΊ is said to be vertex πΈ-magic if there exists a vertex magic labeling over πΈ. Similarly πΊ is edge πΈ-magic if
there exists an edge magic labeling over πΈ; and πΊ is totally πΈ-magic if there exists a totally magic labeling over πΈ [5].
Two πΈ-labelings π1,π2 of πΊ are translation equivalent, denoted by π1~ππ2 if there exists πππΈ such that
βπ§ β π βͺ πΈ,π1(π§) =ππ2(π§). The labeling π1 is the translation of π2 by π and is denoted by π1=ππ2. Clearly,
translation equivalence is an equivalence relation on labelings [5].
Motivated by these works, we introduce face magic πΈ-labeling as follows:
The labeling π is a face magic πΈ-labeling of G if there is an element π=π(π) of πΈ such that for every face
π β πΉ,π(π) =π. We define for every π β πΉ, the weight is the product of the labels of all vertices and edges in the
boundary of the face π, that is π(π) =βπ₯πππ π(π₯) x βπ₯π¦πππ π(π₯π¦)
The element π is the face constant. A graph πΊ is said to be face magic graph over πΈ if there exists a face magic labeling
over πΈ.
In this paper, We introduce face magic πΈ-labeling of πΊ and derive the relation between vertex, edge and face constants
of a graph πΊ. Also we discuss the face magic πΈ-labeling of some graphs obtained by duplication of any one of a vertex
or an edge of a graph.
2 MAIN RESULTS
Proposition 2.1: Let πΊ be a graph having πΈ-labeling which is both edge magic πΈ-labeling with edge constant π and a face magic πΈ-labeling with face constant π. Then the product of the vertex labels of any π -sided face is ππ πβ1.
Proof: Let π be a π -sided face in πΊ which admits a πΈ-labeling π . Product of all edge constants of all edges in π is
=ππ =οΏ½β
π₯πππ(π₯)οΏ½2.οΏ½βπ₯π¦ππ π(π₯π¦)οΏ½
=οΏ½βπ₯πππ(π₯)οΏ½.οΏ½βπ₯π¦ππ π(π₯π¦)οΏ½.οΏ½βπ₯πππ(π₯)οΏ½
=π.βπ₯πππ(π₯)
Hence the result follows.
Proposition 2.2: Let πΊ be a graph having πΈ-labeling which is both vertex magic πΈ-labeling with vertex constant β and
a face magic πΈ-labeling with face constant π. Then the product of all the edge labels incident with every vertex of any
π -sided face is βπ πβ1.
Proof: Let π be a π -sided face in πΊ which admits a πΈ-labeling π . Product of all vertex constants of all vertices in π
-sided face π is
=βπ =β
π₯πππ(π₯)
=βπ₯πποΏ½π(π₯)οΏ½βπ₯π¦ππ π(π₯π¦)οΏ½2οΏ½βπ₯π§πππ(π₯π§)οΏ½ππ₯β2οΏ½
=βπ₯πποΏ½π(π₯)βπ₯π¦ππ π(π₯π¦)οΏ½.βπ₯πποΏ½βπ₯π¦πππ(π₯π¦)βπ₯π§ππ π(π₯π§)οΏ½
=π.βπ₯πποΏ½βπ₯π¦ππΈ(πΊ)π(π₯π¦)οΏ½
Thus the product of all the edge labels incident with every vertex of the π -sided face is βπ πβ1.
Proposition 2.3: Let πΊ be a planar graph in which all its edges are in the boundary of its exterior face. If πΊ has a face magic πΈ-labeling with face constant π, then
Proof: Let πΊ has a face magic πΈ-labeling π with face constant π.Let π0 be the face in πΊ which covers all vertices and
edges of πΊ. Then
π=βπ₯ππ0 π(π₯).βπ₯π¦ππ0 π(π₯π¦)
= 1.π.π2. . .ππ+πβ1
=ππ, where π=(π+π)(π+πβ1)
2
when π+π is odd, ππ = (ππ+π)π+πβ12 = 1πΈ. Also,
οΏ½ππ+π2 οΏ½
π
=οΏ½π
π+π
2 , if π+π is even and r is odd 1πΈ, if π+π is even and r is even
So, ππ =ππ+π2 when π+π is even. Hence the result follows.
Consider the outer planar graph πΊ isomorphic to (π,π)-Tadpole graph.
Let {π’1,π’2, . . . ,π’π} be the vertices on cycle and {π£0,π£1,π£2,. . . ,π£π} be the vertices on path where π’1=π£0. In G,
|π(πΊ)| =π+π, |πΈ(πΊ)| =π+π and |π(πΊ)| + |πΈ(πΊ)| = 2π+ 2π, πΉ(πΊ) = {π0,π1} where π0 is the outer face having
all vertices and edges and π1 is the cycle πΆπ.
Consider any cyclic group β¨πβ© of order 2π+ 2π. Then β¨πβ©= {1,π,π2, . . . ,π2π+2πβ1} where π2π+2π= 1. The labels
of the path in the sequence vertex - edge - vertex - edge - vertex... are given as
π2π+π,π2,π2π+π+1,π3,π2π+π+2,π4, . . . ,π2π+2πβ1. The labels for the cycle πΆ
π starting with identified vertex in the
sequence vertex - edge - vertex - edge - vertex... are given as 1,ππ+π,ππ+1,ππ+π+1,ππ+2, . . . ,ππ+πβ1,π2π+πβ1. The
above labels are the labels in the face π1. Therefore,Weight of the face π1 is
= 1.ππ+π.ππ+1.ππ+π+1.ππ+2. . .ππ+πβ1.π2π+πβ1
=ππ(π+π).π2(1+2+...+(πβ1)).ππ(πβ1)
=ππ(2π+2π)β(π+π)
=π(π+π), where π+π= 2π+ 2π is even and π2π+2π= 1.
Now, Weight of the outer face π0 is the product of all elements in the cyclic group which is
= 1.π.π2.π3. . .π2π+2πβ1
=π(2π+2π)(2π+2πβ1)/2
=ππ+π, where π+π= 2π+ 2π is even and π2π+2π= 1.
This example shows that (π,π)-Tadpole graph is a face magic graph over πΈ with face constant ππ+π and illustrates
proposition 2.3 when π+π is even.
Consider the outer planar graph G isomorphic to a Barbell graph π·π,π,2.
Let π(πΊ) =π(πΆ1)βͺ π(πΆ2) = {π’1,π’2, . . . ,π’3}βͺ{π£1,π£2,. . . ,π£π},πΈ(πΊ) = {π’ππ’π+1: 1β€ π β€ π β1}βͺ{π’ππ’1}βͺ
{π£ππ£π+1: 1β€ π β€ π β1}βͺ{π£ππ£1}βͺ{π’ππ£π} and πΉ(πΊ) = {π0,π1,π2} where π1,π2 are cycles πΆ1,πΆ2 respectively and π0 is
the face having all the vertices and edges of G. In G, π= |π(πΊ)| = 2π, π= |πΈ(πΊ)| = 2π+ 1, πππ(ππ) =π, π= 1,2,
πππ(π0) = 4π+ 1. So, π+π= 4π+ 1 which is odd.
Consider any cyclic group β¨πβ© of order 4π+ 1. Then β¨πβ©= {1,π,π2, . . . ,π4π} where π4π+1= 1. Label the bridge of G
by the identity element 1 of β¨πβ©. Label the first cycle πΆ1starting with vertex π’1 and end with the edge π’ππ’1 in the
sequence vertex - edge - vertex - edge - vertex...edge as π,π4,π5π8,π9,π12, . . . ,π4πβ3,π4π. Label the second cycle πΆ2
starting with vertex π£1 and end with the edge π£ππ£1 in the sequence vertex - edge - vertex - edge - vertex...edge as
π2,π3π6,π7,π10, . . . ,π4πβ6,π4πβ2,π4πβ1.
Now, the weight of the face π1 is the product of all the labels of vertices and edges in πΆ1 which is
= [π.π5.π9. . .π4πβ3]. [π4.π8.π12. . .π4π]
= [π4(1+2+...+π)β3π].[π4(1+2+...+π)]
=π4π2+π
=ππ(4π+1)= 1 πΈ.
Also the weight of the face π2 is the product of all the labels of vertices and edges in πΆ2 which is
= [π2.π6.π10. . .π4πβ2].[π3.π7. . .π4πβ6.π4πβ1]
= [π2(1+3+...+(2πβ1))]. [π4(1+2+...+π)βπ]
=π4π2+π=ππ(4π+1)= 1 πΈ.
Now, the weight of the outer face π0 is the product of all elements in the cyclic group which is
= 1.π.π2. . . .π4π
This example shows that π·π,π,2 is a face magic graph over πΈ with face constant 1πΈ, and illustrates proposition 2.3 when
π+π is odd.
Corollary 2.4: Every Tree is a face magic graph over πΈ where πΈ is a cyclic group of order 2π β1.
Proposition 2.5: If any 2βconnected graph which is totally magic with vertex constant β and an edge constant π admits a face magic πΈ- labeling π of πΊ with a face constant ππΈ ,then the product of all face constants of G is ππΈ.βπ.ππ, where π,π and π are the number of vertices, edges and faces of πΊ respectively and ππΈ=βπππΈπ.
Proof: Product of all face constants of G is ππ which is
=βπππΈπ(π).βπ£ππ (π(π£))ππ£
= [βπππΈπ(π).βπ£ππ π(π£)]. [βπππΈπ(π)]. [βπ£ππ (π(π£))ππ£β1] =ππΈ.βπ.ππΈ.ππΈβ1.ππ
=ππΈ.βπ.ππ
Hence the result follows.
Proposition 2.6: If πΈ is of even order and π is a face magic πΈ-labeling of πΊ, then there exists an element π such that
ππ is also a face magic πΈ-labeling of πΊ.
Proof: If πΈ is of even order, then there exists π in πΊ such that π2=π. For each s-sided face π,
(ππ)π=π2π π(π) =π(π). Hence the result follows.
Proposition 2.7: Let πΈ be an abelian group in which every element is an involution and π be a face magic πΈ-labeling of πΊ. Let ππ be the set of all face magic πΈ labelings obtained from the translations of π, that is, ππ= {ππ:πππΈ}. Then
ππ forms an abelian group under the operation defined by (π1π β π2π)(π₯) = (π1π2)π(π₯),π₯ππ βͺ πΈ
Proof: The set ππ is closed under the operartion β, since if π1π,π2π β ππ, (π1π β π2π)(π₯) = (π1π2)π(π₯) β ππ, by proposition 2.6.
If π1π,π2π β ππ, then(π1π β π2π)β(π3π) = (π1π2)π β π3π= ((π1π2)π3)π= (π1(π2π3))π=π1π β(π2π β π3π)
and hence associativity of ππ follows.
Also, the element πππππ,πππΈ is considered as an identity element, since (ππ β ππ)(π₯) = (ππ)π(π₯) = (ππ)(π₯) =
((ππ)π)(π₯) = (ππ β ππ)(π₯).
Since (ππ β ππ)(π₯) = (π2)π(π₯) = (ππ)(π₯), every element in ππ has a self inverse in ππ.
As (π1π β π2π)(π₯) = (π1π2)π(π₯) = (π2π1)π(π₯),by the commutative property in πΈ, equals (π2π β π1π)(π₯). Hence
(ππ,β) is an abelian group.
Proposition 2.8: The graph obtained by duplication of any vertex in cycle πΆπ by a vertex admits a face magic πΈ -labeling with face constant 1πΈ , for π β₯3.
Proof: Let π£1,π£2,. . . ,π£π be the vertices of the cycle πΆπ, for π β₯3. By the graph isomorphism, duplicate the vertex π£1
by a vertex π£1β². Let the resultant graph be πΊ whose vertex set is π(πΆπ)βͺ{π£1β²},edge set is πΈ(πΆπ)βͺ{π£1β²π£π,π£1β²π£2} and
face set is {π0,π1,π2} where π1 is the cycle πΆπ, π2 is the face bounded by the edges π£1π£2,π£2π£1β²,π£1β²π£π,π£ππ£1 and π0 is the
outer face bounded by all the edges of G except π£1π£2,π£ππ£1.
Consider any cyclic group β©πβͺ of order π+π= 2π+ 3.
Define a labeling π:π(πΊ)βͺ πΈ(πΊ)β β©πβͺ as follows.
π(π£π) =
β© βͺ β¨ βͺ
β§πππ2π+2, , ππ= 1= 2
1, π= 3
ππβ1, 4β€ π β€ π β1
π, π=π,
π(π£1β²) =π2π+1,
π(π£1π£π) = 2,
π(π£1β²π£2) =ππ+2,
π(π£1β²π£π) =ππ+3 and
π(π£ππ£π+1) =οΏ½
ππ+1, π= 1
ππβ1, π= 2
Then the induced face labeling is given by
πβ(π
1) =βππ=1π(π£π).βππ=1π(π£ππ£π+1).π(π£ππ£1)
=ππ.π2π+2. 1.π3.π4. . .ππβ2.π.ππ+1.ππβ1.π2.ππ+4.ππ+5. . .π2π
= [1.π.π2.π3. . .ππβ2.ππβ1.ππ.ππ+1]. [ππ+4.ππ+5. . .π2π].π2π+2
=π[2π(2π+1)/2]β(π+2)β(π+3)+(2π+2)
=π(2π+3)(πβ1)= 1 πΈ,
πβ(π
0) =βππ=2π(π£π).π(π£1β²).βπβ1π=3 π(π£ππ£π+1).π(π£1β²π£2).π(π£1β²π£π).π(π£2π£3)
=π2π+1.π2π+2. 1.π3.π4. . .ππβ2.ππ+2.ππ+3.ππβ1.ππ+4.ππ+5. . .π2π.π
= [π.π3.π4. . .ππβ2.ππβ1.ππ+2.ππ+3]. [ππ+4.ππ+5. . .π2π].π2π+1.π2π+2
=π[(2π+2)(2π+3)/2]β2βπβ(π+1)
=π(2π+3)(π)= 1
πΈ and
πβ(π
2) =π(π£1).π(π£2).π(π£π).π(π£1β²π£2).π(π£1β²π£π).π(π£1β²).π(π£1β²π£2).π(π£1β²π£π).π(π£1π£2).π(π£1π£π)
=ππ.π2π+2.π.ππ+2.ππ+3.π2π+1.ππ+1.π2
=π8π+12=π(2π+3)4= 1
πΈ.
Thus π admits a face magic πΈ-labeling with face constant 1πΈ.
A Face magic πΈ-labeling of a vertex duplication of πΆ9 by a vertex is shown in Figure 1.
Figure-1: Face magic πΈ-labeling of a vertex duplication of πΆ9 by a vertex with face constant 1πΈ.
Proposition 2.9: The graph πΊ obtained by duplication of any edge in cycle πΆπ by an edge admits a face magic πΈ -labeling with face constant 1πΈ for π β₯3.
Proof: Let π£1,π£2,. . . ,π£π be the vertices of the cycle πΆπ, for π β₯3. By the graph isomorphism, duplicate the edge π£1π£2
by a vertex π£1β²π£2β². Let the resultant graph be πΊ whose vertex set is π(πΆπ)βͺ{π£1β²}βͺ{π£2β²}, edge set is πΈ(πΆπ)βͺ
{π£1β²π£π,π£1β²π£2β²,π£2β²π£3} and face set is {π0,π1,π2} where π1 is the cycle πΆπ, π2 is the face bounded by the edges
π£1π£2,π£2π£3,π£3π£2β²,π£1β²π£2β²,π£1β²π£π,π£ππ£1 and π0 is the outer face bounded by all the edges of G except π£1π£2,π£2π£3,π£ππ£1.
Consider any cyclic group β©πβͺ of order π+π= 2π+ 5.
Define a labeling π:π(πΊ)βͺ πΈ(πΊ)β β©πβͺ as follows.
π(π£iβ²) =οΏ½π
π, π= 1
ππ+2, π= 2,
π(π£π) =
β© βͺ β¨ βͺ
β§πππ+3π+5,, ππ= 1= 2
π2π+4, π= 3
ππ+π+3, 4β€ π β€ π β1
π, π=π,
π(π£ππ£π+1) =οΏ½
ππβ1, π= 1
ππ+1, π= 2
ππ, 3β€ π β€ π β2
1, π=π β1,
π(π£ππ£1) =π2,π(π£1β²π£π) =ππ+4,
π(π£1β²π£2β²) =ππ+6 and π(π£2β²π£3) =π2π+3.
.
Then the induced face labeling is given by
πβ(π
1) =βππ=1π(π£π).βπβ1π=1 π(π£ππ£π+1).π(π£ππ£1)
=ππ+3.ππ+5.π2π+4.ππ+7.ππ+8. . .π2π+2.π.ππβ1.ππ+1.π3.π4. . .ππβ2. 1.π2
= 1.π.π2.π3. . .ππβ2.ππβ1.ππ+1.ππ+3.ππ+5.ππ+7.ππ+8. . .π2π+2.π2π+4
=π[(2π+4)(2π+5)/2]βπβ(π+2)β(π+4)β(π+6)β(2π+3)
=π2π2+3πβ5
πβ(π
0) =βππ=3π(π£π).π(π£1β²).π(π£2β²).βπβ1π=3 π(π£ππ£π+1).π(π£1β²π£2).π(π£1β²π£π).π(π£2π£3)
=π2π+4.ππ+7.ππ+8. . .π2π+2.π.π3.π4. . .ππβ2. 1.ππ+6.ππ+4.π2π+3.ππ.ππ+2
= 1.π.π3.π4. . .ππβ2.ππ.ππ+2.ππ+4.ππ+6.ππ+7.ππ+8. . .π2π+2.π2π+3.π2π+4
=π[(2π+4)(2π+5)/2]β(πβ1)β(π+1)β(π+3)β(π+5)β2
=π(2π+5)(π)= 1πΈ and
πβ(π
2) =β3π=1π(π£π).π(π£π).π(π£1).π(π£2).π(π£1π£2).π(π£2π£3).π(π£1π£n).π(π£1β²π£2).π(π£1β²π£n).π(π£2β²π£3)
=ππ+3.ππ+5.π2π+4.π.ππ.ππ+2.ππβ1.ππ+1.π2.ππ+6.ππ+4.π2π+3
=π12π+50=π(2π+5)6= 1
πΈ.
Thus π admits a face magic πΈ-labeling with face constant 1πΈ.
A face magic πΈ-labeling of edge duplication of πΆ8 by an edge is shown in Figure 2.
Figure-2: Face magic πΈ-labeling of edge duplication of πΆ8 by an edge with face constant 1πΈ.
Proposition 2.10: The graph πΊ obtained by duplication of any edge in cycle πΆπ by a vertex admits a face magic πΈ -labeling with face constant 1πΈ for π β₯3.
Proof: Let π£1,π£2,. . . ,π£π be the vertices of the cycle πΆπ, for π β₯3. By the graph isomorphism, duplicate the edge π£1π£2
by a vertex π’.This vertex π’ may be placed inside the cycle πΆπ or outside the cycle πΆπ.
Case i: Assume that vertex π’ is placed outside the cycle πΆπ. Let the resultant graph be G whose vertex set is
π(πΆπ)βͺ{π’}, edge set is πΈ(πΊ) =πΈ(πΆπ)βͺ{π’π£1,π’π£2} and face set is {π0,π1,π2} where π1 is the cycle πΆπ, π2 is the face
bounded by the edges π£1π£2,π’π£1,π’π£2 and π0 is the outer face bounded by all the edges of G except π£1π£2.
Consider any cyclic group β©πβͺ of order π+π= 2π+ 3.
Define a labeling π:π(πΊ)βͺ πΈ(πΊ)β β©πβͺ as follows.
π(π’) =π2π+1,
π(π£π) =οΏ½
π, π= 1
π2π+2, π= 2
ππ+1, π= 3
ππ+π, 4β€ π β€ π,
π(π£ππ£π+1) =οΏ½1,ππ, 2π= 1β€ π β€ π β1,
π(π£ππ£1) =ππ,
π(π’π£1) =ππ+2 and
π(π’π£2) =ππ+3.
Then the induced face labeling is given by
πβ(π
1) =βππ=1π(π£π).βπβ1π=1 π(π£ππ£π+1).π(π£ππ£1)
=π.π2π+2.ππ+1.ππ+4.ππ+5. . .π2π.1.π2.π3. . .ππβ1.ππ
= 1.π.π2.π3. . .ππ.ππ+1.ππ+4.ππ+5.ππ+6. . .π2π.π2π+2
=π(2π+2)(2π+3)/2
=π2π2+πβ3=π(2π+3)(πβ1)= 1 πΈ,
πβ(π
0) =βππ=1π(π£π).π(π’).βπβ1π=1 π(π£ππ£π+1).π(π£ππ£1)
=π.π2π+2.ππ+1.ππ+4.ππ+5. . .π2π.π2π+1.π2.π3. . .ππβ1.ππππ+2.ππ+3
=π.π2.π3. . .ππβ1.ππ.ππ+1.ππ+2. . .π2π.π2π+1.π2π+2
=π(2π+2)(2π+3)/2
=π(2π+3)(π+1)= 1 πΈ and
πβ(π
2) =π(π£1).π(π£2).π(π’).π(π’π£2).π(π£1π£2).π(π’π£1)
=π.π2π+2.π2π+1. 1.ππ+2.ππ+3
=π6π+9=π(2π+3)3= 1 πΈ.
Case ii: Assume that vertex π’ is placed inside the cycle πΆπ. In this case, the resultant graph have the same faces as in
case (i), but π1 is an outer face and π0 is an inner face. By the same labeling defined in case (i), the result follows.
A face magic πΈ-labeling of G obtained by duplicating an edge of πΆ7 by a vertex is shown in Figure 3.
Figure-3: Face magic πΈ-labeling of G obtained by duplicating an edge of πΆ7 by a vertex with face constant 1πΈ.
Proposition 2.11: The graph πΊ obtained by duplication of any vertex in cycle πΆπ by an edge admits a face magic πΈ -labeling with face constant 1πΈ, for π β₯3.
Proof: Let π£1,π£2,. . . ,π£π be the vertices of the cycle πΆπ, for π β₯3. By the graph isomorphism, duplicate the vertex π£1
by an edge π’π£. Let the resultant graph be πΊ whose vertex set is π(πΆπ)βͺ{π’,π£}, edge set is πΈ(πΆπ)βͺ{π’π£,π’π£1,π£π£1} and
face set is {π0,π1,π2} where π1 is the cycle πΆπ, π2 is the face bounded by the edges π’π£,π’π£1,π£π£1 and π0 is the outer face
bounded by all the edges of G.
Consider any cyclic group β©πβͺ of order π+π= 2π+ 5.
Define a labeling π:π(πΊ)βͺ πΈ(πΊ)β β©πβͺ as follows.
π(π’) =ππ+1,
π(π£) =ππ+2
π(π£π) =οΏ½
1, π= 1
ππ+1, 2β€ π β€ π β1
ππ+3, π=π,
π(π’π£) =π2π+4,
π(π’π£1) =π,
π(π£π£1) =π2,
π(π£ππ£π+1) =ππ+3+π, 1β€ π β€ π β1 and
π(π£ππ£1) =π2π+3.
Then the induced face labeling is given by
πβ(π
1) =βππ=1π(π£π).βπβ1π=1 π(π£ππ£π+1).π(π£ππ£1)
= 1.π3.π4. . .ππ.ππ+3.ππ+4.ππ+5. . .π2π+2.π2π+3
=π[(2π+3)(2π+4)/2]β1β2β(π+1)β(π+2)
=π2π2+5π=π(2π+5)(π)= 1
πΈ and
πβ(π
2) =π(π’).π(π£).π(π£1).π(π’π£1).π(π£π£1).π(π’π£)
=ππ+1.ππ+2. 1.π.π2.π2π+4
=π4π+10=π(2π+5)2= 1
πΈ.
Since G is outer planar and π+π= 2π+ 5 is odd, by proposition 2.3, πβ(π0) = 1πΈ.
Thus π admits a face magic πΈ-labeling with face constant 1πΈ.
A face magic πΈ-labeling of G obtained by duplicating a vertex of πΆ6 by an edge is shown in Figure 4.
Proposition 2.12: The graph πΊ obtained by duplication of any vertex in path ππ by a vertex admits a face magic πΈ -labeling with face constant π(π+π)/2 if π+π is even or 1πΈ if π+π is odd, for π β₯2.
Proof: Let π£1,π£2,. . . ,π£π be the vertices of the path ππ, for π β₯2. Let the vertex π£π be duplicated by a vertex π£πβ². Then
the resultant graph is πΊ which is outer planar with all its edges in the boundary of exterior face.
Case i. π= 1 or π
If any one of the end vertices is duplicated, then G is isomorphic to a tree graph having π+π= 2π+ 1 which is odd.
By corollary 2.4, G is a Face magic graph over πΈ with face constant 1πΈ, for π β₯1.
Case ii. 2β€ π β€ π β1
Let the resultant graph G has vertex set π(πΊ) =π(ππ)βͺ{π£πβ²}, edge set πΈ(ππ)βͺ{π£πβ²π£πβ1,π£πβ²π£π+1} and face set {π0,π1}
where π1 is the face bounded by the edges π£πβ1π£π,π£ππ£π+1,π£πβ²π£πβ1,π£πβ²π£π+1 and π0 is the outer face bounded by all the
edges of G.
Consider the cyclic group β©πβͺ of order π+π= 2π+ 2. Assign the labels 1,π,π2,π3,ππβ1,ππ,ππ+1,π2πβ1 to the
vertices and edges of the face π1 and assign the remaining labels to the remaining vertices and edges of the graph πΊ.
Now, the weight of the face π1=π5π+5=π2(2π+2).ππ+1=ππ+1, since π2π+2= 1πΈ. Also the weight of the outer face
π0= 1.π.π2.π3. . .π2π+1=ππ+1.
Thus G obtained by duplication of any vertex in path ππ by a vertex is a face magic graph over πΈ.
A face magic πΈ-labeling of G obtained by duplicating a vertex of ππ by a vertex is shown in Figure 5.
Figure-5: Face magic πΈ-labeling of G obtained by duplicating a vertex of ππ by a vertex.
Proposition 2.13: The graph πΊ obtained by duplication of any arbitrary edge in path ππ admits a face magic πΈ -labeling with face constant π(π+π)/2 if π+π is even or 1πΈ if π+π is odd, for π β₯3.
Proof: Let π£1,π£2,. . . ,π£π be the vertices of the path ππ, for π β₯3. Let the edge π=π£ππ£π+1 be duplicated by the edge
πβ²=π£πβ²π£π+1β². Then the resultant graph is πΊ which is outer planar with all its edges in the boundary of exterior face.
Case i. π= 1 or π
If any one of the edges π£1π£2 or π£πβ1π£π is duplicated, then G is isomorphic to a tree graph having π+π= 2π+ 3
which is odd. By corollary 2.4, G is a Face magic πΈ-graph with face constant 1πΈ , for π β₯3.
Case ii. 2β€ π β€ π β2
Let the resultant graph be πΊ has vertex set π(ππ)βͺ{π£πβ²,π£π+1β²}, edge set πΈ(ππ)βͺ{π£πβ²π£π+1β²,π£πβ²π£πβ1,π£π+1β²π£π+2} and face
set {π0,π1} where π1 is the face bounded by the edges {π£πβ1π£π,π£ππ£π+1,π£π+1π£π+2,π£π+2π£π+1β² ,π£πβ²π£π+1β² ,π£πβ²π£πβ1} and π0 is the
outer face bounded by all the edges of G.
Consider the cyclic group β©πβͺ of order π+π= 2π+ 4. Assign the labels
1,π,π2,π3,π4,ππβ1,ππ,ππ+2,ππ+3,ππ+4,π2πβ1,π2π+1 to the vertices and edges of the face π
1 and assign the
remaining labels to the remaining vertices and edges of the graph. Now, the weight of the face π1=π9π+18=
π4(2π+4).ππ+2=ππ+2, since π2π+4= 1
πΈ. Also, the weight of the outer face π0= 1.π.π2.π3. . .π2π+3=ππ+2.
Thus πΊ obtained by duplication of any edge in path ππ by an edge is a face magic graph over πΈ.
Figure-6: Face magic πΈ-lableing of πΊ obtained by duplicating an edge of path ππ by an edge.
Proposition 2.14: The graph πΊ obtained by duplication of any edge by a vertex in path ππ admits a face magic πΈ -labeling with face constant ππ+1, for π β₯2.
Proof: Let π£1,π£2,. . . ,π£π be the vertices of the path ππ, for π β₯2.
By duplicating any edge π£ππ£π+1 by a vertex π’, 1β€ π β€ π β1, the resultant graph πΊ has vertex set π(ππ)βͺ{π’}, edge set
πΈ(ππ)βͺ{π’π£π,π’π£π+1} and face set {π0,π1} where π1 is the face bounded by the edges π£ππ£π+1,π’π£π+1,π’π£π and π0 is the
outer face bounded by all the edges of G.
Consider the cyclic group β©πβͺ of order π+π= 2π+ 2. Assign the labels 1,π,π2,ππβ1,ππ,ππ+1 to the vertices and
edges of the face π1 and assign the remaining labels to the remaining vertices and edges of the graph. Now, the weight
of the face π1=π3π+3=π2π+2.ππ+1=ππ+1, since π2π+2= 1πΈ. Also the weight of the outer face
π0= 1.π.π2.π3. . .π2π+1=ππ+1.
Thus πΊ obtained by duplication of any edge by a vertex in path ππ is a face magic graph over πΈ.
A face magic πΈ-labeling of πΊ obtained by duplication of any edge by a vertex in path ππ is shown in Figure 7.
Figure-7: Face magic πΈ-labeling of πΊ obtained by duplication of any edge by a vertex in path ππ with face constant
ππ+1.
Proposition 2.15: The graph πΊ obtained by duplication of any vertex by an edge in path ππ admits a face magic πΈ -labeling with face constant ππ+2.
Proof: Let π£1,π£2,. . . ,π£π be the vertices of the path ππ, for π β₯1.
By duplicating any vertex π£π by an edge π’π£, 1β€ π β€ π, the resultant graph πΊ has vertex set π(ππ)βͺ{π’,π£}, edge set
πΈ(ππ)βͺ{π’π£,π’π£π,π£π£π} and face set {π0,π1} where π1 is the face bounded by the edges π’π£,π’π£π,π£π£π and π0 is the outer
face bounded by all the edges of G.
Consider the cyclic group β©πβͺ of order π+π= 2π+ 4. Assign the labels 1,π,π2,ππ,ππ+1,ππ+2 to the vertices and
edges of the face π1 and assign the remaining labels to the remaining vertices and edges of the graph. Now, the weight
of the face π1 =π3π+6=π2π+4.ππ+2=ππ+2, since π2π+4= 1πΈ. Also, the weight of the outer face
π0= 1.π.π2.π3. . .π2π+3=ππ+2.
Thus πΊ obtained by duplication of any vertex by an edge in path ππ is a face magic graph over πΈ.
A face magic πΈ-labeling of πΊ obtained by duplication of any vertex by an edge in path ππ is shown in Figure 8.
Figure-8: Face magic πΈ-labeling of πΊ obtained by duplication of any vertex by an edge in path ππ with face constant
REFERENCES
1. N. Hartsfield and G. Ringel, Pearls in Graph Theory, Academic Press, San Diego, 1990.
2. W. D. Wallis, Magic Graphs, Birhauser, Borton-Bacel-Berlin, 2001.
3. J. A. Gallian, A dynamic survey of graph labeling, The Electronic Journal of Combinatorics, 5(2005), # DS6.
4. Dalibor Froncek, Group distance magic labeling of cartesian product of cycles, Australasian journal of
Combinatorics, 55 (2013), 167β174.
5. D.Combe, A.M.Nelson, W.D.Palmer, Magic labelings of graphs over finite abelian groups, Australasian
journal of Combinatorics, 29 (2004), 259β271.
6. Sylwia Cichacz, Note on Group Distance Magic Graphs πΊ(πΆ4), Graphs and Combinatorics, 30 (2014), 565β
571.
7. A.Durai Baskar and S.Arockiaraj, Further Results on Super Geometric Mean Graphs, International J.Math.
Combin., 4 (2015), 104β128.
8. A.Durai Baskar, S.Arockiaraj and B.Rajendran, Geometric meanness of graphs obtained from paths, Utilitas
Mathematica, 101 (2016), 45β68.
9. S.Arumugam, D. Froncek and N. Kamatchi, Distance Magic Graphs - A Survey, J. Indones. Math. Soc.
Special Ed. (2011), 1β9.
10. A.Meena Kumari and S.Arockiaraj, On (1,1,0)-F-face magic mean labeling of some graphs, Utilitas
Mathematica, 103 (2017), 139β159.
11. S.Arockiaraj and A.Meena Kumari, On F-face magic mean labeling of some planar graphs, International
Journal of Pure and Applied Mathematics,117,No.6 (2017), 1β8.
12. S.Arockiaraj and A.Meena Kumari, On F-face magic mean labeling of some duplicated graphs, International
Journal of Applied Mathematics, 31,No.2 (2018), 231β240.
Source of support: Nil, Conflict of interest: None Declared.