Solving Systems of
Equations
Objectives
• Learn the procedure of the Elimination
Method using addition
• Learn the procedure of the Elimination
Method using multiplication
• Solving systems of equations using the
Elimination Method
When to use
Elimination Method
• Elimination works because opposites
cancel each other out
– Example 3x + (-3x) = 0
Can you eliminate?
Consider the system x - 2y = 5
2x + 2y = 7
REMEMBER: We are trying to find the Point of Intersection. (x, y)
Step 1 – Eliminate like terms
Consider the system x - 2y = 5
2x + 2y = 7
Lets add both equations to each other
Step 2 – Cancel & solve
Consider the system x - 2y = 5
2x + 2y = 7
Lets add both equations to each other
+
3x = 12 x = 4
ANS: (4, y)
Step 3 – Substitute & solve
the other coefficient
Consider the system
2x + 2y = 7
Lets substitute x = 4 into this equation.
4 - 2y = 5 Solve for y - 2y = 1
y = 1
2
Which equation should we
substitute with?
Consider the system x - 2y = 5
ANS: (4, )
We could have substituted x = 4
into this equation (but it is harder) 2(4) + 2y = 7 Solve for y
8 + 2y = 7 -8 -8 2y = -1 2 2
1 2
Step 4 - Check
? ?
Example 2
Consider the system 3x + y = 14
4x - y = 7
Example 2
Consider the system 3x + y = 14
4x - y = 7 7x = 21
x = 3
ANS: (3, y)
+
Example 2
Consider the system
ANS: (3, )
3x + y = 14 4x - y = 7
Substitute x = 3 into this equation
3(3) + y = 14 9 + y = 14
y = 5
5
Example 2
Step 4: Check
Is the solution (3,5) ? Substitute & solve to check
Your Turn…
2x y
+
=
5
3x y
=
15
1. 2.
2y x
=
5
Your Turn (Answers)
2x y
+
=
5
3x y
=
15
1. 2.
2y x
=
5
6y x
+
=
11
Elimination using
Multiplication
Consider the system
Example 3) Elimination using
Multiplication
Consider the system
6x + 11y = -5 6x + 9y = -3
+
Example 3) Elimination using
Multiplication
Consider the system
6x + 11y = -5
6x + 9y = -3 Wouldn’t it be
easy to make the x coefficients
opposites?
Example 3) Elimination using
Multiplication
Consider the system
6x + 11y = -5 6x + 9y = -3
-1 ( ) Distribute
Example 3) Elimination using
Multiplication
Consider the system
- 6x - 11y = 5 6x + 9y = -3
+
-2y = 2 y = -1
ANS: (x, )-1
Example 3
Consider the system
6x + 11y = -5 6x + 9y = -3
ANS: (x, )-1
y = -1
Lets substitute y = -1 into this equation
6x + 9(-1) = -3 6x + -9 = -3
+9 +9 6x = 6
Example 3
Consider the system
6x + 11y = -5 6x + 9y = -3
ANS: ( , )-1
y = -1
Lets substitute y = -1 into this equation
6x + 9(-1) = -3 6x + -9 = -3
+9 +9 6x = 6
x = 1
1
Example 3
Is the solution (1,-1)? Substitute & solve to check
Step 5: Check
Example 4
Consider the system
x + 2y = 6 3x + 3y = -6
Multiply by -3 to eliminate the x term
Example 4
Consider the system
x + 2y = 6 3x + 3y = -6
-3 ( ) Distribute
Example 4
Consider the system
-3x + -6y = -18
3x + 3y = -6
+
-3y = -24 y = 8
ANS: (x, 8)
Example 4
Consider the system
x + 2y = 6 3x + 3y = -6
Substitute y =14 into equation
y =8
x + 2(8) = 6 x + 16 = 6
x = -10
Step 4: Substitute your answer to solve for the other coefficient
Example 4
Is the solution (-10,8)? Substitute & solve to check
Step 5: Check
Your Turn #2
1.
x + 2y = 5
2x + 6y = 12
2.
Your Turn #2
1.
x + 2y = 5
2x + 6y = 12
2.
ANS: (3, 1)
x + 2y = 4 x - 4y = 16
More complex Problems
Consider the system
3x + 4y = -25 2x - 3y = 6
Multiply by 2
Multiply by -3
Example 5
Consider the system 3x + 4y = -25
2x - 3y = 6
2( ) -3( )
Notice – both
equations need to be multiplied to get opposite
coefficients.
Example 5
Consider the system
6x + 8y = -50
-6x + 9y = -18
+
17y = -68 y = -4
ANS: (x, -4)
Example 5
Consider the system
3x + 4y = -25 2x - 3y = 6
ANS: (-3, -4) Substitute y = -4
2x - 3(-4) = 6 2x - -12 = 6
2x + 12 = 6 2x = -6
x = -3
Example 5
Is the solution (-3,-4)? Substitute & solve to check
? ?
Your Turn #3
1. 2.
4x + y = 9 3x + 2y = 8
Your Turn #3
1. 2.
4x + y = 9 3x + 2y = 8
2x + 3y = 1 5x + 7y = 3