On a Nonlinear Nonlocal Cauchy Problem
Sergiu Aizicovici
Abstract -We prove the existence of integral solutions to a nonlinear time-dependent functional differential equation with a nonlocal initial condition. The approach relies on the theory of m-accretive operators and compactness methods.
Index Terms-Compact evolution operator, evolution equation, m-accretive operator, nonlocal Cauchy problem.
I. INTRODUCTION
We are concerned with the existence of solutions to the nonlocal Cauchy problem
) ( ) 0 (
], , 0 [ ),
)( ( ) ( ) ( ) ( '
u g u
T I t t u F t u t A t u
=
= ∈ ∋
+
(1)
in a real Banach space X . Here {A(t):t∈I}are
m-accretive operators in X , while F ,gare functionals
defined on C(I;X)with values in L1(I;X)and X , respectively. Such problems arise in physics and engineering, in particular in the mathematical modeling of heat or diffusion processes, or in the study of atomic reactors; see [1]-[3].
The study of abstract evolution equations with nonlocal initial conditions was initiated by
Byszewski [4], who studied a problem of the form (1) whereA(t)=A,linear and independent of time,
)), ( , ( ) )(
(Fu t = f t u t f :I×X →X,and
), ( )
( 1
i p
i iu t c u
g
∑
=
= with0<t1 <...<tp ≤T
and ci∈R.
Manuscript received March 1, 2009.
S.A. Author is with the Department of Mathematics, Ohio University, Athens, OH 45701 USA (phone: 740-593-1272; fax: 740-593-9805; e-mail: [email protected]).
For some recent results on fully nonlinear nonlocal Cauchy problems, see [5]-[7]. In general, the existing results require a Lipschitz condition on F org,or a compactness assumption on g.In [8], the
authors remove these restrictions for a linear,
autonomous version of (1). It is our goal to generalize their approach to the fully nonlinear, time-dependent case.
II. PRELIMINARIES
In this section, we collect some basic facts on m-accretive operators, evolution operators and non-autonomous evolution equations; see [9], [10] for
details. Let ( X, .)be a real Banach space, of dual
). . *,
(X * The duality mapping J:X →X*is defined
by
, },
* )
( * : * * { )
(x x X x x x 2 x *2 x X
J = ∈ = = ∀ ∈
while the so-called upper semi-inner product is given by
. , )}, ( * : ) ( * sup{
,x x y x J x x y X
y > = ∈ ∀ ∈
< +
It can be shown that <.,.>+is upper semicontinuous on X×X. Let A be a multivalued operator onX,of
domain D(A)and range R( A).We say that A is
accretive if < y'−y,x'−x>+≥0for all x,x'∈D(A) and ally∈Ax,y'∈Ax'. If alsoR(Id+λA)= Xfor all
, 0 >
λ where Iddenotes the identity on X,then A is called m-accretive.
Let {A(t):t∈I}be a family of m-accretive
operators inX,of domains D(A(t)), with
)) ( (At
D = D (independent of t), which satisfy the
)
(HA(t) There exist two continuous functions
)) , 0 [ ( : , : 2
1 I→X m R+→R+ R+ = ∞
m such that
}), , (max{ ) ( ) ( , 2 1 2 2 1 2 1 2 1 2 1 x x m x x s m t m x x y y − − − ≥ > − − < + . 0 , ) ( )), ( ( , ) ( )), ( ( 2 2 2 1 1 1 T t s x s A y s A D x x t A y t A D x ≤ ≤ ≤ ∈ ∈ ∈ ∈ ∀
If (HA(t))holds, then the family {A(t):t∈I}
gives rise to an evolution operator U( st, )on D via
the formula x n s t i s A n s t Id x s t U n i n 1 1 )) ( ( lim ) , ( − = ∞ → − + − +
=
∏
, (2)for all x∈D,0≤s≤t≤T.
It follows that
U(t,t)=Idand U(t,s)x−U(t,s)y ≤ x−y,
for all x,y∈D,and all 0≤s≤t≤T.The evolution
operator U is said to be compact if U( st, )maps
bounded subsets of D into relatively compact subsets of D for all 0≤s<t≤T. In the special case when
A t
A()= is a time-independent m-accretive operator,
) ( ) 0 , (t St
U = is the contraction semigroup generated
by A− on D( A).
Next, consider the Cauchy problem
, ) 0 ( , ), ( ) ( ) ( ) ( ' 0 u u I t t f t u t A t u = ∈ ∋ + (3)
where {A(t):t∈I}satisfy (HA(t)),f ∈L1(I;X),and
. 0 D u ∈
Definition 1. An integral solution of problem (3) is a function u∈C( DI; )satisfying u(0)=u0and the
inequality , ] ) ( ) ( ) ( ) ( , ) ( [ 2 ) ( ) ( 1 1 2 2
τ
θ
τ
τ
τ
τ
d m m x u M x u y f x s u x t u t s − − + > − − < ≤ − − −∫
+ , ) ( )), ( ( ], , 0 [ ,0≤s≤t≤T θ∈ T x∈D Aθ y∈Aθ x
∀ and }). , (max{ ) ; ( 2 x u CI X m
M =
It is well-known that (3) has a unique integral
solution for each u0∈Dand f∈L1(I;X),provided that (HA(t))is satisfied. In particular, U(t,0)u0is the
integral solution of (3) whenf ≡0.
Proposition 2. Let (HA(t))be satisfied, and let
v
u, be integral solutions of (3), corresponding to
) ,
(u0 f and (v0,g),respectively (with u0,v0∈D
and f,g∈L1(I;X)). Then
. 0 , ) ( ) ( ) ( ) ( ) ( ) ( T t s d g f s v s u t v t u t
s − ∀ ≤ ≤ ≤
+ − ≤ −
∫
τ
τ
τ
(4)III. MAIN RESULTS
For a fixed finite r>0,we set
}. , ) ( : ) ; ( { }, : { I t B t X I C K r x X x B r r r ∈ ∀ ∈ ∈ = ≤ ∈ =
φ
φ
We assume that:
} ); ( { )
(H1 At t∈I satisfy(HA(t)),and the
corresponding evolution operatorU (given by (2)) is compact;
)
(H2 The operator F:C(I;X)→L1(I;X)is
continuous, and there exists α=αr∈L1(I;R+)such that
F(u)(t) ≤α(t),a.e. on ,I for all u∈Kr;
)
(H3 The function g:C(I;X)→Dis continuous
and maps Krinto a bounded set;
)
(H4 There exists δ ∈( T0, )such that
) ( ) ( ), ( )
(u F v gu g v
F = = for any u,v∈Krwith
]; , [ ), ( )
(s vs s T
)
(H5 +
∫
≤∈ ∈
T
K I t
r d g
t U
r 0
,
. ) ( )
( ) 0 , (
sup φ α τ τ
φ
Definition 3. A function u∈C( DI; )is called an
integral solution of problem (1), if it is an integral solution, in the sense of Definition 1, of problem (3) with F(u)(t)in place of f(t),and g(u)in place of
. 0 u
Theorem 4. Let (H1)−(H5)be satisfied. Then
problem (1) has at least one integral solution.
This result does not cover the case when ))
( , ( ) )(
(u t f t u t
F = for a given function
, :I X X
f × → since (H4)is not satisfied. We now
replace (H4)by the following condition:
)
(H4# limε↓0 g(φ)−g(φε) =0,uniformly for all ,
r K ∈
φ with
≤ ≤
≤ ≤ =
. ),
(
, 0 ), ( ) (
T t t
t t
ε φ
ε ε
φ φε
Theorem 5. Let (H1)−(H3),(H4#)and (H5)be
satisfied. Then problem (1) has at least one integral solution.
IfA(t)= A(independent of time), then the
evolution operator Uis replaced by the contraction
semigroup S(t)generated by A− (cf. Section II). The
corresponding autonomous initial-value problem (3) has a unique integral solution (that is, a function
) ( ; (I D A C
u∈ ) satisfying the inequality in Definition
1 with M =0)for any f∈L1(I;X)and u0∈D(A).
Theorem 5 now yields the following result:
Corollary 6. Let A be an m-accretive operator inX,such that S(t),the semigroup generated by
A
− on D( A), is compact for t>0.If also
) ( ),
(H2 H3 (with D=D( A)), (H4#)and (H5)(with
) (t
S in place of U(t,0)) are satisfied, then there
exists an integral solution of the problem
). ( ) 0 (
, ), )( ( ) ( ) ( '
u g u
I t t u F t Au t u
=
∈ ∋
+
(5)
Remark 7. In the special case when
F(u)(t)= f(t,u(t)), f :I×X →X,
where f satisfies Caratheodory type conditions,
Corollary 6 is comparable to Theorem 4.3 in [7], which was proved by a different method.
IV. PROOF OF THEOREM 4
We sketch the proof of Theorem 4, only. The proof of Theorem 5 can be carried out by using Theorem 4, and adapting the approximating procedure of [8]. The details will appear elsewhere.
Set
]}. , [ , ) ( : ) ]; , ([ { )
( u C T X ut r t T
Kr δ = ∈ δ ≤ ∀ ∈δ
For any u∈Kr(δ),let u~∈Krbe given by
≤ ≤
≤ ≤ =
. ),
(
, 0 ), ( ) ( ~
T t t u
t u
t u
δ δ δ
Also, define
). ~ ( ) ( ~ ; )), ( ~ ( ) )( ( ~
u g u g I t t u F t u
F = ∈ = (6)
By (H2)−(H4)and (6), it follows that F~and g~are
continuous from Kr(δ)to L1(I;X)and D ,
respectively. In addition, we have
F~(u)(t) ≤α(t),a.e. on I,∀u∈Kr(δ), (7)
. ) ( ) 0 , ( sup ) ( ~ ) 0 , ( sup
, )
( ,
∞ < =
∈ ∈ ∈
∈Iu Kr U t g u t Iv KrU t g v
t δ
(8)
Define the map Ψ:Kr(δ →) C([δ,T];X)by
), ( ],
, [ ), ( ) )(
(w t =uw t t∈ δ T w∈Kr δ
Ψ where uwis
the unique integral solution of
) ( ~ ) 0 (
, ), )( ( ~ ) ( ) ( ) (
w g u
I t t w F t u t A t u dt d
w
w w
=
∈ ∋
+
From (4) we infer that
() (,0)~( ) ~( )( ) . 0 F w s ds w
g t U t
uw − ≤
∫
tThis, (7), (8) and (H5)lead to
, , ) (
) ( ) 0 , ( sup )
(
0 ,
I t r ds s
v g t U t
u
T K v I t w
r
∈ ∀ ≤
+ ≤
∫
∈ ∈
α (10)
so that Ψmaps Kr(δ)into itself. Moreover, on
account of (4), (6), (H2),(H3),Definition 1 and the
upper semicontinuity of <.,.>+, it is easily seen that Ψis continuous. Next, employing (6), (7),
) ( )
(H1 − H3 and the theory of [11], we deduce that
)) ( (Kr δ
Ψ is relatively compact in C([δ,T];X). Applying Schauder’s fixed point theorem, we
conclude that Ψhas a fixed point w*∈Kr(δ).
Let u(t)=uw*(t),t∈Iand remark that
]. , [ ), ( ) ( ) *)( ( ) (
* t w t u * t u t t T
w =Ψ = w = ∀ ∈δ This,
together with (H4), (9) and (10), implies that uis an
integral solution of (1), as desired. The proof is complete.
V. AN APPLICATION
For simplicity, we restrict ourselves to an example that illustrates Corollary 6. Consider the initial-boundary value problem
, ), , ( )
( ) , 0 (
, )
, ( )), , ( ( ) , (
, ) , ( , ) , ( ) (
)) , ( , ( ) , ( ) , (
1 0
0
Ω ∈ +
=
Ω ∂ × ∈ ∈
∂ ∂ −
Ω × ∈ −
+ =
∆ −
∑
∫
=
x x t u c x u x u
I x t x t u x t n u
I x t ds x s u s t k
x t u t h x t u x t u
p
i i i t
t
β (11)
where Ωis a bounded domain in RNwith a smooth boundary ∂Ω,βis an m-accretive operator on R with
n ∂
∂ ∈ (0),
0 β denotes the outward normal derivative,
, ...
0<t1< <tp ≤T ci,i=1,...pare given constants,
, :
), ( 1
R R I h I L
k∈ × → and u0∈L2(Ω).This
problem can be written in the form (1) in the
spaceX =L2(Ω),by setting
), ( :
) ( { ) (
, 2 u
n u H
u A D
A ∈β
∂ ∂ − Ω ∈ = ∆
−
= a.e. on
}, Ω ∂
∫
−+
=ht ut x tkt s u s x ds x
t u F
0 ( ) ( , ) , ))
, ( , ( ) )( )(
( (12)
= ) )( (u x
g ( ) ( , ),(, ) .
1
0 +
∑
∈ ×Ω=
I x t x t u c x u
p
i i i
It is well-known [10] that A is m-accretive in X with D(A)= X,and that the semigroup S(t)
generated by A− on X is compact (for t>0), with .
0 , 0 0 )
(t = ∀t≥
S Assume that
)
(H6 t→h( yt, )is measurable in tfor all y∈R,and
continuous in yfor a.a. t∈I;
)
(H7 There exist 0, ( ; ) 1
+
∈ > b L I R
a such that
), ( )
,
(t y ay bt
h ≤ +
for almost all t∈Iand all y∈R..
Then, it is easily verified that F and g,as given in
(12), satisfy (H2),and respectively (H3)and ( ). # 4 H
Finally, in this set-up, condition (H5)reduces to
) (H8
, ) (
) (
2 / 1 ) (
) ( 1
) ( 0
1
1 2
r b
k T c a r u
I L
I L p
i i L
≤ Ω
+ +
+
+
∑
= Ω
µ
where µdenotes the Lebesgue measure.
Corollary 8. Ifu0∈L2(Ω),k∈L1(I)and
) ( )
(H6 − H8 hold, then problem (1) has at least one
integral solution u∈C(I;L2(Ω)).
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