Journal of Inequalities and Applications Volume 2011, Article ID 320932,17pages doi:10.1155/2011/320932
Research Article
Precise Asymptotics in the Law of
Iterated Logarithm for Moving Average
Process under Dependence
Jie Li
1, 21Wang Yanan Institute for Studies in Economics, Xiamen University, Xiamen 361005, China 2School of Mathematics and Statistics, Zhejiang University of Finance and Economics,
Hangzhou 310018, China
Correspondence should be addressed to Jie Li,[email protected]
Received 10 November 2010; Revised 2 February 2011; Accepted 3 March 2011
Academic Editor: Ulrich Abel
Copyrightq2011 Jie Li. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
Let{ξi, −∞< i <∞}be a doubly infinite sequence of identically distributed andφ-mixing random
variables, and let{ai, −∞< i <∞}be an absolutely summable sequence of real numbers. In this
paper, we get precise asymptotics in the law of the logarithm for linear process{Xki∞−∞aikξi,
k ≥1}, which extend Liu and Lin’s2006result to moving average process under dependence assumption.
1. Introduction and Main Results
Let {ξi, −∞ < i < ∞} be a doubly infinite sequence of identically distributed random variables with zero means and finite variances, and let{ai, −∞ < i < ∞}be an absolutely summable sequence of real numbers. Let
Xk
∞
i−∞
aikξi, k≥1, 1.1
be the moving average process based on{ξi, −∞< i <∞}. As usual, we denoteSn
n
k1Xk,
n≥1 as the sequence of partial sums.
Li et al.4obtained the complete convergence result for{Xk, k≥1}. As we know,Xk k≥1 are dependent even if{ξi, −∞ < i <∞}is a sequence of i.i.d. random variables. Therefore, we introduce the definition ofφ-mixing,
φm:sup k≥1
|PB|A−PB|, A∈ Fk−∞, PA/0, B∈ F∞km−→0, m−→ ∞, 1.2
whereFb
aσξi, a≤i≤b. Many limiting results of moving average forφ-mixing have been obtained. For example, Zhang5got complete convergence.
Theorem A. Suppose that{ξi, −∞< i <∞}is a sequence of identically distributed andφ-mixing random variables with∞m1φ1/2m<∞, and{X
k, k≥1}is defined as1.1. Lethx>0 x > 0be a slowly varying function and1≤t <2,r≥1, thenEξ10andE|ξ1|rth|Ytt|<∞imply
∞
n1
nr−2hnP|Sn| ≥n1/t
<∞, ∀ >0. 1.3
Li and Zhang6achieved precise asymptotics in the law of the iterated logarithm.
Theorem B. Suppose that{ξi, −∞ < i <∞}is a sequence of identically distributed andφ-mixing random variables with mean zeros and finite variances,∞m1φ1/2m < ∞, and 0 < σ2 Eξ2
1
2nk2Eξ1ξk < ∞,Eξ12log|ξ1|δ−1 < ∞, forδ > 0. Suppose that{X, Xk, k ≥ 1}is defined as in
1.1, where{ai, −∞< i <∞}is a sequence of real number with∞i−∞|ai|<∞, then one has
lim 0
2δ2∞
n2
logn δ n P
|Sn| ≥
nlognτ
τ2δ2
δ1E|N|
2δ2, 1.4
whereτ :σ∞i−∞ai,Nis a standard normal random variable.
On the other hand, since Hsu and Robbins7introduced the concept of the complete convergence, there have been extensions in some directions. For the case of i.i.d. random variables, Davis 8 proved ∞n1logn/nP|Sn| ≥
nlogn < ∞, for > 0 if and only if EX1 0, EX21 < ∞. Gut and Sp˘ataru 9 gave the precise asymptotics of
∞
n2lognδ/nP|Sn| ≥
nlogn. We know that complete convergence can be derived from complete moment convergence. Liu and Lin10introduced a new kind of convergence of ∞n2lognδ−1/n2E|Sn|2I{|Sn| ≥
nlogn}. In this note, we show that the precise asymptotics for the moment convergence hold for moving-average process when{ξi, −∞ <
i <∞}is a strictly stationaryφ-mixing sequences. Now, we state the main results.
distributedφ-mixing random variables with mean zeros and finite variances,∞m1φ1/2m<∞and
0< σ2Eξ2 12
n
k2Eξ1ξk<∞,Eξ21log|ξ1|δ<∞, for0< δ≤1, then one has
lim 0
2δ∞
n2
lognδ−1 n2 E|Sn|
2
I
|Sn| ≥
nlognτ
τ2δ2
δ E|N|
2δ2, 1.5
whereτ :σ∞i−∞ai.
Theorem 1.2. Under the conditions inTheorem 1.1, one has
lim 0
2δ∞
n3
log logn δ−1 n2logn ES
2
nI
|Sn| ≥
nlog lognτ
τ2δ2E|N|2δ1
δ . 1.6
Remark 1.3. In this paper, we generate the results of Liu and Lin10to linear process under dependence based on Theorem B by using the technique of dealing with the innovation process in Zhang5.
We first proceed with some useful lemmas.
Lemma 1.4. Let{X, Xk, k ≥ 1}be defined as in1.1, and let{ξi, −∞ < i < ∞}be a sequence of identically distributedφ-mixing random variables withEξ1 0, Eξ12 < ∞,0 < σ2 Eξ21
2∞k2Eξ1ξk<∞,∞m1φ1/22m<∞, then
Sn
τ√n
D
−→N0,1. 1.7
The proof is similar to Theorem 1 in11. SetΔn supx|P|Sn| ≥
√
nx−P|N| ≥x|. FromLemma 1.4, one can getΔn → 0 asn → ∞.
Lemma 1.5see2. Let i∞−∞ai be an absolutely convergent series of real numbers with a
∞
i−∞aiandk≥1, then
lim n→ ∞
1
n
∞
i−∞
in
ji1
aj k
|a|k. 1.8
Lemma 1.6see12. Let{Xi, i≥1}be a sequence ofφ-mixing random variables with zero means and finite second moments. LetSn
n
i1Xi. If existsCnsuch thatmax1≤i≤nES2n ≤Cn, then for all
q≥2, there existsCCq, φ·such that
Emax
1≤i≤n|Si| q≤C
Cq/n 2Emax
1≤i≤n|Xi| q
2. Proofs
Proof ofTheorem 1.1. Without loss of generality, we assume thatτ1. We have
∞
n2
logn δ−1 n2 ES
2
nI
|Sn| ≥
nlogn
2
∞
n2
logn δ n P
|Sn| ≥
nlogn
∞
n2
logn δ−1 n2
∞
√
nlogn
2xP|Sn| ≥xdx.
2.1
Setd expM−2, whereM >1. By Theorem B, we need to show
lim 0
2δ∞
n2
logn δ−1 n2
∞
√
nlogn
2xP|Sn| ≥xdx 1
δδ1E|N|
2δ2. 2.2
By Proposition 5.1 in10, we have
lim 0
∞
n2
logn δ−1 n2
∞
√
nlogn 2xP
|N| ≥ √x n
dx 1
δδ1E|N|
2δ2. 2.3
Hence,Theorem 1.1will be proved if we show the following two propositions.
Proposition 2.1. One has
lim 0
2δd
n2
logn δ−1 n2
∞
√
nlogn
2xP|Sn| ≥xdx−
∞
√
nlogn 2xP
|N| ≥ √x n
dx0. 2.4
Proof. Write
d
n2
logn δ−1 n2
∞
√
nlogn
2xP|Sn| ≥xdx−
∞
√
nlogn 2xP
|N| ≥ √x n
dx
≤
d
n2
logn δ−1 n logn
×
∞
0
2xP
|Sn| ≥
nlognx
−P
|N| ≥
lognxdx
≤d
n2
logn δ−1
n Δn1 Δn2 Δn3,
where
Δn1logn
1/√lognΔ1/4
n
0
2xP
|Sn| ≥
nlognx
−P
|N| ≥
lognxdx,
Δn2logn
∞
1/√lognΔ1/4
n
2xP
|Sn| ≥
nlognx
dx,
Δn3logn
∞
1/√lognΔ1/4
n
2xP
|N| ≥
lognx
dx.
2.6
Sincen≤dimplieslogn≤√M, we have
Δn1≤ClognΔn ⎛ ⎜
⎝ 1
lognΔ1n/4
⎞ ⎟ ⎠ 2
≤CΔ1n/4
MΔn 2
. 2.7
ForΔn3, by Markov’s inequality, we get
Δn3≤Clogn
∞
1/√lognΔ1/4
n
1
logn 3/2x2dx≤CΔ
1/4
n . 2.8
From2.7and2.8, we can get
lim 0
2δ d
n2
logn δ−1
n Δn1 Δn3 0. 2.9
Note thatnk1Xk
∞
i−∞nk1akiξi
∞
i−∞aniξi, whereani
n
k1aki. ByLemma 1.5, we can assume that
∞
i−∞
|ani|t≤n, t≥1, a
∞
i−∞
|ai| ≤1. 2.10
SetSn
∞
i−∞aniξiI{|aniξi| ≤
nlognx}. AsEξ10, by2.10, we have
ES
n≤C E
∞
i−∞
aniξiI
|aniξi|>
nlognx
≤C
∞
i−∞
|ani|E|ξ1|I
|aniξ1|>
nlognx
≤CnE|ξ1|I
a|ξ1|>
nlognx
≤CnE|ξ1|I
|ξ1|>
nlognx
≤CnEξ211/2
P
|ξ1|>
nlognx
1/2
≤C
√
nEξ2 1
lognx .
2.11
So, whenx∈1/
lognΔ1n/4,∞,
|ESn|
nlognx
≤C Eξ
2 1
logn1/lognΔ1n/4
2 < , fornlarge enough. 2.12
By2.12, we have
d
n2
logn δ−1 n Δn2
≤d
n2
∞
1/√lognΔ1/4
n
logn δx n
×
⎡ ⎢ ⎣P
sup
i
|aniξi|>
nlognx
P
⎛ ⎜
⎝Sn−ESn≥
nlognx
2
⎞ ⎟ ⎠ ⎤ ⎥ ⎦dx
:H1H2.
2.13
SetInj {j ∈ L, 1/j1<|anj| ≤1/j, j 1,2, . . .}, then !
j≥1Inj Lreferred by4. We can get
k
j1
#Inj ≤nk1. 2.14
Then,
P
" sup
i
|aniξi|>
nlognx
#
≤ ∞
i−∞
P
|aniξi|>
nlognx
≤∞
j1
i∈Inj
P
|ξ1| ≥
nlognjx
≤∞
j1
#Inj P
|ξ1| ≥
nlognjx
≤∞
j1
k≥j
#Inj P
nlognkx≤ |ξ1|<
nlognk1x
≤∞
k1 k
j1
#Inj P
nlognkx≤ |ξ1|<
nlognk1x
≤∞
k1
nk1P
nlognkx≤ |ξ1|<
nlognk1x
≤ √
nE|ξ1|I
|ξ1| ≥
nlognx
lognx
.
2.15
So, we get
H1≤CE|ξ1|
∞
1/√lognΔ1n/4
d
n2
logn δ−1/2 n1/2
×∞
kn
I
klogkx<|ξ1| ≤
k1logk1x
dx
≤C
∞
0 ∞
k2
E|ξ1|I
klogkx<|ξ1| ≤
k1logk1x
dx
k
n2
logn δ−1/2 n1/2
≤CEξ2 1
∞
0
x−1
∞
k2
logk δ−1I
klogkx<|ξ1| ≤
k1logk1x
dx
≤CEξ21
∞
0
log|ξ1| −logxδ−1x−1I{|ξ1|>x}dx
≤CEξ21log|ξ1| −logδ≤CEξ12
log|ξ1| δCEξ12
−log δ.
2.16
Therefore,
lim 0
2δH
ByLemma 1.6, noting that∞m1φ1/2m<∞, forq >2,
H2≤C
d
n2
∞
0
logn δ−q/2 n1q/2 x
1−q
×
⎧ ⎨ ⎩
∞
i−∞
Eaniξ12I
|aniξ1| ≤
nlognx
q/2
∞
i−∞
E|aniξ1|qI
|aniξ1| ≤
nlogn
∞
i−∞
E|aniξ1|qI
nlogn <|aniξ1| ≤
nlognx
⎫⎬
⎭dx
:H21H22H23.
2.18
ForH21, we have
H21≤
d
n2
∞
0
logn δ−q/2 n x
1−q
Eξ21I
|aniξ1| ≤
nlognx
q/2
dx
≤C−2δMδ1−q/2.
2.19
Then, for 0< δ≤1,q >2, we have
lim
M→ ∞lim sup0 2δH
210. 2.20
ForH22, we decompose it into two parts,
H22≤
d
n2
∞
0
logn δ−q/2 n1q/2 x
1−q∞
j1
i∈Inj
|ani|qE|ξ1|qI
|aniξ1| ≤
nlogn
dx
≤2−q
d
n2
logn δ−q/2 n1q/2
×∞
j1
#Inj j−q ⎧ ⎨ ⎩
2n
k0
E|ξ1|qI
klogk≤ |ξ1|<
k1logk1
j1n
k2n1
E|ξ1|qI
klogk≤ |ξ1|<
k1logk1
⎫⎬
⎭
:H221H222.
It is easy to see that
∞
jm
#Inj j1 −qm1q−1≤
∞
j1
#Inj j1 −1 ≤
∞
i−∞
|ani|
∞
j1
i∈Inj
|ani| ≤n. 2.22
So,
∞
jm
#Inj j−q ≤Cnm−q−1. 2.23
Now, we estimateH221, by2.23,
H221≤2−q
d
n2
logn δ−q/2 nq/2
2n
k0
E|ξ1|qI
klogk≤ |ξ1|<
k1logk1
≤2−q
d
k2
E|ξ1|qI
klogk≤ |ξ1|<
k1logk1
d
nk/2
logn δ−q/2 nq/2
≤2−q
d
k2
logk δ−q/2 kq/2−1 E|ξ1|
qIklogk≤ |ξ
1|<
k1logk1
≤d
k2
logk δ−1Eξ21I
klogk≤ |ξ1|<
k1logk1
≤
d
k2
logk −1log|ξ1| −logδEξ12I
klogk≤ |ξ1|<
k1logk1
≤CEξ12log|ξ1| δCEξ12
−log δ.
2.24
ForH222, we have
H222≤2−q
d
n2
logn δ−q/2 n1q/2
× ∞
k2n1
j≥k/n−1
#Inj j−qE|ξ1|qI
klogk≤ |ξ1|<
k1logk1
≤2−q
d
n2
logn δ−q/2 n1−q/2
∞
k2n1
k1−qE|ξ1|qI
klogk≤ |ξ1|<
k1logk1
≤
d
k2
logk δ−1Eξ12I
klogk≤ |ξ1|<
k1logk1
≤d
k2
logk −1log|ξ1| −logδEξ12I
klogk≤ |ξ1|<
k1logk1
≤CEξ12log|ξ1| δCEξ21−logδ.
From2.24and2.25, we can get
lim 0
2δH
22 lim
0 2δH
221lim
0 2δH
2220. 2.26
Finally,q >2, and we will get
H23 ≤C
d
n2
logn δ−q/2 n1q/2 E|ξ1|
q
I
|aξ 1|>
nlogn
×
∞
0
x1−q
∞
j1
#Inj j−q ⎧ ⎨ ⎩
2n
k0
j1n
k2n1 ⎫ ⎬ ⎭
×I
klogkx<|ξ1| ≤
k1logk1x
dx
≤C
d
n2
logn δ−q/2 nq/2 E|ξ1|
q
I
|aξ 1|>
nlogn
×
∞
0
x1−qI
|ξ1| ≤
2nlog2nx
dxC
d
n2
logn δ−q/2 n1−q/2 E|ξ1|
q
×
∞
0 ∞
k2n1
k1−q
xq−1I
klogkx<|ξ1| ≤
k1logk1x
dx
≤C
∞
k2
Eξ21I
klogk <|ξ1| ≤
k1logk1
k
n2
logn δ−1 n
CEξ12
∞
0
x−1
×∞
k4
logk δ−1I
klogkx<|ξ1| ≤
k1logk1x
dx
≤C
∞
k2
logk δEξ2 1I
klogk <|ξ1| ≤
k1logk1
CEξ12
∞
0
log|ξ1| −logxδ−1x−1I{|ξ1|>x}dx
≤CEξ21log|ξ1| −logδ≤CEξ21
log|ξ1| δCEξ12
−log δ,
2.27
then
lim 0
2δH
230. 2.28
Proposition 2.2. One has
lim 0
2δ ∞
nd1
logn δ−1 n2
∞
√
nlogn
2xP|Sn| ≥xdx−
∞
√
nlogn 2xP
|N| ≥√x n
dx0.
2.29
Proof. Consider the following:
∞
nd1
logn δ−1 n2
∞
√
nlogn
2xP|Sn| ≥xdx−
∞
√
nlogn 2xP
|N| ≥ √x n
dx
≤ ∞
nd1
logn δ n
∞
0
2xP
|N| ≥
lognx
∞
nd1
logn δ n
∞
0
2xP
|Sn| ≥
nlognx
dx
:G1G2.
2.30
We first estimateG1, forθ >2δ, by Markov’s inequality,
G1≤ ∞
nd1
logn δ n
∞
0
1
logn θ2/2xθ1dx
≤CMδ−θ/2−2δ.
2.31
Hence,
lim
M→ ∞lim sup0 2δG
10. 2.32
Now, we estimateG2. Here,n > M−2, so
|ESn|
nlognx
< Eξ
2 1
logn x2 < Eξ2
1
We have
G2≤ ∞
nd1
logn δ n
∞
0
x
⎡ ⎢ ⎣P
sup
i
|aniξi|>
nlognx
P
⎛ ⎜
⎝Sn−ESn≥
nlognx
2
⎞ ⎟ ⎠ ⎤ ⎥ ⎦dx
:G21G22.
2.34
We estimateG21first. Similar to the proof of2.16, we have
G21≤CE|ξ1|
∞
0 ∞
nd1
logn δ−1/2 n1/2
×∞
kn
I
klogkx<|ξ1| ≤
k1logk1x
dx
≤CE|ξ1|
∞
0 ∞
kd1
I
klogkx<|ξ1| ≤
k1logk1x
dx
× k
nd1
logn δ−1/2 n1/2
≤CEξ12
∞
0 ∞
kd1
logn δ−1x−1
×I
klogkx<|ξ1| ≤
k1logk1x
dx
≤CEξ12
∞
0
log|ξ1| −logxδ−1x−1I{|ξ1|>x}dx
≤CEξ12log|ξ1| −logδ≤CEξ12
log|ξ1| δCEξ12
−log δ,
2.35
then
lim
M→ ∞lim sup0 2δG
ByLemma 1.6, forq >2, we have
G22 ∞
nd1
logn δ n
∞
0
xP
⎧ ⎪ ⎨ ⎪ ⎩S
n−ESn≥
nlognx
2
⎫ ⎪ ⎬ ⎪ ⎭dx
≤ ∞
nd1
logn δ−q/2 n1q/2
×
∞
0
x1−q
⎧ ⎨ ⎩
∞
i−∞
Eaniξ12I
|aniξi| ≤
nlognx
q/2
∞
i−∞
E|aniξ1|qI
|aniξi| ≤
nlogn
∞
i−∞
E|aniξ1|qI
nlogn <|aniξi| ≤
nlognx
⎫⎬
⎭dx
:G221G222G223.
2.37
ForG221, we have
G221≤ ∞
nd1
∞
0
lognδ−q/2 n x
1−qEξ2
1I{|aniξ1| ≤nx} q/2
dx
≤C2−q
∞
nd1
logn δ−q/2 n ≤CM
δ1−q/2−2δ.
2.38
Next, turning toG222, it follows that
G222≤2−q ∞
nd1
logn δ−q/2 n1q/2
×∞
j1
#Inj j−q ⎧ ⎨ ⎩
2n
k2
E|ξ1|qI
klogk≤ |ξ1|<
k1logk1
j1n
k2n1
E|ξ1|qI
klogk≤ |ξ1|<
k1logk1
⎫⎬
⎭
:G2221G2222,
then
G2221≤C2−q ∞
nd1
logn δ−q/2 nq/2
2n
k2
E|ξ1|qI
klogk≤ |ξ1|<
k1logk1
≤C2−q
∞
k2
E|ξ1|qI
klogk≤ |ξ1|<
k1logk1
∞
nk/2
logn δ−q/2 nq/2
≤C2−q
∞
k2
logk δ−q/2 kq/2−1 E|ξ1|
q
I
klogk≤ |ξ1|<
k1logk1
≤C
∞
k2
logk δ−1Eξ12I
klogk≤ |ξ1|<
k1logk1
≤C
∞
k2
logk −1log|ξ1| −logδEξ12I
klogk≤ |ξ1|<
k1logk1
≤CEξ21log|ξ1| δCEξ21
−log δ.
2.40
ForG2222, it follows that
G2222≤C2−q ∞
nd1
logn δ−q/2 n1q/2
× ∞
k2n1
j≥k/n−1
#Inj j−qE|ξ1|qI
klogk≤ |ξ1|<
k1logk1
≤C2−q
∞
kd1
k1−qE|ξ1|qI
klogk≤ |ξ1|<
k1logk1
k/2
nd1
logn δ−q/2 n1−q/2
≤C
∞
kd1
logk δ−1Eξ12I
klogk≤ |ξ1|<
k1logk1
≤C
∞
kd1
logk −1log|ξ1| −logδEξ12I
klogk≤ |ξ1|<
k1logk1
≤CEξ21log|ξ1| δCEξ21
−log δ.
Finally,q >2, we have
G223≤C ∞
nd1
logn δ−q/2 n1q/2 E|ξ1|
q
I
|aξ 1|>
nlogn
×
∞
0
x1−q
∞
j1
#Inj j−q ⎧ ⎨ ⎩
2n
k0
j1n
k2n1 ⎫ ⎬ ⎭
×I
klogkx<|ξ1| ≤
k1logk1x
dx
≤C
∞
nd1
logn δ−q/2 nq/2 E|ξ1|
q
I
|aξ 1|>
nlogn
×
∞
0
x1−qI
|ξ1| ≤
2nlog2nx
dxC
∞
nd1
logn δ−q/2 n1−q/2 E|ξ1|
q
×
∞
0 ∞
k2n1
k1−q
xq−1I
klogkx<|ξ1| ≤
k1logk1x
dx
≤C
∞
kd1
Eξ21I
klogk <|ξ1| ≤
k1logk1
k
nd1
logn δ−1 n
CEξ12
∞
0
x−1
× ∞
kd1
logk δ−1I
klogkx<|ξ1| ≤
k1logk1x
dx
≤C
∞
k2
logk δEξ2 1I
klogk <|ξ1| ≤
k1logk1
CEξ12
∞
0
log|ξ1| −logxδ−1x−1I{|ξ1|>x}dx
≤CEξ2
1log|ξ1| −logδ≤CEξ21
log|ξ1| δCEξ21
−log δ.
2.42
From2.38to2.42, we can get
lim M→ ∞lim0
2δG
22 0. 2.43
Proof ofTheorem 1.2. Without loss of generality, we setτ1. It is easy to see that
∞
n3
log logn δ−1 n2logn ES
2
nI
|Sn| ≥
nlog logn
2
∞
n3
log logn δ nlogn P
|Sn| ≥
nlog logn
∞
n3
log logn δ−1 n2logn
∞
√
nlog logn
2xP|Sn| ≥xdx.
2.44
So, we only prove the following two propositions:
2δ2
∞
n3
log logn δ nlogn P
|Sn| ≥
nlog logn
E|N|2δ1
δ1 , 2.45
2δ
∞
n3
log logn δ−1 n2logn
∞
√
nlog logn
2xP|Sn| ≥xdx E|N|
2δ1
δδ1 . 2.46
The proof of2.45can be referred to6, and the proof of2.46is similar to Propositions2.1 and2.2.
Acknowledgments
The author would like to thank the referee for many valuable comments. This research was supported by Humanities and Social Sciences Planning Fund of the Ministry of Education of PRC.no. 08JA790118
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