Volume 2010, Article ID 396080,14pages doi:10.1155/2010/396080
Research Article
Convergence Theorems Concerning Hybrid
Methods for Strict Pseudocontractions and
Systems of Equilibrium Problems
Peichao Duan
College of Science, Civil Aviation University of China, Tianjin 300300, China Correspondence should be addressed to Peichao Duan,[email protected]
Received 23 May 2010; Revised 23 August 2010; Accepted 26 August 2010
Academic Editor: S. Reich
Copyrightq2010 Peichao Duan. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
Let{Si}Ni1be N strict pseudo-contractions defined on a closed and convex subset C of a real
Hilbert space H. We consider the problem of finding a common element of fixed point set of these mappings and the solution set of a system of equilibrium problems by parallel and cyclic algorithms. In this paper, new iterative schemes are proposed for solving this problem. Furthermore, we prove that these schemes converge strongly by hybrid methods. The results presented in this paper improve and extend some well-known results in the literature.
1. Introduction
LetHbe a real Hilbert space with inner product·,·and norm · . LetCbe a nonempty, closed, and convex subset ofH.
Let{Fk}be a countable family of bifunctions fromC×CtoR, whereRis the set of
real numbers. Combettes and Hirstoaga1considered the following system of equilibrium problems:
findingx∈Csuch thatFkx, y≥0, ∀k∈Γ, ∀y∈C, 1.1
whereΓis an arbitrary index set. IfΓis a singleton, then problem1.1becomes the following equilibrium problem:
findingx∈Csuch thatFx, y≥0, ∀y∈C. 1.2
A mappingSofCis said to be aκ-strict pseudocontraction if there exists a constant
κ∈0,1such that
Sx−Sy2≤x−y2κI−Sx−I−Sy2 1.3
for allx, y∈C; see2. We denote the fixed point set ofSbyFS, that is,FS {x∈
C:Sxx}.
Note that the class of strict pseudocontractions properly includes the class of nonexpansive mappings which are mappingSonCsuch that
Sx−Sy≤x−y 1.4
for all x, y ∈ C. That is, S is nonexpansive if and only if S is a 0-strict pseudocontraction.
The problem 1.1 is very general in the sense that it includes, as special cases, optimization problems, variational inequalities, minimax problems, Nash equilibrium problem in noncooperative games, and others; see, for instance,1,3,4and the references therein. Some methods have been proposed to solve the equilibrium problem1.1; related work can also be found in5–8.
Recently, Acedo and Xu9considered the problem of finding a common fixed point of a finite family of strict pseudo-contractive mappings by the parallel and cyclic algorithms. Very recently, Duan and Zhao10considered new hybrid methods for equilibrium problems and strict pseudocontractions. In this paper, motivated by5, 8–12, applying parallel and cyclic algorithms, we obtain strong convergence theorems for finding a common element of the fixed point set of a finite family of strict pseudocontractions and the solution set of the system of equilibrium problems1.1by the hybrid methods.
We will use the following notations:
1for the weak convergence and → for the strong convergence,
2ωwxn {x:∃xnj x}denotes the weakω-limit set of{xn}.
2. Preliminaries
We will use the facts and tools in a real Hilbert spaceHwhich are listed below.
Lemma 2.1. LetHbe a real Hilbert space. Then the following identities hold: ix−y2x2− y2−2x−y, y, for allx, y∈H,
iitx1−ty2tx21−ty2−t1−tx−y2, for allt∈0,1, for allx, y∈H.
Lemma 2.2see6. LetHbe a real Hilbert space. Given a nonempty, closed, and convex subset
C⊂H, pointsx, y, z∈H, and a real numbera∈R, then the set
v∈C:y−v2≤ x−v2z, va 2.1
Recall that given a nonempty, closed, and convex subsetCof a real Hilbert spaceH, for anyx∈, there exists the unique nearest point inC, denoted byPCx, such that
x−PCx ≤x−y 2.2
for ally∈C. Such aPC is called the metricor the nearest pointprojection ofHontoC. As we all knowyPCxif and only if there holds the relation
x−y, y−z≥0 ∀z∈C. 2.3
Lemma 2.3see13. LetCbe a nonempty, closed, and convex subset ofH. Let{xn}be a sequence inHandu∈H. LetqPCu. Suppose that{xn}is such thatωwxn⊂Cand satisfies the following condition:
xn−u ≤u−q ∀n. 2.4
Thenxn → q.
Proposition 2.4see9. LetCbe a nonempty, closed, and convex subset of a real Hilbert spaceH.
iIfT :C → Cis aκ-strict pseudocontraction, thenT satisfies the Lipschitz condition
Tx−Ty≤ 1κ
1−κx−y, ∀x, y∈C. 2.5
iiIfT :C → Cis aκ-strict pseudocontraction, then the mappingI−T is demiclosed (at 0). That is, if{xn}is a sequence inCsuch thatxn xandI−Txn → 0, thenI−Tx0. iiiIfT :C → Cis aκ-strict pseudocontraction, then the fixed point setFTofT is closed
and convex. Therefore the projectionPFTis well defined.
ivGiven an integer N ≥ 1, assume that, for each1 ≤ i ≤ N,Ti : C → Cis aκi-strict pseudocontraction for some0≤κi<1. Assume that{λi}Ni1is a positive sequence such that
N
i1λi 1. Then Ni1λiTiis aκ-strict pseudocontraction, withκ max{κi : 1 ≤ i ≤
N}.
vLet{Ti}Ni1 and{λi}Ni1 be given as in item (iv). Suppose that{Ti}Ni1 has a common fixed point. Then
F N
i1
λiTi
N i1
FTi. 2.6
Lemma 2.5 see2. LetS : C → Hbe aκ-strict pseudocontraction. DefineT : C → Hby
Tx λx 1−λSxfor anyx ∈C. Then, for anyλ ∈ κ,1,T is a nonexpansive mapping with
For solving the equilibrium problem, let one assume that the bifunctionFsatisfies the following conditions:
A1Fx, x 0for allx∈C;
A2Fis monotone, that is,Fx, y Fy, x≤0for anyx, y∈C;
A3for eachx, y, z∈C, lim supt→0 Ftz 1−tx, y≤ Fx, y;
A4Fx,·is convex and lower semicontinuous for eachx∈C.
Lemma 2.6see3. LetCbe a nonempty, closed, and convex subset ofH, letFbe bifunction from
C×CtoRwhich satisfies conditions (A1)–(A4), and letr > 0andx∈H. Then there existsz∈C such that
Fz, y1ry−z, z−x≥0, ∀y∈C. 2.7
Lemma 2.7see1. Forr >0, x∈H, define the mappingTr :H → Cas follows:
Trx z∈C|Fz, y 1/ry−z, z−x≥0, ∀y∈C 2.8
for allx∈H. Then, the following statements hold:
iTris single valued;
iiTr is firmly nonexpansive, that is, for anyx, y∈H,
Trx−Try2≤T
rx−Try, x−y; 2.9
iiiFTr EPF;
ivEPFis closed and convex.
3. Parallel Algorithm
In this section, we apply the hybrid methods to the parallel algorithm for finding a common element of the fixed point set of strict pseudocontractions and the solution set of the problem
1.1in Hilbert spaces.
Theorem 3.1. Let Cbe a nonempty, closed, and convex subset of a real Hilbert space H, and let
Fk, k ∈ {1,2, . . . , M},be bifunctions from C×CtoR which satisfies conditions (A1)–(A4). Let, for each1 ≤ i ≤ N,Si : C → Cbe a κi-strict pseudocontraction for some0 ≤ κi < 1. Letκ
max{κi: 1≤i≤N}.Assume thatΩ ∩Ni1FSi∩∩Mk1EPFk/∅. Assume also that{η
n i }Ni1is a finite sequence of positive numbers such that Ni1ηin 1for alln∈Nandinfn≥1ηin >0for all
1≤i≤N. Let the mappingAnbe defined by
An N
i1
Givenx1∈C, let{xn},{un},and{yn}, be sequences which are generated by the following algorithm:
unTrM,nFMTrMFM−1−1,n · · ·TrF22,nT F1
r1,nxn,
Aλnn λnI 1−λnAn,
ynαnxn 1−αnAλnn un,
Cnz∈C:yn−z≤ xn−z,
Qn{z∈C:xn−z, x1−xn ≥0},
xn1PCn∩Qnx1,
3.2
where {αn} ⊂ 0, afor somea ∈ 0,1,{λn} ⊂ κ, bfor someb ∈ κ,1, and{rk,n} ⊂ 0,∞ satisfieslim infn→ ∞rk,n>0for allk∈ {1,2, . . . , M}. Then,{xn}converge strongly toPΩx1.
Proof. DenoteΘkn Trk,nFk · · ·TF2
r2,nTrF11,n for every k ∈ {1,2, . . . , M} and Θ0n I for all n ∈ N.
Thereforeun ΘMn xn. The proof is divided into six steps.
Step 1. The sequence{xn}is well defined.
It is obvious thatCn is closed and Qn is closed and convex for every n ∈ N. From
Lemma2.2, we also get thatCnis convex.
Takep ∈ Ω, since for each k ∈ {1,2, . . . , M},Trk,nFk is nonexpansive, p Trk,nFkp, and
un ΘMn xn, we have
un−pΘM
n xn−ΘMn p≤ xn−p 3.3
for alln∈N. From Proposition2.4, Lemma2.5, and3.3, we get
yn−pαnxn 1−αnAλnn un−p≤αnxn−p 1−αnAλnn un−p≤xn−p. 3.4
Sop ∈ Cn for alln ∈ N. Thus Ω ⊂ Cn.Next we will show by induction that Ω ⊂ Qn for
all n ∈ N. Forn 1, we have Ω ⊂ C Q1. Assume that Ω ⊂ Qn for some n ≥ 1. Since
xn1PCn∩Qnx1, we obtain
xn1−z, x1−xn1 ≥0, ∀z∈Cn∩Qn. 3.5
AsΩ⊂ Cn∩Qn by induction assumption, the inequality holds, in particular, for allz ∈ Ω.
This together with the definition ofQn1 implies thatΩ⊂ Qn1. HenceΩ⊂ Qnholds for all
n≥1.ThusΩ⊂Cn∩Qn, and therefore the sequence{xn}is well defined.
Step 2.
From the definition ofQn we imply thatxn PQnx1. This together with the fact that Ω⊂Qnfurther implies that
xn−x1 ≤x1−p ∀p∈Ω. 3.7
Then{xn}is bounded and3.6holds. From3.3,3.4, and Proposition2.4i, we also obtain
that{un},{yn},and{Sixn}are bounded.
Step 3. The following limit holds:
lim
n→ ∞xn1−xn0. 3.8
Fromxn PQnx1andxn1∈Qn, we getxn1−xn, xn−x1 ≥0. This together with Lemma2.1 iimplies that
xn1−xn2 xn1−x1−xn−x12
xn1−x12− xn−x12−2xn1−xn, xn−x1
≤ xn1−x12− xn−x12.
3.9
Thenxn−x1 ≤ xn1−x1, that is, the sequence{xn−x1}is nondecreasing. Since{xn−x1}
is bounded, limn→ ∞xn−x1exists. Then3.8holds.
Step 4. The following limit holds:
lim
n→ ∞Anxn−xn0. 3.10
Fromxn1∈Cn, we have
yn−xn≤ xn1−xnyn−xn1≤2xn1−xn. 3.11
By3.6, we obtain
lim
n→ ∞yn−xn0. 3.12
Next we will show that
lim
n→ ∞
Θk
Indeed, forp ∈ Ω, it follows from the firm nonexpansivity ofTrk,nFk that for each k ∈
{1,2, . . . , M},we have
Θk
nxn−p 2
Trk,nFkΘk−n 1xn−Trk,nFkp 2
≤Θk
nxn−p,Θk−n 1xn−p
1
2
Θk
nxn−p 2
Θk−1 n xn−p
2
−Θk
nxn−Θk−n 1xn 2
.
3.14
Thus we get
Θk
nxn−p 2
≤Θk−1 n xn−p
2
−Θk
nxn−Θk−n 1xn 2
, k1,2, . . . , M, 3.15
which implies that, for eachk∈ {1,2, . . . , M},
Θk
nxn−p 2
≤Θ0
nxn−p 2
−Θk
nxn−Θk−n 1xn 2
−Θk−1
n xn−Θk−n 2xn 2
− · · · −Θ2
nxn−Θ1nxn 2
−Θ1
nxn−Θ0nxn 2
≤xn−p2−Θknxn−Θk−n 1xn 2
.
3.16
Therefore, by the convexity of · 2and Lemma2.5, we get
yn−p2≤α
nxn−p2 1−αnAλnn un−p 2
≤αnxn−p2 1−αnun−p2
≤αnxn−p2 1−αnΘknxn−p 2
≤αnxn−p2 1−αnxn−p2−Θknxn−Θk−n 1xn 2
xn−p2−1−αnΘknxn−Θk−n 1xn 2
.
3.17
It follows that
1−αnΘknxn−Θk−n 1xn 2
≤xn−p2−yn−p2 ≤xn−ynxn−pyn−p.
3.18
Since{αn} ⊂0, a, we get from3.12that3.13holds; then we have
Observe thatyn−un ≤ yn−xnxn−un; we also haveyn−un → 0 asn → ∞. On
the other hand, fromynαnxn 1−αnAλnn un, we observe that
1−αnAλnn un−un1−αn
Aλnn un−un
yn−un−αnxn−un
≤yn−unαnxn−un.
3.20
From{αn} ⊂0, a,3.19, andyn−un → 0, we obtainAλnnun−un → 0 asn → ∞. It is
easy to see that
Aλnn xn−xn≤Aλnnxn−AλnnunAλn
nun−unun−xn ≤2un−xnAλnnun−un. 3.21
Combining the above arguments and3.2, we have
Aλnn xn−xnλnxn 1−λnAnxn−xn 1−λnAnxn−xn. 3.22
Now, it follows from{λn} ⊂κ, bthatAnxn−xn → 0 asn → ∞.
Step 5. The following implication holds:
ωwxn⊂Ω. 3.23
We first show thatωwxn⊂ ∩Ni1FSi. To this end, we takeω∈wxnand assume thatxnj ω
asj → ∞for some subsequence{xnj}ofxn.Without loss of generality, we may assume that
ηinj → ηi as j → ∞, ∀1≤i≤N. 3.24
It is easily seen that eachηi>0 and Ni1ηi1. We also have
Anjx → Ax as j → ∞ ∀x∈C, 3.25
where A Ni1ηiSi.Note that, by Proposition 2.4,A is aκ-strict pseudocontraction and
FA ∩N
i1FSi. Since
Axnj−xnj≤Anjxnj−AxnjAnjxnj−xnj
≤N
i1
ηinj−ηiSixnjAnjxnj−xnj,
we obtain by virtue of3.10and3.24that
lim
n→ ∞
Axnj−xnj0. 3.27
So by the demiclosedness principleProposition2.4ii, it follows thatω∈FA ∩Ni1FSi,
and henceωwxn⊂ ∩iN1FSi.
Next we will show thatω∈ ∩Mk1EPFk. Indeed, by Lemma2.6, we have that, for each
k1,2, . . . , M,
Fk
Θk nxn, y
r1 n
y−Θk
nxn,Θknxn−Θk−n 1xn
≥0, ∀y∈C. 3.28
FromA2, we get
1
rn
y−Θk
nxn,Θknxn−Θk−n 1xn
≥Fk
y,Θk
nxn
, ∀y∈C. 3.29
Hence,
y−Θk
njxnj, Θk
njxnj−Θk−nj1xnj
rnj
≥Fk
y,Θk
njxnj
, ∀y∈C. 3.30
From 3.13, we obtain that Θknjxnj ωas j → ∞ for each k 1,2, . . . , M especially,
unj ΘMnjxnj. Together with3.13andA4we have, for eachk1,2, . . . , M,that
0≥Fky, ω, ∀y∈C. 3.31
For any 0< t ≤ 1 andy ∈C, letyt ty 1−tω. Sincey ∈ Candω ∈ C, we obtain that
yt∈C, and henceFkyt, ω≤0. So, we have
0Fkyt, yt≤tFkyt, y 1−tFkyt, ω≤tFkyt, y. 3.32
Dividing by t, we get, for eachk1,2, . . . , M,that
Fkyt, y≥0, ∀y∈C. 3.33
Lettingt → 0 and fromA3, we get
Fkω, y≥0 3.34
for ally ∈Candω ∈EPFkfor eachk 1,2, . . . , M,that is,ω ∈ ∩Mk1EPFk.Hence3.23
Step 6. From3.6and Lemma2.3, we conclude thatxn → q, whereqPΩx1.
Remark 3.2. In 2007, Acedo and Xu studied the following CQ method9:
x0∈C chosen arbitrarily,
ynαnxn 1−αnAnxn,
Cn
z∈C:yn−z2≤ xn−z2−1−αnαn−κxn−Anxn2,
Qn{z∈C:xn−z, x0−xn ≥0},
xn1PCn∩Qnx0.
3.35
In this paper, we first turn the strict pseudocontractionAninto nonexpansive mapping
Aλnn then replaceCnwith a more simple form in the iterative algorithm.
Remark 3.3. IfFkx, y 0,N1, andλnδ, we can obtain14, Theorem 1.
Remark 3.4. IfM 1,N 1,κ 0, andλn 0 and we use 1−αn to replaceαn, we can get
the result that has been studied by Tada and Takahashi in8for nonexpansive mappings. If
Fkx, y 0,N1,κ0, andλn0, we can get7, Theorem 3.1.
Theorem 3.5. Let Cbe a nonempty, closed, and convex subset of a real Hilbert space H, and let
Fk, k∈ {1,2, . . .},be bifunctions fromC×CtoRwhich satisfies conditions (A1)–(A4). Let, for each
1 ≤ i≤ N,Si : C → Cbe aκi-strict pseudocontraction for some0 ≤ κi < 1. Letκ max{κi : 1 ≤i≤ N}.Assume thatΩ ∩iN1FSi∩∩kM1EPFk/∅. Assume also that{ηin}Ni1is a finite sequence of positive numbers such that Ni1ηin 1for allnandinfn≥1ηin >0for all1 ≤i≤N. Let the mappingAnbe defined by
An N
i1
ηinSi. 3.36
Givenx1∈CC1, letxn,un, andynbe sequences which are generated by the following algorithm:
unTrM,nFMTrMFM−1−1,n · · ·TrF22,nT F1
r1,nxn,
Aλnn λnI 1−λnAn,
ynαnxn 1−αnAλnn un,
Cn1
z∈Cn:yn−z ≤ xn−z,
xn1PCn1x1,
3.37
Proof. The proof of this theorem is similar to that of Theorem3.1.
Step 1. The sequence{xn}is well defined. We will show by induction thatCn is closed and convex for alln. For n 1, we haveC C1 which is closed and convex. Assume thatCn
for somen≥ 1 is closed and convex; from Lemma2.2, we have thatCn1is also closed and
convex; The proof ofΩ⊂Cnis similar to the one in Step1of Theorem3.1.
Step 2. xn−x1 ≤ q−x1for alln, whereqPΩx1.
Step 3. xn1−xn → 0 asn → ∞.
Step 4. Anxn−xn → 0 asn → ∞.
Step 5. ωwxn⊂Ω.
Step 6. xn → q.
The proof of Step2–Step6is similar to that of Theorem3.1.
Remark 3.6. IfM1, we can obtain the two corresponding theorems in10.
4. Cyclic Algorithm
Let C be a closed, and convex subset of a Hilbert spaceH, and let {Si}iN−01 be Nκi-strict pseudocontractions onCsuch that the common fixed point set
N−1
i0
FSi/∅. 4.1
Letx0 ∈C,and let{αn}∞n0be a sequence in0,1. The cyclic algorithm generates a sequence
{xn}∞n1in the following way:
x1α0x0 1−α0S0x0,
x2α1x1 1−α1S1x1,
. . .
xNαN−1xN−1 1−αN−1SN−1xN−1,
xN1αNxN 1−αNS0xN,
· · ·.
4.2
In general,xn1is defined by
xn1αnxn 1−αnSnxn, 4.3
Theorem 4.1. Let Cbe a nonempty, closed, and convex subset of a real Hilbert space H, and let
Fk, k ∈ {1,2, . . . , M},be bifunctions from C×CtoR which satisfies conditions (A1)–(A4). Let, for each0 ≤ i ≤ N−1,Si : C → Cbe aκi-strict pseudocontraction for some0 ≤ κi < 1. Let
κmax{κi : 0≤i≤N−1}.Assume thatΩ ∩N−i01FSi∩∩Mk1EPFk/∅. Givenx0 ∈C, let
xn,un, andynbe sequences which are generated by the following algorithm:
unTrM,nFMTrMFM−1−1,n · · ·TrF22,nTrF11,nxn,
SλnnλnI 1−λnSn,
ynαnxn 1−αnSλnnun,
Cnz∈C:yn−z≤ xn−z,
Qn{z∈C:xn−z, x0−xn ≥0},
xn1PCn∩Qnx0,
4.4
where {αn} ⊂ 0, afor somea ∈ 0,1,{λn} ⊂ κ, bfor someb ∈ κ,1, and{rk,n} ⊂ 0,∞
satisfieslim infn→ ∞rk,n>0for allk∈ {1,2, . . . , M}. Then,{xn}converge strongly toPFx0.
Proof. The proof of this theorem is similar to that of Theorem3.1. The main points are the following.
Step 1. The sequence{xn}is well defined.
Step 2. xn−x0 ≤ q−x0for alln, whereqPΩx0.
Step 3. xn1−xn → 0.
Step 4. Snxn−xn → 0.To prove the above steps, one simply replacesAnwithSnin the
proof of Theorem3.1.
Step 5. ωwxn ⊂ Ω.Indeed, let ω ∈ ωwxnandxnm ωfor some subsequence{xnm} of
{xn}. We may assume thatl nm mod Nfor allm. Since, byxn1−xn → 0, we also
havexnmj ωfor allj ≥0, we deduce that
xnmj−Sljxnmjxnmj−Snmjxnmj → 0. 4.5
Then the demiclosedness principle implies thatω ∈FSljfor allj. This ensures thatω ∈
∩N
i1FSi.The Proof ofω∈ ∩Mk1EPFkis similar to that of Theorem3.1.
Step 6. The sequencexnconverges strongly toq.
The strong convergence toqof{xn}is a consequence of Step2, Step5, and Lemma2.3.
Theorem 4.2. Let Cbe a nonempty, closed, and convex subset of a real Hilbert space H, and let
κmax{κi: 0≤i≤N−1}.Assume thatΩ ∩N−i01FSi∩∩Mk1EPFk/∅. Givenx0∈CC0, letxn,un, andynbe sequences whic are generated by the following algorithm:
un TrM,nFMTrMFM−1−1,n · · ·TrF22,nTrF11,nxn,
Sλnn λnI 1−λnSn,
yn αnxn 1−αnSλnnun,
Cn1
z∈Cn:yn−z≤ xn−z,
xn1 PCn1x0,
4.6
where {αn} ⊂ 0, afor somea ∈ 0,1,{λn} ⊂ κ, bfor someb ∈ κ,1, and{rk,n} ⊂ 0,∞ satisfieslim infn→ ∞rk,n>0for allk∈ {1,2, . . .}. Then,{xn}converge strongly toPΩx0.
Proof. The proof of this theorem is similar to that of Step1in Theorem3.5and Step2–Step6
in Theorem4.1.
Remark 4.3. IfM1, we can obtain the two corresponding theorems in10.
Acknowledgment
This research is supported by Fundamental Research Funds for the Central Universities
GRANT:ZXH2009D021.
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