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Volume 2010, Article ID 396080,14pages doi:10.1155/2010/396080

Research Article

Convergence Theorems Concerning Hybrid

Methods for Strict Pseudocontractions and

Systems of Equilibrium Problems

Peichao Duan

College of Science, Civil Aviation University of China, Tianjin 300300, China Correspondence should be addressed to Peichao Duan,[email protected]

Received 23 May 2010; Revised 23 August 2010; Accepted 26 August 2010

Academic Editor: S. Reich

Copyrightq2010 Peichao Duan. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

Let{Si}Ni1be N strict pseudo-contractions defined on a closed and convex subset C of a real

Hilbert space H. We consider the problem of finding a common element of fixed point set of these mappings and the solution set of a system of equilibrium problems by parallel and cyclic algorithms. In this paper, new iterative schemes are proposed for solving this problem. Furthermore, we prove that these schemes converge strongly by hybrid methods. The results presented in this paper improve and extend some well-known results in the literature.

1. Introduction

LetHbe a real Hilbert space with inner product·,·and norm · . LetCbe a nonempty, closed, and convex subset ofH.

Let{Fk}be a countable family of bifunctions fromC×CtoR, whereRis the set of

real numbers. Combettes and Hirstoaga1considered the following system of equilibrium problems:

findingxCsuch thatFkx, y≥0,k∈Γ,yC, 1.1

whereΓis an arbitrary index set. IfΓis a singleton, then problem1.1becomes the following equilibrium problem:

findingxCsuch thatFx, y≥0,yC. 1.2

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A mappingSofCis said to be aκ-strict pseudocontraction if there exists a constant

κ∈0,1such that

SxSy2xy2κISxISy2 1.3

for allx, yC; see2. We denote the fixed point set ofSbyFS, that is,FS {x

C:Sxx}.

Note that the class of strict pseudocontractions properly includes the class of nonexpansive mappings which are mappingSonCsuch that

SxSyxy 1.4

for all x, yC. That is, S is nonexpansive if and only if S is a 0-strict pseudocontraction.

The problem 1.1 is very general in the sense that it includes, as special cases, optimization problems, variational inequalities, minimax problems, Nash equilibrium problem in noncooperative games, and others; see, for instance,1,3,4and the references therein. Some methods have been proposed to solve the equilibrium problem1.1; related work can also be found in5–8.

Recently, Acedo and Xu9considered the problem of finding a common fixed point of a finite family of strict pseudo-contractive mappings by the parallel and cyclic algorithms. Very recently, Duan and Zhao10considered new hybrid methods for equilibrium problems and strict pseudocontractions. In this paper, motivated by5, 8–12, applying parallel and cyclic algorithms, we obtain strong convergence theorems for finding a common element of the fixed point set of a finite family of strict pseudocontractions and the solution set of the system of equilibrium problems1.1by the hybrid methods.

We will use the following notations:

1for the weak convergence and → for the strong convergence,

2ωwxn {x:∃xnj x}denotes the weakω-limit set of{xn}.

2. Preliminaries

We will use the facts and tools in a real Hilbert spaceHwhich are listed below.

Lemma 2.1. LetHbe a real Hilbert space. Then the following identities hold: ixy2x2− y2−2xy, y, for allx, yH,

iitx1−ty2tx21−ty2−t1−txy2, for allt∈0,1, for allx, yH.

Lemma 2.2see6. LetHbe a real Hilbert space. Given a nonempty, closed, and convex subset

CH, pointsx, y, zH, and a real numbera∈R, then the set

vC:yv2≤ xv2z, va 2.1

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Recall that given a nonempty, closed, and convex subsetCof a real Hilbert spaceH, for anyx∈, there exists the unique nearest point inC, denoted byPCx, such that

xPCxxy 2.2

for allyC. Such aPC is called the metricor the nearest pointprojection ofHontoC. As we all knowyPCxif and only if there holds the relation

xy, yz≥0 ∀zC. 2.3

Lemma 2.3see13. LetCbe a nonempty, closed, and convex subset ofH. Let{xn}be a sequence inHanduH. LetqPCu. Suppose that{xn}is such thatωwxnCand satisfies the following condition:

xnuuqn. 2.4

Thenxnq.

Proposition 2.4see9. LetCbe a nonempty, closed, and convex subset of a real Hilbert spaceH.

iIfT :CCis aκ-strict pseudocontraction, thenT satisfies the Lipschitz condition

TxTy 1κ

1−κxy,x, yC. 2.5

iiIfT :CCis aκ-strict pseudocontraction, then the mappingIT is demiclosed (at 0). That is, if{xn}is a sequence inCsuch thatxn xandITxn → 0, thenITx0. iiiIfT :CCis aκ-strict pseudocontraction, then the fixed point setFTofT is closed

and convex. Therefore the projectionPFTis well defined.

ivGiven an integer N ≥ 1, assume that, for each1 ≤ iN,Ti : CCis aκi-strict pseudocontraction for some0≤κi<1. Assume that{λi}Ni1is a positive sequence such that

N

i1λi 1. Then Ni1λiTiis aκ-strict pseudocontraction, withκ max{κi : 1 ≤ i

N}.

vLet{Ti}Ni1 and{λi}Ni1 be given as in item (iv). Suppose that{Ti}Ni1 has a common fixed point. Then

F N

i1

λiTi

N i1

FTi. 2.6

Lemma 2.5 see2. LetS : CHbe aκ-strict pseudocontraction. DefineT : CHby

Tx λx 1−λSxfor anyxC. Then, for anyλκ,1,T is a nonexpansive mapping with

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For solving the equilibrium problem, let one assume that the bifunctionFsatisfies the following conditions:

A1Fx, x 0for allxC;

A2Fis monotone, that is,Fx, y Fy, x≤0for anyx, yC;

A3for eachx, y, zC, lim supt0 Ftz 1−tx, yFx, y;

A4Fx,·is convex and lower semicontinuous for eachxC.

Lemma 2.6see3. LetCbe a nonempty, closed, and convex subset ofH, letFbe bifunction from

C×CtoRwhich satisfies conditions (A1)–(A4), and letr > 0andxH. Then there existszC such that

Fz, y1ryz, zx≥0,yC. 2.7

Lemma 2.7see1. Forr >0, xH, define the mappingTr :HCas follows:

Trx zC|Fz, y 1/ryz, zx≥0,yC 2.8

for allxH. Then, the following statements hold:

iTris single valued;

iiTr is firmly nonexpansive, that is, for anyx, yH,

TrxTry2T

rxTry, xy; 2.9

iiiFTr EPF;

ivEPFis closed and convex.

3. Parallel Algorithm

In this section, we apply the hybrid methods to the parallel algorithm for finding a common element of the fixed point set of strict pseudocontractions and the solution set of the problem

1.1in Hilbert spaces.

Theorem 3.1. Let Cbe a nonempty, closed, and convex subset of a real Hilbert space H, and let

Fk, k ∈ {1,2, . . . , M},be bifunctions from C×CtoR which satisfies conditions (A1)–(A4). Let, for each1 ≤ iN,Si : CCbe a κi-strict pseudocontraction for some0 ≤ κi < 1. Letκ

max{κi: 1≤iN}.Assume thatΩ ∩Ni1FSi∩∩Mk1EPFk/. Assume also that{η

n i }Ni1is a finite sequence of positive numbers such that Ni1ηin 1for alln∈Nandinfn≥1ηin >0for all

1≤iN. Let the mappingAnbe defined by

An N

i1

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Givenx1∈C, let{xn},{un},and{yn}, be sequences which are generated by the following algorithm:

unTrM,nFMTrMFM−1−1,n · · ·TrF22,nT F1

r1,nxn,

Aλnn λnI 1−λnAn,

ynαnxn 1−αnAλnn un,

CnzC:ynzxnz,

Qn{zC:xnz, x1−xn ≥0},

xn1PCn∩Qnx1,

3.2

where {αn} ⊂ 0, afor somea ∈ 0,1,{λn} ⊂ κ, bfor somebκ,1, and{rk,n} ⊂ 0,satisfieslim infn→ ∞rk,n>0for allk∈ {1,2, . . . , M}. Then,{xn}converge strongly toPΩx1.

Proof. DenoteΘkn Trk,nFk · · ·TF2

r2,nTrF11,n for every k ∈ {1,2, . . . , M} and Θ0n I for all n ∈ N.

Thereforeun ΘMn xn. The proof is divided into six steps.

Step 1. The sequence{xn}is well defined.

It is obvious thatCn is closed and Qn is closed and convex for every n ∈ N. From

Lemma2.2, we also get thatCnis convex.

Takep ∈ Ω, since for each k ∈ {1,2, . . . , M},Trk,nFk is nonexpansive, p Trk,nFkp, and

un ΘMn xn, we have

unpΘM

n xn−ΘMn pxnp 3.3

for alln∈N. From Proposition2.4, Lemma2.5, and3.3, we get

ynpαnxn 1−αnAλnn unpαnxnp 1−αnAλnn unpxnp. 3.4

SopCn for alln ∈ N. Thus Ω ⊂ Cn.Next we will show by induction that Ω ⊂ Qn for

all n ∈ N. Forn 1, we have Ω ⊂ C Q1. Assume that Ω ⊂ Qn for some n ≥ 1. Since

xn1PCn∩Qnx1, we obtain

xn1−z, x1−xn1 ≥0,zCnQn. 3.5

AsΩ⊂ CnQn by induction assumption, the inequality holds, in particular, for allz ∈ Ω.

This together with the definition ofQn1 implies thatΩ⊂ Qn1. HenceΩ⊂ Qnholds for all

n≥1.ThusΩ⊂CnQn, and therefore the sequence{xn}is well defined.

Step 2.

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From the definition ofQn we imply thatxn PQnx1. This together with the fact that Ω⊂Qnfurther implies that

xnx1 ≤x1−pp∈Ω. 3.7

Then{xn}is bounded and3.6holds. From3.3,3.4, and Proposition2.4i, we also obtain

that{un},{yn},and{Sixn}are bounded.

Step 3. The following limit holds:

lim

n→ ∞xn1−xn0. 3.8

Fromxn PQnx1andxn1∈Qn, we getxn1−xn, xnx1 ≥0. This together with Lemma2.1 iimplies that

xn1−xn2 xn1−x1−xnx12

xn1−x12− xnx12−2xn1−xn, xnx1

xn1−x12− xnx12.

3.9

Thenxnx1 ≤ xn1−x1, that is, the sequence{xnx1}is nondecreasing. Since{xnx1}

is bounded, limn→ ∞xnx1exists. Then3.8holds.

Step 4. The following limit holds:

lim

n→ ∞Anxnxn0. 3.10

Fromxn1∈Cn, we have

ynxnxn1xnynxn12xn1−xn. 3.11

By3.6, we obtain

lim

n→ ∞ynxn0. 3.12

Next we will show that

lim

n→ ∞

Θk

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Indeed, forp ∈ Ω, it follows from the firm nonexpansivity ofTrk,nFk that for each k

{1,2, . . . , M},we have

Θk

nxnp 2

Trk,nFkΘk−n 1xnTrk,nFkp 2

≤Θk

nxnp,Θk−n 1xnp

1

2

Θk

nxnp 2

Θk−1 n xnp

2

−Θk

nxn−Θk−n 1xn 2

.

3.14

Thus we get

Θk

nxnp 2

≤Θk−1 n xnp

2

−Θk

nxn−Θk−n 1xn 2

, k1,2, . . . , M, 3.15

which implies that, for eachk∈ {1,2, . . . , M},

Θk

nxnp 2

≤Θ0

nxnp 2

−Θk

nxn−Θk−n 1xn 2

−Θk−1

n xn−Θk−n 2xn 2

− · · · −Θ2

nxn−Θ1nxn 2

−Θ1

nxn−Θ0nxn 2

xnp2−Θknxn−Θk−n 1xn 2

.

3.16

Therefore, by the convexity of · 2and Lemma2.5, we get

ynp2α

nxnp2 1−αnAλnn unp 2

αnxnp2 1−αnunp2

αnxnp2 1−αnΘknxnp 2

αnxnp2 1−αnxnp2−Θknxn−Θk−n 1xn 2

xnp2−1−αnΘknxn−Θk−n 1xn 2

.

3.17

It follows that

1−αnΘknxn−Θk−n 1xn 2

xnp2−ynp2 ≤xnynxnpynp.

3.18

Since{αn} ⊂0, a, we get from3.12that3.13holds; then we have

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Observe thatynunynxnxnun; we also haveynun → 0 asn → ∞. On

the other hand, fromynαnxn 1−αnAλnn un, we observe that

1−αnAλnn unun1−αn

Aλnn unun

ynunαnxnun

ynunαnxnun.

3.20

From{αn} ⊂0, a,3.19, andynun → 0, we obtainAλnnunun → 0 asn → ∞. It is

easy to see that

Aλnn xnxn≤AλnnxnAλnnunAλn

nunununxn ≤2unxnAλnnunun. 3.21

Combining the above arguments and3.2, we have

Aλnn xnxnλnxn 1−λnAnxnxn 1−λnAnxnxn. 3.22

Now, it follows from{λn} ⊂κ, bthatAnxnxn → 0 asn → ∞.

Step 5. The following implication holds:

ωwxn⊂Ω. 3.23

We first show thatωwxn⊂ ∩Ni1FSi. To this end, we takeωwxnand assume thatxnj ω

asj → ∞for some subsequence{xnj}ofxn.Without loss of generality, we may assume that

ηinjηi as j → ∞, ∀1≤iN. 3.24

It is easily seen that eachηi>0 and Ni1ηi1. We also have

AnjxAx as j → ∞ ∀xC, 3.25

where A Ni1ηiSi.Note that, by Proposition 2.4,A is aκ-strict pseudocontraction and

FAN

i1FSi. Since

Axnjxnj≤AnjxnjAxnjAnjxnjxnj

N

i1

ηinjηiSixnjAnjxnjxnj,

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we obtain by virtue of3.10and3.24that

lim

n→ ∞

Axnjxnj0. 3.27

So by the demiclosedness principleProposition2.4ii, it follows thatωFANi1FSi,

and henceωwxn⊂ ∩iN1FSi.

Next we will show thatω∈ ∩Mk1EPFk. Indeed, by Lemma2.6, we have that, for each

k1,2, . . . , M,

Fk

Θk nxn, y

r1 n

y−Θk

nxn,Θknxn−Θk−n 1xn

≥0,yC. 3.28

FromA2, we get

1

rn

y−Θk

nxn,Θknxn−Θk−n 1xn

Fk

y,Θk

nxn

,yC. 3.29

Hence,

y−Θk

njxnj, Θk

njxnj−Θk−nj1xnj

rnj

Fk

y,Θk

njxnj

,yC. 3.30

From 3.13, we obtain that Θknjxnj ωas j → ∞ for each k 1,2, . . . , M especially,

unj ΘMnjxnj. Together with3.13andA4we have, for eachk1,2, . . . , M,that

0≥Fky, ω,yC. 3.31

For any 0< t ≤ 1 andyC, letyt ty 1−. SinceyCandωC, we obtain that

ytC, and henceFkyt, ω≤0. So, we have

0Fkyt, yttFkyt, y 1−tFkyt, ωtFkyt, y. 3.32

Dividing by t, we get, for eachk1,2, . . . , M,that

Fkyt, y≥0,yC. 3.33

Lettingt → 0 and fromA3, we get

Fkω, y≥0 3.34

for allyCandω ∈EPFkfor eachk 1,2, . . . , M,that is,ω ∈ ∩Mk1EPFk.Hence3.23

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Step 6. From3.6and Lemma2.3, we conclude thatxnq, whereqPΩx1.

Remark 3.2. In 2007, Acedo and Xu studied the following CQ method9:

x0∈C chosen arbitrarily,

ynαnxn 1−αnAnxn,

Cn

zC:ynz2≤ xnz2−1−αnαnκxnAnxn2,

Qn{zC:xnz, x0−xn ≥0},

xn1PCn∩Qnx0.

3.35

In this paper, we first turn the strict pseudocontractionAninto nonexpansive mapping

Aλnn then replaceCnwith a more simple form in the iterative algorithm.

Remark 3.3. IfFkx, y 0,N1, andλnδ, we can obtain14, Theorem 1.

Remark 3.4. IfM 1,N 1,κ 0, andλn 0 and we use 1−αn to replaceαn, we can get

the result that has been studied by Tada and Takahashi in8for nonexpansive mappings. If

Fkx, y 0,N1,κ0, andλn0, we can get7, Theorem 3.1.

Theorem 3.5. Let Cbe a nonempty, closed, and convex subset of a real Hilbert space H, and let

Fk, k∈ {1,2, . . .},be bifunctions fromC×CtoRwhich satisfies conditions (A1)–(A4). Let, for each

1 ≤ iN,Si : CCbe aκi-strict pseudocontraction for some0 ≤ κi < 1. Letκ max{κi : 1 ≤iN}.Assume thatΩ ∩iN1FSi∩∩kM1EPFk/. Assume also that{ηin}Ni1is a finite sequence of positive numbers such that Ni1ηin 1for allnandinfn≥1ηin >0for all1 ≤iN. Let the mappingAnbe defined by

An N

i1

ηinSi. 3.36

Givenx1∈CC1, letxn,un, andynbe sequences which are generated by the following algorithm:

unTrM,nFMTrMFM−1−1,n · · ·TrF22,nT F1

r1,nxn,

Aλnn λnI 1−λnAn,

ynαnxn 1−αnAλnn un,

Cn1

zCn:ynzxnz,

xn1PCn1x1,

3.37

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Proof. The proof of this theorem is similar to that of Theorem3.1.

Step 1. The sequence{xn}is well defined. We will show by induction thatCn is closed and convex for alln. For n 1, we haveC C1 which is closed and convex. Assume thatCn

for somen≥ 1 is closed and convex; from Lemma2.2, we have thatCn1is also closed and

convex; The proof ofΩ⊂Cnis similar to the one in Step1of Theorem3.1.

Step 2. xnx1 ≤ qx1for alln, whereqPΩx1.

Step 3. xn1−xn → 0 asn → ∞.

Step 4. Anxnxn → 0 asn → ∞.

Step 5. ωwxn⊂Ω.

Step 6. xnq.

The proof of Step2–Step6is similar to that of Theorem3.1.

Remark 3.6. IfM1, we can obtain the two corresponding theorems in10.

4. Cyclic Algorithm

Let C be a closed, and convex subset of a Hilbert spaceH, and let {Si}iN−01 be i-strict pseudocontractions onCsuch that the common fixed point set

N−1

i0

FSi/. 4.1

Letx0 ∈C,and let{αn}∞n0be a sequence in0,1. The cyclic algorithm generates a sequence

{xn}∞n1in the following way:

x1α0x0 1−α0S0x0,

x2α1x1 1−α1S1x1,

. . .

xNαN−1xN−1 1−αN−1SN−1xN−1,

xN1αNxN 1−αNS0xN,

· · ·.

4.2

In general,xn1is defined by

xn1αnxn 1−αnSnxn, 4.3

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Theorem 4.1. Let Cbe a nonempty, closed, and convex subset of a real Hilbert space H, and let

Fk, k ∈ {1,2, . . . , M},be bifunctions from C×CtoR which satisfies conditions (A1)–(A4). Let, for each0 ≤ iN−1,Si : CCbe aκi-strict pseudocontraction for some0 ≤ κi < 1. Let

κmax{κi : 0≤iN−1}.Assume thatΩ ∩N−i01FSi∩∩Mk1EPFk/. Givenx0 ∈C, let

xn,un, andynbe sequences which are generated by the following algorithm:

unTrM,nFMTrMFM−1−1,n · · ·TrF22,nTrF11,nxn,

SλnnλnI 1−λnSn,

ynαnxn 1−αnSλnnun,

CnzC:ynzxnz,

Qn{zC:xnz, x0−xn ≥0},

xn1PCn∩Qnx0,

4.4

where {αn} ⊂ 0, afor somea ∈ 0,1,{λn} ⊂ κ, bfor somebκ,1, and{rk,n} ⊂ 0,

satisfieslim infn→ ∞rk,n>0for allk∈ {1,2, . . . , M}. Then,{xn}converge strongly toPFx0.

Proof. The proof of this theorem is similar to that of Theorem3.1. The main points are the following.

Step 1. The sequence{xn}is well defined.

Step 2. xnx0 ≤ qx0for alln, whereqPΩx0.

Step 3. xn1−xn → 0.

Step 4. Snxnxn → 0.To prove the above steps, one simply replacesAnwithSnin the

proof of Theorem3.1.

Step 5. ωwxn ⊂ Ω.Indeed, let ωωwxnandxnm ωfor some subsequence{xnm} of

{xn}. We may assume thatl nm mod Nfor allm. Since, byxn1−xn → 0, we also

havexnmj ωfor allj ≥0, we deduce that

xnmjSljxnmjxnmjSnmjxnmj 0. 4.5

Then the demiclosedness principle implies thatωFSljfor allj. This ensures thatω

N

i1FSi.The Proof ofω∈ ∩Mk1EPFkis similar to that of Theorem3.1.

Step 6. The sequencexnconverges strongly toq.

The strong convergence toqof{xn}is a consequence of Step2, Step5, and Lemma2.3.

Theorem 4.2. Let Cbe a nonempty, closed, and convex subset of a real Hilbert space H, and let

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κmax{κi: 0≤iN−1}.Assume thatΩ ∩N−i01FSi∩∩Mk1EPFk/. Givenx0∈CC0, letxn,un, andynbe sequences whic are generated by the following algorithm:

un TrM,nFMTrMFM−1−1,n · · ·TrF22,nTrF11,nxn,

Sλnn λnI 1−λnSn,

yn αnxn 1−αnSλnnun,

Cn1

zCn:ynzxnz,

xn1 PCn1x0,

4.6

where {αn} ⊂ 0, afor somea ∈ 0,1,{λn} ⊂ κ, bfor somebκ,1, and{rk,n} ⊂ 0,satisfieslim infn→ ∞rk,n>0for allk∈ {1,2, . . .}. Then,{xn}converge strongly toPΩx0.

Proof. The proof of this theorem is similar to that of Step1in Theorem3.5and Step2–Step6

in Theorem4.1.

Remark 4.3. IfM1, we can obtain the two corresponding theorems in10.

Acknowledgment

This research is supported by Fundamental Research Funds for the Central Universities

GRANT:ZXH2009D021.

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