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R E S E A R C H

Open Access

Some extensions for Geragthy type

contractive mappings

Erdal Karapınar

1,2*

, Hamed H Alsulami

2

and Maha Noorwali

2

*Correspondence: [email protected] 1Department of Mathematics, Atilim University, ˙Incek, Ankara, 06836, Turkey

2Nonlinear Analysis and Applied Mathematics Research Group (NAAM), King Abdulaziz University, Jeddah, Saudi Arabia

Abstract

In this paper, we establish some fixed point theorems on some extensions of Geragthy contractive type mappings in the context ofb-metric-like spaces.

MSC: 46T99; 46N40; 47H10; 54H25

Keywords: b-metric-like space; fixed point;

α-admissible; contractive mapping

1 Introduction and preliminaries

One of the interesting extensions of the notion of a metric space is the dislocated space, introduced by Hitzler []. This notion was rediscovered by Amini-Harandi [] and given the name of a metric-like space.

Definition . On a nonempty setXwe define a functionσ:X×X→[,∞) such that for allx,y,zX:

(σ) ifσ(x,y) = thenx=y; (σ) σ(x,y) =σ(y,x);

(σ) σ(x,y)≤σ(x,z) +σ(z,y);

and the pair (X,σ) is called a dislocated (metric-like) space.

Throughout this paper, we suppose that N=N∪ {}whereNdenotes the set of all

positive integers. Further, the symbolsR+andR+

denotes the set of positive reals and the

set of non-negative reals. First, we recall some basic concepts and notations.

The concept of ab-metric was introduced by Czerwik [] as a generalization of the met-ric (see also Bakhtin [] and Bourbaki []) to extend the celebrated Banach contraction mapping principle. Following this initial paper of Czerwik [], a number of researchers in nonlinear analysis investigated the topology of the paper and proved several fixed point theorems in the context of completeb-metric spaces (seee.g.[–] and references therein).

Definition .[] LetXbe a nonempty set ands≥ be a given real number. A mapping

d: X×X→[,∞) is said to be ab-metric if for allx,y,zXthe following conditions are satisfied:

(bM) d(x,y) = if and only ifx=y;

(bM) d(x,y) =d(y,x);

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(bM) d(x,z)≤s[d(x,y) +d(y,z)].

In this case, the pair (X,d) is called ab-metric space (with constants).

In what follows, we recall the notion ofb-metric-like space which is an interesting gen-eralization of bothb-metric space and metric-like space.

Definition .[] LetXbe a nonempty set ands≥ be a given real number. A mapping

d: X×X→[,∞) is said to beb-metric-like if for allx,y,zXthe following conditions are satisfied:

(bML) ifd(x,y) = thenx=y;

(bML) d(x,y) =d(y,x);

(bML) d(x,z)≤s[d(x,y) +d(y,z)].

In this case, the pair (X,d) is called ab-metric-like space (with constants).

Example . LetX=C([,T]) be the set of all real continuous functions on the closed interval [,T]. Letd:X×X→R+be defined

d(f,g) =maxf(t) –g(t)p+a,

for allf,gX,a∈R+

, andp> . It is easy to see that (X,d) is a completeb-metric-like

space withs= p–. For more examples, seee.g.[].

Remark . Let (X,d) be ab-metric-like space with constants≥. Then it is clear that

ds(x,y) =|d(x,y) –d(x,x) –d(y,y)|satisfies the following: (S) ds(x,x) = for allxX.

Definition .[] Let (X,d) be ab-metric-like space. Then: () a sequence{xn}inXis called convergent toxXif and only if

limn→∞d(xn,x) =d(x,x);

() a sequence{xn}inXis called Cauchy sequence if and only iflimn,m→∞d(xn,xm) exists and finite;

() (X,d)is complete if and only if every Cauchy sequence{xn}inXconverges toxX so that

lim

n→∞d(xn,x) =d(x,x) =m,limn→∞d(xn,xm).

Proposition .[] Let(X,d)be a b-metric-like space with constant s and let{xn}be a

sequence in X such thatlimn→∞d(xn,x) = .Then: () xis unique.

() sd(x,y)≤limn→∞d(xn,y)≤sd(x,y)for allyX.

Lemma .[] Let(X,d)be a b-metric-like space with constant s and{xn}a sequence in

X such that

d(xn+,xn+)≤kd(xn,xn+), n= , , . . . ,

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Lemma .[] Let(X,d)be a b-metric-like space with constant s and assume that{xn}

and{yn}are sequences in X converging to x and y,respectively.Then

sd(x,y) –

sd(x,x) –d(y,y)≤lim infn→∞ d(xn,yn)≤lim supn→∞ d(xn,yn)

sd(x,x) +sd(y,y) +sd(x,y).

In particular,if d(x,y) = thenlimn→∞d(xn,yn) = .

Moreover,for each zX we have

sd(x,z) –d(x,x)≤lim infn→∞ d(xn,z)≤lim supn→∞ d(xn,z)≤sd(x,z) +sd(x,x). ()

In particular,if d(x,x) = ,then

sd(x,z)≤lim infn→∞ d(xn,z)≤lim supn→∞ d(xn,z)≤sd(x,z).

Notice that, in general, ab-metric-like mapping does not need to be continuous. The notion ofα-admissible and triangularα-admissible mappings were introduced by Sametet al.[] and Karapınaret al.[], respectively.

Definition . LetT:XXbe a mapping andα:X×X→[,∞) be a function. We say thatT is anα-admissible mapping if

x,yX, α(x,y)≥ ⇒ α(Tx,Ty)≥.

Moreover, a self-mappingTis called triangularα-admissible ifTisα-admissible and

x,y,zX, α(x,z)≥ andα(z,y)≥ ⇒ α(x,y)≥.

For more details onα-admissible and triangularα-admissible mappings, seee.g.[–]. Very recently, Popescu [] refined the notion of triangularα-orbital admissible as fol-lows.

Definition .[] LetT:XXbe a mapping andα:X×X→[,∞) be a function. We say thatT isα-orbital admissible if

α(x,Tx)≥ ⇒ αTx,Tx≥.

Furthermore,Tis called triangularα-orbital admissible ifTisα-orbital admissible and

α(x,y)≥ andα(y,Ty)≥ ⇒ α(x,Ty)≥.

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Example . LetX={a,b,c,d,e,f,g,h}. We define a self-mappingT:XXsuch that

Tx=x, forx=a,dand

Tx=y for (x,y)∈(b,c), (c,b), (e,f), (f,e), (g,h), (h,g).

Moreover, we defineα:X×X→R+

, such that

α(x,y) =

 if (x,y)∈ {(a,b), (a,c), (b,b), (c,c), (b,c), (c,b), (b,d), (c,d), (d,e)},  otherwise.

Note thatT isα-orbital admissible, sinceα(b,Tb) =α(b,c) =  andα(c,Tc) =α(c,b) = . On the other hand, we have α(d,e) = , but α(Td,Te) =α(d,f) = . Hence,T is notα -admissible.

Lemma .[] Let T:XX be a triangularα-orbital admissible mapping.Assume that there exists x∈X such thatα(x,Tx)≥.Define a sequence{xn}by xn+=Txnfor

each n∈N.Then we haveα(xn,xm)≥for all m,n∈Nwith n<m.

Lemma . Let T:XX be a triangularα-orbital admissible mapping.Assume that there exists x∈X such thatα(Tx,x)≥.Define a sequence{xn}by xn+=Txnfor each

n∈N.Then we haveα(xm,xn)≥for all m,n∈Nwith n<m.

We characterize the notion ofα-regular in the setting of ab-metric-like space.

Definition .(cf.[]) Let (X,d) be ab-metric-like space,Xis said to beα-regular, if for every sequence{xn}inXsuch thatα(xn,xn+)≥ (respectively,α(xn+,xn)≥) for alln

andxnxXasn→ ∞, there exists a subsequence{xnk}of{xn}such thatα(xnk,x)≥ (respectively,α(x,xnk)≥) for allk.

In this paper, we shall prove the existence and uniqueness of a fixed point for certain operators in the setting ofb-metric-like spaces. The presented results improve, extend, and unify a number of existing results in the literature.

2 Main result forb-metric-like spaces

In this section, we shall state and prove our main results. First, we recall the following classes of auxiliary functions. Letbe the set of all increasing and continuous functions

ψ: [,∞)→[,∞) withψ–({}) ={}. LetFsbe the family of all functionsβ: [,∞)→ [,s) which satisfy the condition

lim

n→∞β(tn) =

s implies n→∞lim tn= , ()

for somes≥.

Definition . Let (X,d) be ab-metric-like space with constants≥, andT:XXbe a map. We say thatTis a generalized almostα-ψ-φ-Geraghty contractive type mapping if there exist a functionα:X×X→[,∞),ψ,φ,βFs, and someL≥ such that

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for allx,yX, where

M(x,y) =max

d(x,y),d(x,Tx),d(y,Ty),d(x,Ty) +d(y,Tx)

s and ()

N(x,y) =minds(x,Ty),ds(y,Tx),d(x,Tx),d(y,Ty). ()

Remark . Since the functions belonging toFsare strictly smaller thans, for somes≥, the expressionβ(ψ(M(x,y))) in () can be estimated from above as follows:

βψM(x,y)<

s for anyx,yX.

Theorem . Let(X,d)be a complete b-metric-like space with constant s≥ and T :

XX be a generalized almostα-ψ-φ-Geraghty contractive type mapping.We suppose also that

(i) Tis triangularα-orbital admissible; (ii) there existsx∈Xsuch thatα(x,Tx)≥;

(iii) Tis continuous.

Then T has a fixed point,uX with d(u,u) = .

Proof By (ii) there existsx∈Xsuch thatα(x,Tx)≥. Define a sequence{xn} ⊂Xby

xn+=Txnfor alln∈N. AsT is triangularα-orbital admissible, by Lemma . we have α(xn,xn+)≥ for alln∈N. Throughout the proof, we suppose thatxn=xn+for alln

N. Indeed, if there existsnsuch thatxn=xn+, thenxnbecomes the fixed point ofT, which completes the proof.

SinceTis a generalized almostα-ψ-φ-Geraghty contractive type mapping we have

ψsd(xn+,xn+)

α(xn,xn+)ψ

sd(Txn,Txn+)

βψM(xn,xn+)

ψM(xn,xn+)

+LφN(xn,xn+)

. ()

Thus, we have

ψsd(xn+,xn+)

<

M(xn,xn+)

+LφN(xn,xn+)

, ()

whereN(xn,xn+) =min{ds(xn,xn+),ds(xn+,xn+),d(xn,xn+),d(xn+,xn+)}= , and

M(xn,xn+) =max

d(xn,xn+),d(xn,xn+),d(xn+,xn+),

d(xn,xn+) +d(xn+,xn+)

s .

Note that

d(xn,xn+) +d(xn+,xn+)

s

s[d(xn,xn+) + d(xn+,xn+)]

s

=[d(xn,xn+) + d(xn+,xn+)] 

≤maxd(xn,xn+),d(xn+,xn+)

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Consequently, we have

M(xn,xn+) =max

d(xn,xn+),d(xn+,xn+)

.

IfM(xn,xn+) =d(xn+,xn+), then from () we have

ψsd(xn+,xn+)

<

d(xn+,xn+)

ψd(xn+,xn+)

.

Sinceψis increasing, we derive thatsd(xn+,xn+) <d(xn+,xn+), which is a contradiction

ass≥. Thus,M(xn,xn+) =d(xn,xn+). Again by (), we find

ψsd(xn+,xn+)

<

d(xn,xn+)

ψd(xn,xn+)

.

Hence, we get

sd(xn+,xn+)≤d(xn,xn+) equivalently d(xn+,xn+)≤

sd(xn,xn+). ()

Case (i):s> . Since s >  andss =s< , by Lemma ., the sequence{xn}is Cauchy and

lim

n,m→∞d(xn,xm) = . ()

Case (ii):s= . From (), we haved(xn+,xn+)≤d(xn,xn+) for alln. Thus, we conclude

that

lim

n→∞d(xn,xn+) =r, ()

for somer≥. We shall prove thatr= . Suppose, on the contrary, thatr> . Note that, fors= , the inequality () turns into

ψd(xn+,xn+)

<βψM(xn,xn+)

ψM(xn,xn+)

+LφN(xn,xn+)

, ()

whereN(xn,xn+) =  andM(xn,xn+) =d(xn,xn+) as evaluated above. Thus, () yields

ψ(d(xn+,xn+)) ψ(d(xn,xn+)) ≤

βψd(xn,xn+)

< . ()

By taking the limit asn→ ∞in () and regarding the continuity ofψ, we get

lim

n→∞β

ψd(xn,xn+)

= .

Hence, we have

lim

n→∞ψ

d(xn,xn+)

=  and so lim

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Consequentlyr= . In what follows, we shall prove that{xn}is a Cauchy sequence. Indeed we will prove thatlimm,n→∞d(xn,xm) = . Suppose, on the contrary, that there existε>  and corresponding subsequences{nk}and{mk}ofNsatisfyingnk>mk>kfor which

d(xmk,xnk)≥ε, ()

wherenk,mkare chosen as the smallest integers satisfying (), that is,

d(xmk,xnk–) <ε. ()

By (), (), and the triangle inequality, we easily derive that

εd(xmk,xnk)≤d(xmk,xnk–) +d(xnk–,xnk) <ε+d(xnk–,xnk). ()

Using () and the squeeze theorem we get

lim

k→∞d(xmk,xnk) =ε. ()

In a similar way, we can prove thatlimk→∞d(xmk,xnk+) = ,limk→∞d(xnk,xmk+) = .

Regarding thatTis a generalized almostα-ψ-φ-Geraghty contractive type mapping, we have

ψd(xmk+,xnk+)

α(xmk,xnk)ψ

d(Txmk,Txnk)

βψM(xmk,xnk)

ψM(xmk,xnk)

+LφN(xmk,xnk)

, ()

for allx,yX, where

M(xmk,xnk) = max

d(xmk,xnk),d(xmk,xmk+),d(xnk,xnk+),

d(xmk,xnk+) +d(xnk,xmk+)

 , ()

and

N(xmk,xnk) =min

ds(xmk,xnk+),ds(xnk,xmk+),d(xmk,xmk+),d(xnk,xnk+)

.

By taking the limit ask→ ∞in () and taking (), () into account, we get

ψ(ε)≤ lim

k→∞β

ψM(xmk,xnk)

ψ(ε). ()

Sinceβis a Geraghty function, we derive thatψ(M(xmk,xnk))→. Consequently, we have

d(xmk,xnk)→, which is a contradiction. Hence, we conclude thatlimm,n→∞d(xn,xm) = , and the sequence{xn}is Cauchy for anys≥.

By completeness of (X,d), there existsuXsuch that

lim

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SinceTis continuous,

Tu=T

lim

n→∞xn

= lim

n→∞Txn=n→∞limxn+=u,

anduis a fixed point forT.

In what follows, we replace the condition of continuity of the operator by the condition ofα-regularity of the space.

Theorem . Let(X,d)be a complete b-metric-like space with constant s≥ and T :

XX be a generalized almostα-ψ-φ-Geraghty contractive type mapping.We suppose also that:

(i) Tis triangularα-orbital admissible; (ii) there existsx∈Xsuch thatα(x,Tx)≥;

(iii) Xisα-regular anddis continuous.

Then T has a fixed point,uX with d(u,u) = .

Proof Following the lines of the proof of Theorem ., we conclude that there existsuX

such that

lim

n→∞d(xn,u) =n,m→∞lim d(xn,xm) =d(u,u) = .

SinceXisα-regular,α(xn,xn+)≥ for alln. Due to the fact thatlimn→∞xn=u, there exists a subsequence{xnk}of{xn}such thatα(xnk,u)≥ for allk. To prove thatuis a fixed point forT, suppose on the contrary thatd(u,Tu) > .

Now, by using the properties ofψ and asT is a generalized almost α-ψ-φ-Geraghty contractive type mapping we have

ψd(xnk+,Tu)

α(xnk,u)ψ

sd(Tx

nk,Tu)

βψM(xnk,u)

ψM(xnk,u)

+LφN(xnk,u)

.

Thus we have

ψd(xnk+,Tu)

<

M(xnk,u)

+LφN(xnk,u)

, ()

where N(xnk,u) = min{d s(x

nk,Tu),d s(u,x

nk+),d(xnk,xnk+),d(u,Tu)}, and note that

limk→∞N(xnk,u) = . Moreover,

M(xnk,u) = max

d(xnk,u),d(xnk,xnk+),d(u,Tu),

d(xnk,Tu) +d(u,xnk+) s

≤max

d(xnk,u),d(xnk,xnk+),d(u,Tu),

d(xnk,u) +d(u,Tu) +d(u,xnk) +d(xnk,xnk+)

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Hence

lim

k→∞M(xnk,u)≤max

,d(u,Tu),d(u,Tu)

 =d(u,Tu),

and by the definition ofM(xnk,u) we havelimk→∞M(xnk,u) =d(u,Tu).

By the continuity ofψand theb-metric-liked, taking the limit askgoes to∞on both sides of () we have

ψd(u,Tu)≤

d(u,Tu).

Thus  = ψψ((dd((uu,,TuTu))))≤ s, which is a contradiction in the cases> . Henced(u,Tu) = ; thereforeTu=u. In the cases=  we take the limit askgoes to∞on both sides of

ψd(xnk+,Tu)

βψM(xnk,u)

ψM(xnk,u)

and getlimk→∞β(ψ(M(xnk,u))) =  and asβF so we havelimk→∞ψ(M(xnk,u)) = .

Thus we haved(u,Tu) = ; thereforeTu=u.

For the uniqueness of a fixed point of a generalizedα-ψ-φcontractive mapping, we will consider the following hypothesis.

(H) For allx,y∈Fix(T), eitherα(x,y)≥orα(y,x)≥. Here,Fix(T) denotes the set of fixed points ofT.

Theorem . Adding condition(H)to the hypotheses of Theorem. (or Theorem.),we obtain the uniqueness of the fixed point of T.

Proof Suppose thatx∗andy∗are two fixed points ofT. Then it is obvious thatM(x∗,y∗) =

d(x∗,y∗) andN(x∗,y∗) = . So, we have

ψdx∗,y∗≤ψsdTx∗,Ty

αx∗,yψsdTx∗,Ty

βψdx∗,yψdx∗,y

<

dx∗,y∗,

which is a contradiction.

Definition . Let (X,d) be ab-metric-like space with constants≥,T :XXbe a map, we say thatTis a generalized rationalα-ψ-φ-Geraghty contractive mapping of type (I) if there exist a functionα:X×X→[,∞),ψ,φ,βFs, and someL≥ such that

α(x,y)ψsd(Tx,Ty)≤βψK(x,y)ψK(x,y)+LφN(x,y), ()

for allx,yX, whereN(x,y) is defined as in () and

K(x,y) =max

d(x,y),d(x,Tx)d(y,Ty)  +d(x,y) ,

d(x,Tx)d(y,Ty)

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Definition . Let (X,d) be ab-metric-like space with constants≥,T:XXbe a map, we say thatT is a generalized rationalα-ψ-φ-Geraghty contractive of type (II) mapping if there exist a functionα:X×X→[,∞),ψ,φ,βFsand someL≥ such that

α(x,y)ψsd(Tx,Ty)≤βψQ(x,y)ψQ(x,y)+LφN(x,y), ()

for allx,yX, whereN(x,y) is defined as in () and

Q(x,y) =max

d(x,y),d(x,Tx)d(y,Ty) +d

s(x,Ty)ds(y,Tx)

 +s(d(x,Tx) +d(y,Ty)) . ()

Theorem . Let(X,d)be a complete b-metric-like space with constant s≥and T:XX be a generalized rationalα-ψ-φ-Geraghty contractive mapping of type(I)such that:

(i) Tis triangularα-orbital admissible; (ii) there existsx∈Xsuch thatα(x,Tx)≥;

(iii) Tis continuous.

Then T has a fixed point,uX with d(u,u) = .

Proof We shall use the same techniques as in the proof of Theorem .. First of all, we shall construct a sequence{xn} ⊂Xwherexn+=Txnfor whichα(xn,xn+)≥ andxn=xn+for

alln∈N.

SinceTis generalized rationalα-ψ-φ-Geraghty contractive of type (I) we have

ψsd(xn+,xn+)

α(xn,xn+)ψ

sd(Txn,Txn+)

βψK(xn,xn+)

ψK(xn,xn+)

+LφN(xn,xn+)

. ()

SinceN(xn,xn+) = , the above inequality implies that

ψsd(xn+,xn+)

βψK(xn,xn+)

ψK(xn,xn+)

, ()

where

K(xn,xn+) =max

d(xn,xn+),

d(xn,xn+)d(xn+,xn+)

 +d(xn,xn+)

,d(xn,xn+)d(xn+,xn+)  +d(xn+,xn+)

.

On the other hand, we have

d(xn,xn+)d(xn+,xn+)

 +d(xn+,xn+) ≤

d(xn,xn+)d(xn+,xn+)

d(xn+,xn+)

=d(xn,xn+)

and

d(xn,xn+)d(xn+,xn+)

 +d(xn,xn+) ≤

d(xn,xn+)d(xn+,xn+)

d(xn,xn+)

=d(xn+,xn+).

Consequently, we getK(xn,xn+)≤max{d(xn,xn+),d(xn+,xn+)}.

Ifmax{d(xn,xn+),d(xn+,xn+)}=d(xn+,xn+), then from () together with Remark .,

we have

ψsd(xn+,xn+)

<

d(xn+,xn+)

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This is a contradiction sinceψis increasing. Thus, we havemax{d(xn,xn+),d(xn+,xn+)}=

d(xn,xn+) and by the definition ofK(xn,xn+) we shall haveK(xn,xn+) =d(xn,xn+).

Con-sequently, the inequality () turns into

ψd(xn+,xn+)

ψsd(xn+,xn+)

βψK(xn,xn+)

ψd(xn,xn+)

. ()

By Remark ., we get

ψsd(xn+,xn+)

<ψd(xn,xn+)

and hence,d(xn+,xn+) <

sd(xn,xn+). ()

Case (i):s> . Since s >  andss =s< , by Lemma ., the sequence{xn}is Cauchy and

lim

n,m→∞d(xn,xm) = . ()

Case (ii):s= . Since{d(xn,xn+)}is a decreasing sequence, there existsr≥ such that

lim

n→∞d(xn,xn+) =r, ()

for somer≥. We shall prove thatr= . Suppose, on the contrary, thatr> . By letting

n→ ∞in () we find

ψ(r)≤ lim

n→∞β

ψK(xn,xn+)

ψ(r).

It yields  =limn→∞β(ψ(K(xn,xn+))). SinceβF, we getψ(K(xn,xn+))→, which

im-plies thatd(xn,xn+)→, that is,r= .

In what follows, we shall prove that{xn}is a Cauchy sequence. Indeed we will prove that

limm,n→∞d(xn,xm) = . Suppose, on the contrary, that there existε>  and corresponding

subsequences{nk}and{mk}ofNsatisfyingnk>mk>kfor which

d(xmk,xnk)≥ε, ()

wherenk,mkare chosen as the smallest integers satisfying (), that is,

d(xmk,xnk–) <ε. ()

By (), (), and the triangle inequality, we easily derive that

εd(xmk,xnk)≤d(xmk,xnk–) +d(xnk–,xnk)

<ε+d(xnk–,xnk). ()

Using () and the squeeze theorem we get

lim

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Regarding that T is generalized rational α-ψ-φ-Geraghty contractive mapping of type (I), we have

ψd(xmk+,xnk+)

α(xmk,xnk)ψ

d(Txmk,Txnk)

βψK(xmk,xnk)

ψK(xmk,xnk)

+LφN(xmk,xnk)

, ()

for allx,yX, where

K(xmk,xnk) =max

d(xmk,xnk),

d(xmk,xmk+)d(xnk,xnk+)

 +d(xmk,xnk) ,

d(xmk,xmk+)d(xnk,xnk+)

 +d(xmk+,xnk+)

()

and

N(xmk,xnk) =min

ds(xmk,xnk+),ds(xnk,xmk+),d(xmk,xmk+),d(xnk,xnk+)

.

It is clear that

lim

k→∞K(xmk,xnk) =ε and k→∞limN(xmk,xnk) = .

By taking the limit ask→ ∞in () and taking (), () into account, we get

ψ(ε)≤ lim

k→∞β

ψK(xmk,xnk)

lim

k→∞ψ

K(xmk,xnk)

≤ lim

k→∞β

ψK(xmk,xnk)

ψ(ε). ()

Sinceβis a Geraghty function, we derive thatψ(K(xmk,xnk))→. Consequently, we have

d(xmk,xnk)→, which is a contradiction. Hencelimm,n→∞d(xn,xm) = , and the sequence {xn}is Cauchy for anys≥.

By completeness of (X,d), there existsuXsuch that

lim

n→∞d(xn,u) =d(u,u) =n,m→∞lim d(xn,xm) = .

Now, ifTis continuous, then

Tu=T

lim

n→∞xn

= lim

n→∞Txn=n→∞limxn+=u,

anduis a fixed point forT.

Theorem . Let(X,d)be a complete b-metric-like space with constant s≥and T:XX be a generalized rationalα-ψ-φ-Geraghty contractive of mapping type(I)such that:

(i) Tis triangularα-orbital admissible; (ii) there existsx∈Xsuch thatα(x,Tx)≥;

(iii) Xisα-regular anddis continuous.

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Proof Verbatim of the proof of Theorem ., we conclude that the iterative sequence{xn} is Cauchy and converges touX. SinceXisα-regular, then, as in the proof of Theo-rem ., there exists a subsequence{xnk}of{xn}such that

ψd(xnk+,Tu)

<

K(xnk,u)

+LφN(xnk,u)

, ()

whereK(xnk,u) =max{d(xnk,u),

d(xnk,xnk+)d(u,Tu)

+d(xnk,u) ,

d(xnk,xnk+)d(u,Tu)

+d(xnk+,Tu) }.

Hencelimk→∞K(xnk,u) =  and as in the proof of Theorem .limk→∞N(xnk,u) = . Thus taking the limit ask→ ∞on both sides of () and keeping in mind thatψandd

are continuous we haveψ(d(u,Tu))≤. Henced(u,Tu) = ; thereforeTu=u.

Theorem . Adding condition(H)to the hypotheses of Theorem. (or Theorem.),

we obtain uniqueness of the fixed point of T.

Proof As in the proof of Theorem ., we suppose thatx∗andy∗are two fixed points ofT. Then, clearly, we haveK(x∗,y∗) =d(x∗,y∗) andN(x∗,y∗) = . So, we have

ψdx∗,y∗≤ψsdTx∗,Ty

αx∗,yψsdTx∗,Ty

βψdx∗,yψdx∗,y

<

dx∗,y∗,

which is a contradiction.

Theorem . Let(X,d)be a complete b-metric-like space with constant s≥and T :

XX be a generalized rationalα-ψ-φ-Geraghty contractive mapping of type(II)such that:

(i) Tis triangularα-orbital admissible; (ii) there existsx∈Xsuch thatα(x,Tx)≥;

(iii) Tis continuous.

Then T has a fixed point,uX with d(u,u) = .

Proof Verbatim of the lines in the proof of Theorem ., we construct a sequence{xn} ⊂X wherexn+=Txnfor whichα(xn,xn+)≥ andxn=xn+for alln∈N. Moreover, by using

the fact thatT is a generalized rationalα-ψ-φ-Geraghty contractive mapping of type (II) and the property ofψwe have

ψsd(xn+,xn+)

α(xn,xn+)ψ

sd(Txn,Txn+)

βψQ(xn,xn+)

ψQ(xn,xn+)

+LφN(xn,xn+)

. ()

By using the same arguments as in the proof of Theorem ., we derive that

ψsd(xn+,xn+)

<

Q(xn,xn+)

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where

Q(xn,xn+) =max

d(xn,xn+),

d(xn,xn+)d(xn+,xn+) +ds(xn,xn+)ds(xn+,xn+)

 +s[d(xn,xn+) +d(xn+,xn+)]

.

Sinced(xn,xn+)≤s[d(xn,xn+) +d(xn+,xn+)], we have

d(xn,xn+)≥

d(xn,xn+)d(xn,xn+)

 +d(xn,xn+)

d(xn,xn+)d(xn,xn+)

 +s[d(xn,xn+) +d(xn+,xn+)]

.

Hence, we getQ(xn,xn+) =d(xn,xn+).

By using () we get ψ(sd(x

n+,xn+))≤ ψ(d(xn,xn+)). Since ψ is increasing we

haved(xn+,xn+) < sd(xn,xn+). Ifs>  then, as in the proof of Theorem ., by using

Lemma ., we conclude that{xn} is a Cauchy sequence andlimn,m→∞d(xn,xm) = . If

s= , by verbatim of the proof of Theorem ., we deduce that{xn}is a Cauchy sequence. Since (X,d) is complete, there exists uX such that  = limn,m→∞d(xn,xm) =

limn→∞d(xn,u) =d(u,u). Now, sinceTis continuous,Tu=T(limn→∞xn) =limn→∞Txn=

limn→∞xn+=uanduis a fixed point forT.

Theorem . Let(X,d)be a complete b-metric-like space with constant s≥and T:

XX be a generalized rationalα-ψ-φ-Geraghty contractive mapping of type(II)such that:

(i) Tis triangularα-orbital admissible; (ii) there existsx∈Xsuch thatα(x,Tx)≥;

(iii) Xisα-regular anddis continuous.

Then T has a fixed point,uX with d(u,u) = .

Proof By following the proof of Theorem . line by line, we see that{xn}converges to

uX. Due to the fact thatXisα-regular and by following the lines of the proof of Theo-rem . there exists a subsequence{xnk}of{xn}such that

ψd(xnk+,Tu)

<

Q(xnk,u)

+LφN(xnk,u)

, ()

where

Q(xnk,u) =max

d(xnk,u),

d(xnk,xnk+)d(u,Tu) +ds(xnk,Tu)ds(u,xnk+)

 +s[d(xnk,xnk+) +d(u,Tu)]

.

Note thatlimk→∞Q(xnk,u) =  andlimk→∞N(xnk,u) = . Thus taking the limit asn→ ∞ on both sides of () and keeping in mind that ψ and d are continuous we have

ψ(d(u,Tu)) = , and sod(u,Tu) = . Thusu=Tu.

Theorem . Let(X,d)be a complete b-metric-like space with constant s≥and T:

XX be a mapping. Suppose that there exist a functionα:X×X→[,∞),ψ,

βFssuch that

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for all x,yX.Suppose also that:

(i) Tis triangularα-orbital admissible; (ii) there existsx∈Xsuch thatα(x,Tx)≥;

(iii) Tis continuous.

Then T has a fixed point,uX with d(u,u) = .

Proof By (ii) there existsx∈Xsuch thatα(x,Tx)≥. Define a sequence{xn} ⊂Xby

xn+=Txnfor alln∈N. AsT is triangularα-orbital admissible, by Lemma . we have α(xn,xn+)≥ for alln∈N. Notice that if there exists a natural numbernsuch that

xn=xn+, then the proof is complete. To avoid this trivial case, from now on, we assume thatxn=xn+for alln∈N.

SinceTsatisfies () we have

ψsd(xn+,xn+)

α(xn,xn+)ψ

sd(Txn,Txn+)

βψd(xn,xn+)

ψd(xn,xn+)

.

Thus, we have

ψsd(xn+,xn+)

<

d(xn,xn+)

<ψd(xn,xn+)

. ()

Sinceψis increasing, we haved(xn+,xn+) <sd(xn,xn+).

Case (i): Ifs> , then, since s >  andss =s < , by Lemma .,{xn}is a Cauchy se-quence andlimn,m→∞d(xn,xm) = .

Case (ii): If s = , then as d(xn+,xn+) <d(xn,xn+), there exists r≥  such that

limn→∞d(xn,xn+) =r. Ifr>  then taking the limit asn→ ∞on both sides of

ψd(xn+,xn+)

βψd(xn,xn+)

ψd(xn,xn+)

we getlimn→∞β(ψ(d(xn,xn+))) =  and asβis a Geraghty function, we derive that

lim

n→∞d(xn,xn+) = . ()

That is,r= . In what follows we shall prove that{xn}is a Cauchy sequence. Indeed we will prove thatlimm,n→∞d(xn,xm) = . Suppose, on the contrary, that there existε>  and

corresponding subsequences{nk}and{mk}ofNsatisfyingnk>mk>kfor which

d(xmk,xnk)≥ε, ()

wherenk,mkare chosen as the smallest integers satisfying (), that is,

d(xmk,xnk–) <ε. ()

By (), (), and the triangle inequality, we easily derive that

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Using () and the squeeze theorem we get

lim

k→∞d(xmk,xnk) =ε. ()

AsTsatisfies (), we have

ψd(xmk+,xnk+)

α(xmk,xnk)ψ

d(Txmk,Txnk)

βψd(xmk,xnk)

ψd(xmk,xnk)

. ()

Taking the limit ask→ ∞for () we getlimk→∞β(ψ(d(xmk,xnk))) = . Thus

lim

k→∞d(xmk,xnk) = .

Therefore,{xn}is a Cauchy sequence fors≥. By completeness of (X,d), there existsuX such that  =limn,m→∞d(xn,xm) =limn→∞d(xn,u) =d(u,u).

SinceT is continuous,Tu=T(limn→∞xn) =limn→∞Txn=limn→∞xn+=uanduis a

fixed point forT.

Theorem . Let(X,d)be a complete b-metric-like space with constant s≥and T :

XX be a mapping.Suppose that there exist a functionα:X×X→[,∞),ψ,and βFssuch that

α(x,y)ψsd(Tx,Ty)≤βψd(x,y)ψd(x,y), ()

for all x,yX.Suppose also that:

(i) Tis triangularα-orbital admissible; (ii) there existsx∈Xsuch thatα(x,Tx)≥;

(iii) Xisα-regular anddis continuous.

Then T has a fixed point,uX with d(u,u) = .

Theorem . Adding condition(H)to the hypotheses of Theorem. (or Theorem.),

we obtain the uniqueness of the fixed point of T.

Remark . Notice that we get several corollaries by replacing the auxiliary functions

ψ andβin a proper way. In particular, by takingψ(t) =twe find the extended version of several existing results.

3 Expected consequences

In this section, we shall consider some immediate consequences of our main results. The following result is obtained by lettingL=  in Theorem . or ..

Corollary . Let(X,d)be a complete b-metric-like space with constant s≥and T:XX be a mapping.Suppose that there existα:X×X→[,∞),ψ,βFssuch that

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for all x,yX,where

M(x,y) =max

d(x,y),d(x,Tx),d(y,Ty),d(x,Ty) +d(y,Tx)

s . ()

Suppose also that:

(i) Tis triangularα-orbital admissible; (ii) there existsx∈Xsuch thatα(x,Tx)≥;

(iii) Tis continuous or(iii)Xisα-regular anddis continuous.

Then T has a fixed point.

Adding condition (H) to the hypothesis of Corollary ., we guarantee the uniqueness of the fixed point.

Again by lettingL=  in Theorem . and Theorem . we get two more corollaries as Corollary .. We skip the details regarding the volume of the paper.

Corollary . Let(X,d)be a complete b-metric-like space with constant s≥,T:XX

be a map andα:X×X→[,∞)be a function.Suppose that T satisfies at least one of the following conditions:

(a) α(x,y)d(Tx,Ty)≤sM(x,y); (b) α(x,y)d(Tx,Ty)≤ 

sK(x,y);

where M(x,y),K(x,y)are defined as in(), ().Suppose also that: (i) Tis triangularα-orbital admissible;

(ii) there existsx∈Xsuch thatα(x,Tx)≥;

(iii) Tis continuous or(iii)Xisα-regular anddis continuous.

Then T has a unique fixed point uX with d(u,u) = .

Proof It is sufficient to takeL= ,ψ(t) =t, andβ(t) =sin Theorem . and Theorem . (and thus, Theorem . or Theorem ., Theorem . or Theorem ., respectively).

Adding condition (H) to the hypothesis of Corollary ., we guarantee the uniqueness of the fixed point.

Corollary . Let(X,d)be a complete b-metric-like space with constant s≥,T:XX be a map,andα:X×X→[,∞)be a function.Suppose that T satisfies at least one of the following conditions:

(c) α(x,y)d(Tx,Ty)≤sQ(x,y),

where M(x,y),K(x,y),Q(x,y)are defined as in().Suppose also that: (i) Tis triangularα-orbital admissible;

(ii) there existsx∈Xsuch thatα(x,Tx)≥;

(iii) Tis continuous or(iii)Xisα-regular anddis continuous.

Then T has a fixed point uX with d(u,u) = .

Proof It is sufficient to takeL= ,ψ(t) =t, andβ(t) = 

sin Theorem . or Theorem .,

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3.1 For standardb-metric-like spaces

If we setα(x,y) =  for allx,yXin Theorem ., then we derive the following results.

Corollary . Let(X,d)be a complete b-metric-like space with constant s≥such that d is continuous and T:XX be a mapping.Suppose that there existψ,φ,βFs,and

some L≥such that

ψsd(Tx,Ty)≤βψM(x,y)ψM(x,y)+LφN(x,y), ()

for all x,yX,where

M(x,y) =max

d(x,y),d(x,Tx),d(y,Ty),d(x,Ty) +d(y,Tx)

s and ()

N(x,y) =minds(x,Ty),ds(y,Tx),d(x,Tx),d(y,Ty). ()

Then T has a unique fixed point uX with d(u,u) = .

If we setα(x,y) =  for allx,yXin Theorem ., then we derive the following results.

Corollary . Let(X,d)be a complete b-metric-like space with constant s≥such that d is continuous and T:XX be a mapping.Suppose that there existψ,φ,βFs,and

some L≥such that

ψsd(Tx,Ty)≤βψK(x,y)ψK(x,y)+LφN(x,y), ()

for all x,yX,where

K(x,y) =max

d(x,y),d(x,Tx)d(y,Ty)  +d(x,y) ,

d(x,Tx)d(y,Ty)

 +d(Tx,Ty) and ()

N(x,y) =minds(x,Ty),ds(y,Tx),d(x,Tx),d(y,Ty). ()

Then T has a unique fixed point uX with d(u,u) = .

If we setα(x,y) =  for allx,yXin Theorem ., then we derive the following results.

Corollary . Let(X,d)be a complete b-metric-like space with constant s≥such that d is continuous and T:XX be a mapping.Suppose that there existψ,φ,βFs,and

some L≥such that

ψsd(Tx,Ty)≤βψQ(x,y)ψQ(x,y)+LφN(x,y), ()

for all x,yX,where

Q(x,y) =max

d(x,y),d(x,Tx)d(y,Ty) +d

s(x,Ty)ds(y,Tx)

 +s(d(x,Tx) +d(y,Ty)) and ()

N(x,y) =minds(x,Ty),ds(y,Tx),d(x,Tx),d(y,Ty). ()

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If takeL=  in Corollaries .-., we get three more consequences. Regarding the vol-ume of the paper, we skip the details.

Corollary . Let(X,d)be a complete b-metric-like space with constant s≥such that d

is continuous and T:XX be mapping.Suppose that there existψandβFssuch

that

ψsd(Tx,Ty)≤βψd(x,y)ψd(x,y), ()

for all x,yX.Then T has a unique fixed point uX with d(u,u) = .

Proof It follows from Theorem . byα(x,y) =  for allx,yX.

3.2 Forb-metric-like spaces endowed with a partial order

In this section, from our main results, we shall derive easily various fixed point results on ab-metric-like space endowed with a partial order. We, first, recall some notions.

Definition . Let (X,) be a partially ordered set andT:XXbe a given mapping. We say thatT is nondecreasing with respect toif

x,yX, xyTxTy.

Definition . Let (X,) be a partially ordered set. A sequence{xn} ⊂Xis said to be nondecreasing (respectively, nonincreasing) with respect toifxnxn+(respectively,

xn+xnfor alln).

Definition . Let (X,) be a partially ordered set anddbe ab-metric-like onX. We say that (X,,d) is regular if for every nondecreasing (respectively, nonincreasing) sequence {xn} ⊂Xsuch thatxnxXasn→ ∞, there exists a subsequence{xnk}of{xn}such thatxnkx(respectively,xnkx) for allk.

We have the following result.

Corollary . Let(X,)be a partially ordered set(which does not contain an infinite totally unordered subset)and d be a b-metric-like on X with constant s≥such that(X,d)

is complete.Let T:XX be a nondecreasing mapping with respect to.Suppose that

there existψ,βFssuch that

ψsd(Tx,Ty)βψM(x,y)ψM(x,y), ()

for all x,yX with xy or yx where M(x,y)is defined as in().Suppose also that the following conditions hold:

(i) there existsx∈Xsuch thatxTx;

(ii) T is continuous or(ii)(X,,d)is regular anddis continuous.

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Proof Define the mappingα:X×X→[,∞) by

α(x,y) =

 ifxyorxy,  otherwise.

Clearly,Tsatisfies (), that is,

α(x,y)ψsd(Tx,Ty)≤βψM(x,y)ψM(x,y),

for allx,yX. From condition (i), we haveα(x,Tx)≥. Moreover, for allx,yX, from

the monotone property ofT, we have

α(x,y)≥ ⇒ xyorxyTxTyorTxTyα(Tx,Ty)≥.

Hence, the self-mappingTisα-admissible. Similarly, we can prove thatTis triangularα -admissible and so triangularα-orbital admissible. Now, ifT is continuous, the existence of a fixed point follows from Corollary .. Suppose now that (X,,d) is regular. Let{xn} be a sequence inXsuch thatα(xn,xn+)≥ for allnandxnxXasn→ ∞. From the regularity hypothesis and asXdoes not contain an infinite totally unordered subset, there exists a subsequence{xnk}of{xn}such thatxnkxorxxnkfor allk. This implies from the definition ofαthatα(xnk,x)≥ for allk. In this case, the existence of a fixed point

follows again from Corollary ..

In an analogous way, we derive the following results from Theorem . and Theo-rem ., respectively.

Corollary . Let(X,)be a partially ordered set(which does not contain an infinite totally unordered subset)and d be a b-metric-like on X with constant s≥such that(X,d)

is complete.Let T:XX be a nondecreasing mapping with respect to.Suppose that

there existψ,βFssuch that

ψsd(Tx,Ty)≤βψK(x,y)ψK(x,y), ()

for all x,yX with xy or yx where M(x,y)is defined as in().Suppose also that the following conditions hold:

(i) there existsx∈Xsuch thatxTx;

(ii) T is continuous or(ii)(X,,d)is regular anddis continuous.

Then T has a fixed point uX with d(u,u) = .

Corollary . Let(X,)be a partially ordered set(which does not contain an infinite totally unordered subset)and d be a b-metric-like on X with constant s≥such that(X,d)

is complete.Let T:XX be a nondecreasing mapping with respect to.Suppose that

there existψ,βFssuch that

ψsd(Tx,Ty)≤βψQ(x,y)ψQ(x,y), ()

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(i) there existsx∈Xsuch thatxTx;

(ii) T is continuous or(ii)(X,,d)is regular anddis continuous.

Then T has a fixed point uX with d(u,u) = .

Corollary . Let(X,)be a partially ordered set(which does not contain an infinite totally unordered subset)and d be b-metric-like on X with constant s≥such that(X,d)

is complete.Let T:XX be a nondecreasing mapping with respect to.Suppose that

there existψ,βFssuch that

ψsd(Tx,Ty)≤βψd(x,y)ψd(x,y), ()

for all x,yX with xy or yx.Suppose also that the following conditions hold: (i) there existsx∈Xsuch thatxTx;

(ii) T is continuous or(ii)(X,,d)is regular anddis continuous.

Then T has a fixed point uX with d(u,u) = .

Example . LetX= [,∞) defined:X×X→[,∞) byd(x,y) =|xy|. Then (X,d)

is completeb-metric (sob-metric-like) space with constants= . DefineT:XXand

α(x,y) :X×X→[,∞) as follows:

Tx=

x

 ifx∈[, ],

x

x+ ifx∈(,∞),

and

α(x,y) =

 ifx,y∈[, ],  otherwise.

It is clear thatTis triangularα-orbital admissible and we haveα(,T)≥. Moreover,X

isα-regular anddis continuous.

Letψ(t) =t,β(t) = then clearlyψandβF. Moreover,T satisfies () for the following reason: ifx,y∈[, ], then

α(x,y)ψd(Tx,Ty)= 

x

–

y

=(xy)

 =β

ψd(x,y)ψ(d(x,y).

Otherwise,

α(x,y)ψd(Tx,Ty)= ≤βψd(x,y)ψ(d(x,y).

Therefore, by Theorem .,Thas a fixed pointx= .

Example . LetX={, , }defined:X×X→[,∞) byd(x,y) = (max{x,y}). Then (X,d) is completeb-metric-like space with constants= –=  such thatdis continu-ous. DefineT:XXbyT={(, ), (, ), (, )}.

Letψ(t) =t,β(t) = 

e

t or β(t) =

+t, then clearly

ψ andβF

. Note that

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4 Conclusion

It is clear that we can list several more results by replacing theb-metric-like space, with some other abstract space, such as ab-metric space, a metric space, a metric-like space, a partial metric space, and so on.

Competing interests

The authors declare that they have no competing interests.

Authors’ contributions

All authors contributed equally and significantly in writing this article. All authors read and approved the final manuscript.

Received: 16 July 2015 Accepted: 15 September 2015

References

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10. Kutbi, MA, Karapınar, E, Ahmed, J, Azam, A: Some fixed point results for multi-valued mappings inb-metric spaces. J. Inequal. Appl.2014, Article ID 126 (2014)

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