Solutions
SECTION - A
Objective Type Questions 1. According to modified Ampere's circuital law(iD = displacement current) (1)
∫
⎟ ⎠ ⎞ ⎜ ⎝ ⎛ dt d i dl B 0 C 0 E (2)∫
dt d dl B 0 0 E (3)∫
B dl0i (4)∫
⎟ ⎠ ⎞ ⎜ ⎝ ⎛ E D C i dt d i l d B 0 Sol. Answer (1)According to modified Ampere's circuital law.
∫
⎟ ⎠ ⎞ ⎜ ⎝ ⎛ dt d i dl B 0 C 0 E2. Displacement current is set up between the plates of a capacitor when the potential difference across the plates is
(1) Maximum (2) Zero (3) Minimum (4) Varying
Sol. Answer (4)
Displacement current, Id A 0dE dt
So, the potential difference has to change with time
3. A parallel plate capacitor with circular plates of radius R is being charged as shown. At the instant shown, the displacement current in the region between the plates enclosed between
2 R and R is given by + – i i (1) i 4 3 (2) i 4 1 (3) 3 i (4) i 3 4
Chapter
8
Electromagnetic Waves
Sol. Answer (1)
2 0 0 d dE dE I A R i dt dt ⎛ ⎞ ⎜⎝ 2 2⎟⎠ 0 ' – 4 d dE R I R dt 3 0 2 4 dE R dt 3 ' 4 d I i4. Figure shows a circular region of radius R in which uniform magnetic field B exists. The magnetic field is increasing at a rate
dt
dB. The induced electric field at a distance r from the centre for r < R is
R B O (1) 2 r dt dB (2) Zero (3) dt dB (4) r R dt dB 2 2 Sol. Answer (1) Rate of increase of B dB dt 2 – in d E r dt or E 2 r – dBA dt 2 2 – dB E r r dt E –2r dB dt
5. The speed of electromagnetic waves depends upon
(1) Wavelength (2) Frequency
Sol. Answer (4) Speed of wave I 0 r 0 r I It depends upon the medium.
6. If E and B represent the electric and magnetic field vectors of an electromagnetic wave, then the direction of propagation of the electromagnetic wave is in the direction of
(1) E (2) B (3) E B (4) B E
Sol. Answer (3)
Direction of propagation is given by E B
7. If an electromagnetic wave propagating through vacuum is described by Ey = E0 sin (kx – t); Bz = B0 sin (kx – t), then (1) E0 k = B0 (2) E0 B0 = k (3) E0 = B0 k (4) k B E0 0 Sol. Answer (1) Speed of wave 0 0 E B k kE0 B0
8. Electromagnetic wave is deflected by
(1) Electric field (2) Magnetic field
(3) Both (1) & (2) (4) Neither electric field nor magnetic field Sol. Answer (4)
Electromagnetic wave consists of unchanged particle called photons which are neither deflected by electric field nor by magnetic field.
9. Out of the following, choose the ray which does not travel with the velocity of light
(1) X-ray (2) Microwave (3) -rays (4) -rays
Sol. Answer (4)
-rays do not travel with speed of light, as they are not em waves. 10. Red light differs from blue light in its
(1) Speed (2) Frequency (3) Intensity (4) Amplitude
Sol. Answer (2)
Frequency is different for each light as they have different wavelengths. 11. Which of the following has the largest wavelength?
(1) Radio wave (2) X-ray (3) Ultraviolet ray (4) Infra-red ray Sol. Answer (1)
12. Velocity of electromagnetic waves in a medium is (1) ( 0 0)1/2 (2) ( 0 r 0 r)1/2 (3) 3 × 108 m/s (4) 1/2 0 0 r r ⎛ ⎞ ⎜ ⎟ ⎝ ⎠ Sol. Answer (2)
Speed of light in medium
0 0 1 1 r r
–1 2 0 r 0 r 13. Which of the following is incorrect about a plane electromagnetic wave? (1) The electric field and magnetic field have equal average values
(2) The electric energy and the magnetic energy have equal average values (3) The electric field and magnetic field both oscillate in same phase (4) The electric field and magnetic field oscillate in opposite phase Sol. Answer (4)
and
E B are in the same phase but oscillate in different planes which are perpendicular to each other. 14. In a plane electromagnetic wave, which of the following has/ have zero average value in one complete cycle?
(a) Magnetic field (b) Magnetic energy (c) Electric field (d) Electric energy
(1) (a), (c) (2) (b), (c) (3) (a), (d) (4) All of these
Sol. Answer (1)
Both E and B are sinusoidal, so over a complete cycle, its value will be zero.
15. An electromagnetic wave is propagating in vacuum along z-axis, the electric field component is given by Ex = E0 sin(kz – t), then magnetic component is
(1) Bx = E0sin
kz– t
C (2) By =
0 sin – B kz t C (3) By = E0sin
kz– t
C (4) By = B0C sin(kz – t) Sol. Answer (3) Direction of propagation Z 0sin – x E E kZ tB will be in the y-direction By B0sinkZ–t 0 0 E c B 0 0 E B c So, By E0sinkZ–t c
16. The speed of electromagnetic wave in a medium (whose dielectric constant is 2.25 and relative permeability is 4) is equal to (1) 0.5 108 m/s (2) 0.25 108 m/s (3) 0.75 108 m/s (4) 1 108 m/s Sol. Answer (4) Er = 2.25, r = 4 0 0 1 r r V 0 0 1 1 2.25 4 8 3 10 1.5 2 V = 108 m/s
17. The magnetic field in a plane electromagnetic wave is given by = 2 × 10–7sin(0.5 × 103x + 1.5 × 1011t). This electromagnetic wave is
(1) Visible light (2) Infrared (3) Microwave (4) Radiowave
Sol. Answer (4)
–7 –3 11 2 10 sin 0.5 10 1.5 10 B x t –3 , 0.5 10 c f k 1.5 10 11 11 14 –3 1.5 10 3 10 0.5 10 V k f k 2 k 4 –3 Radio waves 2 2 22 1.25 10 m 7 0.5 10 k 18. The dimensional formula of 0 2 2 1 E is (E = electric field) (1) [M L T–1 (2) [M L2 T–2 (3) [M L–1 T–2 (4) [M L2 T–1 Sol. Answer (3)
2 –2 2 0 3 1 ML T Energy density 2 L E E V =
ML T–1 –2
19. Which of the following represents an infra-red wavelength?
(1) 10–4 cm (2) 10–5 cm (3) 10–6 cm (4) 10–7 cm
Sol. Answer (1)
20. Which of the following is not transported by electromagnetic waves?
(1) Energy (2) Momentum (3) Charge (4) Information
Sol. Answer (3)
Only energy, momentum and information can be transferred with the help of em waves, not any matter. 21. Hertz experiment is used for
(1) Production of electromagnetic wave (2) Detection of electromagnetic wave
(3) Both (1) & (2) (4) None of these
Sol. Answer (3)
Hertz was the scientist who produced and detected the em waves. 22. Electromagnetic waves are produced due to
(1) A charge at rest (2) A moving charge
(3) An accelerated charge (4) None of these
Sol. Answer (3)
Em waves are produced by accelerated charged particles. 23. Ozone layer blocks the radiation of wavelength
(1) Less than 4 × 10–7 m (2) Between 4 × 10–7 m to 8 × 10–7 m
(3) More than 8 × 10–7m (4) None of these
Sol. Answer (1)
Radiation having wavelength less than 4 10–7 m are blocked by ozone layer 24. Which of the following can be used in cancer treatment?
(1) X-rays (2) UV-rays (3) -rays (4) Both (1) & (3)
Sol. Answer (4)
Both X-rays and -rays are used for the treatment of cancer. 25. The following can be arranged in decreasing order of wave number
A. AM radio B. TV and FM radio
C. Microwave D. Short radio wave
(1) A > B > D > C (2) C > D > B > A (3) A > B > C > D (4) D > C > B > A Sol. Answer (2)
Decreasing order of wave number
Microwave > short radiowave > TV and FM radio > AM radio.
SECTION - B
Objective Type Questions1. If the electric field and magnetic field of an electromagnetic wave are related as B =E
c where the symbols have their usual meanings and the energy in a given volume of space due to the electric field part is U, then the energy due to the magnetic field part will be
(1) U c (2) 2 U c (3) 2 U (4) U
Sol. Answer (4) E B C Energy due to E 12 0E2 Energy due to 2 0 0 2 B B part U2 part U2 E B part part E B
2. The direction of poynting vector represents (1) The direction of electric field
(2) The direction of magnetic field
(3) The direction of propagation of EM wave
(4) The direction opposite to the propagation of EM wave Sol. Answer (3) 0 E B S
direction of wave propagation E B ⇒
3. A plane electromagnetic wave is incident on a plane surface of area A normally, and is perfectly reflected. If energy E strikes the surface in time t then average pressure exerted on the surface is (c = speed of light)
(1) Zero (2) E Atc (3) 2E Atc (4) c E Sol. Answer (3) 2I P c [Perfect reflection] 2 E Atc P 2E Atc
4. 5% of the power of 100 W bulb is converted to visible radiation. Average intensity of visible radiation at a distance of 10 m from the bulb is
(1) 2(105 )2 watt/m2 (2) 2 ) 10 ( 4 5 watt/m2 (3) (10)2 5 watt/m2 (4) 8 (10)2 5 watt/m2 Sol. Answer (2) E P I At A 2 2 2 5 100 5 100 watt/m 4 4 10 400 P r
5. Which of the following physical quantities contained in a small volume oscillates at double the frequency of passing electromagnetic wave?
(1) Electric field (2) Magnetic field (3) Magnetic energy (4) All of these Sol. Answer (3)
The electric and magnetic energy oscillate at double the frequency as compared to electric and magnetic field. 6. A capacitor is connected across a battery which delivers a current of 1 A at an instant in the capacitor. Displacement
current through the capacitor at that instant is
(1) 1 A (2) 0 A (3) 2 A (4) A 2 1 Sol. Answer (1) I = 1 A Id = 1 A
7. The magnetic field in a plane electromagnetic wave is given by, B = 3.01 × 10–7 sin (6.28 × 102x + 2.2 × 1010t) T.
[where x in cm and t in second]. The wavelength of the given wave is
(1) 1 cm (2) 628 cm (3) 1.129 cm (4) 314 cm Sol. Answer (1)
–7 2 10 3.01 10 sin 6.28 10 2.2 10 T B x t 2 6.28 10 k 2.2 10 10 2 k 2 –2 2 10 m 6.28 108. At a particular instant the current in the circuit given below is i. The displacement current between the plates of the capacitor shown below is
V i C (1) Zero (2) i (3) 2 i (4) 4 i Sol. Answer (2) Displacement current id = i
9. To establish an instantaneous displacement current of I ampere in the space between the plates of a parallel plate capacitor of
2 1
farad, the value of
dt dV is (1) 2I (2) 2 I (3) I 2 1 (4) I
Sol. Answer (1) 0 d A dE I d d dt 1 2 dE I d dt 1 1 . 2 dV I d dt d 2 dV I dt
10. A plane electromagnetic wave of frequency 28 MHz travels in free space along the positive x-direction. At a particular point in space and time, electric field is 9.3 V/m along positive y-direction. The magnetic field (in T) at that point is
(1) 3.1 × 10–8 along positive z-direction (2) 3.1 × 10–8 along negative z-direction
(3) 3.2 × 107 along positive z-direction (4) 3.2 × 107 along negative z-direction
Sol. Answer (1) f = 28106 Hz E = 9.3 V/m
ˆj Bc = E 8 9.3 3 10 B B = 3.1 × 10–8 along positive z-direction
SECTION - C
Previous Years Questions1. The energy of the em waves is of the order of 15 keV. To which part of the spectrum does it belong? [Re-AIPMT-2015]
(1) -rays (2) X-rays (3) Infra-red rays (4) Ultraviolet rays
Sol. Answer (2) E = 15 keV 19 8 6 –19 6.6 10 3 10 15 10 1.6 10 hc E = 0.8 Å 1 Å
2. A radiation of energy E falls normally on a perfectly reflecting surface. The momentum transferred to the surface
is (C = velocity of light) [AIPMT-2015]
(1) E2 C (2) E C (3) 2E C (4) 2 2E C
Sol. Answer (3)
Surface is perfectly reflecting
So change in momentum i.e., momentum transferred is p p– –
p 2 p p
So, Ep 2C
3. Light with an energy flux of 25 × 104 Wm–2 falls on a perfectly reflecting surface at normal incidence. If the surface area is 15 cm2, the average force exerted on the surface is [AIPMT-2014] (1) 1.25 × 10–6 N (2) 2.50 × 10–6 N (3) 1.20 × 10–6 N (4) 3.0 × 10–6 N Sol. Answer (2) 4 4 av 2 2 25 10 15 10 N8 3 10 I A F c = 250 × 10–8 N = 2.5 × 10–6N
4. The condition under which a microwave oven heats up a food item containing water molecules most efficiently
is [NEET-2013]
(1) The frequency of the microwaves has no relation with natural frequency of water molecules (2) Microwaves are heat waves, so always produce heating
(3) Infra-red waves produce heating in a microwave oven
(4) The frequency of the microwaves must match the resonant frequency of the water molecules Sol. Answer (4)
5. The electric field associated with an e. m. wave in vacuum is given by E iˆ40 cos (kz – 6 × 108t), where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is [AIPMT (Prelims)-2012]
(1) 6 m–1 (2) 3 m–1 (3) 2 m–1 (4) 0.5 m–1
Sol. Answer (3)
6. The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating
in vacuum is equal to [AIPMT (Mains)-2012]
(1) The speed of light in vacuum
(2) Reciprocal of speed of light in vacuum
(3) The ratio of magnetic permeability to the electric susceptibility of vacuum (4) Unity Sol. Answer (2) 0 0 E C B 0 0 1 B E C
7. The electric and the magnetic field, associated with an e.m. wave, propagating along the +z-axis, can be
represented by [AIPMT (Prelims)-2011]
(1) ⎡⎣E E j B B k 0ˆ, 0ˆ⎦⎤ (2) ⎡⎣E E i B B j 0ˆ, 0ˆ⎤⎦
(3) ⎡⎣E E k B B i 0ˆ, 0ˆ⎤⎦ (4) ⎣⎡E E j B B i 0ˆ, 0ˆ⎤⎦ Sol. Answer (2)
If wave is propagating in +z direction then E and B will be in x-y plane. Also, E B = direction of propagation
0ˆ, 0ˆ
E E i B B j
8. The decreasing order of wavelength of infrared, microwave, ultraviolet and gamma rays is
[AIPMT (Prelims)-2011] (1) Infrared, microwave, ultraviolet, gamma rays (2) Microwave, infrared, ultraviolet, gamma rays (3) Gamma rays, ultraviolet, infrared, microwaves (4) Microwaves, gamma rays, infrared, ultraviolet Sol. Answer (2)
Maximum wavelength = microwaves Minimum wavelength = -rays
9. Which of the following statement is false for the properties of electromagnetic waves?
[AIPMT (Prelims)-2010] (1) These waves do not require any material medium for propagation
(2) Both electric and magnetic field vectors attain the maxima and minima at the same place and same time (3) The energy in electromagnetic wave is divided equally between electric and magnetic vectors
(4) Both electric and magnetic field vectors are parallel to each other and perpendicular to the direction of propagation of wave
Sol. Answer (4)
10. The electric field of an electromagnetic wave in free
space is given by E10cos 10
7t kx j
ˆ V/m, where t and x are in seconds and metres respectively. It can be inferred that(a) The wavelength is 188.4 m (b) The wave number k is 0.33 rad/m (c) The wave amplitude is 10 V/m
(d) The wave is propagating along +x direction
Which one of the following pairs of statements is correct ? [AIPMT (Mains)-2010] (1) (c) & (d) (2) (a) & (b) (3) (b) & (c) (4) (a) & (c)
11. The electric field part of an electromagnetic wave in a medium is represented by
Ex = 0; Ey=2.5NCcos 2 106rads t 102radm x
⎡⎛ ⎞ ⎛ ⎞ ⎤
⎜ ⎟ ⎜ ⎟
⎢⎝ ⎠ ⎝ ⎠ ⎥
⎣ ⎦;
Ez = 0. The wave is [AIPMT (Prelims)-2009]
(1) Moving along x-direction with frequency 106 Hz and wavelength 100 m (2) Moving along x-direction with frequency 106 Hz and wavelength 200 m (3) Moving along –x-direction with frequency 106 Hz and wavelength 200 m (4) Moving along y-direction with frequency 2 × 106 Hz and wavelength 200 m Sol. Answer (2) Ex = 0 2.5 y N E C as
2 10 –6t 10–2x
Ez = 0 6 6 –1 2 10 10 s 2 2 w f –2 2 2 200 m 10 .12. The velocity of electromagnetic radiation in a medium of permittivity 0 and permeability 0 is given by [AIPMT (Prelims)-2008] (1) 0 0 (2) 0 0 (3) 0 0 (4) 0 0 1 Sol. Answer (4) 0 0 1 C
13. The electric and magnetic field of an electromagnetic wave are [AIPMT (Prelims)-2007] (1) In opposite phase and perpendicular to each other (2) In opposite phase and parallel to each other (3) In phase and perpendicular to each other (4) In phase and parallel to each other
Sol. Answer (3)
14. If v, x and m represent the wavelengths of visible light, X-rays and microwaves respectively, then :
[AIPMT (Prelims)-2005] (1) m > x > v (2) v > m > x (3) m > v > x (4) v > x > m
15. For a medium with permittivity and permeability , the velocity of light is given by (1) (2) (3) 1 (4) Sol. Answer (3)
Speed of light in vacuum
0 0
1 C
in any other medium, V 1
16. Which of the following electromagnetic radiations have the smallest wavelength?
(1) X-rays (2) -rays (3) UV waves (4) Microwaves
Sol. Answer (2)
-rays minimum wavelength.
17. If 0 and 0 are the electric permittivity and magnetic permeability in a free space, and are the corresponding quantities in medium, the index of refraction of the medium is
(1) 00 (2) 0 0 (3) 0 0 (4) 0 Sol. Answer (2) Refractive index = C V V 1 0 0 1 C 0 0
18. What is the cause of “Greenhouse effect”?
(1) Infra-red rays (2) Ultraviolet rays (3) X-rays (4) Radiowaves Sol. Answer (1)
Green house effect is mainly due to the infrared radiation, methane gas, SO2 etc. 19. The velocity of electromagnetic wave is parallel to
(1) BE (2) EB (3) E (4) B
Sol. Answer (2)
E B Direction of wave propagation perpendicular to the plane of E and B.
SECTION - D
Assertion-Reason Type Questions
1. A : Different electromagnetic waves differ considerably in their mode of interaction with matter. R : Different electromagnetic waves have different wavelength or frequency.
Sol. Answer (1)
2. A : All electromagnetic waves travel through vacuum with same speed but they have different wavelength or frequency.
R : The wavelength of the electromagnetic waves is often correlated with the characteristic size of the system that produces and radiates them.
Sol. Answer (1)
3. A : High frequency electromagnetic waves are detected by some means based on the physical effects they produce on interacting with matter.
R : The oscillating fields of an electromagnetic wave can accelerate charges and can produce oscillating currents therefore, an apparatus designed to detect EM waves is based on this fact.
Sol. Answer (1)
4. A : Infrared waves are often called heat waves.
R : Infrared waves vibrate not only the electrons, but entire atoms or molecules of a substance which increases the internal energy and temperature of the substance.
Sol. Answer (1)
5. A : The centre of sensitivity of our eyes coincides with the centre of the wavelength distribution of the sun. R : Humans have evolved with visions most sensitive to the strongest wavelength from the sun.
Sol. Answer (1)
6. A : Long distance radio broadcasts use short-wave bands. R : Ionosphere reflectes waves in these bands.
Sol. Answer (1)
7. A : It is necessary to use satellites for long distance TV transmission.
R : Television signals are not properly relfected by the ionosphere therefore, relfection is effected by satellites. Sol. Answer (1)
8. A : Optical and radiotelescopes are built on the ground but X-ray astronomy is possible only from satellites orbiting the earth.
R : Atmosphere absorbs X-rays, while visible and radiowaves can penetrate it. Sol. Answer (1)
9. A : If the earth did not have an atmosphere, its average surface temperature would have been lower. R : In the absence of atmosphere, the green house effect will be absent.
10. A : It has been predicted that a global nuclear war on the earth would be followed by a severe 'nuclear winter' with a devastating effect on life on earth.
R : The clouds produced by global nuclear war would perhaps cover substantial parts of the sky preventing solar light from reaching many parts of the globe causing winter.
Sol. Answer (1)
11. A : In an EM wave the magnitude of the electric field vector is more than the magnitude of the magnetic field vector.
R : Energy of the EM wave is shared equally between the electric and magnetic fields. Sol. Answer (2)
12. A : The displacement current goes through the gap between the plates of a capacitor when the charge on the capacitor does not change.
R : Displacement current arises only when the electric field is constant. Sol. Answer (4)
13. A : When the frequency of the AC is increased, the displacement current increases. R : The sum of the conduction current and displacement current is constant. Sol. Answer (3)
14. A : When cooking in microwave ovens, metal containers are used.
R : Energy of the microwaves can be easily transferred to the food thorugh metal. Sol. Answer (4)
15. A : Food is cooked faster by microwaves than by conventional gas burner. R : Microwaves have more energy than heat waves.
Sol. Answer (3)
16. A : Microwaves are commonly used in radar to locate flying objects. R : Microwaves have smaller wavelength than radiowaves.
Sol. Answer (1)
17. A : Environmental damage has depleted the ozone layer in the atmosphere. R : Increase in ozone decreases the amount of UV radiation to earth. Sol. Answer (2)
18. A : The electrical conductivity of the earth's atmosphere does not change with altitude. R : Cosmic rays from outer space entering the earth's atmosphere do not affect it. Sol. Answer (4)
19. A : Static crashes are heard on a radio when a lightening flash occurs. R : Light and radiowaves are EM waves and they interfere.
Sol. Answer (1)
20. A : TV signals are affected if a low flying aircraft passes by or a petrol vehicle is started next to it. R : Aircarft signals or vehicle's spark plug generate interfering EM waves.
21. A : Light waves can be polarised.
R : All electromagnetic waves move with same speed in vacuum. Sol. Answer (2)
22. A : In an electromagnetic wave the energy density in electric field is equal to energy density in magnetic field. R : Electromagnetic waves are transverse in nature.
Sol. Answer (2)
23. A : The Poynting vector given as
0 E B S
represents the instantaneous intensity at a point.
R : The velocity of an electromagnetic wave is in the direction of the vector EB. Sol. Answer (2)
24. A : The radiation pressure due to light waves is maximum when the surface is a perfect reflector. R : The momentum transfer by the photons to a perfectly reflecting surface is maximum.
Sol. Answer (1)
25. A : In a material medium the speed of a particle can be more than the speed of light in that medium.
R : In the phenomenon of green house effect, low wavelength radiation is allowed to pass but high wavelength radiation is not allowed to pass.
Sol. Answer (2)