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Answers to Exercises
24. 25. 26. 27. true28. False. This statement is true only for a right prism.
29. true 30. true
31. False. It is a sector of a circle. 32. true 33. false; counterexample: 34. true 35. true 2x x 2x x
CHAPTER 10 • CHAPTER CHAPTER 10 • CHAPTER
LESSON 10.1 1. polyhedron; polygonal; triangles 2. PQR, TUS 3. PQUT, QRSU, RPTS 4. QU, PT, RS 5. 6 cm 6. GYPTAN 7. point E 8. GE, YE, PE, TE, AE, NE 9. 13 cm 10. D 11. L 12. C 13. G 14. B 15. H 16. E 17. A 18. J 19. J 20. M 21. H 22. I 23.
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Triangular Rectangular Pentagonal Hexagonal n-gonal
prism prism prism prism prism
Lateral 3 4 5 6 . . . n faces Total 5 6 7 8 . . . n 2 faces Edges 9 12 15 18 . . . 3n Vertices 6 8 10 12 . . . 2n 36. (Lesson 10.1) 36. See table below.
Possible answers include that the number of lateral faces of an antiprism is always twice the number for the related prism; that the number of vertices is the same for each related prism and antiprism; and that the number of edges for a prism is three times the number of faces, while for an antiprism, the number of edges is twice the number of faces. 37. Answer should include the idea that the painting “disappears” into the view out the window. Students might also note the effect created by the cone-shaped tower appearing similar to the road disappearing into the distance.
38. 8 39. 60 40. 30 41a. yes 41b. yes 41c. no 41d. yes ⫻ ⫻ ␣ ␣
Triangular Rectangular Pentagonal Hexagonal n-gonal
antiprism antiprism antiprism antiprism antiprism
Lateral 6 8 10 12 . . . 2n faces Total 8 10 12 14 . . . 2n 2 faces Edges 12 16 20 24 . . . 4n Vertices 6 8 10 12 . . . 2n
LESSON 10.2
1. 72 cm3 2. 24 cm3 3. 108 cm3
4. 160 cm3 502.65 cm3
5. 36 cm3 113.10 cm3
6. 324 cm3 1017.88 cm3
7. See table below.
8. 960 in3 9. QT cubic units
10. sample answer:
11. 2x3 12. 3r3 13. 13x3
14. Margaretta has room for 0.5625 cord. She should order a half cord.
15. 170 yd3 16. 5100 lb 17. 11,140
18. The volume of the quilt in 1996 was 4000 ft3.
The quilt panels were stacked 2 ft 8 in. high. 19. 2 12 12 12 8 3 Q T 24 in. 8 in. 12 in. 4 in. 20. 21. true 22. false 23.
24. possible solution: prism
25. approximately 1.89 m 26. 12 62 Salt crystal r r r
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Information about Height Right triangular Right rectangular Right trapezoidal Right
base of solid of solid prism prism prism cylinder
b 6, b2 7, H 20 a. V d. V g. V j. V h 8, r 3 480 cm3 960 cm3 1040 cm3 180 cm3 b 9, b2 12, H 20 b. V e. V h. V k. V h 12, r 6 1080 cm3 2160 cm3 2520 cm3 720 cm3 b 8, b2 19, H 23 c. V f. V i. V l. V h 18, r 8 1656 cm3 3312 cm3 5589 cm3 1472 cm3 H r b b 2 H h H b h h b H 7. (Lesson 10.2)
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LESSON 10.3 1. 192 cm3 2. 84 cm3 263.9 cm3 3. 150 cm3 4. 60 cm3 5. 84 cm3 263.9 cm3 6. 384 cm3 1206 cm3 7. m3 cm3 3 8. 23 b3cm3 9. 324x3cm3; 29.6%10. See table below. 11. V 31M2H ft3
12. sample answer:
13. Mount Etna is larger. The volume for Mount Etna is approximately 2193 km3, and the volume
for Mount Fuji is approximately 169 km3.
48 3 27 16 H M M
Information about Height Triangular Rectangular Trapezoidal
base of solid of solid pyramid pyramid pyramid Cone
b 6, b2 7, H 20 a. V d. V g. V j. V h 6, r 3 b 9, b2 22, H 20 b. V e. V h. V k. V h 8, r 6 b 13, b2 29, H 24 c. V f. V i. V l. V h 17, r 8 H r b 2 b h H H b h h H b 120 cm3 240 cm3 884 cm3 240 cm3 480 cm3 1768 cm3 260 cm3 2856 cm3 60 cm3 240 cm3 512 cm3 24380cm3 14. 78,375 grams 15. 48 in3 16. 4 units3 17. 144x3cm3 18. 40,200 gal; 44 h 40 min 19. 71 ft3 20. 403 barrels 21a. 163cm2 21b. 96 cm2 21c. 803cm2 21d. 2413 120 cm2 22.
Possible answer: From the properties of reflection, 1 3 and 2 4. m1 m2 90°, so m3 m4 90°, and m1 m2 m3 m4 180°. Therefore D, C, and D are collinear. 23a. Y (a c, d) 23b. Y (a c, b d) 23c. Y (a c e, b d f ) D' D'' C B A D 3 1 2 4 10. (Lesson 10.3)
LESSON 10.4 1. 58.5 in3 2. 323 cm3 55.43cm3 3. 15 cm 4. 11 cm 5. 5.0 cm 6. 8.25in.2
11 in. 63.24 in3; 112in.2
8.5 in. 81.85 in3
The short, fat cylinder has greater volume. 7. 257 ft3
8. 4 cm
9. He must refute the statement. 10. 1502 lb
11. 192.4 gal 12. 13 min
13. Answers will vary, but r2H should equal
about 14.4 in3.
14. approximately 38 in3
15. 100,000 m3, or about 314,159 m3;
16,528 loads
16. AB EC because the opposite sides of a parallelogram are congruent. EC BD because the diagonals of a rectangle are congruent. So, AB BD because both are congruent to EC. Therefore,ABD is isosceles.
17. 8.2 cm 18. x 96° 19. 20. 21a. A 21b. S 21c. N 21d. S 21e. A x x x x x x A B C D 45° 45° 45° 45° 3x
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LESSON 10.5 1. 675 cm3 2. 36 cm3 113.1cm3 3. 47 in3 4. 1798.4 g5. The gold has mass 2728.5 g, and the platinum has mass 7529.8 g. The solid cone of platinum has more mass.
6. 1.5 cm
7. 10.5 g/cm3; silver
8. 8000 cm3
9. The volume of the medallion is 160 cm3. Yes, it
is gold, and the Colonel is who he says he is. 10. 679 cm3 11. approximately 193 lb; 22 fish 12. 293 13. flowchart proof: 14. 15 sides 15a. (1, 3) 15b. (x 1)2 (y 3)2 25 16. 58; 3n 2 QR SP MQ MP Given AIA ASA RMQ SMP CPCTC R S Vertical Angles QMR PMS SM MR Given M is the midpoint of PQ Definition of midpoint
LESSON 10.6 1. 36 cm3 113.1 cm3 2. 6cm3 0.533 cm3 3. 932 cm3 0.884 cm3 4. 720 cm3 2262 cm3 5. 30 cm3 94.3 cm3 6. 3456 cm3 10,857 cm3 7. 18 m3 56.6 cm3
8. No. The volume of the ice cream is 85.3 cm3,
and the volume of the cone is 64 cm3.
9. only 20 scoops
10. 1438 m 3, or about 155 m3
11. They have the same volume. 12. 9 in.
13. 3 cm
14. 8193 cm2 3 8579 cm3
15. 18 in3, or about 57 in3
16. No. The unused volume is 16 cm3, and the
volume of the golf ball is 10.6 cm3.
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17. approximately 15,704 gallons; 53 days 18. lithium
19. 31 ft
20. ABCD is a parallelogram because the slopes of CD and AB are both 0 and the slopes of BC and AD are both 53.
21. They trace two similar shapes, except that the one traced by C is smaller by a scale factor of 1: 2. 22. The line traces an infinite hourglass shape. Or, it traces the region between the two branches of a hyperbola. 23. w 110°, x 115°, y 80° y x D (9, 5) C (3, 5) A (3, –5) B (–3, –5)
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LESSON 10.7 1. V 972 cm3 3054 cm3 S 324 cm2 1018 cm2 2. V 0.972 cm3 3.054 cm3 S 3.24 cm2 10.18 cm2 3. V 1152 cm3 3619 cm3 S 432 cm2 1357 cm2 4. S 160 cm2 502.7 cm2 5. V 2536 cm 3 268.1 cm3 6. S 144 cm2 452.4 cm27. Area of great circle r2. Total surface area
of hemisphere 3r2. Total surface area of
hemisphere is three times that of area of great circle. 8. 2 gal 9. V12
43(1.8)312(1.8)2(4.0) 10.368 m3 32.57 m3; S1 2
4(1.8)2 12
2(1.8)(4.0) 13.68 m2 42.98 m2 10a. approximately 3082 ft2 10b. 13 gal 10c. approximately 9568 bushels 11. 153,200,000 km2
12. The total cost is $131.95. He will stay under budget. 13. 1.13% 14. 150 cm3 471.2 cm3 15. 14 16. 12 17. 34
18. The ratio gets closer to 1. 19a and 19b. See tables below.
20. AB CB and AD CD by the definition of rhombus, and BD BD because it is the same segment; therefore ABD CBD by SSS. By CPCTC,2 3 and 1 4, which shows that BD bisects both ABC and ADC. Because all four sides of the rhombus are congruent, a similar proof can be used to show that ABC ADC and thus that A and C are both bisected by diagonal AC.
21a. AB CB by the definition of rhombus and BE BE because it is the same segment. 1 2 by the Rhombus Angles Conjecture. Therefore, AEB CEB by SAS.
21b. AE CE by CPCTC, so BD bisects AC. 21c. 3 4 by CPCTC.Also, 3 and 4 form a linear pair, so they are supplementary. Because two angles that are congruent and supplementary are right angles,3 and 4 are right angles. 21d. Because 3 and 4 are right angles, the diagonals are perpendicular. You still need to show that AC bisects BD. Use a proof similar to that given in 21a to show that AEB AED. Then, by CPCTC, BE DE, which shows that AC bisects BD. n 1 2 3 4 5 6 . . . n . . . 200 f(n) 2 1 4 7 10 13 . . . 3n5 . . . 595 n 1 2 3 4 5 6 . . . n . . . 200 f(n) 0 1 3 12 35 23 57 . . . n n 1 1 . . . 210991 19a. (Lesson 10.7) 19b. (Lesson 10.7)
USING YOUR ALGEBRA SKILLS 10 1. h Ab 2. b P2 or b P2h 2 h 3. r
3VH 4. bc2 a2 5. a 2• P SA l 6. y2 mx2 x1 y1or y2 mx2 mx1 y1 7. v dt
The original formula gives distance in terms of velocity and time.
8. F 9C 32 5
The original formula converts degrees Fahrenheit to degrees Celsius.
9. L g
T22
The original formula gives the period of a pendulum (time of one complete swing) in terms of length and acceleration due to gravity.
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10a. V F E 2 10b. See table below.11a. The corresponding radii are approximately 3.63 cm, 3.30 cm, 3.02 cm, and 2.79 cm.
11b. The corresponding heights are approximately 9.32 cm,10.49 cm,11.61 cm,and 12.70 cm.
11c. The corresponding volumes are approximately 129 cm3, 120 cm3, 111 cm3, and 104 cm3.
11d. Answers will vary. Sample answer: The cone with slant height 10 cm has the widest radius, so a scoop of ice cream is least likely to fall off, and that cone also has the greatest volume.
11e. Answers will vary. Sample answer: The cone with slant height 13 cm has the greatest height, so the cone appears bigger even though it has the same surface area as the other cones; that cone also has the smallest radius and smallest volume, so it could hold less ice cream and still appear to be a bigger cone.
12a. A
12b. average of 60: 31; average of 70: 56; average of 80: 81; average of 90: 106 (impossible)
m1 m2 m3 f f
5
Pentahedron Hexahedron Octahedron Decahedron Dodecahedron
Number of faces
Number of edges 8 10 12 16 20
Number of vertices
5 6 8 10 12
5 6 6 8 10
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CHAPTER 10 REVIEW1. They have the same formula for volume: V BH. 2. They have the same formula for volume: V13BH. 3. 6240 cm3 4. 1029 cm3 3233 cm3 5. 1200 cm3 6. 32 cm3 7. 100 cm3 314.2 cm3 8. 2250 cm3 7069 cm3 9. H 12.8 cm 10. h 7 cm 11. r 12 cm 12. r 8 cm 13. 960 cm3 14. 9 m 15. 851 cm3
16. four times as great 17a. Vextra large 54 in3
Vjumbo 201.1 in3
Vcolossal 785.4 in3
17b. 14.5 times as great
18. Cylinder B weighs 83times as much as cylinder A. 19. 2129 kg; 9 loads 20. H2r.V V sp b h o e x re 0.524. Thus, 52.4% of the box is filled by the ball.
21. approximately 358 yd3
22. No. The unused volume is 98 in3, and the
volume of the meatballs is 32 in3.
23. platinum
24. No. The ball weighs 253 lb. 25. 256 lb 26. approximately 3 in. 27.
8 m3 0.23 m3 28. 160 cubic units 33 32 4 3r3 (2r)3