R E S E A R C H
Open Access
A global result for discrete
φ
-Laplacian
eigenvalue problems
Dingyong Bai
**Correspondence:
[email protected] School of Mathematics and Information Science, Key Laboratory of Mathematics and
Interdisciplinary Sciences of Guangdong Higher Education Institutes, Guangzhou University, Guangzhou, 510006, P.R. China
Abstract
Concerned is the existence, nonexistence and multiplicity of positive solutions for discrete
φ
-Laplacian eigenvalue problems. By using lower and upper solutions method and fixed point index theory, a global result with respect to parameter is established.Keywords: discrete
φ
-Laplacian eigenvalue problem; positive solution; the lower and upper solutions method; fixed point index theory1 Introduction
Fora,b∈Zwitha<b, let [a,b]Z={a,a+ ,a+ , . . . ,b– ,b}. In this paper, we consider
the following discreteφ-Laplacian eigenvalue problem
(φ(u(k– ))) +λp(k)g(u(k)) = , k∈[,T]Z,
u() =u(T+ ) = , ()
whereT> is a given positive integer,u(k) =u(k+ ) –u(k),λis a positive parameter,
p: [,T]Z→(,∞) andg:R+→(,∞) is continuous. We assume that
(A) φ:R→Ris an odd and strictly increasing homeomorphism; (A) limu→∞φg(u)(u)=∞.
The functionφ(u) covers two important cases:φ(u) =uandφ(u) =|u|p–u(p> ). If
φ(u) =u, then problem () is the classical second order difference Dirichlet boundary value problem. For the case thatφ(u) =|u|p–u, problem () is the well-known discrete
p-Laplacian problem. The two cases have been widely studied. To name a few, see [–] and the references therein.
Problem () can be viewed as the discrete analogue of the following differential φ -Laplacian problem
(φ(u))+λp(t)g(u(t)) = , <t< ,
u() =u() = , ()
which rises from the study of radial solutions forp-Laplacian equations (φ(u) =|u|p–u) on an annular domain (see [], and references therein). Recently, the differentialφ-Laplacian problems have been widely studied in many different papers. We refer the readers to [– ] and the references therein.
For discrete φ-Laplacian problems, there are less study results than differential φ -Laplacian problems. See Cabada [], Cabada and Espinar [] and Bondar []. In [, ], some existence results were established by the upper and lower solutions method. In [], the existence and uniqueness of solutions were discussed for mixed and Dirichlet boundary value problems by the fixed point theory of contraction mapping. To the best of our knowledge, there are no results on the existence and multiplicity of positive solutions for differenceφ-Laplacian problems. Therefore, the purpose of this paper is to establish a global result of positive solutions of (). We state our main result as follows.
Theorem . Let(A)and(A)hold.Then there existsλ∗> such that problem()has at least two positive solutions forλ∈(,λ∗),at least one positive solution forλ=λ∗and no solution forλ>λ∗.
The result is motivated mainly by the ideas in [, ], in which some global results of positive solutions were established for boundary value problems ofp-Laplacian differen-tial systems andφ-Laplacian differential systems, respectively.
Generally, in order to make priori estimations on possible positive solutions of φ -Laplacian problems, the functionφ satisfies not only condition (A), but also other ad-ditional conditions. For example, Wang [] used the following condition.
(A∗) There exist two increasing homeomorphismsψ,ψ: (,∞)→(,∞)such that for
allxandy> ,
ψ(x)φ(y)≤φ(xy)≤ψ(x)φ(y).
In [], a more general condition was given.
(A∗∗) Forσ> , there exists a constantCσ> such that for alls∈R, φφ(σ(s)s)<Cσ.
In our discussion for the single discrete problem (), we only assume thatφ satisfies condition (A). In addition, in the discussion of nonlinear differential systems in [, ], monotonicity conditions were imposed on nonlinear terms. In this papergdoes not have to satisfy monotonicity conditions.
The remaining part of this paper is organized as follows. In Section , we show some lemmas for the later use. In Section , we show the proof of Theorem .. Our proofs are mainly based on the upper and lower solutions technique arguments and the fixed-point index theory for cones.
2 Some lemmas
First, we introduce an existence result of solutions based on lower and upper solutions method for discrete φ-Laplacian boundary value problems, which has been proved by Cabada [].
Consider the following boundary value problem
(φ(u(k– ))) +f(k,u(k)) = , k∈[,T]Z,
u() =u(T+ ) = , ()
(B) φ:R→Ris an odd and strictly increasing function; (B) f: [,T]Z×R→Ris continuous.
LetE={u: [,T+ ]Z→RT+}with the normu=maxt∈[,T+]Z|u(t)|. Givenu,v∈E, we say thatu≤vifu(k)≤v(k) holds for allk∈[,T+ ]Z.
Definition . α∈Eis called a lower solution of problem () if
(φ(α(k– ))) +f(k,α(k))≥, k∈[,T]Z,
α()≤, α(T+ )≤.
In a same way, we define the upper solution of () by reversing the above inequalities.
Lemma .[] Let(B)and(B)hold.Assume that there existαandβ,respectively lower and upper solutions of()such thatα≤β.Then problem()has at least one solution u withα≤u≤β.
A functionuof integer variable is said to be concave ifu(k– )≤. This is the same as saying that the first differenceu(k– ) is non-increasing. Ifu(k– ) < , thenuis said to be strictly concave.
Lemma . Let u(k)be concave on[, +T]Z,and u()≥,u(T+ )≥.Then:
(i) u(k)≥for allk∈[,T]Z,andu(k– )≥fork∈[,k∗]Z,u(k)≤for
k∈[k∗,T]Z,wherek∗∈[, +T]Zsatisfiesu(k∗) =maxk∈[,+T]Zu(k).
(ii) For eachk∈[,T+ – ]Z(T+ denotes the integer part of T+ ),
u(k)≥ k
T+ u, u∈[k, +T–k]Z. Specially,u(k)≥
T+u,u∈[,T]Z.
Proof (i) Ifk∗= orT+ , the result is clear. Now we assume thatk∗∈[,T]Z. Since
uk∗– =uk∗–uk∗– ≥, uk∗=uk∗+ –uk∗≤.
We have by the monotonicity ofu(·) thatu(k– )≥ fork∈[,k∗]Z,u(k)≤ fork∈
[k∗,T]Z, which implies thatu(k)≥ holds for allk∈[,T]Zby the boundary conditions
u()≥,u(T+ )≥.
(ii) Fora,b∈Rwitha<b, let [a,b]Rand (a,b)Rdenote the closed and open interval on
R, respectively. For any givenk∈[,T+ ]Z, define
˜
u(t) =u(k) –u(k– )(t–k) +u(k), t∈[k– ,k]R.
Clearly,u˜(k) =u(k) fork∈[,T+ ]Zandu˜(t) is continuous concave on [,T + ]R. Let
· C[,T+]R denote the super norm in the spaceC[,T+ ]R. It is easy to see thatu=
uC[,T+]R. By the concavity ofu˜(t) on [,T+ ]R, we have that for anyδ∈(, T+
)R, ˜
u(t)≥ δ
T+ uC[,T+]R, t∈[δ,T+ –δ]R.
Remark Ifu(k) is strictly concave on [, +T]Z, andu()≥,u(T+ )≥. Thenu(k) >
fork∈[,T]Z, and there existsk∗∈[, +T]Z such thatu(k∗) =u,u(k– ) > for
k∈[,k∗– ]Z,u(k∗– )≥, andu(k) < fork∈[k∗,T]Z.
Lemma . Let(B)hold and u satisfy the following difference inequality
–φu(k– )≥, k∈[,T]Z, ()
Lemmas . and . yield the following result.
Lemma . Let(B)hold.Then each solution u of()is strictly concave and u(k) > for all k∈[,T]Z.
Consider the following boundary value problem
(φ(u(k– ))) +h(k) = , k∈[,T]Z,
u() =u(T+ ) = , ()
whereh(k) > for allk∈[,T]Zandφ satisfies (A). It is easy to check thatu∈E is a
solution of () if and only if
u(k) =
Sinceφ–is a homeomorphism fromRonto itself, the solutionC
of () is unique. Let
Then () can be rewritten as follows
whereCsatisfiesu() = ,i.e.,
By Lemmas . and ., the following result holds.
Lemma . Let(A)hold.Assume that u solves()andu=u(k∗).Then
whereCis the unique solution of the following equation
T+
Proof Suppose that the conclusion is not true. Then there exists a sequence{λn} ⊂ and
uncorresponding positive solutions of () atλnsuch thatun → ∞asn→ ∞. Letλ= holds fornsufficiently large. It follows that
Letun=un(k∗). Ifk∗> , then by Lemma ., we have a contradiction that
Let={λ∈(,∞) : the problem () has at least one positive solution atλ}.
Lemma . Let(A)and(A)hold.Thenis bounded.
Proof Suppose, on the contrary, that there exists a sequence{λn} ⊂andun correspond-ing positive solutions of () atλnsuch thatλn→ ∞asn→ ∞. By (A), there exists> such that for allu≥,g(u)≥φ(u). Sinceλn→ ∞asn→ ∞, there existsδ> satisfy-ingδp> such thatλn>δholds fornsufficiently large. Letun=un(k∗). Similar to the arguments in the proof of Lemma ., ifk∗> , we have the following contradiction
un() >φ–δpφun()>un(),
and ifk∗= , we also have a contradiction that
un(T) >φ–δpφun(T)>un(T).
Lemma . Let(A)and(A)hold.Then there existsλ∗> such that= (,λ∗].
Proof By Lemmas .-.,is a nonempty bounded interval open at the left with the left endpoint /∈. We only need to show that it is closed at the right. Letsup=λ∗. Then there exists a sequence{λn} ⊂satisfyingλn<λn+such thatλn→λ∗asn→ ∞. Since {λn}is bounded, Lemma . implies that there exists a constantℵsuch that for allnand all possible positive solutionsunof () atλn,un ≤ ℵ. It follows that{un}has a convergent subsequence, say again{un}, which converges tou∗. Since (λn,un) solves problem (), we know that
(φ(un(k– ))) +λnp(k)g(un(k)) = , k∈[,T]Z,
un() =un(T+ ) = .
Letn→ ∞, we have by the continuity ofgas well asφthat
(φ(u∗(k– ))) +λ∗p(k)g(u∗(k)) = , k∈[,T]Z,
u∗() =u∗(T+ ) = ,
which implies that (λ∗,u∗) solves problem (). By Lemma .,u∗is positive on [,T]Zand
λ∗∈. The proof is completed.
In the succeeding arguments, we need the following well-known fixed point index the-orem on cones. For proof and details, see Guo [].
Lemma . Let E be a Banach space,let P be a cone in E,and letbe a bounded open set in E with∈.Let T:P∩ ¯→P be a complete continuous operator satisfying that
Tx=μx, x∈P∩∂⇒μ< .
3 The proof of Theorem 1.1
By Lemma ., there existsλ∗> such that problem () has at least one positive solution forλ∈(,λ∗], and no solution forλ>λ∗. So we only need to show the existence of the
and () implies that
φu(k– )
= –λp(k)g∗u(k)≥–λp(k)gu∗(k)
>φu∗(k– )
,
which contradicts (). Thus, ifuis a solution of (), thenu∈. DefineTλ∗the same asTλ
replacinggbyg∗. ThenTλ∗:K→Kis continuous. Sinceg∗is bounded, there existsR> such thatTλ∗u<Rfor allu∈K. Thus, we can chooseRsufficiently large such thatR>R and⊂BR. HereBR={u∈E:u<R}. Then by Lemma ., we havei(Tλ∗,BR∩K,K) = . Since all positive fixed points ofTλ∗are contained in, andTλu=uis equivalent toTλ∗u=u
on∩K, one has
i(Tλ,∩K,K) =i
Tλ∗,∩K,K
=iTλ∗,BR∩K,K
= . ()
By Lemma ., there existsλ¯ >λ∗ such that problem () has no positive solution atλ¯. Thus, for any open setUinE,
i(Tλ¯,U∩K,K) = . ()
Take=λp, wherep=mink∈[,T]Zp(k). By (A), there existsL> such thatg(u) >φ(u)
foru>L. Letbe a compact set of (,∞) containingλandλ¯. Then by Lemma ., we can chooseb> sufficiently large such that all possible solutionsuof () at anyλ˜∈
satisfyu<band thatb> (T+ )Land⊂Bb. HereBb={u∈E:u<b}. Define h: [, ]×(B¯b∩K)→Kby
h(t,u) =Tτλ¯+(–τ)λ(u).
It is easy to see thathis continuous on [, ]×K, h(,u) =Tλuandh(,u) =T¯λu. We
need to prove thath(τ,u)=ufor all (τ,u)∈[, ]×(∂B¯b∩K). Assume that there exists
(τ,u)∈[, ]×(∂B¯b∩K) such that
u(k) = k
s=
φ–
C(h)+τλ¯+ ( –τ)λ
T
l=s
p(l)gu(l)
, k∈[,T+ ]Z,
whereC(h)satisfiesu(T+ ) = . Then by Lemma .,u(k)≥T+ u>Lfork∈[,T]Z. Let
u=u(k∗). Similar to the proof of Lemma ., ifk∗> , then one can get a contradiction that
u() >φ–τλ¯+ ( –τ)λpφu()>u().
Ifk∗= , one can also have a contradiction. Therefore,h(τ,u)=ufor all (τ,u)∈[, ]× (∂B¯b ∩K) andi(h(τ,·),Bb∩K,K) is well defined. Thus, by the property of homotopy
invariance and (),
Then by the additive property, we have from () and (),
iTλ, (Bb\ ¯)∩K,K
= –.
Therefore, problem () has one positive solution in∩K and another in (Bb\ ¯)∩K.
The proof is completed.
Competing interests
The author declares that he has no competing interests.
Author’s contributions
The author worked on the results independently.
Acknowledgements
The author is very grateful to the referees for their helpful comments. This research is supported partially by the Research Funds for the Doctoral Program of Higher Education of China (No. 20104410120001, 20114410110002), PCSIRT of China (No. IRT1226) and the Natural Science Fund of China (No. 11171078).
Received: 11 June 2013 Accepted: 15 August 2013 Published: 29 August 2013 References
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doi:10.1186/1687-1847-2013-264