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R E S E A R C H

Open Access

Properties of solutions for a

reaction–diffusion equation with nonlinear

absorption and nonlinear nonlocal Neumann

boundary condition

Jian Wang

1*

and Hui Yang

1

*Correspondence:

[email protected]

1School of Mathematical Sciences,

Ocean University of China, Qingdao, P.R. China

Abstract

In this paper, the authors consider the reaction–diffusion equation with nonlinear absorption and nonlinear nonlocal Neumann boundary condition. They prove that the solution either exists globally or blows up in finite time depending on the initial data, the weighting function on the border, and nonlinear indexes in the equation by using the comparison principle.

Keywords: Reaction-diffusion equation; Global existence; Nonlinear absorption; Blow-up; Neumann boundary condition

1 Introduction

In this paper, we consider the initial boundary value problem for the following nonlocal reaction–diffusion equation with nonlinear absorption:

ut=u+aup

uq(y,t)dybum, x, 0 <t<T, (1.1)

∂u ∂ν =

k(x,y)ul(y,t)dy, x, 0 <t<T, (1.2)

u(x, 0) =u0(x), x, (1.3)

wherep,q,m,l> 0,is a bounded domain inRn(n1) with smooth boundary,νis

unit outward normal on. Herea,bare positive constants,k(x,y) is a positive continu-ous bounded function defined forx,y. Furthermore, we assume thatu0(x)≥0

and satisfies the compatibility conditions

∂u0

∂ν =

k(x,y)ul

0(y,t)dy, x.

It is found that lots of physical phenomena could be formulated into nonlocal mathemat-ical models and studied by many authors (see [1–5] and the related references). Problem (1.1)–(1.3) can be used to describe, for example, heat conduction in solid media with non-linear absorption terms and nonnon-linear boundary currents. In the last few decades, there

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has been a large amount of literature devoted to the study of properties of solutions to reaction–diffusion equation with nonlocal source with homogeneous Dirichlet boundary conditions or with nonlinear boundary conditions (see [6–9] and the related references). In particular, the following nonlocal reaction–diffusion equation with nonlinear absorp-tion

ut=u+

updxcuq, x,t> 0, (1.4)

u(x,t) =

f(x,y)ul(y,t)dy, x,t> 0, (1.5)

u(x, 0) =u0(x), x, (1.6)

was studied by Mu in [10]. They discussed that the weighting function on the border and nonlinear index influenced global and non-global existence of solutions. The con-ditions on the existence and nonexistence of global positive solutions are given and the uniform blow-up estimates for the blow-up solution are established. They focus on the reaction–diffusion equation with nonlocal source, nonlinear absorption, and nonlocal Dirichlet boundary condition; however, the authors did not give any result about equa-tion (1.4) with nonlinear nonlocal Neumann boundary condition. The nonlinear nonlocal Neumann boundary condition can be considered as some cross boundary flow. Thus, this paper will extend the above work to the reaction–diffusion equation (1.1) with nonlinear nonlocal Neumann boundary condition and obtain the corresponding results.

In addition, in [11] Zhou and Yang considered the local reaction–diffusion equation with the weighted coefficient

ut=u+c(x,t)up

uq(y,t)dy, x,t> 0, (1.7)

∂u ∂ν =

k(x,y)ul(y,t)dy, x, 0 <t<T, (1.8)

u(x, 0) =u0(x), x. (1.9)

The authors discussed the effect of the behavior for the weighted function on the prop-erties of the solution and obtained thatp+q≤1,l≤1, then the solutions exist globally for any nonnegative initial data. They found thatp+q< 1,l> 1, then the solutions exist globally for small initial data. They proved thatp+q> 1,l> 0, then the solutions blow up in finite time for any positive initial data. They also assumed thatmin{p,q}> 1,l> 0, then the solutions blow up in finite time for large initial data. This paper just studied the reaction–diffusion equation with nonlocal source and Neumann boundary condition, but they did not consider the equation with nonlinear absorption. We will show that the ef-fect of the nonlinear absorption of (1.1) plays a substantial role in determining whether a solution blows up or not.

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and nonlocal nonlinear Neumann boundary, which are not only different from the situ-ations with the Dirichlet boundary condition, but also different from the situsitu-ations with problem (1.7)–(1.9) without absorption term. We will show that the nonlinear absorption and the nonlinear termul(y,t) in the boundary condition of (1.1) play substantial roles in determining whether a solution blows up or not. In fact, we will prove that ifp+q<m,

l≤1, the solution exists globally for anyk(x,y) and any nonnegative initial data. We notice that ifp+q>m> 1,l> 0, a blow-up occurs in finite time if the initial datau0(x) satisfies

u0(x)ϕ(x)dx> 1. We also find that ifp+q=m> 1, then problem (1.1)–(1.3) has blow-up

solutions in finite time as well as global solutions.

Because we will study the nonlocal reaction–diffusion equation with nonlinear absorp-tion and coupled with nonlinear nonlocal Neumann boundary condiabsorp-tion, we have some new difficulties to overcome. First, we establish a complete proof for the local existence of the solution of (1.1)–(1.3) which was not proved in [10] and [11]. Second, due to the appearance of the Neumann boundary condition, some approaches used in [10] can-not be extended to handle our problem; for example, the treatment of boundary integral –u∂ϕ∂νdSduring the calculation of auxiliary functionJ(t), the selection of ODE, and the condition of auxiliary functionζ(x). Third, for problem (1.7)–(1.9), there is no global so-lution whenp+q> 1,l> 0. However, for our problem (1.1)–(1.3), ifp+q=m> 1,l≥1, a solution still may exist globally. Thus, compared with [11], we can see that the absorption plays an important role in the properties of solutions.

The structure of this paper is as follows. In Sect.2, we establish and prove the compari-son principle and local existence. In Sect.3, by using the comparison principle and super-subsolution method, we establish the conditions for blow-up in finite time and global ex-istence.

2 The comparison principle and local existence

In this section we start with the definition of supersolution and subsolution of problem (1.1)–(1.3). Then we will prove the comparison principle and give the local existence of solutions for (1.1)–(1.3).

First, for convenience, we setQT=×(0,T),ST=×(0,T), andT=ST×0,

T> 0.

Next, the definitions of supersolution, subsolution, and solution for (1.1)–(1.3) will be given.

Definition 2.1 We say that a nonnegative functionuC2,1(Q

T)∩C(QTT) is a

sub-solution of (1.1)–(1.3) if

utu+aup

uq(y,t)dybum, (x,t)∈QT, (2.1)

∂u ∂ν

k(x,y)ul(y,t)dy, (x,t)∈ST, (2.2)

u(x, 0)≤u0(x), x, (2.3)

and similarly we say that a nonnegative functionu(x,t)∈C2,1(Q

T)∩C(QTT) is a

su-persolution of (1.1)–(1.3) inQTand satisfies (2.1)–(2.3) in the reverse order. We say that

u(x,t) is a solution of problem (1.1)–(1.3) inQT, ifu(x,t) is both a subsolution and a

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The following comparison principle plays an important role in the proof of our main results.

Lemma 2.1 Let u(x,t)and u(x,t)be a subsolution and a supersolution of(1.1)(1.3)in QT,

respectively,with u(x, 0)≤u(x, 0)in.Suppose that u(x, 0) > 0or u(x, 0) > 0in QTTif

min(p,q,m,l) < 1.Then u(x,t)≤u(x,t)in QTT.

Proof Setφ(x,t)∈C2,1(Qt) (0 <t<T) is a nonnegative function which satisfies the

homo-geneous Neumann boundary condition

∂φ

∂ν = 0, x.

Multiplying (2.1) byφand integrating overQt, we obtain that the subsolutionu(x,t)

sat-isfies

u(x,t)φ(x,t)dx

u(x, 0)φ(x, 0)dx

+ t

0

u(x,τ)φτ(x,τ) +u(x,τ)φ(x,τ)

+(x,τ)up(x,τ)

uq(y,τ)dy(x,τ)um(x,τ)

dx dτ

+ t

0

φ(x,τ)

k(x,y)ul(y,τ)dy

dS dτ. (2.4)

On the other hand, the supersolutionu(x,t) satisfies

u(x,t)φ(x,t)dx

u(x, 0)φ(x, 0)dx

+ t

0

u(x,τ)φτ(x,τ) +u(x,τ)φ(x,τ)

+(x,τ)up(x,τ)

uq(y,τ)dy(x,τ)um(x,τ)

dx dτ

+ t

0

φ(x,τ)

k(x,y)ul(y,τ)dy dS dτ. (2.5)

Letω(x,t) =uu, subtracting (2.5) from (2.4) and using mean value theorem, we get

ω(x,t)φ(x,t)dx

ω(x, 0)φ(x, 0)dx

+ t

0

ω(x,τ)

φτ(x,τ) +φ(x,τ)

+apθ1p–1φ(x,τ)

uq(y,τ)dybmθ2m–1

dx dτ

+ t

0

aqupφ(x,τ)

ω(y,τ)θ3q–1(y,τ)dy dx dτ

+ t

0

(x,τ)

k(x,y)θ4l–1ω(y,τ)dy

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whereθi(x,t) (i= 1, 2, 3, 4) are some positive continuous functions betweenuanduinQt,

ifmin(p,q,l,m) < 1 and some nonnegative continuous functions inQtotherwise.

The functionφ(x,t) is defined as a solution of the following problem:

φτ(x,τ) +φ(x,τ) +apθ1p–1φ(x,τ)

uq(y,τ)dybmθ2m–1= 0, (x,τ)∈Qt, (2.7)

∂φ

∂ν = 0, (x,τ)∈St, (2.8) φ(x, 0) =μ(x), x, (2.9)

whereμ(x)∈C0∞(), 0≤μ(x)≤1. By virtue of the comparison principle, the solution

φ(x,t) is nonnegative and bounded (see [12] for example). Denote a solution of (2.7)– (2.9) asφn(x,τ). Then, by the standard theory for linear parabolic equations, we know

thatφnC2,1(Qt), 0≤φn(x,τ)≤1 inQt. Puttingφ=φnin (2.6) andω(x, 0)≤0, we get

ω(x,t)φ(x,t)dxK

t

0

ω+(x,τ)dx dτ, (2.10)

where we denoteω+=max(0,ω) and choose

K=aqsup

Qt

up(x,τ)φ(x,τ)θ3q–1(x,τ) +l|| sup ×Qt

k(x,y)sup

Qt

θ4l–1(x,τ)sup

St

φ(x,τ).

Inequality (2.10) holds for each functionμ(x),

ω(x,t)μn(x,t)dxK

t

0

ω+(x,τ)dx dτ,

so we can choose a sequenceμn(x)∈C0∞() converging inL1() to the function

μ(x) = ⎧ ⎨ ⎩

1, ω(x,t) > 0,

0, ω(x,t)≤0.

Substitutingμn(x) instead ofμ(x) in (2.10) and lettingn→ ∞, we obtain

ω(x,t)μn(x,t)dx=

ω+(x,t)dxK

t

0

ω+(x,τ)dx dτ. (2.11)

By using Gronwall’s inequality, we haveω+(x,t)≤0, which means thatu(x,t)≤u(x,t) in

QTT.

Next, we will establish the local existence of solution for (1.1)–(1.3) using representation formula and the contraction mapping argument.

Let{εm}be decreasing to 0 sequence such that 0 <εm< 1. Forε=εm, letu0ε(x) be the

functions with the following properties (the existence ofu0ε, see [13]):

u0ε(x)∈C1(), u0ε(x)≥ε, u0εi(x)≥u0εj(x), εiεj, u0ε(x)→u0(x) asε→0,

∂u0ε(x)

∂ν =

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Due to the nonlinearities in (1.1) and (1.2), the Lipschitz condition is not satisfied if

min(p,q,m,l) < 1, and thus we need to consider the auxiliary problem

ut=u+aup

uq(y,t)dybum+bεm, x, 0 <t<T, (2.12)

∂u ∂ν =

k(x,y)ul(y,t)dy, x, 0 <t<T, (2.13)

(x, 0) =u0ε(x), x, (2.14)

whereε=εm.

Theorem 2.1 For some small values of T, problem(2.12)(2.14)has a unique solution in QT.

Proof LetGN(x,y;tτ) be the Green function for the following heat equation:

utu= 0, x,t> 0,

with homogeneous Neumann boundary condition. We denote that the functionGN(x,y;

tτ) has the following properties (see [14]):

GN(x,y;tτ)≥0, x,y, 0≤τ<t<T, (2.15)

GN(x,y;tτ)dy= 1, x, 0≤τ<t<T. (2.16)

Then(x,t) is a solution of (2.12)–(2.14) inQTif and only if

(x,t) =

GN(x,y;tτ)u0ε(y)dy

+ t

0

GN(x,y;tτ)aupε

uqε(x,τ)dx dy dτ

+b

t

0

GN(x,y;tτ)

εquq(y,τ)dy dτ

+ t

0

GN(x,y;tτ)

k(ξ,y,τ)uεl(y,τ)dy dSξdτ

=Luε(x,t). (2.17)

To show that (2.17) is solvable for smallT, we will use the contraction mapping argument. To this end, we define a sequence of functions,n(x,t),n= 1, 2, . . . in the following way:

,1(x,t) =ε, (x,t)∈QT, (2.18)

,n+1(x,t) =Luε,n(x,t), (x,t)∈QT,n= 1, 2, . . . . (2.19)

By (2.15)–(2.19) and the properties ofu0ε(x), we get

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Set

M0ε=sup

x u0ε(x).

Using the method of mathematical induction, we prove that the inequalities

sup

QT1

,n(x,t)≤M, n= 1, 2, . . . (2.21)

hold for some constantsT1> 0 andM>max{ε,M0ε}. Forn= 1, it is established obviously.

Supposing that (2.19) is true forn=m, we shall prove it forn=m+ 1. Indeed, by (2.12)– (2.14) and (2.19), we have

,m+1(x,t) =

GN(x,y;t)u0ε(y)dy

+ t

0

GN(x,y;tτ)aupε,m

uqε,m(x,τ)dx dy dτ

+b

t

0

GN(x,y;tτ)

εq,mq(y,τ)dy dτ

+ t

0

GN(x,y;tτ)

k(ξ,y,τ)ulε,m(y,τ)dy dSξdτ

M0ε+Mp+(t) +Mlβ(t), (2.22)

where

γ(t) = t

0

a||GN(x,y;tτ)dy dτ,

β(t) =sup

x

t

0

GN(x,ξ;tτ)

k(ξ,y,τ)dy dSξdτ.

We note that [15] there exist positive constantsδ1anda1such that

β(t)≤a1

t, tδ1. (2.23)

Due to (2.15) and (2.16), we have

γ(t) =a||ta2t, tδ2, (2.24)

whereδ2anda2are some positive constants. We choose 0 <T1<min{δ1,δ2}such that

sup

0<t<T1

M(p+q)γ(t) +Mlβ(t)≤MM0ε. (2.25)

Because of (2.22) and (2.25), we have (2.21) withn=m+ 1. Using mean value theorem, we obtain forn= 2, 3, . . .

sup

QT1

|,n+1–,n|

=sup

QT1

a

t

0

GN(x,y;tτ)

upε,n

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upε,n–1

uqε,n–1(x,τ)dx

dξdτ

b

t

0

GN(x,ξ;tτ)

um

ε,n(ξ,τ) –umε,n–1(ξ,τ)

dξdτ

+ t

0

GN(x,ξ;tτ)

k(ξ,y,τ)ulε,n(y,τ) –ulε,n–1(y,τ)

dy dSξdτ

=sup

QT1

a

t

0

GN(x,y;tτ)

(,n,n–1)1,np–1

uqε,n(x,τ)dx

+upε,n–1

(,n,n–1)2,nq–1(x,τ)dx

dξdτ

b

t

0

GN(x,ξ;tτ)m(,n,n–1)θ3,nm–1(ξ,τ)dξdτ

+ t

0

GN(x,ξ;tτ)

k(ξ,y,τ)luε,n(y,τ) –,n–1(y,τ)

θ4,l–1n dy dSξdτ

,

whereθi,n(x,t) (i= 1, 2, 3, 4) are continuous functions inQT1 such thatα1≤θi,n(x,t)≤M1 for (x,t)∈QT1. Thus,

sup

QT1

|,n+1–,n|

≤ sup

(0,T1)

ρ(t)sup

QT1

,n(x,t) –,n–1(x,t)

≤(M+ε)sup

(0,T1)

ρ(t)n–1,

where

ρ(t) =1p–1+M1p–1

Mq+Mpqα1q–1+M1q–1

γ(t)

b

a||m

α1m–1+M1m–1

γ(t) +1l–1+M1l–1

β(t)

fort∈[0,T1]. We note that positive constantsα1 andM1do not depend onn. By (2.23)

and (2.24) there exists a constantT∈(0,T1) such that

sup

(0,T)

ρ(t) < 1.

Hence, the sequence,n(x,t) converges uniformly inQTasn→ ∞. We denote

(x,t) = lim

n→∞,n(x,t). (2.26) By virtue of (2.20), (2.21) we have

ε(x,t)≤M, (x,t)∈QT. (2.27)

Passing to the limit asn→ ∞in (2.19), by dominated convergence theorem, we obtain that the function(x,t) satisfies (2.17). Thus,(x,t) is the solution of problem (2.12)–

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inQTfor small values ofT. Let problem (2.12)–(2.14) have at least two solutions(x,t)

and(x,t) inQT. Arguing as above, we can get

sup

QT

(x,t) –(x,t)

=sup QT a t 0

GN(x,y;tτ)

upε

uqε(x,τ)dxvpε

vqε(x,τ)dx

dξdτ

b

t

0

GN(x,ξ;tτ)

umε(ξ,τ) –vmε(ξ,τ)

dξdτ

+ t

0

GN(x,ξ;tτ)

k(ξ,y,τ)ulε(y,τ) –vlε(y,τ)dy dSξdτ

=sup QT a t 0

GN(x,y;tτ)

()1,np–1

uqε(x,τ)dx

+vpε

()2,nq–1(x,τ)dx

dξdτ

b

t

0

GN(x,ξ;tτ)m()θ3,nm–1(ξ,τ)dξdτ

+ t

0

GN(x,ξ;tτ)

k(ξ,y,τ)luε(y,τ) –(y,τ)

θ4,l–1ndy dSξdτ

≤sup

QT

1p–1Mq+Mpqθ2q–1–

b a||3

m–1

γ(t)

+4l–1β(t)

sup

QT

(x,t) –(x,t)

αsup

QT

(x,t) –(x,t),

where θi(x,t) (i= 1, 2, 3, 4) are some positive continuous functions between(x,t) and (x,t) inQTandα< 1 for small values ofT. Obviously,(x,t) =(x,t) inQT.

Theorem 2.2 For some values of T,problem(1.1)(1.3)has a maximal solution in QT.

Proof Let be a solution of (2.12)–(2.14). It is easy to see thatis a supersolution of

(1.1)–(1.3). By Lemma2.1, forε1≤ε2, we can obtain1 ≤quε2. According to the Dini theorem (see [16]) for someT > 0, the sequence(x,t) converges asε→0 uniformly

inQT to some functionu(x,t). Passing to the limit asε→0 in (2.17) and using

domi-nated convergence theorem, we have that the functionu(x,t) satisfies inQTthe following

equation:

u(x,t) =

GN(x,y;tτ)u0(y)dy

+ t

0

GN(x,y;tτ)aup

uq(x,τ)dx dy dτ

b

t

0

GN(x,y;tτ)uq(y,τ)dy dτ

+ t

0

GN(x,y;tτ)

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Thus,u(x,t) solves problem (1.1)–(1.3) inQT. It is easy to prove thatu(x,t) is a maximal

solution of (1.1)–(1.3) inQT.

3 Global existence and blow-up in finite time

In order to state the following results, let us introduce some useful symbols. Through-out this paper, letλandϕ(x) be the first eigenvalue and the corresponding normalized eigenfunction of the following problem:

⎧ ⎨ ⎩

ϕ(x) =λϕ, x,

ϕ(x) = 0, x, (3.1)

whereλ> 0,max∂∂ϕ∂ν < 0, thenϕ(x) > 0 and

ϕ(x)dx= 1.

DenoteL=supϕ(x),M1=inf×k(x,y),M2=sup×k(x,y).

Theorem 3.1 Assume that p+q<m,l≤1.Then the solutions of problem(1.1)(1.3)exist

globally for any k(x,y)and any nonnegative initial data.

Proof Letλandϕ(x) satisfy (3.1), then for some 0 <ε< 1 we chooseδto satisfy that

δ≥max

∂ϕ

∂υ

–1

M2

1

(δϕ(x) +ε)ldx.

Let

u(x,t) = ce

rt

δϕ(x) +ε,

where

rλ+sup

2δ2|∇ϕ|2

(δϕ(x) +ε)2,

c=max

sup

u0(x) + 1

δϕ(x) +ε, 1,sup

(δϕ(x) +ε)mp

b

1 (δϕ(x) +ε)qdx

1

mpq

.

Then, when (x,t)∈QT, we have

utuaup

uq(y,t)dy+bum

=ruu

λϕδ δϕ(x) +ε+

2δ2|∇ϕ|2

(δϕ(x) +ε)2

a c

p+qe(p+q)rt

(δϕ(x) +ε)p

1

(δϕ(x) +ε)qdx+b

cmemrt

(δϕ(x) +ε)m

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On the other hand, when (x,t)∈ST, we obtain

∂u ∂υ

k(x,y)ul(y,t)dy

=ce

rtδ

ε2

∂ϕ

∂υ

clelrt

k(x,y) 1 (δϕ(x) +ε)ldy

cert

δ∂ϕ ∂υM2

1 (δϕ(x) +ε)ldx

≥0. (3.3)

Sincec>sup(u0(x) + 1)(δϕ(x) +ε), we get

u(x, 0) = c

δϕ(x) +ε

sup(u0(x) + 1)(δϕ(x) +ε)

δϕ(x) +εu0(x). (3.4)

Combining (3.2)–(3.4), it is clear thatu(x,t) is a supersolution of problem (1.1)–(1.3) in

Qt. By the comparison principle, the solution of problem (1.1)–(1.3) exists globally.

Theorem 3.2 Assume that p+q>m> 1, l> 0, aL >b. Then, for any k(x,y) > 0, the solution of problem (1.1)(1.3)blows up in finite time if the initial data u0(x)satisfies

u0(x)ϕ(x)dx> 1.

Proof Letu(x,t) be the solution of problem (1.1)–(1.3), we define the following auxiliary function:

J(t) =

ϕ(x)u(x,t)dx,

whereϕ(x) satisfies (3.1).

Multiplying both sides of the equation of (1.1) byϕ(x) and integrating over, we could obtain

J(t) =

ϕ

u+aup

uq(y,t)dybum

dx

=

ϕ∂u

∂υdS

u∂ϕ

∂υdS+

uϕdx

+

ϕ(x)aup

uq(y,t)dy dxb

ϕumdx

= –λ

uϕdx+a

ϕ(x)up

uq(y,t)dy dxb

ϕumdx

u∂ϕ

∂νdS.

Using the equality∂ϕ∂υdS= –λϕdx= –λandu(x,t)≥0, we have

J(t)≥–λ

uϕdx+a

ϕ(x)up

uq(y,t)dy dxb

ϕumdx+λinf

ST u(x,t)

λu+aup

uq(y,t)dybum

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From (3.5), Jensen’s inequality, andϕ(x)dx= 1, we obtain

J(t)≥–λ

uϕdx+a

uq(y,t)dy

upϕ(x)dxb

umϕ(x)dx

≥–λJ+ a

supϕ(x)

uqϕ(x)dx

upϕ(x)dxb

umϕ(x)dx

≥–λJ+a

LJ

p+qbJmλJ+

a Lb

Jp+qb.

SinceLab> 0 and the functionf(J) =Jp+qis convex, then there existsη> 1 such that

a Lb

Jp+q≥2(λJ+b) (3.6)

with the initial dataJ(0) =u0(x)ϕ(x)dx. It follows easily that ifJ(0) >η, thenJ(t) is

in-creasing on its interval of existence and

J(t)≥1 2

a Lb

Jp+q.

From above inequality (3.6), we have

lim

tT0J(t) = +∞,

where

T0=

2

(p+q– 1)Jp+q–1(0)

a Lb

.

By the comparison principle for ordinary equations (see [11,17]), it is clear that the solu-tion of (1.1)–(1.3) blows up in finite time.

Theorem 3.3 Assume p+q=m> 1.Then problem(1.1)(1.3)has blow-up solutions in finite time as well as global solutions.More precisely,

(i) ifa||>bandu0(x)is large enough,then for anyk(x,y)≥0,the solution blows up in

finite time;

(ii) ifl≥1andk(x,y)dy< 1,the solution exists globally whenu0(x)≤ρζ(x)for some

ρ> 0,whereζ(x)satisfies

ζ(x) =σ, x, (3.7)

∂ζ

∂υ =δ, x. (3.8)

Proof (i) Consider the following ODE:

u(t) =a||–bum,

u(0) =u0,

(13)

It is clear thatu(t) is a subsolution of (1.1)–(1.3), and we knowlimtT0u(t) = +∞, where

T0=(m–1)(a|1|b)um–1 0 .

By the comparison principle, we could obtain our blow-up result immediately.

(ii) Letζ(x) be the unique positive solution of the following elliptic problem: (3.7)–(3.8) and we chooseσ> 0 such that 0 <ζ(x) < 1.

Let

u(x) =ρζ(x),

where

0 <ρ<min

1,

σ aζp(x)

ζq(y)dybζm(x)

1

m–1 .

Calculating directly, forx, we have that

utuaup

uq(y,t)dy+bum

=σρaρp+qζp(x)

ζp(y)dy+bρmζm(x)≥0. (3.9)

On the other hand, forx, we find that

∂u ∂ν

k(x,y)ul(y,t)dy

=ρδρl

k(x,y)ζl(y)dy

ρδρlM2

ζ(x)dxρ

δρl–1M2max

ζ||

≥0, (3.10)

where we choosemaxζ(x) small enough.

Combining now (3.9)–(3.10) and by Lemma2.1, it follows thatu(x,t) exists globally pro-vided thatu0(x) <ρζ(x). The proof of Theorem3.3is complete.

4 Conclusion

(14)

Acknowledgements

The authors express their deepest thanks to the reviewers and the editor for their careful reading and valuable suggestions.

Funding

This work is supported by NSFC (11671188).

Abbreviations

Not applicable.

Availability of data and materials

Not applicable.

Competing interests

The authors declare that they have no competing interests.

Authors’ contributions

The authors contributed equally in this article. All authors read and approved the final manuscript.

Publisher’s Note

Springer Nature remains neutral with regard to jurisdictional claims in published maps and institutional affiliations.

Received: 28 November 2017 Accepted: 17 September 2018 References

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