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A Hybrid Extragradient Viscosity Approximation Method for Solving Equilibrium Problems and Fixed Point Problems of Infinitely Many Nonexpansive Mappings

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Volume 2009, Article ID 374815,32pages doi:10.1155/2009/374815

Research Article

A Hybrid Extragradient Viscosity

Approximation Method for Solving Equilibrium

Problems and Fixed Point Problems of Infinitely

Many Nonexpansive Mappings

Chaichana Jaiboon and Poom Kumam

Department of Mathematics, Faculty of Science, King Mongkut’s University of Technology Thonburi, Bangkok 10140, Thailand

Correspondence should be addressed to Poom Kumam,[email protected]

Received 25 December 2008; Accepted 4 May 2009

Recommended by Wataru Takahashi

We introduce a new hybrid extragradient viscosity approximation method for finding the common element of the set of equilibrium problems, the set of solutions of fixed points of an infinitely many nonexpansive mappings, and the set of solutions of the variational inequality problems for β-inverse-strongly monotone mapping in Hilbert spaces. Then, we prove the strong convergence of the proposed iterative scheme to the unique solution of variational inequality, which is the optimality condition for a minimization problem. Results obtained in this paper improve the previously known results in this area.

Copyrightq2009 C. Jaiboon and P. Kumam. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

1. Introduction

LetH be a real Hilbert space, and let Cbe a nonempty closed convex subset ofH. Recall that a mappingT of H into itself is called nonexpansivesee1if TxTyxy for allx, yH. We denote byFT {xC: Tx x}the set of fixed points ofT. Recall also that a self-mappingf :HHis acontractionif there exists a constantα∈0,1such thatfxfyαxy, for all x, yH.In addition, letB:CHbe a nonlinear mapping. LetPC be the projection ofHontoC. The classical variational inequality which is

denoted byV IC, Bis to finduCsuch that

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For a givenzH,uCsatisfies the inequality

uz, vu ≥0, ∀vC, 1.2

if and only ifuPCz. It is well known thatPCis a nonexpansive mapping ofHontoCand

satisfies

xy, PCxPCyPCxPCy2,x, yH. 1.3

Moreover,PCxis characterized by the following properties:PCxCand for allxH, yC,

xPCx, yPCx≤0, 1.4

xy2

xPCx2yPCx2. 1.5

It is easy to see that the following is true:

uV IC, B⇐⇒uPCuλBu, λ >0. 1.6

One can see that the variational inequality1.1is equivalent to a fixed point problem. The variational inequality has been extensively studied in literature; see, for instance, 2–

6. This alternative equivalent formulation has played a significant role in the studies of the variational inequalities and related optimization problems. Recall the following.

1A mappingBofCintoHis called monotone if

BxBy, xy≥0, ∀x, yC. 1.7

2A mappingB is calledβ-strongly monotonesee7,8if there exists a constant β >0 such that

BxBy, xyβxy2, x, yC. 1.8

3A mappingBis calledk-Lipschitz continuous if there exists a positive real number ksuch that

BxBykxy,x, yC. 1.9

4A mapping Bis called β-inverse-strongly monotonesee 7, 8 if there exists a constantβ >0 such that

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Remark 1.1. It is obvious that anyβ-inverse-strongly monotone mappingBis monotone and 1/β-Lipschitz continuous.

5An operatorAis strongly positive onH if there exists a constantγ > 0 with the property

Ax, xγx2, xH. 1.11

6A set-valued mappingT :H → 2His called monotone if for allx, yH,fTx, andgTyimplyxy, fg ≥0. A monotone mappingT :H → 2His maximal if the graph ofGT ofT is not properly contained in the graph of any other monotone mapping. It is known that a monotone mappingTis maximal if and only if forx, fH×H,xy, fg ≥ 0 for everyy, gGTimpliesfTx. LetBbe a monotone map ofCintoH,and letNCv

be the normal cone toCatvC, that is,NCv{wH:uv, w ≥0, for alluC},.

Tv

⎧ ⎨ ⎩

BvNCv, vC,

, v /C. 1.12

ThenT is the maximal monotone and 0∈Tvif and only ifvV IC, B; see9.

7 Let F be a bifunction ofC×Cinto R, whereR is the set of real numbers. The equilibrium problem forF:C×C → Ris to findxCsuch that

Fx, y ≥0, ∀yC. 1.13

The set of solutions of 1.13 is denoted by EPF. Given a mapping T : CH, let Fx, y Tx, yx for all x, yC. Then, zEPF if and only if Tz, yz ≥ 0 for all yC.Numerous problems in physics, saddle point problem, fixed point problem, variational inequality problems, optimization, and economics are reduced to find a solution of 1.13. Some methods have been proposed to solve the equilibrium problem; see, for instance, 10–16. Recently, Combettes and Hirstoaga 17introduced an iterative scheme of finding the best approximation to the initial data whenEPFis nonempty and proved a strong convergence theorem.

In 1976, Korpelevich18introduced the following so-called extragradient method:

x0xC,

ynPCxnλBxn,

xn1PCxnλByn

1.14

for alln≥0,whereλ∈0,1/k, Cis a closed convex subset ofRn,andBis a monotone and k-Lipschitz continuous mapping ofCintoRn. He proved that ifV IC, Bis nonempty, then the sequences{xn}and{yn}, generated by1.14, converge to the same pointzV IC, B.

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the set of solution of variational inequalities forβ-inverse-strongly monotone, Takahashi and Toyoda19introduced the following iterative scheme:

x0∈C chosen arbitrary,

xn1αnxn 1−αnSPCxnλnBxn,n≥0,

1.15

whereBisβ-inverse-strongly monotone,{αn}is a sequence in0, 1, and{λn}is a sequence

in0,2β. They showed that ifFSV IC, Bis nonempty, then the sequence{xn}generated

by1.15converges weakly to somezFSV IC, B. Recently, Iiduka and Takahashi20

proposed a new iterative scheme as follows:

x0xC chosen arbitrary,

xn1αnx 1−αnSPCxnλnBxn,n≥0,

1.16

whereBisβ-inverse-strongly monotone,{αn}is a sequence in0, 1, and{λn}is a sequence

in0,2β. They showed that ifFSV IC, Bis nonempty, then the sequence{xn}generated

by1.16converges strongly to somezFSV IC, B.

Iterative methods for nonexpansive mappings have recently been applied to solve convex minimization problems; see, for example,21–24and the references therein. Convex minimization problems have a great impact and influence in the development of almost all branches of pure and applied sciences. A typical problem is to minimize a quadratic function over the set of the fixed points of a nonexpansive mapping on a real Hilbert spaceH:

min

xC

1

2Ax, xx, b, 1.17

whereAis a linear bounded operator,Cis the fixed point set of a nonexpansive mapping SonH, andbis a given point inH. Moreover, it is shown in25that the sequence {xn}

defined by the scheme

xn1 nγfxn 1−nASxn 1.18

converges strongly to z PFSIA γfz. Recently, Plubtieng and Punpaeng 26

proposed the following iterative algorithm:

Fun, y r1 n

yun, unxn≥0, ∀yH,

xn1nγfxn InASun.

1.19

They prove that if the sequences{n}and{rn}of parameters satisfy appropriate condition,

then the sequences{xn}and{un}both converge to the unique solutionzof the variational

inequality

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which is the optimality condition for the minimization problem

min

xFSEPF

1

2Ax, xhx, 1.21

wherehis a potential function forγfi.e.,hx γfxforxH.

Furthermore, for finding approximate common fixed points of an infinite countable family of nonexpansive mappings {Tn} under very mild conditions on the parameters.

Wangkeeree27introduced an iterative scheme for finding a common element of the set of solutions of the equilibrium problem1.13and the set of common fixed points of a countable family of nonexpansive mappings onC. Starting with an arbitrary initialx1 ∈ C, define a sequence{xn}recursively by

Fun, y r1 n

yun, unxn≥0, ∀yC,

ynPCunλnBun,

xn1 αnfxn βnxnγnSnPCunλnByn ,n≥1,

1.22

where{αn},{βn},and{γn}are sequences in0,1. It is proved that under certain appropriate

conditions imposed on {αn},{βn},{γn}, and {rn}, the sequence {xn} generated by 1.22

strongly converges to the unique solution q ∈ ∩∞n1FSnV IC, BEPF, where p

P∩∞

n1FSnV IC,BEPFfqwhich extend and improve the result of Kumam14.

Definition 1.2see21. Let{Tn}be a sequence of nonexpansive mappings ofCinto itself,

and let{μn}be a sequence of nonnegative numbers in0,1. For eachn≥1, define a mapping

WnofCinto itself as follows:

Un,n1I,

Un,nμnTnUn,n1

1−μn I,

Un,n−1μn−1Tn−1Un,n1−μn−1 I,

.. .

Un,kμkTkUn,k1

1−μk I,

Un,k−1μk−1Tk−1Un,k1−μk−1 I,

.. .

Un,2μ2T2Un,3

1−μ2 I,

WnUn,1μ1T1Un,2

1−μ1 I.

1.23

Such a mappingWnis nonexpansive fromCtoC,and it is called theW-mapping generated

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On the other hand, Colao et al.28introduced and considered an iterative scheme for finding a common element of the set of solutions of the equilibrium problem1.13and the set of common fixed points of infinitely many nonexpansive mappings onC. Starting with an arbitrary initialx0∈C, define a sequence{xn}recursively by

Fun, y r1

nyun, unxn ≥0, ∀yH,

xn1nγfxn βxn1−β InA Wnun,

1.24

where{n}is a sequence in0,1. It is proved28that under certain appropriate conditions

imposed on{n}and{rn}, the sequence{xn}generated by1.24strongly converges toz

∩∞

n1FTnEPF, wherezis an equilibrium point forF and is the unique solution of the variational inequality1.20, that is,zP∩∞

n1FTnEPFIAγfz.

In this paper, motivated by Wangkeeree27, Plubtieng and Punpaeng26, Marino and Xu25, and Colao, et al.28, we introduce a new iterative scheme in a Hilbert spaceH which is mixed by the iterative schemes of1.18,1.19,1.22, and1.24as follows.

Letfbe a contraction ofHinto itself,Aa strongly positive bounded linear operator on Hwith coefficientγ >0,andBaβ-inverse-strongly monotone mapping ofCintoH; define sequences{xn},{yn},{kn},and{un}recursively by

x1 xC chosen arbitrary,

Fun, y r1

nyun, unxn ≥0, ∀yC,

ynPCunλnBun,

knαnun 1−αnPCunλnByn ,

xn1nγfxn βnxn1−βn InA Wnkn,n≥1,

1.25

where {Wn}is the sequence generated by 1.23,{n},{αn},and {βn} ⊂ 0,1 and {rn} ⊂

0,∞satisfying appropriate conditions. We prove that the sequences{xn},{yn},{kn}and

{un}generated by the above iterative scheme1.25converge strongly to a common element

of the set of solutions of the equilibrium problem1.13, the set of common fixed points of infinitely family nonexpansive mappings, and the set of solutions of variational inequality

1.1for a β-inverse-strongly monotone mapping in Hilbert spaces. The results obtained in this paper improve and extend the recent ones announced by Wangkeeree 27, Plubtieng and Punpaeng26, Marino and Xu25, Colao, et al.28, and many others.

2. Preliminaries

We now recall some well-known concepts and results.

LetHbe a real Hilbert space, whose inner product and norm are denoted by·,·and

· , respectively. We denote weak convergence and strong convergence by notationsand

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A spaceHis said to satisfy Opial’s condition29if for each sequence{xn}inHwhich

converges weakly to pointxH, we have

lim inf

n→ ∞ xnx<lim infn→ ∞ xny,yH, y /x. 2.1

Lemma 2.1see25. LetCbe a nonempty closed convex subset ofH, letf be a contraction of H into itself withα ∈ 0,1, and letAbe a strongly positive linear bounded operator on Hwith coefficientγ >0. Then , for0< γ < γ/α,

xy,Aγf xAγf yγαγ xy2, x, yH. 2.2

That is,Aγfis strongly monotone with coefficientγγα.

Lemma 2.2see25. Assume thatA is a strongly positive linear bounded operator onH with coefficientγ >0and0< ρA−1. ThenIρA ≤1−ργ.

For solving the equilibrium problem for a bifunctionF :C×CR, let us assume thatFsatisfies the following conditions:

A1Fx, x 0 for allxC;

A2Fis monotone, that is,Fx, y Fy, x≤0 for allx, yC;

A3for eachx, y, zC,limt↓0Ftz 1−tx, yFx, y;

A4for eachxC, yFx, yis convex and lower semicontinuous. The following lemma appears implicitly in30.

Lemma 2.3see30. LetCbe a nonempty closed convex subset ofHand letFbe a bifunction of C×CintoRsatisfying (A1)–(A4). Letr >0andxH. Then, there existszCsuch that

Fz, y 1ryz, zx≥0 ∀yC. 2.3

The following lemma was also given in17.

Lemma 2.4see17. Assume thatF :C×CRsatisfies (A1)–(A4). Forr > 0andxH, define a mappingTr :HCas follows:

Trx

zC:Fz, y 1 r

yz, zx≥0, ∀yC

2.4

for allzH. Then, the following holds:

1Tr is single-valued;

2Tr is firmly nonexpansive, that is, for anyx, yH,

TrxTry2T

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3FTr EPF;

4EPFis closed and convex.

For eachn, k ∈ N, let the mappingUn,kbe defined by1.23. Then we can have the

following crucial conclusions concerningWn. You can find them in31. Now we only need

the following similar version in Hilbert spaces.

Lemma 2.5see31. LetC be a nonempty closed convex subset of a real Hilbert spaceH. Let T1, T2, . . . be nonexpansive mappings of C into itself such that ∩∞n1FTn is nonempty, and let

μ1, μ2, . . .be real numbers such that0 ≤ μnb < 1 for everyn ≥ 1. Then, for everyxCand

k∈N, the limitlimn→ ∞Un,kxexists.

UsingLemma 2.5, one can define a mappingWofCinto itself as follows:

Wx lim

n→ ∞Wnxnlim→ ∞Un,1x 2.6

for everyxC. Such aW is called the W-mapping generated byT1, T2, . . . and μ1, μ2, . . .. Throughout this paper, we will assume that 0≤μnb <1 for everyn≥1. Then, we have the

following results.

Lemma 2.6see31. LetC be a nonempty closed convex subset of a real Hilbert spaceH. Let T1, T2, . . . be nonexpansive mappings of C into itself such that ∩∞n1FTn is nonempty, and let μ1, μ2, . . .be real numbers such that0≤μnb <1for everyn≥1. Then,FW ∩∞n1FTn. Lemma 2.7see32. If{xn}is a bounded sequence inC, thenlimn→ ∞WxnWnxn0.

Lemma 2.8see33. Let{xn}and{zn}be bounded sequences in a Banach spaceX,and let{βn}be

a sequence in0,1with0<lim infn→ ∞βn≤lim supn→ ∞βn<1.Supposexn1 1−βnznβnxn

for all integersn≥0andlim supn→ ∞yn1−znxn1−xn≤0.Then,limn→ ∞znxn0.

Lemma 2.9see34. Assume that{an}is a sequence of nonnegative real numbers such that

an1≤1−lnanσn, n≥0, 2.7

where{ln}is a sequence in0,1and{σn}is a sequence inRsuch that

1∞n1ln∞;

2lim supn→ ∞σn/ln≤0orn1|σn|<.

Thenlimn→ ∞an0.

Lemma 2.10. LetHbe a real Hilbert space. Then for allx, yH,

1xy2≤ x22y, xy;

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3. Main Results

In this section, we prove the strong convergence theorem for infinitely many nonexpansive mappings in a real Hilbert space.

Theorem 3.1. LetCbe a nonempty closed convex subset of a real Hilbert spaceH, letFbe a bifunction fromC×CtoRsatisfying (A1)–(A4), let{Tn}be an infinitely many nonexpansive ofCinto itself,

and let B be an β-inverse-strongly monotone mapping ofC into H such that Θ : ∩∞n1FTn

EPFV IC, B/. Letfbe a contraction ofHinto itself withα∈0,1,and letAbe a strongly positive linear bounded operator onH with coefficient γ > 0 and0 < γ < γ/α. Let {xn},{yn},

{kn},and{un}be sequences generated by1.25, where{Wn}is the sequence generated by1.23,

{n},{αn},and{βn}are three sequences in0,1,and{rn}is a real sequence in0,∞satisfying the

following conditions:

ilimn→ ∞n0,∞n1n∞;

iilimn→ ∞αn0andn1αn∞;

iii0<lim infn→ ∞βn≤lim supn→ ∞βn<1;

ivlim infn→ ∞rn>0andlimn→ ∞|rn1−rn|0;

v{λn/β} ⊂τ,1−δfor someτ, δ∈0,1andlimn→ ∞λn0.

Then,{xn}and{un}converge strongly to a pointz∈Θwhich is the unique solution of the variational

inequality

Aγf z, zx≥0, ∀x∈Θ. 3.1

Equivalently, one haszPΘIAγfz.

Proof. Note that from the conditioni, we may assume, without loss of generality, thatn

1−βnA−1for alln∈N. FromLemma 2.2, we know that if 0≤ρA−1, thenIρA

1−ργ. We will assume thatIA ≤1−γ. First, we show thatIλnBis nonexpansive. Indeed,

from theβ-inverse-strongly monotone mapping definition onBand conditionv, we have

IλnBxIλnBy2xyλnBxBy2

xy2

nxy, BxByλ2nBxBy2

xy2

nβBxBy2λ2nBxBy2

xy2λ

nλn−2β BxBy2

xy2,

3.2

which implies that the mapping IλnB is nonexpansive. On the other hand, sinceAis a

strongly positive bounded linear operator on H, we have

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Observe that

1−βn InA x, x1−βnnAx, x

≥1−βnnA

≥0,

3.4

and this show that1−βnInAis positive. It follows that

1βn InAsup1βn InA x, x:xH,x1

sup1−βnnAx, x:xH,x1

≤1−βnnγ.

3.5

LetQPΘ, whereΘ:∩∞n1FTnEPFV IC, B. Note thatf is a contraction ofHinto itself withα∈0,1. Then, we have

QIAγf xQIAγf y PΘIAγf xPΘIAγf y

IAγf xIAγf y

IAxyγfxfy

≤1−γ xyγαxy

1−γγα xy

1−γγα xy,x, yH.

3.6

Since 0 < 1−γγα < 1, it follows that QIAγf is a contraction ofH into itself. Therefore by the Banach Contraction Mapping Principle, which implies that there exists a unique elementzHsuch thatzQIAγfz PΘIAγfz.

We will divide the proof into five steps.

Step 1. We claim that{xn}is bounded. Indeed, pick anyp∈Θ. From the definition ofTr, we

note thatunTrnxn. If follows that

unpTrnxnTrnpxnp. 3.7

SinceIλnBis nonexpansive andpPCpλnBpfrom1.6, we have

ynpPCunλnBunPCpλnBp

unλnAunpλnBp

IλnAunIλnBp

unpxnp.

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Putvn PCunλnByn. SincepV IC, B, we havep PCpλnBp. Substitutingx

unλnAynandypin1.5, we can write

vnp2 ≤unλnBynp2−unλnBynvn2

unp2−2λnByn, un2nByn2

unvn22λnByn, unvnλ2nByn2

unp2− unvn22λnByn, pvn

unp2− unvn22λnBynBp, pyn

nBp, pynnByn, ynvn.

3.9

Using the fact that B is β-inverse-strongly monotone mapping, and p is a solution of the variational inequality problemV IC, B, we also have

BynBp, pyn≤0, Bp, pyn ≤0. 3.10

It follows from3.9and3.10that

vnp2≤unp2− unvn22λnByn, ynvn

unp2−unyn ynvn22λnByn, ynvn

unp2−unyn2−ynvn2

−2unyn, ynvnnByn, ynvn

unp2−unyn2−ynvn22unλnBynyn, vnyn.

3.11

SubstitutingxbyunλnBunandyvnin1.4, we obtain

unλnBunyn, vnyn≤0. 3.12

It follows that

unλnBynyn, vnynunλnBunyn, vnyn

λnBunλnByn, vnyn

λnBunλnByn, vnyn

λnBunBynvnyn

λβnunynvnyn.

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Substituting3.13into3.11, we have

vnp2≤unp2−unyn2−ynvn22unλnBynyn, vnyn

unp2−unyn2−ynvn22λβnunynvnyn

unp2−unyn2−ynvn2λ

2

n

β2unyn 2v

nyn2

unp2−unyn2λ

2

n

β2unyn 2

unp2

λ2

n

β2 −1

unyn2

unp2≤xnp2.

3.14

Settingknαnun 1−αnvn, we can calculate

xn1pn

γfxnAp βnxnp 1−βn InA Wnknp

≤1−βn knpβnxnpnγfxnAp

≤1−βn αnunp 1−αnvnp

βnxnpnγfxnAp

≤1−βn αnxnp 1−αnxnp

βnxnpnγfxnAp

1−βn xnpβnxnpnγfxnAp

1− xnpnγfxnfp nγfpAp

≤1− xnpnγαxnpnγfpAp

1−γγα n xnγα n

γfpAp γγα .

3.15

By induction,

xnpmaxx1p,γfpAp γγα

, n∈N. 3.16

Hence,{xn}is bounded, so are{un},{vn},{Wnkn},{fxn},{Bun},{yn},and{Byn}.

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Observing thatunTrnxnandun1Trn1xn1,we get

Fun, y r1 n

yun, unxn≥0 ∀yH 3.17

Fun1, y 1 rn1

yun1, un1−xn1

≥0 ∀yH. 3.18

Puttingyun1in3.17andyunin3.18, we have

Fun, un1 r1

nun1−un, unxn ≥0

Fun1, un r1

n1

unun1, un1−xn1 ≥0.

3.19

So, fromA2we have

un1−un,unrxn

n

un1−xn1 rn1

≥0, 3.20

and hence

un1−un, unun1un1−xnrn

rn1

un1−xn1

≥0. 3.21

Without loss of generality, let us assume that there exists a real numbercsuch thatrn> c >0

for alln∈N.Then, we have

un1−un2≤

un1−un, xn1−xn

1− rn

rn1

un1−xn1

un1−un

xn1−xn1−rrn n1

un1−xn1

,

3.22

and hence

un1−unxn1−xnr1 n1|

rn1−rn|un1−xn1

xn1−xnMc1|rn1−rn|,

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whereM1sup{unxn:n∈N}. Note that

vn1−vnPCun1−λn1Byn1 −PCunλnByn

un1−λn1Byn1−

unλnByn

un1−λn1Bun1−unλn1Bun

λn1

Bun1−Byn1−Bun λnByn

un1−λn1Bun1−unλn1Bun

λn1

Bun1Byn1Bun λnByn

un1−unλn1

Bun1Byn1Bun λnByn,

kn1−knαn1un1 1−αn1vn1−αnun−1−αnvn

αn1un1−un αn1−αnun

1−αn1vn1−vn αnαn1vn

αn1un1−un 1−αn1vn1−vn|αnαn1|unvn

αn1un1−un 1−αn1

×un1−unλn1

Bun1Byn1Bun

λnByn|αnαn1|unvn

un1−un 1−αn1λn1

Bun1Byn1Bun

1−αn1λnByn|αnαn1|unvn

xn1−xn M1

c |rn1−rn| 1−αn1λn1

×Bun1Byn1Bun

1−αn1λnByn|αnαn1|unvn.

3.24

Setting

zn xn1−βnxn

1−βn

nγfxn 1−βn InA Wnkn

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we havexn1 1−βnznβnxn, n≥1. It follows that

zn1−zn n1γfxn1

1−βn1 In1A Wn1kn1 1−βn1

nγfxn

1−βn InA Wnkn

1−βn

n1 1−βn1

γfxn1− n

1−βnγfxn Wn1kn1−Wnkn

n

1−βnAWnkn

n1 1−βn1

AWn1kn1

n1 1−βn1

γfxn1−AWn1kn1 n

1−βn

AWnknγfxn

Wn1kn1−Wn1knWn1knWnkn.

3.26

It follows from3.24and3.26that

zn1−znxn1−xnn1 1−βn1

γfxn1AWn1kn1

n

1−βn

AWnknγfxn Wn1kn1−Wn1kn

Wn1knWnknxn1−xn

n1 1−βn1

γfxn1AWn1kn1

n

1−βn

AWnknγfxn kn1−kn

Wn1knWnknxn1−xn

n1 1−βn1

γfxn1AWn1kn1

n

1−βn

AWnknγfxn Mc1|rn1−rn|

1−αn1λn1

Bun1Byn1Bun

1−αn1λnByn|αnαn1|unvn

Wn1knWnkn.

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SinceTiandUn,iare nonexpansive, we have

Wn1knWnknμ1T1Un1,2knμ1T1Un,2knμ1Un1,2knUn,2kn

μ1μ2T2Un1,3knμ2T2Un,3kn

μ1μ2Un1,3knUn,3kn

.. .

μ1μ2· · ·μnUn1,n1knUn,n1kn

M2

n

i1 μi,

3.28

whereM2≥0 is a constant such thatUn1,n1knUn,n1knM2for alln≥0. Combining3.27and3.28, we have

zn1−znxn1−xnn1

1−βn1

γfxn1AWn1kn1

n

1−βn

AWnknγfxn Mc1|rn1−rn|

1−αn1λn1

Bun1Byn1Bun

1−αn1λnByn|αnαn1|unvn

M2

n

i1 μi,

3.29

which implies thatnoting thati,ii,iii,iv,v, and 0< μib <1,for alli≥1

lim sup

n→ ∞ zn1−znxn1−xn≤0. 3.30

Hence, byLemma 2.8, we obtain

lim

n→ ∞znxn0. 3.31

It follows that

lim

n→ ∞xn1−xnnlim→ ∞

(17)

Applying3.32andii,iv, andvto3.23and3.24, we obtain that

lim

n→ ∞un1−unnlim→ ∞kn1−kn0. 3.33

Sincexn1nγfxn βnxn 1−βnInAWnkn, we have

xnWnknxnxn1xn1−Wnkn

xnxn1nγfxn βnxn1−βn InA WnknWnkn

xnxn1nγfxnAWnkn βnxnWnkn

xnxn1nγfxnAWnkn βnxnWnkn,

3.34

that is

xnWnkn ≤ 1

1−βnxnxn1

n

1−βn

γfxnAWnkn . 3.35

Byi,iii, and3.32it follows that

lim

n→ ∞Wnknxn0. 3.36

Step 3. We claim that the following statements hold:

ilimn→ ∞unkn0;

iilimn→ ∞xnun0.

For anyp∈Θ:∩∞n1FTnEPFV IC, Band3.14, we have

knp2αnunp 1−αnvnp2

αnunp2 1−αnvnp2

αnunp2 1−αn

unp2

λ2

n

β2 −1

unyn2

unp2 1−αn

λ2

n

β2 −1

unyn2

xnp2 1−αn

λ2

n

β2 −1

unyn2.

(18)

Observe that

xn1−p21−βnInAWnknp βnxnp nγfxnAp2

1−βnInAWnknp βnxnp2n2γfxnAp2

nnxnp, γfxnAp

2n1−βn InA Wnknp , γfxnAp

≤1−βnnγWnknpβnxnp2

2

nγfxnAp2

nnxnp, γfxnAp

2n1−βn InA Wnknp , γfxnAp

≤1−βnnγknpβnxnp2cn

≤1−βn 2knp2βn2xnp2

21−βn βnknpxnpcn

≤1−βn 2knp2βn2xnp2

1−βn βnknp2xnp2

cn

1− 2−21− βnβ2n

knp2β2nxnp2

1− βnβ2n

knp2xnp2

cn

1− 2knp2−1− βnknp2

1− βnxnp2cn

1− 1−βn knp21− βnxnp2cn,

3.38

where

cn2nγfxnAp22βnnxnp, γfxnAp

2n1−βn InA Wnknp , γfxnAp.

3.39

It follows from conditionithat

lim

(19)

Substituting3.37into3.38, and usingv, we have

xn1p2

1− 1−βn

xnp2

1−αn

λ2

n

β2 −1

unyn2

1− βnxnp2cn

1− 2xnp2

1− 1−βn 1−αn

λ2

n

β2 −1

unyn2cn

xnp2 1−αn

λ2

n

β2 −1

unyn2cn.

3.41

It follows that

1−αnδunyn2≤1−αn

1−λ

2

n

β2

unyn2

xnp2−xn1−p2cn

xnpxn1−p xnpxn1−p cn

xnxn1xnpxn1−p cn.

3.42

Since limn→ ∞cn0 and from3.32, we obtain

lim

n→ ∞unyn0. 3.43

Note that

knvnαnunvn. 3.44

Since limn→ ∞αn0, we have

lim

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AsBis 1/β-Lipschitz continuous, we obtain

vnynPC

unλnBynPCunλnBun

unλnBynunλnBun

λnBunByn

λn

βunyn,

3.46

then, we get

lim

n→ ∞vnyn0. 3.47

from

unknunynynvnvnkn. 3.48

Applying3.43,3.45, and3.47, we have

lim

n→ ∞unkn0. 3.49

For anyp∈Θ, note thatTr is firmly nonexpansiveLemma 2.4, then we have

unp2TrnxnTrnp 2

TrnxnTrnp, xnp

unp, xnp

1

2

unp2xnp2− xnun2

,

3.50

and hence

unp2x

(21)

which together with3.38gives xn1−p2 ≤

1− 1−βn knp21− βnxnp2cn

1− 1−βn

×knun2unp22knun, unp

1− βnxnp2cn

≤1− 1−βn knun2

1− 1−βn unp2

21− 1−βn knununp

1− βnxnp2cn

≤1− 1−βn knun2

1− 1−βn xnp2− xnun2

21− 1−βn knununp

1− βnxnp2cn

≤1− 1−βn knun2

1− 1−βn xnp2

−1− 1−βn xnun2

21− 1−βn knununp

1− βnxnp2cn

1− 2xnp2−1− 1−βn xnun2

1− 1−βn knun2

21− 1−βn knununpcn

1−2nγnγ 2xnp2

−1− 1−βn xnun2

1− 1−βn knun2

21− 1−βn knununpcn

xnp2 2xnp2

(22)

− 1− 1−βn xnun2

21− 1−βn knununpcn.

3.52

So

1− 1−βn xnun2

xnp2−xn1−p2

2xnp2

1− 1−βn knun2

21− 1−βn knununpcn

xnpxn1−p xnpxn1−p

2xnp21− 1−βn knun2

21− 1−βn knununpcn

xnxn1xnpxn1−p

2xnp2

1− 1−βn knun2

21− 1−βn knununpcn.

3.53

Usingn → 0,cn → 0 asn → ∞,3.32, and3.49, we obtain

lim

n→ ∞xnun0. 3.54

Since lim infn→ ∞rn>0, we obtain

lim

n→ ∞

xnun

rn

lim

n→ ∞

1

rnxnun0. 3.55

Observe that

WnununWnunWnknWnknxnxnun

unknWnknxnxnun.

3.56

Applying3.36,3.49, and3.54to the last inequality, we obtain

lim

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Let W be the mapping defined by2.6. Since {un} is bounded, applyingLemma 2.7and

3.57, we have

WununWunWnunWnunun → 0 asn → ∞. 3.58

Step 4. We claim that lim supn→ ∞Aγfz, zxn ≤0,wherezis the unique solution of

the variational inequalityAγfz, zx ≥0, for allx∈Θ.

SincezPΘIAγfzis a unique solution of the variational inequality3.1, to show this inequality, we choose a subsequence{uni}of{un}such that

lim

i→ ∞

Aγf z, zuni

lim sup

n→ ∞

Aγf z, zun. 3.59

Since{uni}is bounded, there exists a subsequence{unij}of{uni}which converges weakly to

wC. Without loss of generality, we can assume thatuni w.FromWunun → 0,we

obtainWuni w. Next, We show thatw∈Θ, whereΘ:∩∞n1FTnEPFV IC, B. First, we show thatwEPF. SinceunTrnxn, we have

Fun, y r1 n

yun, unxn≥0, ∀yC. 3.60

If follows fromA2that

1 rn

yun, unxn≥ −Fun, yFy, un , 3.61

and hence

yuni,

unixni

rni

Fy, uni . 3.62

Sinceunixni/rni → 0 anduni w,it follows byA4thatFy, w≤0 for allyH.Fort

with 0< t≤1 andyH,letytty 1−tw.SinceyHandwH,we haveytHand

henceFyt, w≤0.So, fromA1andA4we have

0Fyt, yttFyt, y 1−tFyt, wtFyt, y , 3.63

and henceFyt, y≥0. FromA3, we haveFw, y≥0 for allyHand hencewEPF.

Next, we show that w ∈ ∩∞n1FTn. By Lemma 2.6, we have FW ∩∞n1FTn.

Assumew /FW.Sinceuni wandw /Ww,it follows by the Opial’s condition that

lim inf

i→ ∞ uniw<lim infi→ ∞ uniWw

≤lim inf

i→ ∞ {uniWuniWuniWw}

≤lim inf

i→ ∞ uniw,

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which derives a contradiction. Thus, we havewFWn1FTn. By the same argument

as that in the proof of35, Theorem 2.1, Pages 10–11, we can show thatwV IC, B.Hence w∈Θ. SincezPΘIAγfz, it follows that

lim sup

n→ ∞

Aγf z, zxnlim sup

n→ ∞

Aγf z, zun

lim

i→ ∞

Aγf z, zuni

Aγf z, zw≤0.

3.65

It follows from the last inequality,3.36, and3.54that

lim sup

n→ ∞

γfzAz, Wnknz≤0. 3.66

Step 5. Finally, we show that{xn}and{un}converge strongly tozPΘIAγfz. Indeed,

from1.25, we have

xn1−z2

nγfxn βnxn 1−βnInAWnknz2

1−βnInAWnknz βnxnz nγfxnAz2

1−βnInAWnknz βnxnz2n2γfxnAz2

nnxnz, γfxnAz

2n1−βn InA Wnknz, γfxnAz

≤1−βnnγWnknzβnxnz2n2γfxnAz2

nnγxnz, fxnfznnxnz, γfzAz

21−βn γnWnknz, fxnfz21−βn nWnknz, γfzAz

− 22

nAWnknz, γfzAz

≤1−βnnγWnknzβnxnz2n2γfxnAz2

nnγxnzfxnfznnxnz, γfzAz

21−βn γnWnknzfxnfz21−βn nWnknz, γfzAz

− 22

(25)

≤1−βnnγxnzβnxnz2n2γfxnAz2

nnγαxnz22βnnxnz, γfzAz

21−βn γnαxnz221−βn nWnknz, γfzAz

− 22

nAWnknz, γfzAz

1− 22βnnγα21−βn γnα

xnz2n2γfxnAz2

nnxnz, γfzAz21−βn nWnknz, γfzAz

− 22

nAWnknz, γfzAz

≤1−2γαγ nxnz2γ22nxnz2n2γfxnAz2

nnxnz, γfzAz21−βn nWnknz, γfzAz

22

nAWnknzγfzAz

1−2γαγ nxnz2n

×n

γ2x

nz2γfxnAz2

2AWnknzγfzAznxnz, γfzAz

21−βn Wnknz, γfzAz.

3.67

Since{xn},{fxn},and{Wnkn}are bounded, we can take a constantM >0 such that

γ2x

nz2γfxnAz22AWnknzγfzAzM 3.68

for alln≥0. It then follows that

xn1−z2≤

1−2γαγ nxnz2nσn, 3.69

where

σnnxnz, γfzAz21−βn Wnknz, γfzAznM. 3.70

Using i,3.65, and3.66, we get lim supn→ ∞σn ≤ 0. ApplyingLemma 2.9to3.69, we

conclude thatxnzin norm. Finally, noticing

unzTrnxnTrnzxnz, 3.71

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Corollary 3.228,Theorem 3.1. LetCbe nonempty closed convex subset of a real Hilbert space H, letF be a bifunction fromC×CtoRsatisfying (A1)–(A4), and let{Tn}be an infinitely many

nonexpansive ofCinto itself such thatΘ:∩∞n1FTnEPF/. Letfbe a contraction ofHinto

itself withα∈0,1,and letAbe a strongly positive linear bounded operator onHwith coefficient γ >0and0< γ < γ/α. Let{xn}and{un}are the sequences generated by

x1xC chosen arbitrary,

Fun, y r1

nyun, unxn ≥0, ∀yC,

xn1nγfxn βxn1−β InA Wnun,n≥1,

3.72

where{Wn}is the sequence generated by1.23∈0,1,{n}is a sequences in0,1,and{rn}is

a real sequence in0,∞satisfying the following conditions:

ilimn→ ∞n0;

iilim infn→ ∞rn>0andlimn→ ∞|rn1−rn|0.

Then,{xn} and{un}converge strongly to a pointz ∈Θwhich is the unique solution of the

variational inequality

Aγf z, zx ≥0, ∀x∈Θ. 3.73

Equivalently, one haszPΘIAγfz.

Proof. PutB0,{βn}β,and{αn}0 inTheorem 3.1., thenynkn un. The conclusion of

Corollary 3.2can obtain the desired result easily.

Corollary 3.3. LetCbe nonempty closed convex subset of a real Hilbert spaceH, letFbe a bifunction fromC×CtoRsatisfying (A1)–(A4) and letBbe anβ-inverse-strongly monotone mapping ofCinto Hsuch thatΘ:EPFV IC, B/. Letf be a contraction ofHinto itself withα∈0,1and letAbe a strongly positive linear bounded operator onHwith coefficientγ >0and0< γ < γ/α. Let

{xn},{yn},{kn},and{un}be sequences generated by

x1xC chosen arbitrary,

Fun, y r1

nyun, unxn ≥0, ∀yC,

ynPCunλnBun,

kn αnun 1−αnPCunλnByn ,

xn1 nγfxn βnxn1−βn InA kn,n≥1,

(27)

where {n}, {αn}, and {βn} are three sequences in 0,1, and {rn} is a real sequence in 0,∞

satisfying the following conditions:

ilimn→ ∞n0andn1n∞;

iilimn→ ∞αn0andn1αn∞;

iii0<lim infn→ ∞βn≤lim supn→ ∞βn<1;

ivlim infn→ ∞rn>0andlimn→ ∞|rn1−rn|0;

v{λn/β} ⊂τ,1−δfor someτ, δ∈0,1andlimn→ ∞λn0.

Then,{xn}and{un}converge strongly to a pointz∈Θwhich is the unique solution of the variational

inequality

Aγf z, zx ≥0, ∀x∈Θ. 3.75

Equivalently, one haszPΘIAγfz.

Proof. PutTnxxfor alln∈Nand for allxC. ThenWnxxfor allxC. The conclusion

follows fromTheorem 3.1.

Corollary 3.4. Let Cbe nonempty closed convex subset of a real Hilbert space H, let {Tn} be an

infinitely many nonexpansive ofCinto itself, and letBbe aβ-inverse-strongly monotone mapping ofCintoHsuch thatΘ : ∩∞n1FTnV IC, B/. Letf be a contraction ofHinto itself with

α∈ 0,1and letAbe a strongly positive linear bounded operator onHwith coefficientγ >0and 0< γ < γ/α. Let{xn},{yn}, and{kn}be sequences generated by

x1xC chosen arbitrary, ynPCxnλnBxn,

knαnxn 1−αnPCxnλnByn ,

xn1nγfxn βnxn1−βn InA Wnkn,n≥1,

3.76

where{Wn}is the sequences generated by1.23, and{n},{αn},{βn}are three sequences in0,1

satisfying the following conditions:

ilimn→ ∞n0andn1n∞;

iilimn→ ∞αn0andn1αn∞;

iii0<lim infn→ ∞βn≤lim supn→ ∞βn<1;

iv{λn/β} ⊂τ,1−δfor someτ, δ∈0,1andlimn→ ∞λn0.

Then, {xn} converges strongly to a point z ∈ Θ which is the unique solution of the variational

inequality

Aγf z, zx ≥0, ∀x∈Θ. 3.77

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Proof. PutFx, y 0 for allx, yCandrn 1 for alln∈NinTheorem 3.1. Then, we have

unPCxnxn. So, byTheorem 3.1, we can conclude the desired conclusion easily.

IfA I, γ ≡1 andγn 1−nβninTheorem 3.1, then we can obtain the following

result immediately.

Corollary 3.5. LetCbe nonempty closed convex subset of a real Hilbert spaceH, letFbe a bifunction fromC×CtoRsatisfying (A1)–(A4), let{Tn}be an infinitely many nonexpansive ofCinto itself, and

letBbe anβ-inverse-strongly monotone mapping ofCintoHsuch thatΘ:∩n1FTnEPF

V IC, B/. Letfbe a contraction ofHinto itself withα∈0,1. Let{xn},{yn},{kn},and{un}

be sequences generated by

x1xC chosen arbitrary,

Fun, y r1

nyun, unxn ≥0, ∀yC,

ynPCunλnBun,

knαnun 1−αnPCunλnByn ,

xn1nfxn βnxnγnWnkn,n≥1,

3.78

where{Wn}is the sequences generated by1.23,{n},{αn}, and {βn}are three sequences in0,1

and{rn}is a real sequence in0,∞satisfying the following conditions:

inβnγn1;

iilimn→ ∞n0andn1n∞;

iiilimn→ ∞αn0andn1αn;

iv0<lim infn→ ∞βn≤lim supn→ ∞βn<1;

vlim infn→ ∞rn>0andlimn→ ∞|rn1−rn|0,

vi{λn/β} ⊂τ,1−δfor someτ, δ∈0,1andlimn→ ∞λn0.

Then,{xn} and {un} converge strongly to a pointz ∈ Θ which is the unique solution of the

variational inequality

zfz, zx ≥0, ∀x∈Θ. 3.79

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Corollary 3.6. LetCbe nonempty closed convex subset of a real Hilbert spaceH, letFbe a bifunction fromC×CtoRsatisfying (A1)–(A4) and let{Tn}be an infinite family of nonexpansive ofCinto

itself such thatΘ:∩∞n1FTnEPF/. Letf be a contraction ofHinto itself withα∈0,1.

Let{xn}and{un}be sequences generated by

x1xC chosen arbitrary,

Fun, y r1

nyun, unxn ≥0, ∀yC,

xn1nfxn βnxnγnWnun,n≥1,

3.80

where {n}, {αn}, and {βn} are three sequences in 0,1, and {rn} is a real sequence in 0,∞

satisfying the following conditions:

inβnγn1;

iilimn→ ∞n0andn1n∞;

iii0<lim infn→ ∞βn≤lim supn→ ∞βn<1;

ivlim infn→ ∞rn>0andlimn→ ∞|rn1−rn|0.

Then,{xn}and{un}converge strongly to a pointz∈Θwhich is the unique solution of the variational

inequality

Aγf z, zx ≥0, ∀x∈Θ. 3.81

Equivalently, one haszPΘIAγfz.

Proof. Put B 0 and {αn} 0 in Corollary 3.5. then yn kn un. The conclusion of

Corollary 3.6can obtain the desired result easily.

4. Application for Optimization Problem

In this section, we shall utilize the results presented in the paper to study the following optimization problem:

min hx,

xC. 4.1

wherehxis a convex and lower semicontinuous functional defined on a closed subsetCof a Hilbert spaceH. We denote byTthe set of solution of4.1. LetFbe a bifunction fromC×C toRdefined byFx, y hyhx. We consider the following equilibrium problem, that is, to findxCsuch that

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It is obvious thatEPF T, whereEPFdenotes the set of solution of equilibrium problem

4.2. In addition, it is easy to see thatFx, ysatisfies the conditionsA1A4inSection 1. Therefore, from theCorollary 3.6, we know the following iterative sequence{xn}defined by

x1 ∈C chosen arbitrary,

hyhun r1 n

yun, unxn

xn1nfxn βnxnγnun,

≥0, ∀yC 4.3

where{n},{βn}, and{γn}are three sequences in0,1,and{rn}is a real sequence in0,∞

satisfying the following conditions:

inβnγn1;

iilimn→ ∞n0 and∞n1n∞;

iii0<lim infn→ ∞βn≤lim supn→ ∞βn<1;

ivlim infn→ ∞rn>0 and limn→ ∞|rn1−rn|0.

Then,{xn}converges strongly to a pointzPTfzof optimization problem4.1.

In special case, we pickfx 0 for allxHandβn0,rn1 ,n1/2 for alln∈N,

thenxn11/2un, and from4.3we obtain a special iterative scheme

hyhun

yun, un−1

2un−1

≥0, ∀yC, n≥2,

hyhu1 yu1, u1−x1 ≥0, ∀yC.

4.4

Then,{un}converges strongly to a solutionzPT0 of optimization problem4.1. In fact, the

zis the minimum norm point on theT.

Therefore, we consider a special from of optimization problem 4.1 which is as follows:i.e., is takinghx x

min x,

xC. 4.5

In fact, the solution of optimization problem4.4is named the minimum norm point on the closed convex setC. From iterative algorithm4.4we obtain the following iterative algorithm4.5, and{un}is defined by

yun

yun, un− 1

2un−1

≥0, ∀yC, n≥2, yu1

yu1, u1−x1

≥0, ∀yC

4.6

for any initial guessx1∈H. Then,{un}converges strongly to a minimum norm point on the

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Acknowledgments

The first author was supported by the Faculty of Applied Liberal Arts RMUTR Research Fund and King Mongkut’s Diamond scholarship for fostering special academic skills by KMUTT. The second author was supported by the Thailand Research Fund and the Commission on Higher Education under Grant no. MRG5180034. Moreover, the authors would like to thank Professor Somyot Plubiteng for providing valuable suggestions, and they also would like to thank the referee for the comments.

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