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Linear Algebra and its Applications
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Structure relations for orthogonal polynomials on the unit
circle
A. Branquinho
a, M.N. Rebocho
b,c,∗
aCMUC, Department of Mathematics, University of Coimbra, Largo D. Dinis, 3001-454 Coimbra, Portugal bDepartment of Mathematics, University of Beira Interior, 6201-001 Covilhã, Portugal
cCMUC, University of Coimbra, 3001-454 Coimbra, Portugal
A R T I C L E I N F O A B S T R A C T Article history:
Received 27 October 2011 Accepted 31 January 2012 Available online 25 February 2012 Submitted by Richard Brualdi AMS classification: 33C45
42C05 Keywords:
Orthogonal polynomials on the unit circle Hermitian linear functionals
Recurrence relations Structure relations
Semi-classical linear functionals
Structure relations for orthogonal polynomials with respect to Her-mitian linear functionals are studied. Firstly, we prove that semi-classical orthogonal polynomials satisfy structure relations of the following type:s1 k=0βn,kPn+s1−k+ s2 k=0γn,kzkPn∗−1−k = r1 k=0 αn,kPn[1]+s1−k+ r2 k=0ηn,k P∗n+r 2−k
,where s1,s2,r1,r2are
inte-gers (specified in the text), Pn∗ is the reversed polynomial of Pn,
Pn[1] = Pn+1/(n+1), andβn,k, γn,k, αn,k, ηn,kare complex num-bers. Then, we study the semi-classical character of sequences of or-thogonal polynomials{Rn}, {Pn}, connected through a structure
re-lation of the following type:s1
k=0βn,kRn+s1−k+ s2 k=0γn,kR∗n+s2−k = r1 k=0αn,kPn[1]+r1−k+ r2 k=0ηn,k Pn∗+r 2−k
, where the integers s1,s2,r1,r2satisfy some natural conditions specified in the text.
© 2012 Elsevier Inc. All rights reserved.
1. Introduction
The so-called structure relations for orthogonal polynomials, that is, finite-type relations involving sequences of orthogonal polynomials and its derivatives, have been widely studied in the literature of orthogonal polynomials (see, for example, [2,3,18] and the list of references therein). Such a type of relations appear in the framework of Sobolev orthogonal polynomials, within the study of coher-ence of measures (see [4,13,19,20]). They also appear in problems concerning quasi-orthogonality and quadrature formulas (see [18,21]), where well-known connections to linear combinations of orthog-onal polynomials emerge.
∗Corresponding author at: Department of Mathematics, University of Beira Interior, 6201-001 Covilhã, Portugal. Tel.: +351 275 329 256; fax: +351 275 319 732.
E-mail addresses:[email protected](A. Branquinho),[email protected],[email protected](M.N. Rebocho). 0024-3795/$ - see front matter © 2012 Elsevier Inc. All rights reserved.
Structure relations and linear combinations of orthogonal polynomials were studied in a vast list of papers, and we refer the reader to [2,3,5,7,16]. The subject matter in [2,5,16] is the modification of measures. In [16] it was proven that the measures of orthogonality of two sequences of orthogonal polynomials on the unit circle, say
{
Pn}
,{
Rn}
, related throughl(n) j=0
β
n,jRn−j=
k(n) j=0α
n,jPn−j,
n1,
where
β
n,j, α
n,j∈ C
and l(
n) +
k(
n)
n/
3,
are a rational modification of each other. Relations ofthe above type arise in problems of signal analysis and linear prediction of stochastic processes (cf. [16, Section 1]).
Concerning orthogonality on the real line, a well-known topic of research in the literature is to establish the semi-classical character of sequences of orthogonal polynomials in terms of structure relations (see [3,6,12,17,18] and the references therein). Unlike orthogonality on the real line, for hermitian orthogonality (also called orthogonality on the unit circle), this topic has not been getting much attention. We refer the reader to [14,23], were structure relations for semi-classical orthogonal polynomials on the unit circle are deduced.
In general terms, in the present paper we are interested in the study of the semi-classical character of sequences of orthogonal polynomial on the unit circle satisfying some structure relations (these will be made precise throughout the text). We prove that semi-classical orthogonal polynomials satisfy structure relations of the following type:
s1 k=0
β
n,kPn+s1−k+
s2 k=0γ
n,kzkPn∗−1−k=
r1 k=0α
n,kPn[1+]s1−k+
r2 k=0η
n,k P∗n+r 2−k,
where the
β
’s,γ
’s,α
’s and theη
’s are complex numbers, P∗n are the reversed polynomials (see its definition in Section 2), P[n1]denotes the monic polynomial of degree n corresponding to Pn,
Pn[1]=
Pn+1
/(
n+
1), ∀
n0, the integers s1,
s2and r1,
r2depend on the degrees of the polynomials involved in the corresponding distributional equation satisfied by the functional of orthogonality (see Section 3). Furthermore, we study sequences of orthogonal polynomials,{
Rn}, {
Pn}
, related throughs1 k=0
β
n,kRn+s1−k+
s2 k=0γ
n,kR∗n+s2−k=
r1 k=0α
n,kPn[1]+r1−k+
r2 k=0η
n,k Pn∗+r 2−k,
(1)where, for the sake of compatibility, the integers s1
,
s2,
r1,
r2satisfy some natural conditions (these shall be specified throughout the text). Under some conditions, stated in Theorem 2, we deduce the semi-classical character of{
Pn}
and{
Rn}
. Further, we deduce a matrix connecting formula betweenϕ
n=
Pn Pn∗ Tandψ
n=
Rn R∗nT, with T denoting the transpose operator (see Theorem 2).
Note that when s1
=
r1=
0 and theγ
’s and theη
’s are all zero in (1), we get Rn=
Pn+ 1n+1
, ∀
n0. In this case it is known [15] that Pn=
zn, ∀
n 0,
thus Rn=
Pn, ∀
n 0. When s1=
r1=
2,β
n,1= β
n,2=
0 and theγ
’s and theη
’s are all zero, we obtain a structure relation of the following type: Rn+1=
Pn+2 n+
2+ τ
n,1 Pn+1 n+
1+ τ
n,2 Pn n,
n1,
(2)that is,
(
Pn,
Rn)
is a generalized coherent pair on the unit circle (according to the definition ofgener-alized pair on the real line studied in [13]). When s1
=
r1=
1,β
n,1=
0, and theγ
’s and theη
’s are all zero, we obtain a structure relation of the following type:Rn
=
Pn+1 n
+
1+ τ
nPn
that is,
(
Pn,
Rn)
constitute a coherent pair on the unit circle. In such a case,{
Pn}
and{
Rn}
aresemi-classical (see [4, Theorem 4]). Furthermore, the linear functionals of orthogonality of
{
Rn}
and{
Pn}
are arational modification of each other. We remark that such a relationship between the linear functionals follows from the application of the techniques on quasi-orthogonality [1] to a connecting formula
zA
ψ
n=
Mnϕ
n, ϕ
n=
Pn Pn∗ T, ψ
n=
Rn R∗n T,
n1,
where A is a polynomial that does not depend on n, andMnis a matrix whose entries are bounded
degree polynomials.
The structure of the paper is as follows. In Section2we give the definitions and state the basic results which will be used in the forthcoming sections. In Section3we deduce structure relations for semi-classical orthogonal polynomials. In Section4we study sequences of orthogonal polynomials connected through structure relations such as (1). In Section5we present some examples of orthogonal polynomials on the unit circle related through (1).
2. Preliminary results and notations
Let
T = {
z∈ C : |
z| =
1}
be the unit circle, let=
span{
zk:
k∈ Z}
be the linear space of Laurent polynomials with complex coefficients, and letP =
span{
zk:
k 0}
be the space of polynomials with complex coefficients. Given a linear functional u:
→ C,
and the sequence of moments(
cn)
n∈Zof u,
cn=
u, ξ
n,
n∈ Z,
c0=
1,
let us define the minors of the Toeplitz matrix= (
ck−j)
by k=
c0. . .
ck... ... ...
c−k. . .
c0,
0=
c0,
−1=
1,
k∈ N.
u is said to be Hermitian if c−n
= ¯
cn, ∀
n 0,
and quasi-definite (respectively, positive definite) if n=
0, ∀
n 0 (respectively,n>
0), ∀
n 0 (see [22]). We will denote byH the set of Hermitian linear functionals defined on .Definition 1. Let
{
Pn}
be a sequence of complex polynomials with deg(
Pn) =
n, and let u∈
H.{
Pn}
is said to be a sequence of orthogonal polynomials with respect to u if
u,
Pn(
z)
z−k=
0,
k=
0, . . . ,
n−
1,
n1,
u,
Pn(
z)
z−n=
en,
en=
0,
n=
0,
1, . . . .
(4) If Pn
(
z) =
zn+
lower degree terms, then{
Pn}
will be called a sequence of monic orthogonalpolyno-mials, and we will denote it by MOPS.
It is well known that a necessary and sufficient condition for u to be quasi-definite is the existence of a sequence of orthogonal polynomials with respect to u (see [9,22]).
If the linear functional u is positive-definite, then it has an integral representation given in terms of a nontrivial probability measure
μ
with infinite support onT
,u
,
einθ=
1 2π
2π 0 e inθdμ(θ),
n∈ Z,
and the corresponding MOPS will also be called the MOPS with respect to
μ
.Given a polynomial B
(
z) =
mk=0bkzkand p∈ N
, the polynomial B∗p is defined by B∗p(
z) =
zpB
(
1/
z),
that is, B∗p(
z) =
mk=0bkz−k+p.
Throughout the paper we will omit the index p in B∗p if,and only if, the degree of B is exactly p
.
Lemma 1. Let P
∈ P
and m∈ N.
The following equalities hold:P∗m
(
z)
∗m=
P(
z),
(
zP(
z))
∗m= (
P(
z))
∗m−1,
z
(
P∗m(
z))
=
mP∗m(
z) − (
P(
z))
∗m−1.
For a sequence of orthogonal polynomials
{
Pn}
, the polynomials Pn∗are called reversed or reciprocalpolynomials, and they satisfy
u,
Pn∗(
z)
z−k=
0,
k=
1, . . . ,
n,
u,
Pn∗(
z) =
en,
n=
0,
1, . . . ,
where enis the same as in (4).
It is well-known that MOPS on the unit circle satisfy the following recurrence relations (the Szeg ˝o forward recurrence relation, see [11]),
ϕ
n=
Anϕ
n−1, ϕ
n=
⎡ ⎣Pn Pn∗ ⎤ ⎦,
An=
⎡ ⎣ z an¯
anz 1 ⎤ ⎦,
an=
Pn(
0),
n∈ N.
Therefore, for all k
1,
ϕ
n+k=
k−1 l=0An+k−l
ϕ
n.
(5)For u
∈
H and A∈ P,
we define Au,
f=
u,
A(
z)
f(
z),
f∈
,
(
A+ ¯
A)
u,
f=
u,
A(
z) + ¯
A(
1/
z)
f(
z),
f∈
,
Du,
f= −
iu,
zf(
z),
f∈
.
Notice that if u∈
H,
then(
A+ ¯
A)
u∈
H.
Definition 2 (see [23]). Let u
∈
H be quasi-definite. u is said to be semi-classical if there exist A,
B∈ P
, A≡
0, such thatD(
Au) =
Bu.
The sequence of orthogonal polynomials with respect to u is said to be semi-classical.Taking into account [1, Theorem 4.1], in [4] the following was proved.
Theorem 1 [4]. Let
{
Pn}
be a MOPS on the unit circle and{
Pn∗}
be the sequence of reversed polynomials.Let
{
Pn}
satisfy a structure relation with bounded degree polynomials, n1,
z
(
z;
n)
Pn(
z) =
G(
z;
n)
Pn(
z) +
H(
z;
n)
Pn∗(
z)
z
(
z;
n)(
Pn∗)
(
z) =
S(
z;
n)
Pn(
z) +
T(
z;
n)
Pn∗(
z).
Then,
(
z;
n) =
(
z;
1)
does not depend on n. Let p=
max{
deg(
G(
z;
n)),
deg(
H(
z;
n))+
1,
deg(
S(
z;
n)),
deg(
(
z;
1) −
T(
z;
n))}, ∀
n1.
If there exists n02p such that deg(
(
z;
1) −
T(
z;
n0)) =
p,
then
{
Pn}
is semi-classical.3. Structure relations for semi-classical orthogonal polynomials Hereafter we shall adopt the conventionml
· =
0 whenever m<
l.
Lemma 2. Let
{
Pn}
be a MOPS with respect to a semi-classical Hermitian linear functional u that satisfiesD
(
Au) =
Bu. Let deg(
A) =
s,
deg(
B) =
s,
s1.
Assume that(
iB+
kA)(
0) =
0,
k=
s, . . . ,
n,
n∈
N
, when s<
s, and A(
0) =
0 when ss.
Then, there exist sequences(β
n,k), (γ
n,k)
,(α
n,k)
and(η
n,k)
such that,
∀
nmax{
s,
s} +
1,s k=0
β
n+s,kPn+s−k+
s−s−2 k=0γ
n−1,kzkPn∗−1−k=
min(s,s−1) k=0α
n+s,kPn[1+]s−k+
s−s k=0η
n+s,k P∗n+s−s−k.
(6)Proof. Case I: deg
(
A) <
deg(
B)
.Let p
=
s−
s. Then,∀
ns,
(6) reads ass k=0
β
n+s,kPn+s−k+
p−2 k=0γ
n−1,kzkPn∗−1−k=
s k=0α
n+s,kPn[1+]s−k.
(7) We write Pn+l=
n+l j=0 cn+l,jPn[1+]l−j,
l=
0, . . . ,
s,
zkPn∗−1−k=
n−1 j=0 cnk−1,jPn[1−]1−j,
k=
0, . . . ,
p−
2.
Thus, s k=0β
n+s,kPn+s−k+
p−2 k=0γ
n−1,kzkPn∗−1−k=
P[ 1] n+s+
n+s−1 j=0μ
n+s−1,jPn[1+]s−1−j,
(8) whereμ
n+s−1,j=
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ cn+s,j+1+
j+1 k=1β
n+s,kcn+s−k,j+1−k,
j=
0, . . . ,
s−
1,
cn+s,j+1+
s k=1β
n+s,kcn+s−k,j+1−k+
p−2 k=0γ
n−1,kcnk−1,j−s,
j=
s, . . . ,
n+
s−
1.
(9)Let us multiply (8) by z−k+1and apply Au. Then, the left-hand side gives us, for k
=
s+
p, . . . ,
n,
u,
⎛ ⎝s k=0β
n+s,kPn+s−k+
p−2 k=0γ
n−1,kzkPn∗−1−k ⎞ ⎠ A z−k+1=
0,
(10) where p1.
The right-hand side gives us, after using the definition of the operatorD as well as D
(
Au) =
Bu,A u
,
Pn[1+]s−1−jz−k+1=
1n
+
s−
j(
iB+
kA)
u,
Pn+s−jzTherefore, since max
{
deg(
iB+
kA),
k1} =
deg(
B)
, as deg(
A) <
deg(
B),
there followsA u
,
Pn[1+]s−1−jz−k+1=
0,
k=
s, . . . ,
n+
s−
j−
1.
(11) From (10) and (11) (note that s=
s+
p) we obtain that the coefficientsμ
n+s−1,jin (8) satisfy0
=
n+s−1 j=n+s−kμ
n+s−1,jξ
k,j,
k=
s, . . . ,
n,
(12) whereξ
k,j=
(
iB+
kA)
u,
Pn+s−jz−k n+
s−
j.
Our goal is to prove that there exist
β
n+s,k,
k=
1, . . . ,
s, γ
n−1,k,
k=
0, . . . ,
p−
2,
such that in(8) one has
μ
n+s−1,s= μ
n+s−1,s+1= · · · = μ
n+s−1,n+s−1=
0.
We expand (12) as ⎡ ⎢ ⎢ ⎢ ⎢ ⎣ξ
n,s· · · ξ
n,n−p...
...
ξ
s+p,n−p ⎤ ⎥ ⎥ ⎥ ⎥ ⎦ ⎡ ⎢ ⎢ ⎢ ⎢ ⎣μ
n+s−1,s...
μ
n+s−1,n−p ⎤ ⎥ ⎥ ⎥ ⎥ ⎦+
⎡ ⎢ ⎢ ⎢ ⎢ ⎣ξ
n,n−p+1· · · ξ
n,n+s−1...
...
ξ
s+p,n−p+1· · · ξ
s+p,n+s−1 ⎤ ⎥ ⎥ ⎥ ⎥ ⎦ ⎡ ⎢ ⎢ ⎢ ⎢ ⎣μ
n+s−1,n−p+1...
μ
n+s−1,n+s−1 ⎤ ⎥ ⎥ ⎥ ⎥ ⎦=
⎡ ⎢ ⎢ ⎢ ⎢ ⎣ 0...
0 ⎤ ⎥ ⎥ ⎥ ⎥ ⎦.
(13) Note thatμ
n+s−1,n−p+1= μ
n+s−1,n−p+2= · · · = μ
n+s−1,n+s−1=
0 (14) impliesμ
n+s−1,s= μ
n+s−1,s+1= · · · = μ
n+s−1,n−p=
0,
because if (14) holds, then (13) is given by ⎡ ⎢ ⎢ ⎢ ⎢ ⎣
ξ
n,s· · · ξ
n,n−p...
...
ξ
s+p,n−p ⎤ ⎥ ⎥ ⎥ ⎥ ⎦ ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣μ
n+s−1,s...
μ
n+s−1,n−p ⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦=
⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ 0...
0 ⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦,
(15)where the matrix of the system (15) is nonsingular (upper triangular), as the elements of the diagonal are given by
ξ
n−l,s+l=
u, (
iB+ (
n−
l)
A)
Pn−lz−n+ln
−
l,
l=
0,
1, . . . ,
n− (
p+
s),
and since(
iB+ (
n−
l)
A)(
0) =
0,
l=
0,
1, . . . ,
n− (
s+
p),
there follows thatξ
n−l,s+l=
0, ∀
ns.
Let us return to (14). Taking into account (9) one expands (14) as Gnp,s−1Bnp,s
= −
cn+s,n−p+2· · ·
cn+s,n+s!T
with Gnp,s−1
=
⎡ ⎢ ⎢ ⎢ ⎢ ⎣ cn+s−1,n−p+1· · ·
cn,n−p−s+2 cn0−1,n−p+1−s· · ·
c p−2 n−1,n−p+1−s...
...
...
...
...
...
cn+s−1,n+s−1· · ·
cn,n c0n−1,n−1· · ·
c p−2 n−1,n−1 ⎤ ⎥ ⎥ ⎥ ⎥ ⎦ Bp n,s=
β
n+s,1· · · β
n+s,sγ
n−1,0· · · γ
n−1,p−2 !T.
Note thatGnp,s−1is a
(
s+
p−
1) × (
s+
p−
1)
matrix.Let us discuss the system (16). We denote byG
˜
np,s−1the(
s+
p−
1) × (
s+
p)
matrix given by ⎡ ⎢ ⎢ ⎢ ⎢ ⎣−
cn+s,n−p+2 Gnp,s−1...
−
cn+s,n+s ⎤ ⎥ ⎥ ⎥ ⎥ ⎦.
If det
(
Gpn,s−1) =
0, then (16) has a solution, and this means that there existβ
n+s,1, . . . , β
n+s,ssuchthat
μ
n+s−1,n−p+1= μ
n+s−1,n+1= · · · = μ
n+s−1,n+s−1=
0,
thus, from our previous discussion, there followsμ
n+s,s= μ
n+s,s+1= · · · = μ
n+s,n−p=
0,
and (7) holds.
If det
(
Gnp,s−1) =
0,
then (16) is possible if, and only if, the matricesG p n,s−1, ˜
Gp
n,s−1have precisely the same number of independent rows.
Let us assume, without loss of generality, that the ith and the jth rows ofGn,s−1are linearly depen-dent, that is,
cn+s−1,n+i cn+s−1,n+j
=
cn+s−2,n+i−1 cn+s−2,n+j−1= · · · =
cn,n+i−(s−1) cn,n+j−(s−1)= · · · =
cn0−1,n−p+1−i cn0−1,n−p+1−j= · · · =
c p−2 n−1,n−p+1−i cnp−2−1,n−p+1−j.
(17)Note that n is arbitrary and the algorithm described above can be carried out to n
+
1, thus we get the same proportion as above using the matrixGpn+1,s−1, thus we can take n+
1 in (17), and we conclude that the ith and the jth rows ofG˜
np,s−1, are linearly dependent. With a similar reasoning one concludes thatGnp,s−1, ˜
Gp
n,s−1have precisely the same number of independent rows. Consequently, (16) is possi-ble and, similarly to the previous discussion in the case det
(
Gpn,s−1) =
0, we conclude that (7) holds. Case II: deg(
A)
deg(
B)
.Let q
=
s−
s. Then,∀
ns+
1,
(6) reads ass k=0
β
n+s,kPn+s−k=
s−q−1 k=0α
n+s,kP[n1+]s−k+
q k=0η
n+s,k Pn∗+q−k.
(18)Let us write Pn[1+]s−l
=
n+s−l j=0 cn+s−l,jPn+s−l−j,
l=
0, . . . ,
s−
q−
1,
(
Pn∗+q−l)
=
n+q−l−1 j=0 cn∗+q−l,jPn+q−l−1−j,
l=
0, . . . ,
q.
Thus, s−q−1 k=0α
n+s,kPn[1+]s−k+
q k=0η
n+s,k P∗n+q−k=
Pn+s+
n+s−1 j=0μ
n+s−1,jPn+s−1−j (19)where, for j
=
n, . . . ,
n+
s−
1,
theμ
n+s−1,j’s are given byμ
n+s−1,j=
cn+s,j+1+
s−q−1 k=1α
n+s,kcn+s−k,j+1−k+
1+q k=1η
n+s,kc∗n+q−k,j+q−s−k+1.
(20) Let us multiply (19) by z−k+1and apply Au. Then, the left-hand side gives us
(
iB+
kA)
u,
⎛ ⎝s−q−1 k=0α
n+s,k Pn+s−k+1 n+
s−
k+
1+
q k=0η
n+s,kPn∗+q−k ⎞ ⎠ z−k,
where we used the definition ofD, as well as D
(
Au) =
Bu. Therefore, since max{
deg(
iB+
kA),
k 1} =
deg(
A)
, as deg(
A)
deg(
B),
there follows, for k=
s+
1, . . . ,
n,
(
iB+
kA)
u,
⎛ ⎝s−q−1 k=0α
n+s,k Pn+s−k+1 n+
s−
k+
1+
q k=0η
n+s,kPn∗+q−k ⎞ ⎠ z−k=
0.
(21)From the right-hand side there follows
A u,
Pn+s−1−jz−k+1=
0,
k=
s+
1, . . . ,
n+
s−
j−
1.
(22)Thus, taking into account (21) and (22) we obtain that the coefficients
μ
n+s−1,jin (19) satisfy0
=
n+s−1 j=n+s−k
μ
n+s−1,jξ
k,j,
k=
s+
1, . . . ,
n,
(23)where
ξ
k,j=
Au,
Pn+s−1−jz−k+1.
As in the previous case, one can prove that there exist
α
n+s,k,
k=
1, . . . ,
s−
q−
1, η
n+s,k,
k=
0
, . . . ,
q,
such that in (19) one hasμ
n+s−1,s= μ
n+s−1,s+1= · · · = μ
n+s−1,n+s−1=
0.
We expand (23) as ⎡ ⎢ ⎢ ⎢ ⎢ ⎣ξ
n,s· · · ξ
n,n−1...
...
ξ
s+1,n−1 ⎤ ⎥ ⎥ ⎥ ⎥ ⎦ ⎡ ⎢ ⎢ ⎢ ⎢ ⎣μ
n+s−1,s...
μ
n+s−1,n−1 ⎤ ⎥ ⎥ ⎥ ⎥ ⎦+
⎡ ⎢ ⎢ ⎢ ⎢ ⎣ξ
n,n· · · ξ
n,n+s−1...
...
ξ
s+1,n· · · ξ
s+1,n+s−1 ⎤ ⎥ ⎥ ⎥ ⎥ ⎦ ⎡ ⎢ ⎢ ⎢ ⎢ ⎣μ
n+s−1,n...
μ
n+s−1,n+s−1 ⎤ ⎥ ⎥ ⎥ ⎥ ⎦=
⎡ ⎢ ⎢ ⎢ ⎢ ⎣ 0...
0 ⎤ ⎥ ⎥ ⎥ ⎥ ⎦.
(24)Note that
μ
n+s−1,n= μ
n+s−1,n+1= · · · = μ
n+s−1,n+s−1=
0 (25) impliesμ
n+s−1,s= μ
n+s−1,s+1= · · · = μ
n+s−1,n−1=
0,
because if (25) holds, then (24) is given by ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣
ξ
n,s· · · ξ
n,n−1...
...
ξ
s+1,n−1 ⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦ ⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣μ
n+s−1,s...
μ
n+s−1,n−1 ⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦=
⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ 0...
0 ⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦,
(26)where the matrix of the system (26) is nonsingular (upper triangular), as the elements of the diagonal are given by
ξ
n−l,s+l=
u,
APn−l−1z−n+l+1,
l=
0,
1, . . . ,
n− (
s+
1),
and since A(
0) =
0,
there follows thatξ
n−l,s+l=
0, ∀
ns+
1.
Let us return to (25). Taking into account (20) one expands (25) as Gn,s−1Bn,s
= −
cn+s,n+1· · ·
cn+s,n+s !T,
(27) with Gn,s−1=
⎡ ⎢ ⎢ ⎢ ⎢ ⎣ cn+s−1,n· · ·
cn+q+1,n+q−s+2 c∗n+q−1,n+q−s· · ·
cn∗−1,n−s...
...
...
...
...
...
cn+s−1,n+s−1· · ·
cn+q+1,n+q+1 c∗n+q−1,n+q−1· · ·
cn∗−1,n−1 ⎤ ⎥ ⎥ ⎥ ⎥ ⎦ Bn,s=
α
n+s,1· · · α
n+s,s−q−1η
n+s,0· · · η
n+s,q !T.
Note thatGn,s−1is a s
×
s matrix.The discussion of the system (27) is similar to the one in case I, thus we conclude that in (19) one has
μ
n+s−1,s= μ
n+s−1,s+1= · · · = μ
n+s−1,n+s−1=
0, hence (18) holds.Remark 1. If deg
(
B) =
deg(
A) +
1,
that is, s=
s+
1, then (6) is given bys k=0
β
n+s,kPn+s−k=
s k=0α
n+s,kPn[1+]s−k, ∀
ns+
1.
4. Orthogonal polynomials related through (1)
Given the MOPS
{
Pn}
and{
Rn}
, in the sequel we will use the vectors defined byϕ
n=
⎡ ⎣Pn Pn∗ ⎤ ⎦, ψ
n=
⎡ ⎣Rn R∗n ⎤ ⎦,
n0.
(28)Notice that
ϕ
nandψ
nsatisfy the recurrence relationsϕ
n=
Anϕ
n−1, ψ
n=
Bnψ
n−1,
n1,
where An=
⎡ ⎣ z an anz 1 ⎤ ⎦,
Bn=
⎡ ⎣ z bn bnz 1 ⎤ ⎦,
with an=
Pn(
0)
and bn=
Rn(
0).
In what follows we will denote by X(i,j)the
(
i,
j)
entry of a matrix X.Theorem 2. Let
{
Rn}, {
Pn}
be two sequences of monic orthogonal polynomials and let{ϕ
n}
and{ψ
n}
bethe corresponding sequences defined in (28). Let
{
Rn}, {
Pn}
be related through (1),∀
n0,
s1 k=0β
n,kRn+s1−k+
s2 k=0γ
n,kR∗n+s2−k=
r1 k=0α
n,kPn[1+]r1−k+
r2 k=0η
n,k Pn∗+r 2−k,
where the integers s1
,
s2,
r1,
r2satisfy s1=
r1, max{
s2,
r2} <
s1.
Then, the following statements hold:(a) there exist A
∈ P
and matricesXnwith polynomial entries such thatzA
ϕ
n=
Xnϕ
n,
n1.
(29) Further, let p=
max"degX(1,1) n,
degX(1,2) n+
1,
degX(2,1) n,
degA−
X(2,2) n #,
n1.
If∃
n02p such that deg(
A−
Xn(20,2)) =
p,
then{
Pn}
is semi-classical.(b) there exist Kn
∈ P
and non-singular matricesTnwith polynomial entries such thatψ
nandϕ
narerelated trough
zAKn
ψ
n=
Tnϕ
n,
n1.
(30)where A is the same as in (29).
(c) there exist A1
∈ P
and matricesUnwith polynomial entries such thatzA1
ψ
n=
Unψ
n,
n1.
(31) Further, let p=
max"degU(1,1) n,
degU(1,2) n+
1,
degU(2,1) n,
degA1−
Un(2,2) #,
n1.
If∃
n02p such that deg(
A1−
Un(20,2)) =
p,
then{
Rn}
is semi-classical.Proof. If we apply the
∗
n+s1 operator to (1) and then write the resulting equation (after using therelations from Lemma1) together with (1) in the matrix form, we get
s1 k=0 En,k
ψ
n+k=
r1+1 k=0 Fn,kϕ
n+k+
r1+1 k=0 Gn,kϕ
n+k with En,k=
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ $β
n,s1−kγ
n,s2−kγ
n,s2−kz s1−kβ
n,s1−kz s1−k %,
k=
0, . . . ,
s2 $β
n,s1−k 0 0β
n,s1−kzs1−k %,
k=
s2+
1, . . . ,
s1,
Fn,k
=
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ $ 0 0η
n,r2−k(
n+
k)
z r1+1−kα
n,r1+1−kz r1+1−k %,
k=
0, . . . ,
r2 $ 0 0 0α
n,r1+1−kzr1+1−k %,
k=
r2+
1, . . . ,
r1+
1,
Gn,k=
⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ ⎡ ⎣ αn,nr1++k1−kη
n,r2−k−η
r2−kz r1+2−k−
αn,r1+1−k n+k z r1+2−k ⎤ ⎦,
k=
0, . . . ,
r2 $αn,r1+1−k n+k 0 0−
αn,nr1++k1−kzr1+2−k %,
k=
r2+
1, . . . ,
r1+
1,
where, by convention,α
n,r1+1=
0.
Using the recurrence relations (5) for
ϕ
nas well as forψ
n, with the convention&n l=m
· =
I whenever m>
n, there follows Hnϕ
n=
Jnϕ
n+
Knψ
n,
n1,
(32) with Hn=
s1+1 k=0 Gn,k k−1 l=0 An+k−l,
Jn= −
s1+1 k=0 Fn,k k−1 l=0 An+k−l−
s1+1 k=0 Gn,k ⎛ ⎝k−1 l=0 An+k−l ⎞ ⎠,
Kn=
s1 k=0 En,k k−1 l=0 Bn+k−l.
If we multiply (32) by adj
(
Kn)
there followsLn
ϕ
n=
Mnϕ
n+
Knψ
n,
n1.
(33)with non-singular matricesLn
,
Mn,
and a polynomial Kngiven byLn
=
adj(
Kn)
Hn,
Mn=
adj(
Kn)
Jn,
Kn=
det(
Kn).
To deduce (29) we start by writing (33) to n
+
1 and use the recurrence relations, thus obtainingLn,1
ϕ
n=
Mn,1ϕ
n+ ξ
nψ
n (34)with
Ln,1
=
adj(
Bn+1)
Ln+1An+1,
Mn,1
=
adj(
Bn+1)(
Mn+1An+1−
Ln+1An+1),
ξ
n=
Kn+1det(
Bn+1).
The elimination of
ψ
nbetween (33) and (34) gives usNn
ϕ
n= (ξ
nMn−
KnMn,1)ϕ
n,
Nn= ξ
nLn−
KnLn,1.
(35)After multiplying (35) by adj
(
Nn),
we getdet
(
Nn)ϕ
n=
Snϕ
n,
Sn=
adj(
Nn)(ξ
nLn−
KnLn,1).
Taking into account Theorem1, we get (29) as well as the semi-classical character of the MOPS
{
Pn}
.(30) follows by eliminating
ϕ
n between (33) and (29), zAKnψ
n=
Tnϕ
n,
Tn=
LnXn−
zAMn.
To obtain (31) we take derivatives on (30), then we multiply the resulting equation by zA and use (29), thus
zA
(
zAKn)
ψ
n+ (
zA)
2Knψ
n= (
zATn+
TnXn)ϕ
n.
(36)The multiplication of (36) by det
(
Tn)
and the use of relation (30) in the equivalent formdet
(
Tn)ϕ
n=
zAKnadj(
Tn)ψ
nyields
(
zA)
2Kndet(
Tn)ψ
n=
Vnψ
n,
with
Vn
= (
zATn+
TnXn)
zAKnadj(
Tn) −
zA(
zAKn)
det(
Tn).
Taking into account Theorem1, we get (31) as well as the semi-classical character of the MOPS
{
Rn}
.Remark 2. If we take r1
1 withβ
n,k=
0,
k=
1, . . . ,
r1,
and all theγ
’s andη
’s equal to zero in (1), we have Rn+r1=
r1 k=0α
n,kPn[1+]r1−k, α
n,0=
1,
n0,
thus we obtain zAA˜
ψ
n=
Tnϕ
n,
n1,
withA˜
=
zr1andTnmatrices with bounded degree polynomial entries. Taking into account the results
of [1] on
T
-quasi-orthogonality, there follows that if{
Pn}
is semi-classical, then{
Rn}
is alsosemi-classical, since the corresponding linear functionals are a rational modification of each other (the proof follows the same technique as in [4, Theorem 4]). In particular, if r1
=
1, we get Theorem 4 in [4], that states the semi-classical character of coherent pairs of linear functionals on the unit circle. Corollary 3. A MOPS{
Pn}
satisfying (6) also satisfieszA
ϕ
n=
Xnϕ
n, ϕ
n=
⎡ ⎣Pn Pn∗ ⎤ ⎦,
n1,
with A∈ P
and matricesXn. Thus, forp
=
max"degX(1,1) n,
degX(1,2) n+
1,
degX(2,1) n,
degA−
X(2,2) n #,
n1,
if∃
n02p such that deg(
A−
Xn(20,2)) =
p,
then{
Pn}
is semi-classical.Taking into account the previous results we state the theorem that follows.
Theorem 3. Under the conditions of Lemma2and Corollary3, a necessary and sufficient condition for a Hermitian linear functional to be semi-classical is that the corresponding MOPS,
{
Pn}
, satisfies structurerelations such as (6). 5. Examples
The case s1
=
r1=
1 withβ
n,1=
0,
and all theγ
’s andη
’s equal to zero in (1),Rn
=
Pn+1
n
+
1+ α
n−1,1 Pnwas analyzed in [4], where some examples of monic orthogonal polynomial sequences satisfying (37) are given.
Let us now consider the case s1
=
r1=
1 withα
n,1=
0,
n0,
and all theγ
’s andη
’s equal to zero in (1), which gives a structure relation of the following type:Rn+1
+ β
nRn=
Pn+2
n
+
2, β
n=
0,
n0.
(38)In what follows we denote by u
,
v the Hermitian linear functionals of orthogonality corresponding to the MOPS{
Pn}
and{
Rn},
respectively.Example 1. Let u be the normalized Lebesgue functional. Then, Pn
(
z) =
zn,
n0,
and (38) becomesRn+1
+ β
nRn=
zn+1,
n0.
Applying v in both hand sides of the above expression, we get
v,
zn+1=
0,
n 1.
Thus, the moments of v, which we denote by vn, satisfy vn=
0,
for all n 2.
Let us assume, without loss ofgenerality, that v0
=
1. To compute v1we use R1+ β
0R0=
z, from which we get, by applying v,β
0v0=
v1. Hence, vn=
⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩ 1,
n=
0β
0,
n=
1 0,
n2.
Therefore, the Toeplitz matrix associated with v is tridiagonal,
=
⎡ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎣ 1β
0β
0 1...
... ... ...
β
0 1β
0... ... ...
⎤ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎦.
According to [8], a necessary and sufficient condition for v to be quasi-definite is
|β
0| = −(
2 cos(
πk n+1))
−1
,
k=
1, . . . ,
n,
and n1
.
v is positive definite if, and only if,|β
0
|
1/
2 (see [10, Eq. (7)]). The linear functional v is a transformation of u, given asv
= (
1+ β
0z+ β
0z−1)
u.
(39)In the positive definite case, the transformation (39) is expressed, in terms of the corresponding mea-sures, as d
σ (θ) = (
1+ β
0eiθ+ β
0e−iθ)
dθ
2π
, θ ∈ [
0,
2π[,
that is, dσ (θ) = (
1+
2|β
0|
cos(θ − θ
0))
dθ
2π
, θ ∈ [
0,
2π[,
whereθ
0=
arg(β
0).
Example 2. Let u be the positive definite linear functional associated with the Bernstein–Szeg ˝o measure d
μ(θ) =
1|
z+
c|
2 dθ
2π
,
z=
e iθ, |
c| <
1,
c=
0. Then, P 0(
z) =
1,
Pn(
z) =
zn−1(
z+
c),
n1,
and (38) becomes
Rn+1
+ β
nRn=
zn+1+
cn
+
1n
+
2zn
,
n0
.
(40)Applying v in both hand sides of the above expression, we get the following identity for the moments of v, vn+1
+
c n+
1 n+
2vn=
0,
n1,
thus vn+1=
2 n+
2(−
c)
nv 1,
n1.
Notice that we assume v0
=
1.
To compute v1we take n=
0 in (40), thus R1=
z+
c/
2− β
0, from which we get, by applying v, v1= β
0−
c/
2.
Hence,vn
=
⎧ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎩ 1,
n=
0β
0−
c/
2,
n=
1 2 n+1(−
c)
n−1v 1,
n2.
(41)Let us now prove that v1
=
0.
We begin by obtaining the expression of Rn, from (40) and using induction arguments,
Rn
(
z) =
zn+
n−1 k=0(−
1)
n−k 'β
k−
c k+
1 k+
2 ( ⎛ ⎝ n−1 j=k+1β
j ⎞ ⎠ zk,
n1
,
(42)where we use the convention&lj=m
· =
1 whenever m>
l. Hence,R1
(
0) =
c/
2− β
0,
Rn(
0) = (−
1)
nβ
n−1. . . β
1(β
0−
c/
2),
n2.
(43) We take n=
2 and n=
3 in (42), thus the conditionsv,
z−1R2=
0,
v,
z−1R3=
0 give us, respectively,(β
0−
c 2)β
1v−1= β
1− β
0−
c 6 (44) v2− (β
2−
3 4c)
v1+ (β
1−
2 3c)β
2= (β
0−
c 2)β
1v−1β
2.
(45)The use of v2given by (41) and the substitution of
(β
0−
2c)β
1v−1given in (44) into (45) yield v1c=
0,
thus v1=
0.
Consequently, from (41) there follows that v0
=
1,
vn=
0,
n 1.
Furthermore, taking intoaccount (43), v1
=
0 implies Rn(
0) =
0,
for all n1.
Thus, we conclude that Rn(
z) =
zn,
n0, vis the Lebesgue functional, and the
β
n’s in (40) satisfyβ
n=
cnn++12,
n0.
Acknowledgements
(1) The authors are grateful to the anonymous referee for the valuable suggestions which improved the final version of the paper.
(2) Research partially supported by CMUC and FCT (Portugal), through European program COM-PETE/FEDER.
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