ON CERTAIN SUBCLASS OF p-VALENT FUNCTIONS WITH POSITIVE COEFFICIENTS
(Berkenaan Subkelas Fungsi p-Valen Tertentu Berpekali Positif) ANAS ALJARAH & MASLINA DARUS
ABSTRACT
In this article, a certain differential operator Sα,β,λ,δk ,pf z( ) and a subclass Sn,p(α,β,δ,λ,p) for analytic functions with positive coefficients of the form
∑
∞+ = + = 1 ) ( n p n n p a z z z f are introduced.
Some properties such as the coefficients inequalities, distortion theorem, radii of starlikeness and convexity, closure theorems and extreme points are given. A class preserving an integral operator is also stated.
Keywords: analytic function; starlike functions; convex functions; integral operator ABSTRAK
Dalam makalah ini, pengoperasi pembeza tertentu Sα,β,λ,δk ,pf z( )dan subkelas Sn,p(α,β,δ,λ,p) bagi fungsi analisis berpekali positif dalam bentuk
∑
∞+ = + = 1 ) ( n p n n p a z z z f diperkenalkan.
Beberapa sifat seperti ketaksamaan pekali, teorem erotan, jejari kebakbintangan dan kecembungan, teorem tutupan dan titik ekstrem diberi. Kelas mengekalkan pengoperasi kamiran juga dinyatakan.
Kata kunci: fungsi analisis; fungsi bakbintang; fungsi cembung; pengoperasi kamiran
1. Introduction and Preliminaries
Let
A p
( )
denote the class of functions of the form:f z
( )
=zp+ n a zn n=p+1 ∞∑
(z∈U,p∈!:={1,2,3,...}), (1.1) which are analytic and p-valent in the open unit disc U ={z∈!:z <1}. A function f z( ) in( )
A p is said to be p-valent starlike of order γ if and only if Re zf'(z) f(z) ⎧ ⎨ ⎩ ⎫ ⎬ ⎭>γ
(
z∈U)
, (1.2)for some γ(0≤ γ ≤ p). We denote by S*(γ) the class of all p-valent starlike functions of order γ.
Similarly, a function f z( ) in A p( ) is said to be p-valent convex of order γ if and only if Re 1+zf'"(z) f(z) ⎧ ⎨ ⎩ ⎫ ⎬ ⎭> γ
(
z∈U)
, (1.3)For the function f A p∈ ( ), we define the following new differential operator: S0 α,β,λ,δ,pf(z)= f(z), S1 α,β,λ,δ,pf(z)=[1−p(λ−δ)(β−α)]f(z)+[(λ−δ)(β−α)]zf'(z),, and Sαk,β,λ,δ,pf(z)=S S αk,−β1,λ,δ,pf(z)
(
)
=zp+(
(λ−δ)(β−α)(n−p)+1)
ka nzn n=p+1 ∞∑
, (1.4) for f ∈A(p),α,β,δ,λ≥0,λ>δ,β >α,p∈!,k=1,2,3,... and n∈!=!∪{ }
0 . It is easily verified from (1.4) that(λ−δ)(β−α)z(Sαk,β,λ,δ,pf(z))'=S
αk,β,λ,δ,p
+1 f(z)−(1−p(λ−δ)(β−α))S
αk,β,λ,δ,pf(z). (1.5)
Remark 1: When p=1, we have the operator introduced and studied by Ramadan and Darus (2011).
Making use of the operator Sα,β,λ,δk ,pf z( ) we say that a function f z( )∈A p( ) is in the class
Sn,p(α,β,δ,λ,p) if it satisfies the following inequality (Aouf 2012):
ℜ
{
zpSkf(z)−αzp+1(
Skf(z))
'}
>β, (1.6)for some α(α>0),β(0≤β<p),p∈!,n∈!0 and for all z U∈ . We note that (Altintas et al.
1994),
M0(1,α,β)= M(1,α,β).
In Uraleggadi and Ganigi (1986), they defined the class *( )
p
H α as follows:
f(z)∈A(p) :ℜ −
{
zp+1f'(z)}
>α,0≤α <p,z∈U{
}
. (1.8)Some other subclasses of the class A p( ) were studied (for example) by Cho et al. (1987, 1989), Liu (2000), Liu and Srivastava (2001; 2004), Joshi et al. (1995), Raina and Srivastava (2006), Aouf and Shammaky (2005).
In this paper, coefficient inequalities, distortion theorem, radii of starlikeness and convexity, closure theorems, extreme points and the class preserving integral operators of the form F(z)= c+p zc tc −1 0 z
∫
f(t)dt for all c>−p, for the class S (α,β,δ,λ,p)are considered.2. Coefficient Inequalities
In this section, we give a necessary and sufficient condition for a function f z( ) given by (1.1) to be in the class Sn,p(α,β,δ,λ,p).
Theorem 2.1. A function f z( ) given by (1.1) is inSn,p(α,β,δ,λ,p), where α >0, β,δ,λ≥0,,
p∈! and n∈!0 if and only if
((λ−δ)(β−α)(n−p))k(αn−1)a n n=p+1
∞
∑
≤(1−αp−β). (2.1)Proof.Suppose that f z( )∈Sn,p(α,β,δ,λ,p). Then we find from (1.6) that
ℜ zp zp+ ((λ−δ)(β−α)(n− p)+1)ka nzn n=p+1 ∞
∑
⎡ ⎣ ⎢ ⎤ ⎦ ⎥ −αzp+1 n ((λ−δ)(β−α)(n−p)+1)ka nzn −1 n=p+1 ∞∑
⎡ ⎣ ⎢ ⎤ ⎦ ⎥ ⎧ ⎨ ⎪ ⎪ ⎩ ⎪ ⎪ ⎫ ⎬ ⎪ ⎪ ⎭ ⎪ ⎪ >β ℜ (1−αp)z2p− ((λ−δ)(β−α)(n−p))k(αn−1)a nzn +p n=p+1 ∞∑
⎧ ⎨ ⎩⎪ ⎫ ⎬ ⎭⎪>β (α> 0, β,δ,λ ≥ 0, p∈! and n∈!0). If we choose z = r<1, then we have1−αp− ((λ−δ)(β−α)(n−p))k(αn−1)a
n≥β
n=p+1
∞
∑
for α> 0, β,δ,λ ≥ 0, p∈! and n∈!0, which is equivalent to (2.1).
Conversely, let us suppose that the equivalent (2.1) holds true. Then we have
zpSnf(z)−αzp+1(Snf(z))−(1−αp)z2p = − ((λ−δ)(β−α)(n−p))k(αn−1)a nzn+p n=p+1 ∞
∑
≤ ((λ−δ)(β−α)(n−p))k(αn−1)a n zn+p n=p+1 ∞∑
≤1−αp−βfor α> 0, β,δ,λ ≥ 0, p∈! and n∈!0, which implies that f(z)∈Sn,p(α,β,δ,λ,p). This
gives the required condition. Hence the theorem follows. □
an≤ (1−αp−β)
((λ−δ)(β−α)(n−p))k(αn−1)zn (k≥ p;p∈!;n∈!0). (2.2)
The equality in (2.2) is attained for the functions f z( ) given by
1 ) ( ) ; ; ( 1) (( )( )( )) = p k n p f z z z k p p n n n p - -- - - 0 ( α β + ( ≥ ∈ ∈ ). α λ δ β α (2.3) 3. Distortion Theorem
A distortion property for functions in the class Sn,p(α,β,δ,λ,p) is contained in the following
theorem.
Theorem 3.1. Let the functions f z( ) given by (1.1) be in the class Sn,p(α,β,δ,λ,p), where > 0
α , β,δ,λ ≥ 0, p∈ and n∈0. Then for z = r<1, we have
p r − (1−αp−β) k ((λ−δ)(β−α)(n− p)) (αn−1) 1+p r ≤ f(z) ≤ p r + (1−αp−β) k ((λ−δ)(β−α)(n− p)) (αn−1) 1+p r and p− (1−αp−β)(1+ pk) ((λ−δ)(β−α)(n− p)) (αn−1) p r ≤ ′ f (z) ≤ p+ (1−αp−β)(1+ pk) ((λ−δ)(β−α)(n− p)) (αn−1) p r .
Proof.Since f∈Sn,p(α,β,δ,λ,p), from Theorem 2.1 readily yields the inequality
n a n=p+1 ∞
∑
≤ (1−αp−β) k ((λ−δ)(β−α)(n− p)) (αn−1). Thus, for z = r<1, and making use of (3.1) we havef(z) ≤ z +p an n=p+1 ∞
∑
n z ≤ p r +rp+1 an n=p+1 ∞∑
≤ p r + (1−αp−β) k ((λ−δ)(β−α)(n− p)) (αn−1) p+1 r and f(z) ≥ zp− an n=p+1 ∞∑
n z ≤ p r −rp+1 an n=p+1 ∞∑
≥ p r − (1−αp−β) k ((λ−δ)(β−α)(n− p)) (αn−1) p+1 r .Also from Theorem 2.1, it follows that k ((λ−δ)(β−α)(n− p)) (αn−1) 1+p nan n=p+1 ∞
∑
≤ k ((λ−δ)(β−α)(n− p)) (αn−1) n=p+1 ∞∑
an≤(1−αp−β). (3.2) Hence ′ f (z) ≤ pz +p−1 nan n=p+1 ∞∑
n−1 z ≤ pr +p−1 p r nan n=p+1 ∞∑
≤ p+ (1−αp−β)(1+ pk) ((λ−δ)(β−α)(n− p)) (αn−1) p r and ′ f (z) ≥ pzp−1− nan n=p+1 ∞∑
n−1 z ≥ p−1 pr − p r nan n=p+1 ∞∑
≥ p− (1−αp−β)(1+ pk) ((λ−δ)(β−α)(n− p)) (αn−1) p r .This completes the proof of Theorem 3.1. □ 4. Radii of Starlikeness and Convexity
In this section, we determine the radii of starlikeness and convexity for functions in the class
( )
n,p p
S α,β,δ,λ, . The result is given as follows.
Theorem 4.1. Let the function f z( ) defined by (1.1) is in the class Sn,p(α,β,δ,λ,p), where > 0
α , β,δ,λ ≥ 0, p∈ and n∈0. Then f z( ) is starlike of order δ 0 ≤ δ <1( ) in z r< 1,
where 1 r = inf n≥p+1 1 n k (p−δ)(p−δ)((λ−δ)(β−α)(n− p)) (αn−1) (1−n− p+δ)(1−αp−β) ⎧ ⎨ ⎪ ⎩⎪ ⎫ ⎬ ⎪ ⎭⎪ (n≥p+1). (4.1) The result is sharp for the function f z( ) given by (2.3).
Proof. It suffices to prove that ( ) ( ) zf z p p f z - - , ′ ≤ δ (4.2) for z r< 1. We have
z ′ f (z) f(z) − p = − (1−n)an n z n=p+1 ∞
∑
p z + anzn n=p+1 ∞∑
≤ n (1−n)a n z n=p+1 ∞∑
1+ an n z n=p+1 ∞∑
. (4.3)Hence (4.3) holds true if
n (1−n)a z n n=p+1 ∞
∑
≤(p−δ) 1+ an n z n=p+1 ∞∑
⎛ ⎝⎜ ⎞ ⎠⎟ or n (1−n− p+ δ) (p−δ) a n z n=p+1 ∞∑
≤ 1 . (4.4)With the aid of (2.1), (4.4) is true if (1−n− p+δ) (p−δ) n z ≤ k ((λ−δ)(β−α)(n− p)) (αn−1) (1−αp−β) . (4.5)
Solving (4.5) for zn, we obtain
z ≤ 1 n k (p−δ)(p−δ)((λ−δ)(β−α)(n− p)) (αn−1) (1−n− p+δ)(1−αp−β) ⎧ ⎨ ⎪ ⎩⎪ ⎫ ⎬ ⎪ ⎭⎪ (n≥ p+1).
This completes the proof of Theorem 4.1. □
Theorem 4.2. Let the function f z( )defined by (1.1) is in the classSn,p(α,β,δ,λ,p), where > 0
α , β,δ,λ ≥ 0, p∈ and n∈0. Then f z( ) is convex of order δ 0 ≤ δ <1( )in z r< 2,
where 2 r =n≥infp+1 1 n−1 k p(1−δ)((λ−δ)(β−α)(n− p)) (αn−1) n(1−n− p+δ)(1−αp−β) ⎧ ⎨ ⎪ ⎩⎪ ⎫ ⎬ ⎪ ⎭⎪ (n≥p+1). (4.6)
The result is sharp for the functions f z( )given by (2.3).
Proof.By using the same technique employed in the proof of Theorem 4.1, we can show that ( ) ( ) " ' zf z p z f ≤ - ,δ (4.7)
5. Closure Theorems
Let the functions
f
j(
z
),
j
=
1
,
2
,...,
l
be defined byfj(z)= p z + an,j n=p+1 ∞ ∑ n z (an,j≥0), (5.1) for z U∈ .
In this section, we prove the closure theorem for the class Sn,p(α,β,δ,λ,p). The results are given in the following theorems.
Theorem 5.1. Let the functions f j( )z defined by (5.1) be in the classSn,p(α,β,δ,λ,p), where > 0
α , β,δ,λ ≥ 0, p∈ and n∈0 for every j = , ,...,l1 2 . Then the function G z( )defined by
G(z)= p z + bn n=p+1 ∞ ∑ n z (bn≥0) (5.2)
is a member of the classSn,p(α,β,δ,λ,p), where
n
b =1l an,j j=1
l
∑ (n≥p+1).
Proof. Since f j( )z ∈Sn,p(α,β,δ,λ,p), it follows from Theorem 2.1 that
k
((λ−δ)(β−α)(n− p)) (αn−1)
n=p+1
∞
∑
an≤(1−αp−β).for every j = , ,...,l1 2 . Hence,
k ((λ−δ)(β−α)(n− p)) (αn−1) n=p+1 ∞
∑
bn = k ((λ−δ)(β−α)(n− p)) (αn−1) n=p+1 ∞∑
1l an,j j=1 l ∑ ⎧ ⎨ ⎩ ⎫ ⎬ ⎭ =1 l k ((λ−δ)(β−α)(n− p)) (αn−1) n=p+1 ∞∑
an,j ⎛ ⎝⎜ ⎞ ⎠⎟ j=1 l∑
≤1 l j=1(1−αp−β) = (1−αp−β) l∑
,which (in view of Theorem 2.1) implies that G z( )∈Sn,p(α,β,δ,λ,p). □
Theorem 5.2. The class Sn,p(α,β,δ,λ,p)is closed under convex linear combination, where > 0 α , β,δ,λ ≥ 0, p∈ and n∈0. Proof. j f (z)= p z + an,j n=p+1 ∞ ∑ n z (an,j≥ 0;j =1,2;p∈!) (5.3)
be in the class Sn,p(α,β,δ,λ,p). It is sufficient to show that the function h(z) defined by
h(z)= tf1(z)+(1−t)f2(z) (0≤t≤ 1) (5.4) is also in the classSn,p(α,β,δ,λ,p). Since for 0≤ ≤1t ,
h(z)= p z + ⎡⎣tan,1+ (1−t)an,2⎤⎦ n=p+1 ∞ ∑ n z (0≤t≤ 1), (5.5) we observe that k ((λ−δ)(β−α)(n− p)) (αn−1) n=p+1 ∞
∑
⎡⎣tan,1+ (1−t)an,2⎤⎦ =t k ((λ−δ)(β−α)(n− p)) (αn−1) n=p+1 ∞∑
an,1 + (1−t) k ((λ−δ)(β−α)(n− p)) (αn−1) n=p+1 ∞∑
an,2 ≤t(1−αp−β) + (1−t)(1−αp−β)= (1−αp−β).Hence h z( )∈Sn,p(α,β,δ,λ,p). This completes the proof of Theorem 5.2. □ 6. Integral Operators
In this section, we consider the integral transforms of functions in the classSn,p(α,β,δ,λ,p). Theorem 6.1. If the function f z( ) given by (1.1) is in the classSn,p(α,β,δ,λ,p), where α> 0,
β,δ,λ ≥ 0, p∈ and n∈0 and let c be a real number such that c>- p, then the function ( ) F z defined by F(z)= c+ pc z c−1 t f(t)dt 0 z ∫ (6.1)
is also belongs to the classSn,p(α,β,δ,λ,p). Proof. From (6.1), it follows that F(z)= p
z + bn n=p+1 ∞ ∑ n z , where b =n ⎛⎝⎜c+ pn+c⎞⎠⎟an. Therefore k ((λ−δ)(β−α)(n− p)) (αn−1) n=p+1 ∞
∑
bn = k ((λ−δ)(β−α)(n− p)) (αn−1) n=p+1 ∞∑
⎛⎝⎜c+ pn+c⎞⎠⎟an ≤ ((λ−δ)(β−α)(n− p)) (k αn−1) n=p+1 ∞∑
an≤(1−αp−β),7. Extreme Points
Now, we determine extreme points for functions in the classSn,p(α,β,δ,λ,p). Theorem 7.1. Let ( ) p p z = f z and n f = p z + (1−αp−β) k ((λ−δ)(β−α)(n− p)) (αn−1) n z .
Then f S∈ n,p(α,β,δ,λ,p) if and only if it can be expressed in the form
f(z)=ξpfp(z)+ ξnfn(z) n=p+1 ∞
∑
, z U∈ , where ξn≥0 and ξp=1− ξn n=p+1 ∞∑
.Proof. Suppose that
f(z)=ξpfp(z)+ ξnfn(z) n=p+1 ∞
∑
f(z)= 1− ξn n=p+1 ∞∑
⎡ ⎣ ⎢ ⎤ ⎦ ⎥ zp+ ξn n=p+1 ∞∑
p z + (1−αp−β) k ((λ−δ)(β−α)(n− p)) (αn−1) n z ⎧ ⎨ ⎪ ⎩⎪ ⎫ ⎬ ⎪ ⎭⎪ = p z + ξn n=p+1 ∞∑
(1−αp−β) k ((λ−δ)(β−α)(n− p)) (αn−1) n z .Then from Theorem 2.1 we have
k ((λ−δ)(β−α)(n− p)) (αn−1) n=p+1 ∞
∑
(1−αp−β) k ((λ−δ)(β−α)(n− p)) (αn−1)ξn≤(1−αp−β). Hence f S∈ n,p(α,β,δ,λ,p).Conversely, let f S∈ n,p(α,β,δ,λ,p). Using Corollary 2.2, we have
n a ≤((λ−δ)(β−α)(n− p)) (k αn−1) (1−αp−β) . We may set n ξ = ((λ−δ)(β−α)(n− p)) (k αn−1) (1−αp−β) an and letting ξp=1− ξn n=p+1 ∞
∑
, we havef(z)= p z + an n=p+1 ∞ ∑ p z =zp− ξn n=p+1 ∞
∑
p z + ξn n=p+1 ∞∑
p z + ξn n=p+1 ∞∑
(1−αp−β) k ((λ−δ)(β−α)(n− p)) (αn−1) n z = 1− ξn n=p+1 ∞∑
⎡ ⎣ ⎢ ⎤ ⎦ ⎥ z +p ξn n=p+1 ∞∑
p z + (1−αp−β) k ((λ−δ)(β−α)(n− p)) (αn−1) n z ⎡ ⎣ ⎢ ⎢ ⎤ ⎦ ⎥ ⎥ =ξpfp(z)+ ξn n=p+1 ∞∑
fn(z).This completes the proof of the theorem. □
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School of Mathematical Sciences Faculty of Science and Technology Universiti Kebangsaan Malaysia 43600 UKM Bangi
Selangor DE, MALAYSIA
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