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Deriving MRS from Utility Function, Budget Constraints, and Interior Solution of Optimization

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1 1UtilityFunction, Deriving MRS

14.01 Principles of Microeconomics, Fall 2007 Chia-Hui Chen

September 14, 2007

Lecture

5

Deriving

MRS

from

Utility

Function,

Budget

Constraints,

and

Interior

Solution

of

Optimization

Outline

1. Chap 3: Utility Function,DerivingMRS

2. Chap 3: BudgetConstraint

3. Chap 3: Optimization: InteriorSolution

1

Utility

Function,

Deriving

MRS

Examples of utility:

Example(Perfect substitutes).

U(x, y) = ax + by.

Example(Perfect complements).

U(x, y) = min{ax, by}.

Example(Cobb-Douglas Function).

c

U(x, y) = Axby .

Example(One good is bad).

U(x, y) = −ax + by.

An important thing is to derive MRS.

dy

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10 9 8 7 6 U(x,y)=ax+by=Const y 5 4 3 2 1 0 0 2 4 6 8 10 x 2 1UtilityFunction, Deriving MRS

Figure 1: Utility Function of Perfect Substitutes

y 10 9 8 7 6 5 4 3 U(x,y)=min{ax,by}=Const 2 1 0 0 2 4 6 8 10 x

(3)

2 4 6 8 10 y U(x,y)=Axa y b=Const 0 0 2 4 6 8 10 x 10 9 8 7 6 U(x,y)=−ax+by=Const y 5 4 3 2 1 0 0 2 4 6 8 10 x 3 1UtilityFunction, Deriving MRS

Figure 3: Cobb-Douglas Utility Function

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r

4 2BudgetConstraint

Because utility is constant along the indifference curve,

u = (x, y(x)) = C,= ⇒ ∂u ∂u dy ∂x + ∂y dx = 0,= ⇒ ∂u dy ∂xdx = ∂u. ∂y Thus, ∂u M RS = ∂x∂u. ∂y

Example(Sample utility function).

u(x, y) = xy 2

.

Two ways to derive MRS:

• Along the indifference curve

xy 2 = C. c y = . x Thus, dy √c y M RSd =−dx = = . 2x3/2 2x

• Using the conclusion above

∂u 2 ∂x y y M RS = ∂u = = . 2xy 2x ∂y

2

Budget

Constraint

The problem is about how much goods a person can buy with limited income.

Assume: no saving, with income I, only spend money on goods x and y with

the price Pxand Py.

Thus the budget constraint is

Px·x + Py· y � I.

Suppose Px= 2, Py = 1, I = 8, then

2x + y � 8.

The slope of budget line is

dy Px

dx =

Py

.

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5 2BudgetConstraint 10 8 6 2x+y≤8 y 4 2 0 0 2 4 6 8 10 x

Figure 5: Budget Constraint

10 9 0 2 4 6 8 10 x 0 1 2 3 4 5 6 7 8 y 2x+y≤8 2x+y≤6

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6 3Optimization: InteriorSolution

10 0 2 4 6 8 10 x 0 1 2 3 4 5 6 7 8 9 y 2x+y≤8 x+y≤4

Figure 7: Budget Line Rotates Because of Change in Price

• Change in Income Assume I = 6, then 2x+y = 6. The budget line shifts

right which means more income makes the affordable region larger.

• Change in Price Assume Px = 2, then 2x + 2y = 8. The budget line

changes which means lower price makes the affordable region larger.

3

Optimization:

Interior

Solution

Now the consumer’s problem is: how to be as happy as possible with limited income. We can simplify the problem into language of mathematics:

 

 xPx+ yPy� I 

max U(x, y) subject to x � 0 .

x,y

 y 0 

Since the preference has non-satiation property, only (x, y) on the budget line

can be the solution. Therefore, we can simplify the inequality to an equality:

xPx + yPy= I.

First, consider the case where the solution is interior, that is, x > 0 and y > 0.

Example solutions: Method 1

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7 3Optimization: InteriorSolution

0 1 2 3 4 5 6 7 8 9 10 y P x x+P yy=I U(x,y)=Const 2 4 6 8 10 x

Figure 8: Interior Solution to Consumer’s Problem

From Figure 8, the utility function reaches its maximum when the indif­ ferent curve and constraint line are tangent, namely:

Px ∂u/∂x ux = M RS = = . Py ∂u/∂y uy – If Px ux > , Py uy

then one should consume more y, less x.

– If

Px ux

< , Py uy

x

then one should consume more x, less y. Intuition behind PP

y = M RS:

Px is the market price of x in terms of y, and MRS is the price of x in

Py

terms of y valued by the individual. If Px/Py> M RS, x is relatively

expensive for the individual, and hence he should consume more y.

On the other hand, if Px/Py < M RS, x is relatively cheap for the

individual, and hence he should consume more x.

Method 2: Use Lagrange Multipliers

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8 3Optimization: InteriorSolution

In order to maximize u, the following first order conditions must be satis­ fied: ∂L ux = 0 = = λ, ∂x ⇒ Px ∂L uy ∂y = 0 = ⇒ Py = λ, ∂L ∂λ = 0 = ⇒xPx + yPy−I = 0. Thus we have Px ux = . Py uy Method 3 • Since xPx + yPy+ I = 0, I −xPx y = . Py

Then the problem can be written as

max u(x, y) = u(x, I −xPx).

x,y Py

At the maximum, the following first order condition must be satisfied:

∂y Px ux + uy( ∂x) = ux + uy(−Py ) = 0. = ⇒ Px ux = . Py uy

References

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