MULTIDIGIT ARITHMETIC
THIS IS A REVIEW OF HOW TO ADD, SUBTRACT, MULTIPLY, &
DIVIDE MULTIDIGIT NUMBERS
ADDING (SLIDES 5-9)
SUBTRACTING (SLIDES 10- 23)
MULTIPLYING (SLIDES 24-28)
KNOW YOU MATH FACTS
•
SUCCESS WITH MULTIDIGIT NUMBERS DEPENDS ON KNOWING
YOUR MATH FACTS
•
IF YOUR MATH FACTS ARE MEMORIZED, YOU KNOW THE
ANSWER AUTOMATICALLY (WITHOUT THINKING) MUCH LIKE YOU
KNOW THE ANSWER TO THE QUESTION “WHAT IS YOUR NAME.”
VOCABULARY
• ADDITION (+) – MEANS TO PUT TOGETHER. THE SUM IS THE ANSWER TO AN ADDITION PROBLEM
• SUBTRACT (-) – MEANS TO REMOVE AN AMOUNT. THE DIFFERENCE IS THE ANSWER TO A
SUBTRACTION PROBLEM
• REGROUP – THE PROCESS OF CHANGING GROUPS OF 1’S INTO 10’S TO MAKE THE PROCESS OF
ADDING/SUBTRACTING EASIER. THIS IS SOMETIMES CALLED “CARRYING” WITH ADDITION OR “BORROWING” WITH SUBTRACTION.
• MULTIPLY (X) – MEANS TO COMBINE AMOUNTS. THE PRODUCT IS THE ANSWER TO A
MULTIPLICATION PROBLEM
• DIVIDE ( – TO SPLIT AN AMOUNT INTO EQUAL PARTS OR GROUPS. THE QUOTIENT IS THE ANSWER
TO A DIVISION PROBLEM.
• REMAINDER – THE AMOUNT LEFT OVER IN A DIVISION PROBLEM.
PARTS OF A PROBLEM
ADDING MULTIDIGIT NUMBERS
STEPS:
1. STACK THE PROBLEMS (LINE UP THE PLACE VALUE OF EACH DIGIT VERTICALLY
SO THAT THE 1’S ON THE TOP ARE DIRECTLY OVER THE 1’S UNDERNEATH IT
AND SO ARE THE 10’S, 100’S, ETC…)
35,785 + 3,506
2. ADD THE DIGITS IN EACH PLACE VALUE WORKING FROM RIGHT TO LEFT
(THE 1’S FIRST, THE 10’S NEXT, AND SO ON)
3. REGROUP IF NECESSARY
• IF THE ANSWER REQUIRES 2 DIGITS, HOLD THE 1’S AND CARRY THE 10’S
• IN THE EXAMPLE TO THE LEFT SINCE 5+6 AND 7+5 ARE REGROUPED BECAUSE THEIR ANSWERS REQUIRE 2 DIGITS
https://www.youtube.com/watch?v=mAvuom42NyY
Using grid paper will help keep the
#’s alligned
+
7 8 5
5 0 6
+
2 9 1
5,
3
3,
9,
3
1
1
3 5 7 8 5 3 5 0 6
1. 71,456 + 13,325 = 2. 64,417 + 22,368 =
3. 54,873 + 7,462 = 4. 48,673 + 3,594 =
84,781
1
Read the problem and identify2 what is being added, if necessary. Line up the numbers by the place value of their digits, if necessary. Add the digit in each place value. Hint: Start from the ones place.
Compose a number, if needed.
Hint: Move a group of numbers to the next higher place value.
Interpret3 the sum. “The sum of _______ and _______ is _______.”
Add multi-digit numbers. 1
2 3
a 4
+ 2 3 6 1 4 4 2 6 7 8 86,785
8 6 , 7 8 5
3 , 5 9 4
1
+ +
62,335 52,267
5 4 , 8 7 3 7 , 4 6 2
6 2 , 3 3 5
4 8 , 6 7 3
8 4 , 7 8 1
5 2 , 2 6 7
1 1 1 1 1 1
ADDITION - YOUR TURN #1
1c. 1b.
1a.
+ 7 9 5 0 4 7 5
3 1
6 + 5 9 6
6 3 9
6 2
5 + 4 2 7
0 6 4 1 5 8 0 2c. 2b. 2a.
+ 9 2 0 6 6 0 2
2 4
0 + 6 7 9
8 9 4
9 2
4 + 3 3 2
5 4 1 1 7 6 5 3c. 3b. 3a.
+ 5 9 1 1 5 3 1
7 5
5 + 2 3 0
9 6 4 1
8 2
4 + 2 6 6
YOUR TURN #1 – CHECK YOUR ANSWERS
1c. 1b.
1a.
+ 7 9 5 0 4 7 5
3 1
6 + 5 9 6
6 3 9
6 2
5 + 4 2 7
0 6 4 1 5 8 0 2c. 2b. 2a.
+ 9 2 0 6 6 0 2
2 4
0 + 6 7 9
8 9 4
9 2
4 + 3 3 2
5 4 1 1 7 6 5 3c. 3b. 3a.
+ 5 9 1 1 5 3 1
7 5
5 + 2 3 0
9 6 4 1
8 2
4 + 2 6 6
4 4 9 2 7 2 6
9 5 , 3 5 7
1 1
7 5 , 3 2 7 6 8 , 8 7 8
4 9 , 8 6 4 1 0 1 , 7 7 6 8 4 , 7 8 1
1 0 2 , 1 0 8 9 6 , 9 9 6
8 9 , 4 3 0
1 1
1
1 1 1 1 1 1
1 1 1
ESTIMATING TO CHECK
Round each number to
the 100’s place
SUBTRACTING MULTIDIGIT NUMBERS
STEPS:
1. STACK THE NUMBERS VERTICALLY LINING UP THE PLACE VALUE OF EACH DIGIT
• REMEMBER THAT ORDER MATTERS WITH SUBTRACTION SO PUT THE 1ST # ON TOP OF
THE 2ND #
2. LOOK AT THE ONES.
ASK: CAN WE SUBTRACT?
3. REGROUP AS NEEDED:
1. GO TO THE NEIGHBOR ON THE LEFT AND TAKE ONE AWAY.
2. ADD THE TEN TO THE DIGIT THAT NEEDS REGROUPING.
4. SUBTRACT THE ONES.
5. SUBTRACT THE TENS AND SO ON…
https://www.youtube.com/watch?v=Y6M89-6106I
1. STACK THE PROBLEM (PUT THE 1
ST
NUMBER ON TOP OF THE 2
ND
#)
82 – 53
SUBTRACTION
– A CLOSER LOOK AT EACH
STEP
8 2
-5
3
-
82
53
2. LOOK AT THE ONES.
ASK:
“CAN WE TAKE 3
AWAY FROM
2?”
8 2
-5
3
If we can’t,
then we have to
regroup.
Remember order matters with subtraction. You need
to subtract 2-3 (not 3-2). Always subtract from top to
bottom
3. REGROUP AS NEEDED.
8
2
-5
3
1
st:
Go next door
to the tens
and take one
away.
7
2
nd:
Add the ten
to the ones.
1
4. SUBTRACT THE ONES.
8
2
-5
3
7
1
What is 12 –
3?
9
5. SUBTRACT THE TENS.
8
2
-5
3
7
1
9
What is 7 – 5?
2
MORE EXAMPLES
ESTIMATING TO CHECK
Round each number to
the 100’s
The estimate 5,700 is close so the answer is reasonable.
SUBTRACTING ACROSS ZEROS
METHOD 1
(THE OLD SCHOOL WAY) - BORROW ONE DIGIT AT
A TIME
Start here. There are
not enough.
Since the neighbor to
the left does not have any,
go all the way to the
left to borrow.
Regroup one digit at a time. Until you reach the digit you are
subtracting
Another Example:
SUBTRACTING ACROSS ZEROS
METHOD 2
– THE BOXING STRATEGY
•
LOOK SEVERAL DIGITS AHEAD & CHUNK/BOX THIS SET
5 0 0 2
- 1 4 8
4 9 9
12
SUBTRACTION – YOUR TURN #2
1. 725 - 68 = 2. 3,789 - 509 =
3. 707 - 361 = 4. 8,000 – 5,274 =
-
--
7 2 5 6 83 , 7 8 9 5 0 9
7 0 7
3 6 1 5 , 2 7 4 8 , 0 0 0
YOUR TURN #2 – CHECK YOUR ANSWERS
1. 725 - 68 = 2. 3,789 - 509 =
3. 707 - 361 = 4. 8,000 – 5,274 =
-
--
7 2 5 6 83 , 7 8 9 5 0 9
7 0 7
3 6 1 5 , 2 7 4 8 , 0 0 0
3 , 2 8 0
2 , 7 2 6 6 5 7
3 4 6
7 9 9 10 6 10
6 12 15 11
MULTIDIGIT MULTIPLICATION
STEPS:
1. STACK THE NUMBERS VERTICALLY LINING UP THE PLACE VALUE OF EACH DIGIT
2. MULTIPLY THE ONES DIGIT
• REGROUP AS NECESSARY (NOTE – ANY REGROUPED AMOUNTS ARE ADDED DURING MULTIPLICATION) 3. INSERT A ZERO AS A PLACEHOLDER FOR YOUR NEXT PARTIAL PRODUCT
4. MULTIPLY THE TENS DIGIT
• REGROUP AS NECESSARY
5. INSERT 2 ZEROS AS PLACEHOLDERS IN YOUR NEXT PARTIAL PRODUCT
6. MULTIPLY THE 100’S DIGIT
7. CONTINUE THE PROCESS OF ADDING PLACEHOLDER TO MULTIPLY EACH PLACE VALUE
• THE 10’S DIGIT HAS ONE PLACEHOLDER
• THE 100’S DIGIT HAS TWO PLACEHOLDERS
• THE 1000’S DIGIT HAS THREE PLACEHOLDERS
• AND SO ON…
8. ADD THE PARTIAL PRODUCTS
https://www.youtube.com/watch?v=FJ5qLWP3Fqo
Note: The number of placeholder used matches the number of
zero’s for each place value. https://www.youtube.com/watch?v=RVYwunbpMHA
MULTIDIGIT BY ONE DIGIT
Add the regrouped amount
This is 6 x 3 which is 18, plus
the regrouped amount (18 +
5 = 23)
Add the regrouped amount
This is 7 x 6 which is 42, plus
the regrouped amount (42 +
2 = 44)
MULTIDIGIT BY TWO DIGITS
Step 1 – Multiplythe ones
Step 2 – Use a placeholder and multiply the tens
Step 3 – Add the partial products
DON’T FORGET THE PLACEHOLDERS
CCSS 5th Grade Numbers and Base Ten 5.0
Multiply using the multiplication algorithm. Lesson to be used by EDI-trained teachers only.
©2013 All rights reserved.
Skill Development/Guided Practice (continued)
Skill Development/Guided Practice (continued)
7.
8.
4 9 3
2 5 1
5 7 9
1 3 4
The multiplication algorithm is a step-by-step method for solving a multiplication problem. • The multiplication algorithm involves multiplying by place value then adding the
partial products.
Partial products are the smaller products obtained when multiplying by place value.
Multiply by place values beginning with the ones place. Write digits in the correct place value.
Add digits in the same place value as needed. Add the partial products.
Interpret the multiplication problem. “______ times ______ is equal to _______.”
Multiply using the multiplication algorithm. 1
2 a b 3
How did I/you multiply by place values?
How did I/you multiply by place values?
CFU
CFU
1
Use 2 placeholders when multiplying the 100’s digit.
LONG DIVISION STEPS
D D M S C B R
1. DASHES
2. DIVIDE
3. MULTIPLY
4. SUBTRACT
5. CHECK
6. BRING DOWN
7. REPEAT (OR REMAINDER)
Dude, does
McDonalds
sell
cheesebur
gers
regularly?
https://www.youtube.com/watch?v=LGqBQrUYua4
This is a sample
long division problem
6
8 9 2
1 4 8 r 4
-6
2 9
-2 4
5 2
-4 8
4
Quotient
Divisor
Dividend
Answer
Number doing the dividing.
Number being divided
STEP BY STEP – A CLOSER LOOK
STEP 1 – DASHES
a) STARTING AT THE LEFT, UNCOVER 1 DIGIT OF THE DIVIDEND AT A TIME
b) ASK “CAN I DIVIDE THE DIVISOR BY THIS DIGIT?”
c) ONCE THE 1
STDASH IS PLACED, USE DASHES OVER ALL THE DIGITS TO
THE RIGHT
WHY DO THIS?
•
DASHES REMIND YOU HOW MANY
DIGITS YOUR ANSWER SHOULD HAVE
•
PEOPLE OFTEN FORGET THE ZEROS
X
5 does not go
into 2
5 does go into 20, so place dashes over all remaining
digits
The dashes tell us that this will be a 3 digit
answer
STEP 2 - DIVIDE
X
Using the 1
stdash,
think “5 goes into
20 how many
times?” or think “5
times what = 20?”
Answer – 4
4
STEP 3 - MULTIPLY
X
Multiply by the
divisor & place this
under the dividend.
5 x 4 = 20
4
2
0
STEP 4 - SUBTRACT
X
20 – 20 = 0
4
- 2 0
0
STEP 5 - CHECK
X
Check – “Is zero
less than 5?”
Answer – Yes so
you may
continue
4
- 2 0
0
If the answer is “no” you made a division error
Check to make sure the answer from the subtraction is less
than the divisor
STEP 6 – BRING DOWN
X
Bring down the
# under the
next dash
4
- 2 0
0
1
If you have any other dashes, bring down the next digit in
the dividend
STEP 7 – REPEAT
X
5 does not go
into zero. Don’t
forget to put a
zero in the next
dash
4
- 2 0
0
1
After bringing down a digit, always return to step 2 (divide)
and proceed through the steps until there are no other
digits to bring down
D D M S C B R
0
Check – Is 1 less
than 5?
Answer – Yes so it’s
okay to continue
STEP 7 – CONTINUED
X
5 x 0 = 0
4
- 0
1
0
After bringing down a digit, always return to step 2 (divide)
and proceed through the steps until there are no other
digits to bring down
D D M S C B R
0
- 2 0
0
1
2
- 1 0
0
Division has stopped and
there is no remainder.
ADDITIONAL SINGLE DIGIT DIVISOR
EXAMPLES
X
X
2 DIGIT DIVISORS
1. ROUND THE DIVISOR, TO ESTIMATE THE QUOTIENT
2. FOLLOW THE REST OF THE LONG DIVISION STEPS (DDMSCBR)
Round the divisor to 25 because this # is easy to work with
using mental math
X
Since you rounded the divisor to 25, use
this to help estimate the first
division 25 x 2 = 50 which is close to
47.
Now try 2 x the actual divisor (23
x 2 = 46)
https://www.youtube.com/watch?v=HdU_rf7eMTI
EXAMPLE 1
Round the divisor to70 because this # is easier to work with.
Use 70 to help estimate. 70 x 8 = 560, so try multiplying the actual divisor by 8.
73 x 8 = 584 (that’s too much, so now try
7)
73 x 7 = 511 (this is as close as we can get so
use 7)
Use the rounded divisor of 70 to help estimate. Since 70 x 9 = 630, try the actual divisor with 9 (73 x 9 = 657). That’s too much,
so use 8 (73 x 8 = 584)
r44
EXAMPLE 2
1. ROUND THE DIVISOR, TO ESTIMATE THE QUOTIENT
2. FOLLOW THE REST OF THE LONG DIVISION STEPS (DDMSCBR)
Round the divisor to 20, since this is
easier to use with mental math. 20 x
2 = 40, since this is close to 36 try the actual divisor x
2
21 x 2 = 42 (that’s too much, so use
1)
20 x 1 = 20
X
1
-2 0
1 8 2
-1 6 8
1 4
2
- 1 2
6
1
6
8
Check “Is 18 smaller than 21?” Answer – Yes (okay to continue)
Use the rounded divisor of 20 to help estimate. Since 20 x 9 = 180, try the actual divisor with
9 (21 x 9 = 189). That’s too much, so use 8 (21 x 8 = 168) Use the rounded divisor of 20 to
help estimate. Since 20 x 7 = 140, try 7 (21 x 7 = 147). That’s
too much to use 6