472 Chapter 9 Factoring
Factoring
• factored form (p. 475) • factoring by grouping (p. 482) • prime polynomial (p. 497) • difference of squares (p. 501) • perfect square trinomials (p. 508)Key Vocabulary
The factoring of polynomials can be used to solve a variety of real-world problems and lays the foundation for the further study of polynomial equations. Factoring is used to solve problems involving vertical motion. For example, the height h in feet of a dolphin that jumps out of the water traveling at 20 feet per second is modeled by a polynomial equation. Factoring can be used to determine how long the dolphin is in the air. You will learn how to solve polynomial equations in Lesson 9-2.
• Lesson 9-1 Find the prime factorizations of integers and monomials.
• Lesson 9-1 Find the greatest common factors (GCF) for sets of integers and monomials. • Lessons 9-2 through 9-6 Factor polynomials. • Lessons 9-2 through 9-6 Use the Zero Product
Chapter 9 Factoring 473 Make this Foldable to help you organize your notes on
factoring. Begin with a sheet of plain 812"by 11" paper.
Label each tab as shown. 9-1 9-2 9-3 9-4 9-5 9-6 F a c t o r i n g Open. Cut short side along
folds to make tabs.
Open. Fold lengthwise, leaving a tab on the right. 1 2"
Fold in thirds and then in half along
the width.
Reading and Writing As you read and study the chapter, write notes and examples for each lesson under its tab.
Prerequisite Skills
To be successful in this chapter, you’ll need to master these skills and be able to apply them in problem-solving situations. Review these skills before beginning Chapter 9.For Lessons 9-2 through 9-6 Distributive Property
Rewrite each expression using the Distributive Property. Then simplify.
(For review, see Lesson 1-5.)
1. 3(4x) 2. a(a5) 3. 7(n23n1) 4. 6y(3y5y2y3)
For Lessons 9-3 and 9-4 Multiplying Binomials
Find each product. (For review, see Lesson 8-7.)
5. (x4)(x7) 6. (3n4)(n5) 7. (6a2b)(9ab) 8. (x8y)(2x12y)
For Lessons 9-5 and 9-6 Special Products
Find each product. (For review, see Lesson 8-8.)
9. (y9)2 10. (3a2)2 11. (n5)(n5) 12. (6p7q)(6p7q)
For Lesson 9-6 Square Roots
Find each square root. (For review, see Lesson 2-7.) 13.
121 14. 0.0064 15. 2 3 5 6 16. 9 8 8 Fold in Sixths Cut Fold Again LabelPRIME FACTORIZATION
Recall that when two or more numbers are multiplied, each number is a factor of the product. Some numbers, like 18, can be expressed as the product of different pairs of whole numbers. This can be shown geometrically. Consider all of the possible rectangles with whole number dimensions that have areas of 18 square units.The number 18 has 6 factors, 1, 2, 3, 6, 9, and 18. Whole numbers greater than 1 can be classified by their number of factors.
Vocabulary
• prime number • composite number • prime factorization • factored form• greatest common factor (GCF)
Factors and Greatest
Common Factors
474 Chapter 9 Factoring
are prime numbers related to the
search for extraterrestrial life?
are prime numbers related to the
search for extraterrestrial life?
Classify Numbers as Prime or Composite
Factor each number. Then classify each number as prime or composite. a. 36To find the factors of 36, list all pairs of whole numbers whose product is 36.
1 36 2 18 3 12 4 9 6 6
Therefore, the factors of 36, in increasing order, are 1, 2, 3, 4, 6, 9, 12, 18, and 36. Since 36 has more than two factors, it is a composite number.
Example
1
Example
1
1 18
2 9 3 6
Prime and Composite Numbers
Words Examples
A whole number, greater than 1, whose only factors
are 1 and itself, is called a . 2, 3, 5, 7, 11, 13, 17, 19
A whole number, greater than 1, that has more than
two factors is called a . 4, 6, 8, 9, 10, 12, 14, 15, 16, 18
0 and 1 are neither prime nor composite.
composite number prime number
Study Tip
Listing Factors
Notice that in Example 1, 6 is listed as a factor of 36 only once.
• Find prime factorizations of integers and monomials.
• Find the greatest common factors of integers and monomials.
In the search for extraterrestrial life, scientists listen to radio signals coming from faraway galaxies. How can they be sure that a particular radio signal was deliberately sent by intelligent beings instead of coming from some natural phenomenon? What if that signal began with a series of beeps in a pattern comprised of the first 30 prime numbers (“beep-beep,” “beep-beep-beep,” and so on)?
Study Tip
Lesson 9-1 Factors and Greatest Common Factors 475
When a whole number is expressed as the product of factors that are all prime numbers, the expression is called the prime factorization of the number.
A negative integer is factored completely when it is expressed as the product of 1 and prime numbers.
www.algebra1.com/extra_examples
b. 23
The only whole numbers that can be multiplied together to get 23 are 1 and 23. Therefore, the factors of 23 are 1 and 23. Since the only factors of 23 are 1 and itself, 23 is a prime number.
Prime Factorization of a Positive Integer
Find the prime factorization of 90.Method 1
90 245 The least prime factor of 90 is 2.
2315 The least prime factor of 45 is 3.
2335 The least prime factor of 15 is 3.
All of the factors in the last row are prime. Thus, the prime factorization of 90 is 2335.
Method 2
Use a factor tree. 90
9 10 90 910
3325 9 33 and 10 25
All of the factors in the last branch of the factor tree are prime. Thus, the prime factorization of 90 is 2335 or 2325.
Usually the factors are ordered from the least prime factor to the greatest.
Example
2
Example
2
Prime Factorization of a Negative Integer
Find the prime factorization of 140.140 1140 Express 140 as 1 times 140. 1270 140 2 70
12710 70 7 10 12725 10 2 5
Thus, the prime factorization of 140 is 1 2 2 5 7 or 1 225 7.
Example
3
Example
3
A monomial is in when it is expressed as the product of prime numbers and variables and no variable has an exponent greater than 1.
factored form
Study Tip
Unique
Factorization
Theorem
The prime factorization of every number is unique except for the order in which the factors are written.
Prime Numbers
Before deciding that a number is prime, try dividing it by all of the prime numbers that are less than the square root of that number.
• The GCF of two or more integers is the product of the prime factors common to the integers.
• The GCF of two or more monomials is the product of their common factors when each monomial is in factored form.
• If two or more integers or monomials have a GCF of 1, then the integers or monomials are said to be relatively prime.
Greatest Common Factor (GCF)
GREATEST COMMON FACTOR
Two or more numbers may have some common prime factors. Consider the prime factorization of 48 and 60.48 2 2 2 2 3 Factor each number.
60 2 2 3 5 Circle the common prime factors.
The integers 48 and 60 have two 2s and one 3 as common prime factors. The product of these common prime factors, 2 2 3 or 12, is called the
of 48 and 60. The GCF is the greatest number that is a factor of both original numbers.
(GCF)
greatest common factor
476 Chapter 9 Factoring
Prime Factorization of a Monomial
Factor each monomial completely.a. 12a2b3
12a2b32 6 aabbb 12 2 6, a2aa, and b3bbb
2 2 3 aabbb 6 2 3
Thus, 12a2b3in factored form is 2 2 3 aabbb.
b. 66pq2
66pq2 1 66 pqq Express 66 as 1 times 66. 1 2 33 pqq 66 2 33
1 2 3 11 pqq 33 3 11
Thus, 66pq2in factored form is 1 2 3 11 pqq.
Example
4
Example
4
GCF of a Set of Monomials
Find the GCF of each set of monomials.a. 15 and 16
15 3 5 Factor each number.
16 2 2 2 2 Circle the common prime factors, if any.
There are no common prime factors, so the GCF of 15 and 16 is 1. This means that 15 and 16 are relatively prime.
b. 36x2y and 54xy2z
36x2y 2 2 3 3 x x y Factor each number.
54xy2z 2 3 3 3 x y y z Circle the common prime factors. The GCF of 36x2y and 54xy2z is 2 3 3 xy or 18xy.
Example
5
Example
5
Alternative
Method
You can also find the greatest common factor by listing the factors of each number and finding which of the common factors is the greatest. Consider Example 5a. 15: 1, 3, 5, 15 16: 1, 2, 4, 8, 16 The only common factor, and therefore, the greatest common factor, is 1.
Practice and Apply
Practice and Apply
1. Determinewhether the following statement is true or false. If false, provide a counterexample.
All prime numbers are odd.
2. Explainwhat it means for two numbers to be relatively prime.
3. OPEN ENDED Name two monomials whose GCF is 5x2.
Find the factors of each number. Then classify each number as prime or composite.
4. 8 5. 17 6. 112
Find the prime factorization of each integer.
7. 45 8. 32 9. 150
Factor each monomial completely.
10. 4p2 11. 39b3c2 12. 100x3yz2
Find the GCF of each set of monomials.
13. 10, 15 14. 18xy, 36y2 15. 54, 63, 180
16. 25n, 21m 17. 12a2b, 90a2b2c 18. 15r2, 35s2, 70rs
19. GARDENING Ashley is planting 120 tomato plants in her garden. In what ways can she arrange them so that she has the same number of plants in each row, at least 5 rows of plants, and at least 5 plants in each row?
Concept Check
Guided Practice
Application
Lesson 9-1 Factors and Greatest Common Factors 477
www.algebra1.com/self_check_quiz
Use Factors
GEOMETRY The area of a rectangle is 28 square inches. If the length and width are both whole numbers, what is the maximum perimeter of the rectangle?
Find the factors of 28, and draw rectangles with each length and width. Then find each perimeter.
The factors of 28 are 1, 2, 4, 7, 14, and 28.
The greatest perimeter is 58 inches. The rectangle with this perimeter has a length of 28 inches and a width of 1 inch.
Example
6
Example
6
P 1 28 1 28 or 58 1 28 14 2 P 2 14 2 14 or 32 7 4 P 4 7 4 7 or 22GUIDED PRACTICE KEY
Find the factors of each number. Then classify each number as prime or composite.
20. 19 21. 25 22. 80 23. 61
478 Chapter 9 Factoring
Homework Help
For See Exercises Examples 20–27, 62, 1 65, 66 32–39 2, 3 40–47 4 48–61, 5 63, 64 28–31, 67 6Extra Practice
See page 839.Marching Bands
Drum Corps International (DCI) is a nonprofit youth organization serving junior drum and bugle corps around the world. Members of these marching bands range from 14 to 21 years of age.
Source:www.dci.org
GEOMETRY For Exercises 28 and 29, consider a rectangle whose area is 96 square millimeters and whose length and width are both whole numbers. 28. What is the minimum perimeter of the rectangle? Explain your reasoning.
29. What is the maximum perimeter of the rectangle? Explain your reasoning.
COOKIES For Exercises 30 and 31, use the following information.
A bakery packages cookies in two sizes of boxes, one with 18 cookies and the other with 24 cookies. A small number of cookies are to be wrapped in cellophane before they are placed in a box. To save money, the bakery will use the same size
cellophane packages for each box.
30. How many cookies should the bakery place in each cellophane package to maximize the number of cookies in each package?
31. How many cellophane packages will go in each size box?
Find the prime factorization of each integer.
32. 39 33. 98 34. 117 35. 102
36. 115 37. 180 38. 360 39. 462
Factor each monomial completely.
40. 66d4 41. 85x2y2 42. 49a3b2 43. 50gh
44. 128pq2 45. 243n3m 46. 183xyz3 47. 169a2bc2
Find the GCF of each set of monomials.
48. 27, 72 49. 18, 35 50. 32, 48
51. 84, 70 52. 16, 20, 64 53. 42, 63, 105
54. 15a, 28b2 55. 24d2, 30c2d 56. 20gh, 36g2h2
57. 21p2q, 32r2t 58. 18x, 30xy, 54y 59. 28a2, 63a3b2, 91b3
60. 14m2n2, 18mn, 2m2n3 61. 80a2b, 96a2b3, 128a2b2
62. NUMBER THEORY Twin primes are two consecutive odd numbers that are
prime. The first pair of twin primes is 3 and 5. List the next five pairs of twin primes.
MARCHING BANDS For Exercises 63 and 64, use the following information.
Central High’s marching band has 75 members, and the band from Northeast High has 90 members. During the halftime show, the bands plan to march into the stadium from opposite ends using formations with the same number of rows.
63. If the bands want to match up in the center of the field, what is the maximum number of rows?
64. How many band members will be in each row after the bands are combined?
NUMBER THEORY For Exercises 65 and 66, use the following information.
One way of generating prime numbers is to use the formula 2p1, where p is a prime number. Primes found using this method are called Mersenne primes. For example, when p2, 221 3. The first Mersenne prime is 3.
65. Find the next two Mersenne primes.
66. Will this formula generate all possible prime numbers? Explain your reasoning.
Online Research
Data Update What is the greatest known primeFinding the GCF of distances will help you make a scale model of the solar system. Visit
www.algebra1.com/ webquestto continue work on your WebQuest project.
Lesson 9-1 Factors and Greatest Common Factors 479
Getting Ready for
the Next Lesson
Maintain Your Skills
Maintain Your Skills
67. GEOMETRY The area of a triangle is 20 square centimeters. What are possible whole-number dimensions for the base and height of the triangle?
68. CRITICAL THINKING Suppose 6 is a factor of ab, where a and b are natural numbers. Make a valid argument to explain why each assertion is true or provide a counterexample to show that an assertion is false.
a. 6 must be a factor of a or of b.
b. 3 must be a factor of a or of b.
c. 3 must be a factor of a and of b.
69. Answer the question that was posed at the beginning of the lesson.
How are prime numbers related to the search for extraterrestrial life?
Include the following in your answer:
• a list of the first 30 prime numbers and an explanation of how you found them, and
• an explanation of why a signal of this kind might indicate that an extraterrestrial message is to follow.
70. Miko claims that there are at least four ways to design a 120-square-foot rectangular space that can be tiled with 1-foot by 1-foot tiles. Which statement best describes this claim?
Her claim is false because 120 is a prime number. Her claim is false because 120 is not a perfect square. Her claim is true because 240 is a multiple of 120. Her claim is true because 120 has at least eight factors.
71. Suppose Ψxis defined as the largest prime factor of x. For which of the following values of x would Ψxhave the greatest value?
53 B 74 C 99 D 117 A D C B A WRITING IN MATH
Find each product. (Lessons 8-7 and 8-8)
72. (2x1)2 73. (3a5)(3a5) 74. (7p24)(7p24)
75. (6r7)(2r5) 76. (10hk)(2h5k) 77. (b4)(b23b18)
Find the value of r so that the line that passes through the given points has the given slope. (Lesson 5-1)
78. (1, 2), (2, r), m3 79. (5, 9), (r, 6), m 3
5
80. RETAIL SALES A department store buys clothing at wholesale prices and then marks the clothing up 25% to sell at retail price to customers. If the retail price of a jacket is $79, what was the wholesale price? (Lesson 3-7)
PREREQUISITE SKILL Use the Distributive Property to rewrite each expression.
(To review the Distributive Property, see Lesson 1-5.)
81. 5(2x8) 82. a(3a1) 83. 2g(3g4)
84. 4y(3y6) 85. 7b7c 86. 2x3x
Standardized
Test Practice
480Investigating Slope-Intercept Form 480 Chapter 9 Factoring
A Preview of Lesson 9-2
Sometimes you know the product of binomials and are asked to find the factors. This is called factoring. You can use algebra tiles and a product mat to factor binomials.
Factoring Using the
Distributive Property
Model and Analyze
Use algebra tiles to factor each binomial.
1. 2x10 2. 6x8 3. 5x22x 4. 93x
Tell whether each binomial can be factored. Justify your answer with a drawing.
5. 4x10 6. 3x7 7. x22x 8. 2x23
9. MAKE A CONJECTURE Write a paragraph that explains how you can use algebra tiles to determine whether a binomial can be factored. Include an example of one binomial that can be factored and one that cannot.
Activity 1
Use algebra tiles to factor 3x 6.Model the polynomial 3x6. Arrange the tiles into a rectangle. The total area of the rectangle
represents the product, and its length and width represent the factors.
The rectangle has a width of 3 and a length of x2. So, 3x63(x2). 3 x 2 x 1 1 x 1 1 x 1 1 1 1 1 1 1 1 x x x
Model the polynomial x24x. Arrange the tiles into a rectangle.
The rectangle has a width of x and a length of x4. So, x24x x(x4).
x x2 xxxx
x 4
x x x x x2
FACTOR BY USING THE DISTRIBUTIVE PROPERTY
In Chapter 8, you used the Distributive Property to multiply a polynomial by a monomial.2a(6a8) 2a(6a) 2a(8)
12a216a
You can reverse this process to express a polynomial as the product of a monomial factor and a polynomial factor.
12a216a2a(6a) 2a(8)
2a(6a8) Thus, a factored form of 12a216a is 2a(6a8).
a polynomial means to find its completely factored form. The expression 2a(6a8) is not completely factored since 6a8 can be factored as 2(3a4).
Factoring
Factoring Using the
Distributive Property
Lesson 9-2 Factoring Using the Distributive Property 481
can you determine how long a
baseball will remain in the air?
can you determine how long a
baseball will remain in the air?
Use the Distributive Property
Use the Distributive Property to factor each polynomial. a. 12a216aFirst, find the GCF of 12a2and 16a. 12a222 3 aa Factor each number.
16a2 2 2 2 a Circle the common prime factors. GCF: 2 •2 •a or 4a
Write each term as the product of the GCF and its remaining factors. Then use the Distributive Property to factor out the GCF.
12a216a4a(3a) 4a(2 2) Rewrite each term using the GCF.
4a(3a) 4a(4) Simplify remaining factors.
4a(3a4) Distributive Property
Thus, the completely factored form of 12a216a is 4a(3a4).
Example
1
Example
1
Nolan Ryan, the greatest strike-out pitcher in the history of baseball, had a fastball clocked at 98 miles per hour or about 151 feet per second. If he threw a ball directly upward with the same velocity, the height h of the ball in feet above the point at which he released it could be modeled by the formula h151t16t2, where
t is the time in seconds. You can use factoring
and the Zero Product Property to determine how long the ball would remain in the air before returning to his glove.
• Factor polynomials by using the Distributive Property.
• Solve quadratic equations of the form ax2bx0.
Vocabulary
• factoring
• factoring by grouping
Look Back
To review the Distributive Property, see Lesson 1-5.
The Distributive Property can also be used to factor some polynomials having four or more terms. This method is called because pairs of terms are grouped together and factored. The Distributive Property is then applied a second time to factor a common binomial factor.
factoring by grouping
482 Chapter 9 Factoring
Use Grouping
Factor 4ab8b3a6.4ab8b3a6
(4ab8b) (3a 6) Group terms with common factors.
4b(a2) 3(a2) Factor the GCF from each grouping.
(a 2)(4b3) Distributive Property
CHECK Use the FOIL method.
F O I L (a2)(4b3)(a)(4b) (a)(3) (2)(4b) (2)(3) 4ab 3a 8b 6
Example
2
Example
2
Factoring by
Grouping
Sometimes you can group terms in more than one way when factoring a polynomial. For example, the polynomial in Example 2 could have been factored in the following way. 4ab8b3a6
(4ab3a) (8b6)
a(4b3) 2(4b3)
(4b3)(a2) Notice that this result is the same as in Example 2.
Study Tip
Factoring
Trinomials
Since the order in which factors are multiplied does not affect the product, (5x3)(y7) is also a correct factoring of 35x5xy3y21.
Study Tip
Factoring by Grouping
• Words A polynomial can be factored by grouping if all of the followingsituations exist.
• There are four or more terms.
• Terms with common factors can be grouped together.
• The two common factors are identical or are additive inverses of each other.
• Symbols axbxaybyx(ab) y(ab)
(ab)(xy) b. 18cd212c2d9cd
18cd2233cdd Factor each number.
12c2d223ccd Circle the common prime factors. 9cd33cd
GCF: 3cd or 3cd
18cd212c2d9cd3cd(6d) 3cd(4c) 3cd(3) Rewrite each term using the GCF.
3cd(6d4c3) Distributive Property
Recognizing binomials that are additive inverses is often helpful when factoring by grouping. For example, 7 y and y7 are additive inverses because their sum is 0. By rewriting 7 y in the factored form 1(y7), factoring by grouping is made possible in the following example.
Use the Additive Inverse Property
Factor 35x5xy3y21.35x5xy3y21 (35x5xy) (3y21) Group terms with common factors.
5x(7 y) 3(y7) Factor the GCF from each grouping.
5x(1)(y7) 3(y7) 7 y 1(y7)
5x(y7) 3(y7) 5x(1) 5x
(y 7)(5x3) Distributive Property
Example
3
Zero Product Property
• Words If the product of two factors is 0, then at least one of the factorsmust be 0.
• Symbols For any real numbers a and b, if ab0, then either a0, b0, or both a and b equal zero.
Lesson 9-2 Factoring Using the Distributive Property 483
SOLVE EQUATIONS BY FACTORING
Some equations can be solved by factoring. Consider the following products.6(0)0 0(3) 0 (5 5)(0) 0 2(3 3) 0
Notice that in each case, at least one of the factors is zero. These examples illustrate the Zero Product Property.
Solve an Equation in Factored Form
Solve (d5)(3d4) 0. Then check the solutions.If (d5)(3d4) 0, then according to the Zero Product Property either
d5 0 or 3d4 0.
(d5)(3d4) 0 Original equation
d5 0 or 3d4 0 Set each factor equal to zero.
d5 3d 4 Solve each equation.
d 4
3 The solution set is
5, 43
.CHECK Substitute 5 and 4
3for d in the original equation.
(d5)(3d4)0 (d5)(3d4) 0 (55)[3(5)4] 0
4 3 53 4 340 (0)(19) 0 1 3 9 (0) 0 0 0 0 0Example
4
Example
4
Common
Misconception
You may be tempted to try to solve the equation in Example 5 by dividing each side of the equation by x. Remember, however, that xis an unknown quantity. If you divide by x, you may actually be dividing by zero, which is undefined.
Study Tip
Solve an Equation by Factoring
Solve x27x. Then check the solutions.
Write the equation so that it is of the form ab0.
x27x Original equation
x27x0 Subtract 7x from each side.
x(x 7) 0 Factor the GCF of x2and 7x, which is x.
x0 or x7 0 Zero Product Property
x7 Solve each equation.
The solution set is {0, 7}. Check by substituting 0 and 7 for x in the original equation.
Example
5
Example
5
If an equation can be written in the form ab0, then the Zero Product Property can be applied to solve that equation.
484 Chapter 9 Factoring
Practice and Apply
Practice and Apply
1. Write4x212x as a product of factors in three different ways. Then decide which of the three is the completely factored form. Explain your reasoning.
2. OPEN ENDED Give an example of the type of equation that can be solved by using the Zero Product Property.
3. Explainwhy (x2)(x4)0 cannot be solved by dividing each side by x2.
Factor each polynomial.
4. 9x236x 5. 16xz40xz2
6. 24m2np236m2n2p 7. 2a3b28ab16a2b3
8. 5y215y4y12 9. 5c 10c22d4cd
Solve each equation. Check your solutions.
10. h(h5) 0 11. (n4)(n2) 0 12. 5m3m2
PHYSICAL SCIENCE For Exercises 13–15, use the information below and in the graphic.
A flare is launched from a life raft. The height h of the flare in feet above the sea is modeled by the formula h100t16t2, where t is the time in seconds after the flare is launched.
13. At what height is the flare when it returns to the sea?
14. Let h0 in the equation h100t 16t2and solve for t.
15. How many seconds will it take for the flare to return to the sea? Explain your reasoning.
h 100t 16t2
100 ft /s
h 0
Factor each polynomial.
16. 5x30y 17. 16a4b 18. a5ba
19. x3y2x 20. 21cd3d 21. 14gh18h
22. 15a2y30ay 23. 8bc224bc 24. 12x2y2z40xy3z2
25. 18a2bc248abc3 26. aa2b2a3b3 27. 15x2y225xy x
28. 12ax320bx232cx 29. 3p3q9pq236pq 30. x22x3x6
31. x25x7x35 32. 4x2 14x6x21 33. 12y29y 8y6
34. 6a215a8a20 35. 18x230x3x5
36. 4ax3ay4bx3by 37. 2my7x7m2xy
38. 8ax6x12a9 39. 10x214xy15x21y
GEOMETRY For Exercises 40 and 41, use the following information.
A quadrilateral has 4 sides and 2 diagonals. A pentagon has 5 sides and 5 diagonals. You can use 1
2n2 3
2n to find the number of diagonals in a polygon with n sides.
40. Write this expression in factored form.
41. Find the number of diagonals in a decagon (10-sided polygon).
Homework Help
For See Exercises Examples 16–29, 1 40–47 30–39 2, 3 48–61 4, 5Extra Practice
See page 840.Concept Check
Guided Practice
Application
Lesson 9-2 Factoring Using the Distributive Property 485 SOFTBALL For Exercises 42 and 43, use the following information.
Albertina is scheduling the games for a softball league. To find the number of games she needs to schedule, she uses the equation g1
2n2 1
2n, where g represents the number of games needed for each team to play each other team exactly once and n represents the number of teams.
42. Write this equation in factored form.
43. How many games are needed for 7 teams to play each other exactly 3 times?
GEOMETRY Write an expression in factored form for the area of each shaded region.
44. 45.
GEOMETRY Find an expression for the area of a square with the given perimeter. 46. P12x20y in. 47. P36a16b cm
Solve each equation. Check your solutions.
48. x(x24) 0 49. a(a16) 0 50. (q4)(3q15) 0 51. (3y9)(y7) 0 52. (2b3)(3b8) 0 53. (4n5)(3n7) 0 54. 3z212z0 55. 7d235d0 56. 2x25x 57. 7x26x 58. 6x2 4x 59. 20x2 15x
60. MARINE BIOLOGY In a pool at a water park, a dolphin jumps out of the water traveling at 20 feet per second. Its height h, in feet, above the water after
t seconds is given by the formula h20t16t2. How long is the dolphin in the air before returning to the water?
61. BASEBALL Malik popped a ball straight up with an initial upward velocity of 45 feet per second. The height h, in feet, of the ball above the ground is modeled by the equation h2 48t16t2. How long was the ball in the air if the catcher catches the ball when it is 2 feet above the ground?
62. CRITICAL THINKING Factor axyaxbyaybxbxy.
63. Answer the question that was posed at the beginning of the lesson.
How can you determine how long a baseball will remain in the air?
Include the following in your answer:
• an explanation of how to use factoring and the Zero Product Property to find how long the ball would be in the air, and
• an interpretation of each solution in the context of the problem.
WRITING IN MATH r r 2 2 2 2 a b www.algebra1.com/self_check_quiz
Marine Biologist
Marine biologists study factors that affect organisms living in and near the ocean.
Online Research
For information about a career as a marine biologist, visit:
www.algebra1.com/ careers
486 Chapter 9 Factoring
P
ractice Quiz 1
P
ractice Quiz 1
1. Find the factors of 225. Then classify the number as prime or composite. (Lesson 9-1)
2. Find the prime factorization of 320. (Lesson 9-1)
3. Factor 78a2bc3completely. (Lesson 9-1)
4. Find the GCF of 54x3, 42x2y, and 30xy2. (Lesson 9-1)
Factor each polynomial. (Lesson 9-2)
5. 4xy2xy 6. 32a2b40b38a2b2 7. 6py16p15y40
Solve each equation. Check your solutions. (Lesson 9-2)
8. (8n5)(n4) 0 9. 9x227x0 10. 10x2 3x
64. The total number of feet in x yards, y feet, and z inches is
3xy1z2. 12(xyz). x3y36z. 3 x 6 1 y 2 z.
65. QUANTITATIVE COMPARISON Compare the quantity in Column A and the quantity in Column B. Then determine whether:
the quantity in Column A is greater, the quantity in Column B is greater, the two quantities are equal, or
the relationship cannot be determined from the information given. D C B A D C B A
Standardized
Test Practice
Maintain Your Skills
Maintain Your Skills
Factor each number. Then classify each number as prime or composite. (Lesson 9-1)
66. 123 67. 300 68. 67
Find each product. (Lesson 8-8)
69. (4s33)2 70. (2p5q)(2p5q) 71. (3k8)(3k8)
Simplify. Assume that no denominator is equal to zero. (Lesson 8-2)
72. s s 4 7 73. 1 1 8 2 x x 3 2 y y 4 1 74. 1 3 7 4 ( p p 7 3 q q 2 r r 1 5 )2
75. FINANCE Michael uses at most 60% of his annual FlynnCo stock dividend to purchase more shares of FlynnCo stock. If his dividend last year was $885 and FlynnCo stock is selling for $14 per share, what is the greatest number of shares that he can purchase? (Lesson 6-2)
PREREQUISITE SKILL Find each product.
(To review multiplying polynomials, see Lesson 8-7.)
76. (n8)(n3) 77. (x4)(x 5) 78. (b10)(b7)
79. (3a1)(6a4) 80. (5p2)(9p3) 81. (2y5)(4y3)
Mixed Review
the negative solution of the negative solution of (a2)(a5) 0 (b6)(b1) 0
Column A Column B
Getting Ready for
the Next Lesson
Algebra Activity Factoring Trinomials 487
A Preview of Lesson 9-3
Factoring Trinomials
You can use algebra tiles to factor trinomials. If a polynomial represents the area of a rectangle formed by algebra tiles, then the rectangle’s length and width are factors of the area.
(continued on the next page)
Activity 1
Use algebra tiles to factor x2 6x 5. Model the polynomial x26x5.Place the x2tile at the corner of the product mat. Arrange the 1 tiles into a rectangular array. Because 5 is prime, the 5 tiles can be arranged in a rectangle in one way, a 1-by-5 rectangle.
Complete the rectangle with the x tiles. The rectangle has a width of x1 and a length of x5. Therefore,
x26x + 5 (x1)(x5). x 1 x 5 1 1 1 1 1 x2 x x x x x x 1 1 1 1 1 x2 x2 1 1 1 1 1 x x x x x x
Activity 2
Use algebra tiles to factor x2 7x 6. Model the polynomialx27x6.
Place the x2tile at the corner of the product mat. Arrange the 1 tiles into a rectangular array. Since 6 2 3, try a 2-by-3 rectangle. Try to complete the rectangle. Notice that there are two extra x tiles.
1 1 1 1 1 1 x2 x2 x x x x x 1 1 1 1 1 1 x x
488Investigating Slope-Intercept Form
Algebra Activity
Algebra Activity
488 Chapter 9 Factoring
Arrange the 1 tiles into a 1-by-6 rectangular array. This time you can complete the rectangle with the x tiles.
The rectangle has a width of x1 and a length of x6. Therefore,
x27x6 (x1)(x6). x 1 x 6 1 1 1 1 1 1 x2 x x x x x x x
Activity 3
Use algebra tiles to factor x2 2x 3. Model the polynomial x22x3.Place the x2tile at the corner of the product mat. Arrange the 1 tiles into a 1-by-3 rectangular array as shown.
Place the x tile as shown. Recall that you can add zero-pairs without changing the value of the polynomial. In this case, add a zero pair of x tiles.
The rectangle has a width of x1 and a length of x3. Therefore, x22x3 (x1)(x3). x2 xxx x 1 x 3 x2 111 111 xx x zero pair x2 111 x x x2 1 1 1
Model
Use algebra tiles to factor each trinomial.
1. x24x3 2. x25x4 3. x2x6 4. x23x2
Factoring Trinomials:
x
2
bx
c
can factoring be used to find the dimensions of a garden?
can factoring be used to find the dimensions of a garden?
• Factor trinomials of the form x2bxc.
• Solve equations of the form x2bxc0.
Tamika has enough bricks to make a 30-foot border around the rectangular vegetable garden she is planting. The booklet she got from the nursery says that the plants will need a space of 54 square feet to grow. What should the dimensions of her garden be? To solve this problem, you need to find two numbers whose product is 54 and whose sum is 15, half the perimeter of the garden.
A 54 ft2
P 30 ft
Reading Math
A quadratic trinomialis a trinomial of degree 2. This means that the greatest exponent of the variable is 2.
Study Tip
Factoring x
2bx
c
• Words To factor quadratic trinomials of the form x2bxc, find
two integers, m and n, whose sum is equal to b and whose product is equal to c. Then write x2bxc using the pattern (xm)(xn).
• Symbols x2bxc(xm)(xn) when mnb and mnc.
• Example x25x6(x2)(x3), since 235 and 236.
FACTOR
x
2bx
c
In Lesson 9-1, you learned that when two numbers are multiplied, each number is a factor of the product. Similarly, when two binomials are multiplied, each binomial is a factor of the product.To factor some trinomials, you will use the pattern for multiplying two binomials. Study the following example.
F O I L
(x2)(x3)(xx)(x3)(x2)(23) Use the FOIL method.
x23x2x6 Simplify.
x2(32)x6 Distributive Property
x25x6 Simplify.
Observe the following pattern in this multiplication. (x2)(x3)x2(32)x(23) (xm)(xn)x2(nm)xmn
x2(mn)xmn
x2 bx c bmnand cmn
Notice that the coefficient of the middle term is the sum of m and n and the last term is the product of m and n. This pattern can be used to factor quadratic trinomials of the form x2bxc.
To determine m and n, find the factors of c and use a guess-and-check strategy to find which pair of factors has a sum of b.
490 Chapter 9 Factoring
b and c Are Positive
Factor x26x8.In this trinomial, b6 and c8. You need to find two numbers whose sum is 6 and whose product is 8. Make an organized list of the factors of 8, and look for the pair of factors whose sum is 6.
Factors of 8 Sum of Factors
1, 8 9
2, 4 6 The correct factors are 2 and 4.
x26x8(xm)(xn) Write the pattern.
(x2)(x4) m2 and n4
CHECK You can check this result by multiplying the two factors.
F O I L (x2)(x4)x24x2x8 FOIL method x26x8 Simplify.
Example
1
Example
1
Testing Factors
Once you find the correct factors, there is no need to test any other factors. Therefore, it is not necessary to test 4 and
4 in Example 2.
Study Tip
b Is Negative and c Is Positive
Factor x210x16.In this trinomial, b 10 and c16. This means that mn is negative and mn is
positive. So m and n must both be negative. Therefore, make a list of the negative factors of 16, and look for the pair of factors whose sum is 10.
Factors of 16 Sum of Factors
1,16 17
2, 8 10
4, 4 8
The correct factors are 2 and 8.
x210x16(xm)(xn) Write the pattern.
(x2)(x8) m 2 and n 8 CHECK You can check this result by using a
graphing calculator. Graph yx210x16 and y(x2)(x8) on the same screen. Since only one graph appears, the two graphs must coincide. Therefore, the trinomial has been factored correctly.
[10, 10] scl: 1 by [10, 10] scl: 1
Example
2
Example
2
When factoring a trinomial where b is negative and c is positive, you can use what you know about the product of binomials to help narrow the list of possible factors.
You will find that keeping an organized list of the factors you have tested is particularly important when factoring a trinomial like x2x12, where the value of c is negative.
Lesson 9-3 Factoring Trinomials: x2bxc 491
SOLVE EQUATIONS BY FACTORING
Some equations of the formx2bxc0 can be solved by factoring and then using the Zero Product Property.
www.algebra1.com/extra_examples
b Is Positive and c Is Negative
Factor x2x12.In this trinomial, b1 and c 12. This means that mn is positive and mn is
negative. So either m or n is negative, but not both. Therefore, make a list of the factors of 12, where one factor of each pair is negative. Look for the pair of factors whose sum is 1.
Factors of 12 Sum of Factors
1,12 11
1, 12 11
2, 6 4
2, 6 4
3, 4 1
3, 4 1 The correct factors are 3 and 4.
x2x12(xm)(xn) Write the pattern.
(x3)(x4) m 3 and n4
Example
3
Example
3
b Is Negative and c Is Negative
Factor x27x18.Since b 7 and c 18, mn is negative and mn is negative. So either m or n
is negative, but not both.
Factors of 18 Sum of Factors
1,18 17
1, 18 17
2, 9 7 The correct factors are 2 and 9.
x27x18(xm)(xn) Write the pattern.
(x2)(x9) m2 and n 9
Example
4
Example
4
Solve an Equation by Factoring
Solve x25x6. Check your solutions.x25x6 Original equation
x25x60 Rewrite the equation so that one side equals 0. (x1)(x6)0 Factor.
x10 or x60 Zero Product Property
x1 x 6 Solve each equation. The solution set is {1, 6}.
CHECK Substitute 1 and 6 for x in the original equation.
x25x6 x25x6 (1)25(1)6 (6)25(6)6 66 66
Example
5
Example
5
Alternate Method
You can use the opposite of FOIL to factor trinomials. For instance, consider Example 3.
x2x12
(x■)(x■) Try factor pairs of 12 until the sum of the products of the Inner and Outer terms is x.
Study Tip
Guided Practice
492 Chapter 9 Factoring
Solve a Real-World Problem by Factoring
YEARBOOK DESIGN A sponsor forthe school yearbook has asked that the length and width of a photo in their ad be increased by the same amount in order to double the area of the photo. If the photo was originally 12 centimeters wide by 8 centimeters long, what should the new dimensions of the enlarged photo be?
Explore Begin by making a diagram like the one shown above, labeling the appropriate dimensions.
Plan Let xthe amount added to each dimension of the photo. The new length times the new width equals the new area.
x12 x8 2(8)(12)
old area Solve (x12)(x8)2(8)(12) Write the equation.
x220x96192 Multiply.
x220x960 Subtract 192 from each side. (x24)(x4)0 Factor.
x240 or x40 Zero Product Property
x 24 x4 Solve each equation.
Examine The solution set is {24, 4}. Only 4 is a valid solution, since dimensions cannot be negative. Thus, the new length of the photo should be 412 or 16 centimeters, and the new width should be 48 or 12 centimeters.
12 8 x xExample
6
Example
6
GUIDED PRACTICE KEY
Concept Check
1. Explainwhy, when factoring x26x9, it is not necessary to check the sum of the factor pairs 1 and 9 or 3 and 3.2. OPEN ENDED Give an example of an equation that can be solved using the factoring techniques presented in this lesson. Then, solve your equation.
3. FIND THE ERROR Peter and Aleta are solving x22x15.
Who is correct? Explain your reasoning.
Factor each trinomial.
4. x211x24 5. c23c2 6. n213n48 7. p22p35 8. 7227aa2 9. x24xy3y2 Aleta x2 + 2x = 15 x2 + 2x - 15 = 0 (x - 3)(x + 5) = 0 x - 3 = 0 or x + 5 = 0 x = 3 x = -5 Peter x2+ 2x = 15 x (x + 2) = 15 x = 15 or x + 2 = 15 x = 13
Lesson 9-3 Factoring Trinomials: x2bxc 493
Solve each equation. Check your solutions.
10. n27n60 11. a25a360 12. p219p420
13. y29 10y 14. 9xx222 15. d23d70
16. NUMBER THEORY Find two consecutive integers whose product is 156.
Application
www.algebra1.com/self_check_quiz
Practice and Apply
Practice and Apply
Factor each trinomial.
17. a28a15 18. x212x27 19. c212c35
20. y213y30 21. m222m21 22. d27d10
23. p217p72 24. g219g60 25. x26x7
26. b2b20 27. h23h40 28. n23n54
29. y2y42 30. z218z40 31. 726ww2
32. 3013xx2 33. a25ab4b2 34. x213xy36y2
GEOMETRY Find an expression for the perimeter of a rectangle with the given area.
35. areax224x81 36. areax213x90
Solve each equation. Check your solutions.
37. x216x280 38. b220b360 39. y24y120 40. d22d80 41. a23a280 42. g24g450 43. m219m480 44. n222n720 45. z2187z 46. h215 16h 47. 24k210k 48. x220x 49. c250 23c 50. y229y 54 51. 14pp251 52. x22x674 53. x2x5617x
54. SUPREME COURT When the Justices of the Supreme Court assemble to go on the Bench each day, each Justice shakes hands with each of the other Justices for a total of 36 handshakes. The total number of handshakes h possible for
n people is given by hn22n. Write and solve an equation to determine the number of Justices on the Supreme Court.
55. NUMBER THEORY Find two consecutive even integers whose product is 168.
56. GEOMETRY The triangle has an area of 40 square centimeters. Find the height h of the triangle.
CRITICAL THINKING Find all values of k so that each trinomial can be factored using integers.
57. x2kx19 58. x2kx14
59. x28xk , k0 60. x25xk, k0
RUGBY For Exercises 61 and 62, use the following information.
The length of a Rugby League field is 52 meters longer than its width w.
61. Write an expression for the area of the field.
62. The area of a Rugby League field is 8160 square meters. Find the dimensions of the field.
(2h 6) cm
h cm
Supreme Court
The “Conference handshake” has been a tradition since the late 19th century. Source:www.supremecourtus.gov
Homework Help
For See Exercises Examples 17–36 1–4 37–53 5 54–56, 6 61, 62Extra Practice
See page 840.Maintain Your Skills
Maintain Your Skills
Solve each equation. Check your solutions. (Lesson 9-2)
70. (x3)(2x5)0 71. b(7b4)0 72. 5y2 9y
Find the GCF of each set of monomials. (Lesson 9-1)
73. 24, 36, 72 74. 9p2q5, 21p3q3 75. 30x4y5, 20x2y7, 75x3y4
INTERNET For Exercises 76 and 77, use the graph at the right.
(Lessons 3-7 and 8-3)
76. Find the percent increase in the number of domain registrations from 1997 to 2000.
77. Use your answer from Exercise 76 to verify the claim that registrations grew more than 18-fold from 1997 to 2000 is correct.
PREREQUISITE SKILL Factor each polynomial.
(To review factoring by grouping, see Lesson 9-2.)
78. 3y22y9y6 79. 3a22a12a8 80. 4x23x8x6 81. 2p26p7p21 82. 3b27b12b28 83. 4g22g6g3 494 Chapter 9 Factoring
Graphing
Calculator
Mixed Review
63. Answer the question that was posed at the beginning of the lesson.
How can factoring be used to find the dimensions of a garden?
Include the following in your answer:
• a description of how you would find the dimensions of the garden, and • an explanation of how the process you used is related to the process used to
factor trinomials of the form x2bxc.
64. Which is the factored form of x217x42?
(x1)(y42) (x2)(x21)
(x3)(x14) (x6)(x7)
65. GRID IN What is the positive solution of p213p300?
Use a graphing calculator to determine whether each factorization is correct. Write yes or no. If no, state the correct factorization.
66. x214x48(x6)(x8) 67. x216x105(x5)(x21) 68. x225x66(x33)(x2) 69. x211x210(x10)(x21) D C B A WRITING IN MATH
Standardized
Test Practice
Getting Ready for
the Next Lesson
USA TODAY Snapshots
®By Cindy Hall and Bob Laird, USA TODAY Source: Network Solutions (VeriSign)
Number of domain
registrations climbs
During the past four years, .com, .net and .org domain registrations have grown more than 18-fold:
28.2 million 1997 1998 1999 2000 1.54 million 3.36 million 9 million
FACTOR
ax
2bx
c
For trinomials of the form x2bxc, the coefficient of x2is 1. To factor trinomials of this form, you find the factors of c whose sum is b. We can modify this approach to factor trinomials whose leading coefficient is not 1.F O I L
(2x5)(3x1) 6x22x15x5 Use the FOIL method. 215 30
65 30 Observe the following pattern in this product.
6x22x15x5 ax2mxnxc
6x2 17x 5 ax2 bx c
21517 and 21565 mnb and mnac
You can use this pattern and the method of factoring by grouping to factor 6x217x5. Find two numbers, m and n, whose product is 65 or 30 and whose sum is 17.
Factors of 30 Sum of Factors
1, 30 31
2, 15 17 The correct factors are 2 and 15.
6x217x5 6x2mxnx5 Write the pattern.
6x22x15x5 m2 and n15
(6x22x) (15x5) Group terms with common factors.
2x(3x1) 5(3x1) Factor the GCF from each grouping.
(3x1)(2x5) 3x1 is the common factor. Therefore, 6x217x5 (3x1)(2x 5).
Factoring Trinomials:
ax
2
bx
c
Lesson 9-4 Factoring Trinomials: ax2bxc 495
Vocabulary
• prime polynomial• Factor trinomials of the form ax2bxc.
• Solve equations of the form ax2bxc0.
The factors of 2x27x6 are the dimensions of the rectangle formed by the algebra tiles shown below.
The process you use to form the rectangle is the same mental process you can use to factor this trinomial algebraically.
x2 1 1 1 1 1 1 x x2 x x x x x x