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WIND WEBINAR SERIES #3:

ASCE 7 10 Wind Loads for Signs, Other

Structures, Roof Top Structures &

Equipment, and Other Special Conditions

Robert Paullus, P.E., S.E., SECB Paullus Structural Consultants

(2)

Wind Loads for Solid Signs,

Other Structures, Roof-Top

Structures & Equipment, and

Other Special Conditions

Bob Paullus, P.E., S.E.

(3)

1.

1. Chapter 29– Other Structures (MWFRS

Directional Method)

a.

Conditions

b.

Limitations

c.

Solid Freestanding Walls or Signs

d.

Solid Attached Signs

e.

Design Wind Loads on Other Structures

f.

Design Wind Loads on Rooftop Structures

and Equipment on Buildings

g.

Parapets

h.

Roof Overhangs

(4)

1.

2. Chapter 30 – Part 6 - Components &

Cladding for Building Appurtenances

and Rooftop Structures and Equipment

(Directional Procedure)

a.

Parapets

b.

Roof Overhangs

c.

Rooftop Structures and Equipment for

Buildings with h ≤ 60 ft (18.3 m)

2.

3. Examples

(5)

1. The structure is a regular-shaped

structure as defined in Section 26.2.2.

Section 26.2.2 - BUILDING OR OTHER

STRUCTURE, REGULAR-SHAPED: A

building or other structure having no

unusual geometrical irregularity in spatial

form.

(6)

2. The structure does not have response

characteristics making it subject to

across-wind loading, vortex shedding, or instability

due to galloping or flutter; or it does not

have a site location for which channeling

effects or buffeting in the wake of upwind

obstructions warrant special consideration.

(7)

1. This chapter DOES consider: load

magnification effect caused by gusts in

resonance with along-wind vibrations of

flexible structures.

2. This chapter DOES NOT consider:

Unusual shapes or configurations that lead

to effects listed in Section 29.1.2 –

Conditions.

(8)

3. If your structure does not fall within the

listed limitations, it should probably be the

subject of Wind Tunnel Study.

(9)

1. No reductions allowed for apparent

shielding by buildings, other structures, or

terrain features.

a.

Individual hills

b.

Individual trees or small groves of

trees

c.

Individual levees and similar

features.

2. Reductions are afforded for Terrain

Features in determining Exposure

Categories in Chapter 26.

(10)
(11)

1. Steps 1-4 are the same as in Chapters

26-30.

a. Chapter 29, like Chapters 26-30, has its

own table, Table 29.3-1, for K

h

and K

z

b. Step 5: Eq. 29.3-1

q

z

= 0.00256K

z

K

zt

K

d

V

2

(lb/ft

2

)

2. Be careful to use q

z

or q

h

, as directed

under each section.

(12)

1. Hollow Signs and Walls are not covered.

a.

Signs which have openings that can be

pressurized

1) Boxed signs

2) Signs made from sea containers

3) Signs with large internal areas for lights

with

translucent panels

2. Research is being conducted at Texas

Tech University by Douglas Smith, PhD

Section 29.4.1 – Solid Freestanding Walls

and Solid Freestanding Signs

(13)

3. Solid Signs can have openings up to

30% of the Gross Area.

a.

Reduction factor can be applied to solid

signs with openings.

b. Reduction factor (1 - (1 - ε)1.5)

c. ε = ratio of solid area to gross area

4. If the area of openings exceeds 30% of

the gross area, it is an open sign.

Proceed to Section 29.5 - Design Wind

Loads—Other Structures

Section 29.4.1 – Solid Freestanding Walls

and Solid Freestanding Signs

(14)

5. Basic Equation: (Eq. 29.4-1)

F = q

h

GC

f

A

s

(lb)

a. q

h

= the velocity pressure evaluated at

height h (defined in Fig. 29.4-1) as

determined in accordance with

Section 29.3.2

»

h = top of the wall or sign

»

Note: q

h

is at the top of the sign or wall

and K

d

in Eq 29.3-1 is the K

d

of Solid

Freestanding Walls and Solid

Free-standing and Attached Signs in Table

Section 29.4.1 – Solid Freestanding Walls

and Solid Freestanding Signs

(15)

b. G = gust-effect factor from Section 26.9

c. C

f

= net force coefficient from Fig. 29.4-1

d.

A

s

= the gross area of the solid

free-standing wall or freefree-standing solid sign, in

ft

2

(m

2

)

Section 29.4.1 – Solid Freestanding Walls

and Solid Freestanding Signs

(16)
(17)
(18)
(19)

Load Cases to Consider

Case A – Load applied to the centroid of

the area

Case B – Load applied with an

eccentricity of 0.2*B (width of the wall or

sign)

Case C – Stepped application of reduced

wind pressures as the distance decreases

from the windward edge.

Section 29.4.1 – Solid Freestanding Walls

and Solid Freestanding Signs

(20)

Case C

Reduction in loads for walls or signs with

returns at the ends

»

Up to 40 % reduction

For Elevated Signs or walls: where s/h > 0.8,

force coefficients shall be multiplied by the

reduction factor (1.8 - s/h)

»

Accounts for reduced wind pressures

when free air flow under the wall or sign

is reduced.

Section 29.4.1 – Solid Freestanding Walls

and Solid Freestanding Signs

(21)

Section 29.4.1 – Solid Freestanding Walls

and Solid Freestanding Signs

(22)

a.

1. Requirements to use method in Section

29.4.1

a.

The plane of the sign is parallel to and in

contact with the supporting wall

b.

Edges of the sign do not extend past the

supporting wall

c.

Use Component & Cladding Wall pressures

calculated in Chapter 30

d.

Set the Internal Pressure Coefficient (GC

pi

)

equal to 0

(23)

a.

2. Procedure can also be used for

signs attached to but not in contact

with the supporting wall.

a.

Sign must be parallel to the supporting wall.

b.

Sign must not be more than three (3) feet

from the wall.

c.

Edges of the sign must be at least (3) feet in

from the free edges of the supporting wall:

a. Top of the supporting wall. b. Bottom of the supporting wall c. Side Edges of the supporting wall

(24)

Section 29.5: Design Wind Loads—Other

Structures

(25)

Basic Equation: (Eq. 29.5-1)

F = q

z

GC

f

A

f

(lb) (N)

a. q

z

= velocity pressure evaluated at height z as

defined in Section 29.3, of the centroid of area A

f

»

Note q

z

is at the centroid of the area and K

d

in

Eq 29.3-1 is the K

d

of the structure type in

Table 26.6-1

b. G = gust-effect factor from Section 26.9 (these

structures may often be flexible)

c. C

f

= force coefficients from Figs. 29.5-1

Section 29.5: Design Wind Loads—Other

Structures

(26)

d. A

f

= projected area normal to the wind except

where C

f

is specified for the actual surface area,

in ft

2

(m

2

)

Section 29.5: Design Wind Loads—Other

Structures

(27)
(28)
(29)
(30)
(31)
(32)
(33)

1.

No guidance is given for rooftop

structures on buildings > 60 feet.

2. Research in the ASCE 7 committee

suggests that it is probably acceptable to

use loads from this section for rooftop

structures on buildings > 60 feet, but this

has not been confirmed yet.

3. Equation 29.5-2 gives lateral pressure

on the rooftop structure.

Section 29.5-1 – Rooftop Structures and

Equipment For Buildings with h ≤ 60 feet

(34)

Lateral Wind force on Rooftop Structures

Basic Equation: (Eq 29.5-2)

F

h

= q

h

(GC

r

)A

f

(lb) (N)

»

(GC

r

) = 1.9 for rooftop structures and

equipment with A

f

less than (0.1Bh). (GC

r

)

shall be permitted to be reduced linearly

from 1.9 to 1.0 as the value of A

f

is

increased from (0.1Bh) to (Bh).

»

q

h

= velocity pressure evaluated at mean

roof height of the building

Section 29.5-1 – Rooftop Structures and

Equipment For Buildings with h ≤ 60 feet

(35)

Lateral Wind force on Rooftop Structures

»

Note, q

h

is at the mean roof height and K

d

in Eq 29.3-1 is the K

d

of the building, in

Table 26.6-1, on which the rooftop

structure sits.

»

A

f

= vertical projected area of the rooftop

structure or equipment on a plane normal

to the direction of wind, in ft

2

(m

2

)

Section 29.5-1 – Rooftop Structures and

Equipment For Buildings with h ≤ 60 feet

(36)

Vertical Wind force on Rooftop Structures

Basic Equation: (Eq 29.5-3)

F

v

= q

h

(GC

r

)A

r

(lb) (N)

»

(GC

r

) = 1.5 for rooftop structures and

equipment with A

r

less than (0.1BL). (GCr)

shall be permitted to be reduced linearly

from 1.5 to 1.0 as the value of A

r

is

increased from (0.1BL) to (BL).

»

q

h

= velocity pressure evaluated at mean

roof height of the building

Section 29.5-1 – Rooftop Structures and

Equipment For Buildings with h ≤ 60 feet

(37)

Vertical Wind force on Rooftop Structures

»

Note q

h

is at the mean roof height and K

d

in

Eq 29.3-1 is the K

d

of the building, in Table

26.6-1, on which the rooftop structure sits.

»

A

r

= horizontal projected area of rooftop

structure or equipment, in ft

2

(m

2

)

Section 29.5-1 – Rooftop Structures and

Equipment For Buildings with h ≤ 60 feet

(38)

Lateral C & C pressure (psf) shall be equal

to the lateral force (Lbs) calculated with

equation (29.5-2) DIVIDED BY the

RESPECTIVE WALL Surface area of the

Rooftop Structure considered.

Forces (psf) shall be considered to act inward

and outward

Section 30.11 – Component & Cladding

Loads for Rooftop Structures and

(39)

Vertical C & C pressure (Lbs) shall be

equal to the vertical force (Lbs) calculated

with equation (29.5-3) DIVIDED BY the

Horizontal projected area of the roof of

the Rooftop Structure considered.

The pressures are ONLY required to be

considered to act in the UPWARD direction.

Section 30.11 – Component & Cladding

Loads for Rooftop Structures and

(40)

Comment: If the Rooftop Structure is

large (10’x20’ or larger), consider looking

at the downward pressures from the

building C&C loading figures and make

some judgment about downward wind

loading rooftop structures that resemble

small buildings (penthouses for instance).

Vertical Wind Load would act in addition to

Dead and Roof Live Loads or Snow Loads.

Section 30.11 – Component & Cladding

Loads for Rooftop Structures and

(41)
(42)

Other Resources

• Prepared by: Task

Committee on Wind-Induced Forces of the

Petrochemical Committee of the Enginery Division of ASCE

• Several of those on the Task Committee are on the ASCE 7 Wind

Subcommittee

(43)

“Wind loads on parapets are specified in

Section 27.4.5 for buildings of all heights

designed using the Directional Procedure

and in Section 28.4.2 for low-rise

buildings designed using the Envelope

Procedure.”

Method presented is the Directional

Procedure

(44)

Chapter 28 – The Envelope Method, is

exactly the same.

Chapter 28 uses the velocity pressure

determined with the Envelope Method,

rather than the velocity pressure in Chapter

27 using the Directional Method.

(45)

MWFRS pressures due to parapets

Rigid or Flexible Buildings

Applies to Flat, Gable, or Hip Roofs

(46)

Basic Equation: (Eq 27.4-4)

p

p

= q

p

(GC

pn

) (lb/ft

2

)

p

p

= combined net pressure on the parapet

due to the combination of the net pressures

from the front and back parapet surfaces.

Plus (and minus) signs signify net pressure

acting toward (and away from) the front

(exterior) side of the parapet

(47)

q

p

= velocity pressure evaluated at the top of

the parapet

»

(GC

pn

) = combined net pressure

coefficient

= +1.5 for windward parapet

= –1.0 for leeward parapet

(48)

Section 27.4.5 – Parapets (MWFRS)

(49)

Applicable to All Building Types

Applicable to All Building Heights

Except Where the Provisions of Part 4

are used (Simplified Method for

Buildings with h ≤ 160 feet)

(50)

Basic Equation: (Eq. 30.9-1)

p = q

p

((GC

p

) – (GC

pi

))

q

p

= velocity pressure evaluated at the top of

the parapet

(GC

p

) = external pressure coefficient given in

»

Fig. 30.4-1 for walls with h ≤ 60 ft (48.8 m)

»

Figs. 30.4-2A to 30.4-2C for flat roofs,

gable roofs, and hip roofs

»

Fig. 30.4-3 for stepped roofs

(51)

(GC

p

) = external pressure coefficient given in

»

Fig. 30.4-4 for multispan gable roofs

»

Figs. 30.4-5A and 30-5B for monoslope

roofs

»

Fig. 30.4-6 for sawtooth roofs

»

Fig. 30.4-7 for domed roofs of all heights

»

Fig. 30.6-1 for walls and flat roofs with h >

60 ft (18.3 m)

»

Fig. 27.4-3 footnote 4 for arched roofs

(52)

(GC

pi

) = internal pressure coefficient from

Table 26.11-1, based on the porosity of the

parapet envelope.

Consider Two (2) Load Cases when

evaluating C & C pressures on parapets

Case A – Pressures on the surfaces of the

Windward parapet

Case B – Pressures on the surfaces of the

Leeward parapet

(53)

Specifics of Case A:

Windward Parapet shall consist of applying the

applicable positive wall pressure from Fig. 30.4-1

(h ≤ 60 ft (18.3 m)) or Fig. 30.6-1 (h > 60 ft (18.3

m)) to the windward surface of the parapet while

applying the applicable negative edge or corner

zone roof pressure from Figs. 30.4-2 (A, B or C),

30.4-3, 30.4-4, 30.4-5 (A or B), 30.4-6, 30.4-7, Fig.

27.4-3 footnote 4, or Fig. 30.6-1 (h > 60 ft (18.3

m)) as applicable to the leeward surface of the

parapet.

(54)

Specifics of Case B:

Leeward Parapet shall consist of applying the

applicable positive wall pressure from Fig. 30.4-1

(h ≤ 60 ft (18.3 m)) or Fig. 30.6-1 (h > 60 ft (18.3

m)) to the windward surface of the parapet, and

applying the applicable negative wall pressure

from Fig. 30.4-1 (h ≤ 60 ft (18.3 m)) or Fig. 30.6-1

(h > 60 ft (18.3 m)) as applicable to the leeward

surface. Edge and corner zones shall be arranged

as shown in the applicable figures. (GCp)

(55)

Section 30.9 – C & C Loading on Parapets

• FIGURE C29.7-1 Design Wind Pressures on Parapets

If internal pressure

is present, both

load cases should

be evaluated

under positive and

negative internal

pressure.

(56)

Step 1: Determine risk category of building,

see Table 1.5-1

Step 2: Determine the basic wind speed, V,

for applicable risk category, see Figure

26.5-1A, B or C

Table 30.9-1 – Steps to Determine C&C

Wind Loads on Parapets

(57)

Step 3: Determine wind load parameters:

Wind directionality factor, K

d

, see Section 26.6

and Table 26.6-1

» Use Kd for Buildings C&C (0.85)

– Exposure category B, C or D, see Section 26.7

Topographic factor, K

zt

, see Section 26.8 and Fig.

26.8-1

Enclosure classification, see Section 26.10

Internal pressure coefficient, (GC

pi

), see Section

26.11 and Table 26.11-1

Table 30.9-1 – Steps to Determine C&C

Wind Loads on Parapets

(58)

Step 4: Determine velocity pressure

exposure coefficient, K

h

, at top of the

parapet see Table 30.3-1

Step 5: Determine velocity pressure, q

p

, at

the top of the parapet using Eq. 30.3-1

Table 30.9-1 – Steps to Determine C&C

Wind Loads on Parapets

(59)

Step 6: Determine external pressure

coefficient for wall and roof surfaces

adjacent to parapet, (GC

p

)

Walls with h ≤ 60 ft., see Fig. 30.4-1

Flat, gable and hip roofs, see Figs. 30.4-2A to

30.4-2C

Stepped roofs, see Fig. 30.4-3

Multispan gable roofs, see Fig. 30.4-4

Monoslope roofs, see Figs. 30.4-5A and 30.4-5B

Sawtooth roofs, see Fig. 30.4-6

Table 30.9-1 – Steps to Determine C&C

Wind Loads on Parapets

(60)

Step 6: (Continued)

Domed roofs of all heights, see Fig. 30.4-7

Walls and flat roofs with h > 60 ft., see Fig. 30.6-1

Arched roofs, see footnote 4 of Fig. 27.4-3

Step 7: Calculate wind pressure, p, using Eq.

30.9-1 on windward and leeward face of

parapet, considering two load cases (Case A

and Case B) as shown in Fig. 30.9-1.

Table 30.9-1 – Steps to Determine C&C

Wind Loads on Parapets

(61)
(62)

Figure 30.6-1

Note 7 defines parapets > 3 feet as tall

parapets

Reduced corner pressures on parapet

Similar note on other figures

(63)

“Wind loads on roof overhangs are

specified in Section 27.4.4 for buildings of

all heights designed using the Directional

Procedure and in Section 28.4.3 for

low-rise buildings designed using the Envelope

Procedure.”

Present Direction Method in Section 27.4.1

Envelope Method in Section 28.3.1 is similar

Uses different factor for C

p

(64)

The positive external pressure on the

bottom surface of windward roof

overhangs shall be determined using C

p

=

0.8 and combined with the top surface

pressures determined using Fig. 27.4-1.

(65)
(66)

Section 27.4 – Roof Overhangs (MWFRS)

Must consider cases with positive internal

pressure and negative internal pressure

(67)

Section 30.10 – C & C Loading on Roof

Overhangs

Applicable to All Building Types

Applicable to All Building Heights

Except Where the Provisions of Part 4

are used (Simplified Method for

Buildings with h ≤ 160 feet)

(68)

Section 30.10 – C & C Loading on Roof

Overhangs

Basic Equation: (Eq. 30.10-1)

p = q

h

((GC

p

) – (GC

pi

))

q

h

= velocity pressure from Section 30.3.2

evaluated at mean roof height h using

exposure defined in Section 26.7.3

(GC

p

) = external pressure coefficients for

overhangs given in Figs. 30.4-2A to 30.4-2C

(flat roofs, gable roofs, and hip roofs),

including contributions from top and bottom

surfaces of overhang.

(69)

Section 30.10 – C & C Loading on Roof

Overhangs

»

The external pressure coefficient for the

covering on the underside of the roof

overhang is the same as the external

pressure coefficient on the adjacent wall

surface, adjusted for effective wind area,

determined from Figure 30.4-1 or Figure

30.6-1 as applicable

(GC

pi

) = internal pressure coefficient

(70)
(71)
(72)

Step 1: Determine risk category of building,

see Table 1.5-1

Step 2: Determine the basic wind speed, V,

for applicable risk category, see Figure

26.5-1A, B or C

Table 30.10-1 – Steps to Determine C&C

Wind Loads on Roof Overhangs

(73)

Step 3: Determine wind load parameters:

Wind directionality factor, K

d

, see Section 26.6

and Table 26.6-1

» Use Kd for Buildings C&C (0.85)

– Exposure category B, C or D, see Section 26.7

Topographic factor, K

zt

, see Section 26.8 and Fig.

26.8-1

Enclosure classification, see Section 26.10

Internal pressure coefficient, (GC

pi

), see Section

26.11 and Table 26.11-1

Table 30.10-1 – Steps to Determine C&C

Wind Loads on Roof Overhangs

(74)

Step 4: Determine velocity pressure

exposure coefficient, K

h

, see Table 30.3-1

Step 5: Determine velocity pressure, q

h

, at

mean roof height h using Eq. 30.3-1

Table 30.10-1 – Steps to Determine C&C

Wind Loads on Roof Overhangs

(75)

Step 6: Determine external pressure

coefficient, (GCp), using Figs. 30.4-2A

through C for flat, gabled and hip roofs.

Step 7: Calculate wind pressure, p, using Eq.

30.10-1. Refer to Figure 30.10-1

Table 30.10-1 – Steps to Determine C&C

Wind Loads on Roof Overhangs

(76)
(77)

The design wind force for other structures

shall be not less than 16 lb/ft

2

(0.77 kN/m

2

)

multiplied by the area A

f

.

16 psf is 10 psf from ASCE 7-05 times 1.6 to bring

the load to a strength level load.

Apply to the full projected area in each

orthogonal direction.

Section 29.8 – Minimum Design Wind

Loading (MWFRS)

(78)

Loads on many shapes in industrial plants

Tanks, Silos, Pipe racks, Partially Clad

Frames, etc.

See ASCE report: “Wind Loads for

Petrochemical and Other Industrial

Facilities”

Wind Loads on roof mounted Solar

Photovoltaic Arrays

See new SEOC Guide

(79)
(80)

Office Complex

Location: Wichita, KS

Freestanding Sign

3-Story Office

5-foot tall parapet

Roof Top Unit

Well Pump & Maintenance Building

Roof Overhang

Chemical Storage Silo

(81)

Site Parameters Common to All Examples

Exposure (Terrain Roughness): C

Location: N 37.7500, W 97.1683Section 26.7.3 (Open Farmland)

Risk Category II Structures

Table 1.5-1

Wind Velocity: 115 mph

Fig. 26.5-1Ahttp://www.atcouncil.org/windspeed/index.php

Topographic Factor, K

zt

: 1.00

Section 26.8

All Loads are Calculated to LRFD Levels

(82)
(83)

Solid Billboard Sign at Ground Level

Dimensions: 30’ Wide x 10’ HighReference Figure 29.4-1 (MWFRS)

s=10’B=30’h=10’

Kh = 0.85 (Table 29.3-1)

Kd = 0.85 (Solid Freestanding Walls & Signs)(Table 26.6-1)qh = 0.00256 KzKztKdV2 (psf)

qh = 0.00256(0.85)(1.00)(0.85)(115)2 = 24.46 psfB/s = 30’/10’ = 3.0

(84)

Enter Figure 29.4-1 for C

f

Applies to Cases A & B

For B/s = 2: Cf = 1.40

For B/s = 4: Cf = 1.35

Interpolating for B/s 3.0, Cf = 1.375G = 0.85 (Section 26.9 – Rigid Structure)F = qhGCfAs (Lb) (Eq 29.4-1)

F = (24.46 psf)(0.85)(1.375)As = 28.59 psf*AsAs = Af = 30’x10’ = 300 ft2

28.59 psf*As > 16 psf * Af (Section 29.8 Min. Load)F = 28.59 psf(300 ft2) = 8577 Lbs

For CASE A, Load is applied at the plan C.L. and at(s/2)+(0.05h) = 5.5’ above base

(85)

» See Cross-Section View, Figure 29.4-1

For CASE B, Load is applied @ 5.5’ above base and at 0.2B offset, either side of plan C.L.

» 0.2B = 0.2(30’) = 6.0’ either side of plan C.L.Check to see if CASE C must be considered

Note 3, Figure 29.4-1

If B/s ≥ 2.0, CASE C must be considered

B/s = 30’/10’ = 3.0 > 2.0, therefore consider CASE CEnter Figure 29.4-1 for Cf, under CASE C

0-s (0’-10’): Cf = 2.60s-2s (10’-20’): Cf = 1.702s-3s (10’-30’): Cf = 1.15

(86)

For CASE C, where s/h > 0.8, Cf may be multiplied by the reduction factor (1.8 – s/h)s/h = 1.0 > 0.8(1.8 – s/h) = (1.8 – 1.0) = 0.8F = qhGCfAs (Lb) (Eq 29.4-1)F1 = (24.46psf)(0.85)(2.60)(0.8)(10’x10’) = 4324 LbsF2 = (24.46psf)(0.85)(1.70)(0.8)(10’x10’) = 2828 LbsF3 = (24.46psf)(0.85)(1.15)(0.8)(10’x10’) = 1913 Lbs

» Apply F1, F2, and F3 at plan C.L. of each plan length, s, from each end of sign. See Figure.

» Apply F1, F2 and F3 at 5.5’ above base of each plan length, s

(87)
(88)

Parapet (MWFRS) (Section 29.6)

Office Building

L = 200 ft., B = 100 ft.

Roof Height: h = 40 ft.

Parapet Height: h

p

= 45 ft.

Roof Slope, Flat: 0.25:12

»

Ridge parallel to 200’ side

Exposure Category: C

Section 29.6 references Section 27.4.5 for

directional procedure for MWFRS Parapet load

determination.

(89)

pp = qp(GCpn) (psf)qp = 0.00256KhKztKdV2 (psf) (Eq 27.3-1)Kh @ hp = 45’, Kh = 1.065Kzt= 1.00 (for complex)Kd = 0.85 (Building MWFRS)(Table 26.6-1)V = 115 mph (for complex)qp = 0.00256(1.065)(1.00)(0.85)(115)2 = 30.65 psfGCpn= +1.5 for windward parapet (Section 27.4.5)GCpn= -1.0 for leeward parapet (Section 27.4.5)Windward Parapet

pp = (30.65 psf)(1.5) = 45.98 psf acting toward buildingLeeward Parapet

pp = (30.65 psf)(-1.0) = -30.65 psf acting away from building

(90)

Parapet (C & C Loads) (Section 30.9)

Office Building – same as previous

qp = 0.00256(1.065)(1.00)(0.85)(115)2 = 30.65 psffrom parapet MWFRS, above

p = qp((GCp) – (GCpi)) (Eq 30.9-1)

Parapet can be pressurized along with buildingSee Figure

GCpi = ±±±± 0.18 (Enclosed Building – Table 26.11-1)

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(92)

Studs @ 16” o.c. (both faces)

Determine Effective Wind Area of Studs

Greater of Tributary Area or Effective Width

» Effective Wind Area Definition (Section 26.2)Greater of 16”/12” = 1.33’ or

Length/3 = 5’/3 = 1.67’ (governs) » Effective Wind Area: l2/3 = 52/3 = 8.33 ft2

» If Effective Wind Area > 700 ft2, use MFWRS loadsDetermine which figure to reference from Table 30.9-1,

Step 6

Figure 30.4-1 for wall pressures, h ≤ 60 ft.

(93)

Figure 30.4-2A for roof loads, h ≤ 60 ft. and gable roofs θ ≤ 7°°°°

Determine “a” distance (Figure 30.4-1 and 30.4-2A) » Lesser of 10% of B = 0.10(100’) = 10’ and 0.4h =

0.4(40’) = 16’10’ governs

» Not less than the greater of 4% of B = 0.04(100’) = 4’ or 3’

» a = 10’

Entering Figure 30.4-1 for pressure coefficients on exterior surfaces of the parapets:

» Zone 4 Positive Pressure: GCp = 1.0 » Zone 5 Positive Pressure: GC = 1.0

(94)

» Zone 4 Negative Pressure: GCp = -1.1 » Zone 5 Negative Pressure: GCp = -1.4

Note 5 says that values of GCpmay be reduced by 10% when θ ≤ 10°°°°

» Zone 4 Positive Pressure: GCp = (0.9)1.0 = 0.9

» Zone 5 Positive Pressure: GCp = (0.9)1.0 = 0.9 Zone 4 Negative Pressure: GCp = (0.9)-1.1 = -1.0

» Zone 5 Negative Pressure: GCp = (0.9)-1.4 = -1.26Entering Figure 30.4-2A for pressure coefficients on

interior (roof side) surfaces of parapet:

» Effective Wind Area: A= 52/3 = 8.33 ft2 » a = 10 ft. as in Figure 30.4-1

Zone 1, 2, and 3 Positive Pressure: GC = 0.3

(95)

» Zone 1 Negative Pressure: GCp = -1.0 » Zone 2 Negative Pressure: GCp = -1.8 » Zone 3 Negative Pressure: GCp = -2.8

Note 5: “If a parapet equal to or higher than 3 ft (0.9m) is provided around the perimeter of the roof with θ ≤ 7°°°°, the negative values of GC

p in Zone 3 shall be equal to those for Zone 2 and positive values of GCp in Zones 2 and 3 shall be set equal to those for wall Zones 4 and 5

respectively in Figure 30.4-1.” » Parapet height hp = 5’ > 3’

Zone 3 Negative GCp is Not Applicable

Zone 2 and Zone 3 Positive Pressure GCp are those of Wall Zone 4 and Zone 5, respectively.

(96)

Step 7: Calculate wind pressure, p using Eq 30.9-1 on windward and leeward faces of parapet, considering two load cases (CASE A and CASE B) as shown in Figure 30.9-1

Note: As wind direction changes, each parapet with shift from a windward parapet to a leeward parapet.

CASE A – Windward ParapetExterior Face Wall Studs

» p = qp((GCp) – (GCpi)) (Eq 30.9-1) » With Positive Internal Pressure

Zone 4 = Zone 5

P = (30.65 psf)((0.9)-(0.18)) = 22.06 psf » With Negative Internal Pressure

Zone 4 = Zone 5

p = (30.65 psf)((0.9)-(-0.18)) = 33.10 psf

(97)

» Apply to Tributary Area, not Effective Wind Area33.10 psf(1.33’) = 44.12 plf

Interior Face (roof side) Parapet Studs » p = qp((GCp) – (GCpi)) (Eq 30.9-1) » With Positive Internal Pressure

Zone 2 (Zone 3 also treated as Zone 2)p = (30.65 psf)((-1.8)-(0.18)) = -60.69 psf » With Negative Internal Pressure

Zone 2 (Zone 3 also treated as Zone 2)p = (30.65 psf)((-1.8)-(-0.18)) = -40.65 psf » Apply to Tributary Area, not Effective Wind Area

-60.69 psf(1.33’) = -80.72 plf

(98)

CASE B – Leeward Parapet

Interior Face Parapet Studs (load toward parapet) » p = qp((GCp) – (GCpi)) (Eq 30.9-1)

» With Positive Internal Pressure

Substitute Zone 4 and Zone 5 pressures for roof Zone 2 and Zone 3 pressures, respectively. Zone 4 = Zone 5

P = (30.65 psf)((0.9)-(0.18)) = 22.06 psf » With Negative Internal Pressure

Zone 4 = Zone 5

p = (30.65 psf)((0.9)-(-0.18)) = 33.10 psf

» Apply to Tributary Area, not Effective Wind Area33.10 psf(1.33’) = 44.12 plf

(99)

Exterior Face Wall Studs (load away from parapet) » p = qp((GCp) – (GCpi)) (Eq 30.9-1)

» With Positive Internal PressureZone 4 pressure

p = (30.65 psf)((-1.0)-(0.18)) = -36.17 psfZone 5 pressure

p = (30.65 psf)((-1.26)-(0.18)) = -44.14 psf » With Negative Internal Pressure

Zone 4 pressure

p = (30.65 psf)((-1.0)-(-0.18)) = -25.13 psfZone 5 pressure

p = (30.65 psf)((-1.26)-(-0.18)) = -33.10 psf

(100)

» Apply to Tributary Area, not Effective Wind AreaZone 4-36.17 psf(1.33’) = -48.11 plfZone 5-44.14 psf(1.33’) = -58.71 plfSummary

» Exterior Wall Studs extended past roof into parapet:Zone 4: 44.12 plf (toward building)

Zone 4: -48.11 plf (away from building)

Zone 5 is anything within 10ft of the cornerZone 5: 44.12 plf (toward building)

Zone 5: -58.71 plf (away from building)

(101)

» Interior (roof side) Parapet Studs

Zone 4: 44.13 plf (toward parapet)

Zone 4: -80.72 plf (away from parapet)

Zone 5 is anything within 10ft of the cornerZone 5: 44.13 plf (toward parapet)

Zone 5: -80.92 plf (away from parapet)

(102)

Rooftop Equipment for Buildings (MWFRS)

(Section 29.5.1)

Office Building – same as previous

Plan Dimensions: 10’ wide x 20’ long

RTU Height: 4’ over 1’ tall curb

Projected Height: 4’+1’=5’

Lateral Force: F

h

= q

h

(GC

r

)A

f

(Lb) (Eq 29.5-2)

Vertical Force: F

v

= q

h

(GC

r

)A

r

(Lb) (Eq 29.5-3)

qh calculated at mean roof height of building

Kh @ h = 40’, Kh = 1.04 (Table 29.3-1)

Use Kd for building NOT Kd for rectangular Other Structures

(103)

Kd = 0.85 (Table 26.6-1)

Other parameters as previously defined for buildingqh = 0.00256(1.04)(1.00)(0.85)(115)2 = 29.93 psf

HORIZONTAL WIND FORCE

Check projected area of side compared with least projected area of building

» B*h = 100’(40’) = 8000 ft2 » Af (max) = 20’(5’) = 100 ft2 » Af <0.1Bh: 100 ft2 < 800 ft2

GCr = 1.9

Fh = (29.93 psf)(1.9)(Af) = 56.87 psf(Af) < 16 psf(Af) » Minimum Load from Section 29.8

Fh = (29.93 psf)(1.9)(100 ft2) = 5687Lbs(Eq 29.5-2)

(104)

» Perpendicular to long side

Fh = (29.93 psf)(1.9)(50 ft2) = 2843 Lbs (Eq 29.5-2) » Parallel to long side

Horizontal wind forces applied to geometric center of vertical projected plane of unit

VERTICAL WIND FORCE

Check projected area of roof compared with that of building » B*L = 100’(200’) = 20,000 ft2 » Ar = 20’(10’) = 200 ft2 » Ar<0.1BL: 200 ft2 < 2,000 ft2GCr = 1.5F = (29.93 psf)(1.5)(200 ft2) = 8979Lbs(Eq 29.5-2)

Example-Rooftop Equip. (MWFRS)

(105)

» Vertical Up

Vertical wind forces applied to geometric center of horizontal projected plane of unit

Note: The UPLIFT pressure on the top of the rooftop

equipment acts SIMULTANEOUSLY with either the Lateral pressure parallel to or perpendicular to the long edge of the rooftop equipment or structure.

The same procedure is used for a roof-mounted penthouse.

(106)

Rooftop Equipment for Buildings (C&C)

(Section 30.11)

Loads for Designing the Equipment cabinet enclosure or the wall components for a penthouse

Lateral C & C pressures

Fh = 5687 Lbs (from previous)

C & C Lateral Loads: Fh/Af = 5687 Lbs/100 ft2 = 56.87 psfLoad is applied toward or away from unit on all sidesC & C Vertical Loads: Fv/Ar = 8979 Lbs/200 ft2 = 44.90 psf

Load is applied only in the Upward direction, away from the top of the unit

(107)

Personal Recommendation (Not in the Standard)

If the unit is large (over 200 ft2), consider a minimum downward wind load.

C & C Loading from Figure 30.4-2A

» GCp = 0.2 (downward component) » Fv = qhGCp = (29.93psf)(0.2) = 6 psf

» For higher wind loads and low snow loads,

particularly less than 10 psf, this may produce a controlling load combination

(108)

Roof Overhang (MWFRS) (Section 29.7)

Equipment Building

L = 60 ft., B = 30 ft.

Eave Height: 10 ft.

Overhang Width: 3 ft.

Roof Slope: 4.375:12 (θ = 20

°

°

°

°

)

»

Ridge parallel to 60’ side

Exposure Category: C

Average Building Height: h = 13.28’ < 15’

Section 29.7 references Section 27.4.4 for

directional procedure for MWFRS Roof Overhang

(109)

Use Cp = 0.8 in Eq 27.4-1 for determining roof and wall loads over and adjacent to roof overhang

p = qGCp-qi(GCpi) (psf) (Eq 27.4-1)

G = 0.85 (rigid structure) (Section 26.9)Kzt= 1.00 (for complex)

Kd = 0.85 (Building MWFRS)(Table 26.6-1)V = 115 mph (for complex)

Kz@ z = 10’ for soffit, Kz= 0.85 (Table 27.3-1)qz = 0.00256KzKztKdV2 (psf) (Eq 27.3-1)

qz = 0.00256(0.85)(1.00)(0.85)(115)2 = 24.46 psfGCpi= ±±±± 0.18 (Enclosed building)(Figure 26.11-1)

Transverse Wind Loading governs, by Inspection

(110)

Pressure on underside of roof overhang

» p = (24.46 psf)(0.85)(0.8) – (24.46 psf)(0.18) » p = 12.23 psf (positive internal pressure) » p = (24.46 psf)(0.85)(0.8) – (24.46 psf)(-0.18) » p = 21.04 psf (negative internal pressure)

Enter Figure 27.4-1 for pressures on windward roof » h/L = 13.28’/60’ = 0.22 < 0.25

» Cp = 0.2 (Condition 1) » Cp = -0.3 (Condition 2) » Condition 1

p = (24.46 psf)(0.85)(0.2) – (24.46 psf)(0.18)p = 0.24 psf (positive internal pressure)

p = (24.46 psf)(0.85)(0.2) – (24.46 psf)(-0.18)p = 8.56 psf (negative internal pressure)

(111)

» Condition 2

p = (24.46 psf)(0.85)(-0.3) – (24.46 psf)(0.18)p = -10.64 psf (positive internal pressure)p = (24.46 psf)(0.85)(-0.3) –(24.46 psf)(-0.18)p = -1.83 psf (negative internal pressure)

» Combine Top & Bottom Pressures with Same Internal Pressure Conditions

Note: signs indicate pressure toward or away from surface

Change signs so (+) is up, globally

Change signs so (-) is down, globally

(112)

Positive Internal Pressure

povh = 12.23 psf - 0.24 psf = 11.99 psf

povh = 12.23 psf + 10.64 psf = 22.87 psf

overall povhis upward

Negative Internal Pressure

povh = 21.04 psf – 8.56 psf = 12.48 psf

povh = 21.04 psf + 1.83 psf = 22.87 psf

overall povhis upward

Note: Net effect of internal pressures is zero so that the total uplift on the overhang is the same.

(113)

Overall pressure on the Leeward Overhang is calculated the same way, but uses the negative pressure on the wall immediately adjacent to the overhang for downward pressures on soffit.

By inspection, total force on windward

overhang will control.

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(115)

Roof Overhang (C & C) (Section 30.10)

Equipment Building

Unless otherwise listed, parameters are

identical to those for the MWFRS calculations

Determine C & C loads for overhangs of roof

trusses, spaced at 2’-0” o.c.

p = q

h

[(GC

p

) – (GC

pi

)] psf (Eq 30.10-1)

K

d

= 0.85 (Building C&C) (Table 26.6-1)

All other parameters for q

h

are same as for

MFWRS

(116)

qh = 0.00256(0.85)(1.00)(0.85)(115)2 = 24.46 psf

Enter Figure 30.4-2B for Roof Overhang C & C coefficientsDetermine Effective Wind Area of Studs

Greater of Tributary Area or Effective Width

» Effective Wind Area Definition (Section 26.2)Greater of 2.0’ or (governs)

Length/3 = 3’/3 = 1.00’

» Effective Wind Area: 3’x2’ = 6.00 ft2

» If Effective Wind Area > 700 ft2, use MFWRS loadsDetermine “a” distance (Figure 30.4-1 and 30.4-2A)

» Lesser of 10% of B = 0.10(30’) = 3’ and 0.4h = 0.4(13.28’) = 5.31’

3’ governs

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» Not less than the greater of 4% of B = 0.04(30’) = 1.2’ or 3’ (3’ controls)

» a = 3’ (equal to width of overhang; therefore, Zone 1 pressures are not applicable to any part of the

overhang)Zone 2: GCp = -2.2

» p = (24.46 psf)[(-2.2) – (0.18)] = -58.21 psf with positive internal building pressure » p = (24.46 psf)[(-2.2) – (-0.18)] = -49.41 psf

with negative internal building pressureZone 3: GCp = -3.7

» p = (24.46 psf)[(-3.7) – (0.18)] = -94.90 psf with positive internal building pressure

(118)

» p = (24.46 psf)[(-3.7) – (-0.18)] = -86.10 psfwith negative internal building pressure » For the overhang portion of the truss:

Tributary Width = 2’

Upward force on the entire truss end is:

Zone 2: (-58.21 psf)(2’) = -116.42 plf

(upward)

Zone 3: (-94.90 psf)(2’) = -189.90 plf

(upward)

These are NOT the loads on the soffit material .

(119)

Section 30.10 states that the external coefficient for the

covering on the underside of the roof overhang (soffit) is the same as the external pressure coefficient on the adjacent wall surface, determined from Figure 30.4-1 or Figure 30.6-1, as applicable.

Use of the GCp with negative internal pressure yields the greatest upward load on the material on the underside of the overhang on the windward wall.

Use of the GCp with positive internal pressure yields the greatest downward load on the material on the

underside of the overhang on the leeward wall.

For this building, assuming effective wind area is the same as for the truss overhang:

(120)

» Windward Wall Soffit Material (Figure 30.4-1)Zone 4 and Zone 5: GCp = +1.0

p = (24.46 psf)[(1.0) –(-0.18)] = 28.86 psf

acting upward

» Leeward Wall Soffit Material (Figure 30.4-1)Zone 4: GCp = -1.1p = (24.46 psf)[(-1.1) –(0.18)] = -31.31 psf (acting downward)Zone 5: GCp = -1.4p = (24.46 psf)[(-1.4) –(0.18)] = -38.65 psf (acting downward)

(121)

Chemical Silo (Other Structure MWFRS)

(Section 29.5)

Silo Dimensions: h = 20’, D = 5.0’

Welded Steel Tank: smooth sides, no ladder

Roof Slope: 1:12 (conical)

Maximum rise: 2.5 inches (consider

contribution to wind load, negligible)

Unless otherwise listed, parameters for

calculation of q

z

are identical to those for the

MWFRS calculations for equipment building.

F = q GC A Lbs (Eq 29.5-1)

(122)
(123)

qz = 0.00256KzKztKdV2 (psf)

Kz = 0.90 (Building C&C) (Table 29.3-1)Kd = 0.95 (Circular Tanks) (Table 26.6-1)G = 0.85 (Rigid Structure) (Section 26.9)

qz = 0.00256(0.90)(1.00)(0.95)(115)2 = 28.95 psfGo to Table 29.5-1

» D/√ qz = 5’/Sqrt(28.95psf) = 0.93 < 2.5 » Go to bottom row

» h/D = 20’/5’ = 4.0

» Must interpolate between h/D=1.0 and h/D= 7.0 » Cf = 0.75

F = (28.95 psf)(0.85)(0.75) Af = (18.45 psf)Af F = (18.45 psf)A < (16psf)A

(124)

Af = 5’x20’ = 100 ft2

F = (18.45 psf)(100 ft2) = 1845 Lbs

» This is conservative, OR calculate F for increase in pressure as height increases

q15 = 0.00256(0.85)(1.00)(0.95)1152 = 27.34 psfq(15-20)= 0.00253(0.90)(1.00)(0.95) (115)2 = 28.95 psf » For 0-15’: D/√ qz = 5’/Sqrt(27.34psf) = 0.96 < 2.5 » Cf = 0.75F0-15 = (27.34 psf)(0.85)(0.75)Af = 17.43 psf Af > 16 psf AfF0-15 = (17.43 psf)(5’)(15’) = 1307 Lbs.F15-20 = (18.45 psf)(5’)(5’) = 461 Lbs.Total F on Silo: 1307 Lbs + 461 Lbs = 1768 Lbs

(125)

Conservative OTM: (1845 Lbs)(10’) = 18,450 ft-lbsMore Detailed OTM: (1307 Lbs)(15’/2)+(461

Lbs)(15’+5’/2) = 17,870 ft-lbs

» The taller the structure is, the more important it is to use the stepped wind force approach.

(126)

References

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