106
ON SOME GENERALIZED DIFFERENCE SEQUENCE SPACES DEFINED BY A SEQUENCE OF MODULI
Vakeel A. Khan1,* & Ayaz Ahmad2
1Department of Mathematics, A.M.U. Aligarh (INDIA)
2National Institute of Technology , Patna ,Bihar (INDIA)
*Email : [email protected]
ABSTRACT
In this paper we define some generalized sequenc spaces defined by a sequence of moduli. The results here in proved are analogous to those by ASMA BEKTAS Cigdem (2006)[Journal of Zhejiang University Science A (2006),7(12) 2093-2096] .
Keywords: Difference sequence space , Sequence of moduli, Strongly almost convergent .
1. INTRODUCTION
Let
0 be the set of all complex sequences andl ,
c
andc
0 be the sets of all bounded, convergent and null sequencesx = ( x
k)
with complex terms, respectively , normed by}.
{1,2,
=
|, sup |
=
||
||
x x
kwhere k I N
k
The idea of difference sequence space was introduced by Kizmaz (1981). In 1981, Kizmaz defined the sequence spaces : 1
}, ) ( : ) (
= {
= )
(
0
x x x l
l
k
k}, ) ( : ) (
= {
= )
( x x
0x c
c
k
k
and
c
0( ) = { x = ( x
k)
0: ( x
k) c
0},
where
x = ( x
k x
k1)
. These are Banach spaces with the norm.
||
||
|
=|
||
|| x
x
1 x
After then R. Colak and M. Et (1995) defined the sequence spaces :
}, ) ( : ) (
= {
= )
(
0
x x x l
l
m k
m k}, ) ( : ) (
= {
= )
( x x
0x c
c
m k
m k
and
c
0(
m) = { x = ( x
k)
0: (
mx
k) c
0},
where
m I N
,), (
0
= x
k x
), (
=
1 x x
kx
k), (
=
mx
m1x
k
m1x
k1and so that
. 1) (
=
0
=
i k i
m
i k
m i x
m
x
and show that these are Banach spaces with the norm
.
||
||
|
|
=
||
||
1
=
x x
x
i mm
i
1 AMS Subject Classification 2000: 40C05, 46A45.
107
Definition 1.1. A function
f : [0, ) [0, )
is called a modulus if 1.f (t ) = 0
if and only ift = 0,
2.
f ( t u ) f ( t ) f ( u ) for all t , u 0,
3. f is increasing, and4. f is continuous from the right of 0.
Let
X
be a sequence space. Then the sequence spaceX ( f )
is defined as}
|)) (|
( : ) (
= {
= )
( f x x
0f x X
X
k
k
for a modulus f(Maddox 1986 and Ruckle 1973).
Kolk (1993, 1994) gave an extension of
X ( f )
by considering a sequence of moduliF = ( f
k)
i.e.}.
|)) (|
( : ) (
= {
= )
( F x x
0f x X
X
k
k k
A sequence
x l
is said to be almost convergent (Lorentz, 1984) if all Banach limits ofx
coincide.Lorentz(1984) proved that
}.
1 , : lim )
(
= { ˆ :=
1
=
0
x uniformly in s x n
x
c
k sn
n k
k
Maddox (1967; 1978) has defined
x
to be strongly almost convergent toL
if0.
>
, 0,
|=
1 | lim
1
=
L some for s in uniformly L
n x
k sn
n k
Let
p = ( p
k)
be a sequence of strictly positive real numbers . Nanda (1984) defined0},
>
, 0,
=
| 1 |
: lim )
(
= { :=
] ˆ , [
1
=
0
x L uniformly in s for some L x n
x p
c
k s pkn
n k
k
}, , 0,
=
| 1 |
: lim )
(
= { :=
] ˆ , [
1
= 0
0
x uniformly in s
x n x p
c
k s pkn
n k
k
}.
, 0,
=
| 1 |
sup : ) (
= { :=
] ˆ , [
1
=
0
x L uniformly in s
x n x p
c
k s pkn
n k
k
2. MAIN RESULTS
Let
F = ( f
k)
be a sequence of moduli,u = ( u
k)
be any sequence such thatu
k= 0
for allk
and)
(
= p
kp
be any sequence space of strictly positive real numbers then we define the following sequence spaces :s in uniformly L
x u n f
x x p
F
c
k k m k s pkn
n k k
m
u
1 [ (| |)] = 0,
: lim )
(
= { :=
) ](
, ˆ , [
1
=
0
0},
>
, for some L
}, 0,
=
|)]
(|
1 [ : lim )
(
= { :=
) ( ] , ˆ , [
1
= 0
0
f u x uniformly in s
x n x p
F
c
k k m k s pkn
n k k
m
u
}, ,
<
|)]
(|
1 [ sup : ) (
= { :=
) ( ] , ˆ , [
1 , =
0
f u x uniformly in s
x n x p
F
c
k k m k s pkn
n k s k
m
u
If
f
k( x ) = x
for everyk
, then[ c ˆ , F , p ](
mu) = [ c ˆ , p ]
,[ c ˆ , F , p ]
0(
mu) = [ c ˆ , p ]
0(
mu)
and) ( ] ˆ , [
= ) ( ] , ˆ ,
[ c F p
umc p
mu .We denote[ c ˆ , F , p ](
mu)
,[ c ˆ , F , p ]
0(
mu)
and[ c ˆ , F , p ]
(
um)
by)
](
ˆ ,
[ c F
mu ,[ c ˆ , F ]
0(
mu)
and[ c ˆ , F ]
(
um)
, whenp
k= 1
for allk
.108
Theorem 2.1. For a sequence
F = ( f
k)
of moduli , the following statements are equivalent:1.
[ c ˆ , p ]
(
mu) [ c ˆ , F , p ]
(
mu),
2.[ c ˆ , p ]
0(
um) [ c ˆ , F , p ]
0(
mu),
3.
1 [ ( )] < ( > 0).
sup
1
=
t t
n f
pk k n
n k
Proof. (i)
(ii) is clear.(ii)
(iii): Let[ c ˆ , p ]
0(
um) [ c ˆ , F , p ]
0(
mu)
. Suppose that (iii) is not true. Then for somet
.
= )]
( 1 [
sup
1
=
n k pk
n k
t n f
and there exists a sequence
( n
i)
of positive integers such that(1) 1,2,
=
>
1 ) 1 (
1
=
i
for i i
n f
kni
i k
Now we define
x = { x
k}
by
. )
>
( , 0
, 1,2,
= , 1
1 ,
=
i i k
n k
i n k i if
x
Then
x [ c ˆ , p ]
0(
mu)
but by Eqn (1),x [ c ˆ , F , p ]
(
um)
which contradicts (ii).Hence (iii) is true.
(iii)
(i) :Let (iii) is true and
x [ c ˆ , p ]
(
um).
If we suppose thatx [ c ˆ , F , p ]
(
um)
. Then.(2)
=
|)]
(|
1 [ sup
1 , =
n k k m k s pkn k s
x u n f
If we take
t =| u
k
mx
ks|
for eachk
and fixeds
, then by Eqn(2),
= )]
( 1 [
sup
1
=
n k pk
n k
t n f
which contradicts (iii). Hence
[ c ˆ , p ]
(
mu) [ c ˆ , F , p ]
(
mu)
.Theorem 2.2. Let
1 sup
k<
k
k
p
p
. For a sequence of moduliF = ( f
k)
the following statements are equivalent:1.
[ c ˆ , F , p ]
0(
mu) [ c ˆ , p ]
0(
mu),
2.[ c ˆ , F , p ]
0(
um) [ c ˆ , p ]
(
mu),
3.1 [ ( )] > 0 ( > 0).
inf
1
=
t t
n f
pk k n
n
kProof. (i)
(ii) is clear.(ii)
(iii): Let[ c ˆ , F , p ]
0(
um) [ c ˆ , p ]
(
mu).
Suppose that (iii) does not hold. Then(3) 0),
>
( 0
= )]
( 1 [
inf
1
=
t t
n f
pk k n
n
kand there exists a sequence
( n
i)
of positive integers such that109
. 1,2,
= 1 ,
<
)]
( 1 [
1
=
i
i for i
n f
pk k ni
i k
Now define the sequence
x = { x
k}
by
.
>
, 0
, 1,2,
= , 1
,
=
ii
k
k n
i for n k if i x
By Eqn.(3),
x [ c ˆ , F , p ]
0(
mu)
butx [ c ˆ , p ]
(
mu),
which contradicts (ii).Hence (iii) is true.
(iii)
(i) :Let (iii) is true and
x [ c ˆ , F , p ]
0(
mu)
i.e.}.(4) 0,
=
|)]
(|
1 [ lim
1
=
s in uniformly x
u n f
pk s k m k k n
n
k
Suppose that
x [ c ˆ , p ]
0(
um)
.Then for some number
0> 0
and positive integern
0 we have|
0| u
k
mx
ks
for somes s
and1 k n
0. Thereforepk s k m k k pk
k
f u x
f ( )] [ (| |)]
[
0
and hence
lim [ (
0)] = 0
1
=
pk k n
n k
f
, which contradicts (iii). Thus[ c ˆ , F , p ]
0(
mu) [ c ˆ , p ]
0(
mu).
Theorem 2.3.
Let
1 sup
k<
k
k
p
p
. The inclusion[ c ˆ , F , p ]
(
mu) [ c ˆ , p ]
0(
um),
holds if and only if0.(5)
>
= )]
( 1 [
lim
1
=
t for t
n f
pk k n
n k
Proof. Let
[ c ˆ , F , p ]
(
mu) [ c ˆ , p ]
0(
um),
. Suppose Eqn(5) does not hold. Then there exists a numbert
0> 0
and a sequence
( n
i)
of positive integers such that.(6) 1,2,
= ,
<
)]
( 1 [
0 1
=
i
M t
n f
pk k ni
i k
Noe we define the sequence
x = ( x
k)
by
.
>
, 0
, 1,2,
= 1
,
=
0
i
i
k
k n
i for n k if t
x
Thus by Eqn (6),
x [ c ˆ , F , p ]
(
mu)
butx [ c ˆ , p ]
0(
mu)
.So that Eqn (5) must hold.Conversely let Eqn (5) hold. If
x [ c ˆ , F , p ]
(
um)
, then for eachs
andn
.(7)
<
|)]
(|
1 [
1
=
f u x M n
pk k m k k n
k
Suppose that
x [ c ˆ , p ]
0(
um)
. Then for some number
0> 0
and positive integers
0 and indexn
0 we have|
0| u
k
mx
ks
fors s
0. Therefore,
|)]
(|
[ )]
(
[ f
k
0 pk f
ku
k
mx
ks pkand hence for each
k
ands
we get110
,
<
)]
( 1 [
0 1
=
f M n
pk k n
k
for some
M > 0
, by Eqn (7) which contradicts Eqn (5). Hence) ( ] ˆ , [ ) ( ] , ˆ ,
[ c F p
um c p
0
um.
Theorem 2.4.
Let
1 sup
k<
k
k
p
p
. The inclusion[ c ˆ , p ]
(
mu) [ c ˆ , F , p ]
0(
um),
holds if and only if0.(8)
>
0
= )]
( 1 [
lim
01
=
t for t
n f
pk k n
n
kProof. Suppose that
[ c ˆ , p ]
(
um) [ c ˆ , F , p ]
0(
mu),
but (8) does not hold. Then for somet
0> 0
0.(9)
=
= )]
( 1 [
lim
01
=
f t L n
pk k n
n k
Define the sequence
x = ( x
k)
by
k k m t
x
mk k
1 1)
(
=
0
= 0
for
k = 1,2, .
Thenx c
0( F , p ,
mv)
, by Eqn (6).Hence Eqn (5) must hold.Conversely let
x [ c ˆ , p ]
(
mu)
, and suppose that Eqn (8) holds. Then for everyk
ands
.
<
|
| u
k
mx
ks M
Therefore
, )]
( [
|)]
(|
[ f
ku
k
mx
ks pk f
kM
pkand
(8).
0,
= )]
( 1 [
) lim
|)]
(|
1 [ lim
1
= 1
=
Eqn by M
n f x
u n f
pk k n
n k pk s k m k k n
n
k
Hence
x [ c ˆ , F , p ]
0(
um)
. 3. REFERENCES [1]. Çig
dem . A. B., 2006. On some difference sequence spaces defined by a sequence of orlicz functions,Journal of Zhejiang University Science A .,7(12) :2093-2096.
[2]. Colak, R., and M. Et,1995. On some generalized difference sequence spaces , Soochow J. Math., 21(4):
377-386.
[3]. Kizmaz,H., 1981. on certain sequence spaces Candian Math. Bull.,24(2): 169-176.
[4]. Kolk,E., 1993. on strong boundedness and summmability with respect to a sequence of moduli, Acta Comment.
Univ. Tartu,960 :41-50
[5]. Kolk,E., 1994. Inclusion theorems for some sequence spaces defined by a sequence of moduli, Acta Comment.
Univ. Tartu,970 :65-72
[6]. Maddox, I.J.,1978. A new type convergence, Math.Proc.Camp.Phil.Soc., 83: 61-64.
[7]. Maddox, I.J.,1986. Sequence spaces defined by a modulus, Math. Camb. Phil. Soc., 100, 161-166.
[8]. Maddox,I.J.,1967. Spaces of strongly summable sequences. Quart. J. Math., 18 : 61 - 64.
[9]. Ruckle,W.H., 1973. FK spaces in which the sequence of coordinate vectors is bounded , Canad.
J.Math.,25,973-975.
[10]. Lorentz, G.G., 1984. A contribution to the theory of divergent sequences. Acta Mathematica, 80 (1) : 167 - 190.
[11]. Nanda , S., 1984. Strongly almost convergent sequences. Bull. Cal Math.Soc., 76 : 236 - 240.