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Unit 9: Molecular Geometry

AP Chemistry, Kreipe

T1: use the VESPR theory and Lewis Dot Diagrams to explain molecular geometry. T2: predict the polarity of a molecule based on molecular geometry and

electronegativity.

T3: explain the concept of SP 1, 2, and 3 hybridization and its relationship to geometric structure.

T4: describe various bonds in terms of pi and sigma overlap including delocalization.

(2)

Bond

Hybridization

(3)

Overlap and Bonding

• We think of covalent bonds forming through the sharing of electrons by adjacent atoms.

In a quantum mechanics approach a chemical bond is

defined as when orbitals on the two atoms overlap.

(4)

Hybridization

• How/why is it possible for atoms to form more than 4 bonds with expanded valence shells of more than 8 electrons?

• Why does a carbon atom form a tetrahedral? If P

orbitals are on 90 degree axis, shouldn’t carbon form a square geometry?

(5)

Hybrid Orbitals

Consider beryllium:In its ground

electronic state, it

would not be able to

form bonds because it has no singly-occupied orbitals.

The Lewis dot-diagram should look like this:With 0 bonding pairs and 1 non-bonding pairThis means Be should NOT bond, EVER.

But what we observe in science and draw is this:With separate bonding electrons in separate

orbitals…

Be

(6)

Hybrid Orbitals

If Be absorbs the

small amount of energy needed to promote one

electron from the 2s to the 2p orbital, it can form two bonds.

It does this through

(7)

Hybrid Orbitals

•Mixing the s and p orbitals yields two orbitals that are hybrids of the two orbitals. Called an “sp” orbital.

•These sp hybrid orbitals have two lobes like a p orbital.

(8)

Hybrid Orbitals

These two “sp hybrid orbitals” would align

themselves 180 from each other, as far apart as possible.

This is consistent with the observed geometry

(9)

Hybrid Orbitals

With hybrid orbitals the orbital diagram for

beryllium would look like this.

(10)

Hybrid Orbitals

(11)

Hybrid Orbitals

Mixing 1 s orbital and 2 p orbitals makes 3 “sp2

orbitals.”

The 3 seperate Sp2 orbitals

repel into a

(12)

Hybrid Orbitals

(13)

Hybrid Orbitals

1 s orbital and 3 p

orbitals combine

to form four “sp

3

orbitals.

The four sp

3

orbitals repel to

the corners of a

tetrahedral

(14)

Hybrid Orbitals

For geometries involving expanded octets on the

central atom, we must use d orbitals in our hybrids.

• This is because we have used all of the p orbitals up!

Group 5 elements can make five sp3d orbitals by

(15)

Hybrid Orbitals

This leads to five sp3d orbitals

that push apart to form a trigonal pyramidal geometry.

• …or elements in group 6 hybridize to make six sp3d2

orbitals.

(16)
(17)

VSEPR +

Geometry

(18)

VSEPR

Valence-Shell Electron-Pair Repulsion Model:

Electron bonding and lone pairs will repel each other to be as geometrically distant as possible.

By assuming the electron pairs are placed as

(19)

Electron Domains

Electron Domain: An area of space occupied

by a lone pair or a bonding pair of electrons around a central atom.

Lone Pair Electrons: non-bonding (spare)

electrons

Bonding Pair Electrons: electron pair shared in

bond

Double/triple bonds count as ONE electron

(20)

• Lets derive some geometric arrangements… together!

(21)

5 Basic Electron

Domain Geometries

• This chart summarizes the MAXIMUM

3-D geometric separation of 2, 3, 4, 5, and 6 electron domains.

ALL molecules have one of these 5

electron domain geometries.

Some have different MOLECULAR

(22)

Molecular Geometries

Electron Domain Geometry: Geometry of ALL

electron pairs (both bonding and non-bonding) around an atom.

Molecular Geometries: The geometry of the

(23)

Linear Molecular Geometries

Linear: In this domain, there is only one

molecular geometry: linear.

(24)

Trigonal Planar Molecular

Geometries

• Trigonal Planar

There are two molecular geometries:Trigonal planar, if all the electron domains

are bonding

Bent, if one of the domains is a nonbonding

(25)

Tetrahedral Electron Domain

Tetrahedral

• There are three molecular

geometries:

• Tetrahedral, if all are bonding pairs

Trigonal pyramidal if

one is a nonbonding pair

Bent if there are two

(26)

Trigonal Bipyramidal Electron

Domain

• Unlike other electron

geometries, for Trigonal

Bipyramidal, there are two distinct positions in this

geometry:

Axial: Point straight up/down • Equatorial: form triangle

(27)

Trigonal Bipyramidal Electron

Domain

Trigonal

Bipyramidal

• There are four

(28)

Octahedral Electron Domain

All positions are

equivalent in the octahedral

domain.

There are three

molecular geometries:

Octahedral

• Square pyramidal

(29)

Now you try…

• Sketch the Lewis dot diagram, and determine the

electron geometry as well as the molecular geometry of:

MgF2 H2O NH3 SCl4 BCl3

EDG:Linear Tetrahedral Tetrahedral Octahedral Trig planar

(30)

A few tweaks to bond angles…

Nonbonding pairs are

physically larger than bonding pairs.

Therefore, their repulsions

(31)

Multiple Bonds and Bond

Angles

Double and triple bonds

place greater electron density on one side of

the central atom than do single bonds.

Therefore, they also

affect bond angles slightly by repelling adjacent electron

(32)

Multiple Geometries, One

Molecule

In larger molecules, it makes more sense to

talk about the geometry about each particular

atom rather than the geometry of the

(33)

Now you try…

• Determine the molecular geometry around all of the central atoms in the amino acid (protein building

block) Glycine. H2N-CH2-COOH

Trig Pyramidal Trig planar Tetrahedral

(34)

Molecular

Polarity

(35)

Polarity

In Unit 8 we discussed bond

dipoles.

Calculated by the difference

in electronegativity of the two bonding elements

Represent with an arrow

pointing toward the higher EN atom

(36)

Polarity

By adding the individual bond

dipoles, in a vector-like fashion, one can determine the overall dipole moment for the molecule.

Most of you should understand vectors from Physics last

year!

Molecule Dipole: If the sum of all bond

(37)
(38)

Polarity Examples

So basically, any molecule that has

asymmetrical atoms of different

electronegativity or has asymmetrical lone pairs of e- will likely be “polar.”

Molecules that are very symmetrical tend to be

non-polar.

(39)

Now you try…

Determine whether the following molecules are polar or

non-polar. If polar than draw the net polarity directional arrow.

CCl4

• 4 Bonding Pairs and 0 non-bonding pairs = Tetrahedral, all Cl dipoles cancel

Non-PolarPCl3

3 BP and 1 NBP = trigonal pyramidal, non-bonding pair is more

(-), polar

H2O

• 2 BP and 2 NBP = Bent, 2 NBP are more (-) region, polar

CO2

(40)

E- Cloud Bond

Overlaps

(41)

Overlap and Bonding

Increased overlap

brings the electrons and nuclei closer

together while simultaneously

decreasing electron-electron repulsion.

However, if atoms get too close, the

(42)

Sigma (

) Bonds

Sigma bonds are characterized by

Head-to-head overlap.

(43)

Pi (

) Bonds

Pi bonds are

characterized by

Side-to-side overlap.Electron density

(44)

Single Bonds

Single bonds are always  bonds, because  overlap is greater, resulting in a stronger

(45)

Multiple Bonds

(46)

Multiple Bonds

In a double bond

containing molecule

like formaldehyde

(shown at left) an sp2

orbital on carbon

overlaps in  fashion

with the

corresponding orbital on the oxygen.

The unhybridized p

(47)

Multiple Bonds

In triple bonds, as in acetylene, two sp

orbitals form a 

bond between the carbons, and two pairs of p orbitals

overlap in  fashion to form the two 

(48)

Delocalized Electrons: Resonance

When writing Lewis structures for species like
(49)

Delocalized Electrons: Resonance

In reality, each of the four atoms in the nitrate ion has a p orbital.

The p orbitals on all three

oxygens overlap with the p

orbital on the central nitrogen.

The pi bonding electrons in

the p orbitals are

(50)

Molecular

Orbitals

(51)

Molecular Orbital (MO)

Theory

Though valence bond theory effectively

conveys most

observed properties of ions and molecules,

there are some concepts better represented by

(52)

Molecular Orbital (MO)

Theory

In MO theory, we invoke the wave nature

of electrons.

If waves interact constructively, the

(53)

Molecular Orbital (MO)

Theory

If waves interact destructively, the
(54)

MO Theory

In H

2 the two electrons go into the bonding

molecular orbital.

The bond order is one

half the difference

between the number of bonding and anti-bonding electrons.

Bond order =

(55)

MO Theory

For hydrogen, with

two electrons in

the bonding MO

and none in the

antibonding MO,

the bond order is

1
(56)

MO Theory

In the case of He2, the

bond order would be

1

2 (2 - 2) = 0

Therefore, the bonding and

(57)

MO Theory

For atoms with both s

and p orbitals, there are two types of

interactions:

The s and the p

orbitals that face

each other overlap in

 fashion.

(58)

MO Theory

The resulting MO

diagram looks like this.

There are both and

 bonding molecular orbitals and * and

* anti-bonding

(59)

MO Theory

The smaller p-block

elements in the second period have a sizeable

interaction between the s

and p orbitals.

This flips the order of the s

(60)

References

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