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(1)

What's going on during phase transition?

(2)

Latent Heat (enthalpy)

12

2

1

2

1

During Phase change, lets say from solid to liquid phase

at constant T and P, l

    

q

u w

u

 

u

P v

(

v

)

12

2

2

1

1

12

2

1

(

) (

)

Where h ca

l

u

pv

u

pv

l

h

h

lled the enthalp

y

23

3

2

,

From liquid to gas l

h

h

13

3

1

From solid to gas l

 

h

h

13

12

23

(3)

dq

du

pdv

First law

At constant volume v:

dq

v

du

v

0

v

v

v

v

v

u

c dT

du

c

T

 

At constant volume :

P

dq

p

du

p

pdV

p

dh

h

(4)

Enthalpy (history of the name)

Over the

history of thermodynamics

, several terms have been used to

denote what is now known as the

enthalpy

of a system.

Originally, it was thought that the word "enthalpy" was created by

Benoit Paul Émile Clapeyron

and

Rudolf Clausius

through the publishing

of the

Clausius-Clapeyron relation

in

The Mollier Steam Tables and

Diagrams

in 1827.

Gibbs

introduced a "heat function for constant pressure" in 1875,

although the word

enthalpy

does not appear in any of Gibbs' work.

In 1909,

Keith Landler

discussed Gibbs's work on this "heat

function" and noted that

Heike Kamerlingh Onnes

had coined the

modern name from the

Greek

word "enthalpos" (ενθαλπος) meaning

"to put heat into.

(5)

Difference between

H

and

U

: the additional term

pV

If

pV

is an additional

energy

associated with the system (say, a gas),

and is not in the

internal energy

U

, then where is it?

The energy

pV

is in the surroundings (typically, the atmosphere).

When a system (e.g.,

n

moles

of a gas of

volume

V

at

pressure

P

and

temperature

T

) is

created

(brought to its present state from

absolute

zero

), energy must be supplied equal to its internal energy

U plus pV

,

where

pV

is the

work

done in pushing against the (atmospheric)

pressure.

This additional energy is therefore stored in the surroundings

(6)

In

thermodynamics

and

molecular chemistry

,

enthalpy

(denoted as

H

, or specific enthalpy denoted as

h

) is a

thermodynamic property

of a

thermodynamic system

.

It can be used to calculate the

heat transfer

during a

quasistatic process

taking place in a

closed

thermodynamic system

under constant

pressure

.

Change in enthalpy Δ

H

is frequently a more useful

value than

H

itself.

For quasistatic processes under constant pressure,

Δ

H

is equal to the change in the internal energy of the

system, plus the work that the system has done on its

surroundings.

Enthalpy

H

U W

(7)

Enthalpy Change

The heat content of a chemical system is called the

enthalpy

(symbol: H) .

The enthalpy change ( H) is the amount of heat released or

absorbed when a chemical reaction occurs at constant

pressure. H is total enthalpy, h is enthalpy per mole

h is specified per mole of substance as in the balanced

chemical equation for the reaction.

The units are usually given as kJ mol

-1

(kJ/mol) or sometimes

2

1

product

reactant

phase

phase

H

H

H

for chemical reaction

H

H

H

for phase change

 

(8)

Latent Heat (enthalpy)

Latent Heat (enthalpy) is the "hidden" heat when a

substance absorbs or releases heat without producing a

change in the temperature of the substance, eg, during a

change of state.

Latent Heat (enthalpy) of Fusion is the heat absorbed

per mole when a substance changes state from solid to

liquid at constant temperature (melting point).

l

12

Latent Heat (enthalpy) of Vaporization is the heat

absorbed per mole when a substance changes state from

liquid to gas at constant temperature (boiling point).

l

23

Latent Heat (enthalpy) of Sublimation is the heat

absorbed per mole when a substance changes state from

solid to gas, without going through the liquid phase, at

constant temperature.

l

13

13

12

23

(9)

Generalized First Law of Thermodynamics

(10)

Taking heat transfer to the system and work done by the

system to be positive quantities, the energy balance for a

closed system can also be expressed as:

3-29

Q W

    

U

KE

 

PE

,

Configuration

Other

W

W

W

 

U

m u

(

2

u

1

)

2

2

1

2

1

2

1

2

(

),

(

)

KE

m v

v

PE

mg z

z

Other

Config

Q W

W

   

U

KE

 

PE

Other

(11)

Liquid Flow

(12)

Liquid Flow (steady state)

z

2

-z

1

2

1

2

2

1

2

1

2

1

2

(

)

(

)

(

)

other

Q W

m h

h

m

 

mg z

z

(13)

Liquid Flow (steady state)

2

2

1

2

1

2

2

1

2

1

(

)

(

)

(

)

Heater

Q W

m h

h

m

 

mg z

z

??

Why

It is energy added to the SY STEM

WORK IS DONE ON THE SY STEM

If the fluid is moving a shaft then

the left hand side becomes:

heater

shaft

(14)

Liquid Flow (steady state, adiabatic

and frictionless)

(15)
(16)

Liquid Flow (steady state, adiabatic

and frictionless)

2

2

1

2

1

2

2

1

2

1

2

2

1

1

2

2

2

2

1

2

1

1

0

(

)

(

)

(

)

constant

m h

h

m

mg z

z

h

gz

h

gz

 

 

2

1

2

2

1

2

constant

constant

h

gz

u

Pv

gz

For incompressible fluid and

W=Q=0 then

 

u

0

2

1.

2

constant

P



gz

(17)

Example 1a:

A cylinder provided with a movable piston ( as shown ),

contains an ideal gas at T

0

, V

0

and P

0

. The cylinder wall is

made of good diathermal material. If the piston is moved

slowly until the gas final pressure is xP

0

.

(18)

Solution 1-a

1- Final Temperature is T

0

(diathermal walls).

0

0

0

0

2

P V

f

f

PV

xPV

f

V

f

V

/

x

3

  

U

f nR T

/ 2

0

4

Q

  

U W

 

Q W

0 0

0 0 0 0

5

ln

ln

f f

V V

V V

dV

W

PdV

nRT

nRT

x

PV

x

V

 

 

0

0

(19)

Example 1-b

The same as problem 1-a but the external pressure on the

piston increased or decreased suddenly up to xP

0

.

1- Final Temperature is T

0

(diathermal walls).

0

0

0

0

2

P V

f

f

PV

xPV

f

V

f

V

/

x

3

  

U

f nR T

/ 2

0

4

Q

  

U

W

by

Q

W

by

 

W

on

0

0

(20)

Example 1-c

The same as problem 1-a but the walls are adiabatic the gas

has constant

the external pressure on the piston increased

or decreased slowly up to xP

0

.

1- Final Temperature

T

0

(adiabatic walls).

1

0

0

0

0

2

P V

f

f

PV

xPV

f

V

f

x V

0

0

0

1

1

1

0

0

0

0

0

3

f

f

f

f

f

f

f

PV

P V

nRT

T

T

P V

T

T

x

T

x

T

PV

(21)

Example 1-

c Cont……

4

Q

U

W

,

Q

0

Adiabatic process

U

W

  

  

1

0

0

1

0

0

5

(

)

(

1)

1

1

(

1)

1

f

nRT

nR

W

T

T

x

(22)

Example 1-d

The same as problem 1-c the walls are adiabatic the gas has

constant

the external pressure on the piston increased or

decreased suddenly up to xP

0

.

1

,

0

by

on

Q

U W

Q

adiabatic process

U

W

W

  

  

0

0

0

0

0

2

W

on

xP V

(

V

f

)

xPV

P V

f

f

nR xT

(

T

f

)

0

0

2

1

3

  

U

f

nR T

(

f

T

)

nR

(

T

f

T

)

W

on

0

0

1

4

nR

(

T

f

T

)

nR xT

(

T

f

)

0

1

5

T

f

x

x

T

 

(23)

Example 1-

d Cont…….

0 0 0

0

0

1

(

1)

6

W

by

   

U

nR

(

T

f

T

)

 

T

P V

(

T

f

T

)

0 0

0

0

0

1

(

1)

by

PV

x

x

W

U

T

T

T



 

   



0 0

(

1)(

1)

(

1)

by

PV

x

W

U



   



(24)

Example 2-a

A cylinder provided with a movable

piston ( as shown ), contains an ideal

gas at T

0

, V

0

and P

0

. The cylinder wall

is made of good diathermal material. If

the piston is moved slowly until the gas

final pressure is xP

0

.Note that the

cylinder is

vertical

and we must take

into account the changes in the

gravitational potential energy

of

the system.

(25)

Example 2-

a Cont…….

1- Final Temperature is T

0

(diathermal walls).

0

0

0

0

2

P V

f

f

PV

xPV

f

V

f

V

/

x

2

1

4

0

gas

(

) 0

Q

U W

PE

KE

Q

W

m

g z

z

  

 

 

 

0 0

0 0 0 0

3

ln

ln

f f

V V

V V

dV

W

PdV

nRT

nRT

x

PV

x

V

 

 

0

1

(26)

The same as example 2-a but the pressure on the piston

increased suddenly to xP

0

.

Example 2-b

1- Final Temperature is T

0

(diathermal walls).

0

0

0

0

2

P V

f

f

PV

xPV

f

V

f

V

/

x

0

0

0

0

3

W

by

 

W

on

xP V

(

f

V

)

 

PV x

(

1)

2

1

4

0

gas

(

) 0

Q

U W

PE

KE

Q

W

m

g z

z

  

 

 

 

0

0 0 0 0 0

1

5

Q

PV x

(

1)

m

gas

g

V

f

V

PV x

(

1)

m

gas

gV

x

A

Ax

 

 

 

 

(27)

Example 2-c

The same as example 2-a but the cylinder wall is adiabatic

and the pressure on the piston increased slowly to xP

0

.

1

(

)

(

)

0

1

gas

d Q

dU

dW

d PE

d KE

m

g

nR

dT

PdV

dV

A

2

nRT

PV

nRdT

PdV

VdP

3

0

1

gas

m

g

PdV

V dP

PdV

dV

A

(28)

Example 2-

c Cont………

4

0

(

1)

gas

dP

dV

m

g

V

P

A

0

0

5

P

f

(

1)

mg A V

/

f

P

(

1)

mg A V

/

1

0

0

0

(

1)

/

6

(

1)

/

f

P

mg A

V

V

xP

mg A

 

1

0

0

0

0

0

0

(

1)

/

7

(

1)

/

f

f

f

P

mg A

P V

T

T

x

T

PV

xP

mg A

(29)

Example 2-

c Cont………

8

(

)

(

)

0

1

gas

d Q

dU

dW

d PE

d KE

m

g

nR

dT

dW

dV

A

0

0

9

1

(

)

(

)

1

gas

gas

f

f

f

f

m

g

nR

dW

dT

dV

A

m

g

nR

W

T

T

V

V

A

(30)

Example 2-d

The same as example 2-a but the

cylinder wall is adiabatic

and the pressure on the piston increased

suddenly

to xP

0

.

0

0

1

(

)

(

)

0

(

)

(

)

1

gas

on

f

f

Q

U

W

PE

KE

m

g

nR

T

T

W

V

V

A

    

 

 

0

0

2

W

on

xP V

(

V

f

)

0

0

0

0

0

0

0

3

0

(

)

(

)

(

)

1

0

(

)

(

)

1

gas

f

f

f

gas

f

f

m

g

nR

T

T

xP V

V

V

V

A

m

g

nR

T

T

xP

V

V

(31)

Example 2-

d Cont……

0

0

0

4

0

(

)

(

)

1

gas

f

f

m

g

nR

T

T

xP

V

V

A

0

0

0

0

0

0

0

0

5

f

f

f

f

f

f

1

f

PV

P V

T

T

V

V

V

V

V

T

T

xT

xT

0

0

0

0

0

0

6

0

(

)

1

1

gas

f

f

gas

f

f

m

g

T

nR

T

T

xP

V

A

xT

m

g

PV

T

T

(32)

Example 2-

d Cont……

0

0

0

[

1]

(

1)

(

1)

gas

f

gas

xP A x

x

m

g

T

T

xP A

m

g

  

0

0

0

0

0

0

7

0

1

1

(

1)

gas

f

m

g

f

PV

T

T

xP

V

T

A

xT

 

0 0

0 0 0 0

0 0 0 0

0

(

1)

(

1)

gas gas

f

PV

m

gV

PV

m

gV

T

PV

xPV

T

xA

A

0

0

0

1

(

1)

(

1)

(

1)

gas

gas

f

m

g

m

g

T

x

T

xP A

xP A

(33)

Example 2-

d Cont……

0

0

f

f

T

V

V

xT

0

(

0

)

on

f

W

xP V

V

0

0

0

[

1]

(

1)

(

1)

gas

f

gas

xP A x

x

m

g

V

V

x

xP A

m

g

  

history of thermodynamics Benoit Paul Émile Clapeyron Rudolf Clausius Clausius-Clapeyron relation Gibbs 9, Keith Landler t Heike Kamerlingh Onnes Greek an additional energy t in the internal energy moles volume t pressure temperature om absolute he work thermodynamics molecular chemistry thermodynamic property thermodynamic system the heat transfer quasistatic process a closed

References

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