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R E S E A R C H

Open Access

Hybrid simultaneous algorithms for the

split equality problem with applications

Chih-Sheng Chuang

1

and Wei-Shih Du

2*

*Correspondence:

[email protected]

2Department of Mathematics,

National Kaohsiung Normal University, Kaohsiung, 82444, Taiwan

Full list of author information is available at the end of the article

Abstract

The split equality problem has board applications in many areas of applied mathematics. Many researchers studied this problem and proposed various

algorithms to solve it. From the literature we know that most algorithms for the split equality problems came from the idea of the projected Landweber algorithm proposed by Byrne and Moudafi (Working paper UAG, 2013), and few algorithms came from the idea of the alternating CQ-algorithm given by Moudafi (Nonlinear Anal. 79:117-121, 2013). Hence, it is important and necessary to give new algorithms from the idea of the alternating CQ-algorithm. In this paper, we first present a hybrid projected Landweber algorithm to study the split equality problem. Next, we propose a hybrid alternating CQ-algorithm to study the split equality problem. As applications, we consider the split feasibility problem and linear inverse problem. Finally, we give numerical results for the split feasibility problem to demonstrate the efficiency of the proposed algorithms.

MSC: 49J53; 49M37; 90C25

Keywords: split equality problem; split feasibility problem; split equality problem; linear inverse problem; simultaneous algorithm

1 Introduction

LetHbe a real Hilbert space with inner product·,·and norm · . We denote the strong convergence and weak convergence of{xn}n∈NtoxHbyxnxandxnx, respectively.

The symbolsNandRare used to denote the sets of positive integers and real numbers, respectively. For eachxH, there is a unique elementx¯∈Csuch thatxx¯=miny∈Cx

y. In this study, we setPCx=x¯, andPCis called the metric projection fromHontoC. LetH andHbe two real Hilbert spaces. LetA:H→H andA∗:H→H be two

linear and bounded operators. ThenA∗is called the adjoint ofAifAz,w=z,Awfor all

zHandwH. It is known that the adjoint operator of a linear and bounded operator

on a Hilbert space always exists and is linear, bounded, and unique. Further, we know that A=A∗.

LetH,H, andHbe real Hilbert spaces. LetCandQbe nonempty closed convex

sub-sets ofH andH, respectively. LetA:H→HandB:H→Hbe linear and bounded

operators with adjoint operatorsA∗ andB∗, respectively. The following problem is the split equality problem, which was studied by Moudafi [, ]:

(SEP) Findx¯∈Candy¯∈Qsuch thatAx¯=By¯.

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Let:={(x,y)∈C×Q:Ax=By}be the solution set of problem (SEP). Further, we ob-served that (x,y) is a solution of the split equality problem if and only if

x=PC(xρA∗(AxBy)),

y=PQ(y+ρB∗(AxBy)),

for allρ>  andρ>  (for details, see []).

As mentioned by Moudafi [], the interest of the split equality problem covers many situations, for instance, in decomposition methods for PDEs, game theory, and intensity modulated radiation therapy (IMRT). For details, see [, , ]. To solve problem (SEP), Moudafi [] proposed the alternating CQ-algorithm:

(ACQA)

xn+:=PC(xnρnA∗(AxnByn)),

yn+:=PQ(yn+ρnB∗(Axn+–Byn)), n∈N,

whereH=RN,H=RM,PCis the metric projection mapping fromHontoC, andPQis

the metric projection mapping fromHontoQ,ε> ,Ais aJ×Nmatrix,Bis aJ×M

matrix,λAandλBare the spectral radii ofAAandBB, respectively, and{ρn}is a sequence

in (ε,min{λ

A,

λB}–ε).

In , Byrne and Moudafi [] presented a simultaneous algorithm, which was called the projected Landweber algorithm, to study the split equality problem

(PLA)

xn+:=PC(xnρnA∗(AxnByn)),

yn+:=PQ(yn+ρnB∗(AxnByn)), n∈N,

whereH=RN,H=RM,PCis the metric projection mapping fromHontoC, andPQis

the metric projection mapping fromHontoQ,ε> ,Ais aJ×Nmatrix,Bis aJ×M

matrix,λAandλBare the spectral radii ofAAandBB, respectively, and{ρn}is a sequence

in (ε,λ

A+λB).

Besides, we also observed that Chenet al.[] gave the following modification of (ACQA) by using the Tikhonov regularization method and proved a convergence theorem under suitable conditions:

(TRA)

xn+:=PC(( –εnρn)xnρnA∗(AxnByn)),

yn+:=PQ(( –εnρn)yn+ρnB∗(Axn+–Byn)), n∈N,

where{εn}n∈Nis a sequence in (,∞). Besides, many researchers studied problem (SEP)

and gave various algorithms. For more details about the algorithms for the split equality problem, we refer to [, ] and related references.

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numer-ical results for the split feasibility problem to demonstrate the efficiency of the proposed algorithms.

2 Main results

In the sequel, we need the following lemma, which is a crucial tool for our results.

Lemma .[] Let C be a nonempty closed convex subset of a real Hilbert space H,and let PCbe the metric projection from H onto C.Then:

(i) xPCx,PCxy ≥for allxHandyC;

(ii) xPCx+PCxy≤ xyfor allxHandyC;

(iii) PCxPCy≤ xy,PCxPCyfor allx,yH.

2.1 Hybrid projected Landweber algorithm

LetH,H, andH be real Hilbert spaces with inner product·,·Hi and norm · Hi, i= , , . For simplicity, we write·,·and · . LetCandQbe nonempty closed con-vex subsets ofH andH, respectively. LetA:H→H andB:H→H be linear and

bounded operators with adjoint operatorsA∗ andB∗, respectively. Chooseδ∈(, ). Let be the solution set of the split equality problem and suppose that=∅. Let{ρn}n∈Nbe

a sequence in (,∞).

Now we present a hybrid projected Landweber algorithm to study the split equality problem.

Algorithm . For givenxnH andynH, find the approximate solution by the

fol-lowing iterative process.

Step . Compute the next iterate(un,vn)as follows:

un=PC[xnρnA∗(AxnByn)], vn=PQ[yn+ρnB∗(AxnByn)],

whereρn> satisfies

ρnA∗(AxnByn) –A∗(AunBvn)

+B∗(AxnByn) –B∗(AunBvn)

δxnun+δynvn,  <δ< . (.)

Step . Ifxn=unandyn=vn, then(xn,yn)is a solution of problem (SEP) and stop. Other-wise, go to Step .

Step . Compute the next iterate(xn+,yn+)as follows:

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

D(n,):=xnun+ρn[A∗(AunBvn) –A∗(AxnByn)], D(n,):=ynvnρn[B∗(AunBvn) –B∗(AxnByn)], αn:=xn

un,D(n,)+ynvn,D(n,) D(n,)+D(n,) , xn+=PC[xnαnD(n,)],

yn+=PQ[ynαnD(n,)].

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Remark . If  <ρn≤ √

δ

(A+B), then (.) holds.

Proof Without loss of generality, we may assume that xn=un andyn=vn. We know

that

ρn·A∗(AxnByn) –A∗(AunBvn)+B∗(AxnByn) –B∗(AunBvn)

ρn·A∗+B∗·(AxnByn) – (AunBvn)

ρn·A∗+B∗·A · xnun+B · ynvn

≤ρn·A+B·A· xnun+B· ynvn

≤ρn·A+B·xnun+ynvn

≤· δ

(A+B) ·

A+B·xnun+ynvn

=δ·xnun+ynvn.

Therefore, the proof is completed.

Theorem . Let{ρn}n∈Nbe a sequence in(, /(A+B))such that(.)holds and

assume thatlim infn→∞ρn( –ρn(A+B)) > .Then,for the sequence{(xn,yn)}n∈Nin Algorithm.,there exists(x¯,y¯)∈such that xnx and yn¯ y as n¯ → ∞.

Proof Take anyn∈Nand letnbe fixed. Take any (u¯,v¯)∈and let (u¯,v¯) be fixed. Then ¯

uC,v¯∈Q, andAu¯=Bv¯. First, we set

εn,:=ρn[A∗(AunBvn) –A∗(AxnByn)],

εn,:=ρn[B∗(AxnByn) –B∗(AunBvn)].

Then

xnun,D(n,)+ynvn,D(n,)

=xnun,xnun+εn,+ynvn,ynvn+εn,

=xnun+xnun,εn,+ynvn+ynvn,εn,

=

xnun

+xnun,ε

n,+

xnun

+

ynvn

+ynvn,ε

n,+

ynvn

≥

xnun

+xnun,ε

n,+

 εn,

+

ynvn

+y

nvn,εn,+

 εn,

=

xnun+εn,

+

ynvn+εn,

= D(n,)

+

D(n,)

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By (.) we know that

αn:=

xnun,D(n,)+ynvn,D(n,) D(n,)+D(n,) ≥

. (.)

Next, by Lemma . we know that

xnαnD(n,)–xn++xn+–u¯≤ xnαnD(n,)–u¯ (.)

and

ynαnD(n,)–yn++yn+–v¯≤ ynαnD(n,)–¯v. (.)

Hence, by (.),

xnu¯–xn+–u¯

xnu¯–xnαnD(n,)–u¯+xn+–xn+αnD(n,) ≥ xnu¯–xnαnD(n,)–u¯

=xnu¯–xnu¯–αnD(n,)+ αnxnu¯,D(n,)

= αnxnu¯,D(n,)–αnD(n,). (.)

Similarly, we have

ynv¯–yn+–v¯≥αnynv¯,D(n,)–αnD(n,). (.)

By (.) and (.) we get

xn+–u¯+yn+–v¯

xnu¯+ynv¯– αnxnu¯,D(n,)– αnyn–¯v,D(n,)

+αnD(n,)+D(n,)

. (.)

Next, we know that

unu¯,D(n,)+vnv¯,D(n,)

=unu¯,xnun+ρn

A∗(AunBvn) –A∗(AxnByn)

+vnv¯,ynvnρn

B∗(AunBvn) –B∗(AxnByn)

=unu¯,xnunρnA∗(AxnByn)+unu¯,ρnA∗(AunBvn)

+vnv¯,ynvn+ρnB∗(AxnByn)–vnv¯,ρnB∗(AunBvn). (.)

By Lemma .,

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and

vn–¯v,yn+ρnB∗(AxnByn) –vn≥. (.)

Besides, we also have

unu¯,A∗(AunBvn)–vn–¯v,B∗(AunBvn)

=AunAu¯,AunBvnBvnBv¯,AunBvn

=AunBvnAu¯+Bv¯,AunBvn

=AunBvn,AunBvn

=AunBvn≥. (.)

So, by (.), (.), (.), and (.) we determine that

unu¯,D(n,)+vnv¯,D(n,) ≥, (.)

which implies that

xnu¯,D(n,)+ynv¯,D(n,) ≥ xnun,D(n,)+ynvn,D(n,). (.)

By (.), (.), and (.),

xn+–u¯+yn+–v¯

xnu¯+ynv¯– αnxnu¯,D(n,)– αnyn–¯v,D(n,)

+αnD(n,)+D(n,)

xnu¯+ynv¯– αn

xnun,D(n,)+ynvn,D(n,)

+αnD(n,)+D(n,)

=xnu¯+ynv¯–αn

xnun,D(n,)+ynvn,D(n,)

xnu¯+ynv¯. (.)

So,{xnu¯+ynv¯}is a decreasing sequence, andlimn→∞xnu¯+ynv¯exists.

Further,{xn}n∈Nand{yn}n∈Nare bounded sequences, and

lim

n→∞xnun,D(n,)+ynvn,D(n,)= . (.)

Besides, we know that

xnun,D(n,)+ynvn,D(n,)

=xnun,xnun+εn,+ynvn,ynvn+εn,

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which implies that

xnun+ynvn

=xnun,D(n,)+ynvn,D(n,)–xnun,εn,–ynvn,εn,

xnun,D(n,)+ynvn,D(n,)+xnun · εn,+ynvn · εn,

xnun,D(n,)+ynvn,D(n,)+

 

xnun+εn,+ynvn+εn,

xnun,D(n,)+ynvn,D(n,)+

 +δ  ·

xnun+ynvn. (.)

Hence, by (.) we derive that

( –δ)xnun+ynvn≤xnun,D(n,)+ ynvn,D(n,). (.)

By (.) and (.) we know that

lim

n→∞xnun=n→∞lim ynvn= . (.)

By Lemma . again,

unu¯ =PC

xnρnA∗(AxnByn)

PC[u¯]

xnρnA∗(AxnByn) –u¯

xnu¯+ρnA· AxnByn– ρnAxnByn,AxnAu¯. (.)

Similarly,

vnv¯≤ ynv¯+ρnB· AxnByn+ ρnAxnByn,BynBv¯. (.)

By (.) and (.),

unu¯+vnv¯

xnu¯+ynv¯+ρnA+B· AxnByn

– ρnAxnByn,AxnAu¯+ ρnAxnByn,BynB¯v

=xnu¯+ynv¯–ρn

 –ρn

A+B· AxnByn. (.)

We also have

unu¯+vnv¯=unxn+ unxn,xnu¯+xnu¯

+vnyn+ vnyn,yn–¯v+yn–¯v. (.)

By (.), (.), and (.) we get

lim

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Since{xn}n∈Nand{yn}n∈Nare bounded sequences, there exist subsequences{xnk}k∈Nand

{ynk}k∈Nof{xn}n∈Nand{yn}n∈N, respectively, such thatxnkx¯andynky¯for somex¯∈H

andy¯∈H. Since{xn}∞n=is a sequence inC, we know thatx¯∈C. Also,y¯∈Q. Sincexnkx¯

andynky¯, it is easy to see thatAxnk Ax¯andBynk By¯by using the properties ofA

andB. Further,AxnkBynkAx¯–B¯y, and the lower semicontinuity of the squared norm implies

Ax¯–By¯≤lim inf

k→∞ AxnkBynk

= lim

n→∞AxnByn

= . (.)

ThenAx¯=By¯and (x¯,y¯)∈.

Next, let{xnk}and{ynk}be other subsequences of{xn}n∈Nand{yn}n∈Nsuch thatxnkxˆ

andynk yˆ, respectively. Following the same argument as before, we get that (xˆ,ˆy)∈. Besides, we have

xnx¯+yny¯

=xnxˆ+ˆxx¯+ xnxˆ,xˆ–x¯

+yn–ˆy+ˆyy¯+ yn–ˆy,yˆ–y¯ (.)

and

xnxˆ+ynyˆ

=xnx¯+ˆxx¯+ xnx¯,x¯–xˆ

+yn–¯y+ˆyy¯+ yn–¯y,y¯–yˆ. (.)

Clearly,limn→∞xnx¯+yny¯exists, andlim

n→∞xnxˆ+ynyˆexists. Hence,

by (.) we get

lim

n→∞

xnx¯+yny¯

= lim

k→∞x nkx¯

+ynky¯

= lim

k→∞x nkxˆ

+ynkyˆ+ˆxx¯+ˆyy¯

+ lim

k→∞

xnkxˆ,xˆ–x¯+  lim

k→∞

ynkyˆ,yˆ–y¯

= lim

k→∞x nkxˆ

+ynkyˆ+ˆxx¯+ˆyy¯

= lim

n→∞

xnxˆ+yn–ˆy

xx¯+ˆy¯y. (.)

Similarly, by (.) we have

lim

n→∞

xnxˆ+yn–ˆy

= lim

n→∞

xnx¯+yny¯

xx¯+ˆyy¯. (.)

By (.) and (.) we know thatx¯=xˆandy¯=yˆ. Therefore,xnx¯andyny¯, and the

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Remark . In Theorem ., if we choose{ρn}n∈N from (,√(Aδ+B)], then we only

need to assume thatlim infn→∞ρn> . Proof Sinceρn∈(,√(Aδ+B)], we have

ρn

A+B≤√·ρn·

A+B≤δ, ∀n∈N, (.)

which implies that

 –ρn

A+B≥ –δ> , ∀n∈N. (.)

Sincelim infn→∞ρn> , we may assume that there isκsuch thatρnκ>  for alln∈N.

Hence, we determine

ρn

 –ρn

A+B≥κ·( –δ) >κ, ∀n∈N. (.)

By (.) we get the conclusion of Remark ..

2.2 Hybrid alternating CQ-algorithm

In this subsection, we present a hybrid alternating CQ-algorithm to study the split equality problem.

Algorithm . For givenxnHandynH, find the approximate solution by the

fol-lowing iterative process.

Step . Compute the next iterate(un,vn)as follows:

un=PC[xnρnA∗(AxnByn)],

vn=PQ[yn+ρnB∗(AunByn)],

whereρn> satisfies

ρnA∗(AxnByn) –A∗(AunBvn)+B∗(AunByn) –B∗(AunBvn) ≤δxnun+δynvn,  <δ< . (.)

Step . Ifxn=unandyn=vn, then(xn,yn)is a solution of problem (SEP) and stop.

Other-wise, go to Step .

Step . Compute the next iterate(xn+,yn+)as follows:

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

D(n,):=xnun+ρn[A∗(AunBvn) –A∗(AxnByn)], D(n,):=ynvnρn[B∗(AunBvn) –B∗(AunByn)], αn:=

xnun,D(n,)+ynvn,D(n,) D(n,)+D(n,) , xn+=PC[xnαnD(n,)],

yn+=PQ[ynαnD(n,)].

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Remark . If  <ρn

δ

max{√·A,·A·|B+B}, then (.) holds.

Proof Without loss of generality, we may assume thatxn=unandyn=vn. We have

ρn·A∗(AxnByn) –A∗(AunBvn)

+B∗(AunByn) –B∗(AunBvn)

ρn·A∗·(AxnByn) – (AunBvn)

+B· ynvn

ρn·A∗·AxnAun+BynBvn+B· ynvn

ρn·A∗·AxnAun+ BynBvn+B· ynvn

ρn·A∗· xnun+A· B+B· ynvn

δxnun+δynvn.

Therefore, the proof is completed.

Theorem . Let{ρn}n∈Nbe a sequence in(, /max{A,B})such that(.)holds and assume thatlim infn→∞ρn( –ρnA) > orlim infn→∞ρn( –ρnB) > .Then,for the sequence{(xn,yn)}n∈N in Algorithm.,there exists(x¯,y¯)∈such that xnx and¯ yn¯y as n→ ∞.

Proof Take anyn∈Nand letnbe fixed. Take any (u¯,v¯)∈and let (u¯,v¯) be fixed. Then ¯

uC,v¯∈Q, andAu¯=Bv¯. First, we set

εn,:=ρn[A∗(AunBvn) –A∗(AxnByn)], εn,:=ρn[B∗(AunByn) –B∗(AunBvn)].

Then

xnun,D(n,)+ynvn,D(n,) ≥

 D(n,)

+

D(n,)

. (.)

By (.) we have that

αn:=

xnun,D(n,)+ynvn,D(n,) D(n,)+D(n,) ≥

. (.)

Next, by Lemma . we have

xnαnD(n,)–xn++xn+–u¯≤ xnαnD(n,)–u¯ (.)

and

ynαnD(n,)–yn++yn+–v¯≤ ynαnD(n,)–¯v. (.)

Hence, by (.),

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Also, by (.),

ynv¯–yn+–v¯≥αnynv¯,D(n,)–αnD(n,). (.)

By (.) and (.) we get

xn+–u¯+yn+–v¯

xnu¯+ynv¯– αnxnu¯,D(n,)– αnyn–¯v,D(n,)

+αnD(n,)+D(n,)

. (.)

Next, we have

unu¯,D(n,)+vnv¯,D(n,)

=unu¯,xnun+ρn

A∗(AunBvn) –A∗(AxnByn)

+vnv¯,ynvnρn

B∗(AunBvn) –B∗(AunByn)

=unu¯,xnunρnA∗(AxnByn)+unu¯,ρnA∗(AunBvn)

+vnv¯,ynvn+ρnB∗(AunByn)–vnv¯,ρnB∗(AunBvn). (.)

By Lemma .,

unu¯,xnρnA∗(AxnByn) –un≥ (.)

and

vn–¯v,yn+ρnB∗(AunByn) –vn≥. (.)

Besides, we also have

unu¯,A∗(AunBvn)–vn–¯v,B∗(AunBvn)=AunBvn≥. (.)

So, by (.), (.), (.), and (.) we determine that

unu¯,D(n,)+vnv¯,D(n,) ≥, (.)

which implies that

xnu¯,D(n,)+ynv¯,D(n,) ≥ xnun,D(n,)+ynvn,D(n,). (.)

By (.), (.), and (.),

xn+–u¯+yn+–v¯

xnu¯+ynv¯– αnxnu¯,D(n,)– αnyn–¯v,D(n,)

+αnD(n,)+D(n,)

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xnu¯+ynv¯– αn

xnun,D(n,)+ynvn,D(n,)

+αnD(n,)+D(n,)

=xnu¯+ynv¯–αn

xnun,D(n,)+ynvn,D(n,)

xnu¯+ynv¯. (.)

So,{xnu¯+yn¯v}is a decreasing sequence,lim

n→∞xnu¯+ynv¯exists,

{xn}n∈Nand{yn}n∈Nare bounded sequences, and

lim

n→∞xnun,D(n,)+ynvn,D(n,)= . (.)

Besides, we have

xnun,D(n,)+ynvn,D(n,)

=xnun+xnun,εn,+ynvn+ynvn,εn,, (.)

which implies that

xnun+ynvn

xnun,D(n,)+ynvn,D(n,)+

 +δ  ·

xnun+ynvn. (.)

Hence, by (.) we derive that

( –δ)xnun+ynvn≤xnun,D(n,)+ ynvn,D(n,). (.)

By (.) and (.) we get that

lim

n→∞xnun=n→∞lim ynvn= . (.)

By Lemma . again,

unu¯ =PCxnρnA∗(AxnByn)–PC[u¯] ≤xnρnA∗(AxnByn) –u¯

xnu¯+ρnA· AxnByn

– ρnAxnByn,AxnAu¯

=xnu¯–ρn·

 –ρnA

· AxnByn

– ρnAxnByn,BynAu¯. (.)

Similarly,

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ynv¯+ρnB· AunByn

+ ρnAunByn,BynBv¯

=ynv¯–ρn

 –ρnB

· AunByn

+ ρnAunByn,AunBv¯. (.)

We also have

AxnByn,BynAu¯=AxnAu¯–AxnByn–BynAu¯ (.)

and

AunByn,AunB¯v=AunBv¯+AunByn–BynBv¯. (.)

By (.), (.), (.), and (.),

unu¯+vnv¯

xnu¯+ynv¯–ρn

 –ρnA

· AxnByn

ρn

 –ρnB

· AunByn+ρn

AunAu¯–AxnAu¯

xnu¯+ynv¯–ρn

 –ρnA

· AxnByn

ρn

 –ρnB

· AunByn

+ρn· A · unxn ·

AunAu¯+AxnAu¯. (.)

We also have

unu¯+vnv¯=unxn+ unxn,xnu¯+xnu¯

+vnyn+ vnyn,yn–¯v+yn–¯v. (.)

Case :lim infn→∞ρn( –ρnA) > .

By (.), (.), and (.) we get

lim

n→∞AxnByn= . (.)

Case : Suppose thatlim infn→∞ρn( –ρnB) > .

By (.), (.), and (.) we get

lim

n→∞AunByn= . (.)

By (.) and (.) we determine

lim

n→∞AxnByn= . (.)

Next, following the same argument as the final proof of Theorem ., we get the

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Remark . Suppose that{ρn}n∈Nsatisfy the following inequality:

 <κρn

δ

max{√· A,· A· B+B,B}.

Then{ρn}n∈Nsatisfy the conditions in Remark . and Theorem ..

3 Applications of the split equality problem

3.1 The split feasibility problem

LetHandHbe real Hilbert spaces. LetCandQbe nonempty closed convex subsets of

H andH, respectively. LetA:H→Hbe a linear and bounded operator with adjoint

operatorA∗. The following problem is the split feasibility problem in Hilbert spaces, which was first introduced by Censor and Elfving []:

(SFP) Findx¯∈Hsuch thatx¯∈CandAx¯∈Q.

Here, let:={xC:AxQ}be the solution set of problem (SFP). It is worth noting

that this problem is a particular case of the split equality problem whenH=HandBis

the identity mapping onH. For additional details, one can refer to [, –] and related

literature.

By Algorithm ., we get the following algorithm to study problem (SFP).

Algorithm . For givenxnH andynH, find the approximate solution by the

fol-lowing iterative process.

Step . Forn∈N, letunandvnbe defined by

un=PC[xnρnA∗(Axnyn)], vn=PQ[yn+ρn(Aunyn)],

whereρn> satisfies

ρnA∗(Axnyn) –A∗(Aunvn)+(Aunyn) –B∗(Aunvn)

δxnun+δynvn,  <δ< . (.)

Step . Ifxn=unandyn=vn, then(xn,yn)is a solution of problem (SFP) and stop. Other-wise, go to Step .

Step . Compute the next iterate(xn+,yn+)as follows:

⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩

D(n,):=xnun+ρn[A∗(Aunvn) –A∗(Axnyn)], D(n,):=ynvnρn[(Aunvn) – (Aunyn)], αn:=xn

un,D(n,)+ynvn,D(n,) D(n,)+D(n,) , xn+=PC[xnαnD(n,)],

yn+=PQ[ynαnD(n,)].

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We get the following convergence theorem for the split feasibility problem by using The-orem ..

Theorem . Let Hand Hbe real Hilbert spaces.Let C and Q be nonempty closed

con-vex subsets of Hand H,respectively.Let A:H→Hbe a linear and bounded operator

with adjoint operator A∗.Chooseδ∈(, ).Letbe the solution set of the split feasibility

problem and suppose that=∅.Let{ρn}n∈N be a sequence in(, /max{A, })such that(.)hold and assume thatlim infn→∞ρn( –ρnA) > orlim infn→∞ρn( –ρn) > s. Then,for the sequence{(xn,yn)}n∈Nin Algorithm.,there existsx¯∈such that xnx¯

as n→ ∞.

3.2 Linear inverse problem

In this subsection, we study an inverse problem by our algorithms and convergence the-orems. LetHandHbe real Hilbert spaces. LetCbe a nonempty closed convex subset

ofH, andA:H→Hbe a linear and bounded operator with adjoint operatorA∗. Given

bH. Then we consider the following inverse problem in this section:

(IV) Findx¯∈Csuch thatAx¯=b.

This is a particular case of the split equality problem ifH=H,Q={b}, andB(x) =x

for allxH. Next, take any (x,y)∈H×Hwithy=b. Then, by Algorithm . we get

the following algorithm to study problem (IV).

Algorithm . For givenxnH, find the approximate solution by the following iterative

process.

Step . Compute the next iterateunas follows:

un=PC

xnρnA∗(Axnb)

,

whereρn> satisfies

ρn·A∗(Axn) –A∗(Aun)≤δxnun,  <δ< . (.)

Step . Ifxn=un, thenxnis a solution of problem (IV) and stop. Otherwise, go to Step . Step . Compute the next iteratexn+as follows:

⎧ ⎪ ⎨ ⎪ ⎩

Dn:=xnun+ρn[A∗(Aun) –A∗(Axn)], αn:=xnDunn,Dn,

xn+=PC[xnαnDn].

Next, updaten:=n+ and go to Step .

We get the following convergence theorem for the linear inverse problem by using The-orem ..

Theorem . Let Hand Hbe real Hilbert spaces.Let C be a nonempty closed convex

subset of H,and A:H→Hbe a linear and bounded operator with adjoint operator A∗.

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Let {ρn}n∈N be a sequence in (, /max{A, })such that (.)holds and assume that

lim infn→∞ρn( –ρnA) > orlim infn→∞ρn( –ρn) > .Then,for the sequence{xn}n∈N in Algorithm.,there existsx¯∈such that xnx as n¯ → ∞.

Remark . By Algorithm . and Theorem ., we can get the related algorithms and convergence theorems for the split feasibility problem and the inverse problems.

4 Numerical results

All codes were written in R language (version .. (--), the R Foundation for Statistical Computing Platform: x--w-mingw/x).

Example . LetH=H=H=R,C:={x∈R:x ≤},Q:={x= (u,v)∈R: (u

)+ (v– )},

A:=

 

 

, B:=

 

 

.

Then problem (SEP) has a unique solution (x¯,y¯)∈R×R, wherex¯:= (x¯,x¯),y¯:= (y¯,y¯).

Indeed,x¯= .,x¯= .,y¯= ,y¯= . Letε>  and the algorithm stop ifxnx¯+yn– ¯

y<ε.

In Table , settingε= –,x= (, )T,y= (, )T, andρn= . for alln∈N, we get

the numerical results.

In Table , settingε= –,x

= (, )T,y= (, )T, andρn= . for alln∈N, we get the

numerical results.

In Table , settingε= ×–,x

[image:16.595.116.480.490.547.2]

= (–, –)T,y= (–, )T, andρn= . for all n∈N, we get the numerical results.

Table 1 ε= 10–1,x1= (10, 10)T,y1= (1, 1)T,ρn= 0.01

Algorithm Time (s) Iteration Approximate solution(x1

[image:16.595.116.481.583.639.2]

n, x2n) Approximate solution(yn1, y2n) Algorithm 2.1 0.01 196 (0.6114674, 0.7912309) (3.0850778, 3.9920504) Algorithm 2.2 0.00 122 (0.5970952, 0.8020906) (3.0421971, 4.0866474) (ACQA) 1.94 58,324 (0.6132467, 0.7898914) (3.0670840, 3.9505550) (PLA) 2.57 78,654 (0.6132467, 0.7898914) (3.0670840, 3.9505550)

Table 2 ε= 10–1,x1= (5, 5)T,y1= (1, 1)T,ρn= 0.01

Algorithm Time (s) Iteration Approximate solution(x1

n, x2n) Approximate solution(yn1, y2n) Algorithm 2.1 0.82 11,168 (0.6132467, 0.7898915) (3.067084, 3.950555)

Algorithm 2.2 0.02 205 (0.6077392, 0.7940725) (3.0847143, 4.0304899) (ACQA) 1.94 58,324 (0.6132467, 0.7898914) (3.067084, 3.950555) (PLA) 2.28 71,521 (0.6132467, 0.7898915) (3.067084, 3.950555)

Table 3 ε= 4×10–2,x1= (12, –50)T,y1= (–40, 20)T,ρn= 0.01

Algorithm Time (s) Iteration Approximate solution(x1

[image:16.595.116.480.675.733.2]
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Competing interests

The authors declare that they have no competing interests.

Authors’ contributions

Both authors contributed equally and significantly in writing this paper. Both authors read and approved the final manuscript.

Author details

1Department of Applied Mathematics, National Chiayi University, Chiayi, Taiwan.2Department of Mathematics, National

Kaohsiung Normal University, Kaohsiung, 82444, Taiwan.

Acknowledgements

Prof. Wei-Shih Du was supported by Grant No. MOST 104-2115-M-017-002 of the Ministry of Science and Technology of the Republic of China.

Received: 10 May 2016 Accepted: 28 July 2016

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(2005)

Figure

Table 1 ε = 10–1, x1 = (10,10)T, y1 = (1,1)T, ρn = 0.01

References

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