Volume 2008, Article ID 373050,17pages doi:10.1155/2008/373050
Research Article
A Class of Commutators for Multilinear Fractional
Integrals in Nonhomogeneous Spaces
Jiali Lian and Huoxiong Wu
School of Mathematical Sciences, Xiamen University, Xiamen Fujian, 361005, China
Correspondence should be addressed to Huoxiong Wu,[email protected]
Received 3 March 2008; Accepted 16 July 2008
Recommended by Nikolaos Papageorgiou
Letμ be a nondoubling measure onRd. A class of commutators associated with multilinear fractional integrals and RBMOμfunctions are introduced and shown to be bounded on product of Lebesgue spaces withμ.
Copyrightq2008 J. Lian and H. Wu. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.
1. Introduction
In recent years, the study of multilinear operators and their commutator has been attracting many researchers. Many results which parallel to the linear theory of classical integral operators are obtained. For details, one can see1–4, and so forth. Meanwhile, as a further development, harmonic analysis on Rd with nondoubling measures has been developed rapidly. Many results of singular integrals and the related operators on Euclidean spaces with Lebesgue measure have been generalized to the Lebesgue spaces with nondoubling measures
see5–10, etc.. Motivated by5,8, we will consider the commutators generated by a class of multilinear fractional integrals and RBMO functions with nondoubling measure, which were introduced by Tolsa in11.
Before stating our results, we recall some definitions and notations. Letμbe a Radon measure onRd satisfying the following growth condition; there exist constants C > 0 and
n∈0, d, such that
μQ≤ClQn
, 1.1
for any cubeQ ⊂ Rd with sides parallel to the coordinate axes, where lQ stands for the side length ofQ. Forr > 0,rQ will denote the cube with the same center as Q and with
Let 0≤β < n, given two cubesQ⊂RinRd, we set
KQ,Rβ 1 NQ,R
k1
μ2kQ l2kQn
1−β/n
, 1.2
whereNQ,Ris the first integerksuch thatl2kQ≥lR. Ifβ0, thenK0Q,RKQ,R. The later quantity was introduced by Tolsa in11.
Givenβd depending ondlarge enoughe.g.,βd>2n, we say that a cubeQ⊂ Rdis doubling ifμ2Q≤βdμQ.
Given a cube Q ⊂ Rd, let N be the smallest nonnegative integer such that 2NQ is doubling. We denote this cube byQ.
Letη > 1 be a fixed constant. We say thatb ∈L1
locμis in RBMOμif there exists a constantC1such that for any cubeQ
1
μηQ
Q
by−m
Qb dμy≤C1,
mQb−mRb ≤C1KQ,R, for any two doubling cubesQ⊂R, 1.3
wheremQbμQ−1
Qbydμy. The minimal constantC1is the RBMOμnorm ofb, and it will be denoted byb∗. In11, Tolsa obtained equivalent norm in the space RBMOμwith
different parametersη >1 andβd>2n.
We consider the following multilinear fractional integral operator
Iα,m
f1, . . . , fm
x
Rdm
f1
x−y1
f2
x−y2
· · ·fm
x−ym
y1, y2, . . . , ym mn−α dμ
y1
· · ·dμym
. 1.4
Form1, we denoteIα,1byIα, which is the Riesz potential operator related toμ. Given m ∈ N, for all 1 ≤ j ≤ m, we denote by Cm
j the family of all finite subsets
σ {σ1, . . . , σj}of{1,2, . . . , m}ofj different elements. For anyσ ∈ Cjm, we denoteσ {1,2, . . . , m} \σ {σj 1, . . . , σm}. Moreover, for bj ∈ RBMOμ, j 1,2, . . . , m, let
b b1, b2, . . . , bmand denote bybσ bσ1, . . . , bσjand by bσx bσ1x· · ·bσjx. Also, we denotef f1, . . . , fm,fσ fσ1, . . . , fσj,bσfσ bσj1fσj1, . . . , bσmfσm. We define a kind of commutator ofIα,mas follows:
b, Iα,m
fx
m
j0
σ∈Cm j
−1m−jbσxIα,m
fσ, bσfσ
x. 1.5
In particular, form2, we define
b1, b2, Iα,2
f1, f2
x b1xb2xIα,2
f1, f2
x−b1xIα,2
f1, b2f2
x −b2xIα,2
b1f1, f2
x Iα,2
b1f1, b2f2
x. 1.6
Obviously, form 1, the operator defined in 1.5is the Coifman-Rochberg-Weiss type commutator of fractional integral,b, Iα. Under the assumption thatμis a nondoubling measure, Chen and Sawyer5established theLp, Lq-boundedness ofb, I
Theorem 1.1. Letμbe defined as above andμ∞,bj ∈RBMORd,j1,2,0< α <2n. Then
b1, b2, Iα,2is a bounded operator fromLq1×Lq2 toLq with1/q 1/q11/q2−α/2n > 0and 1< q1,q2 <∞.
Remark 1.2. ByLemma 2.2inSection 2,Theorem 1.1for the caseμ<∞also holds provided
Iα,2,b1, b2, Iα,2,b1, Iα,2, andb2, Iα,2satisfy certainT1type conditions. For instance, ifIα,2 satisfies theT1condition, that is,I∗1
α,2 0, then we can easily obtain
Iα,2f1, f2xdμx 0 see3for the notationI∗1
α,2.
More generally, we have the following theorem.
Theorem 1.3. Letm∈N,μbe defined as above, andμ ∞,bj ∈ RBMORd,j 1,2, . . . , m, 0< α < mn. Then
b, Iα,m
fLqμ≤C
m
j1
bj∗fj
Lqjμ, 1.7
where1/q1/q11/q2· · ·1/qm−α/mn >0and1< qj <∞,j 1,2, . . . , m.
Clearly,5, Theorem 1is the special case of ourTheorem 1.3form 1. Throughout this paper, we always use the letterCto denote a positive constant that may vary at each occurrence but is independent of the essential variable.
2. Proofs of theorems
We only proveTheorem 1.1sinceTheorem 1.3can follow from the same arguments and an analogous version of the followingLemma 2.5, which can be deduced by induction onm. Before proving our results, we need to recall some notation and establish some lemmas which play important roles in the proofs.
Letfbe a function inL1locRd, we define the noncentered maximal operator
Mp,βηfx sup Qx
1
μηQ1−βp/n
Q
fy pdμy1/p
, 2.1
and the sharp maximal function
M#,βfx sup Qx
1
μ3/2Q
Q
fy−mQf dμy sup R⊃Qx Q,Rdoubling
mQf−mRf KQ,Rβ ,
2.2
where the supremum is taken over all cubes Q with sides parallel to the coordinate axes,
mQfis the mean value offon the cubeQ. Whenβ0, we denoteMp,0ηfbyMp,ηfand M#,0fbyM#f.
We also consider the noncentered doubling maximal operatorN, defined by
Nfx sup Qx Qdoubling
1
μQ
Q
Lemma 2.1see11. Let1≤p < ∞and1< ρ <∞. Thenb∈RBMOμ, if and only if for any cubeQ⊂Rd,
1
μρQ
Q
bx−mQb pdμx≤Cbp
∗, 2.4
and for any doubling cubesQ⊂R,
mQb−mRb ≤CKQ,Rb∗. 2.5 Lemma 2.2see5. Letf ∈L1
locμwith
fdμ0ifμ<∞.For1< p <∞, ifinf1,Nf∈ Lpμ, then for0≤β < nwe have
NfLpμ≤CM#,βf
Lpμ. 2.6
Lemma 2.3see5. Letp < r < n/αand1/q1/r−α/n. Then Mα
p,ηfLqμ≤CfLrμ, 2.7
whereη >1and0≤α < n/p.
Lemma 2.4. Supposeμis a Radon measure satisfying1.1. Letm∈Nand1/s1/r1· · ·1/rm−
α/n >0with0< α < mn,1≤rj ≤ ∞. Then,
aif eachrj>1,
Iα,m
f1, . . . , fmLsμ≤C
m
j1 fj
Lrjμ; 2.8
bifrj1for somej,
Iα,m
f1, . . . , fmLs,∞μ≤C m
j1 fj
Lrjμ. 2.9
Proof. The proof follows the idea that, for the classical setting, can be found in4. For the sake of completeness, we will show it again.
Sinceα > 0, someri < ∞. If say, rl1 · · · rm ∞, 1 ≤ l < m, because α/n < 1/r1· · ·1/rl ≤l, so thatmn−α >m−ln, integration inyl1, . . . , ymreduces matters to the case when allriare finiteandml. Thus, we may assume that allri<∞. Now, observe that if 0< ci,i 1, . . . , m, and 0 < α < mi1ci, we can find 0 < αi < cisuch thatαmi1αi. Apply this observation tocin/ri, and 1/si 1/ri−αi/n. Sincemi11/si1/s, 0< αi/n≤1, 1< si<∞, and
y1 n−α1
y2 n−α2· · · ym n−αm ≤ y1, . . . , ym nm−α, 2.10 whereαmi1αi. It follows that
Iα,m
f1, . . . , fm
x≤m
i1 Iαi
fi
x. 2.11
Lemma 2.5. Letb1, b2, Iα,2be as in1.6,0< α <2n,τ >1,b1, b2∈RBMOμ. Then there exists a constantC >0such that for allf1∈Lq1μ,f2∈Lq2μ, andx∈Rd,
M#,αb1, b2, Iα,2
f1, f2
x≤Cb1∗b2∗Mτ,3/2
Iα,2
f1, f2
x b1∗Mτ,3/2
b2, Iα,2
f1, f2
x b2∗Mτ,3/2b1, Iα,2
f1, f2
x
b1∗b2∗Mpα1,9/8f1xMpα2,9/8f2x
,
2.12
M#,αb
1, Iα,2
f1, f2
x≤Cb1∗
Mτ,3/2Iα,2
f1, f2
x
Mpα1,9/8f1
xMα
p2,9/8
f2
x,
2.13
M#,αb2, Iα,2
f1, f2
x≤Cb2∗
Mτ,3/2Iα,2
f1, f2
x
Mpα1,9/8f1
xMα
p2,9/8
f2
x,
2.14
where
b1, Iα,2
f1, f2
x b1xIα,2
f1, f2
x−Iα,2
b1f1, f2
x,
b2, Iα,2
f1, f2
x b2xIα,2
f1, f2
x−Iα,2
f1, b2f2
x. 2.15
Proof. By the definition, to obtain2.12, it suffices to prove that for anyx∈ Rd and a cube
Qx, 1
μ3/2Q
Q
b1, b2, Iα,2 f1, f2
z−hQ dμz≤Cb1∗b2∗Mτ,3/2Iα,2
f1, f2
x
b1∗Mτ,3/2b2, Iα,2
f1, f2
x b2∗Mτ,3/2b1, Iα,2
f1, f2
x
b1∗b2∗Mpα1,9/8f1xMpα2,9/8f2x
, 2.16
and for any cubesQ⊂R, whereQis an arbitrary cube andRis doubling,
hQ−hR ≤CK2
Q,RK
α
Q,Rb1∗b2∗Mτ,3/2
Iα,2
f1, f2
x
b1∗Mτ,3/2b2, Iα,2
f1, f2
x b2∗Mτ,3/2b1, Iα,2
f1, f2
x
b1∗b2∗Mpα1,9/8f1xMpα2,9/8f2x
,
2.17
where
hQ mQ
Iα,2
mQ
b1
−b1
f1χRd\4/3Q,
mQ
b2
−b2
f2χRd\4/3Q
, hRmR
Iα,2
mR
b1
−b1
f1χRd\4/3R,
mR
b2
−b2
f2χRd\4/3R
.
First of all, it is easy to see that
b1, b2, Iα,2 f1, f2
z−hQ ≤ b1z−mQ
b1
b2z−mQ
b2
Iα,2
f1, f2
z
b1z−mQ
b1
Iα,2
f1,
b2z−b2
f2
z
b2z−mQ
b2
Iα,2
b1z−b2
f1, f2
z Iα,2
b1−mQb1
f1,
b1−mQb1
f2
z−hQ
:Iz IIz IIIz IVz.
2.19
Consequently,
1
μ3/2Q
Q
b1, b2, Iα,2 f1, f2
z−hQ dμz≤CIIIIIIIV, 2.20
where Iμ3/2Q−1QIzdμz, and II, III, IV are defined in the same way.
In what follows, we estimate I–IV, respectively. For I, by H ¨older’s inequality and
Lemma 2.1, we have
I 1
μ3/2Q
Q
Izdμz
≤C
1
μ3/2Q
Q
b1z−m
Q
b1 τ1dμz 1/τ1
×
1
μ3/2Q
Q
b2z−mQ
b2 τ2dμz 1/τ2
×
1
μ3/2Q
Q
Iα,2
f1, f2 τdμz 1/τ
≤Cb1∗b2∗Mτ,3/2
Iα,2
f1, f2
x,
2.21
whereτ1>1,τ2>1 and 1/τ1/τ11/τ21. For II, we have
II 1
μ3/2Q
Q
IIzdμz
≤C
1
μ3/2Q
Q
b1z−mQ
b1 sdμz 1/s
× 1 μ3/2Q
Q
b2, Iα,2 f1, f2
z τdμz1/τ
≤Cb1∗Mτ,3/2b2, Iα,2
f1, f2
x,
2.22
Similarly, we have
III≤Cb2∗Mτ,3/2b2, Iα,2
f1, f2
x. 2.23
It remains to estimate IV. For convenience, we setfj0 fjχ4/3Q,fj fj0fj∞,j 1,2. Then,
IVz ≤ Iα,2
b1−mQ
b1
f10,b2−mQ
b2
f20z Iα,2
b1−mQ
b1
f10,b2−mQ
b2
f2∞
z
Iα,2
b1−mQ
b1
f1∞,b2−mQ
b2
f20z Iα,2
b1−mQ
b1
f1∞,
b2−mQ
b2
f2∞
z−hQ
IV1z IV2z IV3z IV4z,
2.24
and so we have
1
μ3/2Q
Q
IVz dμz≤4
j1 1
μ3/2Q
Q
IVjzdμz:
4
j1
IVj. 2.25
To estimate IV1, sets1√p1,s2 √p2, and 1/v1/s11/s2−α/n. It follows from H ¨older’s inequality andLemma 2.4that
IV1≤ μQ
1−1/v
μ3/2QIα,2
b1−mQ
b1
f10,b2−mQ
b2
f20Lvμ
≤Cμ3/2Q−1/vb1−mQ
b1
f0
1Ls1μb2−mQ
b2
f0
2Ls2μ
≤ C
μ3/2Q1/v
4/3Q
f1y1 p1dμy
1 1/p1
×
4/3Q
b1y1−mQ b1 p1/
√p
1−1dμy
1
√p1−1/p1
×
4/3Q
f2y2 p2dμy
2
1/p2
4/3Q
b2y1−mQ bi p2/
√p
2−1dμy i
√p2−1/p2
≤C 2
i1
1
μ3/2Q1−αpi/2n
4/3Q
fiyi pidμy
i
1/pi
×
1
μ3/2Q
4/3Q
biyi−mQ bi pi/
√p
i−1dμy
i
√p
i−1/pi
≤Cb1∗b2∗Mpα1,9/8f1xMpα2,9/8f2x.
For term IV2, byLemma 2.1, we have
IV2 1
μ3/2Q
Q
IV2zdμz
≤C 1 μ3/2Q
Q
Rd\4/3Q
4/3Q
× b1
y1
−mQ b1 f0 1
y1 b2
y2
−mQ
b2
f2∞y2 z−y1, z−y2 2n−α dμ
y1
dμy2
dμz
≤ C
μ3/2Q
Q
4/3Q
b1y−mQ b1
f10y1 dμ
y1
×
Rd\4/3Q
b2 y2
−mQ
b2
f2∞y2 z−y2 2n−α dμ
y2 dμz ≤C 1
μ3/2Q1−αp1/2n
4/3Q
f1
y1 p1dμ
y1 1/p1
×
1
μ3/2Q
4/3Q
b1−mQ b1 p
1dμy
1 1/p1
×μ
3 2Q
−α/2n
μQ∞
k1
2k4/3Q\2k−14/3Q
b2 y2
−mQ
b2 f2 y2 2k2n−αlQ2n−α dμ
y2
≤Cb1∗Mpα1,9/8f1x
∞
k1
2−kn−α/2l
2k3 2Q
−nα/2
×
2k4/3Q
b2 y2
−mQ
b2
f2
y2 dμ
y2
≤Cb1∗Mpα1,9/8f1x
∞
k1
2−kn−α/2l
2k3 2Q
−nα/2
×
2k4/3Q
b2 y2
−m2k4/3Q
b2
f2
y2 dμ
y2
m2k4/3Q
b2
−mQ
b2
2k3/2Q
f2 y2 dμ
y2
≤Cb1∗Mpα1,9/8f1x
× ∞
k1
2−kn−α/2
1
l2k3/2Qn
2k4/3Q
b2 y2
−m2k4/3Q
b2 p
2dμy
2 1/p2
×
1
l2k3/2Qn−αp2/2
2k4/3Q
f2
y2 p2dμ
y2 1/p2
∞
k1
k2−kn−α/2b2∗
1
l2k3/2Qn−α/2
2k4/3Q
f2 y2 dμ
y2
≤Cb1∗b2∗Mpα1,9/8f1xMpα2,9/8f2x,
where the last inequality follows from the following two facts:
1
l2k3/2Qn−α/2
2k4/3Q
f2 y2 dμ
y2
≤ μ
2k4/3Q1−1/p2
l2k3/2Qn−α/2
2k4/3Q
f2
y2 p2dμ
y2 1/p2
≤Cμ
2k14/3Q1−1/p21/p2−α/2n
l2k14/3Qn−α/2
1
μ2k14/3Q1−αp2/2n
2k14/3Q
f2
y2 p2dμ
y2 1/p2
≤CMpα2,9/8f2x,
2.28 andsee11
m
2k4/3Q
bj
−mQ
bj ≤Cbj∗KQ,2k4/3Q≤Cbj∗KQ,2k4/3Q≤Ckbj∗, j1,2.
2.29 Similarly,
IV3 ≤Cb1∗b2∗Mpα1,9/8f1xMpα2,9/8f2x. 2.30 For term IV4, we have
Iα,2 b1−mQ
b1
f1∞,b2−mQ
b2
f2∞
z−Iα,2
b1−mQ
b1
f1∞,b2−mQ
b2
f2∞
y
≤
Rd\4/3Q
Rd\4/3Q
1
z−y1, z−y2 2n−α
− 1
y−y1, y−y2 2n−α
× 2
i1
bi
yi
−mQ
bi
fi∞yi dμ
y1
dμy2
≤
Rd\4/3Q
Rd\4/3Q
|z−y|
y−y1, y−y2 2n−α1
× 2
i1
bi
yi
−mQ
bi
fi∞yi dμ
y1
dμy2
≤C 2
i1
Rd\4/3Q
|z−y|1/2 y−yi n−α/21/2 bi
yi
−mQ
bi
fi∞yi dμ
yi
≤C 2
i1
∞
k1
2k4/3Q\2k−14/3Q2
−k/2 1
l2kQn−α/2 bi
yi
−mQ
bi fi∞
yi dμ
yi
≤C 2
i1
∞
k1 2−k/2
1
l2k3/2Qn
2k4/3Q
bi yi
−mQ
bi p
idμy
i
1/pi
×
1
l2k3/2Qn−αpi/2
2k4/3Q
fi
yi pidμ
yi
≤C 2
i1
∞
k1
2−k/2Mpα
i,9/8fix
×
1
l2k3/2Qn
2k4/3Q
bi yi
−m2k4/3Q
bi
m2k4/3Q
bi
−mQ
bi p
idμy
i
1/pi
≤C 2
i1
∞
k1
2−k/2kbi∗Mpαi,9/8fix
≤Cb1∗b2∗Mpα1,9/8f1xMpα2,9/8f2x.
2.31
Taking the mean overy∈Q, we obtain
Iα,2 b1−mQ
b1f1∞,
b1−mQ
b1
f2∞
z−hQ ≤Cb1∗b2∗Mpα1,9/8f1xMpα2,9/8f2x. 2.32
Thus,
IV4 1
μ3/2Q
Q
IV4zdμz≤Cb1∗b2∗Mpα1,9/8f1xMpα2,9/8f2x. 2.33
Combing2.20–2.33, we obtain2.16.
Now we turn to estimate2.17. For any cubes,Q⊂Rwithx∈Q, whereQis arbitrary andRis doubling. We denoteNQ,R1 simply byN, write
hQ−hR mQ Iα,2
b1−mQb1
f1∞,b2−mQb2
f2∞ −mR
Iα,2
b1−mRb1
f1∞,b2−mRb2
f2∞ ≤ mR
Iα,2
b1−mQb1
f1χRd\2NQ,
b2−mQb2
f2χRd\2NQ
−mQ
Iα,2
b1−mQb1
f1χRd\2NQ,
b2−mQb2
f2χRd\2NQ
mR
Iα,2
b1−mRb1
f1χRd\2NQ,
b2−mRb2
f2χRd\2NQ
−mR
Iα,2
b1−mQb1
f1χRd\2NQ,
b2−mQb2
f2χRd\2NQ
mQ
Iα,2
b1−mQb1
f1χ2NQ\4/3Q,
b2−mQb2
f2χRd\4/3Q
mQ
Iα,2
b1−mQb1
f1χRd\2NQ,
b2−mQb2
f2χ2NQ\4/3Q
mR
Iα,2
b1−mRb1
f1χRd\4/3R,
b2−mRb2
f2χ2NQ\4/3R
mR
Iα,2
b1−mRb1
f1χ2NQ\4/3R,b2−mRb2f2χRd\2NQ
6
i1 Ai.
2.34
By the similar arguments used in proving2.33, we obtain that
A1 ≤C
KQ,R
2
To estimateA2, we write
Iα,2
b1−mR
b1
f1χRd\2NQ,
b2−mR
b2
f2χRd\2NQ
z −Iα,2
b1−mQ
b1
f1χRd\2NQ,
b2−mQ
b2
f2χRd\2NQ
z mR b2 −mQ
b2
Iα,2
b1−mR
b1
f1χRd\2NQ, f2χRd\2NQ
z mR b1 −mQ
b1
Iα,2
f1χRd\2NQ,
b2−mR
b2
f2χRd\2NQ
z mR b1 −mQ
b1 mR b2 −mQ
b2
Iα,2
f1χRd\2NQ, f2χRd\2NQ
z.
2.36
Then,
A2≤ mR
b2
−mQ
b2
μR1
R
Iα,2
b1−mR
b1
f1χRd\2NQ, f2χRd\2NQ
zdμz mR b1 −mQ
b1
μR1
R
Iα,2
f1χRd\2NQ,b2−mRb2f2χRd\2NQzdμz
mR b1 −mQ
b1 mR
b2
−mQ
b2
μR1
R
Iα,2
f1χRd\2NQ, f2χRd\2NQ
zdμz
A21A22A23.
2.37
It is obvious that
A23≤CKQ,R2 b1∗b2∗Mτ,3/2Iα,2
f1, f2
x. 2.38
In order to estimate termA21, we write
Iα,2
b1−mRb1
f1χRd\2NQ, f2χRd\2NQ
z Iα,2
b1−mRb1
f1, f2
z−Iα,2
b1−mRb1
f1χ2NQχ4/3R, f2χ4/3R
z −Iα,2
b1−mRb1
f1χ4/3R, f2χ2NQχ4/3R
z Iα,2
b1−mRb1
f1χ2NQχ4/3R, f2χ2NQχ4/3Rz
−Iα,2
b1−mRb1
f1χRd\4/3R, f2χ2NQz
−Iα,2
b1−mRb1
f1χ2NQ, f2χRd\4/3R
z Iα,2
b1−mRb1
f1χ2NQ\4/3R, f2χ2NQ\4/3R
z
7
j1 Bjz.
2.39
ForB1z, we write Iα,2
b1−mRb1
f1, f2
z ≤ Iα,2
b1−b1z
f1, f2
z Iα,2
b1z−mRb1
f1, f2
By H ¨older’s inequality and the fact thatRis doubling, we have
1
μR
R
Iα,2
b1−mRb1
f1, f2
zdμz≤Cb1∗Mτ,3/2
Iα,2
f1, f2
x,
1
μR
R
Iα,2
b1−b1z
f1, f2
zdμz≤CMτ,3/2b1, Iα,2
f1, f2
x,
2.41
which imply
mRB1 ≤Cb1
∗Mτ,3/2
Iα,2
f1, f2
x Mτ,3/2
b1, Iα,2
f1, f2
x. 2.42
ForB2z, sets1√p1,s2p2, and 1/v1/s11/s2−α/n. Using H ¨older’s inequality and
Lemma 2.4, we have
1
μR
R
B2zdμz≤C
μR1−1/v
μR Iα,2
b1−mR
b1
f1χ2NQχ4/3R, f2χ4/3R
Lvμ
≤Cμ
3 2R
−1/v
b1−mR b1
f1χ2NQχ4/3R
Ls1μf2χ4/3RLs2μ
≤Cμ
3 2R
−1/v
4/3R
f2y p2dμy
1/p2
4/3R
f1x p1dμy
1/p1
×
4/3R
b1y−mR b1 p1/
√p
1−1dμy
√p1−1/p1
≤C
1
μ3/2R1−αp1/2n
4/3R
f1y p1dμy
1/p1
×
1
μ3/2R
4/3R
b1y−mR b1 p1/
√p
1−1dμy
√p 1−1/p1
×
1
μ3/2R1−αp2/2n
4/3Q
f2y p2dμy
1/p2
≤Cb1∗Mpα1,9/8f1xMpα2,9/8f2x,
2.43
which implies
mRB2 ≤Cb1∗Mα
p1,9/8f1xM
α
p2,9/8f2x. 2.44 Similarly,
mRB3 ≤Cb1
∗Mpα1,9/8f1xM
α
p2,9/8f2x,
mRB4 ≤Cb1
∗Mpα1,9/8f1xM
α
p2,9/8f2x.
ForB5z, sincez∈R, we have
B5z ≤ 2NQ
Rd\4/3Q
b1−mR b1
f1 f2
y2 z−y1, z−y2 2n−α dμ
y1
dμy2
≤
2NQ
f2 y2 dμ
y2
Rd\4/3Q
b1 y1
−mR
b1
f1 z−y1 2n−α dμ
y1
≤ C l2Rn−α/2
2NQ
f2 y2 dμ
y2
×∞
k1
2−kn
l2k4/3n−α/2
2k4/3R\2k−14/3R
b1 y1
−mR
b1
f1 dμ
y1
≤C 1 l2Rn−α/2
2NQ
f2 y2 dμ
y2
×∞
k1
2−kn
l2k4/3Rn−α/2
×
2k4/3R
b1 y1
−m2k4/3R
b1
f1 dμ
y1
2k4/3R
m2k4/3R
b1
−mR
b1
y1 f1
y1 dμ
y1
≤C 1 l2Rn−α/2
2NQ
f2 y2 dμ
y2
×∞
k1 2−kn
1
l2k4/3Rn
2k4/3R
b1 y1
−m2k4/3R
b1 p
1dμy
1 1/p1
× 1
l2k4/3Rn−αp1/2
2k4/3R
f1 p1
dμy1 1/p1
Cb1∗ 1
l2k4/3Rn−α/2
2k4/3R
f1 dμ y1
≤C 1 l2Rn−α/2
2NQ
f2 y2 dμ
y2
∞
k1
2−knb1∗
Mpα1,9/8f1x Mp1,9/8f1x
≤C
N
k1 1
l2Rn−α/2
2kQ\2k−1Q
f2 y2 dμ
y2b1∗Mpα1,9/8f1x
1
l2Rn−α/2
Q
f2 y2 dμ
y2b1∗Mpα1,9/8f1x
≤C
N
k0 1
l2Rn−α/2
2kQ
f2 y2 dμ
≤C
N
k0
μ2k1Q1−α/2n l2k1Qn−α/2
l2k1Qn−α/2 l2Rn−α/2
1
μ2k1Q1−α/2n
×
2kQ
f2 y2 dμ
y2b1∗Mpα1,9/8f1x
≤C
N
k0
μ2k1Q1−α/2n l2k1Qn−α/2
1
μ9/82kQ1−α/2n
2kQ
f2 y2 dμ
y2b1∗Mpα1,9/8f1x
≤CKQ,Rαb1∗Mpα1,9/8f1xMpα2,9/8f2x.
2.46
Taking the mean onzoverR, we obtain
mRB5 ≤CKα
Q,Rb1∗Mpα1,9/8f1xM
α
p2,9/8f2x. 2.47 Similarly, we have
mRB6 ≤CKα
Q,Rb1∗Mpα1,9/8f1xM
α
p2,9/8f2x,
mRB7 ≤CKα
Q,Rb1∗Mpα1,9/8f1xM
α
p2,9/8f2x.
2.48
Summing up the estimates2.39–2.48, we obtain
A21≤CKQ,RKQ,Rαb1∗b2∗Mτ,3/2Iα,2
f1, f2
x
b2∗Mτ,3/2b1, Iα,2
f1, f2
x b1∗b2∗Mp1,9/8f1xMp2,9/8f2x
.
2.49
By the same arguments, we can get
A22≤CKQ,RKQ,Rαb1∗b2∗Mτ,3/2
Iα,2
f1, f2
x
b1∗Mτ,3/2b2, Iα,2
f1, f2
x b1∗b2∗Mp1,9/8f1xMp2,9/8f2x
.
2.50
Consequently,
A2≤CKQ,R2 K α
Q,Rb1∗b2∗Mτ,3/2Iα,2
f1, f2
x
b1∗Mτ,3/2b2, Iα,2
f1, f2
x b2∗Mτ,3/2b1, Iα,2
f1, f2
x b1∗b2∗Mp1,9/8f1xMp2,9/8f2x
.
2.51
Using the similar arguments to those used in provingB5z, we can conclude that
A3A4A5A6 ≤CK2Q,RK
α
Therefore, we obtain
hQ−hR ≤CK2
Q,RK
α
Q,Rb1∗b2∗Mτ,3/2
Iα,2
f1, f2
x
b1∗Mτ,3/2b2, Iα,2
f1, f2
x b2∗Mτ,3/2b1, Iα,2
f1, f2
x b1∗b2∗Mp1,9/8f1xMp2,9/8f2x
,
2.53
which implies2.17.
Finally, we show how to derive 2.12 from 2.16 and 2.17. From 2.16, if Q is doubling andx∈Q, we have
mQ
b1, b2, Iα,2
f1, f2
−hQ ≤ 1
μQ
Q
b1, b2, Iα,2 f1, f2
z−hQ dμz
≤Cb1∗b2∗Mτ,3/2Iα,2
f1, f2
x b1∗Mτ,3/2b2, Iα,2
f1, f2
x b2∗Mτ,3/2b1, Iα,2
f1, f2
x b1∗b2∗Mp1,9/8f1xMp2,9/8f2x
.
2.54
Also, for any cubeQwithx∈ Q,KQ,Q ≤ CandK α
Q,Q ≤ C, by2.16,2.17, and2.54, we have
1
μ3/2Q
Q
b1, b2, Iα,2 f1, f2
z−mQ
b1, b2, Iα,2
f1, f2 dμz
≤ 1
μ3/2Q b1, b2, Iα,2
f1, f2
z−hQ dμz
1
μ3/2Q
Q
mQ
b1, b2, Iα,2
f1, f2
−hQ dμz
1
μ3/2Q
Q
hQ−hQ dμz
≤Cb1∗b2∗Mτ,3/2Iα,2
f1, f2
x b1∗Mτ,3/2b2, Iα,2
f1, f2
x b2∗Mτ,3/2b1, Iα,2
f1, f2
x b1∗b2∗Mp1,9/8f1xMp2,9/8f2x
.
2.55
On the other hand, for all doubling cubesQ⊂Rwithx∈Q, such thatKQ,Rα ≤Pα, wherePα is the constant in5, Lemma 6, by2.17, we have
hQ−hR ≤CK2
Q,RPαb1∗b2∗Mτ,3/2Iα,2
f1, f2
x b1∗Mτ,3/2b2, Iα,2
f1, f2
x b2∗Mτ,3/2b1, Iα,2
f1, f2
x b1∗b2∗Mp1,9/8f1xMp2,9/8f2x
.
Hence, by5, Lemma 6, we get
hQ−hR ≤CKα
Q,Rb1∗b2∗Mτ,3/2Iα,2
f1, f2
x
b1∗Mτ,3/2b2, Iα,2
f1, f2
x b2∗Mτ,3/2
b1, Iα,2
f1, f2
x b1∗b2∗Mp1,9/8f1xMp2,9/8f2x
,
2.57
for all doubling cubesQ⊂Rwithx∈Q. Invoking2.55yields that
mQ
b1, b2, Iα,2
f1, f2
−mR
b1, b2, Iα,2
f1, f2 ≤ mQ
b1, b2, Iα,2
f1, f2
−hQ hR−mR
b1, b2, Iα,2
f1, f2 hQ−hR
≤CKQ,Rαb1∗b2∗Mτ,3/2Iα,2
f1, f2
x
b1∗Mτ,3/2b2, Iα,2
f1, f2
x b2∗Mτ,3/2b1, Iα,2
f1, f2
x b1∗b2∗Mp1,9/8f1xMp2,9/8f2x
.
2.58
From this estimate and the definition of the sharp maximal function, we complete the proof of2.12. Similarly, we can deduce2.13and2.14. The details are omitted.
Now we are in the position to proveTheorem 1.1.
Proof ofTheorem 1.1. By the Lebesgue differentiation theorem, it is easy to see that for any
f∈L1 locRd,
fx ≤ Nfx, 2.59
forμ− a.e.x∈Rd, see11for details. By Lemmas2.2–2.5, we have
b1, b2, Iα,2
f1, f2Lq≤N
b1, b2, Iα,2
f1, f2Lq
≤M#,βb1, b2, Iα,2
f1, f2Lq
≤Cb1∗b2∗Mτ,3/2Iα,2
f1, f2Lq
b1∗Mτ,3/2b2, Iα,2
f1, f2Lq
b2∗Mτ,3/2b1, Iα,2
f1, f2Lq
b1∗b2∗Mpα1,9/8f1xMpα2,9/8f2Lq
≤Cb1∗b2∗f1Lq1f2Lq2
b1∗b2, Iα,2
f1, f2Lq
b2∗b1, Iα,2
f1, f2Lq
≤Cb1∗b2∗f1Lq1f2Lq2
b1∗M#,β
b2, Iα,2
f1, f2Lp1
b2∗M#,β
b1, Iα,2
f1, f2Lp2
≤Cb1∗b2∗f1Lq1f2Lq2.
2.60
This provesTheorem 1.1.
Acknowledgments
The authors would like to express their deep thanks to the referees for their valuable remarks and suggestions. Huoxiong Wu was partially supported by the NSF of ChinaG10571122.
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