Observation on the Positive Pell Equation
10
15
2
2
x
y
M. A. Gopalan1, A. Sathya2, A. Nandhinidevi3*
1
Professor, Department of Mathematics, Shrimati Indira Gandhi College, Trichy-620 002, Tamil nadu, India. 2
Assistant Professor, Department of Mathematics, Shrimati Indira Gandhi College, Trichy-620 002, Tamil nadu, India.
3*
PG Scholar, Department of Mathematics, Shrimati Indira Gandhi College, Trichy-620 002, Tamil nadu, India.
Abstract: The binary quadratic Diophantine equation represented by the positive Pellian y2 15x210is analyzed for its
non-zero distinct integer solutions. A few interesting relations among the solutions are given. Employing the solutions of the above hyperbola, we have obtained solutions of other choices of hyperbolas and parabolas.
Keywords: Binary quadratic, Hyperbola, Parabola, Pell equation, Integer solutions
I. INTRODUCTION
The binary quadratic equation of the form y2 Dx21 where D is non-square positive integer, has been selected by various
mathematicians for its non-trivial integer solutions when D takes different integral values [1-4]. For an extensive review of various
problems, one may refer [5-16]. In this communication, yet another an interesting equation given by y2 15x210 is considered and infinitely many integer solutions are obtained. A few interesting properties among the solutions are presented.
II. METHODOFANALYSIS
The Positive Pell equation representing hyperbola under consideration is
2 15 2 10
x
y (1)
The smallest positive integer solutions of (1) are
x01,y05
To obtain the other solutions of (1) , consider the pellian equation
15 1
2 2
x
y (2) whose initial solution is given by
1 ~
0
x ,~y0 4
The general solution
x~n,y~n
of (2) is given by
n
n g
x
15 2
1
~ ,
n
n f
y
2 1
~
where
1 1
) 15 4 ( ) 15 4
(
n n
n
f
(4 15) (4 15) , 1,0,1,...
1 1
n
gn n n
Applying Brahmagupta lemma between
x0,y0
and
~xn,~yn
, the other integer solution of (1) are given by
n n
n f g
x
15 2
5 2
1
1
n n
n f g
y
2 15 2
5
1
The recurrence relations satisfied by the solutions xand yare given by xn38xn2xn10
Some numerical examples of xn and yn satisfying (1) are given in the Table 1 below,
Table 1: Numerical Examples
n
n
x
yn0 9 35
1 71 275
2 559 2165
3 4401 17045
4 34649 134195
From the above table, we observe some interesting relations among the solutions which are presented below: Both xn and yn values are odd.
A. Relations Among The Solutions Are Given Below 1) xn3 8xn2 xn1 0
2) yn3 31xn2 4xn1 0
3) 8yn131xn1xn3 0
4) 8yn3 31xn3 xn1 0
5) xn2 4xn1 yn1 0
6) yn2 4yn115xn1 0
7) yn3 31yn1120xn1 0
8) 4xn2 xn1 yn2 0
9) xn3 xn1 2yn2 0
10) 4yn3 31yn215xn1 0
11) yn1 31xn2 4xn3 0
12) yn2 4xn2 xn3 0
13) yn3 xn2 4xn3 0
14) 4yn2 yn115xn2 0
15) yn3yn130xn3 0
16) yn3 4yn2 15xn2 0
17) yn3 4xn131xn2 0
18) 4xn3 xn2 yn3 0
19) 31yn2 4yn1 15xn30
20) 31yn3 yn1120xn3 0
21) 4yn3 yn2 15xn3 0
22) yn3 8yn2 yn1 0 23) 445yn3976yn231307yn10
24) 14640xn313543yn3952753yn10
25) 14640xn2 1717yn3 120787 yn10
B. Each Of The Following Expressions Represents A Nasty Number 1)
12 6x2n3 42x2n2
2)
96 6 2 4 330 2 2
8 1
x n x n
3)
12 6y2n2 18x2n2
4)
48 6 2 3 162 2 2
4 1
y n x n
5)
372 6 2 4 1278 2 2
31 1
y n x n
6)
1242x2n4330x2n3
7)
48 42 2 2 18 2 3
4 1
y n x n
8)
12 42y2n3 162x2n3
9)
48 42 2 4 1278 2 3
4 1
y n x n
10)
372 330 2 2 18 2 4
31 1
y n x n
11)
48 330 2 3 162 2 4
4 1
y n x n
12)
12330y2n41278x2n4
13)
60 54 2 2 6 2 3
5 1
y n y n
14)
480 426 2 2 6 2 4
40 1
y n y n
15)
60 426 2 3 54 2 4
5 1
y n y n
III.EACHOFTHEFOLLOWINGEXPRESSIONSREPRESENTSACUBICALINTEGER
1)
x3n4 7x3n3 3xn2 21xn1
2)
3 5 55 3 3 3 3 165 1
8 1
n n n
n x x x
x
3)
y3n3 3x3n3 9xn1 3yn1
4)
3 4 27 3 3 81 1 3 2
4 1
n n n
n x x y
y
5)
3 5 213 3 3 3 3 639 1
31 1
n n n
n x y x
y
6)
7x3n555x3n4 21xn3165xn2
7)
7 3 3 3 3 4 21 1 9 2
4 1
n n n
n x y x
y
8)
7y3n427x3n4 81xn221yn2
9)
7 3 5 213 3 4 639 2 21 3
4 1
n n n
n y x y
y
10)
55 3 3 3 3 5 9 3 165 1
31 1
n n n
n x x y
y
11)
55 3 4 27 3 5 81 3 165 2
4 1
n n n
n x x y
y
13)
9 3 3 3 4 27 1 3 2
5 1 n n n
n y y y
y
14)
71 3 3 3 5 213 1 3 3
40 1
n n n
n y y y
y
15)
71 3 4 9 3 5 213 2 27 3
5 1
n n n
n y y y
y
IV.EACHOFTHEFOLLOWINGEXPRESSIONSREPRESENTSABIQUADRATICINTEGER
1)
x4n57x4n428x2n2 4x2n36
2)
55 220 4 48
8 1 4 2 2 2 4 4 6
4n xn x n x n
x
3)
y4n43x4n412x2n24y2n26
4)
27 4 108 24
4 1 2 2 3 2 4 4 5
4n xn y n xn
y
5)
213 4 852 186
31 1 2 2 4 2 4 4 6
4n xn yn xn
y
6)
7x4n6220x2n355x4n528x2n46
7)
7 3 12 28 24
4 1 2 2 3 2 5 4 4
4n x n x n y n
y
8)
7y4n528y2n327x4n5108x2n36
9)
7 28 213 852 24
4 1 3 2 5 4 4 2 6
4n y n xn xn
y
10)
55 3 12 220 186
31 1 2 2 4 2 6 4 4
4n x n xn yn
y
11)
220 55 27 108 24
4 1 4 2 6 2 5 4 3
2n yn xn xn
y
12)
55y4n6220y2n4213x4n6852x2n46
13)
9 36 4 30
5 1 3 2 2 2 5 4 4
4n y n y n y n
y
14)
71 284 4 240
40 1 4 2 2 2 6 4 4
4n y n yn yn
y
15)
71 9 284 36 30
5 1 4 2 3 2 6 4 5
4n xn yn yn
y
V. EACHOFTHEFOLLOWINGEXPRESSIONSREPRESENTSAQUINTICINTEGER
16)
x5n67x5n5 5x3n5 35x3n3 70xn110xn2
17)
5 7 55 5 5 5 3 5 275 3 3 550 1 10 3
8 1
n n n n n
n x x x x x
x
18)
y5n53x5n5 5y3n315x3n330xn110yn1
19)
5 6 27 5 5 5 3 4 135 3 3 270 1 10 2
4 1
n n n n n
n x x x x y
y
20)
5 7 213 5 5 1065 3 5 5 3 5 2130 1 10 3
31 1
n n n n n
n x x y x y
y
21)
7y5n755x5n635x3n5275x3n4550xn2 70xn3
22)
7 5 5 3 5 6 15 3 4 35 3 4 30 2 70 1
4 1
n n n n n
n x x x x y
y
24)
7 5 7 213 5 6 10653 4 35 3 5 2130 2 70 3
4 1
n n n n n
n x x y x y
y
25)
5 6 27 5 5 5 3 4 135 3 3 270 1 10 2
4 1
n n n n n
n x x x x y
y
26)
55 5 5 3 5 7 15 3 5 275 3 3 30 3 550 1
31 1
n n n n n
n x x y x y
y
27)
55 5 6 27 5 7 135 3 5 275 3 4 270 3 550 2
4 1
n n n n n
n x x y x y
y
28)
55y5n7213x5n71065x3n5275y3n52130xn3550yn3
29)
9 5 5 5 6 5 3 4 45 3 3 90 1 10 2
5 1
n n n n n
n y y y y y
y
30)
71 5 5 5 7 355 3 3 5 3 5 710 1 10 3
40 1
n n n n n
n y y y y y
y
31)
71 5 6 9 5 7 355 3 4 45 3 5 710 2 90 3
5 1
n n n n n
n y y y y y
y
VI. REMARKABLEOBSERVATIONS
1) Employing linear combinations among the solutions of (1), one may generate integer solutions for other choices of hyperbolas
[image:5.612.106.511.339.715.2]which are presented in Table 2 below:
Table 2: Hyperbolas
S.NO Hyperbola (X,Y)
1 5 2 3 2 20
Y
X
xn2 7xn1 , 9xn1 xn2
2 5 2 3 2 1280
Y
X
xn355xn1 , 71xn1xn3
3 5 2 3 2 20
Y
X
yn13xn1 , 5xn1 yn1
4 5 2 3 2 320
Y
X
yn2 27xn1 , 35xn1 yn2
5 5X23Y2 19220
3 1 1
3 213 , 275
n n n
n x x y
y
6 5 2 3 2 20
Y
X
7xn355xn2 , 71xn29xn3
7 5 2 3 2 320
Y
X
7
y
n1
3
x
n2,
5
x
n2
9
y
n1
8 5 2 3 2 20
Y
X
7yn227xn2 ,35xn29yn2
9 5 2 3 2 320
Y
X
7yn3213xn2,275xn29yn3
10 5 23 2 19220
Y
X
55yn13xn3 ,5xn371yn1
11 5 2 3 2 320
Y
X
55yn227xn3,35xn371yn2
12 5 2 3 2 20
Y
X
55yn3213xn3,275xn371yn3
13 11163 2 20 2 71443200
Y
X
71yn1yn3 ,55yn1yn3
14 3 2 5 2 300
Y
X
9yn1 yn2 , yn27yn1
15 3 2 5 2 300
Y
2) Employing linear combination among the solutions of (1), one may generate integer solutions for other choices of parabolas which are presented in Table 3 below
Table 3: Parabolas
S.NO Parabola (X,Y)
1 3 2 5 10
X
Y
x2n3 7x2n2 , 9xn1 xn3
2 3 2 40 640
X
Y
x2n4 55x2n2 , 71xn1xn3
3 3 2 5 10
X
Y
y2n2 3x2n2 , 5xn1 yn1
4 3 2 20 160
X
Y
y2n3 27x2n2 ,35xn1 yn2
5 3 2 155 9610
X
Y
y2n4213x2n2 ,275xn1yn3
6 3 2 5 10
X
Y
7x2n455x2n3,71xn29xn3
7 3 2 20 160
X
Y
7y2n23x2n3 , 5xn2 9yn1
8 3 2 5 10
X
Y
7y2n327x2n3,35xn29yn2
9 3 2 20 160
X
Y
7y2n4213x2n3,275xn29yn3
10 3 2 155 9610
X
Y
55y2n23x2n4 ,5xn371yn1
11 3 2 20 160
X
Y
55y2n327x2n4,35xn371yn2
12 3 2 5 10
X
Y
55y2n4213x2n4,275xn371yn3
13 3 2 5 10
X
Y
9
y
2n2
y
2n3,
y
n2
7
y
n1
14 2 22326 1786080
X
Y
71y2n2y2n4 ,55yn1yn3
15 2 3 30
X
Y
71y2n39y2n4 ,7yn355yn2
VII. CONCLUSION
In this paper, we have presented infinitely many integer solutions for the positive Pell equation y215x210 . As the binary quadratic Diophantine equations are rich in variety, one may search for the other choices of Pell equations and determine their integer solutions along with suitable properties.
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